Answer:
the answer is letter d because both of them are pushing the couch in the same direction so 4 plus 2 will give you 6N
A 59 kg man has a total mechanical energy of 150,023. J. If he is swinging downward and is currently 2.6 m above the ground, what is his speed ?
Answer:
71
Explanation:
A 59 kg man has a total mechanical energy of 150,023. J. If he is swinging downward and is currently 2.6 m above the ground, his speed 71 m/sec.
What is energy?Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Using conservation of energy
m*g*h + 0.5 m*v² = 150023 joule
59*9.8*2.6 + 0.5*59*v² = 150023
1503.32 + 29.5 v² = 150023
29.5 v² = 148519.60
v² = 5034.56
v = 70.95 = 71 m/sec
A 59 kg man has a total mechanical energy of 150,023. J. If he is swinging downward and is currently 2.6 m above the ground, his speed 71 m/sec.
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You serve a volleyball with mass of 2.1kg. The call leaves your hand at 30m/s. The ball has Energy calculate it
Answer: 945 joules
Explanation:
Given that:
mass of volleyball = 2.1kg.
Speed at moving volleyball = 30m/s. Energy possessed by volleyball = ?
Recall that the energy possessed by a moving object is known as kinetic energy. Thus, the moving volleyball has kinetic energy.
So, apply the formula for kinetic energy
K.E = 1/2 x mass x speed^2
K.E = 1/2 x 2.1kg x (30m/s)^2
K.E = 0.5 x 2.1kg x 900
K.E = 945 Joules
Thus, the volleyball has kinetic energy of the 945 joules
for inclined plane derive efficiency =L/h
Answer: L=F/a
Explanation:
Efficiency of inclined plane is L/h VR.
What is meant by the efficiency of an inclined plane ?Efficiency of an inclined plane is defied as the ratio of effort in moving a body up or down without friction to that with friction.
Here,
The efficiency of an inclined plane,
η = MA/VR
η = (l/h)/ (dE/dl)
η = L/h (VR)
Hence, derived the efficiency for inclined plane is L/h VR.
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is there carbon atoms in the compound Ca3N2
No, there are not any carbon atoms inside this compound.
The compound is [tex]Ca_3N_2[/tex]. This means there are 3 "Ca" atoms and 2 "N" atoms.
Ca is calciumN is nitrogenThus, none of the elements in this compound are carbon, meaning there are no carbon atoms. Let me know if you need any clarifications, thanks!
~ Padoru
what is the position of the car at the end of the 10 secs?
Answer:
S=400m
Explanation:
Given t=10.and [tex]a=8m/s^2[/tex],
Initial velocity,[tex]u[/tex], of the car is zero.
To find distance,[tex]s[/tex]
[tex]S=ut+0.5at^2[/tex]
[tex]S=0\times10+0.5\times8\times10^2\\S=400m[/tex]
Therefore, car's position after 10seconds is 400m away from the start.
help? the first line is supposed to say "all _ has heat"
click the image
Objects that are not moving have NO _____. A. mass (only) B. mass and momentum (only) C. velocity and momentum (only) D. mass, velocity, and momentum
Answer:
Objects that are not moving have NO velocity and momentum (only)
Explanation:
This best explains the potential energy of an object, when an object is at rest. it is said to have possessed a potential energy but without velocity and momentum i.e energy at rest
Which numbers indicate the phases during which the moon is waxing?
A)1,5
B)2,3,4
C)5,6,7,8
D)2,3,4,5,6,7
Answer:
A
Explanation:
it is just right
How do you find the value of e?
refractive index = sin i / sin e
where i is the angle of incidence
e is the angle of refraction
1.5 = sin 35 / sin e
1.5 = 0.5736/sin e
sin e = 0.5736/ 1.5
sin e = 0.3824
e = 22.48°
The moon’s relative motion causes
Answer: Different cycles of the moon and ocean currents are all I can think of.
Answer:
Different cycles of the moon and ocean currents.
Explanation:
what device is made of coils of wire with an electrical current passing through it in order to generate a magnetic field
Transformer
Explanation:
A transformer is a device with two or more magnetically coupled windings. A time varying current in one coil (primary winding) generates a magnetic field which induces a voltage in the other coil (secondary winding). Transformers are capable of either increasing or decreasing the voltage and current levels of their supply, without modifying its frequency, or the amount of electrical power being transferred from one winding to another via the magnetic circuit. There are two types of transformer:
1. Step up transformer - increases voltage
2. Step down transformer - decreases voltage
When a light ray passes from LESS dense water (n = 1.33) into a MORE dense diamond (n = 2.419) at an angle of 45 degrees, its path is bend _____ the normal.
Towards
Explanation:
When light is incident at a transparent surface, the transmitted component of the light changes direction at the interface. Another component of the light is reflected at the surface. When a ray of light passes from water to diamond at an angle 45°, its path is bent towards the normal. This is so because water is less dense than the diamond. The refractive index of water (n = 1.33) is less than the refractive index of diamond (n = 2.419).
Light passing from less dense water to more dense diamond bends towards the normal due to a significant change in refractive indices.
When a light ray passes from less dense water (n = 1.33) into more dense diamond (n = 2.419) at an angle of 45 degrees, its path is bent towards the normal.
To calculate the angle of refraction, we can use Snell's Law: n1sinθ1 = n2sinθ2. Given n1 (water) = 1.33, n2 (diamond) = 2.419, and θ1 = 45°, we can solve for θ2.
The larger change in direction in diamond compared to water is due to the significant difference in refractive indices, leading to a greater impact on the path of the light ray.
In lab, your instructor generates a standing wave using a thin string of length L = 1.65 m fixed at both ends. You are told that the standing wave is produced by the superposition of traveling and reflected waves, where the incident traveling waves propagate in the +x direction with an amplitude A = 3.65 mm and a speed vx = 13.5 m/s . The first antinode of the standing wave is a distance of x = 27.5 cm from the left end of the string, while a light bead is placed a distance of 13.8 cm to the right of the first antinode. What is the maximum transverse speed vy of the bead?
The given standing wave on a string has a wavelength (λ) of 0.55 m, a frequency (f) of 24.54 Hz, a wave number (k) of 11.46 rad/m, and an angular frequency (ω) of 154.3 rad/s. The displacement of the bead at its position is given by the wave equation, and the maximum transverse speed (vy_max) is estimated to be approximately 0.4 m/s.
Length of the string (L) = 1.65 m
Amplitude of the traveling wave (A) = 3.65 mm
Speed of the traveling wave (vx) = 13.5 m/s
Distance of the first antinode from the left end (x) = 27.5 cm
Distance of the bead from the first antinode (d) = 13.8 cm
2. Finding the wavelength (λ):
Since the antinode is the point of maximum displacement, the first antinode is located at half the wavelength from the fixed end. Therefore,
λ = 2 * x = 2 * 0.275 m = 0.55 m
3. Finding the frequency (f):
We can use the relationship between wave speed, wavelength, and frequency:
v = λf
f = v / λ = 13.5 m/s / 0.55 m = 24.54 Hz
4. Finding the wave equation:
The equation for a standing wave on a string can be written as:
y(x, t) = A sin(kx) cos(ωt)
where:
k = wave number (k = 2π/λ)
ω = angular frequency (ω = 2πf)
5. Finding the wave number (k):
k = 2π/λ = 2π / 0.55 m = 11.46 rad/m
6. Finding the angular frequency (ω):
ω = 2πf = 2π * 24.54 Hz = 154.3 rad/s
7. Finding the displacement of the bead at its position:
The bead is located at x = x1 + d, where x1 is the distance of the first antinode from the left end (0.275 m) and d is the distance of the bead from the first antinode (0.138 m).
x1 + d = 0.275 m + 0.138 m = 0.413 m
Substitute this value of x in the wave equation:
y(0.413 m, t) = 3.65 mm * sin(11.46 rad/m * 0.413 m) * cos(154.3 rad/s * t)
8. Finding the maximum transverse speed (vy):
The maximum transverse speed occurs when the derivative of the displacement with respect to time (dy/dt) is at its maximum.
vy(t) = dy/dt = -Aω * cos(kx) sin(ωt)
The maximum value of sin(ωt) is 1, and the maximum value of cos(kx) depends on the position of the bead. Since the bead is not at a node or antinode, cos(kx) will not be 0 or 1.
Therefore, the maximum transverse speed (vy_max) can be estimated as:
vy_max ≈ Aω ≈ 3.65 mm * 154.3 rad/s ≈ 0.4 m/s
Four ball are simultaneously launched with the same speed from the same height and h above the ground. At the same instant, ball 5 is released from the rest at the same height. Rank in order, from shortest to longest, the amount of time it takes each of these balls to hit the ground ( some maybe simultaneously.)
In this scenario of Physics involving free fall and projected motion, all the balls launched, whether from rest or different angles, from the same height will hit the ground simultaneously. The time of flight in such a case, considering no air resistance, will only depend on the initial height from the ground and the acceleration due to gravity, not on the initial speed or direction of projection.
Explanation:The question pertains to the physics concept of free fall and their time of flights. To reiterate, all the balls are being launched from the same height, h, including ball 5 which is released from rest. According to physics, irrespective of their initial velocities or launch angles, all objects in free fall will hit the ground at the same time assuming they are dropped from the same height. This is because the time a projectile is in the air is governed by its vertical motion alone and in this scenario, all the balls have the same vertical component which is the same height from which they are dropped. So, all of the balls including ball 5 will hit the ground simultaneously.
This understanding is backed by two key principles. One, that the horizontal and vertical motions of a projectile are independent of each other, meaning the horizontal velocity does not affect the vertical fall. Two, that the time of flight of a projectile is linearly proportional to the initial velocity in the y direction (height in this case) and inversely proportional to g (acceleration due to gravity). Considering the fact that all the balls start from rest, have the same height, and experience the same acceleration due to gravity, the time of flight for all balls becomes equal.
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I need help for this exercise:
Crumple zones in cars increase the time and the distance over the which a car stop during a collision. The length of the crumple zone is 1.6m.
a) Find the maximum speed that the car could have when hitting a wall head-on without subjecting the passager to an acceleration of more than 46.2g (i.e., 46.2 times the acceleration due the gravity)
b) How long would that collision last?
Answer:
a) The maximum speed is 38 m/sb) The collision would last 0.083 s
Explanation:
By increasing the time and the distance over which a car stops during a collision, the change in the velocity (acceleration) is reduced, reducing, in consequence, the impact.
The equation to determine the change in velocity for a uniformly accelerated motion is given by the relation between the speed, the distance, and the acceleration:
v² - u² = 2×acceleration × distanceThe acceleration must be less than or equal to 46.2g, which is 46.2 × 9.8m/s² = 452.76m/s². Thus, the condition is acceleration ≤ 452.76m/s²
Here, using the maximum acceleration:
u = final velocity = 0acceleration = 457.76m/s²distance = 1.6 mThus:
v² = 2 (457.76m/s²) × 1.6mv = 38.06m/sv = 38 m/sTo determine the time use the impulse notion.
Impulse = Force × ΔtChange in momentum = mass × ΔvImpulse = Change in momentumForce × Δt = mass × ΔvForce / mass = Δv / Δtacceleration = Δv / ΔtSince the final velocity is 0 (the car stops), Δv is the speed of the car: Δv = v.
Substitute:
v/Δt = 457.76 m/s²Δt = v / 457.76 m/s²Δt = (38 m/s) / (457.76m/s²) = 0.083sin which medium does sound travel the fastest
Answer:
Solids
Explanation:
Aluminum
Explanation:
Desiree has a scientific question that she wants to investigate. She has developed a hypothesis and method for her experiment. Which step of scientific inquiry should Desiree take next?
Desiree should present her findings to her teacher and classmates.
Desiree should collect data, which may support or refute her hypothesis.
Desiree should provide an explanation for her results.
Answer:
Desiree should collect data, which may support or refute her hypothesis.
Explanation:
The next step Desiree must take is to collect data which might likely support or refute her hypothesis.
This is usually done by carrying out experiments or field studies.
The scientific method provides the steps through which knowledge of science is investigated. It usually starts with observation. After an observation is made, a scientific question is asked. This leads to the development of hypothesis. Then, experiments are carried out and data collect to either bolster the claim or refute it. Interpretation follows and conclusion is draw.Desiree should proceed to the step of collecting data, which may support or refute her hypothesis. Therefore option B is correct.
Collecting data is a crucial stage in the scientific inquiry process. It involves conducting experiments or observations to gather information that can either confirm or contradict the hypothesis she has formulated.
By systematically collecting and analyzing data, Desiree can draw conclusions based on empirical evidence. This step forms the backbone of scientific investigation as it provides the tangible information required to validate or revise her hypothesis.
Once she has sufficient data, Desiree can move on to analyzing her results and drawing meaningful conclusions, paving the way for the interpretation and potential communication of her findings.
Therefore option B is correct.
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which type of energy is stored in a stretched string on the bow in the following figure
Answer:
potential energy
Explanation:
Answer: Elastic Potential Energy
Explanation: For stretched material such as ropes or strings they have a certain form of energy that allows them to stretch or compress. The energy is called elastic energy. For the case of the string on the bow it possess Elastic Potential Energy since there is no motion in the string.
Why and how is oil used to reduce the effects of friction in large machines
By reducing friction
Explanation:
A big machine is composed of several moving and stationary parts. Some of these parts are in a state of constant motion hence they periodically rub against each other. The friction between the body parts causes the body part to wear out and heat up in the process. This heat is symbolic of waste of energy.
The lubricating agents are a saviour in such conditions. Lubricating oils with high viscosities reduces friction. If we go deep into the working of the lubrication we find that the interacting parts of machines are quite rough when viewed under microscope. These rough surfaces when interact produce bumpy motion, wear and tear, heat etc.
Oil fills these microscopic voids and thus provides temporary relief. When these lubricated body parts interact, they encounter plain surface with decreased friction (due to high viscosity of the oils) and thus glide over each other freely thereby producing smooth movements, noiseless working.
A sample of gas has a volume of 42 L at a pressure of 200 kPa and a temperature of 30^ * C . What would be the volume, if the pressure were increased to 250 kPa and the temperature were decreased to 5^ * C ?
Answer:
30 L
Explanation:
Ideal gas law:
PV = nRT
Rearranging:
PV / T = nR
Since n and R are constant:
P₁ V₁ / T₁ = P₂ V₂ / T₂
Plugging in values and solving:
(200 kPa) (42 L) / (30 + 273.15 K) = (250 kPa) V / (5 + 273.15 K)
V = 30.8 L
Rounded to one significant figure, the new volume is 30 L.
A cetain car weighs 25,000 N. Calculate the mass of the car.
245.000 kg
25,000 kg
9.81 m/s2
2,500 kg
Answer:2500kg
Explanation:
Weight of car(w)=25000N
Acceleration due to gravity approximately(g) 10m/s^2
Mass=w/g
Mass=25000/10
Mass=2500kg
a current-carrying wire has the maximum magnetic force in it when it is placed in a constant magnetic field when
Answer:
Maximum magnetic force on current carrying wire when wire is placed at 90 degree with magnetic field
Explanation:
As we know that the magnetic force on current carrying conductor is given as
[tex]\vec F = i(\vec L \times \vec B)[/tex]
here we have
[tex]F = i L Bsin\theta[/tex]
here we know that
[tex]\theta [/tex] = angle between length vector and magnetic field vector
so if we would like to have maximum magnetic force on the current carrying wire then
[tex]\theta = 90 [/tex]
so we have
[tex]F_{mex} = iLB[/tex]
If two objects with different masses are pushing each other, which exerts the greater force?
A. The object with the greater mass exerts the greater force on the smaller object because the larger object has more inertia.
B. It is impossible to tell which object exerts the greater force unless we know which object accelerates.
C. The object with the smaller mass exerts the greater force on the larger object because it requires more force to make the larger object move.
D. They both exert the same amount of force on each other regardless of their mass, but in opposite directions.
Answer:
the answer is 100% A
Explanation:
Answer:
If two objects with different masses are pushing each other, which exerts the greater force?
The object with the greater mass exerts the greater force on the smaller object because the larger object has more inertia.
Explanation:
A 63 kg astronaut drifting with 7.0 m/s to the right with
respect to a spacecraft uses a jetpack to slow down.
Suppose it takes 14.0 s to come to a stop with respect to the spacecraft. What is the force exerted by the jetpack?
Answer:
31.5N
Explanation:
M = 63kg, v = 7.0m/s t = 14.0s F =?
Force = Mass * acceleration
but acceleration = change in velocity / time
a = dV/dt
F = (63 * 7.0) / 14
F = 31.5N
To calculate the force exerted by the jetpack, we use the astronaut's deceleration and mass. The deceleration is obtained from the change in velocity (from 7.0 m/s to 0 m/s in 14.0 s). Applying Newton's second law, the force equals to the mass (63 kg) multiplied by the deceleration (-0.5 m/s²), resulting in a force of 31.5 newtons in magnitude.
Explanation:The question is asking to calculate the force exerted by a jetpack that an astronaut uses to come to a stop relative to a spacecraft. First, we'll use the formula for acceleration (a) which is the change in velocity (Δv) divided by the change in time (Δt). In this case, the astronaut decelerates from 7.0 m/s to 0 m/s in 14.0 s, so the acceleration is -7.0 m/s divided by 14.0 s, which equals -0.5 m/s² (the negative sign indicates deceleration).
The next step is to apply Newton's second law of motion: F = ma, where F is the force, m is the mass, and a is the acceleration. Plugging in the values we have: F = 63 kg * (-0.5 m/s²) = -31.5 N. The negative sign indicates that the force is in the opposite direction of the initial velocity, i.e., to the left if the initial movement was to the right.
The magnitude of the force exerted by the jetpack is 31.5 newtons.
Why is the speed of sound faster in a humid and warm sea-level rainforest compared to the top of Mount Everest?
Answer: Because the speed of sound varies depending on the medium and its temperature.
Explanation:
Sound is a mechanical wave, this means its velocity of propagation depends on the medium.
Now, in general sound waves travel faster in solids than in liquids or gases. In addition, it varies with changes in the temperature of the medium. This is because an increase in temperature means that the frequency of interactions between the particles that transport the vibration increases, hence this increase in activity increases the speed.
So, the speed of sound in a gas (air, for example) is not constant, but depends on the temperature.
Hence, the higher the air temperature, the greater the velocity of propagation; that is why the speed of sound is faster in a humid and warm sea-level rainforest compared to the top of Mount Everest, which is cold.
2. A 1.00 x 103 kg sports car accelerates from rest to 25.0 m/s in 7.50 s. What is the
average power output of automobile engine?
a. 20.8 kW
b. 30.3 kW
C. 41.7 kW
Answer:
C = 41.7kW
Explanation:
Data ;
Mass (M) = 1x10³kg
Initial velocity (u) = 0m/s
Final velocity (v) = 25m/s
Time (t) = 7.5s
Power = Work / time
Work = force * distance
acceleration = average velocity/ time
Acceleration = (25 - 0) / 7.5 = 3.3m/s²
Power = force * velocity (speed)
Average velocity = (25 - 0) / 2 = 12.5m/s
Force = mass * acceleration = 1x10³ * 3.3 = 3333.33N
Power = force * velocity
Power = 3333.33 * 12.5 / 41666.67W
Answer:
C. 41.7 kW
Explanation:
car's acceleration is the velocity difference over time: a = (v1 - v0)/t = (25 - 0)/7.5 = 3.3 m/s^2
The avg. power P = F * v
The avg. speed is thus v = (v0 + v1)/2 = (0 + 25)/2 = 12.5 m/s
F = m * a = 1*10^3 * 3.3 = 3,333 N
P = 3,333 * 12.5 = 41,667 W = 41.7 kW
a heavy object falls with the acceleration as a light object during free fall. Why?
A heavy object falls with the acceleration as a light object during free fall because of acceleration due to gravity.
Explanation:
A motion can be termed as free fall when the object is completely under the influence of gravity. So in this case, no other force will be acting on the object other than the gravitational force. As the gravity influences the object in free fall, the acceleration attained by any object in free fall is same. And this acceleration is termed as acceleration due to gravity. Since, the gravity gives the acceleration to every object experiencing free fall, then the acceleration should be constant. Thus, a heavy object and a light object will have same acceleration during free fall.
5. In Ohm's Law, "\" stands for
it is measured in amps.
O current
O resistance
Answer:current is measured in amps
Explanation:
Current measured in amps
Answer:
Current
Explanation:
Obviously
what is nuclear radiation?
Answer:
noun. Physics. radiation in the form of elementary particles emitted by an atomic nucleus, as alpha rays or gamma rays, produced by decay of radioactive substances or by nuclear fission.
Explanation:
Nuclear radiation, or radioactivity, is energy and particles emitted by the nucleus in a nuclear reaction. It includes gamma-rays, alpha-particles, beta-particles, neutrons, and positrons. While useful in many areas, such as cancer detection and city powering, it can also pose health risks.
Explanation:Nuclear radiation, also known as radioactivity, is the energy and particles emitted by the nucleus during a nuclear reaction. It is a form of ionizing radiation, meaning the energy is sufficient to ionize matter, or change the structure of atoms.
Nuclear radiation includes gamma-rays (y-radiations), alpha-particles (a-particles), beta-particle (B-particles), neutrons (n), and positrons (3+-particles). These types of radiation originate from the radioactive decay of naturally occurring radionuclides.
While nuclear radiation is integral to many aspects of daily life, such as cancer detection, artifact study, city powering, it can also pose health risks. For instance, high doses of nuclear radiation can cause burns and hair loss.
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5. A 5.5 x10-6 C charge is located 0.28 m from a -3.5 x 10-6 C charge.
a) What is the magnitude of the force that the positive charge exerts on the negative charge?
b) If the negative charge was doubled, how would the force change?
(a) The magnitude of force that the positive charge exerts on the negative charge is - 2.209 N.
(b) If the negative charge is doubled, then the force will also get doubled.
The new force will be F = -4.418 N.
Explanation:
The force acting between two charged particles separated by a distance is termed as Coloumb's force or electrostatic force. It can be termed as electrostatic force of attraction if the the force acting between the charges are oppositely charged. And it can be termed as electrostatic force of repulsion if the charges are similar or like charges.
In the present case, there is a positive and negative charge, so electrostatic force of attraction will be acting between them. As per Coloumb's law, the electrostatic force of attraction is directly proportional to the product of charges and inversely proportional to the square of distance of separation.
[tex]F = \frac{kQq}{d^{2} }[/tex]
Here, k is the constant of proportionality which is equal to 9 ×[tex]10^{9}[/tex] and Q, q are the two charges, d is the distance of separation.
So here Q = 5.5 ×[tex]10^{-6} C[/tex] and q = - 3.5 ×[tex]10^{-6} C[/tex] and d = 0.28 m
Then, [tex]F=-\frac{9*10^{9}*5.5*10^{-6} * 3.5 * 10^{-6} }{(0.28)^{2} } = 2209.82*10^{-3}[/tex]
So the magnitude of force that the positive charge exerts on the negative charge is - 2.209 N.
(b) If the negative charge is doubled, then the force will also get doubled.
The new force will be F = -4.418 N.
The question requires the calculation of the electric force between two point charges using Coulomb's law and understanding how changes in the magnitude of one charge affect the force.
Explanation:The question involves understanding and applying Coulomb's law, which describes the electric force between two point charges.
a) Magnitude of the Force
To find the magnitude of the force that one charge exerts on another, we use the formula given by Coulomb's law:
[tex]F = k * |q1 * q2| / r^2[/tex]
Where:
F is the magnitude of the force between charges,k is the Coulomb's constant [tex](8.9875 x 10^9 N m^2/C^2),[/tex]q1 and q2 are the charges [tex](5.5 x 10^-6 C and -3.5 x 10^-6 C respectively),[/tex]r is the separation between the charges (0.28 m).Plugging in the values, we calculate F.
b) Effect of Doubling the Negative Charge
If the negative charge was doubled, the new charge would become [tex]-7.0 x 10^-6 C.[/tex] Since the force is directly proportional to the product of the two charges, doubling one of the charges would double the force as well.