Answer:
#include <stdio.h>
int p;
int g(int n)
{
static int minimum=101, maximum=-1, average=0;
if(n==0)
return -1;
else
{
printf("Enter course grade %d: ",p-n+1);
int grade;
scanf("%d",&grade);
g(n-1);
printf("%d\n",grade);
if(minimum>grade)
minimum=grade;
if(maximum<grade)
maximum=grade;
average=average+grade;
if(n==p)
{
printf("minimum= %d\n",minimum);
printf("maximum= %d\n",maximum);
printf("Average= %.2f\n",(double)average/(double)n);
}
return -1;
}
}
int main()
{
printf("Enter the number of grades:\n");
scanf("%d",&p);
g(p);
return 0;
}
Explanation:
Use a conditional statement to check to find the maximum and minimum grade.Check if n is equal to p, then display the values of maximum and minimum.Calculate the average by dividing the sum with the total numbers and then display its value.Inside the main function, get number of grades from user as an input.Lastly, call the function g and pass it the value of grade.Give a linear-time algorithm to sort the ratios of n given pairs of integers between 1 and n. I.e., we need to sort, within O(n) time, n pairs of the form (ai , bi) where 1 ≤ ai ≤ n and 1 ≤ bi ≤ n using the sort key ai bi . Prove both run-time and correctness.
Answer:
12
Explanation:
Median of a sample If the distribution is given, as above, the median can be determined easily. In this problem we will learn how to approximate the median when the distribution is not given, but we are given samples that it generates. Similar to distributions, we can define the median of a set to be the set element m′ such that at least half the elements in the set are ≤m′ and at least half the numbers in the collection are ≥m′. If two set elements satisfy this condition, then the median is their average. For example, the median of [3,2,5,5,2,4,1,5,4,4] is 4 and the median of [2,1,5,3,3,5,4,2,4,5] is 3.5. To find the median of a P distribution via access only to samples it generates, we obtain ???? samples from P, caluclate their median ????????, and then repeat the process many times and determine the average of all the medians.
Exercise 2
Write a function sample_median(n,P) that generates n random values using distribution P and returns the median of the collected sample.
Hint: Use function random.choice() to sample data from P and median() to find the median of the samples
* Sample run *
print(sample_median(10,[0.1 0.2 0.1 0.3 0.1 0.2]))
print(sample_median(10,[0.1 0.2 0.1 0.3 0.1 0.2]))
print(sample_median(5,P=[0.3,0.7])
print(sample_median(5,P=[0.3,0.7])
* Expected Output *
4.5
4.0
2.0
1.0
Exercise 4
In this exercise, we explore the relationship between the distribution median mm, the sample median with ????n samples, and ????[????????]E[Mn],the expected value of ????????Mn.
Write a function average_sample_median(n,P), that return the average ????????Mn of 1000 samples of size n sampled from the distribution P.
* Sample run *
print(average_sample_median(10,[0.2,0.1,0.15,0.15,0.2,0.2]))
print(average_sample_median(10,[0.3,0.4,0.3]))
print(average_sample_median(10,P=[0.99,0.01])
* Expected Output *
3.7855
2.004
1
----------------------------------------------------------------------
Question a:
In exercise 2,
Which of the following is a possible output of sample_median(n, [0.12,0.04,0.12,0.12,0.2,0.16,0.16,0.08]) for any n?
3
9
7
4
Question b:
In exercise 4,
what value does average_sample_median(100,[0.12, 0.04, 0.12, 0.12, 0.2, 0.16, 0.16, 0.08]) return?
Answer:
def sample_median(n,P):
return np.median(np.random.choice(np.arange(1,len(P)+1),n,p=P))
Explanation:
See attached picture.
Which client software can be used to connect remote Linux client into a Palo Alto Networks Infrastructure without sacrificing the ability to scan traffic and protect against threats?
Answer:
GlobalProtect Linux
Explanation:
GlobalProtect Linux can be used to connect remote Linux client into a Palo Alto Networks Infrastructure without sacrificing the ability to scan traffic and protect against threats.
Assume the following JavaScript program was interpreted using static-scoping rules. What value of x is displayed in function sub1? Under dynamic-scoping rules, what value of x is displayed in function sub1? var x; function sub1() { document.write("x = " + x + ""); } function sub2() { var x; x = 10; sub1(); } x = 5; sub2();
Answer:
The value of x in both scope can be described as follows:
i) Static scope:
x= 5
ii) Dynamic scope:
x=10
Explanation:
The static scoping is also known as an arrangement, which is used in several language, that defines the variable scope like the variable could be labelled inside the source that it is specified.
i) program:
function sub1() //defining function sub1
{
print("x = " + x + ""); //print value
}
function sub2()//defining function sub2
{
var x; //defining variable x
x = 10; //assign value in variable x
sub1(); //caling the function sub1
}
x = 5; //assign the value in variable x
sub2(); //call the function sub2
In Dynamic scoping, this model is don't see, it is a syntactic mode that provides the framework, which is used in several program. It doesn't care how well the code has been written but where it runs.
ii) Program:
var x //defining variable x
function sub1() //defining a function sub1
{
print("x = " + x + ""); //print the value of x
}
x = 10; // assign a value in variable x
sub2(); // call the function sub2
function sub2() //defining function sub2
{
var x; //defining variable x
x = 5; // assign value in x
sub1();//call the function sub1
}
In this exercise we have to use the knowledge in computer language to write a code in JAVA, like this:
the code can be found in the attached image
to make it simpler we have that the code will be given by:
The first code will be:unction
sub1 () //defining function sub1
{
print ("x = " + x + ""); //print value}
function
sub2 () //defining function sub2
{
var x; //defining variable x
x = 10; //assign value in variable x
sub1 (); //caling the function sub1
}
x = 5;
The secound code will be:var x //defining variable x
function
sub1 () //defining a function sub1
{
print ("x = " + x + ""); //print the value of x
}
x = 10; // assign a value in variable x
sub2 (); // call the function sub2
function
sub2 () //defining function sub2
{
var x; //defining variable x
x = 5; // assign value in x
sub1 (); //call the function sub1
}
See more about JAVA at brainly.com/question/2266606
The second half to the Student Report will retrieve the specific fees for which the student whose ID is in cell B2 is responsible. In cell E5, enter a VLOOKUP function that will retrieve the student's Uniform Size from the range A12:E36 on the StudentReport worksheet. Incorporate an IFERROR function so that if there is no Student ID in cell B2, a blank value ("") is returned instead of a___________.
To retrieve a student's Uniform Size using the student ID in cell B2 with a VLOOKUP function and handle errors with IFERROR, the following Excel formula should be entered in cell E5: '=IFERROR(VLOOKUP($B$2, StudentReport!$A$12:$E$36, 5, FALSE), "")'. It returns the Uniform Size or a blank value if an error occurs or if there is no ID.
Explanation:To retrieve the Uniform Size for a student using a VLOOKUP function, while also handling errors with the IFERROR function in Excel, you can use the following formula in cell E5:
=IFERROR(VLOOKUP($B$2, StudentReport!$A$12:$E$36, 5, FALSE), "")
This formula will look for the student ID located in cell B2 within the range A12:E36 on the StudentReport worksheet. If the student ID is found, it will return the value in the fifth column of the range (which corresponds to the Uniform Size). If the student ID is not present in cell B2 or an error occurs during the lookup, a blank value ("") will be returned, preventing any error messages from being displayed.
Use a loop with indirect or indexed addressing to reverse the elements of an integer array in place. Do
not copy the elements to any other array. Use the SIZEOF, TYPE, and LENGTHOF operators to make
the program as flexible as possible if the array size and type should be changed in the future. Optionally,
you may display the modified array by calling the DumpMem method from the Irvine32 library.
My current code:
.data
array BYTE 10h, 20h, 30h, 40h
.code
main PROC
mov esi, 0
mov edi, 0
mov esi, OFFSET array + SIZEOF array - 1
mov edi, OFFSET array + SIZEOF array - 1
mov ecx, SIZEOF array/2
l1: mov al, [esi]
mov bl, [edi]
mov [edi], al
mov [esi], bl
inc esi
dec edi
LOOP l1
call DumpRegs
call DumpMem
exit
main ENDP
END main
Answer:
; Use a loop with indirect or indexed addressing to
; reverse the elements of an integer array in place
INCLUDE Irvine32.inc
.data
;declare and initialize an array
array1 DWORD 10d,20d,30d,40d,50d,60d,70d,80d,90d
.code
main PROC
;assign esi value as 0
mov esi,0
;find the size of array
mov edi, (SIZEOF array1-TYPE array1)
;find the length of the array
;divide the length by 2 and assign to ecx
mov ecx, LENGTHOF array1/2
;iterate a loop to reverse the array elements
L1:
;move the value of array at esi
mov eax, array1[esi]
;exchange the values eax and value of array at edi
xchg eax, array1[edi]
;move the eax value into the array at esi
mov array1[esi], eax
;increment the value of esi
add esi, TYPE array1
;decrement the value of edi
sub edi, TYPE array1
loop L1
;The below code is used to print
;the values of array after reversed.
;get the length of the array
mov ecx, LENGTHOF array1
;get the address
mov esi, OFFSET array1
L2:
mov eax, [esi]
;print the value use either WriteDec or DumpMems
;call WriteDec
;call crlf
call DumpMem
;increment the esi value
add esi, TYPE array1
LOOP L2
exit
main ENDP
END main
The code provided demonstrates how to reverse an array of integers in place using Assembly language without copying elements to another array. It uses indirect addressing and the SIZEOF, TYPE, and LENGTHOF operators for greater code flexibility. The array is reversed by swapping elements using appropriate pointers in a loop.
To reverse an array of integers in place using Assembly language, you can utilize a loop with indirect addressing. This approach eliminates the need to create a separate array, thereby optimizing memory usage. Here is an updated version of your code:
Reversed Integer Array Code :
Let's update your code to correctly reverse the array using the SIZEOF, TYPE, and LENGTHOF operators:
.dataThis updated version correctly reverses the array in place by addressing elements indirectly and using the TYPE operator to handle elements of any type. This code will also be more flexible if the array type or size changes.
Write a C program that inputs four strings that represent integers, converts the string to integers, sums the values and prints the total of the four.
The C program is an illustration of integers, converts the string to integers, sums the values, and prints the total of the four.
What is a coding program?A coding program is a sort of software that is used just for codings, such as Java, C, C#, C++ Python, and many more. A coding program is an executable form of program that is built on programmers' and machine tools' intelligence.
As per the question, Here is a C program that inputs four strings that represent integers, converts the string to integers, sums the values, and prints the total of the four:
#include <stdio.h>
#include <stdlib.h>
int main()
{
char str1[10], str2[10], str3[10], str4[10];
int num1, num2, num3, num4, sum;
// Input four strings
printf("Enter the first number: ");
scanf("%s", str1);
printf("Enter the second number: ");
scanf("%s", str2);
printf("Enter the third number: ");
scanf("%s", str3);
printf("Enter the fourth number: ");
scanf("%s", str4);
// Convert strings to integers
num1 = atoi(str1);
num2 = atoi(str2);
num3 = atoi(str3);
num4 = atoi(str4);
// Calculate sum
sum = num1 + num2 + num3 + num4;
// Print sum
printf("The sum is: %d\n", sum);
return 0;
}
Learn more about the programming language here:
https://brainly.com/question/7344518
#SPJ5
Write a function index(elem, seq) that takes as inputs an element elem and a sequence seq, and that uses recursion (i.e., that calls itself recursively) to find and return the index
Answer:
I am writing the function in Python. Let me know if you want this function in some other programming language.
def index(elem, seq):
if len(elem) == 0:
return -1
elif elem[0] == seq:
return 0
else:
return 1 + index(elem[1:], seq)
Explanation:
The function index() takes two parameters elem which is a string array and seq that is the index to find in elem.
If the length of the elem array is 0 means the array is empty then -1 is returned.
If the 1st element at 0th index is equal to seq, which means if the index is found at the first position in the elem then 0 is returned which means that the index is found at the first (0th index) position of elem.
If both of the above condition evaluate to false then the else part is executed which calls the index() recursively. This will traverse through the elem until it finds the seq which means that it will move through elem array until it finds the desired index.
Lets see how this function works.
print(index(['banana'],'b'))
Here we call the function index() to print the index (seq) position of b in banana(elem).
So it is found in the first index which evaluates elif elem[0] == seq condition to true so output is 0.
For print (index([1,2,3,4,5,6,7,8], 3)) statement in order to find 3 seq in [1,2,3,4,5,6,7,8] elem list, the recursive function is called which calls itself recursively and keeps slicing the list to find and return the desired index.
The screenshot of program with its output is attached.
Look at the following array definition. char str[10]; Assume that name is also a char array, and it holds a C-string. Write code that copies the contents of name to str if the C-string in name is not to big to fit in str.
Answer:
if(strlen(name)<=9)
strcpy(str,name);
Explanation:
In the above chunk of code, IF condition is used which checks if the length of the array name is less than or equals to 9.
This means that in order to copy the contents of name array to str array the string contained in name should not be larger than the length of the str. The length of str is given which is 10.
So strlen() function returns the length of the string in the name array and if this length is less than or equal to 9 then the If condition evaluates to true and the next line strcpy(str,name); is executed which copies the contents of name array to the str array.
strcpy() function is used to copy the string contents from source to destination. Here the source is the name array and the destination is str array.
If you want to see the output then you can enter some contents into the name array as follows:
#include <iostream>
#include <string.h>
using namespace std;
int main()
{
char str[10];
char name[]={'a','b','c','d','e','f','g','h','i'};
if(strlen(name) <= 9)
strcpy(str,name);
cout<<str;
}
This program has two array str of length 10 and name[] array contains 9 characters. These contents are copied to the str array if the length of the name array is less than or equal to 9, which is true, so the ouput is:
abcdefghi
⦁ Consider transferring an enormous file of L bytes from Host A to Host B. Assume an MSS of 536 bytes. ⦁ What is the maximum value of L such that TCP sequence numbers are not exhausted? Recall that the TCP sequence number field has 4 bytes. ⦁ For the L you obtain in (a), find how long it takes to transmit the file. Assume that a total of 66 bytes of transport, network, and data-link header are added to each segment before the resulting packet is sent out over a 155 Mbps link. Ignore flow control and congestion control so A can pump out the segments back to back and continuously.
The maximum value of L such that TCP sequence numbers are not exhausted is 4,295,797,296 bytes. It takes approximately 249.02 seconds to transmit this file over a 155 Mbps link, considering the added headers for each segment.
TCP Sequence Numbers and File Transfer :
To determine the maximum value of L such that TCP sequence numbers are not exhausted, we need to consider the range of sequence numbers. TCP sequence numbers have 4 bytes, which means they can represent values from 0 to 232-1, which equals 4,294,967,295.
Given an MSS (Maximum Segment Size) of 536 bytes:
Total Number of MSS-sized segments = Floor(4,294,967,296 / 536) = Floor(8,014,536.24) = 8,014,536 segments.Therefore, the maximum value of L = 8,014,536 segments * 536 bytes/segment = 4,295,797,296 bytes.Time to Transmit the File :
Assuming a total of 66 bytes of transport, network, and data-link headers added to each segment, the size of each packet becomes 536 + 66 = 602 bytes.
The transmission rate is 155 Mbps (Megabits per second) which is 155,000,000 bits per second.
Total number of bits to be transmitted = 4,295,797,296 bytes * 8 bits/byte + (8,014,536 packets * 66 bytes/header * 8 bits/byte) = 34,366,378,368 bits + 4,231,790,848 bits = 38,598,169,216 bits.Transmission time = Total number of bits / Transmission rate = 38,598,169,216 bits / 155,000,000 bits/second ≈ 249.02 seconds.Thus, it takes approximately 249.02 seconds to transmit the file.
A customer is looking to replace three aging network servers that are not able to keep up with the growing demand of the company’s users. The customer would also like to add three additional servers to provide on-site DNS, intranet, and file services. A technician is recommending a bare metal hypervisor as the best solution for this customer.
Which of the following describes the recommended solution?
a. Type 2 hypervisor installed on a Windows or Linux host OS.
b. Type 2 hypervisor installed directly on server hardware.
c. Type 1 hypervisor installed directly on server hardware.
d. Hosted hypervisor installed as an application.
Answer:
c. Type 1 hypervisor installed directly on server hardware.
Explanation:
The customer plans to replace the old network services to ensure that the operation and service of the company is fast and up-to-date. The old servers will slow down the activities of the company and can also affect the overall company's output. The best option is to use and type 1 hypervisor and it should be installed on the server hardware directly.
Multicore processors are formed by:
A. connecting identical processors in a parallel combination, and drawing power from the same source.
B. putting two or more lower power processor cores on a single chip.
C. connecting a series of high powered processors through a single power source.
D. slicing a flat chip into pieces and reconnecting the pieces vertically.
E. connecting a combination of parallel and series-connected processors to a single larger processor to supplement its functioning.
Answer:
B. putting two or more lower power processor cores on a single chip
Explanation:
Multi-core processor Is a computer processor with integrated circuit which involves two or more processor joined together so as to improve performance and reduce the rate of power consumption as well as improve the efficiency of processing multiple tasks.
Let G be the grammar
S --> abSc | A
A --> cAd | cd
a) Give a left-most derivation of ababccddcc.
b) Build the derivation tree for the derivation in part (a).
c) Use set notation to define L(G).
Answer:
Explanation:
a) The Left-most derivataion for ababccddcc
S ⇒ AB
L.M.D
→ aAbB
→ aabbB
→ aabb CBd
→ aabb CCdd
b) Derivation tree for the derivation in part(a)
The attached diagram ilustrate the three derivation
c) To define L(G) with set notation
L(G) = {a ∧n b ∧n |n ≥ 0}.
A left-most derivation of the string ababccddcc from the grammar G follows a sequential expansion of the left-most nonterminal symbol, leading to the final string. The derivation tree visualizes this process with a branching structure based on the grammar's production rules. L(G) is defined using set notation to encompass all strings derivable from the start symbol following the grammar's rules.
Explanation:The student has asked for a left-most derivation of the string ababccddcc from the grammar G, along with the construction of the derivation tree and the definition of the language L(G) generated by G using set notation.
For a left-most derivation of the string ababccddcc, we would begin with the start symbol S and repeatedly expand the left-most nonterminal until the string is derived. The exact steps of this derivation would involve expanding S into abSc, then again into ababSc, and so on, until the string matches ababccddcc.Building the derivation tree would involve placing the start symbol S at the root and branching out according to the production rules used at each step in the derivation. Each node would represent a nonterminal or terminal symbol, and each level of the tree would represent a step in the derivation.To define L(G), we would use set notation to describe all strings that can be derived from the start symbol using the production rules of G. It usually includes all combinations of terminals that can be generated according to the rules of G.
Write a function in MATLAB called MYCURVEFIT that determines the y value of a best fit polynomial equation based on a single input, an x value. Predict the y value by fitting a 3rd order polynominal y=f(x) to the data points shown below. The input will be a single x value in the range of 0 to 20. The output should be a single y value obtained by evaluating the best fit third order polynomial at x.
X=0:0.5:20
Y=[14,16,18,22,28,35,50,68,90,117,154,200,248,309,378,455,550,654,770,900,1044,1200,1378,1560,...
1778,2004,2250,2500,2800,3100,3434,3786,4158,4555,4978,5424,5900,6401,6930,7474,8074]
You need to copy and paste the data above into your function
Solution:
The following will be used:
clc% clears screen
clear all% clears history
close all% closes all files
format long
MY CURVEFIT(7)
function y = MYCURVEFIT(x)
X = 0:0.5:20;
Y = [14, 16, 18, 22, 28, 35, 50, 68, 90, 117, 154, 200, 248, 309, 378, 455, 550, 654, 770, 900, 1044, 1200, 1378, 1560, 1778, 2004, 2250, 2500, 2800, 3100, 3434, 3786, 4158, 4555, 4978, 5424, 5900, 6401, 6930, 7474, 8074];
C = polyfit (X,Y,3);
y = polyval (C,x);
end
Internet sites often vanish or move, so that references to them can't be followed. Supposed 13% of Internet sites referenced in major scientific journals are lost within two years after publication. If a paper contains five Internet references, what is the probability that all five are still good two years later
Answer:
The probability that all five are still good two years later is 0.498.
Explanation:
Let X = number of internet sites that vanishes within 2 years.
The probability of an internet site vanishing within 2 years is: P (X) = p = 0.13.
A paper consists of n = 5 internet references.
The random variable X follows a Binomial distribution with parameters n = 5 and p = 0.13.
The probability mass function of a Binomial distribution is:
[tex]P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2,3...[/tex]
Compute the probability of X = 0 as follows:
[tex]P(X=0)={5\choose 0}(0.13)^{0}(1-0.13)^{5-0}=1\times 1\times 0.498421\approx0.498[/tex]
Thus, the probability that all five are still good two years later is 0.498.
We discussed making incremental dumps in some detail in the text. In Windows it is easy to tell when to dump a file because every file has an archive bit. This bit is miss- ing in UNIX. How do UNIX backup programs know which files to dump?
Answer:
Detailed procedure for UNIX backup programs to dump files is attached in picture.
Explanation:
See attached picture.
Write an application TestBooks that asks the user for a number of books read during summer. The application repeatedly creates that many book objects, and then prints to the screen information about the "smallest" book, (i.e. the book with the smallest number of pages), as well as the average number of pages per book read. Hint: Have counter variables pageSum and numBooks for keeping track of the total number of pages and the number of books. Other variables you may want to consider having are pages and title, for creating a new book object every time the user enters the page and title data.
Answer:
The code to this question as follows:
Code:
import java.util.*; //import package for objects
public class Book //defining class Book
{
private int pages; //defining integer variable
private String title; //defining String variable
Book(int pages, String title) //defining parameterized constructor
{
this.pages = pages; //holding value in private variable
this.title = title; //holding value in private variable
}
int getPages() // defining method getPages
{
return pages; //return a value
}
void setPages(int pages) //defining method setPages,that accepts integer value
{
this.pages = pages; //holding value
}
String getTitle() // defining method getTitle
{
return title; //return title
}
void setTitle(String title) //defining method setTitle
{
this.title = title; // holding value
}
public String toString() //defining method toString
{
return "Book{"+"pages=" + pages +", title='" + title + '\'' +'}'; //return value
}
boolean equals(Object o) //defining method equals
{
//using conditional statement
if (this == o) //check value
return true; //return value true
if (o == null || getClass() != o.getClass()) return false; //return value false
Book book = (Book) o; //reference
return pages == book.pages && Objects.equals(title, book.title); //return value
}
int compareTo(Book o) //defining method compareTo
{
return this.getPages() - o.getPages(); //return getPages value
}
}
Explanation:
In the above code, first, a package is import for holding objects, in the next line a class book is declared, inside these class two private variable pages and title is declared, in which pages is integer variable and title is string variable, parameterized constructor and method is declared, all the calculation is done in that methods, which can be described as follows:
In the constructor, the this keyword is used that holds private variable value. In the next step get and set method is used in which the set method is used to set the value by using parameters and the get method is used to return all the set values. At the last, the conditional statement is used that creates a book object and checks the condition, and defined method "compareTo" to return its value.Final answer:
The TestBooks application captures user input for books read over summer, calculates and displays details of the book with the least pages, and computes the average page count per book. It showcases fundamental programming techniques involving loops, user input handling, and basic arithmetic operations.
Explanation:
Designing an application like TestBooks in a programming environment involves understanding basic programming concepts such as loops, conditionals, and objects. The application's core functionality revolves around gathering user input for the number of books read and the details (title and pages) for each book. This process requires a loop that iterates based on the number of books read.
During each iteration, a book object is created with the provided title and number of pages. To find the book with the smallest number of pages and calculate the average number of pages per book, variables such as pageSum (for total pages) and numBooks (for the number of books) are essential.
Additionally, tracking the smallest book might involve storing its page count and title separately. Upon completion of data collection, the application calculates the average by dividing the total page count by the number of books and displays the smallest book alongside the average pages.
Write a C function namedliquid()that is to accept an integer number and theaddresses of the variablesgallons,quarts,pints, andcups. The passed integer rep-resents thetotalnumber of cups, and the function is to determine the number of gal-lons, quarts, pints, and cups in the passed value. Using the passed addresses, the functionshould directly alter the respective variables in the calling function. Use the relationshipsof 2 cups to a pint, 4 cups to a quart, and 16 cups to a gallon.
Answer:
#include <stdio.h>
#include <math.h>
void liquid(int ,int*,int*,int*,int*);
int main()
{
int num1, gallons, quarts, pints, cups;
printf("Enter the number of cups:");
scanf("%2d",&num1);
liquid(num1, &gallons, &quarts, &pints, &cups);
return 0;
}
void liquid(int x, int *gallons, int *quarts, int *pints, int *cups)
{
static int y;
y = x;
if (y >= 16)
{
*gallons = (y / 16);
printf("The number of gallons is %3d\n", *gallons);
}
if (y - (*gallons * 16) >= 4)
{
*quarts = ((y - (*gallons * 16)) / 4);
printf("The number of quarts is %3d\n", *quarts);
}
if ((y - (*gallons * 16) - (*quarts * 4)) >= 2)
{
*pints = ((y - (*gallons * 16) - (*quarts * 4)) / 2);
printf("The number of pints is %3d\n", *pints);
}
if ((y - (*gallons * 16) - (*quarts * 4) - (*pints *2)) < 2 || y == 0)
{
*cups = (y - (*gallons * 16) - (*quarts * 4) - (*pints *2));
printf("The number of cups is %3d\n", *cups);
}
return;
}
Define a function SetBirth, with int parameters monthVal and dayVal, that returns a struct of type BirthMonthDay. The function should assign BirthMonthDay's data member month with monthVal and day with dayVal.
#include
typedef struct BirthMonthDay_struct {
int month;
int day;
} BirthMonthDay;
/* Your solution goes here */
int main(void) {
BirthMonthDay studentBirthday;
int month;
int day;
scanf("%d %d", &month, &day);
studentBirthday = SetBirth(month, day);
printf("The student was born on %d/%d.\n", studentBirthday.month, studentBirthday.day);
return 0;
}
Answer:
The method definition to this question can be described as follows:
Method definition:
BirthMonthDay SetBirth(int monthVal, int dayVal) //defining method SetBirth
{
BirthMonthDay type; //defining structure type variable
type.month = monthVal; //holding value
type.day = dayVal;//holding value
return type; //retrun value
}
Explanation:
Definition of the method can be described as follows:
In the above method definition a structure type method "SetBirth" is defined, that accepts two integer parameter, that is "monthVal and dayVal". This method uses typedef for declaring the structure type method. Inside the method, a structure type variable that is "type" is declared, which holds the method parameter value and uses the return keyword to return its value.Answer: DateOfBirth SetBirth (int monthVal, int dayVal){
DateOfBirth tempVal;
int numMonths = monthVal;
int numDays = dayVal;
tempVal.numMonths = numMonths;
tempVal.numDays = numDays;
return tempVal;
Explanation:
Print "userNum1 is negative." if userNum1 is less than O. End with newline Convert userNum2 to 0 if userNum2 is greater than 8. Otherwise, print "userNum2 is less than or equal to 8.. End with newline. 1 public class UserNums 2public static void main (String args) int userNum1; int userNum2 userNumt - -1; userNum2 7; Your solution goes here / 10 System.out.printin("userNum2 is "userNum2);
Answer:
import java.util.Scanner;
public class num1 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter User name 1 and 2");
int userNum1 = in.nextInt();
int userNum2= in.nextInt();
if(userNum1<0){
System.out.println("userNum1 is negative.");
}
else if(userNum2>8){
userNum2 =0;
}
else{
System.out.println("userNum2 is less than or equal to 8..");
}
}
}
Explanation:
This is implemented in Java programming language
Using the scanner class, the user is prompted to enter two numbers
These are saved in the variable userNum1 and userNum2 respectively.
If, else if and else statements are then used according to the specifications given in the question.
Final answer:
The question involves implementing conditional logic in Java to check if one number is negative and to modify or print a message about another number based on its value. The solution includes an if-else structure to address the requirements and corrects any typos in the code provided by the student.
Explanation:
The logic needed to fulfill the requirements described in the question can be implemented within a Java program. Specifically, the provided code snippet appears to be in Java. Let's address each requirement one at a time, following a step-by-step approach based on the given code structure:
Check if userNum1 is negative and print the specified message, making sure to terminate the output with a newline.Determine if userNum2 is greater than 8, and if so, set its value to 0. Otherwise, print a message indicating that userNum2 is less than or equal to 8 followed by a newline.Here is the corrected and completed code based on the requirements:
public class UserNums {When you need to discipline employees, it is important to discipline different employees differently for the same policy violation in order to prevent them from becoming complacent. It is necessary to work independently from the human resources department and create your own procedures.
Answer: False
Explanation:
Employees should be discipline same way for same policy violations. This will give the employees the impression that no one was cheated or given preferential treatment. Everyone gets same stroke for same offence. The human resources department can't be do away with. They are the ones in charge of employees.
Final answer:
Disciplining employees should be consistent and fair, in line with established company policies and procedures in collaboration with the human resources department. Formal sanctions are part of disciplinary actions, while maintaining open communication and problem-solving focus. It is also critical to handle serious infractions with urgency and proper protocol.
Explanation:
Disciplining Employees and Workplace Policies
When it comes to disciplining employees, consistency and fairness are key principles. It is a misconception that disciplining different employees differently for the same policy violation prevents complacency; instead, it may create perceptions of unfairness and preferential treatment, which can demoralize staff and lead to bigger issues within the workplace. All disciplinary actions should adhere to the established procedures, working in concert with the human resources department, to ensure that the actions are legally defensible and align with company values and policies.
Employees must understand the expectations set for them and the potential consequences of failing to meet those standards. Formal sanctions such as termination or suspension are tools that can be used to enforce norms and deter rule-breaking behavior. Additionally, it is crucial to focus on problem-solving and open communication when addressing issues; this encourages a culture of accountability and improvement. Demonstrating respect for authority and offering exceptional customer service are behaviors that should be modeled and encouraged within the workplace.
It is also important to recognize the impact of personal relationships in small groups, where informal checks and balances often operate alongside formal mechanisms to regulate behavior. Nonetheless, serious infractions that endanger others, such as workplace violence, need immediate attention and should be handled with the appropriate urgency and procedure, often involving supervisors or security personnel.
Problem 1. A computer with a 5-stage pipeline like the one described in class deals with conditional branches by stalling for the next three cycles, so that it knows which branch to take. How much does stalling hurt the performance, if 20% of all instructions are conditional branches
Answer:
The correct answer to the following question will be "0.625".
Explanation:
Amount of clock cycles required for subsidiary conditional guidance
= 1+3
= 4
Probability of component instruction with condition
= 0.2
Amount of clock cycles required for further guidance
= 1
Probability of a particular command
= 0.8
Normal duration of the clock
= 0.2×4+1×0.8
= 0.8+0.8
= 1.6 clocks
Median number of instructions per clock
= 1/1.6
= 0.625
Slow down
= 0.625/1
= 0.625
2. Given the following list, write a snippet of code that would print the individual elements of the list using the indexes of the elements. my_list = [‘Rain fell from blue sky’, ’while I was having coffee,’, ‘procrastinating’]
Answer:
my_list = ["Rain fell from blue sky", "while I was having coffee,", "procrastinating"]
print(my_list[0])
print(my_list[1])
print(my_list[2])
Explanation:
Using Python Programming language:
Since the given list contains three string elements, the indexes are from 0-2
The print function can then be used to print elements are specific indexes as given above
Tiny College wants to keep track of the history of all its administrative appointments, including dates of appointment and dates of termination. ( Time-variant data are at work.) The Tiny College chancellor may want to know how many deans worked in the College of Business between January 1, 1960, and January 1, 2012, or who the dean of the College of Education was in 1990. Given that information, create the complete ERD that contains all primary keys, foreign keys, and main attributes.
Answer:
See attached pictures for ERD.
Explanation:
See attached pictures for explanation.
Which soft skill involves the ability to produce ideas that will give an organization an advantage with respect to other organizations?
A.
conflict resolution
B.
strategic thinking
C.
presentation skills
D.
teamwork
B. Strategic thinking
Explanation:
Strategic thinking helps to come up with great ideas that makes the company better than the other company. One can apply strategic thinking to arrive at decisions that can be related to your work or personal life. Strategic thinking involves developing an entire set of critical skills. Strategic thinking enables a business owner to determine how to use these resources most effectively and advance the company toward its objectives. Strategic thinking focuses the management team on markets that are most likely to succeed.
Write a program that does the following: 1. Uses a menu system 2. Creates an array with 25 rows and an unknow number of columns 3. You can assume that the row index represents one individual student 4. Each column represents an exam score for that individual student (the number of exams will vary by student) 5. Enter at least 10 students along with a varying number of exam scores for each different student. 6. Display the Average for all exams by each Student Id 7. Display the Average for each exam by Exam Number 8. Display the class average 9. Everything needs to be a written in Static Method 10. Do not forget your design tool The menu system will have an option to input grades for the next student. Once pressed the user will then enter how many exams that student has taken. The program will then ask the user to enter each of those exam scores. Menu will have an option to display the exam average by student. Menu will have an option to display the exam average by exam. Menu will have an option to display the current class average for all exams.
Answer:
import java.util.Scanner;
/**
*
* @author pc
*/
public class JaggedARrayAssignment {
private static int students[][] = new int[25][];//create a jagged array having 25 rows and unknown columns
public static void menu()
{
int index=0;//intitalize number of students to zero intially
Scanner sc=new Scanner(System.in);// create scanner for taking input from user
int choice;//choice
int maxExams=0;//maximum number of exams taken by any student
do
{
//print the menu
System.out.println("1-Input grades for next student");
System.out.println("2-Display the exam Average by student");
System.out.println("3-Display the exam Average by exam");
System.out.println("4-Display the current class average for all exams");
System.out.println("5-Exit");
choice=sc.nextInt();
//if choice is 1
if(choice==1)
{//ask how many xams
System.out.println("Please enter how many exams this student has taken?");
int noOfExams=sc.nextInt();//take input
students[index]=new int[noOfExams];//intialize array index by no of exams
System.out.println("Please enter the each of those exam scores one by one");//enter scores
if(maxExams<noOfExams)//if this noofexams is greater then update maxexams
maxExams=noOfExams;
//take scores from user
for(int i=0;i<noOfExams;i++)
{
students[index][i]=sc.nextInt();
}
index++;//increase index
}
else if(choice==2)
{
//calculate avregage by student and print it
System.out.println("*** Average by Student Id ***");
System.out.println("Student Id\tAverage Score");
for(int i=0;i<index;i++)
{
System.out.print((i+1)+"\t");//print student id
int sum=0;
//calculate sum
for(int j=0;j<students[i].length;j++)
{
sum=sum+students[i][j];
}
double avg=sum*1.0/students[i].length;//find average
System.out.printf("%.2f",avg);//print average by precison of two
System.out.println();
}
}
else if(choice==3)
{//caculate averag eby exams and print it
System.out.println("*** Average by Exam Number ***");
System.out.println("Exam Number\tAverage Score");
for(int i=0;i<maxExams;i++)
{
int sum=0,total=0;
for(int j=0;j<index;j++)
{
if(students[j].length>=i+1)
{
total++;
sum=sum+students[j][i];
}
}
double avg=sum*1.0/total;
System.out.print((i+1)+"\t");
System.out.printf("%.2f",avg);
System.out.println();
}
}
else if(choice ==4)
{//find iverall average
int sumtotal=0;
for(int i=0;i<index;i++)
{
int sum=0;
for(int j=0;j<students[i].length;j++)
{
sum=sum+students[i][j];
}
double avg=sum*1.0/students[i].length;
sumtotal+=avg;
}
double avgTotal=sumtotal*1.0/index;
System.out.println("Current class Average for all exams - "+avgTotal);
}
}while(choice!=5);
}
public static void main(String[] args) {
menu();
}
}
8.10 LAB: Convert to binary - functions Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in binary. For an integer x, the algorithm is: As long as x is greater than 0 Output x % 2 (remainder is either 0 or 1) x
Final answer:
The question requires creating a program to convert a positive integer to its binary representation using division by 2 and logging the remainders. This is related to the general mathematical concept of expressions involving bases, exponents, and logarithms.
Explanation:
The question involves writing a program to convert a positive integer into its binary equivalent. The algorithm includes repeatedly dividing the number by 2 and recording the remainder at each step, which will be either 1 or 0, until the number is reduced to 0. The remainders form the binary representation when read in reverse.
In general mathematical terms, any base b raised to a power n can be written as bn = en ln b, which can further be understood as equivalent to 10n.log10 b. This demonstrates the relationship between logarithms and exponential forms, which is a fundamental concept in converting numbers between different bases.
___________ increases the availability of systems even when an isolated outage occurs, while ___________ provides the procedures to recover systems after a major failure.
Answer:
Fault tolerance increases the availability of systems even when an isolated outage occurs, while disaster recovery provides the procedures to recover systems after a major failure.
Explanation:
There are two main properties of the system that should be under consideration while designing or deploying a system. fault tolerance and disaster recovery are the two important properties of the system.
In Fault tolerance, a system should be deigned as if some parts or components of the system will fail or not working properly, the system should work smoothly with the help of some alternate components or devices. This is called fault tolerance.
In Disaster recovery, a system should be able to overcome or restarts it working in case of some disaster. This feature enables the system to start its working after recovering from the disaster.
You have enabled IPv6 on two of your routers, but on the interfaces you have not assigned IPv6 addresses yet. You are surprised to learn that these two machines are exchanging information over those interfaces. How is this possible?a. Due to anycast addressingb. Due to ICMPv6c. Due to the NATv6 capabilityd. Due to the link-local IPv6 addresses
Answer:
You have enabled IPv6 on two of your routers, but on the interfaces you have not assigned IPv6 addresses yet. You are surprised to learn that these two machines are exchanging information over those interfaces. How is this possible?
a. Due to anycast addressing
b. Due to ICMPv6
c. Due to the NATv6 capability
d. Due to the link-local IPv6 addresses
The correct answer is D. Due to the link-local addresses
Explanation:
LINK-LOCAL ADDRESS
Link-local addresses are addresses that can be used for unicast communications on a confined LAN segment. The requirement with these addresses is that they are only locally-significant (i.e., restricted to a single LAN broadcast domain) and are never used to source or receive communications across a layer-3 gateway.
Typically, link-local IPv6 addresses have “FE80” as the hexadecimal representation of the first 10 bits of the 128-bit IPv6 address, then the least-significant 64-bits of the address are the Interface Identifier (IID). Depending on the IID algorithm the node’s operating system is using, the IID may use either modified EUI-64 with SLAAC, the privacy addressing method (RFC 4941)), or the newly published Stable SLAAC IID method(RFC 8064).
When a host boots up, it automatically assigns an FE80::/10 IPv6 address to its interface. You can see the format of the link-local address below. It starts with FE80 and is followed by 54 bits of zeros. Lastly, the final 64-bits provide the unique Interface Identifier.
FE80:0000:0000:0000:abcd:abcd:abcd:abcd
Link-local IPv6 addresses are present on every interface of IPv6-enabled host and router. They are vital for LAN-based Neighbor Discovery communication. After the host has gone through the Duplicate Address Detection (DAD) process ensuring that its link-local address (and associated IID) is unique on the LAN segment, it then proceeds to sending an ICMPv6 Router Solicitation (RS) message sourced from that address.
IPv6 nodes send NS messages so that the link-layer address of a specific neighbor can be found. There are three operations in which this message is used:
▪ For detecting duplicate address
▪ Verification of neighbor reachability
▪ Layer 3 to Layer 2 address resolution (for ARP replacement) ARP is not included in IPv6 as a protocol but rather the same functionality is integrated into ICMP as part of neighbor discovery. NA message is the response to an NS message. From the figure the enabling of interaction or communication between neighbor discoveries between two IPv6 hosts can be clearly seen.
"When an interrupt or a system call transfers control to the operating system, a kernel stack area separate from the stack of the interrupted process is generally used. Why?"
Answer:
Explanation:
There are two reasons, first, the operating system could be blocked because a program with poorly written user program does not allow for enough stack space.
Second, the kernel can leave data in the user memory of a program, and this data can be used for another user to get another delicate information.