What happens when you position the mouse cursor over an edge or corner of a bounding box that has sizing handles?

Answer:

The correct answer is letter "C": Geographical location.

Explanation:

Within an organization, different employees possess different experiences. Those experiences are also influenced by the organizational culture of the previous companies where they used to work. Different geographical locations imply businesses are managed differently according to what the customers request and what the firm wants to promote among the employees. When workers leave those environments to others where they will be playing similar roles but the company's culture is different, conflict takes place.

The correct answer is option a. It would appear that this difference in culture is primarily driven by key organizational members.

The difference in culture between the Luther Post Office and the Jones Post Office regarding their lunch break policy is likely driven by key organizational members. These individuals can influence policies and practices based on their preferences and management styles. The decision to close the window entirely for lunch at the Luther Post Office versus staggering breaks at the Jones Post Office reflects the choices and leadership styles of the key organizational members at each location.

Answer:

JPanel PayrollPanel=new JPanel();

JButton saveButton=new JButton("Save");

A full code snippet and screen shot is provided in the explanation section

Explanation:

import java.awt.*;

import javax.swing.*;

public class TestClass {

   TestClass()  {

       JFrame f= new JFrame("Payroll Panel");

       JPanel payrollPanel=new JPanel();

       payrollPanel.setBounds(10,20,200,200);

       payrollPanel.setBackground(Color.gray);

       JButton saveButton=new JButton("Save");

       saveButton.setBounds(50,100,80,30);

       saveButton.setBackground(Color.yellow);

       payrollPanel.add(saveButton);

       f.add(payrollPanel);

       f.setSize(400,400);

       f.setLayout(null);

       f.setVisible(true);

   }

   public static void main(String args[]) {

       new TestClass();

   }

}

Answer:

JPanel PayrollPanel=new JPanel();

JButton saveButton=new JButton("Save");

A full code snippet and screen shot is provided in the explanation section

Explanation:

import java.awt.*;

import javax.swing.*;

public class TestClass {

  TestClass()  {

      JFrame f= new JFrame("Payroll Panel");

      JPanel payrollPanel=new JPanel();

      payrollPanel.setBounds(10,20,200,200);

      payrollPanel.setBackground(Color.gray);

      JButton saveButton=new JButton("Save");

      saveButton.setBounds(50,100,80,30);

      saveButton.setBackground(Color.yellow);

      payrollPanel.add(saveButton);

      f.add(payrollPanel);

      f.setSize(400,400);

      f.setLayout(null);

      f.setVisible(true);

  }

  public static void main(String args[]) {

      new TestClass();

  }

}

Answer:

The correct answer is letter "C": Highly centralized.

Explanation:

Jointness is a strategy of the Department of Defense (DoD) in the attempt of combining efforts between the U.S. Military Forces in all stages of operations. With this approach, the Army, Navy, and Air Forces would share resources to help each other while each body would keep its own management.

Answer: read, write and modify

Explanation:

Answer: a database system is complex to build and understand, and apart from that, a database systems contains many different tables and fields which a lot of computers are connected to. A failure will lead to information loss

Explanation:

Answer:

The correct answer to the following question will be "Software Development Tools".

Explanation:

Therefore, the Software development tool is the right answer.

Final answer:

Programmers use Integrated Development Environments (IDEs) to develop, modify, and test software. These environments include tools for version control, like GitHub, and practices such as unit testing to ensure software quality.

Explanation:

Applications that programmers use to create, modify, and test software are referred to as Integrated Development Environments (IDEs). An IDE is a powerful suite of software development tools in one single application. It enables programmers to write code, debug errors, and test their applications before deployment. Features like versioning allow developers to manage different stages of their software builds, and tools like GitHub facilitate collaboration and source code management among teams. Unit testing is a crucial process in an IDE that allows developers to validate each part of the code individually to ensure correct behavior.

Other types of applications, often referred to simply as apps, include software like word processors, media players, and accounting software, designed to perform specific tasks for end-users. However, it's the development apps like IDEs where software creation and modification occur.

Answer:

True

Explanation:

A Domain Name Service comprises of computer servers that carries a database of public IP addresses and their related human-readable domain names/hostnames, it receives query as hostnames and helps to translates those human-readable domain names/hostnames into IP addresses that computers and routers understand.

Answer:

b. System.Data.OleDb

Explanation:

OLE DB: It describes a collection of classes used to access an OLE DB data source in the managed space.

Answer:

The Java code is given below with appropriate comments for explanation

Explanation:

// java code to contradict birth day paradox

import java.util.Random;

public class BirthDayParadox

{

public static void main(String[] args)

{

   Random randNum = new Random();

   int people = 5;

   int[] birth_Day = new int[365+1];

   // setting up birthsdays

   for (int i = 0; i < birth_Day.length; i++)

       birth_Day[i] = i + 1;

   int iteration;

   // varying number n

   while (people <= 100)

   {

       System.out.println("Number of people: " + people);

       // creating new birth day array

       int[] newbirth_Day = new int[people];

       int count = 0;

       iteration = 100000;

       while(iteration != 0)

       {

           count = 0;

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               // generating random birth day

               int day = randNum.nextInt(365);

               newbirth_Day[i] = birth_Day[day];

           }

           // check for same birthdays

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               int bday = newbirth_Day[i];

               for (int j = i+1; j < newbirth_Day.length; j++)

               {

                   if (bday == newbirth_Day[j])

                   {

                       count++;

                       break;

                   }

               }

           }

           iteration = iteration - 1;

       }

       System.out.println("Probability: " + count + "/" + 100000);

       System.out.println();

       people += 5;

   }

}

}

Answer:

The source code and output is attached.

I hope it will help you!

Explanation:

The combined resistance of three resistors connected in parallel is calculated using the formula Rt = 1 / (1/R1 + 1/R2 + 1/R3), and in this case, the equivalent resistance is 2 ohms.

The student's question pertains to the calculation of the combined resistance of three resistors connected in parallel. The provided equation shows how to calculate the total resistance of a parallel circuit. If we define R1, R2, and R3 as the resistance values of the three resistors, we can then use the formula Rt = 1 / (1/R1 + 1/R2 + 1/R3) to find the equivalent resistance. To illustrate, let's assume that R1 is 4 ohms, R2 is 6 ohms, and R3 is 12 ohms. Applying the formula, we calculate the combined resistance (Rt) as follows: Rt = 1 / (1/4 + 1/6 + 1/12) = 1 / (0.25 + 0.1667 + 0.0833) = 1 / 0.5 = 2 ohms. Hence, the equivalent resistance of the three resistors connected in parallel is 2 ohms.

Answer: Interoperability

Explanation:

Interoperability is the skill in system that helps in communicating and exchanging information and services with each other.It can be used in various industries and platform as the task is performed without considering specification and technical build.

Answer:

No

Explanation:

Wireless communication devices like the cell phones transmits signals using radio or electromagnetic wave, which would trigger a bomb. An example of this kind of bomb is the home-made bomb also known as IED (improved explosive device).

The most common type of this IED is the radio controlled IED, which uses electromagnetic wave from a cell phone or a radio controlled type firing circuit. Insurgents, criminals etc, make use of such devices, since the materials are easy to get and are affordable.

Answer:

The correct answer is letter "C": always.

Explanation:

Vulnerability management is in charge of preventing, identifying, and eliminating threats that could exploit vulnerabilities in a software system. The threat can damage or destroy the software after the threat gained unauthorized access and it does not matter how large the vulnerability of the software is, a threat will exploit it.

A. 11011111

To convert -33 to a signed binary number, a 2's complement representation of the number is used. Signed numbers are stored on the computer using 2's complement notation.

(i) First convert 33 to binary

2  |   33

2  |    16 r 1

2  |    8 r 0

2  |    4 r 0

2  |    2 r 0

2  |     1 r 0

2  |     0 r 1

Therefore writing the remainders from bottom to top, we have that

33 in binary is 100001

(ii) Since the options are all in 8 bits, convert the binary to its 8-bit representation by padding it with zeros(0s) at the left.

=> 100001 = 00100001

(iii) Now, convert to 2's complement by

(a) flipping all the bits in the binary number. i.e change all 1s to 0s and all 0s to 1s

=> 00100001 => 11011110

(b) and then adding 1 to the result as follows;

1 1 0 1 1 1 1 0

+                1

1 1 0 1 1 1 1 1

Therefore, -33 to binary is 11011111

Hope this helps!

Final answer:

The binary translation of signed decimal -33 in two's complement representation is 11011111, which corresponds to option (a).

Explanation:

To find the binary translation of the signed decimal -33, we use the two's complement method which is a way of encoding negative numbers in binary. First, we find the binary representation of the positive number, then invert all the bits (change 0s to 1s and 1s to 0s), and finally, add 1 to that inverted number.

The binary representation of 33 is 00100001. Inverting the bits gives us 11011110. Adding 1 to that gives us 11011111, which is option (a).

Answer:

The correct answer should be: "Besides many important topics, 'privacy policies' and 'technology ethics" are two mandatory ones for security education and training".

Explanation:

'Privacy policies' concerning technology is a key for technologies reliability and functionality nowadays for they are patterns to better organize, normatize, and outline how they must work and which are their limits, possibilities, advantages, and disadvantages for technology users. 'Technology ethics' are principles, perspectives, values, and foundations that govern and maintain technology organizations in a reliable and ethical state. All organizations must take care of their employees and educate them concerning their working foundations, policies, and organization. Employees must follow them in order to develop and implement their working foundations and make all things improve and work properly. There are many other topics to be included in security education and training, but these two are the most important ones and must not be left off.

(ps: mark as brainliest, please?!)

Answer:

The cross sectional area in mm2 is 7.07[tex]mm^{2}[/tex]

The cross sectional area in cm2 is 0.0707[tex]cm^{2}[/tex]

Explanation:

The cross-sectional area (a) of the wire is given by;

a = [tex]\pi[/tex] x [tex]\frac{d^{2} }{4}[/tex]

where d is the diameter of the cross section = 3.00mm

1 => To find the cross-sectional area in [tex]mm^{2}[/tex], substitute the value of d = 3.00mm into the equation above as follows;

a = [tex]\pi[/tex] x [tex]\frac{3.00^{2} }{4}[/tex]

Taking [tex]\pi[/tex] to be [tex]\frac{22}{7}[/tex] we have;

a = [tex]\frac{22}{7}[/tex] x [tex]\frac{3.00^{2} }{4}[/tex]

a = 7.07[tex]mm^{2}[/tex]

2 => To find the cross-sectional area in [tex]cm^{2}[/tex], first convert the diameter in mm to cm as follows;

3.00mm = 0.3cm

Now, substitute the value of d = 0.3cm into the equation above as follows;

a = [tex]\pi[/tex] x [tex]\frac{0.3^{2} }{4}[/tex]

Taking [tex]\pi[/tex] to be [tex]\frac{22}{7}[/tex] we have;

a = [tex]\frac{22}{7}[/tex] x [tex]\frac{0.3^{2} }{4}[/tex]

a = 0.0707[tex]cm^{2}[/tex]

Final answer:

The cross-sectional area of the wire is approximately 0.07069 mm² in mm² and 0.0007069 cm² in cm².

Explanation:

To calculate the cross-sectional area of the wire in mm2, we can use the formula for the area of a circle:

A = πr2

Since the diameter of the wire is given as 3.00mm, the radius is half of that, which is 1.50mm. Converting mm to cm, the radius becomes 0.15cm. Plugging this value into the area formula, we get:

A = π(0.15cm)2

A ≈ 0.07069 cm2

To calculate the cross-sectional area of the wire in cm2, we can simply convert the area in mm2 to cm2. Since 1 cm is equal to 10 mm, we divide the area in mm2 by 100:

A in cm2 ≈ 0.07069 cm2 ÷ 100

A ≈ 0.0007069 cm2

Answer:

Explanation:

An Access Control Matrix ACM can be defined as a table that maps the permissions of a set of subjects to act upon a set of objects within a system. The matrix is a two-dimensional table with subjects down the columns and objects across the rows. The permissions of the subject to act upon a particular object are found in the cell that maps the subject to that object.

Summary

The rows correspond to the subject

The columns correspond to the object

What does each cell in the matrix contain? Answer: Each cell is the set of access rights for that subject to that object.

Answer:

Below is a possible implementation using D-flip-flops.

Explanation:

Creating a counter that only counts even numbers is easy, just add a dummy bit-0 that is always 0. Creating a counter with D-flip-flops is also quite straightforward. The clock should be connected to the clock of the least significant bit, and the !Q output of the D flip flop should be fed back to the D input. Also, !Q should be used as a clock for the next bit.

Now, letting the counter wrap around to zero at 10 is tricky because of switching hazards. I created an NAND gate that compares the outputs to be 101, and the clock to be 0. Only this way you can guarantee that the outputs are stable. Now the resulting signal has to be delayed for one clock pulse. This can be achieved with an additional flip flop. The Q output of that flip flop operates the async resets of the counter flipflops.

Answer:

Here is the JAVA program:

import java.util.Scanner;   // for importing scanner class

public class RomanToDecimal{  //class to convert roman numeral to decimal

       static String romNum;  // variable that stores roman numeral

       static int decNum;  //variable that stores decimal number

       public static void main(String args[]) {  //start of the program

              //romtodec object created

              RomanToDecimal romtodec = new RomanToDecimal();  

//call function decimalConversion() that converts roman numeral to decimal

              romtodec. decimalConversion();  

//call function displayRomanNumeral to display the results of conversion

               romtodec. displayRomanNumeral(romNum);

//call function to display the decimal no. of roman numeral

               romtodec . displayDecimalNumber(decNum);   }

//method decimalConversion to convert Roman numeral to decimal

     public void decimalConversion () {

     Scanner scan = new Scanner(System.in);  //to get input

       //prompts user to enter a Roman numeral

     System.out.print("enter a Roman numeral: ");

               romNum = scan.nextLine();  //reads input    

               //stores the length of the entered Roman numeral                                            

                int length=  romNum.length();  

               int number=0;  //initializes number to 0

               int prevNum = 0;  //initializes previous number to 0

          //loops through the length of the input Roman numeral

               for (int i=length-1;i>=0;i--)  

//charAt() method returns the roman numeral symbol at the index i

               { char symbol =  romNum.charAt(i);

       //every symbol will be converted to upper case

                       symbol = Character.toUpperCase(symbol);

//switch statement tests the symbol variable for equality against a list of //numerals given and each numeral is assigned its equal decimal value.

                         switch(symbol)

                       {   case 'I':

                               prevNum = number;

                               number = 1;

                               break;

                            case 'V':

                                    prevNum = number;

                               number = 5;

                               break;

                               case 'X':

                                       prevNum = number;

                               number = 10;

                                break;

                               case 'L':

                                       prevNum = number;

                               number = 50;

                               break;

                               case 'C':

                                        prevNum = number;

                               number = 100;

                               break;

                               case 'D':

                                        prevNum = number;

                               number = 500;

                               break;

                               case 'M':

                                        prevNum = number;

                               number = 1000;

                               break; }          

/*checks if the number is greater than previous number

if the value of current roman symbol (character) is greater than the next

symbol's value. then add value of current roman symbol to the decNum

else subtract the value of current roman symbol from the value of its next symbol. */              

                       if (number>prevNum)

                           { decNum= decNum+number;  }

                       else

                          decNum= decNum-number;  }

//displays the decimal value of the roman numeral

       public static void displayRomanNumeral (String romNum){

               System.out.println ("The Roman numeral "+romNum+" is equal to decimal number"+decNum); }

//displays the number as decimal

           public static void displayDecimalNumber (int decNum){

       System.out.println ("The decimal number is: " + decNum);  } }      

Output:

enter a Roman numeral: MCXIV

The Roman numeral MCXIV is equal to decimal number 1114

Output:

enter a Roman numeral: CCCLIX

The Roman numeral CCCLIX is equal to decimal number 359

Output:

enter a Roman numeral: MDCLXVI

The Roman numeral MDCLXVI is equal to decimal number 1666

Answer:

#include <stdio.h>// header file

int main() // main function definition

{

   int number; // variable declaration

   scanf("%d",&number); // user input for number

   if(number%2==0) // check the number to even.

   printf("Number is a even number"); // print the message for true value

   else

   printf("Number is a odd number"); // print the message for false value.

   return 0; // return statement.

}

Output:

Explanation:

An app can be written to determine whether an integer is odd or even using the remainder operator in programming.

To write an app that determines whether an integer is odd or even, you can use the remainder operator in programming. Here's an example in C++:

In the above code, the remainder operator % is used to check if the num variable is divisible by 2. If the remainder is 0, then the number is even; otherwise, it is odd.

https://brainly.com/question/32572857

#SPJ11

Answer:

See the explanation

Explanation:

#1 part 1

See the attached Image 1

#1 part 2

See the attached Image 2

To display the user agent in a webpage, use the writeln method of the document object with window.navigator.userAgent. Use document.querySelector to assign the first h2 element and document.getElementsByClassName for all elements with the class 'language-item'. The correct syntax to write 'Hello World' in JavaScript is document.write('Hello World').

To display the user agent using JavaScript, you can use the writeln method of the document object. Here's a sample code:

DOM Manipulation

To assign the first h2 element and all elements with a class name of 'language-item', you can use the following code:

Output in JavaScript

The correct JavaScript syntax to write 'Hello World' is:

This method allows you to place text directly into the DOM, making it visible on the webpage.

Answer:

(a) 58

(b) 447

(c) 16534

Explanation:

Since these integers are in hexadecimal format, it is worthy to know or note that;

A => 10

B => 11

C => 12

D => 13

E => 14

F => 15

Therefore, using these, let's convert the following to decimal:

(a) 3A = 3 x [tex]16^{1}[/tex] + 10 x [tex]16^{0}[/tex]

=> 3A = 48 + 10

=> 3A = 58 (in decimal)

(b) 1BF = 1 x [tex]16^{2}[/tex] + 11 x [tex]16^{1}[/tex] + 15 x [tex]16^{0}[/tex]

=> 1BF = 256 + 176 + 15

=> 1BF = 447 (in decimal)

(c) 4096 = 4 x [tex]16^{3}[/tex] + 0 x [tex]16^{2}[/tex] + 9 x [tex]16^{1}[/tex] + 6 x [tex]16^{0}[/tex]

=> 4096 = 4 x 4096 + 0 + 144 + 6

=> 4096 = 16534 (in decimal)

Note:

Do not forget that any number greater than zero, when raised to the power of zero gives 1.

For example,

[tex]4^{0}[/tex] = 1

[tex]59^{0}[/tex] = 1

Answer:

Option (A)

Explanation:

In the post order traversal, we always print left subtree, then right subtree and then the root of the tree. In preorder traversal, First the root is printed, then, left subtree and at last, right subtree, so, the first element in preorder is the root of the tree and we can find elements of left sub tree from in order as all the elements written left to the root will of left subtree and similarly the right one. This is how repeating it will give the post order traversal.

Answer:

The correct answer to the following question will be Option A (d e b f g c a).

Explanation:

In the given question the binary tree is missing, so the question is incomplete. The complete question will be:

                            a

                        /         \

                     b             c

                 /       \        /     \

               d         e    f         g

Now coming to the answer:

In this tree we are applying the post order algorithm for traversing the tree is given below:

Step 1: Go to the left-subtree.

Step 2: Go to the right-subtree.

Step 3: Print the data.

The root 'a' is follow the algorithm Post order After applying the algorithm it comes to the node 'b', 'b' is also follow the Post order algorithm then it comes to 'd', after applying the algorithm Post order it prints 'd'. Similarly all the node follow the same algorithm .

Answer:

short_names = ['Gus', 'Bob','Zoe']

Explanation:

A list is a type of data structure in python that allows us to store variables  of different types. Each item in a list has an index value which must be a integer value, and the items can be assessed by stating the index position. The syntax for creating and initializing a list is:

list_name = [item1, item2,item3]

The python code below shows the implementation of the solution of the problem in the question:

short_names = ['Gus', 'Bob','Zoe']

print(short_names[0])

print(short_names[1])

print(short_names[2])

The output is:

Gus

Bob

Zoe

To initialize the `short_names` list with 'Gus', 'Bob', and 'Zoe', assign these names to the list variable and use the `print()` function to print each name individually. This is how the program achieves the required output.

To initialize a list in Python with specific strings, you can simply assign the list elements directly to a variable. Here is how you do it:

short_names = ['Gus', 'Bob', 'Zoe']

Next, to print each element individually as specified in your program, you can use the print() function:

When you run this code, you will get the following output:

Gus
Bob
Zoe

Here is the complete code for clarity:

Answer:

const stdin = process.openStdin();

const stdout = process.stdout;

const reverse = input => {         //checks if input is number

 if (isNaN(parseInt(input))) {

   stdout.write("Input is not a number");

 }

 if (parseInt(input) <= 0) {.                       // checks if no. is positive

   stdout.write("Input is not a positive number");

 }

 let arr = [];                                  // pushing no. in array

 input.split("").map(number => {

   if (number % 2 == 0) {

     arr.push(number);

   }

 });

 console.log(arr.reverse().join(""));              // reversing the array

};

stdout.write("Enter a number: ");

let input = null;

stdin.addListener("data", text => {

 reverse(text.toString().trim());             //reversing

 stdin.pause();

});

Explanation:

In this program, we are taking input from the user and checking if it is a number and if it is positive. We will only push even numbers in the array and then reversing the array and showing it on the console.

High quality pages in a task should all get the same Needs Met rating. For example, a high quality page for a common interpretation of the query should get the same Needs Met rating as a high quality page for a minor interpretation of the query - False

The Needs Met rating for a high-quality page should correspond to the relevance and usefulness of the content concerning the user's query, which can vary even among high-quality pages. When considering a page's relevance, it is important to evaluate if the content directly relates to the research topic or question at hand. We must also consider precision and recall, where precision is the correctness of the information in context, and recall is the completeness of the information provided.

Assessing report quality goes beyond just ensuring high-quality content; it involves meeting the intention of the assignment and the specific requests of the task. It also includes identifying any opportunities and threats that arise during the research process. Moreover, conclusions and recommendations should be supported with data and logic to ensure that the decision based on the report is sound.

Answer:

Option C is the correct answer for the above question.

Explanation:

The ciphertext is a text which is formed from an original text and can be called a duplicate text which has no meaning for the other user. This can be formed with the help of encryption technology. Encryption technology is a technology that uses some mythology to convert the original data into other text data (which is also called a ciphertext) because no one can able to hack the data.

The above question asked about the term which is called for the text when it is converted from original data. That text is known as ciphertext which is described above and it is stated from option c. Hence option c is the correct answer while the other is not because--

Answer:

False

Explanation:

Proprietary networks are those that are privately and exclusively managed, controlled and even owned by some organizations.

Internet Service Providers (ISPs) are companies that provide internet access services to companies and consumer products. They allow devices to connect to the internet. They offer much more than just internet access. They also offer related services such as email access, web development and virtual hosting.

ISPs can be open source or proprietary. They could be owned by a community, a firm and even non-profit organizations.

Answer:

55kbps

Explanation:

Answer:

Option c is the correct answer for the above question.

Explanation: