To keep the center plate stationary, the bottom plate must move at 2 m/s to the left, counteracting the top plate's movement to the right at the same speed.
Explanation:Three large plates are separated by thin layers of ethylene glycol and water. The top plate moves to the right at 2m/s. To hold the center plate stationary, the velocity profile of the fluid layers between the plates indicates that for every action, there is an equal and opposite reaction according to Newton's third law. Given that the top plate moves at 2 m/s, to keep the center plate stationary, the bottom plate must also move at 2 m/s but in the opposite direction, which is to the left.
This setup demonstrates the principles of fluid dynamics, where the velocity gradient across the thickness of the fluid layers causes a shear stress that is directly proportional to the velocity gradient according to Newton's law of viscosity. The equilibrium of forces ensures the central plate remains stationary if the bottom plate's movement perfectly counterbalances the top plate's movement.
The bottom plate should move left at 2 m/s to keep the center plate stationary relative to the top plate.
To hold the center plate stationary, the relative velocity between the top and bottom plates should be zero. Since the top plate moves to the right at 2 m/s, the bottom plate must move to the left at the same speed to cancel out this motion.
The velocity of the bottom plate [tex](\(v_b\))[/tex] relative to the center plate is the sum of the velocities of the bottom plate relative to the top plate ( [tex]\(v_{b/t}\))[/tex] and the velocity of the top plate relative to the center plate
[tex](\(v_{t/c}\))[/tex] . Since [tex]\(v_{t/c}\)[/tex] is given as 2 m/s to the right, to make [tex]\(v_b\)[/tex] zero, [tex]\(v_{b/t}\)[/tex] should be 2 m/s to the left.
So, the bottom plate must be moved to the left at 2 m/s to hold the center plate stationary relative to the top plate. This ensures that the relative velocity between the top and bottom plates is zero, maintaining the center plate stationary.
def find_missing_letters(sentence): the input sentence is an array/list (created from normalize()) returns a sorted list of letters that are NOT in the sentence use the built in Python type set to solve (see previous lesson) def find_missing letters algorithm(sentence): the input sentence is an array/list (created from normalize()) returns a sorted array of letters that are NOT in the sentence you must NOT use the set type Hints for find_missing_letters algorithm: create your own algorithm and use only the data types (other than set) that we have discussed the set datatype is removed during the running of the tests (so don't use it) the output should be the same as that from find_missing_letters (easy to test) if you find yourself writing over 30 lines of code, you are proba
Answer:
Follow step by step explabation to get answer to the question and also see attachments for output.
Explanation:
code:
def normalize(input_string):
l=list();
for i in input_string:
if (i>='a' and i<='z') or (i>='A' and i<='Z'):
l.append(i.lower())
return l
def find_missing_letters_algorithm(sentence,prevsentece):
l=list();
for i in prevsentece:
i=i.lower();
if i not in sentence:
l.append(i)
return l
print(find_missing_letters_algorithm(normalize("O.K. #1 Python!"),"O.K. #1 Python!"))