Answer:
Answer one: the parent function has been translated to the left
Answer tw: the parent function has been translated down
Answer three: the parent function has been compressed
Which function f (x) , graphed below, or g (x) , whose equation is g (x) = 3 cos 1/4 (x + x/3) + 2, has the largest maximum and what is the value of this maximum?
f(x), and the maximum is 3.
g(x), and the maximum is 5.’
f(x), and the maximum is 2.
g(x), and the maximum is 2.
Answer:
Second option
g(x), and the maximum is 5.’
Step-by-step explanation:
In the graph it can easily be seen that the maximum value reached by the function f(x) is y = 3.
Then, the function g (x) is:
[tex]g(x) = 3cos(\frac{1}{4}(x + \frac{1}{3}x)) + 2[/tex]
By definition the function
[tex]y = cos(x)[/tex] reaches its maximum value when x = 0, [tex]2\pi[/tex], [tex]4\pi[/tex], ..., [tex]2k\pi[/tex]
So
When [tex](\frac{1}{4}(x + \frac{1}{3}x)) = 0[/tex] entonces [tex]cos((\frac{1}{4}(x + \frac{1}{3}x)) = 1[/tex].
Thus:
[tex]g(0) = 3(1) + 2\\\\g(0) = 5[/tex].
Therefore the function that has the greatest maximum is g(x) when [tex]g(x) = 5[/tex]
The answer is the second option
Line CD passes through (0, 1) and is parallel to x + y = 3. Write the standard form of the equation of line CD. x + y = 1 x – y = 1 x + 1 = y x + y = 11
ANSWER
x+y=1
EXPLANATION
We want to find the equation of line CD which passes through (0, 1) and is parallel to x + y = 3.
In slope intercept form, the given line is
y=-x+3
The slope of this line is m=-1
Line CD also has the same slope
The equation is given by:
y=mx+b
The given point (0,1) means the y-intercept;is b=1
Hence the equation is
y=-x+1
In standard form the equation is:
x+y=1
Answer:
The answer is x + y = 1
Step-by-step explanation:
Given: Line CD passes through (0, 1) and is parallel to x + y = 3.
We know that if two line are parallel then they have equal slopes.
Thus, the slope of line = slope of line x + y = 3
x + y = 3 when we compare this to the standard linear equation
= 3 - x
y = m x + c .we get m = -1 .
The slope of CD (m)= -1
Now, the equation of line CD passing through (0,1) is given by :-
( y - 1 ) = m ( x - 0 )
⇒ ( y - 1 ) = ( -1 ) x
⇒ x + y = 1
The equation of line CD = x + y = 1
Please help me asap! In an election, 2/5 of the voters voted for a new school tax. What is the probability that a randomly selected voter did not vote for the tax? Express your answer as a percentage.
a. 40%
b. 6%
c. 60%
d. 4%
Answer:
the answer is c 60%, may i have brainlyiest
Final answer:
To find the probability that a voter did not vote for a new school tax when 2/5 did, subtract 2/5 from 1 to get 3/5, then convert to a percentage to get 60%.
Explanation:
In the given problem, we know that 2/5 of the voters voted for a new school tax. To find the probability that a randomly selected voter did not vote for the tax, we need to calculate the fraction of those who did not vote for the tax. Since the total probability must be 1 (or 100%), those who did not vote for the tax would account for the remaining fraction of 1 - 2/5, which is 3/5. To express this as a percentage, we convert 3/5 into a decimal and then into a percentage.
First, calculate 3/5 as a decimal: 3/5 = 0.6. Then, to convert it to a percentage, multiply by 100: 0.6 × 100 = 60%.
Therefore, the probability that a randomly selected voter did not vote for the new school tax is 60%, which corresponds to answer choice c. 60%.
New Question, I'll offer 40 points again. Please help me if you can. Thank you!!! Which statement best describes the association between variable X and variable Y?
A) moderate positive association
B) weak positive association
C) weak negative association
D) moderate negative association
Answer:
C) weak negative association
Step-by-step explanation:
As X increases, Y generally decreases. So this is a negative association. Because the points are widely scattered, it is also a weak association. So the answer is C.
the answer is c because the graph is going down
Find an equation of a line that comes close to the points listed in below. Then use a graphing calculator to check that your line comes close to the points.
x (2,4,5,6,8)
y (12,10,6,6,1)
A.
y = 2 x + 2
B.
y = negative 2 x + 17
C.
y = negative 2 x + 18
D.
y = negative 1.3 x + 15
Answer:
Option B: y = -2x + 17.
Step-by-step explanation:
Lets calculate values for option B:
x = 2 , y = -4+17 = 13 ( B gives the value 12)
x = 4, y = -8+17 = 9 (10)
x = 5, y = -10+17 = 7 (6)
x = 6, y = -12+17 = 5 (6)
x = 8, y = -16+17 =- 1 (1)
Sum of the differences = 1 + 1 + 1 + 1 = 4.
These values are close to the ones given in the question.
Option A y = 6, 10, 12, 14, 18 - some of the values of y are a lot different than the given values.
Option C:
Working them out we get y = 14, 10, 8, 6, 2. which are not quite as good as Option B values The total difference is 5 compared with 4 for option B.
Option D.
y = 12.4, 9.8, 8.5, 7.2, 4.6 where some of the differences are large.
In the straightedge and compass construction of the parallel line below, which of the following reasons can you use to prove that CD and EG are parallel?
A. ∠FCD ≅ ∠FDC by construction
B. ∠FEG≅ ∠FGE by construction
C. ∠FCD ≅ ∠GEC by construction
D. ∠FEG ≅ ∠FCD by construction
Answer:
D.
Step-by-step explanation:
Lines EG and CD are cut by transversal CF.
By construction, ∠FEG=∠FCD. These two angles are corresponding angles.
Since two corresponding angles are congruent, then lines EG and CD are parallel (by converse of the corresponding angles postulate).
Converse of the Corresponding Angles Postulate: If the corresponding angles formed by two lines and a transversal are congruent, then lines are parallel.
Cathy has a nickel, a dime, and a quarter in her purse. She randomly picks a coin, replaces it, and then picks another coin. The probability that the two coins are of different denominations is .
SOMEONE HELP PLEASE THIS IS FOR PLATO.
Hence, the probability that the two coins are of different denomination is:
2/3
Step-by-step explanation:Let N denote nickel, D denotes dime and Q denotes Quarter.
Now when two coins are drawn one after the other with replacement then the outcomes is given by:
(N,N) (N,D) (N,Q)
(D,N) (D,D) (D,Q)
(Q,N) (Q,D) (Q,Q)
This means that there are a total of 9 outcomes.
The outcomes such that both the denominations are different i.e. the number of favorable outcomes are: 6
{ (N,D) (N,Q) (D,N) (D,Q) (Q,N) (Q,D) }
The probability that the two coins are of different denomination is:
6/9=2/3
If you're any good at inequalities, please help!
The gas tank in Lou’s car holds 13 gallons of gasoline. There are already 7 gallons of gasoline in the tank. He is putting gasoline that costs $2.50 per gallon in his car. Lou spends x dollars putting gasoline in his car. Model a compound inequality for this situation.
Answer:
So the maximum amount of gasoline the tank can contain is 13 gallons and there are already 7 gallons of gasoline in the tank. Therefore, we want to make sure that the amount of gasoline put in the tank doesn't reach any higher than 13 gallon.
The amount of gasoline that Lou bought with x dollars is x/2.50 gallons.
We have the inequality:
x/2.50 + 7 ≤ 13
*If you solve it, x should be smaller or equal to $15.
The math problem can be solved by setting up a compound inequality expressing the range that Lou can spend on gasoline. This factors in the total capacity of his tank, the current amount of gas, and the price per gallon. The result is 0 <= x <= $15.
Explanation:For this problem, Lou needs to fill the remainder of his gas tank, which is 13 gallons total but already has 7 gallons. That means he needs to fill 13 - 7 = 6 gallons more. Gasoline costs $2.50 per gallon, so the total amount of money he spends, represented by x, can be calculated using the inequality $2.50 * number of gallons <= x.
But because Lou can add anywhere from 0 to 6 gallons, we will have a compound inequality. So, the inequality will be: $2.50 * 0 <= x <= $2.50 * 6.
This simplifies to 0 <= x <= $15, meaning Lou can spend anywhere from $0 to $15 on gasoline, depending on how much more he wants to put in his tank.
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What is the average rate of change from x = −3 to x = −4?
Answer:
-2
Step-by-step explanation:
Since it would be immensely helpful to know the equation of this parabola, we need to figure it out before we can continue. We have the work form of a positive upwards-opening parabola as
[tex]y=a(x-h)^2+k[/tex]
where a is the leading coefficient that determines the steepness of lack thereof of the parabola, x and y are coordinates of a point on the graph, and h and k are the coordinates of the vertex. We know the vertex: V(-3, -3), and it looks like the graph goes through the point P(-2, -1). Now we will fill in the work form equation and solve for a:
[tex]-1=a(-2-(-3))^2-3[/tex]
which simplifies a bit to
[tex]-1=a(1)^2-3[/tex]
and
-1 = a(1) - 3. Therefore, a = 2 and our parabola is
[tex]y=2(x+3)^2-3[/tex]
Now that know the equation, we can find the value of y when x = -3 (which is already given in the vertex) and the value of y when x = -4. Do this by subbing in the values of x one at a time to find y. When x = -3, y = -3 so the coordinate of that point (aka the vertex) is (-3, -3). When x = -4, y = -1 so the coordinate of that point is (-4, -1). The average rate of change between those 2 points is also the slope of the line between those 2 points, so we will use the slope formula to find it:
[tex]m=\frac{-1-(-3)}{-4-(-3)} =\frac{2}{-1}=-2[/tex]
And there you have it! I'm very surprised that this question sat unanswered for so very long! I'm sorry I didn't see it earlier!
Find the value of tan(sin^-1(1/2))
If you know that [tex]\sin\dfrac\pi3=\dfrac12[/tex], then you know right away
[tex]\tan\left(\sin^{-1}\dfrac12\right)=\tan\dfrac\pi3=\dfrac1{\sqrt}3=\dfrac{\sqrt3}3[/tex]
###
Otherwise, you can derive the same result. Let [tex]\theta=\sin^{-1}\dfrac12[/tex], so that [tex]\sin\theta=\dfrac12[/tex]. [tex]\sin^{-1}[/tex] is bounded, so we know [tex]-\dfrac\pi2\le\theta\le\dfrac\pi2[/tex]. For these values of [tex]\theta[/tex], we always have [tex]\cos\theta\ge0[/tex].
So, recalling the Pythagorean theorem, we find
[tex]\cos^2\theta+\sin^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\sqrt{1-\left(\dfrac12\right)^2}=\dfrac{\sqrt3}2[/tex]
Then
[tex]\tan\theta=\tan\left(\sin^{-1}\dfrac12\right)=\dfrac{\sin\theta}{\cos\theta}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}=\dfrac{\sqrt3}3[/tex]
as expected.
Answer:
c. square root 3/3
Step-by-step explanation:
just did it on edg
The area of a rectangle is (81x^2 − 4y^2) square units. Determine the dimensions of the rectangle by factoring the area expression completely. Show your work.
Answer 81x^2 - 4y^2 Note this is the difference of 2 perfect squares
a^2 - b^2 = (a + b)(a - b)
so here we have a = 9x and b = 2y
and our factors are
(9x + 2y)(9x - 2y)
the dimensions are 9x + 2y and 9x - 2y
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Show Work
81x^2 - 4y^2 Note this is the difference of 2 perfect squares
a^2 - b^2 = (a + b)(a - b)
so here we have a = 9x and b = 2y
and our factors are
(9x + 2y)(9x - 2y)
The dimensions of the rectangle with an area of (81x² - 4y²) square units are (9x + 2y) and (9x - 2y) units, as the area expression is a difference of squares that has been factored accordingly.
The area of a rectangle is given by the expression (81x² − 4y²) square units. To determine the dimensions of the rectangle, we need to factor this expression completely.
This expression is a difference of squares and can be factored as follows:Use the difference of squares formula, which is a²- b² = (a - b)(a + b).Apply the formula: (81x² − 4y²) = (9x)² - (2y)² = (9x + 2y)(9x - 2y).Therefore, the dimensions of the rectangle can be 9x + 2y and 9x - 2y units.
WILL GIVE BRAINLIEST
Answer: try A I took the same test earlier
Step-by-step explanation:
An office supply store has five different packages of black ink pens which is the best deal available on black ink pens at this office supply
Answer:
12 pack for $15.00
Step-by-step explanation:
4 pack for $7.00: 7 ÷4 = 1.75
6 pack for $10.25: 10.25 ÷6 ≈ 1.71
10 pack for $13.00: 13 ÷10 = 1.30
12 pack for $15.00: 15.00 ÷12 = 1.25
25 pack for $32.50: 32.50 ÷25 = 1.30
Samantha is making special edition hazelnut and almond chocolate boxes to give to her friends. It costs Samantha $15 to make one hazelnut chocolate box and $30 to make one almond chocolate box. It takes her 20 minutes to make either box of chocolates. She wants to spend no more than $210 and 200 minutes making the chocolate boxes to give to her friends.
Answer:
6 hazelnut
4 almond
Step-by-step explanation:
Answer:
Samantha should make six hazelnut chocolate boxes and four almond chocolate boxes in order to maximize the number of chocolates she gives to her friends.
Step-by-step explanation: This is the right answer
If BC = 6 and AD = 5, find DC. 4 4.5 7.2
Answer:
4
Step-by-step explanation:
The value of Side DC is 4.
What are similar triangles?Triangles with the same shape but different sizes are said to be similar triangles. Squares with any side length and all equilateral triangles are examples of related objects. In other words, if two triangles are similar, their corresponding sides are proportionately equal and their corresponding angles are congruent.
We have three similar triangles because each has a right angle and shares an angle. Let's write the angles in order: opposite to the short leg, long leg, and the hypotenuse.
CAB ≡ BAD ≡ CBD
Or as ratios,
CA:AB:CB = BA:AD:BD = CB:BD:CD
We also know
AC = AD + CD
(AD+CD):AB:CB = BA:AD:BD = CB:BD:CD
(AD+CD)/CB=CB/CD
Let CD = x
(5 +x )/6 = 6/x
(5+x)*x = 6*6
5x + x² = 36
x² + 5x - 36 = 0
x² + 9x -4x -36 = 0
x(x+9 ) -4 (x +9 ) = 0
(x-4)(x+9) = 0
x= 4, -9
We reject the negative root and conclude x=4
Therefore, Side DC is 4.
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If A=16°55’ and c=13.7, find a (picture provided)
Answer:
c. 4.0
Step-by-step explanation:
To find a, we'll use the Law of Sines that says:
[tex]\frac{a}{sin(A)} = \frac{c}{sin(C)}[/tex]
And we'll isolate a to get:
[tex]a = \frac{sin(A) * c}{sin(C)}[/tex]
Then we will plug-in the information we already have (changing 16°55' into 16.92)
[tex]a = \frac{sin(16.92) * 13.7}{sin(90)} = 3.99[/tex]
So, let's round it to 4 to match the answer number C.
Answer:
C
Step-by-step explanation:
Use the definition of the sine function:
[tex]\sin \angle A=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{BC}{AB}.[/tex]
Substitute [tex]\angle A=16^{\circ}55'[/tex] and [tex]c=13.7[/tex] into the previous formula:
[tex]\sin 16^{\circ}55'=\dfrac{a}{c},\\ \\\sin 16^{\circ}55'=\dfrac{a}{13.7},\\ \\a=13.7\cdot \sin16^{\circ}55',\\ \\a\approx 13.7\cdot 0.284\approx 4[/tex]
What Is The Circumference Of This Circle? Use 3.14 For Pi. There Is A Line Down The Middle Saying "12 cm"
12 is the diameter. We need the circumference which you get by multiplying 12x2 sides which = 24 which is the circumference
Antoine stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the ground), xx seconds after Antoine threw it, is modeled by: h(x)=-2x^2+4x+16h(x)=−2x 2 +4x+16 What is the height of the ball at the time it is thrown?
Answer:
[tex]\boxed{\text{16 ft}}[/tex]
Step-by-step explanation:
h(x) = -2x² + 4x + 16
At the time the ball is thrown,
x = 0
h(0) = -2 × 0² + 4 × 0 + 16 = [tex]\boxed{ \textbf{16 ft}}[/tex]
Answer:
The height of the ball at the time it is thrown is 16 meters.
Step-by-step explanation:
To find the height of the ball at the time it is thrown, we have that we set the time accordingly. So the height of the ball at the time it is thrown is given by h(0) since the ball was thrown at second 0.
Now that we know the time, which is our x, we set all of our x's to 0.
[tex]h(0)=-2(0)^{2} +4(0)+16[/tex]
Next we solve,
[tex]=0+0+16[/tex]
[tex]=16[/tex]
In conclusion, the height of the ball at the time it is thrown is 16 meters.
Solved and got it right on Khan Academy!
if 5x^2 + 7x = 6, which statement is correct?
A) x = 2 or x = 3/5
x = -2 or x = 3/5
X=2 or X= -3/5
x=-2 or X =-3/5
Answer:
12x^2=6
Divide by 12
x^2=1/2or.5
square root
x=0.707
Step-by-step explanation:
Given: PRST is a square
PMKD is a square
PR = a, PD = a
Find the area of PMCT.
Answer:
[tex](1-\sqrt{2})a^2[/tex]
Step-by-step explanation:
Consider irght triangle PRS. By the Pythagorean theorem,
[tex]PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a[/tex]
Thus,
[tex]MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a[/tex]
Consider isosceles triangle MSC. In this triangle
[tex]MS=MC=(\sqrt{2}-1)a.[/tex]
The area of this triangle is
[tex]A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}[/tex]
Consider right triangle PTS. The area of this triangle is
[tex]A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}[/tex]
The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:
[tex]A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2[/tex]
Which of the following expressions is equal to sin(-150°)?
A. sin(30°)
B. -sin(-30°)
C. -sin(30°)
D. sin(150°)
Check the picture below.
let's notice that the angle -150° has a reference angle of 30°, so any trigonometric function for either angle will be the same value, however, let's recall that the sine or y-coordinate is negative on the III Quadrant, so sin(-150°) is the same as sin(30°) BUT negative, -sin(30°).
Answer:
C. -sin(30°)
Step-by-step explanation:
180-150=30
-sin(30) = -.5 on calculator j like sin(-150) is
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Assume that there are 2 trials.
X = 2 where X represents the number of successes.
Which probability matches the probability histogram?
Round the answer to one decimal place.
Answer: The probability of the histogram is 0.6.
Step-by-step explanation:
Look at the images below for the step-by-step explanation. It's a lot easier to write on docs, rather than on this website. Anyway, I hope you've learned something. Bye!!!
simplify the number using the imaginary unit i √-75
[tex] \sqrt{ - 75} = \sqrt{ - 1 \times 75} = \sqrt{ {i}^{2} \times 75 } = 5i \sqrt{3} \\(therefore \: {i}^{2} = - 1)[/tex]
Answer:
[tex]\large\boxed{\sqrt{-75}=5\sqrt3\ i}[/tex]
Step-by-step explanation:
[tex]i=\sqrt{-1}\\\\\sqrt{-75}=\sqrt{(25)(3)(-1)}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt{25}\cdot\sqrt3\cdot\sqrt{-1}=5\cdot\sqrt3\cdot i=5\sqrt3\ i[/tex]
(8Q) Tell whether the function exhibits damped oscillation. If it does, identify the damping factor and tell whether the damping occurs.
Answer:
Option c.
No damping
Step-by-step explanation:
We can easily solve this question by using a graphing calculator or any plotting tool.
The function is
f(x) = (√11)*cos(3.7x)
Which can be seen in the picture below
We can notice that f(x) is a cosine with maximum amplitude of (√11). Neither this factor nor the multiplication of x by 3.7 serve as a damping factor since they are constants.
f(x) does not present any dampening
Answer:
C) No damping.
Step-by-step explanation:
This is the correct answer on ed-genuity, hope this helps! :)
HELP ASAP PLZ
the function f(x) is the height of a model rocket x seconds after launch. The rocket reaches its maximum height in 2 seconds and hits the ground at 4 seconds. What is the practical domain for the function f(x)?
Final answer:
The practical domain of the function f(x), representing the height of a model rocket after launch, is [0,4], including the launch at time x=0, reaching the maximum height at x=2 seconds, and landing at x=4 seconds.
Explanation:
The practical domain for the function f(x), which represents the height of a model rocket x seconds after launch, refers to the interval of time during which the rocket is in flight. Since the rocket is launched at time x=0, reaches its maximum height at x=2 seconds, and hits the ground at x=4 seconds, the practical domain of f(x) is [0,4].
This domain includes all times from the launch to when the rocket lands, as the function's values will only be meaningful or defined within this interval.
A middle school has 490 students. Mae surveys a random sample of 60 students and finds that 24 of them have pet dogs. How many students are likely to have pet dogs?
Answer:
196
Step-by-step explanation:
What is the solution to the equation below?
[tex]\frac{\sqrt{3-2x} }{\sqrt{4x} } =2[/tex]
A. x = 5/6
B. x = 9/10
C. x = 1/6
D. x = 3/10
Answer: OPTION C
Step-by-step explanation:
Given the equation [tex]\frac{\sqrt{3-2x} }{\sqrt{4x} } =2[/tex], you need to solve for the variable "x".
First, you need to multiply both sides of the equation by [tex]\sqrt{4x}[/tex]:
[tex](\frac{\sqrt{3-2x}}{\sqrt{4x}})(\sqrt{4x} })=2(\sqrt{4x} })\\\\\sqrt{3-2x}=2\sqrt{4x}[/tex]
Now you need to square both sides of the equation:
[tex](\sqrt{3-2x})^2=(2\sqrt{4x})^2\\\\3-2x=4(4x)\\\\3-2x=16x[/tex]
Subtrac 3 and 16x from both sides:
[tex]3-2x-(3)-(16x)=16x-(3)-(16x)\\\\-18x=-3\\[/tex]
Divide both sides by -18:
[tex]\frac{-18x}{-18}=\frac{-3}{-18}\\\\x=\frac{1}{6}[/tex]
What is the amplitude and period of f(t)=2.5 tan t?
Answer:
Option d.
Amplitude: None
Period: π
Step-by-step explanation:
To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.
Please see the attached image below, to find more information about the graph
The equation is:
f(t) = 2.5 tan (t)
We can see from the graph that the amplitude goes up to infinity, and the period is equal to π.
Option d.
Amplitude: None
Period: π
The amplitude of the function f(t)=2.5 tan t is 2.5, as it's the coefficient of the tangent function. The period is π, as it's obtained by dividing π by the number multiplying 't', which in this case, is 1.
Explanation:The function given, f(t)=2.5 tan t, is a trigonometric function, which represents a wave. In the context of a wave represented by a trigonometric function such as this, there are several key components. The two most important for this question are:
Amplitude: The amplitude of a wave is the peak value of the wave. In the given equation, the amplitude is the coefficient of the trigonometric function, which is 2.5.Period: The period of a wave is the length of one cycle of the wave. The period of a tan function is (π/b), where 'b' is the number multiplying t. In this case, as 't' doesn't have any multiplier, the period is π. Learn more about Amplitude and Period here:
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6 libras de café y 5 de azúcar costaron 227 pesos y 5 libras de café y 4 libras de azúcar (a los mismos precios) costaron 188 pesos hallar el precio de una libra de café y una libra de azúcar
Answer:
The price of one pound of coffee is 32 pesos
The price of one pound of sugar is 7 pesos
Step-by-step explanation:
The question in English is
6 pounds of coffee and 5 pounds of sugar cost 227 pesos and 5 pounds of coffee and 4 pounds of sugar (at the same prices) cost 188 pesos Find the price of one pound of coffee and one pound of sugar.
Let
x-----> the price of one pound of coffee
y-----> the price of one pound of sugar
we know that
6x+5y=227 -----> equation A
5x+4y=188 ----> equation B
Solve the system of equations by graphing
Remember that the solution of the system of equations is the intersection point both graphs
The solution is the point (32,7)
see the attached figure
therefore
The price of one pound of coffee is 32 pesos
The price of one pound of sugar is 7 pesos
Help me please.................
Answer:
$4140
Step-by-step explanation:
For each of the amounts, the final balance is ...
A = P(1 +rt)
Filling in the given numbers, we can add the final balances:
900(1 + 0.06·4) + 900(1 + 0.06·3) + 900(1 + 0.06·2) + 900(1 + 0.06·1)
= 900(4 + 0.06(4 +3 +2 +1)) = 900·4.60
= 4140
The amount withdrawn is $4140.