Preserving confidentiality, integrity, and availability of data is a restatement of the concern over interruption, modification, and fabrication. How do the first three concepts relate to the last four? That is, is any of the four equivalent to one or more of the three? Is one of the three encompassed by one or more of the four?

Answer:A. ISSUE-SPECIFIC

Explanation:Security policy is a set of actions an organization,Country , State or local governments put in place on order to guarantee the security of life and properties. It can also be described as the restrictions on behavior or actions of members of a society, community or an organization as well as restrictions imposed on adversaries by processes such as doors, locks, keys and walls.

Issue specific policy are policies directed to treat or handle particular factors known to aid or abate a crime. It can also be used to outline or reach at an understanding of what to used or what not to use in order to ensure effective security in an organization.

Answer:

c

Explanation:

because only certain amount of laptops/pc's can vairy between all the internet data networks. most laptops and pc's run on WPA only because its cheaper and it has a better efficiency at running the fomain faster than most other networks. they are also most common for the most reliable updates. WEPD is not really a popular domain that most people use, but it is really common if they live in big cities where multiple users are basing off the same internet company ( a.k.a workspaces/offices). And when the DHCP scope is full that basically means that in a DHCP server, a scope is configured to determine the address pool of IPs that the server can provide to DHCP clients. Scopes determine which IP addresses are provided to the clients. They should be defined and activated before DHCP clients use the DHCP server for its dynamic IP configuration.

Answer:

The cpp program for the scenario is given below.

#include <iostream>

using namespace std;

int main() {

   // array to store seven test scores

   double scores[7];

   // variable to store sum of all test scores

   double sum=0;

   // variable to store average of all test scores

   double avg_score;

   // user is prompted to enter seven test scores

   cout<<"Enter the test scores ";

// user input is taken inside for loop

// for loop executes seven times to take input for seven test scores

   for(int j=0; j<7; j++)

   {

       cin>>scores[j];

       sum = sum + scores[j];

   }

// average of test scores is calculated and assigned

   avg_score = sum/7;

   cout<<"The average of all entered test scores are "<< avg_score <<endl;

   return 0;

}

OUTPUT

Enter the test scores 90

88

76

65

56.89

77.11

68

The average of all entered test scores are 74.4286

Explanation:

The program execution is explained below.

1. An array, scores, is declared of size seven to store seven user-entered test scores.

2. Variables, sum and avg_score, are declared to store the sum and average of all the seven test score values. The variable sum is initialized to 0.

3. User is prompted to enter the test scores using cout keyword.

4. Inside for loop, all seven test scores are stored inside array, scores, using cin keyword.

5. Inside the same for loop, the values in the array, scores, are added and assigned to the variable sum.

6. Outside the for loop, the average score is calculated and assigned to the variable avg_score.

7. At the end, the average score is displayed. New line is inserted using endl after the average score is displayed.

8. In order to store decimal values, all variables and the array are declared with double datatype.

9. The main() has return type of integer and thus, ends with a return statement.

10. The iostream is included to enable the use of keywords like cin, cout, endl and others.

Answer:

c) put a $ in front of the letter and number that represents the cell position.

Explanation:

Dollar sign ($) is used to lock the formula in the cell. This is called absolute reference. In this type of referencing, A dollar sign is place in front of the letter and number to lock that cell. Whenever we copy that cell, the formula will be copied in other cell without changing its reference number.

As

Example 1

C1 = A1 + B1

if we copy this formula in C2 then it becomes

C2= A2 + B2

there both reference of A and B has been changed.

Example 2

If we put $ sign as

C1= $A$1 + $B$1

now of we copy C1 and into C2

C2= $A$1 + $B$1

There reference of cell is not changed.

To freeze a cell in Excel, use the dollar sign ($) in front of the letter and number of the cell position. For example, if the total cell is A1, change it to $A$1. This technique ensures Excel maintains the cell reference when copying the formula.

To freeze a total cell in Excel so that it doesn't change when copied, you should use the dollar sign ($) in front of the letter and number that represent the cell position. This operation is commonly referred to as cell referencing. For instance, if your total cell is A1, you would change it to $A$1 to freeze it.

The dollar sign instructs Excel to maintain the reference to the specific cell when you copy the formula to other cells. Without the dollar sign, Excel will adjust the formula to refer to relative cells. Therefore, option (c) is the correct technique for freezing the total cell in Excel.

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14.0

Using the level of precedence in Java,

From left to right;

(i) the first division operation will be done.

(ii)followed by the second division operation.

(iii)followed by the first multiplication operation.

(iv)followed by the third division operation.

(v)followed by the second multiplication operation.

(vi) followed by the first addition operation.

(vii)lastly followed by the second addition operation.

=================================================

Taking the steps above one after the other;

(i) the first division operation will be done (i.e 19 / 2)

=> Integer division in Java gives an integer result. Therefore, 19 / 2 = 9.5 will give 9.

So,

=> 19 / 2 / 2.0 + 2.5 * 6 / 2 + 0.5 * 4

=> 9 / 2.0 + 2.5 * 6 / 2 + 0.5 * 4

(ii)followed by the second division operation. (i.e 9 / 2.0)

=> From the result from step (i), the second division operation is now 9 / 2.0.

=> 9 / 2.0 = 4.5

So,

=> 9 / 2.0 + 2.5 * 6 / 2 + 0.5 * 4

=> 4.5 + 2.5 * 6 / 2 + 0.5 * 4

(iii)followed by the first multiplication operation. (i.e 2.5 * 6)

=> The first multiplication operation is given by 2.5 * 6

=> 2.5 * 6 = 15.0

So,

=> 4.5 + 2.5 * 6 / 2 + 0.5 * 4

=> 4.5 + 15.0 / 2 + 0.5 * 4

(iv)followed by the third division operation. (i.e 15.0 / 2)

=> The third division operation is given by 15.0 / 2

=> 15.0 / 2 = 7.5

So,

=> 4.5 + 15.0 / 2 + 0.5 * 4

=> 4.5 + 7.5 + 0.5 * 4

(v)followed by the second multiplication operation. (i.e 0.5 * 4)

=> The second multiplication operation is given by 0.5 * 4

=> 0.5 * 4 = 2.0

So,

=> 4.5 + 7.5 + 0.5 * 4

=> 4.5 + 7.5 + 2.0

(vi) followed by the first addition operation. (i.e 4.5 + 7.5)

=> The first addition operation is given by 4.5 + 7.5

=> 4.5 + 7.5 = 12.0

So,

=> 4.5 + 7.5 + 2.0

=> 12.0 + 2.0

(vii) lastly followed by the second addition operation. (i.e 12.0 + 2.0)

=> The second addition operation is given by 12.0 + 2.0

=> 12.0 + 2.0 = 14.0

So,

=> 12.0 + 2.0

=> 14.0

Therefore, 19 / 2 / 2.0 + 2.5 * 6 / 2 + 0.5 * 4 = 14.0

In Java, the order of precedence for arithmetic operators is;

=> /, * and %

=> followed by + and -

Answer:

a ) The bandwidth-delay is 160,000 bits.

b)The maximum number of bits at a given time will be 160,000 bits.

c ) The maximum number of bits on the transmission line is equal to the product of he bandwidth and the delay

d) The length is 125 meters which is longer than a football field

e) The general expression is given as  [tex]\frac{S}{R}[/tex]

Explanation:

                 Step-by-Step Explanation

(a) We are old from he question that A and B are connected with a direct link.

  The length between A and B  is given as ( d )[tex] = 20,000 Km = 2×10⁷ meters  [/tex]       given that (1 Km = 10³ )

  The rate of transmission on the direct connection between A and B

   Denoted as (R) = 2 Mbps = 2 × 10⁶bps  given that (1Mbps = 10⁶bps)

  Speed of propagation of the link between A and B

  Denoted as (S)  = 2.5 × 10⁸ meters/sec

  Formula to calculate propagation delay denoted as dₐ =  [tex]\frac{D}{S}[/tex]

            dₐ = [tex]\frac{D}{S}[/tex]

                 =  [tex]\frac{2 * 10 ^7}{2.5*10^8}[/tex]

                 =   0.08 sec

         We multiply the rate of transmission with the propagation delay to get the bandwidth delay

i.e.  R × dₐ = (2 × 10⁶)  × 0.08

                 =  16 × 10⁴ bits

Hence the bandwidth delay is given as 160,000 bits.

Step 2 :

b)   From the question we are given that file is been transmitted from host A to host B consistently as one large message.

      Given that the size of the file o be transmitted is  =800,000 bits

                = 8 × 10⁵bits

     The rate of transmission of the direct connection between A and B (R)

                = 2 Mbps

                = 2 × 10⁶bps   (Given that 1Mbps = 10⁶ bps)

              Note : That the maximum number of bits the connection can carry is not dependent on the file size

but on the bandwidth -delay i.e (R * da). It is also equal in value hence

At a given time the maximum number of bits is equal to the bandwidth product delay = 160,000 bits

Step 3

c) The highest number of bits on the link between A and B is gotten from the product of bandwidth and delay

Step 4:

Given from the question that the propagation speed of the connect A and B (S) = 2.5 × 10⁸ meters/sec

The rate of transmission through the direct connection between A and B (R) = 2 Mbps

    = 2 × 10⁶ bps (Given that 1Mbps = 10⁶ bps)

We then have that the length of 1 bit on the link can be calculated with the formula [tex]\frac{S}{R}[/tex]

  Length of 1 bit  = [tex]\frac{S}{R}[/tex]

                            = [tex]\frac{2.5 * 10^8}{2*10^6}[/tex]

                           = 125 m/bit

We can see from the answer that the length of 1 bit is longer than a football field

Step 5:

We can deduce the width of a bit by looking at the unites of the given parameters

Unit for the  length of the link = m meters

Unit of propagation speed = S m/s

the transmission rate is  = R bps

Note :Width of a bit is not dependent on the length but on the propagation speed and the rate of transmission and it is the ratio these parameter

Hence the width of a bit is given as = [tex]\frac{S}{R}[/tex]

Answer:

a)

int: [10, 20, 10, 5]

out: [0, 10, 20, 10]

b)

int: [8, 2, 9, 7, -1, 55]

out: [0, 0, 8, 9, -1, 55]

c)

int: [0, 16, 9, 1, 64, 25, 25, 14]

out: [0, 0, 0, 0, 16, 9, 64, 25]

Explanation:

What the code is doing is changing the list if and only if the item number i, where i is an odd position on the list, is greater than the item number i-1. If the condition mentioned is satisfied, the element number i is removed, and a zero is added to the beginning of the list; this is why the dimension of the input is equal to the output (for every element removed a zero is added).

Note:

Answer:

Correctly position the platen of the printer to hold the paper in place.

Explanation:

Since the dot matrix printer is printing dark and clear on the left of the paper but very light on the right side of the paper, it is possible that the paper is not being held properly. So adjusting the platen will hold the paper properly and hence uniform prints on the paper.

Note: Dot matrix printers are printers that print closely related dots to form require texts (shapes) by striking some pins against an ink ribbon.

Some of the parts of these printers are; power supply, carriage assembly, Paper sensor, ribbon, platen and pins.

Answer:

Program:

First_number = int(input("Enter first number")) # The first number is entered by the user.

second_number = int(input("Enter second number")) # The second number is entered by the user.

third_number = int(input("Enter Third number")) # The Third number is entered by the user.

if(First_number<second_number)and(second_number<third_number):# compare the first number with second number and the second number with the third number.

   store ='A' # assign the 'A' value on store variable.

else:

   store= 'D' # Assign the D value on store variable.

Output:

Explanation:

Final answer:

To check if three int values are in ascending order and assign 'A' or 'D' to a char variable accordingly, use the conditional operator in a single line of code after obtaining the int values from the user.

Explanation:

To determine if three integer values are in ascending order using the conditional operator, you can perform a comparison between them. If you have three variables, let's call them num1, num2, and num3, the ascending order condition would be num1 < num2 and num2 < num3. If this condition is true, the character 'A' is assigned to a character variable; otherwise, the character 'D' is assigned. With the conditional operator, it would look something like this:

char order = (num1 < num2 && num2 < num3) ? 'A' : 'D';

This single line checks the condition and assigns 'A' to order if the numbers are in ascending order, or 'D' if they are not. It's important to ensure that you retrieve the integer values from the keyboard correctly and store them in the variables num1, num2, num3 before evaluating the conditional expression.

Answer:

C. CMR systems

Explanation:

CMR or customer relationship management is a strategy that uses data analysis of customers to manage the interaction between a company and current and potential customers.

It analyses the data of client from different channels like wesites, email, social media,telephone log etc, describing and predicting potential decisions to be made to enhance customer service and acquisition.

Answer:

Java code is given below with appropriate comments

Explanation:

import java.util.*;

public class Student

{

String ID, lastName;

//Arraylist to store courses

ArrayList courses = new ArrayList();

public Student()

{

//Default constructor

ID = "";

lastName = "";

}

public Student(String I, String l)

{

//Parameterized Constructor to initialize

ID = I;

lastName = l;

int i, n;

String temp;

Scanner sc = new Scanner(System.in);

System.out.print("\nHow many courses you want to add: ");

n = Integer.parseInt(sc.nextLine());

if(n < 3){ //Cannot choose less than 3 courses

System.out.println("\nNumber of courses must be at least 3.");

return;

}

for(i = 1; i <= n; i++)

{

System.out.print("\nEnter course name: ");

temp = sc.nextLine();

if(courses.contains(temp))//If course already present

{

System.out.println("\nCourse already present. Try another.");

i--;

}

else

{

courses.add(temp); //Adding course

}

}

}

//Accessors

public String getID()

{

return ID;

}

public String getName()

{

return lastName;

}

public ArrayList getCourses()

{

return courses;

}

//Mutators

public void setID(String i)

{

ID = i;

}

public void setName(String n)

{

lastName = n;

}

public void setCourses(ArrayList c)

{

courses.clear();

courses.addAll(c);

}

}

class StudentTest

{

//To store 10 students

Student[] list = new Student[10];

public StudentTest(){

int i, j, flag;

Scanner sc = new Scanner(System.in);

for(i = 0; i < 10; i++)

{

String temp, l;

System.out.print("\nEnter student ID: ");

temp = sc.nextLine();

flag = 1;

for(j = 0; j < i; j++)

{

if(list[j].getID().equals(temp))//If ID already exists

{

System.out.println("\nID already exists. Try another.");

flag = 0;

i--;

break;

}

}

if(flag == 1)

{

System.out.print("\nEnter student Last name: ");

l = sc.nextLine();

list[i] = new Student(temp, l); //Initializing student

}

}

}

public void sort()

{

//To sort and display

int i, j;

String temp;

ArrayList t = new ArrayList();

for(i = 0; i < 9; i++)

{

for(j = 0; j < 9 - i; j++)

{

if(list[j].getName().compareTo(list[j + 1].getName()) > 0)//If list[j + 1].lastName needs to come before list[j].lastName

{

//Swapping IDs

temp = list[j].getID();

list[j].setID(list[j + 1].getID());

list[j + 1].setID(temp);

//Swapping last names

temp = list[j].getName();

list[j].setName(list[j + 1].getName());

list[j + 1].setName(temp);

//Swapping courses

t.clear();

t.addAll(list[j].getCourses());

list[j].setCourses(list[j + 1].getCourses());

list[j + 1].setCourses(t);

}

}

}

//Display

System.out.println();

for(i = 0; i < 10; i++)

{

System.out.print(list[i].getID() + ", " + list[i].getName());

//Using fencepost loop to print with comma before

System.out.print(" " + list[i].getCourses().get(0));

for(j = 1; j < list[i].getCourses().size(); j++)

System.out.print(", " + list[i].getCourses().get(j));

System.out.println();

}

}

public static void main(String args[])

{

StudentTest S = new StudentTest();

S.sort();

}

}

Answer:

Answer explained below

Explanation:

Depending upon the current situation we can switch. That means suppose the entire project is mid way that means we already implemented the project by Waterfall methodology then it would take lot of time to switch to Prototype model. Again if we see the efficiency I mean if we complete the project using prototype model and the outcome would be very well and robust then we should definitely switch to prototype model. So depending on the scenario we need to decide whether it would be beneficial to switch or not.

Further, we have the differences between Waterfall and Prototype :

I) In case of Waterfall model requirements should be very well known. On the other hand in case of prototype model if the user requirements are not complete then we can choose prototype model.

II) Technical issues should be cleared in case of Waterfall model, on the other hand technical requirements need not be clear.

Advantages of Waterfall:

I) Easy to understand this model and easy to use.

II) It provides structure to inexperienced staff

III) Milestones are well understood

IV) Set requirements stability

Disadvantages of Waterfall Model:

I) All requirements must be known upfront

II) Inhibits flexibility

III) Can give a false impression of progree

Advantage of Prototype Model:

I) Even if user requirements are not complete we can use

II) Even if technical issues are not clear we can use

Disadvantage of Prototype:

I) The Model is complex

II) Risk Assessment expertise is required

III)Time spent for evaluating risks too large for small projects.

Answer:

C. Uninterrupted power supply.

Explanation:

Uninterrupted power supply or UPS is device that is connected to the main power supply of a system or a network of computer systems to provide power, when the main power supply is down. It promotes power redundancy for a reliable network.

Network cloaking device is used to hide a networks domain name, while it is being broadcast across.

The backup punch card is an outdated technology used for recording digital data.

Service level agreement is a documented agreement between the services providers and companies, on the method or form of service to be rendered.

Answer:

c.uninterruptible power supply

Explanation:

Disruption means disturbance or problems which interrupt an event, activity, or process.

Uninterrupted power supply helps to prevent our system from being interrupted while functioning.

Answer:

Yes, the software license is a major problem in cloud computing.

Explanation:

The ad network administrator or system administrator he or she has to buy hardware appliance such server, firewall protection and operating system and their licenses. Each purchase is addon cost to and depends on the organization decided on the investment process.

Moreover, the system administrator should do daily routine check the patches of the operating system and firewall and schedule checking has to be made and update the firewall. In case if any hijacking taking place he has to contact immediately the hardware firewall supplier or service provider for help

In clouds, all threats are taken care and the network administrator only has to check any new supporting software that has to update in the client pc or workstation and laptop.

As an investor of organizations has to compare cloud licenses cost and local hardware appliance and software licenses and has to make a decision.

Answer:

D

Explanation:

because it is a administrative procedure

Answer:

the answer is D. administrative procedure

Explanation:

that is the answer

Answer:

Answer explained with detail below

Explanation:

Consider the solution given by the greedy algorithm as a sequence of packages, here represented by indexes: 1, 2, 3, ... n. Each package i has a weight, w_i, and an assigned truck t_i. { t_i } is a non-decreasing sequence (as the k'th truck is sent out before anything is placed on the k+1'th truck). If t_n = m, that means our solution takes m trucks to send out the n packages.

If the greedy solution is non-optimal, then there exists another solution { t'_i }, with the same constraints, s.t. t'_n = m' < t_n = m.

Consider the optimal solution that matches the greedy solution as long as possible, so \for all i < k, t_i = t'_i, and t_k != t'_k.

t_k != t'_k => Either

1) t_k = 1 + t'_k

    i.e. the greedy solution switched trucks before the optimal solution.

    But the greedy solution only switches trucks when the current truck is full. Since t_i = t'_i i < k, the contents of the current truck after adding the k - 1'th package are identical for the greedy and the optimal solutions.

    So, if the greedy solution switched trucks, that means that the truck couldn't fit the k'th package, so the optimal solution must switch trucks as well.

    So this situation cannot arise.

  2) t'_k = 1 + t_k

     i.e. the optimal solution switches trucks before the greedy solution.

     Construct the sequence { t"_i } s.t.

       t"_i = t_i, i <= k

       t"_k = t'_i, i > k

     This is the same as the optimal solution, except package k has been moved from truck t'_k to truck (t'_k - 1). Truck t'_k cannot be overpacked, since it has one less packages than it did in the optimal solution, and truck (t'_k - 1)

     cannot be overpacked, since it has no more packages than it did in the greedy solution.

     So { t"_i } must be a valid solution. If k = n, then we may have decreased the number of trucks required, which is a contradiction of the optimality of { t'_i }. Otherwise, we did not increase the number of trucks, so we created an optimal solution that matches { t_i } longer than { t'_i } does, which is a contradiction of the definition of { t'_i }.

   So the greedy solution must be optimal.

Answer:

2 x 10⁵ bytes per second

Explanation:

Given:

MIPS rate = maximum speed of CPU to execute instructions = 10 million instructions per seconds

number of instructions required to transfer 1 byte using interrupt driven I/O = 50

Maximum number of bytes that can be transferred in 1 second = MIPS rate / number of instructions for 1 byte

=> max number of bytes = 10 million / 50 = 10 x 10⁶ / 50 = 2 x 10⁵

which is less than the maximum transfer rate of memory = 100 million bytes per second

So, maximum data transfer rate during I/O operations by using interrupt-driven I/O is 2 x 10⁵ bytes per second

Answer:

The answers are A and C.

Explanation:

To create a PDF quote document formatted using the company's branding guidelines, and automatically save it to the Opportunity record the developer must;

A .) Create a Visualforce page with custom styling.

C.) Install an application from the AppExchange to generate documents.

To create a PDF quote document formatted using the company's branding guidelines and save it to the Opportunity record, developers can choose between creating a visualforce page with custom styling or creating a visual flow that implements the company's formatting.

In order to create a PDF quote document formatted using the company's branding guidelines and save it to the Opportunity record, there are two recommended ways a developer can create this functionality:

Answer:

Contingency Planning Management Team (CPMT)

Explanation:

:)

Answer:

maxSum=findMax(numA,numB)+findMax(numY,numZ);

Explanation:

In the above statement, a function is used twice to calculate the maximum of 2 numbers passed as parameters of type double and returns the maximum value of type double as well. As the function is static, so, there is no need to make an object of the class in which the function is made. After finding the largest of both the pairs, the values are added and printed to console.

Answer:

maxSum = findMax(numA, numB); // first call of findMax

maxSum = maxSum + findMax(numY, numZ); // second call

Explanation:

Answer: A. True/false-Type of Busirness/entity and

B. True/false-User Location

Explanation

Business/entity and Usee location ia what considered when determining whether a business is too far based on the query and the user location

Answer:

The C code is given below with appropriate comments

Explanation:

#include <stdio.h>

int main()

{

//array declaration

int arr[3][7], cumulativeSum = 0;

//initialize the array

for(int i=0; i<3; i++)

{

for(int j=0; j<7; j++)

{

arr[i][j] = i+j;

}

}

//calculate the cumulative sum

for(int i=0; i<3; i++)

{

for(int j=0; j<7; j++)

{

if((arr[i][j] % 5) != 0)

{

cumulativeSum += arr[i][j];

arr[i][j] = 0;

}

}

}

//display the final array

printf("The final array is: \n\n");

for(int i=0; i<3; i++)

{

for(int j=0; j<7; j++)

{

printf("%d ", arr[i][j]);

}

printf("\n");

}

//display the cumulative sum

printf("\nCumulative Sum = %d", cumulativeSum);

return 0;

}

Answer:

click on the Reload or Refresh button

Explanation:

If you are having problems with a page that loads slowly or does not display correctly, you can refresh the page. Depending on which Internet browser you are using - Internet Explorer, Firefox or Chrome - the buttons may be in different areas of the screen or look slightly different. However, it does not matter if they are different since each button will give the same result: the web page you are viewing will reload or update.

Answer:

The correct answer is letter "B": masquerading.

Explanation:

The attack referred to as masquerading simply consists of impersonating the identity of an authorized user of an information system. The impersonation could take place electronically -the user has a login and password that does not belong to him to access a server- or personally -employees accessing restricted areas of a company.

b. masquerading attack is a threat to confidentiality.

Masquerade terms can be as follows:

Learn more: https://brainly.com/question/17085630

Answer and explanation:

While traveling abroad the main barrier to be considered is language. Entrepreneurs should focus special attention on developing mobile apps that interpret people's segments accurately so regardless of the country and language they can communicate through the app and make them feel they are "citizens of the world".

Hi, you haven't provided the programing language in which you need the code, I'll just explain how to do it using Matlab, and you can apply a similar method for any programming language.

Answer:

attendanceValues  = [attendanceValues(2:end),attendanceValues(end)]

Explanation step by step:

The program written shifts the row array of attendance values one position to the left, the program written in python 3 goes thus :

attendanceValues = [10, 20, 30, 40]

#the variable attendanceValues is a list of integers

shiftedValues = attendanceValues[1:], attendanceValues[-1]

#using list slicing, the value is selected from index 1 till the end and the last index value is added.

print(shiftedValues)

#displays the values in the shiftedValues list.

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Answer:

A  java Main arg0 arg1 arg2 arg3

Explanation:

The bee may travel to a different species of plant, so the pollen may not fertilize another flower. The wind can blow the dandelion seeds into an area where they can’t sprout. The squirrel might come back for the seeds it buried in the ground

NSX enhance logical switching, load balancing and microsegmentation which improves networking performance and operations.  

The performance starts in Layer 2, NSX manage routing even in virtual or cloud networks. Its firewall can support up to 20Gb traffic and monitoring all at once. Next work will in Layer 4 to 7, using SSL by making regular routine checks on network activities on this layer.  

As for security features, it uses microsegmentation which can make administrators manage policies of the network including making security groups.This would prevent previous attacks to happen again because NSX has firewalls that records and set policies in a network.

Answer:

The answer is explained below

Explanation:

The Organization mask is 21 so number of addresses granted to organization are 32 - 21 = 2048 addresses

Now, medium-size company has mask as 22 so number of addresses to medium-size organization are 32 - 22 = 1024 addresses

Each small organization has 32 - 23 = 512 addresses as mask is 23

That implies the range of addresses for each organization

Large Organization = 12.44.184.0/21 - 12.44.191.255/21

Medium organization = 12.44.184.0/22 - 12.44.187.255/22

small Organization 1: 12.44.188.0/23 - 12.44.189.255/23

small Organization 2: 12.44.190.0/23 - 12.44.181.255/23

so now if we have a router then we need to configure it so that when an address is routed correctly.

So router should be installed or configured for forward lookup which are defined in forwarding table

The forwarding table is configured o bases of longest prefix match

So Forward table will be:

00001100 00101100 10111110           small organization1

00001100 00101100 10111111           small organization2

00001100 00101100 1011110           medium-size organization

For each of them we can take an example in the range of its IP address and check this forwarding table  will correctly identify the other inner organizations

Answer:

The correct answer is letter "C": network intrusion detection system (NIDS).

Explanation:

A Network Intrusion Detection System (NIDS) is a network protection system configured to spot threats in any server connected to it. The NIDS has a history of common threats that is used to filter all the data flowing through the network. If malware is identified, an alert pops up with the suggested actions to follow in front of that case.