The pair of sets, {x | x < 0} and {x | x > 0}, has no solution because no number can be simultaneously less than zero and greater than zero. The other pairs do have solutions as they include the number zero.
Explanation:The set of mathematical expressions provided in the question represent intervals along the number line. Understanding which intervals overlap and which intervals don't is the key to comprehending which of these options potentially has a solution. To consider when these sets will have no solution, you must find where no numbers exist that can satisfy both conditions simultaneously.
The first pair, {x | x < 0} and {x | x > 0}, means 'the set of all x such that x is less than 0' and 'the set of all x such that x is greater than 0'. Because no number can be both less than zero and greater than zero at the same time, this pair has no solution.
The other pairs, {x | x ≤ 0} and {x | x ≥ 0} and {x | x ≤ 0} or {x | x ≥ 0} do have solutions because they both include 0 itself, so there are numbers that can satisfy both conditions.
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Given the trinomial 5x2 - 2x - 3, predict the type of solutions.
Two rational solutions
One rational solution
Two irrational solutions
Two complex solutions
Answer:
Two rational solutions. This is the right answer
Step-by-step explanation:
What is 2/3 times 26 but estimated ?
b-4/6=b/2. Solve for b.
2(b−4)=6(b) 2b - 8 = 6b 2b - 6b = 8 -4b = 8 Now you can solve.....
What are prime numbers of 50?
The linear function f(x) passes through the points (1,2) and (3,0).
A few values from the exponential function g(x) are shown in the table
What is the positive difference in the y-intercept of f(x) and g(x)?)
Solve and graph the absolute value inequality: |2x + 4| > 8. number line with open circles on negative 6 and 2, shading in between. number line with closed circles on negative 6 and 2, shading going in the opposite directions. number line with open circles on negative 6 and 2, shading going in the opposite directions. number line with open circles on negative 2 and 2, shading going in the opposite directions.
Final answer:
The inequality |2x + 4| > 8 is resolved by considering the inside expression being greater than 8 and less than -8, which leads to x > 2 and x < -6. The proper representation on a number line is with open circles on -6 and 2, shading away from these points, indicating the range of solutions.
Explanation:
To solve the absolute value inequality |2x + 4| > 8, we must consider the two scenarios that could make the inequality true: when (2x + 4) is greater than 8 and when -(2x + 4) is less than -8. Absolute values denote the distance from zero, so they are never negative. Since the inequality is strict (indicated by '>'), we will use open circles in the graph.
First, let's consider when the expression inside the absolute value is positive:
2x + 4 > 8
2x > 4
x > 2
This scenario corresponds to all x-values greater than 2.
Now for the negative scenario:
-(2x + 4) > 8
-2x - 4 > 8
-2x > 12
x < -6
This scenario corresponds to all x-values less than -6.
The correct graph of the solution set on a number line would have open circles on -6 and 2, with shading going in opposite directions away from these points, indicating all the numbers greater than 2 and all the numbers less than -6 satisfy the original inequality.
Based on this, the third choice is correct: A number line with open circles on negative 6 and 2, shading going in the opposite directions.
What is 788 divided by 14 in a long division model?
One year there was a total of 73 commercial and noncommercial orbital launches worldwide. In addition, the number of noncommercial orbital launches was one more than three times the number of commercial orbital launches. Determine the number of commercial and noncommercial orbital launches.
Final answer:
The number of commercial orbital launches is 18, and the number of noncommercial orbital launches is 55.
Explanation:
Let's assume that the number of commercial orbital launches is represented by x. According to the problem statement, the number of noncommercial orbital launches is more than three times the number of commercial orbital launches. So, the number of noncommercial orbital launches would be 3x + 1.
Given that the total number of commercial and noncommercial orbital launches is 73, we can set up the equation:
x + (3x + 1) = 73
Combining like terms, we get:
4x + 1 = 73
Subtracting 1 from both sides, we get:
4x = 72
Dividing both sides by 4, we get:
x = 18
Therefore, there were 18 commercial orbital launches and 55 noncommercial orbital launches.
The number of commercial orbital launches is 24, and the number of noncommercial orbital launches is 49.
Explanation:Let's assume that the number of commercial orbital launches is represented by 'x'. According to the question, the number of noncommercial orbital launches is one more than three times the number of commercial orbital launches. So, the number of noncommercial orbital launches can be represented by '3x + 1'.
Given that the total number of commercial and noncommercial orbital launches is 73, we can set up the equation 'x + (3x + 1) = 73' to represent the total launches. Solving this equation will give us the values of 'x' and '3x + 1', which represent the number of commercial and noncommercial orbital launches, respectively.
By solving the equation, we find that 'x = 24' and '3x + 1 = 73 - 24 = 49'.
What is 324 divided by 6??
If $2500 is invested at an interest rate of 2.5% per year, compouded daily, find the value of the inevestment after 2 years
if 2tanA=3tanB,then prove that tan(A-B)=sin2B/(5-cos2B) ...?
What is the fifth root of -32?
The fifth root of -32 is -2. To find it, think of a number that, when raised to the power of 5, gives the original number.
The fifth root of -32 is -2. To find the fifth root of a number, we can think of it as finding a number that, when raised to the power of 5, gives us the original number. In this case, -2 * -2 * -2 * -2 * -2 = -32.
Find the distance between -422 and 166.
Find the greatest common factor of the monomials. 16x, 36x ...?
Final answer:
The greatest common factor of the monomials 16x and 36x is 4x, obtained by finding the common prime factors of 16 and 36 and including the variable x, which is present in both monomials.
Explanation:
To find the greatest common factor of the monomials 16x and 36x, we need to break each monomial into its prime factors and compare them.
Prime factors of 16 are 2 x 2 x 2 x 2.
Prime factors of 36 are 2 x 2 x 3 x 3.
Both 16 and 36 have two 2's in common.
Therefore, the GCF of 16 and 36 is 2 x 2 = 4. Since x is present in both monomials, x is also part of their GCF.
The greatest common factor of the monomials 16x and 36x is therefore 4x.
What is the decimal expansion of the following fraction?
1/4
1.4
0.14
___
0.25
0.25
Pleeease help!!
Write an equation in point-slope form of the line that passes through the given point and with the given slope m.
(-2,1);m=7
Which expression is equal to 5/(sqrt)11?
a) 5(sqrt)11/11
b) (sqrt)5/11
c) (sqrt)55/11
d) 25/11
please help, I'm confused.
Answer:
Option A is correct
the expression is equal to [tex]\frac{5}{ \sqrt{11}}[/tex] is [tex]\frac{5\sqrt{11}} {11}[/tex]
Explanation:
Given expression is, [tex]\frac{5}{ \sqrt{11}}[/tex]
Multiply and divide by the denominator by [tex]\sqrt{11}[/tex] in the given expression, we have,
[tex]\frac{5}{\sqrt{11}} \times \frac{\sqrt{11}} { \sqrt{11}}[/tex]
or
[tex]\frac{5 \cdot \sqrt{11}} {\sqrt{11} \cdot \sqrt{11}}[/tex]
use : [tex]\sqrt{a}\cdot\sqrt{a}=(\sqrt{a} )^2 = a[/tex]
then;
[tex]\frac{5\sqrt{11}} { (\sqrt{11})^2} =\frac{5\sqrt{11}} {11}[/tex]
Therefore, the expression is equal to [tex]\frac{5}{ \sqrt{11}}[/tex] is, [tex]\frac{5\sqrt{11}} {11}[/tex]
Goran is going to rent a truck for one day. There are two companies he can choose from, and they have the following prices. Company A charges $93 and allows unlimited mileage. Company B has an initial fee of $65 and charges an additional $0.70 for every mile driven. For what mileages will Company A charge less than Company B? Use m for the number of miles driven, and solve your inequality for m .
Mrs. Curtis wants to buy online tickets for a concert. Two options are given here.
Option 1: $53 for each ticket plus a shipping fee of $10
Option 2: $55 for each ticket and free shipping
What is a system of equations to represent the costs of the tickets?
Express your equations in the form of y=mx+by=mx+b where x is the number of tickets purchased and y is the total cost.
You work at a dog food factory. The factory makes 10,600 kilograms of dog food a day. How many metric tons of dog food does the factory make a day?
What is the lateral area of a pyramid with base edges 5ft and surface area 55ft^2? ...?
Help Please? Factor Completely: 2x2 − 32
Prime
2(x2 − 16)
2(x + 4)(x + 4)
2(x + 4)(x − 4) ...?
Answer:
Option 4th is correct
[tex]2 \cdot (x-4)(x+4)[/tex]
Step-by-step explanation:
Using difference of square:
[tex]a^2-b^2=(a-b)(a+b)[/tex]
GCF is the largest number that divide the given polynomial or expression.
Given the expression:
[tex]2x^2-32[/tex]
We have to completely factor the expression.
GCF of [tex]2x^2[/tex] and 32 is, 2
then;
[tex]2 \cdot (x^2-16)[/tex]
Using difference of square
[tex]2 \cdot (x-4)(x+4)[/tex]
therefore, the completely factor of [tex]2x^2-32[/tex] is, [tex]2 \cdot (x-4)(x+4)[/tex]
Answer:
D. 2(x + 4)(x − 4)
Step-by-step explanation:
If A is an obtuse angle in a triangle and sin A is 5/13, calculate the exact value of sin 2A
Your car gets 20 miles per gallon of gas. This is 4 more miles per gallon than your friend's car gets. How many miles per gallon does your friend's car get?
Answer:
Answer:
16 miles per gallon
Step-by-step explanation:
Write 0.000045 in scientific notation.
The options are:
A. 4.5 · 10-4
B. 4.5 · 10-6
C. 4.5 · 10-5
D. 4.5 · 105
A steel plate has the form of a quarter of a circle with a radius of 49 cm. Two 2-cm holes are to be drilled in the plate. Let (X1,Y1) and (X2,Y2) be the coordinates of the centers of the holes. Find the coordinates for both holes.
The task is to determine the coordinates of two 2-cm holes in a quarter-circle steel plate, but there is insufficient information to provide a precise location without additional details or constraints.
Explanation:The question requires us to find the coordinates for the centers of two 2-cm holes to be drilled in a steel plate, which is shaped like a quarter of a circle with a radius of 49 cm. Assuming the plate is positioned with its corner at the origin (0,0), with the circular edge encompassed by the positive x-axis and positive y-axis, the holes should be placed in such a way that their centers within the quarter circle are equidistant from the axes and from the plate's circular edge.
However, the question does not provide sufficient information or constraints about the location of the holes within the quarter-circle plate. To determine the exact coordinates, we need more specifics, such as how far from the edges or any other centering constraints for the holes. Without this additional information, there are infinitely many possible coordinates for the holes that meet the given condition of being within the quarter-circle plate.
If the holes are to be evenly distributed and placed symmetrically, a possible choice could be to align the centers of the holes along the line y = x, which bisects the quarter-circle. Yet, without precise instructions, we cannot provide a definitive answer to the coordinates of the holes.
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Where is the dependent variable plotted on a line graph?
can u do this bro 100x7+8-678x56
Answer:
-37260
Step-by-step explanation:
did it in my head
Judy has a sugar cone and wants to know how many cubic inches of ice cream it will hold if it is filled completely to the top of the cone and no more. the cone has a height of 4.5 inches and a radius of 1.5 inches.
The cone of dimension 4.5 inches height and 1.5 inches radius can hold 9.425 inches^3 of ice cream.
A sugar cone can be seen as a three-dimensional object, specifically a cone, which has a known formula for calculating its volume.
Volume of a cone: (1/3) x π x radius2 x height
Substituting the given values: (1/3) x π x 1.52 x 4.5 = 9.425 inches^3.
what does it mean for an equation to be balanced and why must you keep an equation in balance?