What is the molar mass of 37.96 g of gas exerting a pressure of 3.29 on the walls of a 4.60 L container at 375 K?

Answer:

B. It is important that people are not harmed for the sake of science.

Explanation:

Ethical principles stress the need to do good and cause no harm.A researcher is therefore required to;

Answer:

It is important that people are not harmed for the sake of science.

Explanation:

Answer:

1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate

Explanation:

Step 1: Data given

Mass of sodium bicarbonate = 2.7 grams

Step 2: The balanced equation

HCl + NaHCO3 ⇔  NaCl + H2O + CO2

Step 3: Calculate moles NaHCO3

moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles

Step 4: Calculate moles HCl

For 1 mol NaHCO3 we need 1 mol HCl

For 0.032 moles NaHCO3 = 0.032 moles HCl

Step 5: Calculate mass HCl

Mass HCl = moles HCl * molar mass HCl

mass HCl = 0.032 * 36.46 g/mol= 1.17 grams

1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate

The key process being used here is stoichiometry, which is a core aspect of chemistry that studies the quantitative relationships, or ratios, among reactants in a chemical equation. By writing and analyzing a balanced chemical equation, performing correct conversions, and understanding mole-to-mole ratios, we determine that 2.7 grams of sodium bicarbonate can neutralize approximately 1.17 grams of hydrochloric acid.

The subject of this specific problem is stoichiometry, a central concept in chemistry. The first step involves writing a balanced chemical equation between sodium bicarbonate (NaHCO₃) and hydrochloric acid (HCl). The equation will look like this: NaHCO₃ (aq) + HCl (aq) → NaCl (aq) + CO₂ (g) + H₂O (l). This reaction demonstrates that one mole of sodium bicarbonate reacts with one mole of hydrochloric acid.

Next, we'll need to calculate the number of moles of sodium bicarbonate, using the molar mass of sodium bicarbonate, which is approximately 84 g/mol. So, 2.7 g of sodium bicarbonate equals 2.7 g / 84 g/mol = 0.0321 mol.

Since the equation shows a 1:1 ratio, this means that 0.0321 mol of sodium bicarbonate will neutralize the same amount of moles of hydrochloric acid. The molar mass of HCl is about 36.5 g/mol, so multiplying this with the moles of HCl gives the mass: 0.0321 mol * 36.5 g/mol = 1.17 g.

So, 2.7 g of sodium bicarbonate can neutralize 1.17 g of hydrochloric acid.

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Answer:

The atomic number of an element is: the number of protons in the nucleus of one atom.

Explanation:

The atomic number is a concept related to the structure of the atoms of each element and it is the total number of protons or elementary positive charges, of the nucleus of a certain atom.

Answer:

Option 3==> the number of protons in the nucleus of one atom.

Explanation:

In an atom, atomic number is the number of proton in the nucleus. In order to determine the number of an element in the periodic table we can make use of the number of proton in the atom that is the atomic number.

If the atoms are neutral, then the number of proton is equal to the number of electron. For instance, the neutral atom of carbon, the number of proton in it is 6 and on the periodic table or chart the 6th element is the carbon.

Answer:

C) 9

Math

Algebra I

Chemistry

Acid-Base Equilibrium

Step 1: Define

[OH⁻] = 1 × 10⁻⁹ M

Step 2: Find pOH

Simply take negative log₁₀ of the concentration.

Answer:

                                   Δ            

            CaCO3(s)     →  →      CaO (s)   +  CO2 (g)

Explanation: Calcium Carbonate also known as Limestone will undergo decomposition reaction in the presence of heat to produce Quick-lime and Carbon dioxide.

Answer:

The balanced chemical equation is:

[tex]CaCO_{3}[/tex]  →  [tex]CaO + CO_{3}[/tex]

Explanation:

The problem said:

Solid calcium carbonate decomposes into solid calcium oxide and carbon dioxide gas.

Corresponde to chemicale equation:

                                               [tex]CaCO_{3}[/tex]   →  [tex]CaO + CO_{3}[/tex]

A chemical reaction must be based on the law of the conservation of matter, which implies that matter is not created or destroyed but transformed. Therefore, the same amount of each atom must be involved in the reagents and products.

this reaction have:

Reagents.

Products.

∴ This equation is balanced.

Answer:

in nuclear fusion deep in the interiors of stars

Explanation:

Nuclear fusion -

It is the type of reaction , where two or more atomic nuclei of the atom merges together to release two or more different nuclei along with some subatomic particles , is referred to as a nuclear fusion reaction .

The reaction can very well be done on stars , because of very high energy .

Hence , a nuclear fusion occurs deep inside the stars .

Answer: The symbol of diphosphate ion is [tex]P_2O_7^{4-}[/tex]

Explanation:

An ionic compound is defined as the compound which is formed when electron gets transferred from one atom to another atom.

These are usually formed when a metal reacts with a non-metal or a metal reacts with a polyatomic ion or a reaction between two polyatomic ions takes place.

Calcium diphosphate [tex](Ca_2P_2O_7)[/tex] is formed by the combination of calcium ions [tex](Ca^{2+})[/tex] and diphosphate ions [tex](P_2O_7^{4-})[/tex]

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral ionic compound.

Hence, the symbol of diphosphate ion is [tex]P_2O_7^{4-}[/tex]

Final answer:

The correct symbol for the diphosphate ion in calcium diphosphate Ca₂P₂O₇ is P₂O₇₄₋ to balance the positive charge of the two calcium ions, but the response options in the question may contain a typo. D) is correct.

Explanation:

To determine the correct symbol for the diphosphate ion, we need to consider the charge balance in the compound calcium diphosphate with the formula  Ca₂P₂O₇. Calcium has a 2+ charge (Ca₂+), and since the compound must be electrically neutral, we need to balance this charge with an appropriate anion. In this case, each calcium ion has a 2+ charge, and there are two calcium ions, resulting in a total positive charge of 4+. Therefore, the diphosphate anion must have a 4- charge in total to neutralize the charges. The correct option for the diphosphate ion is  P₂O₇₄₋, so the answer is D) P₂O₇₂₋, which accounts for two negative charges per diphosphate ion (note: this seems to be a typo in the options—the correct option should be  P₂O₇₄₋, not P₂O₇₂₋).

Explanation:

Answer : The final concentration of [tex]N_2O_5[/tex] is, 2.9 M

Explanation :

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant  = [tex]5.89\times 10^{-3}\text{ min}^{-1}[/tex]

t = time passed by the sample  = 3.5 min

a = initial concentration of the reactant  = 3.0 M

a - x = concentration left after decay process = ?

Now put all the given values in above equation, we get

[tex]3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}[/tex]

[tex]a-x=2.9M[/tex]

Thus, the final concentration of [tex]N_2O_5[/tex] is, 2.9 M

To determine the final concentration of N2O5 after 3.5 minutes using the provided rate constant and first-order kinetics, the integrated rate law is used, where the time is converted to seconds and calculations are made using the initial concentration, resulting in a final concentration of 0.17 M.

The student is asking about the final concentration of N2O5 after a first-order decomposition reaction where the initial concentration and rate constant are provided. To find the final concentration of N2O5 after a period of 3.5 minutes, we use the first-order integrated rate law:

ln[A] = -k * t + ln[A0]

Where:

Since the time given is in minutes, we first convert it to seconds: t = 3.5 min × 60 s/min = 210 s. Now we can use the integrated rate law to find the final concentration:

ln[3.0] = -5.89 × 10⁻³ × 210 + ln[3.0]

Solving for [A], we find that the final concentration of N2O5 is 0.17 M (using appropriate exponential and logarithmic operations).

This is an incomplete question, here is a complete question.

Consider the following reaction:

[tex]A+B+C\rightarrow D[/tex]

The rate law for this reaction is as follows:

[tex]Rate=k\times \frac{[A][C]^2}{[B]^{1/2}}[/tex]

Suppose the rate of the reaction at certain initial concentrations of A, B, and C is 1.12 × 10⁻² M/s.

What is the rate of the reaction if the concentrations of A and C are doubled and the concentration of B is tripled?

Rate 2 = ? M/s

Answer : The rate of reaction will be, [tex]5.17\times 10^{-2}M/s[/tex]

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given chemical reaction is,

[tex]A+B+C\rightarrow D[/tex]

The expression of rate law for this reaction will be,

[tex]\text{ Initial rate}=k\times \frac{[A][C]^2}{[B]^{1/2}}[/tex]

As the concentrations of A and C are doubled and the concentration of B is tripled then the rate of reaction will be:

[tex]Rate=k\times \frac{[2A][2C]^2}{[3B]^1/2}[/tex]

[tex]Rate=4.62k\times \frac{[A][C]^2}{[B]^{1/2}}[/tex]

[tex]Rate=4.62\times \text{ Initial rate}[/tex]

Given:

Initial rate = 1.12 × 10⁻² M/s

[tex]Rate=4.62\times 1.12\times 10^{-2}M/s[/tex]

[tex]Rate=5.17\times 10^{-2}M/s[/tex]

Thus, the rate of reaction will be, [tex]5.17\times 10^{-2}M/s[/tex]

Answer:

The molal boiling point elevation constant (Kb) is calculated by dividing the change in boiling point (∆Tb) by the molality of the solution (m)

Explanation:

Kb = ∆Tb/m

Kb is the molal boiling point elevation constant of the liquid

∆Tb is the change in boiling point. It is calculated by subtracting the initial boiling point of the liquid from the final boiling point of the solution.

m is the molality of the solution. It is calculated by dividing the number of moles of urea (number of moles of urea is calculated by dividing the mass in grams of urea by its molecular weight) by the mass of the liquid in kilograms.

Answer:

0.735M

Explanation:

The balanced equation of reaction is:

HCl + KOH ===> KCl + H2O

Using titration equation of formula

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 1 (from the balanced equation of reaction)

NB is the number of mole of base = 1 (from the balanced equation of reaction)

CA is the concentration of acid = 2.5M

CB is the concentration of base = to be calculated

VA is the volume of acid = 14.7mL

VB is the volume of base = 50mL

Substituting

2.5×14.7/CB×50 = 1/1

Therefore CB =2.5×50×1/14.7×1

CB= 0.735M

Answer: Thermal

Explanation: All areas on the earth surface does not absorb equal amount of sunlight, as a result of this, some areas tend to heat up more quickly than the others. The air in contact with these heated areas becomes  warmer than its surroundings causing a hot bubble of air called ''thermal'' to break away from the  warm surface,rising, expanding and cooling as it ascends, as observed during cloud development.

Final answer:

A rising hot "bubble" of air that expands and cools as it ascends due to convection is known as a thermal. This results in adiabatic cooling, which can lead to condensation and cloud formation.

Explanation:

A hot "bubble" of air that breaks away from the warm surface and rises, expanding and cooling as it ascends, is known as a thermal. This is due to the process of convection where warmer air, being less dense, rises above colder air. As this air rises, it expands due to lower atmospheric pressure at higher altitudes, which in turn causes it to cool, a process known as adiabatic cooling. If the air cools to its dew point, condensation can occur, potentially leading to cloud formation.

Answer:

Option (E) is correct

Explanation:

Solubility equilibrium of [tex]Pb(IO_{3})_{2}[/tex] is given as follows-

                   [tex]Pb(IO_{3})_{2}\rightleftharpoons Pb^{2+}+2IO_{3}^{-}[/tex]

Hence, if solubility of [tex]Pb(IO_{3})_{2}[/tex] is S (M) then-

                             [tex][Pb^{2+}]=S(M)[/tex] and [tex][IO_{3}^{-}]=2S(M)[/tex]

Where species under third bracket represent equilibrium concentrations

So, solubility product of [tex]Pb(IO_{3})_{2}[/tex] , [tex]K_{sp}=[Pb^{2+}][IO_{3}^{-}]^{2}[/tex]

Here, [tex][Pb^{2+}]=S(M)=5.0\times 10^{-5}M[/tex]

So, [tex][IO_{3}^{-}]=2S(M)=(2\times 5.0\times 10^{-5})M=1.0\times 10^{-4}M[/tex]

So, [tex]K_{sp}=(5.0\times 10^{-5})\times (1.0\times 10^{-4})^{2}=5.0\times 10^{-13}[/tex]

Hence option (E) is correct

Answer:

E) 5 x 10-13 Molar

Explanation:

plato

Answer:

The formula of aspirin = [tex]C_9H_8O_4[/tex]

Explanation:

Mass of water obtained = 0.400

Molar mass of water = 18 g/mol

Moles of [tex]H_2O[/tex] = 0.400 g /18 g/mol = 0.0222 moles

2 moles of hydrogen atoms are present in 1 mole of water. So,

Moles of H = 2 x 0.0222 = 0.0444 moles

Molar mass of H atom = 1.008 g/mol

Mass of H in molecule = 0.0444 x 1.008 = 0.0448 g  

Mass of carbon dioxide obtained = 2.20 g

Molar mass of carbon dioxide = 44.01 g/mol

Moles of [tex]CO_2[/tex] = 2.20 g  /44.01 g/mol = 0.05 moles

1 mole of carbon atoms are present in 1 mole of carbon dioxide. So,

Moles of C = 0.05 moles

Molar mass of C atom = 12.0107 g/mol

Mass of C in molecule = 0.05 x 12.0107 = 0.6005 g

Given that the aspirin acid only contains hydrogen, oxygen and carbon. So,

Mass of O in the sample = Total mass - Mass of C  - Mass of H

Mass of the sample = 1.00 g

Mass of O in sample = 1.00 - 0.6005 - 0.0448 = 0.3547 g  

Molar mass of O = 15.999 g/mol

Moles of O  = 0.3547  / 15.999  = 0.0222 moles

Taking the simplest ratio for H, O and C as:

0.0444 : 0.0222 : 0.05

= 8 : 4 : 9

The empirical formula is = [tex]C_9H_8O_4[/tex]

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 9×12 + 8×1 + 16×4= 180 g/mol

The molar mass of aspirin is between 170 and 190 g/mol

So,  

Molecular mass = n × Empirical mass

170 <  n × 180 < 190

⇒ n = 1

The formula of aspirin = [tex]C_9H_8O_4[/tex]

The molecular formula for aspirin can be determined through the quantities of CO2 and H2O produced by burning it. This involves calculating the quantities of each element present and obtaining an empirical formula that must be scaled to match the molar mass of aspirin. Through this process, aspirin's molecular formula is found to be C9H8O4.

The empirical formula of aspirin can be determined by understanding the quantity of each element present in the provided quantities of Carbon Dioxide (CO2) and water (H2O) produced by burning the aspirin. From the 2.20 g of CO2, the amount of carbon is calculated to be: mass CO2 x (atomic mass of C/molar mass of CO2). Similarly, from the 0.400 g of water, the quantity of hydrogen is calculated to be: mass H2O x (2 x atomic mass of H/molar mass of H2O). The balance of the original aspirin's 1.00 g mass constitutes oxygen.

Using atomic masses (C = 12.01 g/mol, H = 1.008 g/mol, O = 16.00 g/mol), you generate the empirical formula with the simplest ratio of these elements. However, this formula will not match the molecular mass of 180.15 amu for aspirin. Therefore, a multiple is required to transform the empirical formula into the molecular formula. The required multiple is calculated as (molar mass of aspirin / molar mass of empirical formula).

Applying these calculations and steps reveals that the molecular formula for aspirin is indeed C9H8O4.

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Answer:

The correct answer is 21.3 J

Explanation:

The heat absorbed by water can be calculated by using the following equation:

heat= m x Sh x ΔT

Where m is the mass of water (2.46 kg= 2460 g), Sh is the specific heat capacity of water (4.18 J/g.ºC) and ΔT is the difference of temperatures (final T - initial T). We introduce this values and calculate the heat:

heat=2460 g x 4.18 J/g.ºC x (27.31ºC - 25.24ºC)

heat= 21,285.39 J

As 1 KJ= 1000 J, we must divide the answer into 1000 to obtain the heat in KJ:

21,285.39 J x 1 KJ/1000 J= 21.28 KJ≅ 21.3 KJ

Final answer:

To calculate the heat absorbed by the water, first convert the mass to grams, then find the temperature change, apply the specific heat formula, and finally convert the energy to kilojoules. The water absorbed 21.27 kJ of heat.

Explanation:

The student's question revolves around calculating the amount of heat absorbed by water when its temperature is increased. To find the quantity of heat absorbed, we use the formula q = m x c x \\u0394T, where q is the heat absorbed in joules, m is the mass of water in kilograms (which needs to be converted to grams for the specific heat value given), c is the specific heat capacity (4.18 J/g\\u00b0C for water), and \\u0394T is the change in temperature in degrees Celsius.

To solve the problem:

Convert the mass of water to grams: 2.46 kg x 1000 g/kg = 2460 g

Calculate the change in temperature: 27.31 \\u00b0C - 25.24 \\u00b0C = 2.07 \\u00b0C

Apply the formula: q = 2460 g x 4.18 J/g\\u00b0C x 2.07 \\u00b0C = 21270.44 J

Convert joules to kilojoules: 21270.44 J / 1000 = 21.27 kJ

Therefore, the water absorbed 21.27 kJ of heat.

Answer:

1. 276 g of NO₂

2. 34.8 moles of LiO

3. 4.23×10²⁵ molecules of SO₂

4. 540 g of H₂O

5. 224 g CO

Explanation:

Let's define the molar mass of the compound to define the moles or the grans of each.

Molar mass . moles = Mass

Mass (g) / Molar mass = Moles

1. 6 mol . 46 g / 1 mol = 276 g of NO₂

2. 800 g . 1mol / 22.94 g = 34.8 moles of LiO

3. To determine the number of molecules, we convert the mass to moles and then, we use the NA (1 mol contains 6.02×10²³ molecules)

4500 g . 1mol / 64.06 g = 70.2 moles of SO₂

70.2 mol . 6.02×10²³ molecules / 1 mol = 4.23×10²⁵ molecules of SO₂

4. 30 mol . 18g / 1 mol = 540 g of H₂O

5. 8 mol . 28g /  1mol = 224 g CO

Super saturated solution is formed.

Explanation:

Solubility is the property of any substance's capacity, that is the solute of the substance is dissolved in the given solvent to form the solution. We have three different types of solution, unsaturated, saturated and supersaturated solution.

The solubility of KI at 30°C is 153 g / 100 ml. Here 180 g of KI in 100 ml of water at 30°C is given, which has more solute than required, so it is super saturated solution.

Answer:

A) Saturated

Explanation:

Got it right on USA Test Prep

Explanation:

D(aq) + E(aq) <=> F(aq)

This question is based on Le Chatelier's principle.

Le Chatelier's principle is an observation about chemical equilibria of reactions. It states that changes in the temperature, pressure, volume, or concentration of a system will result in predictable and opposing changes in the system in order to achieve a new equilibrium state.

Increase D

D is a reactant. if we add reactants to the system, equilibrium will be shifted to the right to in order to maintain equilibrium by producing more products.

Increase E

E is a reactant. if we add reactants to the system, equilibrium will be shifted to the right to in order to maintain equilibrium by producing more products.

Increase F

F is a product.  If we add additional product to a system, the equilibrium will shift to the left, in order to produce more reactants. The reaction would shift to the left.

Decrease D

if we remove reactants from the system, equilibrium will  be shifted to the left.

Decrease E

if we remove reactants from the system, equilibrium will  be shifted to the left.

Decrease F

if we remove products from the system, equilibrium will be shifted to the right to in order to maintain equilibrium by producing more products.

Triple D and reduce E to one third

no shift in the direction of the net reaction, Both changes cancels each other.

Triple both E and F

no shift in the direction of the net reaction, Both changes cancels each other.

Answer:

decreases going down within a group

Explanation:

Ionization energy of an atom is defined as the energy required to remove electron from the gaseous form the atom. The energy required to remove the highest placed electron in the gaseous form of an atom is referred to as the first ionization energy.

In the periodic table, the first ionization energy decreases down the group because as the principal quantum number increases, the size of the orbital increases and the electron is easier to remove.

In addition, the first ionization energy increases across the period because electrons in the same principal quantum shell do not completely shield the increasing nuclear charge of the protons.

The ionization energy of atoms decreases going down a group on the periodic table and increases going across a period. This is because the atomic radius and the attraction between the nucleus and the outer electrons change.

The ionization energy of atoms is the energy required to remove an electron from an atom or ion. As you move down a group on the periodic table, the ionization energy generally decreases. This is because as you go down a group, the atomic radius increases and the outer electrons are further away from the nucleus, making them easier to remove.

On the other hand, as you go across a period from left to right, the ionization energy generally increases. The electrons are closer to the nucleus and thus more strongly attracted to the center, making them more difficult to remove. So, the correct choices would be 'decreases going down within a group' and 'increases going across a period'.

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Answer:

The answer to your question is  T = 204.9°K

Explanation:

Data

Temperature = T = ?

number of moles = n = 4

Volume = V = 12 L

Pressure = P = 5.60 atm

constant of gases = 0.082 atm L /mol °K

Process

To solve this problem, use the Ideal Gas Law and solve it for T

Formula

            PV = nRT

            T = PV / nR

-Substitution

             T = (5.60)(12)/(4)((0.082)

-Simplification

              T = 67.2 / 0.328

-Result

               T = 204.9°K

Considering the ideal gas law, at 204.878 K will 4.00 moles of gas occupy a volume of 12.0 L at a pressure of 5.60 atm.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances. The numerical value of R will depend on the units in which the other properties are worked.

In this case, you know:

Replacing in the ideal gas law:

5.60 atm×12  L = 4 moles×0.082[tex]\frac{atmL}{molK}[/tex]×T

Solving:

[tex]T=\frac{5.60 atmx12 L}{4 moles x 0.082 \frac{atmL}{molK}}[/tex]

T=204.878 K

Finally, at 204.878 K will 4.00 moles of gas occupy a volume of 12.0 L at a pressure of 5.60 atm.

Learn more about the ideal gas law:

Answer : The empirical of the compound is, [tex]C_1H_2O_3[/tex]

Solution : Given,

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 19.36 g

Mass of H = 3.25 g

Mass of O = 77.39 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of C = [tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{19.36g}{12g/mole}=1.613moles[/tex]

Moles of H = [tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{3.25g}{1g/mole}=3.25moles[/tex]

Moles of O = [tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{77.39g}{16g/mole}=4.837moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = [tex]\frac{1.613}{1.613}=1[/tex]

For H = [tex]\frac{3.25}{1.613}=2.01\approx 2[/tex]

For o = [tex]\frac{4.837}{1.613}=2.99\approx 3[/tex]

The ratio of C : H : O = 1 : 2 : 3

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = [tex]C_1H_2O_3[/tex]

Therefore, the empirical of the compound is, [tex]C_1H_2O_3[/tex]

The empirical formula of a compound with 3.25% H, 19.36% C, and 77.39% O by mass is CH2O3, found by converting the mass of each element to moles and then determining the simplest whole number ratio.

To determine the empirical formula of a compound composed of 3.25% hydrogen (H), 19.36% carbon (C), and 77.39% oxygen (O) by mass, we first assume a 100 g sample of the compound. This means we would have 3.25 g of H, 19.36 g of C, and 77.39 g of O.

Next, we convert the mass of each element to moles by dividing by their respective molar masses:

To find the simplest whole number ratio, we divide each mole value by the smallest number of moles calculated:

The ratios indicate the empirical formula is CH2O3.

Answer:

Catalysis

Explanation:

Pepsin is able to break peptide bonds, turning large protein molecules into small peptide chains.

When pepsin acts to break down pepsinogen (inactive form of pepsin), it is accelerating pepsinogen → pepsin reactions, acting as a catalyst, reducing activation energy and favoring proteolytic reactions at a higher rate.

This process of accelerating reactions is characteristic of enzymes and is known as catalysis.

Answer: The total pressure inside the container is 77.9 kPa

Explanation:

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the total pressure inside the container, we use the law given by Dalton, which is:

[tex]P_T=p_{N_2}+p_{O_2}+p_{Ar}[/tex]

We are given:

Vapor pressure of oxygen gas, [tex]p_{O_2}[/tex] = 40.9 kPa

Vapor pressure of nitrogen gas, [tex]p_{N_2}[/tex] = 23.3 kPa

Vapor pressure of argon, [tex]p_{Ar}[/tex] = 13.7 kPa

Putting values in above equation, we get:

[tex]p_T=23.3+40.9+13.7\\\\p_{T}=77.9kPa[/tex]

Hence, the total pressure inside the container is 77.9 kPa

Answer:

A

Explanation:

During a chemical reaction two or more chemical substances interact with one another, causing the atoms to move around and rearrange their arraignment and bond together in a different way to make a new product or products.

Answer:

A

Explanation:

One of the principal laws guiding chemical reactions is the law of conservation of mass. It states that matter can not be created nor destroyed but can be converted from one form to another. Although this has been shown to be wrong to an extent, it is still the basic law guiding the way in which chemical reactions operate.

Now, to form new substances, we have some old substances coming together. These old substances are the ones that come together to form the new ones. Surely, these old substances have their own atoms too. Since they are not destroyed in the process of forming new substances, what will happen is that they are rearranged or converted from their original form to another new form to make way for the emergence of new substance type.

Answer:

5 g/dm³ is the correct answer

Explanation:

Concentration in units of g/dm³ means the grams of solute, in 1 dm³ of solution.

We can make a rule of three:

In 2 dm³ of solution we have 10 g of NaCl

Therefore, 1 dm³ of solution we would have (1dm³ . 10g) / 2dm³ = 5g

If we were asked for concentration of g/dm³ we can also make this division:

10 g / 2dm³ = 5g/dm³

The 10.0 g of NaCl in 2.00 dm³ of water results in a concentration of 5.0 g/dm³.

To find the concentration of the solution in units of g/dm³, use the formula:

Given:

Now, plug in the values:

Therefore, the concentration of the sodium chloride solution is 5.0 g/dm³.

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Answer:

Water is polar covalent while isoporopanol is covalent

Explanation:

Water contains polar covalent bonds. Water has a high dipole moment and thus dissolves ionic substances easily such as sodium chloride. Water is also a good electrolyte. Water is not volatile. Water molecules are held together by hydrogen bonds. Isopropanol is a covalent compound. It is non polar and suitable for dissolving non polar substances such as campohor. It is volatile but dissolves in water due the the -OH group present in the molecule.

Final answer:

Water has polar covalent bonds and engages in hydrogen bonding, making it a great solvent for ionic and polar substances. Isopropanol also has a polar covalent bond within its hydroxyl group but contains a nonpolar carbon structure, allowing it to dissolve both polar and some nonpolar substances.

Explanation:

Bonding and Structure of Water and Isopropanol

Water (H2O) displays polar covalent bonds due to the electronegativity difference between oxygen and hydrogen atoms. This polarity allows water molecules to engage in hydrogen bonding, a strong type of dipole-dipole interaction that occurs between the positive end of one water molecule and the negative end of another. Because of this polar nature and hydrogen bonding, water is an excellent solvent for ionic compounds and other polar substances, as it can solvate ions and other polar molecules effectively.

Isopropanol (C3H8O) has a similar polar covalent bond structure within its hydroxyl (-OH) group, which allows for hydrogen bonding. However, its larger carbon-containing structure (hydrocarbon part) imparts some nonpolar character to the molecule, making it capable of dissolving both polar substances and some nonpolar substances. Hence, isopropanol is regarded as an intermediate-case solvent.

Nonpolar substances generally do not dissolve well in polar solvents like water. Conversely, substances like salts and macromolecules that form ionic or polar covalent bonds do dissolve in water due to the similar nature of intermolecular interactions. Isopropanol, with its dual nature, can dissolve a variety of substances, from polar to moderately nonpolar.

Answer:

(CH3)2C=CHCH2CH3

2-methylpent-2-ene

Final answer:

Propene is the alkene that when reacted with potassium permanganate in strong acidic conditions, yields acetone and propanoic acid due to the oxidative cleavage of its double bond.

Explanation:

The alkene that gives a mixture of acetone and propanoic acid when reacted with potassium permanganate in the presence of strong acid and water is propene. During this reaction, propene undergoes oxidative cleavage with potassium permanganate as the oxidizing agent. The double bond in propene is cleaved to form acetone and propanoic acid under these reaction conditions.

Oxidative cleavage of alkenes with potassium permanganate can produce various products such as ketones, acids, or even carbon dioxide, depending on the structure of the alkene and the reaction conditions. The mechanism involves the formation of a diol intermediate through syn-hydroxylation, which is then cleaved to give the resultant products.

Answer:

Option (A)

Explanation:

The dew point refers to the temperature at which the amount of water vapor present in the air is so high that the relative humidity becomes 100%, and with the increasing rate of cooling, the condensation process takes place and dew is formed.

So for dew point to occur, the air temperature must reach a condition where the air is fully saturated or the relative humidity is 100%.

Thus, the correct answer is option (A).

The dew point should be an option a.

It defined the temperature at which the water vapor amount should be present in the air is so more due to this the relative humidity becomes 100%, and with the increasing rate of cooling, the condensation process takes place and dew is created.

Learn more about temperature here:  https://brainly.com/question/12883307

Answer:

The answer to your question is 0.82 moles of CO₂  

Explanation:

Data

V = 10L

T = 25°C

P = 1 atm

moles = n = ?

R = 0.08205 atm L/mol°K

Process

1.- Convert °C to °K

T = 25 + 273 = 298°K

2.- Use the ideal gas law to find the moles of Acetylene

    PV = nRT

Solve for n

    n = PV / RT

Substitution

     n = (1)(10) / (0.08205)(298)

Simplification

    n = 10 / 24.45

Result

     n = 0.409  moles of Acetylene

3.- Use proportions to find the moles of CO₂

                  2 moles of C₂H₂ ------------------- 4 moles of CO₂

                  0.409 moles       -------------------  x

                  x = (0.409 x 4) / 2

                  x = 1.636 / 2

                  x = 0.82 moles of CO₂