A cabin cruiser traveling with the current went 45 mi in 3 h. Traveling against the current it took 5H to go the same distance find the rate of the cabin cruiser in calm water and the rate of the current

Assuming it is .005y^2 + 10y not .005*y*2 + 10y

Profit = Revenue - Cost

Profit = (.005y^2 + 10y) - (20y + 1,000,000)

Profit at 30,000 cars so y = 30000

Profit = (.005(30000)^2 + 10(30000)) - (20(30000) + 1,000,000)

Profit = $3,200,000

Answer:

12

Step-by-step explanation:

15000x = 9000x +72000

6000x = 72000

x = 12

Answer: the number of units that must be sold to break even is 12

Step-by-step explanation:

The cost function is expressed as

C(x)= 9000x +72000

The revenue function is expressed as

R(x) = 15000x

Profit = Revenue - cost

At the point of break even, the total revenue is equal to the total cost. This means that profit is zero. The expression becomes

Revenue - cost = 0

Revenue = cost

R(x) = C(x)

Therefore,

15000x = 9000x +72000

15000x - 9000x = 72000

6000x = 72000

x = 72000/6000

x = 12

Answer:

Explanation:

The question is incomplete. The complete question is:

A bag contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans.

If we choose a jelly bean, then another jelly bean without putting the first one back in the bag, what is the probability that the first jelly bean will be green and the second will be red?

The probability that the first jelly bean will be green is the number of green jelly beans divided by the total number of jelly beans:

After chosing the first green jelly bean, there will be 13 jelly beans, from which 6 are red. Thus, the probability that the second jelly bean will be red is:

The probability of the joint events is the product of the two consecutive events:

The probability that the first jelly bean will be green and the second will be red is 12/91.

We start by determining the total number of jelly beans in the bag, which is:

6 red + 4 green + 4 blue = 14 jelly beans.

Step 1: Probability of the first jelly bean being green

The probability of drawing a green jelly bean first is the number of green jelly beans divided by the total number of jelly beans:

P(Green first) = 4/14 = 2/7.

Step 2: Probability of the second jelly bean being red

Once the first green jelly bean is chosen, there are now 13 jelly beans left in the bag, with 6 being red:

P(Red second | Green first) = 6/13.

Step 3: Combined probability

The combined probability of both events happening (first green, then red) is given by multiplying their individual probabilities:

P(Green first and Red second) = (2/7) * (6/13) = 12/91.

Thus, the combined probability is 12/91.

Complete question: A bag contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans. If we choose a jelly bean, then another jelly bean without putting the first one back in the bag, what is the probability that the first jelly bean will be green and the second will be red?

[tex]A) -27a^3 b^6 + 8a^9 b^{12}\\D) 27a^3 b^6 + 8a^9 b^{12}[/tex]

Step-by-step explanation:

Here, the given expressions are:

[tex]A) -27a^3 b^6 + 8a^9 b^{12}\\= (-3)^3(a^3)(b^2)^3 + (2)^3(a^3)3(b^4)^3\\= (-3ab^2)^3 +(2a^3b^4)^3[/tex]

So, the above expression is "sum of cubes".

[tex]B) -9a^3 b^6 + a^9 b^{10}\\[/tex]

But (-9) can not be expressed as a Perfect cube root.

So, the above expression is not "sum of cubes".

[tex]C) 9a^3 b^6 + 8a^9 b^{12}\\[/tex]

But (9) can not be expressed as a Perfect cube root.

So, the above expression is not "sum of cubes".

[tex]D) 27a^3 b^6 + 8a^9 b^{12}\\\\= (3)^3a^3(b^2)^3 + (2)^3(a^3)^3(b^4)^3\\= (3ab^2)^3+ (2a^3b^4)^3[/tex]

So, the above expression is  "sum of cubes".

Answer:

16 to the power of 1 over 4 equals 2 to the power of 4 to the power of 1 over 4 equals 2 to the power of 4 multiplied by 1 over 4 equals 2

Step-by-step explanation:

16 to the power of 1 over 4 equals 2 to the power of 4 to the power of 1 over 4 equals 2 to the power of 4 multiplied by 1 over 4 equals 2

(16)^1/4 = (2^4)^1/4

4 cancels 4

2^1 = 2

Answer:

Step-by-step explanation:

The answer is the first one.

[tex]16^{\frac{1}{4}}[/tex]  simplifies down to

[tex](2^4)^{\frac{1}{4}}[/tex]  The power to power rule is that you multiply the exponents together:

[tex]2^{\frac{4}{4}}[/tex]  which is [tex]2^1[/tex]  which is 2

I'm assuming that you are also working with radicals (since radicals and exponents are inverses of each other).  The way to write this is as a radical and simplify it is:

[tex]16^{\frac{1}{4}[/tex]  as a radical is

[tex]\sqrt[4]{16^1}[/tex]

To simplify, try to write the radicand (the number under the square root) so it's a number with a power that matches the index (the number in the "arm" of the radical sign.  Our index is a 4).  

16 is the same as 2⁴:

[tex]\sqrt[4]{2^4}[/tex]

The power on the 2 is a 4, which is the same as the index.  When the power matches the index, you pull out the base as a single number:

[tex]\sqrt[4]{2^4}=2[/tex]

Answer:

Fruit smoothie: $3.4

Protein bar: $2.5

Step-by-step explanation:

Let x represent cost of fruit smoothie and y represent cost of protein bar.

We have been given that Jake buys a fruit smoothie and a protein bar for​ $5.90. We can represent this information in an equation as:

[tex]x+y=5.90...(1)[/tex]

[tex]x=5.90-y...(1)[/tex]

We are also told that Kobe buys 2 fruit smoothies and 4 protein bars. He pays​ $16.80. We can represent this information in an equation as:

[tex]2x+4y=16.80...(2)[/tex]

Upon substituting equation (1) in equation (2), we will get:

[tex]2(5.90-y)+4y=16.80[/tex]

[tex]11.80-2y+4y=16.80[/tex]

[tex]2y=16.80-11.80[/tex]

[tex]2y=5[/tex]

[tex]y=\frac{5}{2}=2.5[/tex]

Therefore, each protein bar costs $2.5.

Upon substituting [tex]y=2.5[/tex] in equation (1), we will get:

[tex]x=5.90-2.5=3.4[/tex]

Therefore, each fruit smoothie costs $3.4.

Each fruit smoothie costs [tex]3.40\ dollars[/tex], and each protein bar costs [tex]2.50\ dollars[/tex].

To solve for the cost of each fruit smoothie [tex](\( x \))[/tex] and each protein bar [tex](\( y \))[/tex], we'll use the given system of equations:

1. [tex]\( x + y = 5.90 \)[/tex]

2. [tex]\( 2x + 4y = 16.80 \)[/tex]

Let's solve this step by step.

Step 1: Solve the first equation for [tex]\( x \)[/tex]

[tex]\[ x + y = 5.90 \][/tex]

[tex]\[ x = 5.90 - y \][/tex]

Step 2: Substitute [tex]\( x = 5.90 - y \)[/tex] into the second equation:

[tex]\[ 2(5.90 - y) + 4y = 16.80 \][/tex]

[tex]\[ 11.80 - 2y + 4y = 16.80 \][/tex]

[tex]\[ 2y = 16.80 - 11.80 \][/tex]

[tex]\[ 2y = 5 \][/tex]

[tex]\[ y = \frac{5}{2} \][/tex]

[tex]\[ y = 2.50 \][/tex]

Step 3: Substitute [tex]\( y = 2.50 \)[/tex] back into [tex]\( x = 5.90 - y \)[/tex]

[tex]\[ x = 5.90 - 2.50 \][/tex]

[tex]\[ x = 3.40 \][/tex]

Answer:

[tex]\text{Area of margin}=145\text{ cm}^2[/tex]

Step-by-step explanation:

We have been given that a painting is drawn on a cardboard 22 cm long and 12 cm wide such that there is a margin of 2.5 meter cm along each side. We are asked to find the area of the margin.

The total area of the margin would be equal to area of whole cardboard minus area of painting.

[tex]\text{Area of whole cardboard}=22\text{ cm}\times 12\text{ cm}[/tex]

[tex]\text{Area of whole cardboard}=264\text{ cm}^2[/tex]

Since there is a margin of 2.5 meter cm along each side, so sides of painting would be 2,5 cm smaller on four sides. The sides painting would be [tex]22-5=17[/tex] and [tex]12-5=7[/tex].

[tex]\text{Area of painting}=17\text{ cm}\times 7\text{ cm}[/tex]

[tex]\text{Area of painting}=119\text{ cm}^2[/tex]

[tex]\text{Area of margin}=264\text{ cm}^2-119\text{ cm}^2[/tex]

[tex]\text{Area of margin}=145\text{ cm}^2[/tex]

Therefore, the total area of the margin is 145 squared cm.

Answer:

164 pounds

Step-by-step explanation:

Please see attached picture for full solution.

Answer:

The required scatterplot is given in attached file.

Step-by-step explanation:

From the scatterplot we see that two study variables are not linearly related. There may be some non-linear relation between the two variables.

The question asks about the relationship between canary chick begging intensity and their relative growth rate. This can be determined by creating and interpreting a scatterplot of the provided data. The relationship would be considered linear if there's a consistent rate of change between begging intensity and growth rate, and non-linear if the rate of change varies.

The question is asking if the relationship between the relative growth rate of canary chicks and the difference in begging intensity is linear or not. By plotting the data on a scatterplot, we would visualize whether there is a consistent, straight-line relationship (linear) or not (non-linear) between these two variables.

Without the actual scatterplot, I cannot definitively say if the relationship is linear or not. However, linear relationships typically involve variables moving in the same direction at a constant rate, while non-linear relationships involve variables moving at different rates or directions. Therefore, if the increase in begging intensity is consistently associated with an increase in relative growth rate (and vice versa), the relationship could be considered linear. On the other hand, if increases or decreases in begging intensity inconsistently affect the relative growth rate, the relationship would likely be non-linear.

An important part of this research is the ability to interpret scatterplots and understand the concepts of linear and non-linear relationships in biological data. Interpreting such relationships is integral in the study of animal behavior and understanding how different factors, such as parental care and chick begging, affect survival and growth in bird species like canaries.

https://brainly.com/question/31693063

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Answer:

P ( E_1*E_2*E_3*E_4 ) = 0.1055

Step-by-step explanation:

Given:

- 52 cards are dealt in 1 , 2 , 3 , 4 hands.

- Events:

             E_1       Hand 1 has exactly 1 ace

             E_2       Hand 2 has exactly 1 ace

             E_3       Hand 3 has exactly 1 ace

             E_4       Hand 4 has exactly 1 ace

Find:

p =P ( E_1*E_2*E_3*E_4 )

Solution:

Multiplication rule.

- For n ε N and events E_1 , E_2 , ... , E_n:

P ( E_1*E_2*......*E_n ) = P (E_1)*P(E_2|E_1)*P(E_3|E_2*E_1)*......*(E_n|E_1*E_2...E_n-1 )

- So for these events calculate 4 probabilities:-

-  For E_1, is to choose an ace multiplied by the number of ways to choose remaining 12 cards out of 48 non-aces:

                               P ( E_1 ) = 4C1 * 48C12 / 52C13

- For E_2 | E_1 , one ace and 12 other cards have already been chosen. there are 39C13 equally likely hands. The number of different one ace hand 2 is the number of ways to choose an ace from 3 remaining multiplied by the number of ways to choose the remaining 12 from 36, we have:

                               P ( E_2 | E_1  ) = 3C1 * 36C12 / 39C13

                               P ( E_3| E_2*E_1  ) = 2C1 * 24C12 / 26C13

                               P ( E_4 | E_3*E_2*E_1  ) = 1C1*12C12 / 13C13 = 1

- So the multiplication rule for n = 4 is as follows:

     P ( E_1*E_2*E_3*E_4 ) = P (E_1)*P(E_2|E_1)*P(E_3|E_2*E_1)*P ( E_4 | E_3*E_2*E_1  ) = [ 4C1 * 48C12 / 52C13 ] * [ 3C1 * 36C12 / 39C13 ] * [ 2C1 * 24C12 / 26C13 ]

     P ( E_1*E_2*E_3*E_4 ) = [ 4!*48! / (12!)^4 ] / [ 52! / (13!)^4 ]

     P ( E_1*E_2*E_3*E_4 ) = [ 4!*13^4 / (52*51*50*49) ]

    P ( E_1*E_2*E_3*E_4 ) = 0.1055

The probability that each hand in a deck of 52 cards gets exactly one ace is approximately 10.5%.

To determine the probability that each hand in a randomly divided deck of 52 cards has exactly one ace, we use the concept of conditional probability.
Let's find it step by step

Step 1 : consider the event E1 that the first hand has exactly one ace:

There are 4 aces and 52 total cards. The probabilities for drawing an ace for the first hand are affected by the decreasing number of both aces and cards.

The probability of the first hand receiving one ace is calculated as:

P(E1) = (4/52) * (48/51) * (47/50) * ... * (36/39)

Step 2 : consider the event E2 that the second hand receives exactly one ace, given that the first hand already has one:

With one ace already given to the first hand, there are 3 aces remaining and 39 cards left for the second hand.

The probability is calculated as:

P(E2|E1) = (3/39) * (35/38) * ... * (25/26)

Step 3 : Proceed similarly for the third and fourth hands:

P(E3|E1E2) = (2/26) * ... * (12/13)

P(E4|E1E2E3) = 1 (since only one ace remains for the last hand)

Step 4 : Using the multiplication rule, the overall probability P(E1E2E3E4) is calculated by multiplying the individual probabilities:

P(E1E2E3E4) = P(E1) * P(E2|E1) * P(E3|E1E2) * P(E4|E1E2E3)

Step 5 : After performing the calculations, we find:

The combined probability P(E1E2E3E4) = (4/52)*(3/39)*(2/26)(1/13) after simplifying is approximately 0.105 or 10.5%.

Answer:

Total number of possibilities 2,095,681,645,538.

Step-by-step explanation:

The variables can be 1 to 8 characters long.

The first space can be filled by any of the 26 letters.

The remaining n places can be filled by any of the 26 letters or any of the 10 digits.

For a single character variable the number of ways to select a variable name is,

n (1 character) = 26

For two character variable the number of ways to select a variable name is,

n (2 character) = 26 × 36 = 936

For three character variable the number of ways to select a variable name is,

n (3 character) = 26 × 36 × 36 = 26 × 36² = 33,696

For four character variable the number of ways to select a variable name is,

n (4 character) = 26 × 36 × 36 × 36 = 26 × 36³ = 1,213,056

And so on.

Similarly for the eight character variable the number of ways to select a variable name is,

n (8 character) = 26 × 36 × 36... × 36 = 26 × 36⁷ = 2,037,468,266,496

Total number of possibilities 2,095,681,645,538.

Answer:

A. I Only.

Step-by-step explanation:

To begin, we must first be clear that it is the median and that it is the arithmetic mean:

Median is the middle value of a sequence of ordered numbers, for example:

{4,4,4,4,4}, the median is 4 despite being the same numbers.

Now the arithmetic mean is the average value of the samples and is independent of the amplitudes of the intervals.

Then let's analyze each of our options:

I. At least one of the homes was sold for more than $ 165,000.

We know through the flushed:

X1 + X2 +. . . + X7 + (X8 = $130,000) + X9 +. . . + X15 = 15 ∗ 150,000 = $ 2,250,000

Now we will assume the lowest possible value from X1 to X8 = $ 130,000 and from X9 to X15 = X, which is what we want to calculate. That is to say:

X1 = X2 = X3 = X4 = X5 = X6 = X7 = X8 = 130 and X9 = X10 = X11 = X12 = X13 = X14 = X15 = X,

knowing that the total value must be the average of 15, which is equal to $ 2250000 , we have the following equation:

8 ∗ $ 130,000 + 7X = $ 2,250,000

Rearranging:

X = ($ 2,250,000 $ - $ 1,040,000) / 7

X = $ 172,857

Therefore the first statement is true, because at least one house was sold at $ 172,857 which is more than $ 165,000

Evaluating the second option

II. At least one of the homes was sold for more than $ 130,0000 and less than $ 150,000

As the example of the median in the previous case you could have 8 houses that were sold for $ 130,000 or less, therefore here it loses validity, statement II is false.

Evaluating the third option

III. At least one of the homes was sold for less than $ 130,000.

We know that the eighth house sold for $ 130,000, but houses 1 to 7 may also have been sold for that same price. The statement III is false.

Therefore the answer is A. I Only.

The solution for the equation is [tex]p=\frac{9}{8}[/tex]

Explanation:

The given equation is [tex]p-\frac{1}{4}=\frac{7}{8}[/tex]

We need to solve the equation.

The solution of the equation can be determined by finding the value for p.

Thus, from the equation, let us add both sides of the equation by [tex]\frac{1}{4}[/tex]

Hence, we have,

[tex]p-\frac{1}{4}+\frac{1}{4}=\frac{7}{8}+\frac{1}{4}[/tex]

Simplifying the equation, we get,

[tex]p=\frac{7}{8}+\frac{1}{4}[/tex]

Taking LCM for 4 and 8, we get,

[tex]p=\frac{7+2}{8}[/tex]

Adding the numerator, we have,

[tex]p=\frac{9}{8}[/tex]

Thus, the value of p is [tex]p=\frac{9}{8}[/tex]

Hence, the solution for the equation is [tex]p=\frac{9}{8}[/tex]

The probability of drawing two chips of different colors from the bag is 35/33.

The probability of drawing the chips:

Calculate the total number of ways to draw 2 chips: 12 chips total, so 12C2 = 66 ways.

Calculate the number of ways to draw 2 chips of different colors: (5 blue chips × 7 non-blue chips) + (7 non-blue chips × 5 blue chips) = 70 ways.

Probability = Number of favorable outcomes / Total outcomes = 70/66 = 35/33.

the probability that the two selected chips are of different colors is [tex]\( \frac{94}{144} \), which simplifies to \( \frac{47}{72} \).[/tex]

To find the probability that the two selected chips are of different colors, we can use the concept of complementary probability.

The complementary event of selecting two chips of different colors is selecting two chips of the same color.

Let's calculate the probability of selecting two chips of the same color and then subtract that from 1 to find the probability of selecting two chips of different colors.

1. Probability of selecting two blue chips:

[tex]\[ P(\text{blue, blue}) = \frac{5}{12} \times \frac{5}{12} = \frac{25}{144} \][/tex]

2. Probability of selecting two red chips:

[tex]\[ P(\text{red, red}) = \frac{4}{12} \times \frac{4}{12} = \frac{16}{144} \][/tex]

3. Probability of selecting two yellow chips:

[tex]\[ P(\text{yellow, yellow}) = \frac{3}{12} \times \frac{3}{12} = \frac{9}{144} \][/tex]

Now, let's add these probabilities together because any of these scenarios results in two chips of the same color:

[tex]\[ P(\text{same color}) = P(\text{blue, blue}) + P(\text{red, red}) + P(\text{yellow, yellow}) \]\[ P(\text{same color}) = \frac{25}{144} + \frac{16}{144} + \frac{9}{144} = \frac{50}{144} \][/tex]

Finally, we subtract this probability from 1 to find the probability of selecting two chips of different colors:

[tex]\[ P(\text{different colors}) = 1 - P(\text{same color}) \]\[ P(\text{different colors}) = 1 - \frac{50}{144} = \frac{144}{144} - \frac{50}{144} = \frac{94}{144} \][/tex]

So, the probability that the two selected chips are of different colors is [tex]\( \frac{94}{144} \), which simplifies to \( \frac{47}{72} \).[/tex]

Answer:

a) P ( E | F ) = 0.54545

b) P ( E | F' ) = 0

Step-by-step explanation:

Given:

- 4 Coins are tossed

- Event E exactly 2 coins shows tail

- Event F at-least two coins show tail

Find:

- Find P ( E |  F )

- Find P ( E | F prime )

Solution:

- The probability of head H and tail T = 0.5, and all events are independent

So,

                    P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT)  = 6*(1/2)^4 = 0.375

                    P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)

      = 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875

- The probabilities for each events are:

                    P ( E ) = 0.375

                    P ( F ) = 0.6875

- The Probability to get exactly two tails given that at-least 2 tails were achieved:

                    P ( E | F ) = P ( E & F ) / P ( F )

                    P ( E | F ) = 0.375 / 0.6875

                    P ( E | F ) = 0.54545

- The Probability to get exactly two tails given that less than 2 tails were achieved:

                    P ( E | F' ) = P ( E & F' ) / P ( F )

                    P ( E | F' ) = 0 / 0.6875

                    P ( E | F' ) = 0                

Answer:

(1,-3)

Step-by-step explanation:

the x-axis for A is positive and the y-axis is negative. point A's X value is 1 because it is 1 point away from the origin and the value of the Y is 3 units away from the origin and it has to be negative.

Answer:

Step-by-step explanation:

We would apply the formula for

exponential decay which is expressed as

A = P(1 - r)^t

Where

A represents the population after t years.

t represents the number of years.

P represents the initial population.

r represents rate of growth.

From the information given,

P = 1,450,000

r = 0.99% = 0.99/100 = 0.0099

t = x years

Therefore, an exponential equation to represent this situation after x years is

A = 1450000(1 - 0.0099)^t

A = 1450000(0.9901)^t

23) x = [tex]\frac{-60}{9}[/tex] = -6.666.

24) x = [tex]\frac{-12}{7}[/tex] = -1.7142.

25) x = [tex]\frac{-37}{5}[/tex] = -7.4.

Step-by-step explanation:

Step 1; For [tex]\frac{x+6}{3}[/tex] = [tex]\frac{x+4}{12}[/tex], we cross multiply the denominators and get,

3 × (x + 4) = 12 × (x + 6),

3x + 12 = 12x + 72.

We take all the x terms to the LHS and keep the constants on the RHS.

3x - 12x = 72 - 12,

-9x = 60, x = [tex]\frac{-60}{9}[/tex] = -6.6666.

Step 2; For [tex]\frac{-5}{x-4}[/tex] = [tex]\frac{9}{x+12}[/tex], we cross multiply the denominators and get,

-5 × (x + 12) = 9 × (x - 4),

-5x - 60 = 9x - 36.

We take all the x terms to the LHS and keep the constants on the RHS.

-5x - 9x = -36 + 60,

-14x = 24, x = [tex]\frac{-24}{14}[/tex] = -1.7142.

Step 3; For [tex]\frac{6}{11}[/tex] = [tex]\frac{x-1}{x-8}[/tex], we cross multiply the denominators and get,

6 × (x - 8) = 11 × (x - 1),

6x - 48 = 11x - 11.

We take all the x terms to the LHS and keep the constants on the RHS.

6x - 11x = -11 + 48,

-5x = 37, x = [tex]\frac{-37}{5}[/tex] = -7.4.

Answer:

(a) [tex]P(X < 12)=0.26[/tex]

(b) [tex]P(X=2)=0.15[/tex]

Step-by-step explanation:

Question a

This is a Poisson distribution. The average/mean, μ = 14

So, probability that fewer than 12 field mice are found on a given acre is:

[tex]P(X < 12) = e^{-14}(\frac{14^{0}}{0!} +\frac{14^{1}}{1!} + \frac{14^{2}}{2!} + \frac{14^{3}}{3!} +\frac{14^{4}}{4!} + \frac{14^{5}}{5!} +\frac{14^{6}}{6!}+\frac{14^{7}}{7!}+\frac{14^{8}}{8!} +\frac{14^{9}}{9!}+\frac{14^{10}}{10!}+\frac{14^{11}}{11!})\\ \\P(X < 12) = e^{-14}(1+14+98+457.33+1600.67+4481.87+10457.69+20915.38+36601.91+56936.31+79710.83+101450.15)\\\\P(X < 12) = 8.315*10^{-7}(312725.1248)=0.26 \\\\P(X < 12)=0.26[/tex]

Question b

This is a Binomial distribution with:

Probability of success, p = 0.26

n = 3

[tex]P(X=2)= (3C2)p^{2}(1-p)=\frac{3!}{2!(3-2)!}*(0.26^{2})*(1-0.26)\\ \\P(X=2)=3(0.0676)(0.74)=0.15\\\\P(X=2)=0.15[/tex]

Final answer:

To find the probability that fewer than 12 field mice are found on a given acre and on 2 of the next 3 acres inspected, use the cumulative distribution function (CDF) of the Poisson distribution and the binomial distribution.

Explanation:

To find the probability that fewer than 12 field mice are found on a given acre, we need to use the cumulative distribution function (CDF) of the Poisson distribution. The average number of field mice per acre is 14, so the parameter of the Poisson distribution is also 14.

(a) To find the probability that fewer than 12 field mice are found on a given acre, we calculate P(X < 12) = P(X = 0) + P(X = 1) + P(X = 2) + ... + P(X = 11), where X is the number of field mice found on a given acre

(b) To find the probability that fewer than 12 field mice are found on 2 of the next 3 acres inspected, we calculate P(X < 12) for each acre and use the binomial distribution to determine the probability of 2 successes out of 3 trials.

Answer:

y = 3.6(sine( 6.2(x-4.2))+4.4

Step-by-step explanation:

(8.2-.6)/2 = altitude = 3.6

6.2 = Wavelength

(8.2+.6)/2 = 4.4 The "line" (the horizontal central line thingy whose name I forgot cuz it's 12:00)

4.2 = x shift

y = 3.6(sine( 6.2(x-4.2))+4.4

Answer: 2.1 feet

Step-by-step explanation:

The ladder forms a right angle triangle with the wall and the ground. The length of the ladder represents the hypotenuse of the right angle triangle. The height from the top of the ladder to the base of the wall represents the opposite side of the right angle triangle.

The distance, d from the bottom of the ladder to the base of the wall represents the adjacent side of the right angle triangle.

To determine the distance, d from the bottom of the ladder to the base of the wall, we would apply we would apply the cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 65 = d/5

d = 5Cos 65 = 5 × 0.4226

d = 2.1 feet

In a cyclic quadrilateral ( a quadrilateral that is inscribed in a circle),

opposite angles add up to 180 degrees. So you can form an equation and solve for x, and thus angle E.

Therefore:

(-2 + 6x) + (7x - 13) = 180

13x - 15 = 180

13x = 195

x = 15

So angle E = 5x

                 = 5 (15)

                 = 75 degrees

Answer: $406

Step-by-step explanation:

Answer: she earned $406 last week.

Step-by-step explanation:

Last week, she worked 2 hours on Monday, 10 hours on Tuesday, and 9 hours on Wednesday. This means that the number of hours that she worked for the first three days is

2 + 10 + 9 = 21 hours

She had Thursday off, and then she worked 8 hours on Friday. Therefore, the total number of hours that she worked for the week is 21 + 8 = 29 hours.

If Nanette earns $14 per hour, then the total amount of money that Nanette earned in all last week is

29 × 14 = $406

Answer:

Step-by-step explanation:

What is the question

Answer:

D

Step-by-step explanation:

Answer:

Pressure would be approximately 4.66 pounds.

Step-by-step explanation:

Given:

Volume of gas (V) = 25 cubic cm

Pressure of the  gas (P) = 11 pounds

We need to find the pressure when volume is 59 cubic cm.

Solution:

Now Given:

[tex]V[/tex] ∝ [tex]\frac{1}{P}[/tex]

so we can say that;

[tex]V =\frac kP[/tex]

where k is a constant.

When V = 25 cubic cm, P =11 pounds.

[tex]25 = \frac{k}{11}\\\\k= 25\times 11 = 275\ cm^3.pounds[/tex]

So the equation becomes as.

[tex]V = \frac{275}{P}[/tex]

Now we need to find the pressure when Volume is 59 cubic cm.

[tex]59 =\frac{275}{P}\\\\P=\frac{275}{59}\\\\P\approx 4.66\ pounds[/tex]

Hence Pressure would be approximately 4.66 pounds.

What is the volume of a cylinder, in cubic m, with a height of 5m and a base diameter of 20m? Round to the nearest tenths place.

Answer: 1570.8

The volume of a cylinder with a height of 5m and a base diameter of 20m is approximately 1,570.8 cubic meters when rounded to the nearest tenths place.

To find the volume of a cylinder with a height of 5m and a base diameter of 20m, we will use the formula for the volume of a cylinder: V = πr²h , where V is volume, r is the radius of the base, and h is the height of the cylinder. The radius is half of the diameter, so for a diameter of 20m, the radius is 10m. Substituting these values into the formula gives us V = (π × 10² × 5), which we can calculate as V = 3.1416 × 100 × 5 = 1,570.8 cubic meters, rounded to the nearest tenths place.

Answer:It depends

Step-by-step explanation:

To solve the equation sin 2x - sin 4x = 0, we apply the identity for the difference of two sines and set each term equal to zero. The solutions in the interval [0, 2π) are x = 0, π/6, 5π/6, π.

The equation given is sin 2x - sin 4x = 0. To find the solutions to this equation in the interval [0, 2π), we can use the trigonometric identity for the difference of two sines, sin A - sin B = 2 sin((A - B)/2) cos((A + B)/2). Applying this identity:

2 sin(-2x/2) cos(6x/2) = 0
2 sin(-x) cos(3x) = 0

Since sin(-x) = -sin(x), we can rewrite the equation further:

-2 sin(x) cos(3x) = 0

To find the solutions, set each part equal to zero:

sin(x) = 0

cos(3x) = 0

For sin(x) = 0, the solutions in [0, 2π) are x = 0, π, 2π. However, since the interval is [0, 2π), 2π is not included.

For cos(3x) = 0, the solutions are x = π/6, 5π/6 since cos(x) has a period of 2π and 3x adds additional repetitions of the solutions in the interval.

The complete set of solutions in the interval [0, 2π) are therefore:

0

π/6

5π/6

π

Answer: kg*m^2 / s^3

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Answer:

Answer: kg*m^2 / s^3

Step-by-step explanation: