What net force is required to push a sofa with a mass of 59 kilograms so that it accelerates at 9.75 meters/secondÆ? (Assume a flat, frictionless surface.)
A. 6.1 Newtons
B. 59 Newtons
C. 5.8 x 10^2 newtons
D. 6.0 x 10^2 newtons

The ball will have a speed of 22 m/s after 2 seconds.

When the ball rolls off the edge of a horizontal roof, it becomes a projectile and begins to fall under the influence of gravity. The horizontal component of its velocity remains constant, so after 2 seconds, the ball will still have a horizontal speed of 10 m/s.

However, the vertical component of its velocity will increase due to the acceleration of gravity. The acceleration due to gravity is approximately 9.8 m/s². So after 2 seconds, the ball will have accelerated 9.8 m/s² for 2 seconds, resulting in a change in velocity of 19.6 m/s.

To find the speed of the ball after 2 seconds, we need to find the resultant velocity by using the Pythagorean theorem. The initial horizontal velocity is 10 m/s and the change in vertical velocity is 19.6 m/s. So:

Resultant velocity = sqrt((10)^2 + (19.6)^2) = 22 m/s.

Therefore, the correct answer is d. 22 m/s.

Final answer:

The final speed of a ball rolling off a horizontal roof with an initial horizontal speed of 10 m/s after 2 seconds will be 22 m/s, due to the additional vertical velocity it gains from gravity. So the correct option is d.

Explanation:

A ball rolls off the edge of a horizontal roof at 10 m/s. To determine the speed of the ball 2 seconds later, we use the equation for the final velocity of an object in free fall: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (9.8 m/s²), and t is time. Since the ball rolls off horizontally, the initial vertical velocity is 0, and the horizontal velocity remains the same since there's no air resistance. Hence, the horizontal velocity after 2 seconds is still 10 m/s. For the vertical velocity, we use u=0, a=9.8 m/s², and t=2 s:

Vertical velocity after 2 seconds = 0 m/s + (9.8 m/s² * 2 s) = 19.6 m/s

We now have both horizontal and vertical velocities. The speed of the ball will be the vector sum of these two velocities, calculated using the Pythagorean theorem:

Total speed = sqrt(10 m/s² + 19.6 m/s²) = 22 m/s

Therefore, the correct answer is (d) 22 m/s.

If the gas in a sealed container has a pressure of 50 kPa at 300 K, so the pressure if the temperature rises will be 60 kPa.

The physical force applied to an object is referred to as pressure. A perpendicular force is applied to the surfaces of the objects per unit area. The basic formula for pressure is F/A. (Force per unit area). Pressure is measured in Pascals (Pa).

There are several types pressure of them are Atmospheric Pressure, Gauge pressure, Differential Pressure, and Absolute pressure.

According to the question,

PV=nRT

P/T=nR/V

P/T= constant

Therefore,

(P/T)1=(P/T)2

50/100=P2/360

P2=50×(360/300)

P2= 60 kPa.

Hence, the pressure P2 is 60 kPa.

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Our Sun and Earth are part of what we call our solar system. There are eight big planets and five small, dwarf planets in the solar system. Each planet orbits the Sun.

The speed of the ball just before impact is calculated using the conservation of energy principle, translating the potential energy into kinetic energy and solving for velocity to obtain 5.60 m/s.

The speed of the ball just before impact on the building site, we can make use of the principle of conservation of energy. Initially, when the ball is held at a height, it possesses potential energy. When released, this potential energy is converted into kinetic energy just before impact. Given the height it falls through, we can calculate its final speed using the equation for potential energy (PE) and kinetic energy (KE):

PE = KE at the point of release and just before impact,

mgh = ½ mv²,

where m is the mass of the ball, g is the acceleration due to gravity (approximately 9.81 m/s²), h is the height, and v is the final speed. After rearranging and solving for v, we get v = √(2gh).

Inserting the values: v = √(2 * 9.81 m/s² * 1.6 m) = √(31.392) = 5.60 m/s. Therefore, the speed of the ball just before impact is approximately 5.60 meters per second.

Answer:

Ultraviolet radiation  

Explanation:

Apex

The basis for dividing the atmosphere into four layers is due to the temperature gradient of the layers.

The layer of gases that covers Earth is known as the atmosphere. The gravitational pull of the planet's neighbor, Earth, keeps it close to the surface.

Here,

The troposphere, stratosphere, mesosphere, thermosphere, and exosphere are the principal layers of the atmosphere, listed in order from lowest to highest. The troposphere of the planet is a layer of air that rises from the surface of the planet to an average height of 12 kilometres (7.5 miles), however it is higher in the equator and lower at the poles.

Temperature gradient is the term used to describe a difference in temperature with distance. According to the temperature gradient inside each layer, the Earth's atmosphere is classified into layers, and each layer's heat source defines its own temperature gradient.

Hence,

The basis for dividing the atmosphere into four layers is due to the temperature gradient of the layers.

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Answer:

B) Copper atoms have loosely held free electrons in their outer shell that is able to move freely in other atoms.

Explanation:

A material which has loosely held free electrons in its outermost shell is always a good conductor. These loosely held free electrons move from atoms to atoms and cause conductivity. It is known that copper and other metals are good conductors. Therefore, option (B) supports the argument and is a right answer.

Answer: The answer is 2. Prohibited the Chinese laborers from entering the country.

Explanation: The Chinese Exclusion Act of 1882 was a federal law in the United States signed by President Chester. It effectively halted Chinese immigration. I hope your answer is very helpful, please mark me as Brainliest and have a wonderful day! :D

Before answering this question, first we have to understand the effect of ratio of surface area to volume on the rate of diffusion.

The rate of diffusion for a body having larger surface area as compared to the ratio of surface area to volume will be more than a body having less surface area. Mathematically it can written as-

                           V∝ R            [ where v is the rate of diffusion and r is the ratio of surface area to volume]

As per the question,the ratio of surface area to volume for a sphere is given [tex]0.08m^{-1}[/tex]

The surface area to volume ratio for right circular cylinder is given [tex]2.1m^{-1}[/tex]

Hence, it is obvious that the ratio is more for right circular cylinder.As the rate diffusion is directly proportional to the surface area to volume ratio,hence rate of diffusion will be more for right circular cylinder.

Hence the correct option is B. The rate of diffusion would be faster for the right cylinder.

Answer:  d. congruent sides

Explanation:

The distance formula is a formula in geometry to calculate the length of a line segment having two distinct point on a Cartesian plane

The distance formula to calculate the distance between two distinct points A(a,b) and B(p,q) is given by :-

[tex]\text{d}=\sqrt{(p-a)^2+(q-b)^2}[/tex]

Since it is used to calculate the distance between two points therefore, it is used to check whether a quadrilateral has congruent sides.

Hence, the distance formula can be used to prove a quadrilateral has congruent sides.

Answer:

C) plasma

A star is a luminous ball of hot plasma held together by its own gravity.

Explanation:

Stars are formed from molecular clouds. When a cloud receives an impact wave from a near supernova or another astronomical event, as a consequence, it will start to collapse under its gravity, until it breaks in small pieces (each of this pieces will become a star).

Stars are submitted to a hydrostatic equilibrium (its gravitational force pulls inward and its nuclear pressure pulls outward), that gave rise to higher pressures and higher temperatures, those temperatures allow atoms being completely ionized¹. Stars are compounded with a gas mixture of atoms, free protons and free electrons (plasma).

¹Ionized: When an atom loses electrons.

Answer: His average speed (in m/s) for the race was 10.08 m/s

Explanation:

Given data

Total distance traveled , D= 100 meter

Total time taken , T= 9.92 seconds

>The average speed([tex]V_{avg}[/tex] ) of an object is the total distance traveled by the object divided by the total time taken to cover that distance .i.e.,

[tex]V_{avg}=\frac{D}{T}=\frac{100}{9.92}\, \frac{m}{s}=10.08\: \frac{m}{s}[/tex]

Thus his average speed (in m/s) for the race was 10.08 m/s

Answer:

[tex]725\ degree=2\ revolution[/tex]                

Explanation:

We know that 1 complete revolution is equal to 360 degrees. We need to find the number of complete revolution needed to draw the angle of 725 degrees.  

Since, 1 revolution = 360 degrees

or

[tex]1\ revolution=2\pi \ radian[/tex]

[tex]1\ degree=\dfrac{1}{360}\ revolution[/tex]

[tex]725\ degree=\dfrac{725}{360}\ revolution[/tex]

[tex]725\ degree=2.01\ revolution[/tex]

or

[tex]725\ degree=2\ revolution[/tex]

So, to draw an angle of 725 degrees, there are 2 revolutions. Hence, this is the required solution.

By definition, the gravitational force is given by:

[tex] F = G(\frac{m1m2}{r^2}) [/tex]

Where,

G: gravitational constant

m1: mass of object 1

m2: mass of object 2

r: distance between objects:

We know that the force is equal to 10N:

[tex] G(\frac{m1m2}{r^2}) = 10 [/tex]

If the distance is double we have:

[tex] F = G(\frac{m1m2}{(2r)^2}) = G(\frac{m1m2}{4r^2}) = \frac{1}{4}G(\frac{m1m2}{r^2}) [/tex]

[tex] \frac{1}{4}(10) = 2.5 [/tex]

Therefore, the new force is:

2.5 newtons

Answer:

the changed force of attraction between them is:

A. 2.5 newtons

Final answer:

The linear speed of a point on a 3.5-inch floppy disk rotating at 31.4 rad/s is calculated using the formula v = r⋅ω, resulting in a linear speed of 1.396 m/s.

Explanation:

The question is about determining the linear speed of a point on a 3.5-inch floppy disk that rotates with an angular speed. The linear speed v can be calculated using the formula v = r⋅ω, where r is the radius of the disk and ω is the angular speed. Given the diameter of the disk is 3.5 inches, we must first convert it to the radius in meters which is 0.04445 meters (since 1 inch = 0.0254 meters). Therefore, the linear speed is v = 0.04445 m × 31.4 rad/s = 1.396 m/s.

A signaling site criterion involves selecting a location based on characteristics that enhance the likelihood of successful signal transmission, much like the site location analysis done by geographers.

A signaling site criterion is an important factor when selecting a location for sending out signals so that they can be effectively detected by friendly forces or intended recipients. This concept is similar to site location analysis in geography, where geographers assess various factors to determine the most advantageous location for a city, business, or other establishments based on site and situation factors. The criteria focus on attributes such as the availability of resources, the location's visibility, accessibility, and the likelihood of successful signal transmission. Like how a city benefits from a good harbor or central location, a signaling site should enhance the probability of signal detection while considering both the physical characteristics of the site and the external factors affecting its efficacy.

Answer:

F = 100 N

Explanation:

Since the wagon is pulled along the inclined plane upwards so here the component of the weight of the wagon will act down the plane.

There is no friction force on the wagon so here in order to move the wagon upwards along the plane we require a force along the plane upwards which must be of same magnitude as that the magnitude of weight along the plane downwards.

now the component of weight along the inclined is given as

[tex]F = Wsin\theta[/tex]

[tex]F = 200 sin30[/tex]

[tex]F = 200(0.5) [/tex]

[tex]F = 100 N[/tex]

To pull a 200 N wagon up a 30-degree incline at constant speed, a parallel force of 100 N is needed. This calculation assumes no friction. It is derived using the component of the gravitational force parallel to the incline.

To determine the force needed to pull a 200 N wagon up a 30-degree incline at a constant speed, we need to analyze the components of the gravitational force acting on the wagon.

Therefore, a force of 100 N parallel to the incline is needed to pull the wagon up at a constant speed, assuming no friction.

The correct answer to the question is D). Ability to combine with oxygen.

EXPLANATION:

Before going to answer this question, first we have to understand physical and chemical change.

The change or reaction  is said to be physical if there will be no change in the chemical configuration of the substance. The property corresponding to this change is called physical property which won't change the configuration of the substance. It is measurable and simply denotes the physical states of a system.

A chemical change is a change in  which a new substance is formed due to the chemical reaction. Here, both the reactants and products have different chemical configuration. The property corresponding to it is called chemical property.

As per our questions, hardness, boiling and ability to conduct electricity are the physical properties of a substance.

The ability to combine with oxygen is not a physical property. It is so because it will result into the formation of a new compound.

Hence, the correct answer to the question is the ability to combine with oxygen.

Answer:

a. in roentgens per hour  

Explanation:

Exposure rate is the ratio of radiation exposure per unit of time. It is often used to measure radiation fields in the environment of a radioactive facility for exposure prevention and control. Exposure rate is generally expressed as per hour roentgens (R / h) used for X-ray or Gamma in air.

The röntgen or roentgen (R) is a unit of exposure to ionizing radiation. The name was given as a tribute to the German physicist Wilhelm Conrad Röntgen (or Roentgen) (1845-1923) who discovered X-rays.

During nuclear fission and fusion matter that seems to disappear but is actually converted into energy.

When the slow moving neutrons are bombarded with the heavy radioactive nuclei, the product is the more number of neutrons are produced with the large amount of energy. This multiplying process is called nuclear fusion.

The amount of energy produced in such a reaction can be calculated using the equivalence of mass and energy relationship.

E = mc²

The same happens in nuclear fusion where large amount of energy is needed  to make more heavy nuclei.

Thus, during nuclear fission and fusion matter that seems to disappear but is actually converted into energy.

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During nuclear fusion and fission, the matter that seems to disappear is converted into energy.

This is explained by Einstein's famous equation which shows that energy and mass are interchangeable:

Here:

This equation explains that:

That is why during nuclear fusion and fission reactions, the matter that seems to disappear is actually converted into energy.

The absolute error and % error in the measurement of equivalent resistance are :

Electrical circuits can generally be divided into two types , i.e :

In series circuit, the electric current flowing on each resistor is always the same as the total current.

To find the total resistances you can use the following formula:

[tex]\large {\boxed {R_s = R_1 + R_2 + R_3 + ...} }[/tex]

In parallel circuits, the electrical voltage at each resistor is always the same as the source voltage.

To find the total resistances you can use the following formula:

[tex]\large {\boxed {\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ...} }[/tex]

Let's tackle the problem now !

Given:

[tex]R_1 = 100 \pm 3 ~ Ohm[/tex]

[tex]R_2 = 200 \pm 4 ~ Ohm[/tex]

Unknown:

Absolute Error = ?

% Error = ?

Solution:

[tex]R_s = R_1 + R_2[/tex]

[tex]R_s = ( 100 \pm 3 ) + ( 200 \pm 4 )[/tex]

[tex]\large {\boxed {R_s = 300 \pm 7 ~ Ohm} }[/tex]

[tex]\frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2}[/tex]

[tex]\frac{1}{R_p} = \frac{R_2}{R_1 ~ R_2} + \frac{R_1}{R_2 ~ R_1}[/tex]

[tex]\frac{1}{R_p} = \frac{R_1 + R_2}{R_1 ~ R_2}[/tex]

[tex]R_p = \frac{R_1 ~ R_2}{R_1 + R_2}[/tex]

[tex]R_p = \frac{100 \times 200}{100 + 200}[/tex]

[tex]R_p = \frac{20000}{300}[/tex]

[tex]R_p = \frac{200}{3} ~ Ohm[/tex]

[tex]R_p \approx 67 ~ Ohm[/tex]

To find the % Error , we will use this following formula :

[tex]\frac{\Delta R_p}{R_p} = \frac{\Delta R_1}{R_1} + \frac{\Delta R_2}{R_2} + \frac{\Delta (R_1 +R_2)}{R_1 + R_2}[/tex]

[tex]\frac{\Delta R_p}{R_p} = \frac{3}{100} + \frac{4}{200} + \frac{7}{300}[/tex]

[tex]\frac{\Delta R_p}{R_p} = \frac{11}{150}[/tex]

[tex]\frac{\Delta R_p}{R_p} = \frac{11}{150} \times 100{\%}[/tex]

[tex]\frac{\Delta R_p}{R_p} \approx 7{\%}[/tex]

[tex]Absolute ~ Error = \Delta R_p[/tex]

[tex]Absolute ~ Error = \frac{11}{150} \times \frac{200}{3}[/tex]

[tex]Absolute ~ Error = \frac{44}{9}[/tex]

[tex]Absolute ~ Error \approx 5 ~ Ohm[/tex]

[tex]\large {\boxed {R_p = 67 \pm 5 ~ Ohm} }[/tex]

Grade: High School

Subject: Physics

Chapter: Current of Electricity

Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm