The person's weigh on Jupiter is 1326.52 N.
What is weight?Weight is a measurement of how much gravity is pulling on a body.
Weight is calculated using the formula: w = mg.
Given that weight is a force, its SI unit is also a force; hence, the SI unit of weight is the Newton (N). By examining the weight expression, we can see that it is dependent on mass and the acceleration caused by gravity.
Given that: a person weighs 500 N on Earth.
the acceleration due to gravity on Jupiter is 26 m/s^2.
Acceleration due to gravity on Earth is 9.8 m/s^2.
Hence, mass of the person
= Weight on Earth/acceleration due to gravity on Earth
=500 N/9.8 m/s^2.
= 51.02 kg.
Her weigh on Jupiter is
= mass of the person × acceleration due to gravity on Jupiter
= 51.02 kg × 26 m/s^2
= 1326.52 N.
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A youngster throws a rock from a bridge into the river 50 m below. The rock has a speed of 15 m/s when it leaves the youngster’s hand. Calculate the velocity of the rock when it strikes the water if it is thrown upward.
...?
A train travels at a velocity of +50 m/s. It takes 80 s to slow down to 5 m/s with constant acceleration. What was its acceleration?
This is a depiction of 2 forces acting on a puck (top view). Which direction would a 3rd force have to be to balance the forces? [picture below]
A force
F acts in the x - direction, its magnitude given by F = ax^2, where x is in meters and a =5.0N/m^2
. Find the work done by this force as it acts on a particle moving from x = 0 to x = 6.0 m.
The work done by a force can be calculated using the formula W = ∫F dx. In this case, we need to integrate the force function F = ax^2 and substitute the given values to find the work done.
Explanation:The work done by a force can be calculated using the formula:
W = ∫F dx
In this case, the force acting in the x-direction is given by F = ax^2. To find the work done by this force as the particle moves from x = 0 to x = 6.0 m, we need to integrate the force function with respect to x over the given range.
Using the formula for work, we have:
W = ∫(ax^2) dx
Integrating with respect to x, we get:
W = (a/3)x^3
Substituting the values of a and x, we can calculate the work done.
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Marcel is helping his two children, jacques and gilles, to balance on a seesaw so that they will be able to make it tilt back and forth without the heavier child, jacques, simply sinking to the ground. given that jacques, whose weight is w, is sitting at distance l to the left of the pivot, at what distance l1 should marcel place gilles, whose weight is w, to the right of the pivot to balance the seesaw?
Given that Jacques and Gilles have the same weight, Gilles should sit at the same distance as Jacques from the pivot for the seesaw to be in balance, meaning l1 (the distance for Gilles) equals l (the distance for Jacques).
Explanation:To solve this problem, we must remember that the seesaw is in equilibrium, which means all forces and torques balance out. Here, the principle of moments states that the total clockwise moment must equal the total anticlockwise moment. It implies that, for a seesaw to balance, the weight of each person (considered as force) must be multiplied by their distance from the pivot and the two results obtained must be equal.
Since Jacques and Gilles have the same weight (w), Jacques is sitting at a distance l, the distance l1 at which Gilles should sit is found by equating Jacques' product of weight and distance to Gilles'. Therefore, l1 = l. This confirms the intuition that if they both weigh the same, they should both sit at the same distance from the pivot for the seesaw to be in balance.
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Which of the following is not a carbohydrate?
A. Cellulose
B. Sugars
C. Starches
D. Cholesterol
The option that is not a carbohydrate is cholestrol, which is the option D.
D. Cholesterol
What is carbohydrate?Carbohydrate are organic compounds that are made of carbon, hydrogen and oxygen atoms, forming polar hydroxyl groups, (-OH). Carbohydrate are an important source of energy in an healthy diet. There are three main types of carbohydrates, namely; sugars, starch, and fibers.
Cholesterol is a waxy, faty chemical substance that is solid and white or light yellow. The chemical formula for cholesterol is C₂₇H₄₆O, hence cholesterol is a lipid, as it has few hydroxyl groups, (-OH)
The other compounds, cellulose, sugars, and starches are carbohydrates
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The planets are pulled towards the sun by?
If 3000ft/3 of air crossing an evaporator coil and is cooled from 75F to 55F, what would be the volume of air,in ft/3, exiting the evaporator coil?
The volume of air remains the same before and after passing the evaporator coil, which is 3000 ft³, as change in temperature does not affect the volume of air assuming constant pressure and amount of air.
Explanation:Given that the question is related to air volumes in relation to temperature changes, here we won't experience a change in volume of air due to the cooling process. According to the ideal gas law, assuming constant pressure and amount of air, a decrease in temperature does not change the volume of the air. Therefore, the volume of the air exiting the evaporator coil is still the same as the volume that entered it, which is 3000 ft³.
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To find the volume of air exiting the evaporator coil, you can use the ideal gas law. Plugging in the given values, the volume of air exiting the evaporator coil would be 2200 ft³.
Explanation:To find the volume of air exiting the evaporator coil, we can use the principle of conservation of mass. The initial volume of air is given as 3000 ft³ and the final temperature is 55°F. We can assume that the air behaves ideally, so we can use the ideal gas law to solve for the final volume of air.
Using the ideal gas law:
V1/T1 = V2/T2
Where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.
Plugging in the values:
V2 = (V1 * T2) / T1 = (3000 ft³ * 55°F) / 75°F = 2200 ft³
Therefore, the volume of air exiting the evaporator coil would be
2200 ft³
.
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What two forces can act on an object without touching it??
two crates, of mass 75kg and 110 kg are in contact and at rest on a horizontal surface. a 730 N force is exerted on a 75kg crate. if the coefficient of kinetic friction is 0.15, calculate (a) the acceleration of the system and (b) the force that each crate exerts on the other.
...?
To calculate the acceleration of the system, use Newton's second law of motion. The force exerted by each crate on the other is equal and opposite.
Explanation:To calculate the acceleration of the system, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. The net force acting on the system is the applied force minus the force of friction. So, the acceleration of the system can be calculated as:
Net force = Applied force - Force of friction
F_net = F_applied - F_friction
The force of friction can be calculated using the formula:
Force of friction = coefficient of friction * Normal force
Now, to calculate the force that each crate exerts on the other, we need to consider that the force exerted by one crate on another is equal in magnitude but opposite in direction. So, if we know the force exerted by one crate on the other, we can simply use Newton's third law of motion to find the force exerted by the other crate on the first crate.
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A roller-coaster car has a mass of 1200 kg when fully
loaded with passengers. As the car passes over the top of a circular
hill of radius 18 m, its speed is not changing. At the top of the
hill, what are the (a) magnitude FN and (b) direction (up or
down) of the normal force on the car from the track if the car’s
speed is v 11 m/s? What are (c) FN and (d) the direction if v
14 m/s?
Final answer:
At the top of the hill, the roller-coaster car experiences a normal force (FN) from the track that is equal to the gravitational force (mg). The direction of the normal force at the top of the hill is downwards. When the car's speed increases to 14 m/s, the magnitude of the normal force remains the same, but its direction stays downwards.
Explanation:
To determine the magnitude of the normal force (FN) and its direction at the top of the hill, we need to consider the forces acting on the roller-coaster car. At the top of the hill, the car's speed is not changing, meaning its acceleration is zero. This means that the net force acting on the car is zero. The only forces acting on the car at the top of the hill are the gravitational force (mg) and the normal force (FN) from the track.
(a) When the car's speed is 11 m/s, we can equate the gravitational force and the normal force:
mg = FN
Using the given mass of 1200 kg, we can calculate the magnitude of the normal force:
FN = mg = 1200 kg * 9.8 m/s^2 = 11760 N
(b) The direction of the normal force at the top of the hill is downwards (towards the center of the circular path), as it opposes the gravitational force pulling the car downwards.
(c) When the car's speed is 14 m/s, the magnitude of the normal force remains the same:
FN = mg = 1200 kg * 9.8 m/s^2 = 11760 N
(d) The direction of the normal force at the top of the hill is still downwards, as it continues to oppose the gravitational force.
(a) At a speed of [tex]\(v = 11 \ m/s\)[/tex], the magnitude of the normal force [tex](\(F_N\))[/tex] on the roller-coaster car at the top of the hill is [tex]\(9810 \ N\)[/tex] (upward).
(b) At a speed of [tex]\(v = 14 \ m/s\)[/tex], the magnitude of the normal force [tex](\(F_N\))[/tex] on the roller-coaster car at the top of the hill is [tex]\(7560 \ N\)[/tex] (downward).
Explanation:In circular motion, at the top of the hill, the centripetal force required to keep the car moving in a circular path is provided by the normal force [tex](\(F_N\)). At \(v = 11 \ m/s\)[/tex], the net force is zero as the car's speed is constant, so [tex]\(F_N\)[/tex] equals the gravitational force [tex](\(mg\))[/tex], resulting in [tex]\(F_N = 9810 \ N\)[/tex] (upward). This is because the normal force opposes the gravitational force and provides the centripetal force needed.
At [tex]\(v = 14 \ m/s\)[/tex], the normal force is directed downward. In this case, the centripetal force is greater than the gravitational force, leading to a net force directed toward the center of the circular path. The normal force now includes both the gravitational force [tex](\(mg\))[/tex] and the additional force required for centripetal acceleration. The magnitude of [tex]\(F_N\) is \(7560 \ N\)[/tex], and it is directed downward as the net force acts in the opposite direction to the gravitational force.
Understanding the dynamics involves recognizing that at different speeds, the balance between gravitational force and the force required for circular motion changes. At lower speeds, the normal force opposes gravity, while at higher speeds, it supplements gravity to provide the necessary centripetal force.
The earth's differentiation and size were significant factors for life on Earth because Earth's composition and gravitational attraction _____.
-keep the moon and sun in orbit
-keep people grounded
-helped to create and retain Earth's atmosphere
-create and retain internal heat
Final answer:
The Earth's differentiation and size have been crucial in maintaining a life-sustaining atmosphere due to its gravitational pull, which helps generate and preserve internal heat, and creates the greenhouse effect for temperature regulation.
Explanation:
The Earth's differentiation and size were critical in forming an environment suitable for life due to a combination of factors, primarily influenced by Earth's mass and gravitational forces. The composition and gravitational attraction of Earth have been instrumental in creating and retaining a protective atmosphere, which in turn has allowed for the development and sustenance of life. Differentiation is a process where gravity separates a planet's interior into layers, with heavier elements forming the core and lighter minerals forming the crust. Consequently, Earth's ability to generate and retain internal heat has contributed to the eventual development of not just an atmosphere, but one that is conducive to life, maintaining a balance of gases such as oxygen and carbon dioxide while shielding the planet from harmful radiation. Additionally, Earth's atmosphere acts as insulation, creating what's known as the greenhouse effect, which helps regulate the planet's temperature, preventing the oceans from freezing.
If element X has 99 protons, how many elctrons does it have?
Which element(s) is/are not balanced in this equation?
MgO+2 LiCI → MgCI2+Li2O
A.All elements are balanced
B.Mg
C.CI
D.Li
In A boat race, Dan drove his motorboat over the 1000-meter course from start to finish in 40 seconds. What was Dan's average speed during the race ?
In a boat race, Dan drove his motorboat over the 1000-meter course from start to finish in 40 seconds, and his average speed during the race was 25 meters per second.
What is the calculation of average speed?The average speed indicated that the person maintained a linear speed during a drive because the speed is not always maintained properly due to various factors on the person's path.
Dan's average speed during the race is the distance he covered divided by the time taken to cover the distance.
Dan's average speed during the race was,
Average speed = distance covered / time taken
Average speed = 1000 meters / 40 seconds
Average speed = 25 meters per second
Hence, the average speed during the race was 25 meters per second for Dan while driving the motor boat.
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What method of heat transfer does heat energy use to reach earth from the sun?
Answer: Radiation
Explanation:
Heat transfer through radiation. Radiation is one of the mode of heat transfer and is the transfer of heat from one body to another without passing through any intervening medium. It is the heat energy directly from the sun. This energy reaches the earth directly without obstruction.
Surface waves move only in a back and forth motion.
True
False
What is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.13?
Let us assume that pulley is mass less.
Let the tension produced at both ends of the pulley is T.
We are asked to calculate the acceleration of the block.
Let the masses of two bodies are denoted as [tex]m_{1} \ and\ m_{2}\ respectively[/tex]
[tex]Let\ m_{1} =1 kg\ and\ m_{2} =2 kg[/tex]
As per this diagram, the body having mass 1 kg is moving downward and the body having mass 2 kg is moving on the surface of the table.
Let the acceleration of each block is a .
For body having mass 1 kg:
The net force acting on 1 kg body will be-
[tex]m_{1} g-T=m_{1} a[/tex] [1]
Here tension in the rope will be vertically upward and weight of the body will be in vertical downward direction.
For body having mass 2 kg:
The coefficient of kinetic friction [tex][\mu]=0.13[/tex]
[tex]Hence\ the\ frictional\ force\ F=\mu N[/tex]
[tex]F=\mu m_{2} g[/tex]
Hence the net force acting on the body having mass 2 kg-
[tex]T-\mu m_{2} g=m_{2} a[/tex] [2]
Here the tension of the rope is towards right i.e along the direction of motion of the 2 kg block and frictional force is towards left.
Combining 1 and 2 we get-
[tex]m_{1} g-T=m_{1}a[/tex] [1]
[tex]T-\mu m_{2}g= m_{2} a[/tex] [2]
---------------------------------------------------
[tex][m_{1} -\mu m_{2} ]g=[m_{1} +m_{2} ]a[/tex]
[tex]a=\frac{m_{1}-\mu m_{2}} {m_{1}+ m_{2}}*g[/tex]
[tex]a=\frac{1-[2*0.13]}{1+2} *9.8\ m/s^2[/tex]
[tex]a=\frac{0.74}{3} *9.8\ m/s^2[/tex]
[tex]a=2.417 m/s[/tex] [ans]
The acceleration of a block subject to kinetic friction is determined by subtracting the force of friction from the gravitational force parallel to the surface and then dividing by the mass of the block. The force of friction is calculated by multiplying the normal force by the coefficient of kinetic friction.
Explanation:The acceleration of a block sliding on a surface with kinetic friction can be found by using Newton's second law, F = m*a, where F is the net force acting on the object, m is the mass, and a is the acceleration. Given that the coefficient of kinetic friction between the block and the table is 0.13, we first need to find the force of friction, which is the product of the coefficient of kinetic friction (μk) and the normal force (N). Assuming that the only forces acting on the block are gravity, the normal force, and friction, the force of friction can be subtracted from the component of the gravitational force along the inclined plane to get the net force. The net force is then divided by the mass of the block to obtain the acceleration.
To solve for acceleration, the following equations are generally used: Ffriction = μk * N and a = (Fgravity, parallel - Ffriction) / m. It's important to note that without the mass of the block or further details of the scenario, we cannot calculate a numeric answer.
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a particle is constrained to move along a straight line through O.
it starts initially at D, which is a fixed distance from O in the positive direction&moves at a constant velocity of 4ms^-1 for 15 sec. until; it is 100m from O for a furhter 25 sec, after which it travels in the opposite direction for 20 sec.
the total distance is 180m.
How far from O does the particle stop?
how do i draw a velocity–time graph?
and what is the final displacement of the particle from its initial position? ...?
The particle ends up 20 meters away from point O in the direction opposite to its initial movement, with a net displacement of -20 meters from its initial position. A velocity-time graph for the particle's motion would show constant velocities in positive and negative directions, with a stationary phase in between.
Explanation:The situation described involves a particle's motion along a straight line with a series of movements at different speeds and directions. To solve this question, we break down the motion into segments and analyze each part to determine the final position and displacement of the particle.
The particle moves at a constant velocity of 4 m/s for 15 seconds, covering a distance of 60 m (4 m/s * 15 s).Afterwards, it remains 100m away from O for 25 seconds, which doesn't affect its position.Finally, it moves in the opposite direction for 20 seconds. Without the velocity of this movement specified, we assume it continues at the previously stated velocity of 4 m/s, thus moving 80 m backwards (4 m/s * 20 s).The total movement towards O (+ direction) is 60m and then 80m away from O (- direction), resulting in the particle ending up 20m away from O in the direction opposite to its initial movement.
To draw a velocity-time graph, plot velocity on the y-axis and time on the x-axis. The graph will show a constant positive velocity of 4 m/s for the first 15 seconds, then a stationary phase (velocity = 0) for the next 25 seconds, followed by a constant negative velocity of -4 m/s for the last 20 seconds.
The final displacement of the particle from its initial position is a result of its entire journey, factoring in the direction of movement. Initially, it moved away from its starting point by 60m but then moved back towards it by 80m, resulting in a net displacement of -20m (20 meters in the direction opposite to the initial positive direction).
What is the purpose of the universal gravitation constant in newtons law of universal gravitation?
Explanation : According to the law, it says that F ∝ Mm ÷ R²
Where :
F = Gravitational forceM = Mass of the first bodym = mass of the second bodyR = Distance between the 2 bodiesFor calculating the gravitational force (F), we must have an equation. According to the law, we are ain't getting any equation. Hence, we must convert it by putting a constant.
A constant is any value that is fixed, and it won't change under any circumstance. And in this case, the value of the gravitational constant (G) is 6.67 x 10⁻¹¹.
Now, here comes the final equation : F = GMm ÷ R²
Where :
F = Gravitational forceG = Gravitational constant (6.67 x 10⁻¹¹)M = Mass of the first bodym = Mass of the second bodyR = Distance between the 2 bodiesHence, the main purpose of the universal gravitational constant (G) is to have an equation, which is F = GMm ÷ R².
Which of the following energy forms is associated with an object in motion?
potential energy
elastic potential energy
nonmechanical energy
kinetic energy
A 0.40kg object is attached to a spring constant 160N/m so that the object is allowed to move on a horizontal frictionless surface. The object is released from rest when the sprin g is compressed 0.15m find:
a) the force on the object and b) its acceleration at this instant.
The force on a 0.40kg object attached to a compressed spring is 24N, and its acceleration is 60 m/s^2 based on Hooke's Law and Newton's second law.
Explanation:A 0.40kg object is attached to a spring with a spring constant (k) of 160N/m and is set to move on a horizontal frictionless surface. When the spring is compressed 0.15m, we need to find the force on the object and its acceleration.
Force on the Object
The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is equal to the spring constant times the displacement from equilibrium (F = -kx). Since the displacement (x) is given as 0.15m, and k is 160N/m, the force is:
F = 160N/m * 0.15m = 24N.
Acceleration of the Object
Using Newton's second law (F = ma), the acceleration (a) can be found by dividing the force by the mass of the object. Given that the mass (m) is 0.40kg:
a = F/m = 24N / 0.40kg = 60 m/s2.
Therefore, at the moment the spring is released from being compressed by 0.15m, the force on the object is 24N and its acceleration is 60 m/s2.
Who invented the electric scoreboard
The electric scoreboard was invented by George A. Baird in 1908.
The electric scoreboard invention was a significant advancement in the way sports scores were displayed during games, making it easier for spectators to follow the progress of the game in real-time.
What is newton's first law of motion?
Answer:
If a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
Explanation:
A basketball player, who weighs 600 newtons, jump 0.5 meters vertically off the floor. Calculate her kinetic energy just before hitting the floor.
a)300J
b)3000J
c)9.81m/s^2
d)0
Answer:
300 J
Explanation:
[tex]v = \sqrt{2gh}[/tex]
[tex]KE = \frac{1}{2}mv^{2}[/tex]
——
[tex]v = \sqrt{2(9.81 m/s^{2})(0.5 m)}\\ v = 3.13[/tex]
[tex]KE = \frac{1}{2}(61.2 kg)(3.13 m/s)^{2}\\ KE = 300 J[/tex]
Kinetic energy of an object is calculated from its mass and velocity. The mass of the player is 61.2 g and the velocity is 3.13 m/s. Then the kinetic energy of the basketball player is 300 J.
What is kinetic energy?Kinetic energy of an object is generated by virtue of its motion. Kinetic energy depends on the mass and velocity of the body by the expression:
K = 1/2 mv².
Given the weight = 600 N
mass = 600 N/9.8 m/s²= 61.2 kg
height = 0.5 m
velocity = √2gh
= √(2×9.8 m/s² × 0.5 m ) = 3.13 m/s
Then, kinetic energy of the player = 1/2 61.2 kg × 3.13 × 3.13
k = 300 J.
Therefore, the kinetic energy of the basketball player is 300 J.
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Which of the following statements is true about solar eclipses?
There is a solar eclipse every month.
All solar eclipses are total.
Some solar eclipses are not total.
There can be 12 solar eclipses in a single year.
the captain of a ship views the top of a lighthouse at an angle of 60degree with the horizontal at an elevation of of 6 meters above sea level.five minutes later,the same captain of the ship views the top of the same lighthouse at an angle of 30degree with the horizontal.determine the speed of the ship if the lighthouse is known to be 50 meters above sea level. ...?
The speed of the ship is determined to be approximately 0.17 meters per second.
To determine the speed of the ship, we will need to use trigonometry to find the distances the ship travels over the 5-minute interval.
Given:
The height of the lighthouse (h) is 50 meters.The initial angle of elevation (θ₁) is 60 degrees.The final angle of elevation (θ₂) is 30 degrees.The height of the observer above sea level is 6 meters.First, find the initial horizontal distance (d₁) from the ship to the lighthouse using tan(θ₁):
tan(60°) = height difference / d₁
tan(60°) = (50 m - 6 m) / d₁
d₁ = (44 m) / tan(60°)
d₁ = 44 / √3 ≈ 25.4 meters
Next, find the final horizontal distance (d₂) from the ship to the lighthouse using tan(θ₂):
tan(30°) = height difference / d₂
tan(30°) = (50 m - 6 m) / d₂
d₂ = (44 m) / tan(30°)
[tex]d_2 = \frac{44}{\left( \frac{\sqrt{3}}{3} \right)} = 44 \cdot \sqrt{3} \approx 76.2 \, \text{meters}[/tex]
The distance traveled by the ship (Δd) is:
Δd = d₂ - d₁ ≈ 76.2 m - 25.4 m ≈ 50.8 meters
The time interval Δt is 5 minutes, which is 300 seconds.
Therefore, the speed (v) of the ship is:
v = Δd / Δt ≈ 50.8 m / 300 s ≈ 0.17 meters per second.
(a) Suppose that a NASCAR race car is moving to the right with a constant velocity of +93 m/s. What is the average acceleration of the car? (b) Twelve seconds later, the car is halfway around the track and traveling in the opposite direction with the same speed. What is the average acceleration of the car?
How is social status directly related to health care?
a. Wealthy Americans receive adequate medical care.
b. Poor Americans receive adequate medical care.
c. No one receives adequate medical care.
d. none of the above
Answer:
the answer is A) Wealthy Americans receive adequate medical care.
Explanation:
I got a 100 on the test on edge!
Social status can have an influence on access to healthcare, but it does not directly determine whether individuals receive adequate medical care. The most appropriate answer is none of the above.
The relationship between social status and healthcare is complex and multifaceted. Factors such as income, education, employment, insurance coverage, and systemic barriers can impact access to healthcare.
While individuals with higher social status or greater wealth may have more resources and options for healthcare, it does not guarantee that they will receive adequate or optimal medical care.
Conversely, individuals with lower social status or limited financial means may face barriers to accessing quality healthcare, but it does not mean they will not receive any medical care at all. The ability to receive adequate medical care is influenced by various individual and systemic factors, and it is not solely determined by social status.
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A snowmobile has an initial velocity of 3.0 m/s
Part 1: If it accelerates at the rate of 0.5 m/s/s for 7.0 sec, what is the final vel.?
Part 2: If it accelerates at the rate of -0.60m/s/s, how long will it take to reach a complete stop?
Answer:
Part a)
[tex]v_f = 6.5 m/s[/tex]
Part b)
[tex]t = 5 seconds[/tex]
Explanation:
Part a)
As we know that
[tex]v_f = v_i + at[/tex]
here we know that
[tex]v_i = 3 m/s[/tex]
[tex]a = 0.5 m/s^2[/tex]
[tex]t = 7.0 s[/tex]
so we will have
[tex]v_f = 3 + (0.5)(7.0)[/tex]
[tex]v_f = 6.5 m/s[/tex]
Part b)
if finally the snowmobile comes to rest
So here we can say that
[tex]v_f = 0[/tex]
[tex]v_i = 3.0 m/s[/tex]
[tex]a = -0.60 m/s^2[/tex]
so now we have
[tex]v_f = v_i + at[/tex]
[tex]0 = 3.0 - (0.60)t[/tex]
[tex]t = 5 s[/tex]