Final answer:
Using Hooke's Law and the spring constant calculated from the initial scenario, the length of the spring when a 3.0 kg mass is suspended from it will be 17.5 cm.
Explanation:
The question involves calculating how much a spring will stretch under a certain weight, which can be addressed using Hooke's Law and the concept of spring constants in physics. We are given a scenario in which a spring stretches an additional 5 cm (from 10 cm to 15 cm) when a 2.0 kg mass is hung from it. To determine how long the spring will be when a 3.0 kg mass is suspended from it, we first need to calculate the effective spring constant (k) using the initial provided information.
We can use the formula for Hooke's Law: F = k × Δx, where F is the force applied to the spring (which is the weight of the mass), k is the spring constant, and Δx is the change in length of the spring from its equilibrium position. Because the weight force due to gravity is F = m × g (where m is the mass and g is the acceleration due to gravity, 9.8 m/s²), we can find k as follows:
For a 2.0 kg mass, F = 2.0 kg × 9.8 m/s² = 19.6 N. The change in length Δx is 5 cm or 0.05 m. Therefore, k = F / Δx = 19.6 N / 0.05 m = 392 N/m.
Now we can find the new change in length for a 3.0 kg mass. Let Δx' be the new change in length. We have F' = 3.0 kg × 9.8 m/s² = 29.4 N. Since k is constant for the spring: 29.4 N = 392 N/m × Δx'. Solving for Δx' gives Δx' = 29.4 N / 392 N/m = 0.075 m or 7.5 cm. Therefore, the total length of the spring when a 3.0 kg mass is hung will be 10 cm + 7.5 cm = 17.5 cm.
An object travels with velocity v = 4.0 meters/second and it makes an angle of 60.0° with the positive direction of the y-axis. Calculate the possible values of vx.
Answer:
2 m/s and -2 m/s
Explanation:
The object travels with an angle of
60.0°
with the positive direction of the y-axis: this means that it lies either in the 1st quadrant (positive x) or in the 2nd quadrant (negative x).
If it lies in the 1st quadrant, the value of vx (component of v along x direction) is:
[tex]v_x = v cos \theta = (4.0 m/s) cos 60.0^{\circ}=2 m/s[/tex]
If it lies in the 2nd quadrant, the value of vx (component of v along x direction) is:
[tex]v_x = -v cos \theta = -(4.0 m/s) cos 60.0^{\circ}=-2 m/s[/tex]
What is the mass of a student that weighs 3000N stands on one foot, balancing on a step stool.
Weight = (mass) x (gravity)
so
Mass = (weight) / (gravity)
Mass = (3000N) / (9.8 m/s^2)
Mass = 306.1 kg
But he could never stand on one foot balanced on a step stool. The poor kid weighs 675 pounds ! !
The mass of a student can be calculated using the formula F = m*g. Hence the mass is approximately 305.81 kg.
To find the mass of the student, we need to convert the weight to force using the formula, F = m * g where F is the force or weight, m is the mass, and g is the acceleration due to gravity (g = 9.8 m/s² on Earth) or Using the relationship between weight and mass, which is expressed by the formula W = m*g, where W is weight.
To calculate the mass (m), we rearrange the formula to m = W/g.
m = 3000 N / 9.81 m/s^2 = 305.81 kg
Therefore, the mass of the student who exerts a force of 3000N due to gravity on the step stool while balancing on one foot is 305.81 kilograms.
The mass of the sun is 1.99×1030kg and its distance to the earth is 1.50×1011m. What is the gravitational force of the sun on the earth?
Answer: [tex]3.524(10)^{22}N[/tex]
Explanation:
According to Newton's law of Gravitation, the force [tex]F[/tex] exerted between two bodies of masses [tex]m1[/tex] and [tex]m2[/tex] and separated by a distance [tex]r[/tex] is equal to the product of their masses and inversely proportional to the square of the distance:
[tex]F=G\frac{(m1)(m2)}{r^2}[/tex] (1)
Where:
[tex]G[/tex] is the Gravitational Constant and its value is [tex]6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}[/tex]
[tex]m1=1.99(10)^{30}kg[/tex] is the mass of the Sun
[tex]m2=5.972(10)^{24}kg[/tex] is the mass of the Earth
[tex]r=1.50(10)^{11}m[/tex] is the distance between the Sun and the Earth
Substituting the values in (1):
[tex]F=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.99(10)^{30}kg)(5.972(10)^{24}kg)}{(1.50(10)^{11}m)^2}[/tex] (2)
Finally:
[tex]F=3.524(10)^{22}N[/tex] This is the gravitational force of the Sun on the Earth.
Final answer:
The resulting force is approximately 3.54 times [tex]10^{22}[/tex] N.
Explanation:
The question pertains to calculating the gravitational force exerted by the Sun on Earth which can be found using Newton's law of universal gravitation. The formula for the gravitational force F between two masses m1 and m2 separated by a distance r is given by F = G * (m1 * m2) / [tex]r^2[/tex], where G is the gravitational constant (6.67430 times [tex]10^{-11}[/tex]N times[tex](m/kg)^2[/tex]).
Given the mass of the Sun (m1) is 1.99 times [tex]10^{30}[/tex]kg, the mass of the Earth (m2) is 5.972 times [tex]10^{24}[/tex] kg (approximately, for ease of calculation), and the average distance (r) between the Earth and Sun is 1.50 times [tex]10^{11}[/tex] m, we can substitute these values into the gravitational force formula to generate accurate answer.
Therefore, the gravitational force of the Sun on the Earth is calculated to be approximately 3.54 times [tex]10^{22}[/tex]N.
What is the entropy of isolated system?
Answer: Entropy is the measure of the disorder of a system
Explanation:
Entropy is a thermodynamic quantity defined as a criterion to predict the evolution or transformation of thermodynamic systems. In addition, it is used to measure the degree of organization of a system.
In other words: Entropy is the measure of the disorder of a system and is a function of state. That is, it depends only on the state of the system.
However, in the case of an isolated system in an irreversible process, the value of entropy increases in the course of a process that occurs naturally. While in a reversible process the entropy of the isolated system remains constant.
3. Which equation shows the relationship between the Kelvin and Celsius temperature scales? K = 273 – °C K = °C + 273 K = °F + 273 K = °C + °F
Answer: [tex]K=\°C+273.15[/tex]
Explanation:
The Kelvin ([tex]K[/tex]), is the unit of temperature of the scale created by the British physicist William Thomson (Lord Kelvin) in 1848, taking as a base the Celsius scale, establishing the zero point for this scale in the absolute zero which is in [tex]-273.15\°C[/tex].
This was achieved by observing that when a gas cools, its volume decreases proportionally to its temperature. That is, for each degree of temperature that the gas decreases, its volume also decreases by a certain percentage.
After which, Kelvin made the calculations and it turned out that at a temperature of [tex]-273.15\°C[/tex] the volume of the gas would be zero (theoretically).
It should be noted that the Kelvin is the unit of temperature of the International System of Units and that although the scale starts at absolute zero (theoretical), in which no molecule should move, in reality it is not so, because according to quantum physics, at this temperature the molecules retain a residual movement.
Use ohms law to determine the battery voltage you would need to send 2.5 A of current through a light bulb with 3.6 Ω of resistance.
According to Ohm's law, the voltage drop V across a resistor when a current flows through it is V = IR. To determine the battery voltage needed to send 2.5 A of current through a light bulb with 3.6 Ω of resistance, we rearrange Ohm's law and substitute the known values.
Explanation:According to Ohm's law, the voltage drop V across a resistor when a current flows through it is calculated using the equation V = IR, where I equals the current in amps (A) and R is the resistance in ohms. To determine the battery voltage needed to send 2.5 A of current through a light bulb with 3.6 Ω of resistance, we rearrange Ohm's law as V = IR. Substituting the known values, we have V = (2.5 A)(3.6 Ω), which gives us a battery voltage of 9 V.
All life on earth exists in a region known as
Hello There!
All life on Earth exists in a region called the biosphere.
The biosphere is known as the global sum of all ecosystems. It's called the "zone of life"
Answer:the bioshpere
Explanation:
On a trip to the Colorado Rockies, you notice that when the freeway goes steeply down a hill, there are emergency exits every few miles. These emergency exits are straight ramps which leave the freeway and are sloped uphill. They are designed to stop runaway trucks and cars that lose their brakes on downhill stretches of the freeway even if the road is covered with ice. You are curious, so you stop at the next emergency exit to take some measurements. You determine that the exit rises at an angle of 10o from the horizontal and is 100m long. What is the maximum speed of a truck that you are sure will be stopped by this road, even if the frictional force of the road surface is negligible?
Answer:
The maximum speed that the truck can have and still be stopped by the 100m road is the speed that it can go and be stopped at exactly 100m. Since there is no friction, this problem is similar to a projectile problem. You can think of the problem as being a ball tossed into the air except here you know the highest point and you are looking for the initial velocity needed to reach that point. Also, in this problem, because there is an incline, the value of the acceleration due to gravity is not simply g; it is the component of gravity acting parallel to the incline. Since we are working parallel to the plane, also keep in mind that the highest point is given in the problem as 100m. Solving for the initial velocity needed to have the truck stop after 100m, you should find that the maximum velocity the truck can have and be stopped by the road is 18.5 m/s.
Explanation:
Using principles from physics, specifically the energy conservation principle and trigonometry, you can determine that the maximum speed a truck could be going and still be stopped by the emergency exit—even with negligible friction—is roughly 18.56m/s or 66.81km/h.
Explanation:In physics, when a vehicle goes up a slope, two main forces tend to stop the vehicle: gravity and friction. In this problem, we are asked to ignore friction, so that only gravity will slow down the vehicle. Given that that the velocity of the truck at the end of the emergency exit has to be zero, we should use the energy conservation principle because work done by gravity equals the initial kinetic energy of the truck. Since work done by gravitational force equals mass (m) * gravitational acceleration (g) * height (h), and initial kinetic energy equals 0.5 * mass (m) * velocity^2 (v^2), we have m * g * h = 0.5 * m * v^2 (with v being the maximum velocity). Then, we can calculate the height using trigonometry because we know the angle and the length of the slope. So, h = 100m * sin(10) = 17.36m. Plug h into the equation above and solve for v gives v = sqrt(2 * g * h). With g = 9.8m/s^2, v = sqrt(2 * 9.8m/s^2 * 17.36m) = 18.56m/s or 66.81km/h.
Learn more about Energy Conservation here:https://brainly.com/question/32490774
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Object A has a length of 3 cm, a width of 2 cm, and a height of 4 cm. Object B is dropped into a graduated cylinder. It displaces 19 mL of water. The volume of object A is:
A: greater than the volume of object B
B: less than the volume of object B
C: equal to the volume of object B
Answer:
A: greater than the volume of object B
Explanation:
Based on the dimensions, the volume of object A is ...
(3 cm)(2 cm)(4 cm) = 24 cm³ = 24 mL
If object B displaces 19 mL of water, we presume that is its volume. Since 24 mL is more than 19 mL, we conclude ...
The volume of object A is greater than the volume of object B.
_____
Comment on density
We have presumed that object B is completely submerged. If it is not, then the relative volumes will depend on the densities. If the density of object B is less than about (19/24) g/mL, its volume may very well be larger than that of object A.
Answer:
A: greater than the volume of object B
Explanation:
Based on the dimensions, the volume of object A is ...
(3 cm)(2 cm)(4 cm) = 24 cm³ = 24 mL
If object B displaces 19 mL of water, we presume that is its volume. Since 24 mL is more than 19 mL, we conclude ...
The volume of object A is greater than the volume of object B.
_____
Comment on density
We have presumed that object B is completely submerged. If it is not, then the relative volumes will depend on the densities. If the density of object B is less than about (19/24) g/mL, its volume may very well be larger than that of object A.
Which is not true of the Intertropical Convergence Zone?A) It features heavy precipitation B) It's where the trade winds collideC) It's a high-pressure zone with sinking air D) It is also known as the doldrums
Explanation:
The intertropical convergence zone is the region of the terrestrial globe where the trade winds of the northern hemisphere converge with those of the southern hemisphere.
It is characterized by being a belt of low pressure and inconsistent location around the equator constituted by ascending air currents, where large masses of warm and humid air converge from the north and south of the intertropical zone.
The reason of its inconsistent location is due to the movements of the Earth with the seasons, having as a consequence the amount variation of heat energy from the sun in this region.
Wind and solar energy are examples of scarce resources. Renewable resources. Capital resources. Nonrenewable resources.
Answer:
Renewable Resources
Explanation:
This is because wind is almost infinite and doesn't pollute.
Answer: Renewable resources
Explanation:
Suppose that as an object falls from the top of a cliff, its position in feet above the ground after t seconds is given by s(t) = 160-16t^2. Find the average velocity from t=1to t=1+h seconds, where h not= 0.
a.32+16h
b.-32-16h
c.32-16h
d.-32+16h
The average velocity of the object can be found by calculating the change in position divided by the change in time.
Explanation:The average velocity of the object from t=1 to t=1+h seconds can be found by calculating the change in position divided by the change in time.
To find the change in position, subtract s(1) from s(1+h):
s(1+h) - s(1) = (160-16(1+h)^2) - (160-16(1)^2)
simplifying gives: -16h - 16h^2
To find the change in time, subtract 1 from 1+h: 1+h - 1 = h
So, the average velocity is:
-16h - 16h^2 / h = -16 - 16h
Therefore, the correct answer is d. -32 + 16h.