What is the steps for solving 3x-10=84 and tell me what x equals

Answer:

Step-by-step explanation:

[tex]f(x)=4x^2+4x-4\ or\ f^*(x)=4x+4x-4=8x-4\\\\f(0)-\text{put}\ x=0\ \text{to}\ f(x):\\\\f(0)=4(0)^2+4(0)-4=4(0)+0-4=0-4=-4\\\\f^*(0)=8(0)-4=0-4=-4[/tex]

For this case we have the following expression:

[tex]2x ^ 2 + 2x ^ 3[/tex]

The terms are not similar, so they cannot be added.

Examples of similar terms:

[tex]x ^ 3 + x ^ 3 = 2x ^ 3\\3x ^ 4 + 2x ^ 4 = 5x ^ 4[/tex]

Then, the expression given can only be rewritten as:

[tex]2 (x ^ 2 + x ^ 3)[/tex]

This is taking common factor 2 to both terms.

Answer:

[tex]2 (x ^ 2 + x ^ 3)[/tex]

Answer:

linear

Step-by-step explanation:

It is linear because the line is straight.

Answer:

Therefore the correct option is B.

Step-by-step explanation:

i) A convex polygon is a polygon which has all its interior angles as less than 180°.

ii) From visual inspection of all four options only option B seems to fulfill the criteria mentioned in i)

Therefore the correct option is B.

Answer:the answer is b

Step-by-step explanation:

I got it corrrect trust me

Answer:

A. The graph approaches –3 as x approaches infinity.

Step-by-step explanation:

when looking at the problem F (x) + 3x/x-4 the answer would lead up to..

Finding the domain by finding where the function is defined. The range is the set of values that correspond with the domain.

Domain:  

( − ∞ , 4 ) ∪ ( 4 , ∞ ) , { x | x ≠ 4 }

Range:  ( − ∞ , − 3 ) ∪ ( − 3 , ∞ ) , { y | y ≠ -3 }

are what it leads to and seeing the range -3 would have x as infinite/ -∞

so A is the correct option to me

The statement that describes the behavior of the function f(x) = 3x/4-x is The graph approaches 0 as x approaches infinity.

Option B is the correct option.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

The statement "The graph approaches 0 as x approaches infinity" is the correct statement that describes the behavior of the function f(x) = 3x/(4-x).

We can use the limit definition of approaching infinity.

When x becomes very large (positive or negative), the term 4 - x in the denominator becomes very small, approaching zero.

As a result,

The fraction 3x/(4-x) approaches zero as x approaches infinity.

This can be confirmed using L'Hopital's rule, which gives the limit of the function as 0/1, or simply by observing the graph of the function.

Thus,

The graph approaches 0 as x approaches infinity.

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The fraction is 5/15, which simplifies to 1/3. So Andy ate one third of the tuna sandwich.

The student's question involves determining the fraction of the tuna sandwich that Andy ate. Andy cut a tuna sandwich into 12 more pieces than the chicken sandwich and the total number of pieces was 18. Since tuna has 12 more pieces, we let the number of chicken pieces be x. Hence, the tuna pieces would be x + 12. The equation then is x + (x + 12) = 18. Solving this, we get x = 3 (chicken pieces) and x + 12 = 15 (tuna pieces).

Andy ate 5 pieces of the tuna sandwich, so the fraction of the tuna he ate is 5 out of the total tuna pieces, which is 15. Therefore, the fraction is 5/15, which simplifies to 1/3. So Andy ate one third of the tuna sandwich.

Answer:

I got u

Step-by-step explanation:

sin C = 7/25 or 0.28

cos C = 24/25 or 0.96

tan C = 7/24 or about 0.292

lmk if u want me to explain how trigonometric functions work

The ratios for sin C, cos C, and tan C in a right triangle are y/h, x/h, and y/x respectively, where y is the opposite side, x is the adjacent side, and h is the hypotenuse.

To write ratios for sin C, cos C, and tan C in a right triangle, you need to refer to the lengths of the sides of the triangle relative to angle C. If we denote the opposite side to angle C as y, the adjacent side as x, and the hypotenuse as h, the ratios are defined as follows:

In a practical scenario, if you know the magnitude of one side and the direction angle, you can use these ratios to find the scalar components of a vector in a coordinate system, solve problems involving the Law of Sines and Law of Cosines, or analyze wave functions in physics. For example, the Law of Sines relates the lengths of the sides of a triangle to the sines of its angles as follows:

 a/sin A = b/sin B = c/sin C

Where a, b, and c are the sides of the triangle opposite to angles A, B, and C, respectively.

Answer:

If you are looking for n then

N = -13

Step-by-step explanation:

-13+-9 is -22

Answer

n= -13

-22 = -9 + n

first flip the equation

n + -9 = -22

then add 9

so -22 + -9 = - 13

so n = -13

Answer:

h has a coefficient 1 so u will afd 6h +h=7h

Step-by-step explanation:

[tex]22=\boxed{2}\times11\\\\34=\boxed2\times17\\\\GCD(22,\ 34)=\boxed2\\\\\dfrac{22}{34}=\dfrac{22:2}{34:2}=\dfrac{11}{17}[/tex]

Answer:

11/17

Step-by-step explanation:

22 and 34

22: 1, 2, 11, 22

34: 1, 2, 17, 34

22/34 ÷ 2/2 = 11/17

Answer:

( 1.17 3 ,  4.6 )

Step-by-step explanation:

Answer:

69°

Step-by-step explanation:

The three interior angles in a triangle will always add up to 180°, so we have:

43°+x+(x-1)=180°

43°+2x-1°=180°

2x=180°-43°+1°

2x=138°

x=69°

Answer:

69 degrees

Step-by-step explanation:

Answer:

Part 1) [tex]m\angle QML=90^o[/tex]

Part 2) [tex]m\angle PMN=63^o[/tex]

Step-by-step explanation:

The complete question in the attached figure

Part 1) Find the measure of angle QML

we know that

According to the Perpendicular Tangent Theorem, tangent lines are always perpendicular to a circle's radius at the point of intersection

so

radius OM is perpendicular to LN at point M

therefore

[tex]m\angle QML=90^o[/tex]

Part 2) Find the measure of angle PMN

we know that

[tex]m\angle QMN=m\angle QMP+m\angle PMN[/tex] ---> by angle addition postulate

we have

[tex]m\angle QMN=90^o[/tex]

[tex]m\angle QMP=27^o[/tex]

substitute

[tex]90^o=27^o+m\angle PMN[/tex]

[tex]m\angle PMN=90^o-27^o=63^o[/tex]

Applying the perpendicular tangent theorem, the missing angles are:

m∠QML = 90°

m∠PMN = 63°

The Perpendicular Tangent Theorem states that tangent lines are perpendicular to the radius of a circle at the point where they intersect, forming a right angle.

Based on the perpendicular tangent theorem,

m∠QML = m∠QMN = 90°

m∠QML = 90°

m∠PMN = 90° - 27°

m∠PMN = 63°

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Answer:

g-1(x) = -x/3 - 6.

Step-by-step explanation:

Let g(x) = y = -3(x + 6)

y = -3x - 18

3x = - y - 18

x =  -y/3 - 6

Now replace x by the inverse g-1(x)  and y by x, so

g-1(x) = -x/3 - 6.

Answer:

Therefore the Area of Triangle is 24 units².

Step-by-step explanation:

On a Co-ordinate plane

A Triangle having

Base = 8 units

Height = 6 units

To Find:

Area of Triangle = ?

Solution:

When Base and Height is given , then Area of triangle is given by

[tex]\textrm{Area of Triangle} = \dfrac{1}{2}\times Base\times Height[/tex]

Substituting the values we get

[tex]\textrm{Area of Triangle} = \dfrac{1}{2}\times 8\times 6=24\ units^{2}[/tex]

Therefore the Area of Triangle is 24 units².

Answer: 24

Step-by-step explanation:

base is 8

height is 6

Answer:

35

Step-by-step explanation:

just due 280 divided by 8

Answer:

log(14) / log(3) + 1   OR  3.40217350

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

Answer:

D. 7,927,173,860

Step-by-step explanation:

Because math

Answer:

B

Step-by-step explanation:

Because they have same volume we have :

V(boxA)=2*3*6=36[tex]in^3[/tex]

V(boxB)=3*4*l=12l

V(boxA)=V(boxB)

So we have this equation :

36=12l

Divide by 12

l=3

Answer:

31/50

Step-by-step explanation:

0.62 = 62/100 = 31/50

Answer: 1.5

Da maths: Bruh ask google

The required area of the flying disc is 154 square inches.

A flying dis has radius of 7 inches. Area of the disc to be determine.

Area of circle is given by the pie times square of radius.

Area of circle = πr^2

                       = 3.14 * 7 *7
                       =  154 square inches

Thus, the required area of the flying disc is 154 square inches.

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Answer:

the answer is c :)

Answer:

S>36

where S is saving

Marilyn can cut 14 equal pieces

Solution:

Given that, Marilyn has 7/8 yard of ribbon

To find: Maximum number of 1/16 yard long pieces Marilyn can cut from this ribbon

From given information,

[tex]\text{Total length of ribbon } = \frac{7}{8} \text{ yard }[/tex]

[tex]\text{Length of 1 piece } = \frac{1}{16} \text{ yard }[/tex]

Number of pieces that can be cut from total length of ribbon is found by dividing the total length of ribbon by length of 1 piece

Therefore,

[tex]\text{Number of pieces } = \frac{\text{Total length of ribbon}}{\text{Length of 1 piece }}[/tex]

Substituting the values, we get

[tex]\text{Number of pieces } = \frac{\frac{7}{8}}{\frac{1}{16}}\\\\\text{Number of pieces } = \frac{7}{8} \times \frac{16}{1}\\\\\text{Number of pieces } = 14[/tex]

Thus 14 pieces of ribbon can be cut

Answer:

  1

Step-by-step explanation:

The square root function is monotonically increasing, so will have a maximum at the right end of any interval. Here the maximum is at x=2. That value is ...

  y = √(2+2) -1 = 2 -1 = 1

The maximum value on the interval is 1.

Answer:

B I think

Step-by-step explanation:

The best sequence for the events in the personal narrative would be: waking up, feeling nervous, walking up to the stage, forgetting the line, director helping with the line, and receiving a standing ovation.

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The markup percentage on the shoes that were bought for $50 and sold for $80 is 60%.

To calculate the markup percentage, you subtract the original cost from the selling price and then divide that number by the original cost. Finally, you multiply the result by 100 to get the percentage.

The formula looks like this: ((Selling Price - Original Cost) / Original Cost)×  100. Let's apply this formula to your question.

The store bought the shoes for $50 and sold them for $80. So the markup in dollars is

$80 - $50 = $30

Now, let's convert this to a percentage:

Markup Percentage =

[tex]= \frac{80-50}{50} \times 100 \\\\= \frac{30}{50} \times100\\\\ = 60\%[/tex]

The markup percentage is 60%.