What is the electromagnetic spectrum and how is it used to gather information about
components in the universe?

The velocity of the apple just before it hits the ground is 10 m/s.

The given parameters;

Apply the principle of conservation of mechanical energy to determine the velocity of the apple before it hits the ground.

K.E = P.E

¹/₂mv² = 10

mv² = 2(10)

mv² = 20

0.2v² = 20

[tex]v^2 = \frac{20}{0.2} \\\\v^2 = 100\\\\v = \sqrt{100} \\\\v = 10 \ m/s[/tex]

Thus, the velocity of the apple just before it hits the ground is 10 m/s.

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The given question requires calculating the work done to pump liquid into a specifically shaped container by integrating the weight of the liquid over the height it is lifted, taking gravity into account.

The question concerns calculating the work required to pump liquid into a container. This container has been formed by revolving the region bounded by y=x^2 and the x-axis around the y-axis, between x=0 and x=2. When calculating the work done in a physics context, the scenario typically involves considerations of force, distance, and energy. For this particular case, you would use the concept of work done against gravity to fill the container with a liquid from a source below its base, which involves integrating the weight of the liquid elements being moved over the height they are lifted. The fact that pg=1 implies we're assuming a uniform density of the liquid and a gravitational field strength of 1, probably to simplify calculations. However, without additional information such as vector force fields or specific motion paths like in other provided excerpts, we can't calculate an exact numerical answer here.

The energy of an object as it is in motion is defined as Kinetic energy.

Explanation:

The energy that is attained by an object when it is moving is called as Kinetic energy. It is the amount of energy that is essential for inducing an acceleration in an object and making it to displace from its idle position to the destination. When an object attains the acceleration it can have this kinetic energy until there is a change in the speed of the object with which it moves.

The forms of energy changes and it can take any form like thermal, electrical, electromagnetic,etc. Potential and kinetic energy are the two things under which these forms are energy are grouped. There can be a transferring of Kinetic energy from one object to another. The kinetic energy can also take any form of energy.  

Answer:

11 m/s²

Explanation:

Acc = v/t

Acc = 22 / 2.0

Acc = 11 m/s²

Answer: a= m/s divide by sec

22m/s divided by 2.0sec

11m/s

Explanation: dividing the meter per second [m/s] by the second [s

Answer:

[tex]W=-21,870,000\ J[/tex]

Explanation:

Work and Kinetic Energy

The work an object does due to its motion is equal to the change of its kinetic energy. Being ko and k1 the initial and final kinetic energy respectively and m the mass of the object, then

[tex]W=\Delta k=k_1-k_0[/tex]

Since

[tex]\displaystyle k=\frac{mv^2}{2}[/tex]

We have

[tex]\displaystyle W=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}[/tex]

The truck has a mass of 60,000 kg and is moving at 27 m/s. The runaway truck ramp must stop the truck, so the final speed is 0. Thus

[tex]\displaystyle W=\frac{(60,000)0^2}{2}-\frac{(60,000)(27)^2}{2}[/tex]

[tex]W=0-21870000\ J[/tex]

[tex]\boxed{W=-21,870,000\ J}[/tex]

The work done to stop a 60,000-kg truck moving at 27 m/s is -2.2 × 10⁷ J.

The principle of work and kinetic energy (also known as the work-energy theorem) states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.

We can calculate the work done to stop the truck using the work-energy principle.

W = ΔK

W = 1/2 × m × v² - 1/2 × m × u²

W = 1/2 × 60,000 kg × (0 m/s)² - 1/2 × 60,000 kg × (27 m/s)²

W = -2.2 × 10⁷ J

where

The work done to stop a 60,000-kg truck moving at 27 m/s is -2.2 × 10⁷ J.

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Answer:

dependent variable is the light the plant received

Explanation:

Answer:

kjhgfd

Explanation:

Answer: KE = 4500 J

Explanation: Solution:

First convert 54 km/h to m/s

54 km/h x 1000m/ 1km x 1h /3600s

= 15 m/s

Use the equation for Kinetic Energy and substitute the values:

KE = 1/2 mv²

= 1/2 40 kg x ( 15 m/s)²

= 1/2 9000

= 4500 J

Answer:

a. [tex]\displaystyle k_o=1350\ J[/tex]

b. [tex]\displaystyle k_1=0\ J[/tex]

c. [tex]\Delta k=-1350\ J[/tex]

d. [tex]W=-1350\ J[/tex]

e. [tex]F=-675\ N[/tex]

Explanation:

Work and Kinetic Energy

When an object moves at a certain velocity v0 and changes it to v1, a change in its kinetic energy is achieved:

[tex]\Delta k=k_1-k_0[/tex]

Knowing that

[tex]\displaystyle k=\frac{mv^2}{2}[/tex]

We have

[tex]\displaystyle \Delta k=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}[/tex]

The work done by the force who caused the change of velocity (acceleration) is

[tex]\displaystyle W=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}[/tex]

If we know the distance x traveled by the object, the work can also be calculated by

[tex]W=F.x[/tex]

Being F the force responsible for the change of velocity

The 75 kg baseball player has an initial velocity of 6 m/s, then he slides and stops

a. Before the slide, his initial kinetic energy is

[tex]\displaystyle k_o=\frac{mv_0^2}{2}[/tex]

[tex]\displaystyle k_o=\frac{(75)6^2}{2}[/tex]

[tex]\boxed{\displaystyle k_o=1350\ J}[/tex]

b. Once he reaches the base, the player is at rest, thus his final kinetic energy is

[tex]\displaystyle k_1=\frac{(75)0^2}{2}[/tex]

[tex]\boxed{\displaystyle k_1=0\ J}[/tex]

c. The change of kinetic energy is

[tex]\Delta k=k_1-k_0=0\ J-1350\ J[/tex]

[tex]\boxed{\Delta k=-1350\ J}[/tex]

d. The work done by friction to stop the player is

[tex]W=\Delta k=k_1-k_0[/tex]

[tex]\boxed{W=-1350\ J}[/tex]

e. We compute the force of friction by using

[tex]W=F.x[/tex]

and solving for x

[tex]\displaystyle F=\frac{W}{x}[/tex]

[tex]\displaystyle F=\frac{-1350\ J}{2\ m}[/tex]

[tex]\boxed{F=-675\ N}[/tex]

The negative sign indicates the force is against movement

Answer:

a) 24 J

b) Gravitational Force

c) 45 J

d) 0

e) 6.782m/s

Explanation:

a) m = 3kg

v = 4m/s

h = 1.5m

KE = ?

0.5 * 3 * 16 = 24J

b) Gravitational force

c) F = ma = 3 * 10 = 30N

Work done = Force * distance = 30 * 1.5 = 45J

d) Final Kinetic Energy of the ball is zero because the ball eventually stops moving

e) velocity of ball as it strikes the ground = v

[tex]v^{2} - u^{2} = 2as[/tex] where

v is the velocity as it strikes the ground

u is the initial velocity

a is acceleration

s is the distance

Now since the ball is thrown downwards, a is positive because the velocity of the ball is increasing as the gravitational force acts on it

u = 4m/s

a = 10

s = 1.5

=>  [tex]v = \sqrt{2as + u^{2} }[/tex]

= [tex]\sqrt{(2*10*1.5) + 16}[/tex]

= [tex]\sqrt{46} = 6.782m/s[/tex]

The average force is -2600 N

Explanation:

First of all, we need to calculate the acceleration of the man during the collision, which is given by the suvat equation:

[tex]v^2-u^2=2as[/tex]

where:

v = 0 is his final velocity (he comes to a stop)

u = 4.0 m/s is the initial velocity

a is the acceleration

s = 0.20 m is the distance covered

Solving for a,

[tex]a=\frac{v^2-u^2}{2s}=\frac{0-4.0^2}{2(0.20)}=-40 m/s^2[/tex]

The negative sign indicates that it is a deceleration.

Now we can find the average force on the man by using Newton's second law of motion:

[tex]F=ma[/tex]

where

m = 65 kg is the mass

[tex]a=-40 m/s^2[/tex]

And substituting,

[tex]F=(65)(-40)=-2600 N[/tex]

where the negative sign indicates the force is in the direction opposite to the motion.

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To calculate the average force with which the parachuter hits the sand, we can use the equation F = ma, where F is the force, m is the mass, and a is the acceleration. The average force is approximately 67 N (in magnitude), with a negative sign indicating the direction of the force exerted on the parachuter.

To calculate the average force with which the parachuter hits the sand, we can use the equation F = ma, where F is the force, m is the mass, and a is the acceleration. Since the parachuter lands with a certain speed, we can assume that the acceleration is equal to the change in velocity divided by the time taken to come to a stop. The change in velocity can be calculated by subtracting the final velocity from the initial velocity, and the time taken to come to a stop can be found using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.

Given that the mass of the parachuter is 65 kg, the initial velocity is 4.0 m/s, and the final velocity is 0 m/s, we can calculate the acceleration using a = (v - u)/t. Assuming the time taken is the same as the time taken to come to a stop, we can rearrange the equation to solve for t: t = (v - u)/a. Substituting the given values into the equation, we can calculate the time taken. Finally, we can substitute the mass and acceleration into the equation F = ma to calculate the average force.

So, the average force with which the parachuter hits the sand can be calculated as F = (65 kg) * (-(0 m/s) - (4.0 m/s))/(3.84 s), which gives a result of -67 N (or approximately 67 N in magnitude).

6. "The electric field caused by an electron is weakest near the electron" is FALSE.

7. "An electric field becomes weaker as distance from the electron increase" is TRUE.

Explanation:

The "electrical field" covers the electrical charge and exerts, attracts or repels other charges in the field.The electric field caused by an electron is strongest near the electron while it become weak as distance from the electron increase.

The reason behind is, at a point the direction of the field line is at that point the direction of the field. The relative magnitude of the electric field will be proportional to the field line density. The field is strongest where the field lines are near together and when the field lines are at increasing distance the field is weakest.

Answer:

190 m/s

Explanation:

For the plane to stay in the air, the lift force must equal the weight.

The lift force is also equal to the pressure difference across the wings (pressure at the bottom minus pressure at the top) times the area of the wings.

Therefore:

mg = (P₂ − P₁) A

P₂ − P₁ = mg / A

Using Bernoulli equation:

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²

½ ρ (v₁² − v₂²) = P₂ − P₁

½ ρ (v₁² − v₂²) = mg / A

v₁² − v₂² = 2mg / (Aρ)

v₁² = v₂² + 2mg / (Aρ)

Substituting values (assuming air density of 1.225 kg/m³):

v₁² = (100 m/s)² + 2 (2×10⁶ kg) (9.8 m/s²) / (1200 m² × 1.225 kg/m³)

v₁² = 36,666.67 m²/s²

v₁ = 191 m/s

Rounding to two significant figures, the air must move at 190 m/s over the top of the wing.

To keep the plane in the air, the air flowing over the upper surface of the wings must be faster than the air flowing past the lower surface. This is due to Bernoulli's principle, which states that as the speed of a fluid increases, its pressure decreases. We can use the equation v₂ = sqrt(v₁² + 2(P₁ - P₂)/ρ) to calculate the speed of the air over the upper surface of the wing.

To keep the plane in the air, the air flowing over the upper surface of the wings must be faster than the air flowing past the lower surface. This is due to Bernoulli's principle, which states that as the speed of a fluid increases, its pressure decreases. The difference in pressure between the upper and lower surfaces of the wing creates lift.

To calculate the speed of the air over the upper surface of the wing, we can use the equation:

P₁ + ½ρv₁² = P₂ + ½ρv₂²

P₁ is the pressure below the wing, P₂ is the pressure above the wing, ρ is the density of the air, v₁ is the speed of the air below the wing, and v₂ is the speed of the air above the wing.

We can rearrange the equation to solve for v₂:

v₂ = sqrt(v₁² + 2(P₁ - P₂)/ρ)

Plugging in the given values, we get:

v₂ = sqrt(100² + 2(0 - P₂)/(1.2))

Since we don't have the specific values for P₁ and P₂, we cannot calculate the exact speed of the air over the upper surface of the wing. However, we can determine that it must be greater than 100 m/s in order for the plane to stay in the air.

Answer:

0 J

Explanation:

Work = force × distance

Since the object isn't moved, the distance is 0.  So the work is 0.

The work done while holding an object at a certain height with no movement is zero because work requires movement. The work done pulling a cart at an angle involves the horizontal component of force and distance, while pulling horizontally simply requires multiplying force by distance.

When an object of mass 12kg is held at a height of 5m above the ground without any vertical or horizontal movement, the work done during the time it is held is zero. This is because work is defined as the force applied to an object times the distance over which the force is applied (Work = Force × Distance). If there is no movement, the distance is zero, hence no work is done, regardless of the time the object is held in place.

For part (a) of the student's example question, the work done on the cart by the boy pulling it with a 20-N force at an angle of 30° for a distance of 12 m can be found using the formula for work done when a force is applied at an angle to the displacement. The work is calculated as the product of the horizontal component of the force and the distance: Work = F × d × cos(θ), where F is the applied force, d is the distance, and θ is the angle of force. Therefore, Work = 20 N × 12 m × cos(30°) = 240 Nm × √3/2 ≈ 207.85 J.

For part (b), if the boy pulls with the same force horizontally, the work done would simply be the force times the distance, since the angle θ would be 0° and cos(0°) is 1. So, Work = 20 N × 12 m = 240 J.

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To control sound reflection in an office, cork partitions would be installed.

It is referred to as the reflection of sound when sound is travelling through one medium and then collides with the surface of another medium and travels in a different direction. The incidental and reflected sound waves are the ones that are being analysed.

An echo is a sound that is heard after a surface has reflected it.

In the same way that heat or light are partially reflected and partially absorbed when they strike a surface, sound does the same.

Hard surfaces reflect sound more effectively than soft surfaces do, and vice versa.

One of the most popular materials for reducing sound reflection is cork, due to its capacity for both sound absorption and sound proofing.

Hence,

To control sound reflection in an office, cork partitions would be installed.

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Answer:

The actual dimensions of the classroom are 50 cm x 70 cm

Explanation:

Scaling

When we need to represent real-world dimensions into small spaces, we use scaling. Distance scaling tells us what is the equivalence between the real units and the scaled units. In this case, we are told that 10 cm is equivalent to 1 meter. As 1 meter is 100 cm, it means that the scale is 100/10=10. Thus, each centimeter in the paper is equivalent to 10 cm in the real distance.

The classroom is 5 cm x 7 centimeters. Scaling back to the real values, the classroom has measures of 50 cm x 70 cm.

Scientists' estimate of the world's age has changed significantly over time, thanks to the discovery of radiometric dating techniques. They now estimate the Earth to be around 4.5 billion years old.

Over time, scientists' estimate of the world's age has changed significantly. Initially, scientists believed that the Earth was only a few thousand years old, based on religious and historical texts. However, with the discoveries of radioactivity and the development of radiometric dating techniques, scientists now estimate the age of the Earth to be around 4.5 billion years. This estimate has become increasingly accurate and is supported by various lines of evidence, including the dating of rocks and the Moon's formation.

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1) The car overtakes the truck at a distance of 160 m far from the intersection.

2) The velocity of the car is 40 m/s

Explanation:

1)

The car is travelling with a constant acceleration starting from rest, so its position at time t (measured taking the intersection as the origin) is given by

[tex]x_c(t) = \frac{1}{2}at^2[/tex]

where

[tex]a=5 m/s^2[/tex] is the acceleration

t is the time

On the other hand, the truck is travelling at a constant velocity, therefore its position at time t is given by

[tex]x_t(t) = vt[/tex]

where

v = 20 m/s is the velocity of the truck

t is the time

The car overtakes the truck when the two positions are the  same, so when

[tex]x_c(t) = x_t(t)\\\frac{1}{2}at^2 = vt\\t=\frac{2v}{a}=\frac{2(20)}{5}=8 s[/tex]

So, after a time of 8 seconds. Therefore, the distance covered by the car during this time is

[tex]x_c(8) = \frac{1}{2}(5)(8)^2=160 m[/tex]

So, the car overtakes the truck 160 m far from the intersection.

2)

The motion of the car is a uniformly accelerated motion, so the velocity of the car at time t is given by the suvat equation

[tex]v=u+at[/tex]

where

v is the velocity at time t

u is the initial velocity

a is the acceleration

For the car in this problem, we have:

u = 0 (it starts  from rest)

[tex]a=5 m/s^2[/tex]

And we know that the car overtakes the truck when

t = 8 s

Substituting into the equation,

[tex]v=0+(5)(8)=40 m/s[/tex]

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The Traits an organism displays are ultimately determined by the genes it inherited from its parents, in other words by its genotype. Variant copies of a gene are called alleles, and an individuals genotype is the sum of all the alleles inherited from the parents.

Answer:

200 ohms

Explanation:

Answer:

200

Explanation:

Answer:

153.54 cm³

Explanation:

The formula for the volume of a cube is v = lwh, where l is the length, w is the width, and h is the height of the block.  Multiply, 6.21*4.63*5.34 = 153.54

Answer: It would increase.

Explanation:

The equation for determining the force of the gravitational pull between any two objects is:

[tex]F = G \frac{m1m2}{r^2}[/tex]

Where G is the universal gravitational constant, m1 is the mass of one body, m2 is the mass of the other body, and r^2 is the distance between the two objects' centers squared.

Assuming the Earth's mass but not its diameter increased, in the equation above m1 (the term usually indicative of the object of larger mass) would increase, while the r^2 would not.

Thus, it goes without saying that, with some simple reasoning about fractions, an increasing numerator over a constant denominator would result in a larger number to multiply by G, thus also meaning a larger gravitational strength between Earth and whatever other object is of interest.

Final answer:

If Earth's mass increased with its diameter unchanged, gravitational strength at its surface would also increase proportionally. The weight of objects on Earth would thus increase in direct relation to the mass increase.

Explanation:

If Earth's mass increased but its diameter remained unchanged, the gravitational strength near Earth's surface would increase proportionally to the mass increase. This is because gravitational force is directly proportional to the mass of the objects. For example, if Earth had 10 times its present mass but the same volume, a person's weight would increase by a factor of 10.

Conversely, with one-third of Earth's present mass, the gravitational force would reduce by a factor of 1/3, and a person would weigh only one-third as much as they currently do. Since the question implies that the gravitational force is what changes with the mass of Earth, we can infer that a greater mass leads to a stronger gravitational pull and thus an increase in weight for objects at the surface, assuming the radius stays constant.

Answer:

C. The warm air will rise, causing water vapor to condense and form clouds.

Explanation:

411.4272 grams of flour is required to make 32 cupcakes.

Measurement is defined as the quantification of characteristics of an object or phenomenon that can be used to compare them with other objects or phenomena. Measurement is described as the process of determining how large or small a physical quantity is compared to a basic reference quantity of the same type.

Above given example is measured as:

Since 360 ​​grams of flour is used to make 28 cupcakes, so, the amount (mass) of flour is distributed evenly over all 28 cupcakes

Each cupcake requires 360/28 grams of flour = 12.8571 grams.

So, for making 32 cupcakes= 32* 12.8571= 411.4272 grams of flour is required

Thus, 411.4272 grams of flour is required to make 32 cupcakes.

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Neither side of the equation may be used because there are too many unknown quantities before, during, and after the collision

Explanation:

The impulse theorem states that the change in momentum of an object is equal to the impulse, which is the product between the average force applied and the duration of the collision:

[tex]\Delta p = F \Delta t[/tex]

where

[tex]\Delta p[/tex] is the change in momentum

F is the average force

[tex]\Delta t[/tex] is the duration of the collision

In this problem, neither side of the equation can be used to measure the change in momentum. In fact:

- The change in momentum (left side) is given by

[tex]\Delta p = m(v-u)[/tex]

where

m is the mass of the object

u is the initial velocity

v is the final velocity

Here the final velocity is not known, so it's not possible to use this side of the equation

- The impulse (right side) is given by

[tex]F\Delta t[/tex]

here the average force is known, however the duration of the collision is not known, so it's not possible to use this side of the equation.

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Neither side of the equation may be used because there are too many unknown quantities before, during, and after the collision. Therefore, option (C) is correct.

According to the impulse-momentum theorem, "The change in momentum of an object is equal to the impulse produced by the object. Where the impulse is expressed as the product of average force on the object and the duration of collision (reaction time)".

The expression is given as,

..............................................(1)

Here, [tex]\delta p[/tex] is the change in momentum, [tex]F_{av.}[/tex] is the average force and t is the reaction time.

In equation (1),  [tex]\delta p[/tex] is the change in momentum which is given as,

[tex]\delta p = m(v-u)[/tex]

Here, m is the mass, v and u are the final and initial velocities of object respectively.

Thus, we can conclude that there are various unknown variables present in the problem, for which neither side of the equation may be used to determine change in momentum of object. Hence, option (C) is correct.

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Correct Question:

Calculate the distance (in km) charlie runs if he maintains an average speed of 8 km/hr for 1 hour

Answer:

The total distance covered by Charlie is 8 km in 1 hour.

Explanation:

The average velocity as given in the question is,

v = 8 km/hr

Total time taken,

[tex]$t=1 hour[/tex]

As we know the formula to evaluate the total distance d when the average velocity and time is given;

[tex]v=\frac{d}{t}[/tex]

[tex]d=v \times t[/tex]

[tex]d=8 \times 1[/tex]

[tex]d=8 k m[/tex]

Hence, the total distance covered by Charlie in 1 hour will be 8 km.

Charlie runs a distance of 60 kilometers in 1 hour if he maintains an average speed of 60 km/h; this is calculated using the formula Distance = Speed × Time.

To calculate the distance that Charlie runs if he maintains his average speed for 1 hour, we follow a simple relation, which is: Distance = Speed × Time.

In question 8, an average speed calculation was mentioned, but since we don't have the exact number here, let's assume (based on the given information elsewhere) that the average speed we calculated previously was 60 km/h. To find the distance Charlie runs at this average speed over the course of 1 hour, we simply use the formula:

Distance = Average Speed × Time

Substituting the values we have:

Distance = 60 km/h × 1 hour = 60 km

Hence, Charlie runs a distance of 60 kilometers in 1 hour if he maintains the aforementioned average speed.

Explanation:

Magnet

• Magnet :- is an object which attracts pieces of iron, steel etc towards itself.  

Some facts about magnets:-  

• When magnet is freely suspended it always align towards north-south direction    

• Like poles always repel  & opp. poles attract each other.  

• Magnet always exist as dipole    

• Two poles can never be separated : if we try to cut it then still both the poles will exist even ina small piece of magnet .it automatically develops the lost polarity

Magnet always develop certain area around it where its effect can be felt ie. magnetic field.  

MAGNETIC Field  

is studied by drawing imaginary lines called magnetic lines of forces.  

  Characteristics.  

• They always originate from North pole & terminate at South pole. This shows that if north pole was free is move it would have mvre towards south pole.  

•Place where they are closer indicate strong M. field i.e. at poles.  

•Mag. Field lines gives the direction of magnetic force.  

•Two magnetic lines will never intersect each other as they give direction of force & force can’t have 2 direction at a time.  

This is what that happens in  magnetic materials .

Non magnetic materials

Types of magnetic materials

Soft magnetic materials (e.g. iron) have domains that easily move into line when the metal is placed in a magnetic field but as soon as the field is removed the domains take on a random pattern again. It returns to being unmagnetized straight away.

Hard magnetic materials (e.g. steel) have domains that do not easily move into line when the metal is placed in a magnetic field, a strong field is needed for some time, but then, when the field is removed the domains retain the magnetic pattern. The metal stays magnetic for a long time.

Answer:

Strong Push

Explanation:

tbh it's self explanatory! but, i just took this test and this was the correct answer, i hope this helps you! <3

Answer:

b - wires

Explanation:

cells , dry cells , electrical outlets are all responsible for the varying electron pressure/ potential difference hence wires is our answer because wires are just conductors which can only influence resistance.