Which statements describe the Mercalli scale? Check all that apply. This scale measures seismic waves based on their size. This scale rates an earthquake according to how much damage it causes. This scale produces a single rating for earthquakes that reach the surface. This scale uses Roman numerals to rank the damage caused by an earthquake. This scale measures the magnitude of an earthquake based on the size of seismic waves.
This scale rates an earthquake according to how much damage it causes.
This scale uses Roman numerals to rank the damage caused by an earthquake.
Explanation:The intensities of the earthquake can be easily measured with the scale called The Mercalli intensity scale. The Scale called the Richter scale considers the energy of the earthquake. But the Mercalli scale will not consider the energy of the earthquake.
The effects of the earthquake is considered by the Mercalli scale and then the intensity of the earthquake will be calculated based on the effects that is being observed.It is a type of linear measurement. It uses the Roman numerals for the purpose of ranking the damages that are caused by the earthquake.
Answer:
This scale rates an earthquake according to how much damage it causes.
This scale uses Roman numerals to rank the damage caused by an earthquake.
Explanation:
Its CORRECT because I passed the test 100% on e d g e n u i t y 2020
Which of the following statements best describes how waves interact with the media in which they move?
A. Only the energy travels with the wave, not the medium itself.
B. Both energy and the medium itself travel with the wave.
C. Only the medium travels with the wave; the energy remains static.
D. Neither the medium nor the energy travels with the wave.
Answer:
d
Explanation:
Neither the medium nor the energy travels with the wave.
How does the wave interact with the medium via which it travels?the speed of a wave relies upon the uses of the medium via which it travels.for instance, sound travels an awful lot faster through water than via air. whilst a wave enters a perspective a medium thru which its pace might be slower, the wave is bent in the direction of the perpendicular.Waves carry electricity via area or a medium without transporting be counted number.even as all waves can transmit electricity through a medium, wonderful waves also can transmit strength thru space. A medium is a cloth through which waves can tour.A wave is a disturbance in a medium that includes power with out a internet motion of particles. it could take the shape of elastic deformation, a version of stress, electric or magnetic depth, electric powered potential, or temperature.
wave, propagation of disturbances from region to location in a regular and organized way. most acquainted are floor waves that tour on water, however sound, light, and the movement of subatomic debris all exhibit wavelike homes.
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A 0.90-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 4.0 N for a distance of 3.0 m. How much farther would the force have to act for the block to have 61 J of kinetic energy?
Answer:
12 m
Explanation:
Work = change in energy
W = ΔE
Fd = ΔE
(4.0 N) d = 61 J
d = 15.25 m
Rounded to two significant figures, the distance the force would have to act over is 15 m, which is 12 m more than the 3.0 m it traveled.
Final answer:
To calculate the additional distance needed for the block to have 61 J of kinetic energy, we used the work-energy theorem and found that after applying a force of 4 N over 3 m, the kinetic energy is 12 J. An additional 49 J is needed, resulting in a requirement of an additional 12.25 m for the force to act upon.
Explanation:
To determine how much farther the force would have to act for the block to have 61 J of kinetic energy, we'll first use the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy (KE). Initially, the block has 0 J of kinetic energy since it's at rest, and the work done by a constant force is W = F * d, where F is the force and d is the distance the force is applied over.
Since 4 N of force is applied over 3 m, the work done is:
W = 4 N * 3 m = 12 J
This means the kinetic energy of the block is now 12 J after the force has been applied for 3 m. To reach 61 J of kinetic energy, the block needs an additional:
KEneeded = 61 J - 12 J = 49 J
Now, we can find the additional distance (dadditional) required using the same work done equation:
49 J = 4 N * dadditional
dadditional = 49 J / 4 N = 12.25 m
Therefore, the force would have to act over an additional 12.25 m to give the block 61 J of kinetic energy.
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a counter weight of 13.5kg is used to help a person of a mass 62.4kg do chin ups
1. Calculate the force applied by the person if he accelerates at 1.9m/s^2
2. calculate the magnitude of the tension in the wire.
Answer:
1. Force = -623.43 N
2.Tension = 106.65 N
Explanation:
Let us call the bigger mass [tex]M[/tex], and the smaller mass [tex]m[/tex].
Since the two masses are connected to each other, they must experience same acceleration (if they didn't, the unequal acceleration will cause the string to break. )
From the free body diagram, the forces acting on the mass [tex]M[/tex] are
[tex]T - Mg-F_p[/tex],
and according to Newton Second Law, this causes acceleration [tex]a[/tex]; therefore,
(1). [tex]\boxed{ T-Mg-F_p=Ma}[/tex].
Similarly, the forces acting on the mass [tex]m[/tex] are
[tex]T -mg[/tex],
which causes the acceleration [tex]-a[/tex] (upward); therefore,
[tex]T-mg=-ma \\[/tex]
or
[tex]\boxed{ mg-T = ma}[/tex]
From this equation we solve for [tex]T[/tex] and get:
[tex]T = mg-ma \\\\T =m(g-a).[/tex]
We put this into equation (1) and get:
[tex]m(g-a)-Mg-F_p=Ma[/tex]
[tex]F_p = m(g-a)-M(g+a)[/tex]
putting in [tex]M=62.4kg,m=13.5kg,[/tex] and [tex]a=1.9m/s^2[/tex], we get:
[tex]F_p=13.5(9.8-1.9)-62.4(9.8+1.9)\\\\\boxed{ F_p=-623.43N}[/tex]
The tension in the wire is
[tex]T =m(g-a)\\\\T = 13.5(9.8-1.9)\\\\\boxed{ T= 106.65N}[/tex]
A skateboarder who travels 60 meters in 30 seconds has a speed of
Answer:
2m/s
Explanation:
Speed= distance / time
? = 60m / 30s
speed= 60/30
60/30=2
speed= 2m/s
distinguishing sound and electromagnetic waves
Electromagnetic waves are not mechanical and transverse in nature, while
Sound waves are mechanical and longitudinal
Explanation:
In physics, waves are classified into two types:
Mechanical waves are those where the vibration is produced by the vibrations of the particles in a medium, therefore they need a medium to propagateElectromagnetic waves are those produced by the oscillations of electric and magnetic fields; they do not a medium to propagate, since they can travel through a vacuumMoreover, depending on the direction of the vibration, waves are further classified into:
Transverse waves: those where the direction of the vibration is perpendicular to the direction of propagation of the waveLongitudinal waves: those where the direction of the vibration is parallel to the direction of propagation of the waveElectromagnetic waves are not mechanical and transverse in nature (the oscillations of the electric and magnetic fields occur in a plane perpendicular to the direction of the wave), while
Sound waves are mechanical and longitudinal (the vibrations of the particles of the medium is back-and-forth along the direction of propagation of the wave)
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Before colliding , the momentum of Block A is +450 kg^ * m/s , and Block Bis -150 kg^ * m/s . After , Block A has a momentum +100 kg*m/s. What is the momentum of Block B afterwards ?
Answer:
Momentum of Block B after collision is 200 kg.m/s
Explanation:
Momentum of block A before collision is [tex]p_{1A} = 450kg.m/s[/tex]
Momentum of block B before collision is [tex]p_{1B} = -150kg.m/s[/tex]
Momentum of block A after collision is [tex]p_{2A} = 100kg.m/s[/tex]
According to conservation of momentum, total momentum before collision is equal to total momentum after collision
[tex]p_{1A}+p_{1B}=p_{2A}+p_{2B}\\450-150=100+p_{2B}\\p_{2B}=300-100\\p_{2B}=200 kg.m/s[/tex]
Momentum of Block B afterwards is 200 kg.m/s
Answer:
200
Explanation:
Plant and animal cells make exact copies through the process of)mitosis.B)oxidation.C)segmentation.D)interactive replacement.
Answer:
(A) Mitosis
Explanation:
What is the difference between relative time and absolute time?
Final answer:
Relative time determines the sequence of events without specific ages, while absolute time gives a precise measurement of age or date. Geologists use relative dating for stratigraphy and absolute dating for techniques like carbon dating. Time dilation in relativity illustrates that the rate of time is relative to the observer's motion.
Explanation:
The difference between relative time and absolute time lies in how they quantify the duration and sequence of events. Relative time refers to the sequence of events without assigning a specific age or date to them; it's a way to determine the order in which events have occurred. For instance, geologists use relative time to assert that one rock layer is older than another. On the other hand, absolute time or radiometric dating provides a precise measurement, giving an actual number or date to an event or object, such as specifying that a rock layer is 300 million years old.
These concepts are critical in fields such as geology, paleontology, and astronomy. In special relativity, the concept of time dilation shows that absolute time is not a fixed unit across all references, as the observed rate at which time passes depends on the observer's relative motion.
An example of relative dating would be using stratigraphy to understand that one geological layer is younger than the layer below it, while an example of absolute dating would be using carbon dating to determine the exact age of an archaeological object.
You are driving on a freeway and notice a small car (very small) cut off a big truck. Explain why it is a bad idea for the small car to cut off a very big truck?
Answer: small cars can stop and go fast big trucks can not
Explanation:
How do you calculate acceleration
Answer: acceleration is equal to the change in velocity per unit time in seconds.
a= ∆v / t = vf - vi / t
Explanation: change in velocity or ∆v can be expressed as (vf - vi)
Gamma radiation:
А
)
causes you to turn green when angry
B
travels at the speed of light
c) is easily stopped by paper
D
is a particle
Answer:
Is a particle
Explanation:
Gamma Ray is a particle and can be stopped with a very thick concrete and iron mixture.
Answer: Is a particle
Explanation:
Took a quiz!
The right-hand rule predicts which of the following?
The direction of the force on a charged object moving in a gravitational field.
The direction of the motion of a charged object moving through an electric field.
The speed of a test charge through a magnetic field.
The direction of the force on a charged object moving through a magnetic field.
Answer:
The direction of the force on a charged object moving through a magnetic field.
Explanation:
When considering the motion of a charged particle in a magnetic field, the important vectors are the magnetic field B, the velocity of the particle v, and the magnetic force exerted on the particle F. The vectors are all perpendicular to each other. As demonstrated by the right-hand rule.
prove: st = ut+½ at²
Explanation:
Let the distance covered by the body be s, initial and final velocities be u and v respectively and time taken be t.
[tex] \therefore Average\: velocity = \frac{u+v}{2} \\\\ Now, \:we \:know\: that\\\\ Distance \:covered\\ = Average\: velocity \times time\\\\ \therefore s= \frac{(u+v) }{2} \times t..... (1)\\\\[/tex]
By first equation of motion:
[tex] v = u + at[/tex]
Substituting the value of v in equation (1), we find:
[tex] s= \frac{(u+u + at)}{2} \times t\\\\ \therefore s= \frac{(2u + at)}{2} \times t\\\\ \therefore s= \frac{(2ut + at^2)}{2}\\\\ \therefore s= \frac{2ut} {2}+ \frac{at^2}{2}\\\\ \huge \orange {\boxed {\therefore s= ut+ \frac{1}{2}at^2}} \\\\[/tex]
Hence proved.
6) Consider a 10.0 kg block of wood that's released from rest at a distance 20.0m above the
ground and assume ground level is the point of zero gravitational potential energy. Calculate:
a) the initial gravitational potential energy of the block upon release
b) the translational kinetic energy of the block just before it hits the ground.
c) the translational kinetic energy of the block when it has fallen half the distance to the
ground.
d) the speed of the block when it has fallen half the distance to the ground.
Explanation:
a) Potential energy is weight times height.
PE = mgh
PE = (10.0 kg) (9.8 m/s²) (20.0 m)
PE = 1960 J
b) Energy is conserved. As the block falls, potential energy is converted to kinetic energy. Just before the block lands, all of the potential energy has been converted to kinetic energy.
KE = 1960 J
c) When the block has fallen half the distance, half the potential energy has been converted to kinetic energy.
KE = 1960 J / 2
KE = 980. J
d) Kinetic energy equals half the mass times the square of the velocity.
KE = ½ mv²
980. J = ½ (10.0 kg) v²
v = 14.0 m/s
Covert 60 mph to SI mks units
Answer:
26.8224
Explanation:
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Types of mechanical waves include
transverse waves.
longitudinal waves.
surface waves.
all of the above.
Mechanical waves are categorized into transverse, longitudinal, and surface waves. Transverse waves have disturbances perpendicular to wave direction, longitudinal waves have parallel disturbances, and surface waves are a combination of both.
Explanation:Mechanical waves can be classified based on the type of motion involved in the wave's propagation. There are mainly two categories of mechanical waves, namely transverse waves and longitudinal waves. However, there is also a third category known as surface waves, which is a combination of both transverse and longitudinal motions.
Transverse waves are characterized by a disturbance that moves perpendicular to the direction of wave propagation. An example of a transverse wave is a wave on a string or an electromagnetic wave, such as visible light. Whereas, longitudinal waves have disturbances that move parallel to the direction of propagation, like sound waves in air or water.
Surface waves are typically observed in fluids, like water waves in the ocean, where the motion of the particles at the surface follows a circular path, thus involving both longitudinal and transverse motions.
Therefore, when considering the types of mechanical waves, the answer would be all of the above as it includes transverse waves, longitudinal waves, and surface waves.
When a beam of light passes from substance 1 (index of refraction = 1.55) to substance 2, it has an angle of incidence of 39 ∘
and an angle of refraction of 24∘ What’s the index of refraction of substance 2? For those who’ll attempt the problem, Snells law should be used.k
Answer:
2.40
Explanation:
Snell's law states:
n₁ sin θ₁ = n₂ sin θ₂
where n₁ and n₂ are the indexes of refraction, θ₁ is the angle of incidence (relative to the normal), and θ₂ is the angle of refraction (relative to the normal).
1.55 sin 39° = n sin 24°
n = 2.40
What is the chemical formula of water?
A)N2O
B)H2O
C)NH3
D)HO3
Answer:
B H2O.
Explanation:
Because H2O stands for hydrogen, which has the amount of 2. And O stands for oxygen, which is by itself. When you put that together it makes H2O.
How do molecules behave when they transition from a solid, liquid, to gas?
What is a conversion factor?
a derived unit with a new name
the graph of recorded data
the density of a substance
a ratio of equivalent units
Answer:
A ratio of equivalent units
Explanation:
A conversion factor is a ratio of equivalent units and depends on which units are to be converted.
For example we want to convert 275 [mm] to inches, so we have to find the right conversion factor to allow us to work that conversion.
275 [mm] = inches = ?
[tex]275 [mm] * \frac{1in}{25.4mm} = 10.82 [in][/tex]
In this case the ratio is 1/25.4 = 0.039 [in/mm]
5) Consider pushing a 50.0 kg box through a 5.00 m displacement on both a flat surface and up a
ramp inclined to the horizontal by 15.0°. In both cases, you apply a force of 100.N parallel to the
surface (parallel to the floor or parallel to the ramp). Calculate the work done by:
a) the gravitational force as the box is pushed across the flat ground
b) the gravitational force as the box is pushed up the ramp
c) the force you apply as the box is pushed across the flat ground
d) the force you apply as the box is pushed up the ramp
a) The work done by the gravitational force on the flat surface is zero
b) The work done by the gravitational force on the ramp is -634 J
c) The work done by the applied force on the flat surface is 500 J
d) The work done by the applied force on up along the ramp is 500 J
Explanation:
a)
The work done by a force is given by the equation
[tex]W=Fdcos \theta[/tex]
where
F is the magnitude of the force
d is the dispalcement of the object
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this problem, we want to calculate the work done by the gravitational force as the box is pushed across the flat ground.
We immediately notice that the gravitational force acts downward, while the displacement is horizontal: therefore, the angle between force and displacement is [tex]90^{\circ}[/tex]; this means that [tex]cos 90^{\circ}=0[/tex], and therefore, the work done is zero:
[tex]W=0[/tex]
b)
In this case, the box is pushed along the ramp. We have:
[tex]F=mg=(50.0)(9.8)=490 N[/tex] is the magnitude of the force of gravity, where
m = 50.0 kg is the mass of the box
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
d = 5.00 m is the displacement of the box along the ramp
The ramp is inclined to the horizontal by [tex]15.0^{\circ}[/tex], therefore the angle between the force of gravity and the displacement of the box (moving up along the ramp) is:
[tex]\theta=90^{\circ}+15^{\circ}=105^{\circ}[/tex]
Therefore, the work done by gravity in this case is:
[tex]W=(490)(5.00)(cos 105^{\circ})=-634 J[/tex]
c)
In this case, we want to calculate the work done by the force you apply as the box is pushed across the flat ground.
Here we have:
F = 100.0 N (force applied)
d = 5.00 m (displacement of the box)
[tex]\theta=0^{\circ}[/tex] (the force is applied parallel to the flat surface, therefore force and displacement have same direction)
Therefore, the work done by the force you apply on the flat ground is:
[tex]W=(100.0)(5.00)(cos 0^{\circ})=500 J[/tex]
d)
In this last case, we want to calculate the work done by the force you apply as the box is pushed up along the ramp.
This time we have:
F = 100.0 N (force applied is the same)
d = 5.00 m (displacement of the box is also the same)
[tex]\theta=0^{\circ}[/tex] (the force is applied parallel to the ramp, therefore force and displacement have again same direction)
Therefore, the work done by the force you apply while pushing the box along the ramp is:
[tex]W=(100.0)(5.00)(cos 0^{\circ})=500 J[/tex]
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Water is made of two hydrogen atoms and one oxygen atom bonded together. Julia is describing how water undergoes a physical change when it boils. She says that the particles shift to be farther apart and that the oxygen and hydrogen separate. She also says that the total mass of the steam is the same as the initial water, and that heat energy was required to cause the change. She finishes her description by saying that the steam can be turned back into water if it is cooled
Boiling water causes molecular movement to increase without breaking H₂O bonds. It's a physical change where molecules move farther apart as steam forms. Cooling steam back into water is reversible, showcasing the unique properties of water's hydrogen bonding.
When water undergoes a physical change, such as boiling, the arrangement of the water molecules changes due to increased kinetic energy. However, the chemical composition remains the same, meaning that the hydrogen and oxygen atoms do not separate into different atoms; they stay bonded as H₂O. The molecules move farther apart, transitioning from a liquid to a gaseous state without changing their actual molecular structure. This transformation requires the input of heat energy, and it is completely reversible; if the steam (water vapor) is cooled, it will condense back into liquid water, demonstrating one of water's unique characteristics due to its ability to form and break hydrogen bonds.
During the boiling of water, the hydrogen bonds between water molecules are broken as they gain enough kinetic energy to escape into the air as steam. When water freezes, however, these molecules form a crystalline structure that is less dense than liquid water, which explains why ice floats. This phenomenon is distinctive to water and differs from most other liquids, where the solid form is denser than the liquid.
Mars has two moons, Phobos and Deimos, with masses 1.08 x 1016 kg and 1.8 x 1015 kg, respectively. How far apart
are the two moons when the gravitational force between them is 3 x 1012 N? Do not use scientific notation. Round
to one decimal
Answer:
20784.6m
Explanation:
Check attachment
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A friend is making vegetable soup. he add some salt to the simmering broth. the salt dissolves, and your friend says the broth saltiness it’s just right. after two more hours of cooking on the stove top the broth is way too salty, what happened?
Answer:
It is due to the effect of temperature on our taste receptors.
Explanation:
The taste receptors on our tongue is extremely sensitive.It can vary the taste of same element due to difference in temperature. So cooking further, the temperature of that food is increased which makes it taste more saltier than before.The solubility may also have the effect on this case because solubility increases with the increase in temperature. So at high temperature salt may expand and dissolve more to make the food saltier than before.HELP PLEASEEEE
how much time would it take to stop a 2.75kg ball traveling at 3.90m/s if a constant force of -5.00N is applied to it?
Answer: 2.15secs
Explanation:
Force = mass*velocity/time
F = 5N
M = 2.75kg
V = 3.90m/s
5.00 = 2.75*3.90/time
Time = 10.725/5.0 = 2.15sec
It will take approximately 2.145 seconds to stop a 2.75 kg ball traveling at 3.90 m/s with a constant force of -5.00 N.
First, we need to calculate the initial momentum of the ball using the formula:
Momentum (p) = mass (m) × velocity (v)
Given:
mass (m) = 2.75 kg and initial velocity (v) = 3.90 m/sp (momentum) = 2.75 kg × 3.90 m/s
p (momentum) = 10.725 kg·m/s
Next, we use the principle of impulse to find the time needed to stop the ball. Impulse (J) is equal to the change in momentum, and it is also equal to the applied force (F) times the time (t):
Impulse (J) = Force (F) × time (t)Since the force applied is -5.00 N (acting against the ball's motion), we rearrange the equation to solve for time:
t = J / FThe change in momentum is equal to the initial momentum (since the final momentum will be 0 when the ball stops):
J = 10.725 kg·m/sThus,
[tex]t = \frac{10.725 kg \cdot m/s}{ 5.00 N }= 2.145 s[/tex]Therefore, it will take approximately 2.145 seconds to stop the ball.
a person drops apple from window and it takes about 5s to reach the ground. Determine the height of the wimdow from the ground
Answer:
122.5 m
Explanation:
Given:
Time taken by apple to reach ground (t) = 5 s
Acceleration of the apple is due to gravity (g) = 9.8 m/s²
The displacement of the apple is equal to the height of window (h) = ?
As the apple is dropped, the initial velocity is, [tex]u=0\ m/s[/tex]
Now, using Newton's equation of motion along the vertical direction that relates displacement, initial velocity, acceleration and time taken, we have:
[tex]h=ut+\frac{1}{2}gt^2[/tex]
Plug in the given values and solve for 'h'. This gives,
[tex]h=0+\frac{1}{2}\times 9.8\times 5^2\\\\h=4.9\times 25=122.5\ m[/tex]
Therefore, the height of the window above the ground is 122.5 m.
Find the equivalent resistance between points A and B shown in the figure(Figure 1). Consider R1 = 1.9 Ω , R2 = 2.5 Ω , R3 = 4.4 Ω , R4 = 3.5 Ω , R5 = 5.5 Ω , and R6 = 7.1 Ω .
The equivalent resistance between the point A and B is 0.95 ohm.
Explanation:
Solving for R3, R4, and R5 since they are in parallel formation. Their equivalent resistance could be
1 / R = (1 /R3) + (1 / R4) + (1 / R5)
= (1 / 4.4) + (1 / 3.5) + (1 / 5.5)
1 / R = 0.69
R = 1.43 ohm.
Next solving R6 and leg of this resistance which are in series connection,
r = R + R6
= 1.43 + 7.1)
r = 8.53 ohm.
Finally the three resistance R1, R2 and the leg resistance which are in parallel connection,
1 / r = (1 / 1.9) + (1 / 2.5) + (1 / 8.53)
= 1.04 ohm
Equivalent resistance R eq = 1 / 1.04 = 0.95 ohm.
The equivalent resistance of the circuit shown in the attachment is 0.958 Ω.
What is a resistor?The resistor can be defined as a device that has some electrical resistance and that is used in an electric circuit for protection, operation, or current control.
Given that there are 6 resistors connected in-between points A and B as shown in the attachment.
R1 = 1.9 Ω, R2 = 2.5 Ω, R3 = 4.4 Ω, R4 = 3.5 Ω, R5 = 5.5 Ω, and R6 = 7.1 Ω.
The resistors R3, R4, and R5 are in parallel connections. Let's consider that R' is the equivalent resistor of this parallel connection, then,
[tex]\dfrac {1}{R'} =\dfrac {1}{R_3} + \dfrac {1}{R_4}+\dfrac {1}{R_5}[/tex]
[tex]\dfrac {1}{R'}= \dfrac {1}{4.4}+ \dfrac {1}{3.5}+\dfrac {1}{5.5}[/tex]
[tex]\dfrac {1}{R'}= 0.69[/tex]
[tex]R' = 1.45[/tex]
The equivalent resistor is in series connection with R6. Hence, the equivalent resistance R'' is given below.
[tex]R'' = R' + R_6[/tex]
[tex]R'' = 1.45 + 7.1[/tex]
[tex]R'' = 8.55[/tex]
Now the resistors R1, R2, and R'' are in parallel connection, so the equivalent resistor R is given as,
[tex]\dfrac {1}{R} = \dfrac {1}{R_1} + \dfrac {1}{R_2} + \dfrac {1}{R''}[/tex]
[tex]\dfrac {1}{R} = \dfrac {1}{1.9} +\dfrac {1}{2.5} +\dfrac {1}{8.55}[/tex]
[tex]\dfrac {1}{R} = 1.043[/tex]
[tex]R = 0.958[/tex]
Hence we can conclude that the equivalent resistance of the circuit shown in the attachment is 0.958 Ω.
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What is a mechanical property that describes the extent to which solid materials can be plastically deformed without fracturing?
Answer:
Elasticity
Explanation:
The property of a body, by virtue of which it tends to regain its
original size and shape when the applied force is removed, is
known as elasticity and the deformation caused is known
as elastic deformation.
Ductility is the mechanical property that describes the extent to which solid materials can be plastically deformed without fracturing.
Explanation:The mechanical property that describes the extent to which solid materials can be plastically deformed without fracturing is ductility.
Ductility is the ability of a material to undergo significant plastic deformation under tensile stress without breaking. Ductile materials, such as metals, can be stretched into thin wires or shaped into various forms without fracturing.
For example, copper and aluminum are highly ductile metals that can be easily drawn into wires and used for electrical conductivity, while brittle materials like glass or ceramic lack ductility and break easily when subjected to stress.
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Which is an example of physical weathering?
(1 point)
acid rain breaking down compounds in
rock statues
rock breaking apart when it falls from a
cliff
oxygen interacting with minerals in rock
bits of iron in rock rusting when exposed
to oxygen and water in
Answer:
Rock breaking apart when it falls from a cliff
Rock breaking apart when it falls from a cliff is an example of physical weathering (option B)
What physical weathering?Physical weathering, also known as mechanical weathering, involves the physical breakdown of rock into smaller pieces without changing its chemical composition.
In this case, the force of gravity and the impact of the falling rock cause it to break into smaller fragments, which is a mechanical process and a common example of physical weathering. The other options involve chemical weathering processes.
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Radium-228 decays by alpha decay. Part of the nuclear equation is shown
below. Fill in the blank with a number.
Ra → He+7 Rn
Answer here
SUBMIT
₈₈ Ra²²⁸ → ₂He⁴ + ₈₆Rn²²⁴
Explanation:
Radium -228 is a radio-active element. It undergoes ∝- decay which means it emits a helium particle that is composed of 2 neutrons and 2 protons. Then the radium- 228 is converted into radon-224 which is again a radio-active element contains 86 protons and 138 neutrons by emitting an ∝-particle. The other isotopes of Ra²²³, Ra²²⁴ and Ra²²⁶ occurs naturally in the chain decay of the radio-active elements Uranium and Thorium. The ∝- decay of ₈₈ Ra²²⁸ is given as,
₈₈ Ra²²⁸ → ₂He⁴ + ₈₆Rn²²⁴