Find the areas of the parallelogram whose vertices are given below. ​A(negative 1​,4​) ​B(4​,0​) ​C(12​,3​) ​D(7​,7​) The area of parallelogram ABCD is nothing square units.

Answers

Answer 1

Answer:

So the parallelogram is in the first and second quadrants.

Step-by-step explanation:

From Exercise we have that the parallelogram have a vetrices:

A(negative 1​,4​) ​B(4​,0​) ​C(12​,3​) ​D(7​,7​). We use a site geogebra.org to plof a graph for the given parallelogram.

From the graphs we can see that the parallelogram is mostly in the first quadrant and smaller in the second quadrant. So the parallelogram is in the first and second quadrants.

Find The Areas Of The Parallelogram Whose Vertices Are Given Below. A(negative 1,4) B(4,0) C(12,3) D(7,7)

Related Questions

Lisa put tulips and roses into vases. Each vase has 12 flowers. The red vase has 7 tulips. the blue vase has twice as mnay roses as the red vase. How many roses are in the blue vase?

Answers

Answer:

10 roses

Step-by-step explanation:

Final answer:

To find the number of roses in the blue vase, we double the number of roses in the red vase. Since the red vase has 5 roses, the blue vase contains 10 roses.

Explanation:

The student's question is about determining the number of roses in the blue vase given certain conditions about the number of flowers in vases. We know that each vase has 12 flowers, the red vase has 7 tulips, and thus 5 roses because the total is 12. The blue vase has twice as many roses as the red vase, so we need to double the number of roses in the red vase to find that number.

Since the red vase has 5 roses, the blue vase will have twice as many, which is 10 roses.

Here's the calculation step by step:

Subtract the number of tulips from the total flowers in the red vase to find the number of roses: 12 flowers - 7 tulips = 5 roses.Multiply the number of roses in the red vase by 2 to find the number in the blue vase: 5 roses x 2 = 10 roses.

Solve the right triangle

Answers

SR =sin (angle) = opposite leg/ hypotenuse

sin(52) = SR/ 7.6

SR = 7.6 x sin(52)

SR = 5.988 ( round answer as needed.)

QR = cos(angle) = adjacent leg / hypotenuse

Cos(52) = QR/ 7.6

QR = 7.6 x cos(52)

QR = 4.679. ( round answer as needed).

Angle S = 180 - 90 -52 = 38 degrees

Determine if the statement is true or false. A system in echelon form can have more variables than equations. True False Justify your answer.

Answers

Answer:

Yes

Step-by-step explanation:

A system in echelon form can have more variables than equations. ... Every linear system with free variables has infinitely many solutions. True, a free variable can take any value, and so there are infinitely many solutions. Any linear system with more variables than equations cannot have a unique solution.

A quantity and its 2/3 are added together and from thesum 1/3 of the sum is subtracted, and 10 remains.What is the quantity?

Answers

Answer:

[tex]14\frac{1}{3}[/tex]

Step-by-step explanation:

Let's write this out as an equation. Let the unknown quantity be x:

[tex]x+\frac{2}{3} - \frac{1}{3} (x+\frac{2}{3}) = 10\\\\3x+2-x -\frac{2}{3} = 30\\\\9x+6-3x-2=90\\\\6x= 86\\\\x = \frac{86}{6} =\frac{43}{3} =14\frac{1}{3} \\[/tex]

Answer: the quantity is 9

Step-by-step explanation:

Let x represent the quantity.

A quantity and its 2/3 are added together. The 2/3 of the number is 2/3 × x = 2x/3

The sum of the quantity and its 2/3 would be

x + 2x/3 = (3x + 2x)/3 = 5x/3

From the sum, 1/3 of the sum is subtracted. 1/3 of the sum would be

1/3 × 5x/3 = 5x/9

Subtracting 1/3 of the sum from the sum, it becomes

5x/3 - 5x/9 = (15x - 5x)/9 = 10x/9

If the remainder is 10, it means that

10x/9 = 10

Crossmultiplying

10x = 9 × 10 = 90

x = 90/10

x = 9

Can some body pls help me

Answers

Answer:

Step-by-step explanation:

The diagram consists of different boxes if the same sizes. Each box is a square with sides measuring 1 cm. The area of each box would be

1 × 1 = 1cm^2

The area of the parallelogram is the total number of squares that it contains. To determine this, the first step is to count the total number of complete squares. Looking at the diagram, there are 11 complete squares. This means

11 × 1 = 11 square units.

The next step is to count the number of incomplete squares and divide by 2. The number of incomplete squares are 8

8/2 = 4

4 × 1 = 4 square units

The area of the parallelogram would be

11 + 4 = 15 square units

The list of individuals from which a sample is actually selected is called the sampling frame. Ideally, the frame should list every individual in the population, but in practice this is often difficult. A frame that leaves out part of the population is a common source of undercoverage.
Suppose that a sample of households in a community is selected at random from the telephone directory.
What types of people do you think are likely to live in these households?These people will probably be underrepresented in the sample. (Select all that apply.)1.People with extra time on their hands.2.People without the extra income to keep a phone line will largely comprise the population without a phone line.3.Very busy people or those interested in maintaining privacy will largely comprise those with unlisted numbers.4.People who do not like to take surveys are likely to live in these households.

Answers

Answer:

Step-by-step explanation:

answer to Step 1

Households with unlisted numbers or without telephones.

answer to Step 2

2.People without the extra income to keep a phone line will largely comprise the population without a phone line.

3.Very busy people or those interested in maintaining privacy will largely comprise those with unlisted numbers.

Find the matrix P that multiplies (x; y; z) to give (y; z; x). Find the matrix Q that multiplies (y; z; x) to bring back (x; y; z).

Answers

Answer:

[tex]P = \left[\begin{array}{ccc}0&1&0\\0&0&1\\1&0&0\end{array}\right][/tex]

[tex]Q = \left[\begin{array}{ccc}0&0&1\\1&0&0\\0&1&0\end{array}\right][/tex]

Step-by-step explanation:

[tex]P*\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}0&1&0\\0&0&1\\1&0&0\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}y\\z\\x\end{array}\right][/tex]

[tex]Q*\left[\begin{array}{c}y\\z\\x\end{array}\right]=\left[\begin{array}{ccc}0&0&1\\1&0&0\\0&1&0\end{array}\right] \left[\begin{array}{c}y\\z\\x\end{array}\right] = \left[\begin{array}{c}x\\y\\z\end{array}\right][/tex]

New drug strategies have centered on cholesterol ______ statins. Select one:
a. lowering b. raising c. destroying d. improving

Answers

Answer: lowering

Step-by-step explanation:

Statins are drugs that are administered in order to help reduce cholesterol level in the body. Statins achieves this by making it impossible for the body to have access to substances that helps to produce cholesterol. This drug reduces cholesterol up to 50% and are taken once every day. Examples includes rosuvastatin, pitavastatin, simvastatin.

Sarah inherited a sum of 1,539 dollars with an interest rate of 1% per year what is the accrued value after 5 years, 10 years, and 15 years. Show all work.

Answers

Answer:

The accrued value after 5 years is $1,605.95.

The accrued value after 10 years is $1,672.9.

The accrued value after 15 years is $1,739.85.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

[tex]E = P*I*t[/tex]

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

[tex]T = E + P[/tex].

In this problem, we have that:

[tex]P = 1539, I = 0.01[/tex]

Accrued value after 5 years

This T when t = 5. So

[tex]E = P*I*t[/tex]

[tex]E = 1339*0.01*5 = 66.95[/tex]

The total is

[tex]T = E + P = 66.95 + 1539 = 1605.95[/tex]

The accrued value after 5 years is $1,605.95.

Accrued value after 10 years

This T when t = 10. So

[tex]E = P*I*t[/tex]

[tex]E = 1339*0.01*10 = 133.9[/tex]

The total is

[tex]T = E + P = 133.9 + 1539 = 1672.9[/tex]

The accrued value after 10 years is $1,672.9.

Accrued value after 15 years

This T when t = 15. So

[tex]E = P*I*t[/tex]

[tex]E = 1339*0.01*15 = 200.85[/tex]

The total is

[tex]T = E + P = 200.85 + 1539 = 1739.85[/tex]

The accrued value after 15 years is $1,739.85.

A prize was awarded to 56 women and 642 men.
a. What fraction of the prize winners were​ women?
b. What fraction were​ men?
SIMPLIFY EACH plz

Answers

My work to your question

0
21
22
01:39:07
The cost, c, of a ham sandwich at a deli varies directly with the number of sandwiches, n. If c = $54 when n is 9, what is the
cost of the sandwiches when n is 3?
$18
$21
$27
$48
Mark this and return
Next
Submit

Answers

Answer:

$18

Step-by-step explanation:

The cost, c, of a ham sandwich at a deli varies directly with the number of sandwiches, n. c = $54 when n is 9

This means that to buy 9 sandwiches, it costs $54. So one sandwich costs 54/9 = $6.

What is the cost of the sandwiches when n is 3?

To buy three sandwiches, it costs $6*3 = $18.

So the correct answer is:

$18

Answer:A

Step-by-step explanation:

$18

the absolute value of a complex number z=a+bi, denoted |z|, is given by the formula
|z|=square root a^2+b^2.

find six distinct complex numbers (which are neither purely imaginary nor purley real) such that each has an absolute value of 7.

Answers

Step-by-step explanation:

You need to find six combinations of a and b such that a² + b² = 7.

a = 1, b = √6

a = √2, b = √5

a = √3, b = 2

a = 2, b = √3

a = √5, b = √2

a = √6, b = 1

Which of the following equations is also true?

Answers

Answer:

cos 38 = 17/c

Step-by-step explanation:

cos 38 = 17/c is the correct statement

Observations on burst strength (Ib/in2) were obtained both for test nozzle closure welds and for production canister nozzle welds. Test 7200 6100 7300 7300 8000 7400 7300 7300 8000 6700 8300 5250 5625 5900 5900 5700 6050 5800 6000 5875 6100 5850 6600 Cannister A comparative boxplot is given below. Test Nozde Cannister 5000 000006000 Bunt strength (b, m Comment on interesting features (the cited article did not include such a picture, but the authors commented that they had looked at one). (Select all that apply.) The production canister welds have consistently lower burst strengths than the test nozze welds. The production canister weids have much more variable burst strengths The test nozzle welds data contain 2 outliers. test nozzle welds have much more variable burst strengths. The production canister welds have much higher burst strengths. The production canister welds data contain 2 outiers.

Answers

Answer:

1) The production canister welds have consistently lower burst strengths than the test nozze welds.

2) The production canister weids have much more variable burst strengths.

3) The test nozzle welds data contain 2 outliers.

4) Test nozzle welds have much more variable burst strengths.

5) The production canister welds have much higher burst strengths.

6) The production canister welds data contain 2 outiers.

Step-by-step explanation:

Hello!

The boxplots summarize the information of test nozzle closure welds and production canister nozzle welds.

The boxplot for the test nozzle closure welds shows that the first quartile and second quartile are close to each other but the third quartile is more separated to them, meaning that the data contained in the box is asymmetric, the data seems to have less variability between C₁ and C₂ and more between C₂ and C₃, the box is right-skewed.

The left whisker is larger than the right one, there are no outliers in the sample, due to most of the data being comprehended below C₁, the overall distribution of the data set is left-skewed, with large variability.

The boxplot for production cannister nozzle welds shows that the box is small (the variability of the data set is low) and symmetric, with C₂ in the middle of it and C₁ and C₃ are equidistant to the second quartile.

The whiskers of the box are small but they have almost the same length, showing that there is the same amount of data in them, this adds to the overall symmetry of the data set.

Finally, this data set shows two outliers, these values are far from the box, meaning that they are relatively extreme unusual values in regards to the rest of the sample but their distance to the box seems to be equal wich adds to the conclusion of the symmetrical distribution, with low variability of the data set.

I hope it helps!

A person walks in the following pattern: 2.4 km north, then 1.9 km west, and finally 4.7 km south. (a) How far and (b) at what angle (measured counterclockwise from east) would a bird fly in a straight line from the same starting point to the same final point?

Answers

Answer:

a) Figure attached

b) For this case w have that A =(2.4 km)j, B= (-1.9 km) i , C= (-4.7 km)j

And the final position vector can be calculated adding the 3 vectors like this:

[tex] s = A +B+C[/tex]

[tex] s= (-1.9 km)i +(2.4 -4.7 km) j= (-1.9km)i + (-2.3 km)j[/tex]

We can find the magnitude of s like this:

[tex] |s| = \sqrt{(-1.9)^2 +(-2.3)^2}=2.983[/tex]

And then we can find the angle with this formula:

[tex] \theta = \tan^{-1} (\frac{-2.3 km}{-1.9 km})=50.44 [/tex]

The other possibility is [tex] \theta = 50.44+180 =230.44[/tex]

And since they want the angle measured from East the correct angle would be [tex] \theta = 230.44[/tex]

Step-by-step explanation:

Part a

On the figure attached we have the vectors for the pattern described.

Part b

For this case w have that A =(2.4 km)j, B= (-1.9 km) i , C= (-4.7 km)j

And the final position vector can be calculated adding the 3 vectors like this:

[tex] s = A +B+C[/tex]

[tex] s= (-1.9 km)i +(2.4 -4.7 km) j= (-1.9km)i + (-2.3 km)j[/tex]

We can find the magnitude of s like this:

[tex] |s| = \sqrt{(-1.9)^2 +(-2.3)^2}=2.983[/tex]

And then we can find the angle with this formula:

[tex] \theta = \tan^{-1} (\frac{-2.3 km}{-1.9 km})=50.44 [/tex]

The other possibility is [tex] \theta = 50.44+180 =230.44[/tex]

And since they want the angle measured from East the correct angle would be [tex] \theta = 230.44[/tex]

Find the Surface area

Answers

Answer:

27m²

Step-by-step explanation:

surface area is area of all sides

these is two triangles and a rectangle

area of triangle = (base x height) /2 = (3 x 4)/2= 12/2 =6

area of rectangle = length x breadth = 5x3 = 15

surface area = area of triangle + area of triangle + area of rectangle

6 + 6 + 15 = 27m²

Let V be the volume of the solid obtained by rotating about the y-axis the region bounded y = 25x and y = x2 25 . Find V by slicing.

Answers

Answer:

[tex]volume\ = \pi \frac{625^2}{6}[/tex]

Step-by-step explanation:

See the attached figure.

y₁ = 25x  and  y₂ =x²

The intersection between y₁ and y₂

25x = x²

x² - 25x = 0

x(x-25) = 0

x = 0 or x =25

y = 0 or y =25² = 625

The points of intersection (0,0) and (25,625)

To find the volume of the solid obtained by rotating about the y-axis the region bounded by y₁ and y₂

y₁ = 25x ⇒ x₁ = y/25 ⇒ x₁² = y²/625

y₂ =x² ⇒ x₂ = √y ⇒ x₂² = y

v = ∫A(y) dy = π ∫ (x₂² - x₁²) dy

∴ V =

[tex]\pi \int\limits^{625}_0 {y-\frac{y^2}{625} } \, dy =\pi( \frac{y^2}{2} -\frac{y^3}{3*625} ) =\pi (\frac{625^2}{2} -\frac{625^3}{3*625}) =\pi ( \frac{625^2}{2}-\frac{625^2}{3}) =\pi \frac{625^2}{6}[/tex]

Final answer:

To find the volume of the solid formed by rotating the region bounded by y = 25x and y = x²25 about the y-axis, one needs to calculate the area of a typical slice, then integrate this area over the range of x-values.

Explanation:

To find the volume V of the solid obtained by rotating the region bounded by y = 25x and y = x225 about the y-axis, we can apply the method of slicing.

First, we need to find the area A(x) of a typical slice perpendicular to the x-axis. Here we have two functions, finding the x- values where these functions intersect gives the bounds on the integral for the volume.

We can find the area A(x) = pi*(outer radius)2 - pi*(inner radius)2 = pi[(25x)ˆ2 - (xˆ2 * 25)ˆ2].

To find V, we integrate A(x) over the interval of x-values. This will give us the exact volume of the solid.

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PLEASE HELP! See attached image for the equation!

Answers

Answer:

Step-by-step explanation:

The first step is to rearrange the given quadratic equation so that it will take the form of the standard quadratic equation which is expressed as

ax² + bx + c = 0

The given quadratic equation is expressed as

2 = - x + x² - 4

Rearranging it, we would subtract 2 from the left hand side and the right hand side of the equation. It becomes

2 - 2 = - x + x² - 4 - 2

- x + x² - 6 = 0

x² - x - 6

a = 1

b = - 1

c = - 6

Substituting into the quadratic formula, it becomes

x = [- (- 1) ± √(- 1)² - 4(1)(- 6)] /2(1)

Find the solution of the system of equations 3x+4y=10 and x−y=1. Give the x value followed by the y value, separated by a comma

Answers

Answer:

Solution of the system is (2,1).                                                          

Step-by-step explanation:

We are given the following system of equation:

[tex]3x+4y=10\\x - y = 1[/tex]

We would use the elimination method to solve the following system of equation.

Multiplying the second equation by 4 and adding the two equation we gwt:

[tex]3x + 4y = 10\\4\times (x-y = 1)\\\Rightarrow 4x - 4y = 4\\\text{Adding equations}\\3x + 4y + (4x-4y) = 10 + 4\\7x = 14\\\Rightarrow x = 2\\\text{Substituting value of x in second equation}\\2 - y = 1\\\Rightarrow y = 1[/tex]

Solution of the system is (2,1).

Answer: the solution is (2, 1)

Step-by-step explanation:

The given system of simultaneous equations is given as

3x+4y=10 - - - - - - - - - - - - -1

x−y=1 - - - - - - - - - - - - 2

We would eliminate x by multiplying equation 1 by 1 an equation 2 by 3. It becomes

3x + 4y = 10

3x - 3y = 3

Subtracting, it becomes

7y = 7

Dividing the left hand side and the right hand side of the equation by 7, it becomes

7y/7 = 7/7

y = 1

Substituting y = 1 into equation 2, it becomes

x - 1 = 1

Adding 1 to the left hand side and the right hand side of the equation, it becomes

x - 1 + 1= 1 + 1

x = 2

math answers- the length of segment AB is 3.6. the length of segment AC is 11.8. what is the length of segment BC? write and solve a decimal addition equation and a decimal subtraction equation.

Answers

Answer:

answer is AC^2

Step-by-step explanation:

Charlie is a car salesman. He earns $800 plus a 9% commission on all of his sales for the week. If Charlie received a paycheck for 1,916 this week, how much were his total sales?

Answers

Answer:

$12,400

Step-by-step explanation:

Given:

Week earning + 9% commission = $1,916

Weekly Earning = $800

Commission for the Week = $1,916 - $800 = $1,116

Let total sales for the week = x

Therefore, x = ($1,116 * 100)/9

x = $12,400

Answer:

$12400

Step-by-step explanation:

Wages = Basic pay + Commission

1916 = 800 + 9%A

Let A be the total sales

9%A = 1916 - 800

9%A = 1116

A = $12400

The table below shows selected points from a function.

The rate of change for the interval shown in the table is
A. constant
B. not constant
part b
A. linear
B. not linear

Answers

The rate of change is A. constant, B. linear

Step-by-step explanation:

Rate of change is the ratio of change in value of y with corresponding value of x

Rate of change=Δy/Δx

Rate of change=5-2/4-1 =3/3=1

The rate of change is constant in the given interval and linear with a positive slope.

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help pls asap in Ixl for geometry

Answers

Answer:

Step-by-step explanation:

Triangle QRS is a right angle triangle.

From the given right angle triangle

RS represents the hypotenuse of the right angle triangle.

With 30 degrees as the reference angle,

QR represents the adjacent side of the right angle triangle.

QS represents the opposite side of the right angle triangle.

To determine QR, we would apply trigonometric ratio

Cos θ = adjacent side/hypotenuse side. Therefore,

Cos 30 = QR/14

√3/2 = QR/14

QR = 14 × √3/2

QR = 14√3/2 = 7√3/2

USA Today reported that about 20% of all people in the United States are illiterate. Suppose you take eleven people at random off a city street. (a) Make a histogram showing the probability distribution of the number of illiterate people out of the eleven people in the sample.

Answers

Final answer:

To create a histogram showing the probability distribution of the number of illiterate people out of eleven people in a sample, you can use the binomial probability formula. Calculate the probability for each possible number of illiterate people and represent it in a histogram.

Explanation:

This question is asking for a histogram showing the probability distribution of the number of illiterate people out of eleven people in a sample, based on the information that about 20% of all people in the United States are illiterate.

To create the histogram, we can use the binomial probability formula. The formula is P(X = k) = C(n, k) * p^k * (1 - p)^(n - k), where C(n, k) represents combinations, n is the number of trials, k is the number of successes, and p is the probability of success.

We can calculate the probability for each possible number of illiterate people out of the eleven, ranging from 0 to 11, and represent it in a histogram.

Suppose Z has a standard normal distribution with a mean of 0 and standard deviation of 1. The probability that Z is less than 1.15 is:_________

Answers

Answer:

0.8749

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 0, \sigma = 1[/tex]

The probability that Z is less than 1.15 is:

This is the pvalue of Z = 1.15, which is 0.8749.

The probability that Z is less than 1.15: P(Z < 1.15) = Φ(1.15) ≈ 0.8749 or 87.49%

For a standard normal distribution with a mean of 0 and a standard deviation of 1, the probability that the random variable Z is less than 1.15 can be calculated using the standard normal cumulative distribution function (CDF).

The standard normal CDF gives the probability that a standard normal random variable takes a value less than or equal to a given value. We can use a standard normal distribution table or a calculator/software to find the value of the CDF at the desired point.

Let's denote the CDF of the standard normal distribution as Φ(z). Then, the probability that Z is less than 1.15 is given by:

P(Z < 1.15) = Φ(1.15)

Using a standard normal distribution table or calculator, we find that Φ(1.15) ≈ 0.8749.

Therefore, the probability that Z is less than 1.15 is approximately 0.8749 or 87.49%.

If 400 mL of a 20% w/v solution were diluted to 2 L, what would be the final percentage strength?

Answers

Answer:

4%

Step-by-step explanation:

A 20% solution with a total volume of 400 mL has 20% * 400 mL of solute.

20% * 400 mL = 80 mL

When you dilute the solution to 2 L, you introduce additional water, but no additional solute, so now you have the same 80 mL of solute in 2 L of total solution.

The concentration is:

(80 mL)/(2 L) = (80 mL)/(2000 mL) = 0.04

As a percent it is:

0.04 * 100% = 4%

"4" will be the final percentage strength.

According to the question,

20% solution with 400 mL has 20% × 400 mL of solute

then,

→ [tex]20 \ percent\times 400=80[/tex]

hence,

The concentration will be:

→ [tex]\frac{80 \ mL}{2 \ L} = \frac{80 \ mL}{2000 \ mL}[/tex]

            [tex]= 0.04[/tex]

or,

            [tex]= 0.04\times 100[/tex]

            [tex]= 4[/tex] (%)

Thus the answer above is right.

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Let S = {2,4,6} and T = {1,3,5}. Use the set-roster notation to write each of the following sets, and indicate the number of elements that are in each set?

a. S X T

b. T X S

c. S X S

d. T X T

Answers

Answer:

a. [tex]S\times T=\{(2,1),(2,3),(2,5),(4,1),(4,3),(4,5),(6,1),(6,3),(6,5)\}[/tex] . Set S × T has 9 elements.

b. [tex]T\times S=\{(1,2),(1,4),(1,6),(3,2),(3,4),(3,6),(5,2),(5,4),(5,6)\}[/tex]. Set T × S has 9 elements.  

c. [tex]S\times S=\{(2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,4),(6,6)\}[/tex] . Set S × S has 9 elements.

d. [tex]T\times T=\{(1,1),(1,3),(1,5),(3,1),(3,3),(3,5),(5,1),(5,3),(5,5)\}[/tex] . Set T × T has 9 elements.

Step-by-step explanation:

The given sets are S={2,4,6} and T={1,3,5}.

We need to find the set-roster notation to write each of the following sets, and the number of elements that are in each set.

a.

[tex]S\times T=\{(s,t)|s\in S and t\in T\}[/tex]

[tex]S\times T=\{(2,1),(2,3),(2,5),(4,1),(4,3),(4,5),(6,1),(6,3),(6,5)\}[/tex]

Set S × T has 9 elements.

b.

[tex]T\times S=\{(t,s)|s\in S and t\in T\}[/tex]

[tex]T\times S=\{(1,2),(1,4),(1,6),(3,2),(3,4),(3,6),(5,2),(5,4),(5,6)\}[/tex]

Set T × S has 9 elements.  

c.

[tex]S\times S=\{(s,s)|s\in S \}[/tex]

[tex]S\times S=\{(2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,4),(6,6)\}[/tex]

Set S × S has 9 elements.

d.

[tex]T\times T=\{(t,t)|t\in T\}[/tex]

[tex]T\times T=\{(1,1),(1,3),(1,5),(3,1),(3,3),(3,5),(5,1),(5,3),(5,5)\}[/tex]

Set T × T has 9 elements.

Using the set roster notation, the number of elements in each of the sets would be the product of the number of elements in each individual set, which is 9.

S = {2, 4, 6}T = {1, 3, 5}

A.) S × T :

{2, 4, 6} × {1, 3, 5}

{(2, 1), (2, 3), (2, 5), (4, 1), (4, 3), (4, 5), (6, 1), (6, 3), (6, 5)}

Number is of elements = 9

B.) T × S :

{1, 3, 5} × {2, 4, 6}

{(1,2), (1,4), (1,6), (3,2), (3,4), (3, 6), (5, 2), (5,4), (5,6)}

Number is of elements = 9

C.) S × S :

{1, 3, 5} × {1, 3, 5}

{(1, 1), (1, 3), (1, 5), (3, 1), (3, 3), (3, 3), (5, 1), (5, 3), (5, 5)}

Number is of elements = 9

D.) T × T :

{2, 4,6} × {2, 4, 6}

{(2,2), (2, 4), (2, 6), (4,2), (4, 4), (4, 6), (6,2), (6, 4), (6,6)}

Number is of elements = 9

Hence, the distribution of values of each set.

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which is the equation of a libe that has a slope of 1/2 and passes through (2,-3)​

Answers

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

The slope is given as 1/2 and the line passes through (2, - 3)

To determine the intercept, we would substitute x = 2, y = - 3 and m= 1/2 into y = mx + c

y = mx + c. It becomes

- 3 = 1/2 × 2 + c = 1 + c

c = - 3 - 1 = - 4

The equation becomes

y = x/2 - 4

Suppose x x represents the value of some varying quantity. As the value of x x varies from 3.5 to 8.
What is the change in the value of x x?

Answers

Answer: The change in the value of x would be : [tex]\Delta x=4.5 [/tex]    .

Step-by-step explanation:

We know that if y represents the value of some varying quantity, then as the value of y varies from p to q.

The change in the value of y is given by :-

[tex]\Delta y=q-p[/tex]     [Next value - previous value]

Given : x represents the value of some varying quantity.

So , As the value of x  varies from 3.5 to 8.

The change in the value of x is given by :-

[tex]\Delta x=8-3.5=4.5 [/tex]  

Hence, the change in the value of x would be : [tex]\Delta x=4.5 [/tex]  

Suppose the length of the vegetable garden is increased by 50%. The new length can be written as (3y + 5) + 1 2(3y + 5) or 1.5(3y + 5). Explain why both expressions are correct. Then write the new length of the garden in simplified form.

Answers

Answer:

Given:

Length of the garden is represented by :

[tex]3y+5[/tex]

The length is increased by 50%.

To find the new length.

Solution:

1) The original length = [tex]3y+5[/tex]

The increase in length will be = [tex]50%[/tex] of [tex]3y+5[/tex]

⇒ [tex]\frac{50}{100}(3y+5)[/tex]

⇒ [tex]\frac{1}{2}(3y+5)[/tex]

The new length  = Original length + Increased length = [tex](3y+5)+ \frac{1}{2}(3y+5)[/tex]

2) Let the original length = 100%

Increase percent of length = 50%

Total percent of length = [tex]100\%+50\%=150\%[/tex]

New length = [tex]150%[/tex] of [tex]3y+5[/tex]

⇒ [tex]\frac{150}{100}(3y+5)[/tex]

⇒ [tex]1.5(3y+5)[/tex]

Thus,  the new length of the garden can be represented by both expression :

[tex](3y+5)+ \frac{1}{2}(3y+5)[/tex] or [tex]1.5(3y+5)[/tex]

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