which of the following represent the values of x, y, and z.

Let's say the first truck weighs x tons

Then, the weight of 2nd truck = x+2 tons

The weight of 3rd truck = (x + 2) + 2 = x+4 tons

The weight of 4th truck = (x + 4) + 2 = x+6 tons

Total weight of 4 trucks:

x + (x+2) + (x+4) + (x+6) = 32

which can be solved easily to give x = 5

Answer: Option D.

Step-by-step explanation:

You need to remember that the circumference of a circle can be calculated with this formula:

[tex]C=2\pi r[/tex]

Where "r" is the radius of the circle and [tex]\pi =3.14[/tex]

In this case the distance 150 feet (From the edge of the track to the center of the circle) is the radius.

Since she walks her horse 4 times around the track, you need to multiply the circumference by 4 to calculate the approximate number of feet that she and her horse will travel:

 [tex]C=4[2(3.14)(150ft)]=3,768ft[/tex]

Answer:

[tex]\large\boxed{x=-4}[/tex]

Step-by-step explanation:

[tex]-4x+3=19\qquad\text{subtract 3 from both sides}\\\\-4x+3-3=19-3\\\\-4x=16\qquad\text{divide both sides by (-4)}\\\\\dfrac{-4x}{-4}=\dfrac{16}{-4}\\\\x=-4[/tex]

Step 1: Combine like terms ( 3 and 19) by subtracting 3 to both sides

-4x + (3-3) = 19 -3

-4x = 16

Step 2: Isolate x by dividing -4 to both sides

[tex]\frac{-4x}{-4} =\frac{16}{-4}[/tex]

x = -4

Hope this helped!

Answer:

92°

Step-by-step explanation:

The supplementary relationship between angles 2 and 3 means lines a and b are parallel. Since those lines are parallel, corresponding angles 1 and 4 are congruent.

m∠1 = m∠4 = 92°

From this triangle we know:

THE AREA:

[tex]A=80cm^2[/tex]

THE HEIGHT:

[tex]H=B+12[/tex]

We know that the area, height, and base of a triangle are related according to the following formula:

[tex]A=\frac{BH}{2} \\ \\ Substituting \ H: \\ \\ A=\frac{B(B+12)}{2} \\ \\ Substituting \ A: \\ \\  80=\frac{B(B+12)}{2} \\ \\ 2(80)=B(B+12) \\ \\ 160=B^2+12B \\ \\ B^2+12B-160=0[/tex]

Solving B by quadratic formula:

[tex]B_{12}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ B_{12}=\frac{-12 \pm \sqrt{12^2-4(1)(-160)}}{2(1)} \\ \\ B_{12}=\frac{-12 \pm \sqrt{12^2-4(1)(-160)}}{2(1)} \\ \\ B_{1}=8 \ and \ B_{2}=-20[/tex]

Since we can’t have a negative value of the base, the correct option is:

[tex]B=8cm[/tex]

We must use the formula:

[tex]h(t)=-5.2t^2+v_{0}t+h_{0}[/tex]

Since James drops the balloon from a height of 45m, then this is the initial height, so [tex]h_{0}=45m[/tex]. Moreover, at the very instant he drops the balloon the initial velocity is zero, so [tex]v_{0}=0[/tex]. When the ballon hit the ground [tex]h(t)=0[/tex]. Therefore:

[tex]0=-5.2t^2+45[/tex]

Solving this equation:

[tex]5.2t^2=45 \\ \\ t^2=\frac{45}{5.2} \\ \\ t^2=8.653 \\ \\ t=\sqrt{8.653} \\ \\ t=2.941s[/tex]

Rounding to the nearest tenth:

[tex]\boxed{t=2.9s}[/tex]

Finally, the water balloon will hit the ground after 2.9 seconds.

We have the equation:

[tex]h(t)=-16t^2+32t+12[/tex]

But we know that this equation follows the form:

[tex]h(t)=-16t^2+v_{0}t+h_{0}[/tex]

According to this:

The height of the platform is [tex]h_{0}=12ft[/tex]

The initial velocity of the ball is [tex]v_{0}=32ft/s[/tex]

let's keep in mind that perpendicular lines have negative reciprocal slopes, hmmm what is the slope of line S anyway?

[tex]\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-7}{6-2}\implies \cfrac{-6}{4}\implies -\cfrac{3}{2} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{3}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{3}}\qquad \stackrel{negative~reciprocal}{\cfrac{2}{3}}}[/tex]

so, we're really looking for the equation of a line whose slope is 2/3 and runs through (5,2)

[tex]\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{2})~\hspace{10em} slope = m\implies \cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=\cfrac{2}{3}(x-5)\implies y-2=\cfrac{2}{3}x-\cfrac{10}{3} \\\\\\ y=\cfrac{2}{3}x-\cfrac{10}{3}+2\implies y=\cfrac{2}{3}x-\cfrac{4}{3}[/tex]

Answer:

8cm

Step-by-step explanation

In between AE and DE

A. Getting recommended by a teacher

A getting recommended by a teacher the reason the reason why this is correct is because the teacher is not randomly picking you she already knows who she wants to recommend

Answer:

See below.

Step-by-step explanation:

x^2 + 2x = 19

(x + 1)^2 - 1 = 19

(x + 1)^2 = 20.

Answer:

(x+1)2+2x=19

Step-by-step explanation:

i just did it on a p e x

Answer:

a building

Step-by-step explanation:

Your exams? Probably at home, unless it’s AZmerit or CAmerit.

[tex]\bf \textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=&radius\\ \theta =&angle~in\\ &degrees\\ \cline{1-2} r=16\\ \theta =80 \end{cases}\implies s=\cfrac{(80)\pi (16)}{180}\implies s=\cfrac{64\pi }{9} \\\\\\ s\approx 22.34\implies \stackrel{\textit{rounded up}}{s=22}[/tex]

Final answer:

The length of the arc intercepted by a central angle of 80 degrees in a circle with a radius of 16 inches is approximately 22 inches to the nearest inch.

Explanation:

To find the arc length of a circle that is intercepted by a central angle of 80 degrees, we first need to know the formula for the circumference of a circle, which is 2πr.

In a full circle, which is 360 degrees, the arc length is equal to the circumference. However, because we are only dealing with an 80-degree angle, we need to find the fraction of the circumference that corresponds to this angle. The formula to calculate the arc length (As) for any given angle (Θ) in degrees is:

As = (2πr * Θ) / 360

Given a radius (r) of 16 inches, and a central angle of 80 degrees, the arc length is:

As = (2π * 16 * 80) / 360 ≈ (100.53 inches * 80) / 360 ≈ 8033.6 / 360 ≈ 22.3 inches

Therefore, to the nearest inch, the length of the arc is 22 inches.

Answer:

y=3.11x

Step-by-step explanation:

Not sure if it's correct. But my reasoning behind it is that 23.81-20.70=3.11 which means every year the cost goes up by $3.11

Answer:

$5

Step-by-step explanation:

Answer:

the answer is 5$

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

A(rectangle) = 14 * 21 = 294

A(triangle) = ((21 - 12) * 16) / 2 = 72

A(figure) = 294 + 72 = 366

Answer:

B 366 cm²

Step-by-step explanation:

Multiply 21 by 14 to find area of the rectangle

21 × 14 = 294

Subtract 12 from 21

21 - 12 = 9

Multiply 9 by 16

144

Divide 144 by 2 to get area of triangle

144 ÷ 2 = 72

Add 72 with 294 to get final answer

72 + 294 = 366

Answer: B 366 cm²

Answer:

1  3/4 miles in 1/4 hour.

Step-by-step explanation:

Write and solve an equation of ratios:

 x           (1/4) hr

--------- = ------------

14 mi       2 hr

Cross multiplying, we get 2x = (1/4)(14), or

                                              x = (1/4)(7), or x = 7/4

Steve can jog 7/4 miles in 1/4 hour.  That's 1  3/4 miles in 1/4 hour.

Answer:

Step-by-step explanation:

Answer:

y = -√(x + 5) + 2.

Step-by-step explanation:

y = -√x

Shifting this 2 units up produces the equation:

y = -√x + 2

Moving it 5 units to the left gives:

y = -√(x + 5) + 2.

The equation of graph of  [tex]y=-\sqrt{x}[/tex] is shifted 2 units up and 5 units left.

[tex]y=-\sqrt{x+5}+2[/tex]

Given :

The graph of  [tex]y=-\sqrt{x}[/tex] is shifted 2 units up and 5 units left.

The parent equation of the graph is [tex]y=-\sqrt{x}[/tex]

The graph is shifted 2 units up

When any graph is shifted up  then we add the units at the end

Graph shifted 'a' units up then f(x) becomes f(x) +a

when a graph is shifted 'a' units left , then we add the units with 'x'

Graph shifted 'a' units left then f(x) becomes f(x+a)

The graph of  [tex]y=-\sqrt{x}[/tex] is shifted 2 units up and 5 units left.

Add 5 units with 'x' and add 2 units at the end

[tex]y=-\sqrt{x+5}+2[/tex]

Learn more :  brainly.com/question/2527724

Substitute:

f(3) = (1/8)(8^(3))

Evaluating the function gives us the answer of 64.

f(3) = 64

Answer: (5x^2 + 2)(3x - 1)

I'll break it down:

You start off with 15x^3 - 5x^2 + 6x - 2

You first group the first two terms together, and then the last two pairs together: (15x^3 - 5x^2) (6x - 2)

Then you simplify (just factor out as much as you can): 5x^2(3x - 1) 2(3x - 1)

Then you take the terms that you get from doing that.

To find the First Term:

5x^2(3x - 1) 2(3x - 1)

(5x^2 + 2)

To find the Second Term:

5x^2(3x - 1) 2(3x - 1)

(3x - 1)

So your terms are (5x^2 + 2) and (3x -1)

Final Answer: (5x^2 + 2)(3x - 1)

The resulting expression will be (5x² + 2)(3x - 1). The correct answer is option A.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

The grouping of the given expression will be done as:-

You start off with 15x³ - 5x²+ 6x - 2

You first group the first two terms together, and then the last two pairs together: (15x³ - 5x²) (6x - 2)

Then you simplify (just factor out as much as you can): 5x²(3x - 1) 2(3x - 1)

Then you take the terms that you get from doing that.

To find the First Term:

5x² (3x - 1) 2(3x - 1)

(5x² + 2)

To find the Second Term:

5x²(3x - 1) 2(3x - 1)

(3x - 1)

So your terms are (5x² + 2) and (3x -1)

Therefore the resulting expression will be (5x² + 2)(3x - 1)

To know more about expression follow

https://brainly.com/question/723406

#SPJ2

Answer: The answer is 100.

Step-by-step explanation: 40 divided by 2 = 20

x=20

20x5=100

Answer: answer is 140 on gradpoint.com

Answer:

Part 1) The inscribed angle is the angle ∠TRS and the intercept arc is the arc LST

Part 2) The inscribed angle is the angle ∠YWX and the intercept arc is the minor arc XY

Part 3) The inscribed angle is the angle ∠YXZ and the intercept arc is the arc YBZ

Part 4) The figure does not show an inscribed angle

Step-by-step explanation:

Part 1) The figure shown a inscribed angle

The inscribed angle is the angle ∠TRS

The intercept arc is the arc LST

Remember that

The inscribed angle measures half that of the arc comprising

so

∠TRS=(1/2)[arc LST]

Part 2) The figure shown a inscribed angle

The inscribed angle is the angle ∠YWX

The intercept arc is the minor arc XY

Remember that

The inscribed angle measures half that of the arc comprising

so

∠YWX=(1/2)[minor arc XY]

Part 3) The figure shown a inscribed angle

The inscribed angle is the angle ∠YXZ

The intercept arc is the arc YBZ

Remember that

The inscribed angle measures half that of the arc comprising

so

∠YXZ=(1/2)[arc YBZ]

Part 4) The figure does not show an inscribed angle

The figure shown a interior angle ∠BAC

Answer:

∠E = ∠F = 41°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 given angles and equate to 180

x + x + 98 = 180 ( subtract 98 from both sides )

2x = 82 ( divide both sides by 2 )

x = 41

Hence

∠E = ∠F = 41°

Answer:

B, A and C.

Step-by-step explanation:

(7x^2-5x+3)+(2x^2+3x-1) is equivalent to expression B .

(3x^2-4x-4)+(-12x^2+2x+11) is equivalent to expression A .

(4x^2-3x-9)+(5x^2+5x+2) is equivalent to expression C .

You combine like terms to arrive with the answer.

The answer is:

- The first operation match with the polynomial:

B.  [tex]9x^{2} -2x+2[/tex]

- The second operation match with the polynomial:

A. [tex]-9x^{2}-2x+7[/tex]

- The third operation match with the polynomial:

C. [tex]9x^{2} +2x-7[/tex]

In order to solve the given operations, we need to group the like terms.

Remember, like terms are terms that share the same variable and the same exponent.

For example:

[tex]x^{2} +2x^{2} +3x^{3} +2=3x^{2} +3x^{3} +2[/tex]

We only operate with the variables that shares the same exponent.

Also, we need to remember the distributive property:

[tex](a+b)(c+d)=ac+ad+bc+bd[/tex]

So, we are given the following polynomials:

[tex]A.9x^{2} -2x+7\\\\B. 9x^{2} -2x+2\\\\C. 9x^{2} +2x-7[/tex]

And we need to perform the following operations:

First operation,

[tex](7x^{2}-5x+3)+(2x^{2} +3x-1)=7x^{2} +2x^{2} -5x+3x+3-1\\\\7x^{2} +2x^{2} -5x+3x+3-1=9x^{2} -2x+2[/tex]

So, the first operation match with the polynomial:

B.  [tex]9x^{2} -2x+2[/tex]

Second operation,

[tex](3x^{2}-4x-4)+(-12x^{2}+2x+11)=3x^{2} -12x^{2} -4x+2x-4+11\\\\3x^{2} -12x^{2} -4x+2x-4+11=-9x^{2}-2x+7[/tex]

So, the second operation match with the polynomial:

A. [tex]-9x^{2}-2x+7[/tex]

Third operation,

[tex](4x^{2} -3x-9)+(5x^{2} +5x+2)=4x^{2}+5x^{2} -3x+5x-9+2\\\\4x^{2}+5x^{2} -3x+5x-9+2=9x^{2} +2x-7[/tex]

So, the second operation match with the polynomial:

C. [tex]9x^{2} +2x-7[/tex]

Have a nice day!

Graphing the linear equation -2x - 3y = -7: Identify three points satisfying the equation, such as (0, 3), (1, 1), and (2, 1). Plotting these points on the graph, connect them to depict the line representing the equation on the Cartesian plane.

To graph the linear equation -2x - 3y = -7, we can first rearrange it to solve for y:

-2x - 3y = -7

-3y = 2x - 7

[tex]\[ y = \frac{2}{3}x + \frac{7}{3} \][/tex]

Now, we can select three points to plot on the graph. For simplicity, let's choose some integer values for x to find corresponding y values:

1. When x = 0: [tex]\(y = \frac{7}{3}\)[/tex], giving the point [tex](0, \(\frac{7}{3}\))[/tex].

2. When x = 3: y = 3, giving the point (3, 3).

3. When x = -3: y = -1, giving the point (-3, -1).

Now, plot these three points on the graph and connect them to visualize the line represented by the equation.

For more questions on graph:

https://brainly.com/question/19040584

#SPJ6

Answer:

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

The rate of change of a linear function is the slope m

h(x) = 2x is a linear function with slope m = 2

Hence rate of change is 2

Answer:a squared-b squared

Step-by-step explanation:

Answer:

[tex](a+b)(a-b)=a^{2} -b^{2}[/tex]

Step-by-step explanation:

This is a example of remarkable identities.

We know that the result of multiplication is called product and the values ​​that multiply are called factors.

We call remarkable identities to certain algebraic expressions with binomial products very frequent in the calculation.

For this example, we got a Product of the sum for the difference of two binomials.

[tex](a+b)(a-b)[/tex]

The product of the sum for the difference of two binomials is equal to the square of the first quantity, minus the square of the second.

[tex](a+b)(a-b)=a^{2} -b^{2}[/tex]

Demostration:

[tex](a+b)(a-b)= a^{2} -ab+ab-b^{2}=a^{2} -b^{2}[/tex]

.

Answer:

5(pi) (exactly) or 15.7 (approximately)

Step-by-step explanation:

The length of arc of an entire circle is the circumference of the circle.

The length of arc of a semicircle circle is half of the circumference of the circle.

C = pi * d

For a semicircle:

arc length = 0.5 * pi * d

arc length = 0.5 * pi * 10

arc length = 5(pi)

arc length = 15.7

Answer:

A. 7 units

Step-by-step explanation:

Answer:

The correct option is A. The length of chord ST in P is 7 units.

Step-by-step explanation:

Given information: QR=7, distance between center and QR is 3.2 units and the distance between center and ST is 3.2 units.

If two chords are equidistant from the center of the circle, then the length of both chords are same.

From the given figure it is clear that the two chords QR and ST are equidistant from the center of the circle,so the length of both chords are same.

[tex]QR=ST[/tex]

[tex]7=ST[/tex]

The length of chord ST in P is 7 units. Therefore the correct option is A.

Answer:

m = 33*g.

Step-by-step explanation:

The consumption of gas = 396 / 12

= 33 miles / gallon.

m = 33*g (answer).

Answer:

There are  8 boys in the chorus and 16 girls in the chorus

The graph in the attached figure

Step-by-step explanation:

Let

x----> the number of boys

y----> the number of girls

we know that

[tex]y=2x[/tex] -----> equation A

[tex]x=y-8[/tex] ----> equation B

Solve the system of equations by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution is the point (8,16)

see the attached figure

therefore

There are  8 boys in the chorus

There are  16 girls in the chorus