ANSWER
[tex] \sum_{n=1} ^{32} (4n + 1) = 2144[/tex]
EXPLANATION
The given series is
[tex] \sum_{n=1} ^{32} (4n + 1) [/tex]
The first term in this series is
[tex]a_1=4(1) + 1 = 5[/tex]
The last term is
[tex]l = 4(32) + 1 = 129[/tex]
The sum of the first n terms is
[tex]S_n= \frac{n}{2} (a + l)[/tex]
The sum of the first 32 terms is
[tex]S_ {32} = \frac{32}{2} (5 + 129)[/tex]
[tex]S_ {32} =16 \times 134[/tex]
[tex]S_ {32} =2144[/tex]
Therefore,
[tex] \sum_{n=1} ^{32} (4n + 1) = 2144[/tex]
Traci bought 1 1/4 yards of yellow ribbon, 2 5/6 yards of pink ribbon, and 3 1/2 yards of purple ribbon. How many did she buy altogether
The total ribbon is 7 whole 7/12 yards if the Traci bought 1 1/4 yards of yellow ribbon, 2 5/6 yards of pink ribbon, and 3 1/2 yards of purple ribbon.
What is a fraction?Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.
We have:
Traci bought 1 1/4 yards of yellow ribbon, 2 5/6 yards of pink ribbon, and 3 1/2 yards of purple ribbon.
The total ribbon:
[tex]= \rm 1\dfrac{1}{4} +2\dfrac{5}{6} +3\dfrac{1}{2} \\\\=\rm \dfrac{5}{4}+\dfrac{17}{6}+\dfrac{7}{2}\\\\=\dfrac{15+34+42}{12}\\=\dfrac{91}{12}\\\\=7\dfrac{7}{12} \ yards[/tex]
Thus, the total ribbon is 7 whole 7/12 yards if the Traci bought 1 1/4 yards of yellow ribbon, 2 5/6 yards of pink ribbon, and 3 1/2 yards of purple ribbon
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According to the US Bureau of Labor Statistics, the percentage of jobs in the STEM fields in 2005 that were math-related occupations was 13 percent.
True
False
i think the answer is true
The statement is False, with only 13 percent of jobs in STEM fields being math-related in 2005. This means that out of all the jobs in the areas of Science, Technology, Engineering, and Mathematics, only 13 percent were math-related.
Explanation:The statement is False.
The US Bureau of Labor Statistics reported that in 2005, 13 percent of jobs in the STEM fields were math-related occupations, not the percentage of math-related occupations in the overall job market.
This means that out of all the jobs in the areas of Science, Technology, Engineering, and Mathematics, only 13 percent were math-related.
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The number of defective units in a production run of 850 circuit boards are normally distributed with 21 defective units and 3 defective units. Find the probability P(17 < X < 25) with the help of the graphing calculator. Round your answer to the nearest integer.
77%
81%
80%
82%
Answer:
82%
Step-by-step explanation:
We let the random variable X denote the number of defective units in the production run. Therefore, X is normally distributed with a mean of 21 defective units and a standard deviation of 3 defective units.
We are required to find the probability, P(17 < X < 25), that the number of defective units in the production run is between 17 and 25.
This can be carried out easily in stat-crunch;
In stat crunch, click Stat then Calculators and select Normal
In the pop-up window that appears click Between
Input the value of the mean as 21 and that of the standard deviation as 3
Then input the values 17 and 25
click compute
Stat-Crunch returns a probability of approximately 82%
Find the attachment below.
what is the surface area of the rectangular prism below?
A. 496 unites^2
B. 248 units^2
C. 980 units^2
D. 490 units^2
Answer:
D
Step-by-step explanation:
2·(14·7+7·7+7·14) =490
Answer: D. 490 units^2
Step-by-step explanation:
7x7=49
49x2=98 units^2
14x7=98
98x2=196 units^2
14x7=98
98x2=196 units^2
196+196+98= 490 units^2
A company manufactures televisions in batches of 25 and there is a 1% rate of defects. Find the standard deviation for the number of defects per batch.
Final answer:
To find the standard deviation for the number of defects per batch, use the formula for the standard deviation of a binomial distribution.
Explanation:
To find the standard deviation for the number of defects per batch, we need to use the formula for the standard deviation of a binomial distribution.
Given that the company manufactures televisions in batches of 25 and there is a 1% rate of defects, we can calculate the mean and variance of the number of defects per batch.
The mean (μ) of a binomial distribution is given by μ = np, where n is the number of trials (batch size) and p is the probability of success (defect rate). In this case, μ = 25 * 0.01 = 0.25. The variance (σ^2) of a binomial distribution is given by σ² = np(1-p). In this case, σ² = 25 * 0.01 * (1-0.01) = 0.2475.
The standard deviation (σ) is the square root of the variance, so σ ≈ √0.2475 ≈ 0.4975. Therefore, the standard deviation for the number of defects per batch is approximately 0.4975.
To calculate the standard deviation for the number of defects per batch with a 1% defect rate, use the formula for the standard deviation of a binomial distribution. The standard deviation is approximately 0.4975, indicating the variation in defects per batch.
Explanation:The question you asked is about finding the standard deviation for the number of defects per batch in a manufacturing process where there is a 1% rate of defects.
To calculate the standard deviation for a binomial distribution, which is the case here since each television can be either defective or not, we use the formula: σ = √(np(1-p)), where σ is the standard deviation, n is the number of trials (or televisions), and p is the probability of success (or defect in this context).
Since each batch contains 25 televisions and the defect rate is 1% (0.01), we have:
n = 25
p = 0.01
1-p = 0.99
Plugging these values into the formula we get:
σ = √(25 * 0.01 * 0.99) = √(0.2475) ≈ 0.4975
Therefore, the standard deviation for the number of defects per batch is approximately 0.4975, which means – on average – you would expect the number of defects to vary around this value.
If triangle ABC is defined by the coordinates A(-4, -4), B(2, -2), C(0, 4) is dilated by a scale factor of 1 2 , with resulting vertex A' at (-2, -2). What is the center of the dilation?
Answer:
the origin, (0, 0)
Step-by-step explanation:
The coordinates of A' are 1/2 those of A, meaning each has been multiplied by the scale factor 1/2. When the dilated points are all the original points multiplied by the scale factor, the center of dilation is the origin.
_____
For center of dilation Q, the image of a point A after dilation by a factor of k is ...
A' = kA + (k-1)Q
Then for points A, A', and dilation factor k, the center of dilation can be found to be ...
(A' -kA)/(k-1) = Q
Here, that is ...
Q = ((-2, -2) -(1/2)(-4, -4))/(1/2 -1) = (0, 0)/(-1/2)
Q = (0, 0)
Which is never a chord?
I diameter
II radius
III secant
IV tangent
The distance between the center to the circumcenter is called a radius. The radius can not be a chord.
What is a chord of a circle?It is the distance between the two points in a circle that is known as a chord.
1 Diameter - If the chord length is longest then it is called the diameter. This can be a chord.
2 Radius - The distance between the center to the circumcenter is called a radius. This can not be a chord.
3 Secant - The line passing through the circle is known as a secant. This can be a chord.
4 Tangent - The line which touches the circle then line is called a tangent. This can be a chord.
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Lionel needs money quite frequently and doesn't need much interest at all. Which of these options for saving money is best for him?
A. savings bond
B. money market account
C. certificate of deposit
D. savings account
Answer: Savings account - Apex
Answer:
Option D is the correct answer.
Step-by-step explanation:
The saving bonds are a good way to earn money but they work at fixed rate of interest over a set time period.
Money market accounts give a limited access to account and not more than three checks are written in a month. Its a type of short term savings.
The certificate of deposit or CD's have higher interest rate than savings account. But one cannot withdraw the money before the term maturity otherwise penalty is to be paid.
Savings account are deposit accounts that can be accessed whenever needed. These yield less interest as compared to money market accounts or CD's.
Therefore, the best option for Lionel to choose will be Savings account
Write the equation in standard form for the circle with center (9,
-
4) and radius 9.
Answer:
[tex](x-9)^{2}+(y+4)^{2}=81[/tex]
Step-by-step explanation:
we know that
The equation of a circle in standard form is equal to
[tex](x-h)^{2}+(y-k)^{2}=r^{2}[/tex]
where
(h,k) is the center
r is the radius
In this problem we have
[tex](h,k)=(9,-4)[/tex]
[tex]r=9\ units[/tex]
substitute
[tex](x-9)^{2}+(y+4)^{2}=9^{2}[/tex]
[tex](x-9)^{2}+(y+4)^{2}=81[/tex] ----> equation of the circle in standard form
PLZZZ HELP pictures down below
Answer:
C
Step-by-step explanation:
We can multiply each equation by a constant so they'll equal either 15 or -15 since that is the LCM.
Since the answer choices want us to make the top a negative 15, we'll do that.
[tex]2x-5y=-21 \\ \\ 3(2x-5y)=(-21)*3 \\ \\ 6x-15y=-63[/tex]
To make the y's cancel out, the second equation would have to have the y's coefficient equal 15.
Let's do that.
[tex]3x-3y=-18 \\ \\ -5(3x-3y)=(-18)*-5 \\ \\ -15x+15y=90[/tex]
So the resulting equations are answer choice C.
what is the surface area of the cube below?
A. 486 units^2
B. 508 units^2
C. 729units^2
D. 405 units^2
Answer:
Correct option is:
A. 486 units²
Step-by-step explanation:
We have to find the surface area of cube with side length 9 units
We know that surface area of cube is:
6s²
where s is the side of the cube
Here, s=9 units
Surface area=6×9×9
= 486 units²
Hence, Correct option is:
A. 486 units²
486 units²
Further explanationGiven:
s = 9 units
Let us find out the surface area of a cube.
The formula of the surface area of a cube is [tex]\boxed{ \ S = 6(s^2) \ }[/tex],
where s is the length of one of the sides.
[tex]\boxed{ \ S = 6(9^2) \ }[/tex]
[tex]\boxed{ \ S = 6(81) \ }[/tex]
[tex]\boxed{ \ S = 6 \times 81 \ }[/tex]
Thus, the surface area of the cube is 486 sq. units.
Notes:
From the formula for surface area, we make it s as a subject.
[tex]\boxed{ \ 6(s^2) = S \ }[/tex]
[tex]\boxed{ \ s^2 = \frac{S}{6} \ }[/tex]
[tex]\boxed{\boxed{ \ s = \sqrt{\frac{S}{6}} \ }}[/tex] ... Equation-1
The formula of the volume of a cube is [tex]\boxed{ \ V = s^3 \ }.[/tex]
Substitute Equation-1 into the volume formula.
[tex]\boxed{ \ V = \bigg( \sqrt{\frac{S}{6}} \bigg)^3 \ }.[/tex]
Thus, we have connected formulas of surface area with the volume of the cube.
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Please help with multiple choice question
The function f(x) = 2x + 5 represents Ken’s earnings working x hours as a waiter. On
3 separate days, he works 2, 8, and 14 hours, representing the domain of the function.
What is the range of f(x)?
a. {4, 16, 28}
b. {–1, 11, 23}
c. {14, 26, 38}
d. {9, 21, 33}
Answer:
D: {9, 21, 33}
Step-by-step explanation:
Ken worked 2, 8 and 14 hours on 3 separate days.
For working 2 hours, his earnings were f(2) = 2(2) + 5, or 9;
For working 8 hours, his earnings were f(28) = 2(8) + 5, or 21; and
For working 14 hours, his earnings were f(14) = 2(14) + 5, or 33
Thus, the range of this function for the days given is {9, 21, 33} (Answer D)
Identify the volume of the hemisphere in terms of π. HELP PLEASE!!
Answer:
V = 1152π in³
Step-by-step explanation:
The formula for the volume of a hemishere is
[tex] \frac{ \frac{4}{3}\pi {r}^{3} }{2} [/tex]
Next we need to substitute the values from the question in.
[tex] \frac{ \frac{4}{3}\pi {12}^{3} }{2} [/tex]
Then finally we need to simplify.
[tex] \frac{2304\pi}{2} = 1152\pi[/tex]
The values in the table represent a linear function. What is the common difference of the associated arithmetic sequence?
X Y
1 4
2 21
3 38
4 55
5 72
Choices
A. 17
B. 1
C. 19
D. 3
A bc the Y numbers increase by 17 every time X increases by 1
The common difference of the associated arithmetic sequence is:
Option: A
17
Step-by-step explanation:We know that the sequence is said to be arithmetic if each of the sequence is differ by the preceding term by a fix constant which is known as a common difference.
i.e. d is called a common difference of the sequence if [tex]a_n\ and\ a_{n+1}[/tex]
are the nth and (n+1)th term of the sequence then,
[tex]a_{n+1}-a_n=d[/tex]
Here we have a table of values as:
X Y d
1 4
2 21 21-4=17
3 38 38-21=17
4 55 55-38=17
5 72 72-55=17
Hence, we get that the common difference is: 17
Can someone please check this? Thanks!
Answer:
Your choice is correct.
Step-by-step explanation:
The amplitude (multiplier of sin( )) is half the diameter, so is 17.5. The midline (value added to the sine function) is the difference between the maximum (50) and the amplitude (17.5), so is 50-17.5 = 32.5. All choices have the correct frequency.
The function will look like ...
f(t) = 17.5·sin(2πt/5) +32.5 . . . . . as you have marked
The graph of y= sin (x-3pi/2) is the graph of the y = sin(x) shifted in which direction?
Answer:
[tex]y=\sin(x-\frac{3\pi}{2})[/tex] is the graph of [tex]y=\sin x[/tex] shifted to the right by [tex]\frac{3\pi}{2}[/tex] units.
Step-by-step explanation:
The given function is
[tex]y=\sin(x-\frac{3\pi}{2})[/tex]
The base function of this trigonometric function is [tex]y=\sin x[/tex]
In general, the transformation [tex]y=\sin(x-k)[/tex] will shift the graph of the base function, [tex]y=\sin x[/tex], k units to the right.
Therefore, [tex]y=\sin(x-\frac{3\pi}{2})[/tex] is the graph of [tex]y=\sin x[/tex] shifted to the right by [tex]\frac{3\pi}{2}[/tex] units.
Answer:
B. 3pi/2 units to the right
Step-by-step explanation:
edge2021
Find the domain and range of f(x)=-2x+|3sinx|
Answer:
Domain: (-∞, ∞); range: (-∞, ∞).
Step-by-step explanation:
In the given function, f(x)= -2x + |3sinx|, the range of the |3sinx| term is [0, 3]. That of the -2x term is (-∞, ∞).
The range of f(x)= -2x+|3sinx| is thus (-∞, ∞); the |3sinx| term has no effect on this.
There are no restrictions on the input to f(x)= -2x+|3sinx|. The domain is thus (-∞, ∞).
Correlation Coefficients problem. Image attached.
A. 10
B. 8
C. 6
D 4
Answer:
A
Step-by-step explanation:
xbar is the average of all the x-values in the table. To get the average, we need to add all the x-values and then divide by the number of values there are (there are 5 values).
THus
x bar = [tex]\frac{8+9+10+11+12}{5}=10[/tex]
correct answer is A
Which set of steps could be used to solve this story problem? Helen read 4 books per week for the first 3 weeks of her summer vacation. She read 2 books per week for the last 4 weeks. She also read 2 magazines each week. How many books did Helen read over summer vacation? A. Multiply 4 by 3. Then multiply 2 by 4. Add the two products. B. Add 3 and 4. Then add 2 and 4. Add the two sums. C. Multiply 3 × 4. Then add 4 to that product. Then subtract 2. D. Add 4 and 4. Then divide that sum by 2 and add 3 to the quotient.
Answer:
A. Multiply 4 by 3. Then multiply 2 by 4. Add the two products.
Step-by-step explanation:
As with many rate problems, ...
quantity = rate · time
The total quantity will be the sum of quantities associated with different rates or time periods:
total quantity = quantity1 + quantity2
= (rate 1)(time 1) + (rate 2)(time 2)
= (4 books/week)(3 weeks) + (2 books/week)(4 weeks)
= 4·3 books + 2·4 books . . . . . . units of (weeks/weeks) cancel
= (4·3 + 2·4) books . . . . . . formula matches selection A
PLEASE HELP FAST!
A marble is selected from a bag containing eight marbles numbered 1 to 8.
The number on the marble selected will be recorded as the outcome.
Consider the following events.
Event A: The marble selected has an even number.
Event B: The marble selected has a number from 3 to 6.
Give the outcomes for each of the following events.
If there is more than one element in the set, separate them with commas.
Answer:
A and B: {4, 6}
A or B: {2, 3, 4, 5, 6, 8}
Complement of B: {1, 2, 7, 8}
Step-by-step explanation:
A and B refer to the elements that are in both A and B at the same time
The even numbers from 1 to 8 are {2, 4, 6, 8}
The numbers from 3 to 6 are {3, 4, 5, 6}
Look for the common elements between both sets.
A and B: {4, 6}
A or B is the union of the two sets
Join the elements of both sets
A or B: {2, 3, 4, 5, 6, 8}
The complement of B are all the elements that are not in B.
Write all the elements of the sample space except those of event B
Complement of B: {1, 2, 7, 8}
Event A: 2, 4, 6, 8; Event B: 3, 4, 5, 6.
Explanation:In probability theory, events are outcomes or sets of outcomes from a random experiment. They are subsets of the sample space, representing possible results. Simple events consist of a single outcome, while compound events involve more than one outcome. Probability measures the likelihood of events occurring.
Event A consists of the even numbers 2, 4, 6, and 8.
Event B consists of the numbers 3, 4, 5, and 6.
The outcomes for Event A are 2, 4, 6, and 8.
The outcomes for Event B are 3, 4, 5, and 6.
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please help me out with this one
answer choices :
- 3648
- 2632
- 1387
- 2109
Answer:
[tex]V = 2622\ in ^ 3[/tex]
Step-by-step explanation:
We have a composite figure, therefore the volume of the figure will be the sum of the volume of both figures.
The volume of the rectangular prism is the product of its length by its width by its height
[tex]V_r = 7 * 12 * 19\\\\V_r = 1596\ in^3[/tex]
The volume of the triangular prism is
[tex]V_t = A_b * l[/tex]
Where [tex]A_b[/tex] is the area of the triangular base and l is the length
[tex]A_b = 0.5 * 9 * 12 = 54\ in^2[/tex]
[tex]V_t = 0.54 * 19 = 1026\ in^3[/tex]
Finally
[tex]V = 1596 + 1026[/tex]
[tex]V = 2622\ in ^ 3[/tex]
The answer is:
The total volume is equal to: [tex]2622in^{3}[/tex]
Why?To calculate the total volume of the composite figure, we need to calculate the volume of both of the figures that creates the composite figure.
So, calculating we have:
First figure:
The first figure has a triangular base (side for this case) and height, to find its volume, we just need to calculate the area of its base and then, multiply it by its height.
We are given that:
[tex]base_{height}=9in\\base_{base}=12in\\length=19in[/tex]
Calculating the area of the side/base, we have:
[tex]A=\frac{b*h}{2}[/tex]
[tex]A=\frac{12in*9in}{2}=54in^{2}[/tex]
Now, calculating the volume, we have:
[tex]Volume_{1}=Area*Length\\\\Volume_{1}=54in^{2}*19in=1026in^{3}[/tex]
Second figure:
The second figure is a rectangle, we can calculate its volume using the following formula:
[tex]Volume_2=base*height*width\\\\Volume_2=12in*7in*19in=1596in^{3}[/tex]
Hence, we can calculate the total volume by adding the first volumen and the second volume:
[tex]TotalVolume=Volume_1+Volume_2\\\\TotalVolume=1026in^{3} +1596in^{3}=2622in^{3}[/tex]
The total volume is equal to [tex]2622in^{3}[/tex]
Have a nice day!
Jake cut a round gelatin dessert into 8 equal parts. five of the pieces were eaten . what is the angle measure of the dessert that was left
Answer:
3/8
Step-by-step explanation:
8-5=3
The value of the angle measure of the dessert that was left is equal to
3/8.
We have given that,
Jake cut a round gelatin dessert into 8 equal parts. five of the pieces were eaten.
We have to determine the angle measure of the dessert that was left
What is the angle measure?An angle measure can be defined as the measure of the angle formed by the two rays or arms at a common vertex. Angles are measured in degrees ( °), using a protractor.
Therefore
Jake cut a round gelatin dessert into 8 equal parts is given by,
[tex]\frac{360}{8}=45^0[/tex]
8-5=3
Therefore the angle measure of the dessert that was left is,
[tex]3(45^0)=135^0[/tex]
Therefore the value of the angle measure of the dessert that was left is equal to 3/8.
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Joe spends 18.75% of his working day washing cars. He spends 1.5 hours washing cars. How many total hours does he work per day?
Answer:
8 hours
Step-by-step explanation:
Joe spends 18.75% of his working day washing cars.
Joe spends 1.5 hours washing car.
Therefore 18.75% is equal to 1.5 hour.
18.75% = 1.5 hour
1% = 1.5 ÷ 18.75 = 0.08 hour
100% = 0.08 x 100 = 8 hours
Consider the function represented by the equation 6q = 3s - 9. Write the equation in function notation, where q is the independent variable
A. f(q) = 1/2q - 3/2
B. f(q) = 2s + 3
C. f(s) = 1/2s - 3/2
D. f(q) = 2q + 3
Answer:
D. f(q) = 2q + 3
Step-by-step explanation:
Choices B and C are eliminated right away because there is no "q" in the definition, just "s". If the function is to be a function of "q", then "q" is expected to appear in the definition.
__
The two variables in the given equation are "s" and "q". If "q" is designated as the independent variable, then the dependent variable is "s". The equation must be solved for "s":
6q = 3s - 9
We observe that the coefficient of "s" is 3, and that all numbers are multiples of 3, so we can divide by 3 to simplify this a bit:
2q = s - 3
Since we want an expression for s alone, we can add 3 to get ...
2q +3 = s
Now, we can write ...
s = f(q) = 2q +3
Answer:D
Step-by-step explanation:
Ebit goes from $30m to $33m; depreciation goes from $10m to $12m; and interest expense goes from $6 m to $8m. what is the percent change in the numerator of the cash coverage ratio? what is the percent change in the denominator of the cash coverage ratio?
i am pretty sure you add up all of them
The percent change in the numerator for the cash coverage ratio, considering the changes in EBIT and depreciation, is 12.5%. Meanwhile, the percent change in the denominator, based on the interest expense, is 33.33%.
Explanation:The cash coverage ratio is a measure of a company's ability to pay off its obligations and is calculated by adding depreciation and EBIT and then dividing by the interest expense. For this question, we are looking at the percent change in the numerator, which is EBIT + depreciation, and the denominator, which is the interest expense. With EBIT going from $30m to $33m, depreciation going from $10m to $12m, and interest expense going from $6m to $8m we can calculate as follows.
The original numerator value was $40m (EBIT of $30m + depreciation of $10m) and the new numerator is $45m (EBIT of $33m + depreciation of $12m). So, the percent change in the numerator of the cash coverage ratio is ((45-40)/40)*100 = 12.5%. The original denominator was $6m and the new denominator is $8m. Thus, the percent change in the denominator of the cash coverage ratio is ((8-6)/6)*100 = 33.33%.
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Which choice is equivalent to the expression below when y is greater or less than 0?
ANSWER
A. y√y
EXPLANATION
The given expression is:
[tex] \sqrt{ {y}^{3} } + \sqrt{16 {y}^{3} } - 4y \sqrt{y} [/tex]
We factor the perfect square in the first two terms to obtain;
[tex] \sqrt{ {y}^{2} \times y} + \sqrt{ {(4y)}^{2} \times y } - 4y \sqrt{y} [/tex]
This simplifies to:
[tex]y\sqrt{y } + 4y \sqrt{y } - 4y \sqrt{y} [/tex]
We simplify to get;
[tex]y\sqrt{y } + 0 = y \sqrt{y} [/tex]
The correct choice is A.
Please help me out please
Answer:
10.92 m
Step-by-step explanation:
To solve for the height, we first find the area of the triangle. Since the area of a triangle is 1/2 of the base times the height, we get the area to be 109.2. Dividing it by 20 and then multiplying by 2, we get 10.92 as the height.
if rectangle ABCD is dilated by a scale factor of 3 with a center of dilation at vertex D, what is the perimeter of A'B'C'D'?
Final answer:
To find the perimeter of the dilated rectangle A'B'C'D', we need to know the dimensions of the original rectangle ABCD and the scale factor of the dilation. The perimeter of A'B'C'D' is equal to the sum of the lengths of all the sides in the dilated rectangle. Since AB = A'B' and BD = B'D', the perimeter can be simplified to AB + BC + CD + BD.
Explanation:
To find the perimeter of the dilated rectangle A'B'C'D', we need to know the dimensions of the original rectangle ABCD and the scale factor of the dilation.
If the scale factor is 3, it means that each side of the original rectangle will be multiplied by 3 to get the corresponding side of the dilated rectangle.
Since the rectangle ABCD is dilated with a center of dilation at vertex D, the length of side AB remains the same in the dilated rectangle A'B'.
To find the perimeter of A'B'C'D', we need to compute the lengths of all the sides in the dilated rectangle and sum them up.
Perimeter of A'B'C'D' = A'B' + B'C' + C'D' + D'A'
Since AB = A'B' and BD = B'D', the perimeter can be simplified to:
Perimeter of A'B'C'D' = AB + BC + CD + BD
The perimeter of rectangle A'B'C'D', which is a dilation of rectangle ABCD by a scale factor of 3 with center D, is three times larger than the original perimeter of ABCD.
Explanation:If rectangle ABCD is dilated by a scale factor of 3 with a center of dilation at vertex D, to find the perimeter of A'B'C'D', we must first understand that a dilation scales all dimensions by the given factor. If the original lengths of the sides of rectangle ABCD are 'a' and 'b', with CD and AD being adjacent to vertex D, then after the dilation, the lengths of the corresponding sides would be '3a' and '3b'.
Since the perimeter of a rectangle is calculated by adding together the lengths of all its sides, the formula for the perimeter 'P' before dilation is P = 2a + 2b. After dilation, the new perimeter 'P' of A'B'C'D' will be P = 2(3a) + 2(3b) = 6a + 6b, which is simply three times the original perimeter. Therefore, the perimeter of rectangle A'B'C'D' after dilation is three times larger than the perimeter of the original rectangle ABCD.
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The results of a poll show that the percent of people who want a new restaurant is in the interval (24%, 38%) . There are 112,483 people in the city.
What is the interval for the number of people who are likely to want this restaurant in their city?
Round to the nearest person.
Answer: (26996, 42744)
Step-by-step explanation:
24% of 112,483 = 26,995.92 --> rounded to the nearest person is 26,996
38% of 112,483 = 42,743.54 --> rounded to the nearest person is 42,744
The number of people who want a new restaurant is somewhere between 26,996 and 42,744.
Answer:
26,996-42,744
Step-by-step explanation:
To calculate the spam of the people that who are likely to want this restaurant you just have to multiply the total number people in the city by the two points in the extremes of the intervals.
24% * 112,483=26996
and the other one would be:
38%* 112,483= 42744
And those are the extremes of the interval of people in the city who are likely to want this new restaurant.
¯¯¯¯¯¯ J K is a tangent to circle C . If m ∠ K J L = 27 °, What is m ˆ K L ?
To find the angle ∠KL, knowing m∠KJL = 27°, it is essential to apply the properties of tangents and circles.
The angle ∠KJL can be determined using the properties of tangents and circles. Since JK is a tangent to circle C, we know that angle ∠KJL is equal to half of the intercepted arc KL. Therefore, if m∠KJL = 27°, then m∠KL = 2 × 27° = 54°.