A carpet cleaner charges $0.70 per square foot to clean carpet. In the next house she is going to clean, the living room measures 18 feet by 24 feet. How much will she charge?

Answers

Answer 1

18 * 24 equals something that should be right then you times that by 0.70 square foot to clean the carpet and then you're going to get your total so the charge would be a number that's all I have for you today

Answer 2

Answer:

$302.4

Step-by-step explanation:

We are given that a carpet cleaner charges $0.70 per square foot to clean carpet.

She needs to clean a room measuring 18 feet by 24 feet and we are to calculate how much will she charge for it.

Area of the room = [tex] 1 8 \times 2 4 [/tex] = 432 square feet

Amount she will charge = [tex] 4 3 2 \times 0 . 7 0 [/tex] = $302.4


Related Questions

Which side of DEF is longest?

Answers

Answer:

A. DE

Step-by-step explanation:

The side opposite the angle with the largest measure is the longest

<F has a measure of 72, so it is the largest angle and DE is opposite <F

Side DE is the longest

A line passes through the points (2,4) and (-4,-1). Find its equation in slope-intercept form. (2 points, 1 for work, 1 for equation)

Answers

Hello!

The answer is:

The equation of the line in slope-intercept form:

[tex]y=\frac{5}{6}x+\frac{7}{3}[/tex]

Why?

To find the equation in slope-intercept form, we need to follow the next steps:

Find the slope of the line:

Using the slope formula, we have:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

We are given the points:

[tex](2,4)\\(-4,-1)[/tex]

So, substituting we have:

[tex]m=\frac{(-1)-(4)}{-4-2}[/tex]

[tex]m=\frac{-5}{-6}[/tex]

[tex]m=\frac{5}{6}[/tex]

Find the "b" value:

Now that we know the value of the slope, we can write the equation of the line:

[tex]y=\frac{5}{6}x+b[/tex]

In order to find "b" we need to substituite any of the given points, we know that line is thru both of the given points, so, substituting (2,4) we have:

[tex]4=\frac{5}{6}*2+b\\\\4=\frac{10}{6}+b\\\\4=\frac{5}{3}+b\\\\b=4-\frac{5}{3}=\frac{(3*4)-5}3}=\frac{12-5}{3}=\frac{7}{3}[/tex]

Now that we know the slope and "b", we can write the equation of the line in slope-intercept form:

[tex]y=\frac{5}{6}x+\frac{7}{3}[/tex]

Have a nice day!

2.15a+0.03∙(3.4a−12a)

Answers

1.892a is the correct answer

The expanded form of the expression 2.15a+0.03∙(3.4a−12a) is 2.252a - 0.36

Factoring an expression

Given the following expression

2.15a+0.03∙(3.4a−12a)

Open the parenthesis

2.15a+0.03∙(3.4a) −0.03(12a)

2.15a+ 0.102a - 0.36

Simplify

2.252a - 0.36

Hence the expanded form of the expression 2.15a+0.03∙(3.4a−12a) is 2.252a - 0.36

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Please help me ASAP I’ll give 25 points to whoever gets it right!!!

Answers

Answer:

Step-by-step explanation:

The general equation is y = a*b^x

The specific equation is

100000 = 78918 * 1.06^x

y is the goal (100000 people)

a is the beginning number of people at the time the prize is offered.

a = 78918

b = the base increase per year. (1.06 in this case)

x is the number of years. Just for fun, let's solve for x even though you are not asked for it.

100000 = 78918 * 1.06^x  Divide both sides by 78918

100000/78918 = 1.06^x

1.26713 = 1.06^x                Take the log of both sides.

log(1.26713) = x * log(1.06) Divide both sides by log(1.06)

log(1.26713)/log(1.06) = x

x = 4.06 years.

What the mass of an encyclopedia grams or kilograms?

Answers

Answer:

kilograms

Step-by-step explanation:

The graph of the function f(x)=6/x-3 is shown below

Answers

Answer:

[tex]x=3[/tex]

Step-by-step explanation:

we know that

The vertical asymptote occur when the denominator of the function f(x) is equal to zero.

we have

[tex]f(x)=\frac{6}{x-3}[/tex]

so

[tex]x-3=0[/tex]

[tex]x=3[/tex]-----> is the vertical asymptote

Answer: 3

Step-by-step explanation:

The red line goes through it

Simplify the following expression (3x^2y)^3

Answers

Answer:

[tex]\large\boxed{\left(3x^2y\right)^3=27x^6y^3}[/tex]

Step-by-step explanation:

[tex]\text{Use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\\left(3x^2y\right)^3=3^3(x^2)^3y^3=27x^6y^3[/tex]

20 points!!! plz help asap
Suppose 10% of the flights arriving at an airport arrive early, 60% arrive on time, and 30%
arrive late. Valerie used the random-number table to find the experimental probability that of 5
flights, at least 2 will arrive late. The digit 0 represents flights arriving early. The digits 1,2,3,
4, 5, and 6 represent flights arriving on time. The digits 7, 8, and 9 represent flights arriving
late. Find the experimental probability that of 5 flights at least 2 will arrive late.
A: 3/10
B:2/5
C: 9/20
D: 11/20

Answers

Answer:

D. 11/20

Step-by-step explanation:

7, 8, and 9 represent late flights.  We want to count how many of the 20 trials have at least two of these digits.  Counting, we find that 11 of the 20 have at least two of these digits.

D. 11/20

Select the correct answer. If f(x)=2-x^1/2 and g(x)=x^2-9 , what is the domain of g(x) ÷ f(x)

Answers

Answer:

the domain of g(x) ÷ f(x) is :D = ]-∞ ; 4[U] 4 ; +∞[

Step-by-step explanation:

g(x) ÷ f(x) exist for : 2-x^1/2 ≠ 0

 2-x^1/2 = 0

  x^1/2 = 2

  (x^1/2)² = 2²

x = 4

the domain of g(x) ÷ f(x) is :D = ]-∞ ; 4[U] 4 ; +∞[

ANSWER

[0,4) U (4,+∞)

EXPLANATION

The given functions are:

[tex]f(x)=2- \sqrt{x} [/tex]

and

[tex]g(x) = {x}^{2} - 9[/tex]

We want to find the domain of:

[tex] g(x) \div f(x) = \frac{ {x}^{2} - 9}{2 - \sqrt{x} } [/tex]

This function is defined for:

[tex]2 - \sqrt{x} \ne0[/tex]

[tex]2 \ne \: \sqrt{x} [/tex]

Square both sides,

[tex] {2}^{2} \ne \: ({\sqrt{x}})^{2} [/tex]

[tex]4 \ne \: x[/tex]

Also [tex] x\:\ge0[/tex]

Therefore the domain is

[0,4) U (4,+∞)

if John has 5 apples and gives away 3 how many apples does he have?​

Answers

if this is some kind of riddle then i think its 5

2 apples left? I think that’s what it is

Solve the equation. x – 2 = 7

Answers

Answer:

x=9

Step-by-step explanation:

x – 2 = 7

Isolate the variable, x.

x-2+2=7+2

x=9

x=9

Answer: [tex]x=9[/tex]

Step-by-step explanation:

Given the equation [tex]x-2=7[/tex], you need solve for the variable "x", to do this, you need to remember the Addition property of equality, which states that:

[tex]If\ a=b,\ then\ a+c=b+c[/tex]

Therefore, add 2 to both sides of the equation to calculate the value of the variable "x", then you get the following result:

[tex]x-2+(2)=7+(2)[/tex]

[tex]x=9[/tex]

Jovie is maintaining a camp fire. She has kept the fire steadily burning for 10 hours with 15 logs. She wants to know how many hours (h) she could have kept the fire going with 9 logs. She assumes all logs are the same.
How many hours can Jovie keep the fire going with 9 logs?

Answers

It is would last for 6 hours.

Lily designed a deck in her backyard that looks like a quadrilateral that has only 1 pair of parallel sides. How can you classify the figure?

The quadrilateral is a _____________.

Answers

A quadrilateral with one pair of parallel sides is a trapezoid

Final answer:

A quadrilateral with only one pair of parallel sides can be classified as a trapezoid, which is a distinct type of four-sided figure unlike rectangles or squares.

Explanation:

The quadrilateral Lily designed, with only one pair of parallel sides, can be classified as a trapezoid. In geometry, this kind of shape is distinct from others we learn about in elementary levels, such as squares and triangles. A trapezoid is a four-sided figure, which makes it a type of quadrilateral but not all sides are parallel like in a rectangle or a square.

The defining feature of a trapezoid is that it has at least one set of parallel sides, known as the bases, while the other sides, which are not parallel, are referred to as the legs. Because it only has one pair of parallel sides, it differs from other quadrilaterals like rectangles, squares, and parallelograms, which have two pairs of parallel sides. The non-parallel sides of a trapezoid can be of different lengths and angles to each other, which can make trapezoids quite diverse in shape and size.

Determine the domain of the function h=9x/x(x^2-49)

Answers

ANSWER

[tex]( - \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , + \infty )[/tex]

EXPLANATION

The given function is

[tex]h(x) = \frac{9x}{x( {x}^{2} - 49) } [/tex]

This function is defined for values where the denominator is not equal to zero.

[tex]x( {x}^{2} - 49) \ne0[/tex]

[tex]x(x - 7)(x + 7) = 0[/tex]

The domain is

[tex] x \ne - 7, x \ne0, \: and \: x \ne 7,[/tex]

Or

[tex]( - \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , + \infty )[/tex]

Final answer:

The domain of the function h=9x/x(x^2-49) is x = -7, x = 7.

Explanation:

The domain of the function h = 9x/(x(x^{2}-49)) can be determined by considering the values of x that make the denominator non-zero. Since division by zero is undefined, we need to find the values that would make the denominator equal to zero. In this case, the denominator is x(x^{2}-49), which factorizes to x(x+7)(x-7). So, the values of x that make the denominator equal to zero are x=0, x=-7, and x=7.

However, we also need to consider that the function is undefined when cancelling out those values of x that would also make the numerator zero. In this case, x=0 would make the numerator zero, so it cannot be a part of the domain.

Therefore, the domain of the function h = 9x/(x(x^{2}-49)) is given by x = -7, x = 7.

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if point (-1,0) is on the line whose equation is y=2x+b what is the value of b? show your work and explain) A. 1 B. 2 C. 3 D. 0​

Answers

[tex]\bf y=2x+b~~\hspace{8em} (\stackrel{x}{-1},\stackrel{y}{0})~\hspace{8em} 0=2(-1)+b \\\\\\ 0=-2+b\implies 2=b[/tex]

To find the value of b plug in the point (-1,0) into the known part of the equation ( y = 2x + b ) and solve for b

0 = 2(-1) + b

0 = -2 + b

To isolate b add 2 to both sides (addition of 2 will make -2 zero and cancel it from the right side and bring it to the left)

0 + 2 = (-2 + 2) + b

2 = 0 + b

2 = b <------------------------B. 2

Hope this helped!

Write and solve an equation to find the measurements of acute angle npo

Answers

Final answer:

We can solve for an acute angle in a right triangle if we know the other two angles. In the given hypothetical example, we assumed one angle was 30 degrees and the other was 90 (a right angle). We then subtracted these angles from 180 (the sum of all angles in a triangle) to find the acute angle NPO.

Explanation:

To solve for the acute angle NPO, we would typically need more specific information about the properties of the figure in question. However, let's suppose that triangle NPO is a right triangle and one of the given angles is 30 degrees. In this case, we can use the knowledge that the sum of all angles in a triangle equals 180 degrees.

Therefore, we set up an equation: 30 (degree of the given angle) + 90 (degree of the right angle) + X (angle NPO to be found) = 180. Solving for X gives us that NPO = 180 - 30 - 90 = 60 degrees.

Please remember that solving for an acute angle typically requires specific information about the figure and not all problems are as simple as this example demonstrates.

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A linear pair involves adjacent angles formed when two lines intersect. In this context, <NPO is 40°, and <SPR is 50°, adhering to the linear pair property.

A linear pair is formed when two lines intersect at a single point, creating two adjacent angles. If these angles align in a straight line, they constitute a linear pair, and the sum of their measures is always 180°. These angles are often termed supplementary or additional angles.

In the given scenario, angle <QPO is provided as 140°. According to the linear pair property, the angle <NPO supplementary to <QPO forms a straight line, and their sum equals 180°. Therefore, <NPO is calculated as 180° - 140°, resulting in <NPO being 40 degrees.

Moving on to the second part, three angles <SPN, <SPR, and <RPQ are considered. Applying the linear pair property, the sum of these angles is 180°. Given that <SPN is 90° and <RPQ is already known as 140°, the calculation involves finding <SPR. Thus, 90° + <SPR + 40° equals 180°. Solving for <SPR, it is determined to be 50 degrees.

In summary, for the provided angles:

a) <NPO is found to be 40 degrees.

b) <SPR is determined as 50 degrees through the linear pair property.

The question probable may be:

7.What is the measure of Angle NPO?

8.What is the measure of Angle SPR if the measure of Angle RPQ is 40°?

Find all solutions in the interval [0, 2π).

4 sin2 x - 4 sin x + 1 = 0

Answers

ANSWER

[tex]x = \frac{\pi}{6} \: or \: x = \frac{5\pi}{6} [/tex]

EXPLANATION

The given trigonometric equation is

[tex]4 \sin ^{2} x - 4 \sin(x) + 1 = 0[/tex]

This is a quadratic equation in sinx.

We split the middle term to obtain,

[tex]4 \sin ^{2} x - 2 \sin(x) - 2 \sin(x) + 1 = 0[/tex]

Factor by grouping to get,

[tex]2 \sin(x) (2 \sin(x) - 1) - 1(2 \sin(x) - 1) = 0[/tex]

This implies that,

[tex](2 \sin(x) - 1)(2 \sin(x) - 1) = 0[/tex]

[tex] \sin(x) = 0.5[/tex]

This gives us,

[tex]x = \frac{\pi}{6} [/tex]

in the first quadrant.

Or

[tex]x = \pi - \frac{\pi}{6} [/tex]

[tex]x = \frac{5\pi}{6} [/tex]

in the second quadrant.

Answer:

x = [tex]\frac{\pi}{6}[/tex], [tex]\frac{7\pi}{6}[/tex],  [tex]\frac{11\pi}{6}[/tex].

Step-by-step explanation:

The given equation is 4 sin²x - 4 sin x + 1 = 0

(2sinx)² - 2(2sinx) + 1 = 0

(2sinx - 1 )² = 0

Sinx = [tex]\frac{1}{2}[/tex] ⇒ x = sin⁻¹ ( [tex]\frac{1}{2}[/tex])

So between the interval [0, 2π] value of x will be  [tex]\frac{\pi}{6}[/tex],  [tex]\frac{7\pi}{6}[/tex],  [tex]\frac{11\pi}{6}[/tex]

[Since sine is positive in 1st 3rd and 4th quadrant]

So value of x will be x =  [tex]\frac{\pi}{6}[/tex], [tex]\frac{7\pi}{6}[/tex],  [tex]\frac{11\pi}{6}[/tex].

If xy = 1, which is equivalent to x(x – 1)(y + 1)?
A) x – 1
B) x2 – 1
C) x2 – x
D) x2 – x + y – 1

Answers

Answer:

B) x^2 – 1

Step-by-step explanation:

x(x – 1)(y + 1)

FOIL (x-1)(y+1)

firsy: xy

outer 1x

inner -1y

last (1)(-1) =-1

Add them together  xy +x-y-1

x( xy +x-y-1)

Replace xy with 1

x( 1+x-y-1)

x(+x-y)

Distribute

x^2-xy

But xy=1

x^2 -1

A middle school basketball team won 36% of the games it played last season. the team won exactly 9 games last season. what is the total number of games that the team played? explain how you got your answer​

Answers

9 games equals 36 percent of x number of total games.

9=(36/100)x

Multiply both sides by (100/36) to isolate x.

9*(100/36)=x

x=25 total games

HELP WILL MARK BRAINLIEST 72.74mm = blank m

Answers

Answer:

.074 I believe

Step-by-step explanation:

1 meter = 1000 millimeters, so set an equal proportion. x / 72.74mm = 1m / 1000mm. Cross multiply to get 1000x = 72.74; divide both sides by 1000 to get x = 0.07274 m or if you're rounding, 0.07m

Which transformation is shown in the line of music?
elide reflection
he
reflection
rotation
translation

Answers

Answer:

Translation and a rotation 90 degrees

Step-by-step explanation:

The perimeter of a rectangular yard is 316 ft. The width of the yard is 100 ft. What is the area of the yard?

Answers

................. ...............

area of rectangle is 5800.

Today, there were 2 members absent from the band. The present members folded 25 programs each, for a total of 525 programs.
What question does the equation 525=25(x-2), help answer?
Choose 1 answer:

Answers

The equation [tex]\(525=25(x-2)\)[/tex] helps answer option (C): How many members are in the band when no one is absent?

let's break it down step by step:

1. Define variables: Let [tex]\(x\)[/tex] represent the total number of members in the band.

2. Calculate members present: Since 2 members were absent, the number of members present is [tex]\(x - 2\).[/tex]

3. Programs folded by each member: We know that each present member folded 25 programs.

4. Total programs folded: To find the total number of programs folded, we multiply the number of present members by the number of programs each member folded. So, the total programs folded is \(25(x-2)\).

5. Set up equation: We are given that the total number of programs folded is 525. So, we set up the equation:

[tex]\[ 25(x-2) = 525 \][/tex]

6. Solve for [tex]\(x\):[/tex] By solving this equation, we can find the value of [tex]\(x\),[/tex]which represents the total number of members in the band when no one is absent.

So, the equation [tex]\(525=25(x-2)\)[/tex] helps us determine how many members are in the band when no one is absent. This aligns with option (C).

Complete Question:

Simplify this expression 13+(-12)-(-5)

Answers

The answer is 6

Explaination:

Step-by-step explanation:

(-)(-) = (+)(+) = (+)

(-)(+) = (+)(-) = (-)

13 + (-12) - (-5) = 13 - 12 + 5 = 1 + 5 = 6

HELP PLEASE
Use elimination to solve the system of equations
2x + 3y = 9
x + 5y = 8

Answers

Answer:

y=5/7   x=31/7

Step-by-step explanation:

Make the x values the opposite of each other:

-2(x+5y=8)

-2x-10y=-16

2x+3y=9

Combine like terms and solve for y:

-7y=-5

y=5/7

Plug y in to find x.

x+5(5/7)=8

x+25/7=8

56/7-25/7=x

x=31/7

93 27 14 what is next in the sequence?

Answers

The next term in the given sequence is 4

Sequence and series

Given the sequence of values

93 27 14

The product of the two digits of each term will give the subsequent term. From the sequence given for instance;

93 = 9 * 3  = 27 (next term)

27 = 2 * 7 = 14 (3rd term)

For the next term;

14 = 1 * 4 = 4 (This will given the next term in the sequence)

Hence the next term in the sequence is 4

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Final answer:

Without additional context or a defined pattern, it's not possible to definitively determine the next number in the sequence 93, 27, 14. The sequence could potentially be arithmetic, geometric, quadratic, or even something more complex, but with only three terms provided, it's not possible to identify a clear pattern.

Explanation:

The given sequence in the question is 93, 27, 14. The solution to this sequence isn't immediately clear, as a standard mathematical pattern - such as addition, subtraction, multiplication, or division - doesn't seem to apply across all elements. Unfortunately, without additional context or a defined pattern to follow, it's not possible to definitively determine the next number in the sequence. Sequences can follow a vast array of potential patterns, including (but not limited to) geometric sequences, arithmetic sequences, quadratic sequences, or even patterns that incorporate elements of probability, set theory, or number theory.

For example, if we were looking for a simple arithmetic pattern in the given sequence, an initial glance might suggest that we are subtracting 66 and then 13 to find the second and third terms respectively. However, continuing this pattern does not result in a logical (-1) for the 'fourth' term in the sequence.

The sequence could also potentially be following a more intricate pattern - it could be geometric (each term multiplied or divided by a consistent number), quadratic (based on square or cube numbers), or even something more complex. However, with only three terms provided, it's not possible to identify a clear pattern of this nature.

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In the diagram, AB is parallel to DE. Also, DE is drawn such that the length of DE is half the length of AB. If sin A = 0.5, then what is sin E?


A) 2
B) 1
C) 0.5
D) 0.25
E) 0.1

Random answers will be reported!

Answers

I believe it is C, there is a geometric law that states that the opposite angles across a line with both going into parallel lines will be the same angle. Rather confusing but a video online would likely explain it better than anyone could here.

Answer:

Option C. 0.5

Step-by-step explanation:

In the given diagram, AB is parallel to DE, and line AE is the transverse.

So ∠DEF ≅ ∠FAB [ Alternate angles ]

and ∠EFD ≅ AFB ≅ 90° [ Vertically opposite angles ]

So, Third angle of the triangles will also be equal.

Since angles DEF and FAB are equal so their sine values will also be equal.

Therefore, sinA = sinE = 0.5

Option C). 0.5 will be the answer.

wright in standard notation for 5,000,000
, 0.001394,
8,900,000. and
0.000005​

Answers

Answer:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10

. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

5×106 this is for 5,000,000

Step-by-step explanation:

Isabella has 2 1/4 oranges. Colleen has 3 1/4 oranges. How many all together?

Answers

The answer is 5 1/2.

Answer:

There are 5 1/2 oranges altogether.

Step-by-step explanation:

The 2 and 3 in front of each fraction indicate that there are a total of 5 whole oranges altogether. Now we have to settle these fractions. the 1/4 and the 1/4 both have a common denominator so there is no need to find one. When the common denominator is found, we simply have to add the numberators on the top of the fraction. 1+1 is 2, and, since the denominator stays the same, we should get a total of 2/4. I am unsure as to whether you were asked to simplify your answer (if you weren't you could keep your answer like this), but if you were to simplify the answer, both the numerator and denominator of our total can be divided by 2, so when that is done, we have a simplified total of 1/2. Take that 1/2 of an orange and add it to our 5 whole oranges, and we should get our answer of 5 1/2 oranges in total.

HELPPPPPPPPPP Add & subtract matrices .....

PLZ GIVE THE ANSWER .. THANKSSSSS .

Answers

For this case, we must subtract the given matrices, for this we subtract term to term.

So, we have:

Equal signs are added and the same sign equals:

[tex]\left[\begin{array}{ccc}-2-2\\-2-1\\1-1\end{array}\right][/tex]=

[tex]\left[\begin{array}{ccc}-4\\-3\\0\end{array}\right][/tex]

ANswer:

[tex]\left[\begin{array}{ccc}-4\\-3\\0\end{array}\right][/tex]

Answer:

[tex]\left[\begin{array}{ccc}-4\\-3\\0\end{array}\right][/tex]

Step-by-step explanation:

Given in the question two matrix, a matrix can only be added to (or subtracted from) another matrix if the two matrices have the same dimensions.

Here the dimensions are 3x1 and 3x1 .

[tex]\left[\begin{array}{ccc}-2\\-2\\1\end{array}\right][/tex]-[tex]\left[\begin{array}{ccc}-2\\1\\1\end{array}\right][/tex]

To subtract two matrices, just subtract the corresponding entries

=[tex]\left[\begin{array}{ccc}-2-2\\-2-1\\1-1\end{array}\right][/tex]

=[tex]\left[\begin{array}{ccc}-4\\-3\\0\end{array}\right][/tex]

Other Questions
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