Answer:
Explanation:
An air mass is a large body of air that exhibits uniform temperature and moisture characteristics and helps to determine the weather within an area. Warm air masses tend to form over oceans in warm-temperature regions of the tropics and sub-tropics, while cold air masses tend to form over land in cold-weather regions nearer the poles. The cold air masses that form at the poles move toward the equator, while the warm air masses that form at the equator move toward the poles. These air masses can undergo gradual, but significant, changes as they pass over warmer or colder land surfaces encountering different types of air. These boundary lines are called fronts.
Cold fronts occur when a cold air mass moves into warmer air. Since cold air is heavier than warm air, the incoming colder air forms a wedge that displaces the warm, and often moist, air at the surface. As the warm moist air rises, towering clouds often form releasing energy in the form of brief, intense rain storms with high winds and lightning. On the other hand, warm fronts will ride up and over cold air near the surface. These fronts can also cause clouds and rain, but they tend to be less violent and longer lasting.
Air pressure is determined by how much the air weighs in a given space. Pressure varies with altitude, with denser air residing in lower altitudes and lighter air in higher altitudes. This is caused by the Earth’s gravity—its strength decreases the farther away from the center of the planet, therefore it holds fewer molecules together in the same amount of space. Air pressure is also a function of temperature and density; differences in pressure can be an important weather maker. As air descends, it warms, inhibiting cloud formation which is often associated with good weather. Air rises in areas where the pressure at the surface is low. As it rises, the air cools and the humidity condenses to form clouds and precipitation. The centers of all storms are areas of low pressure; therefore, low pressure is often associated with bad weather.
the highest directly measured frequency is 5.20 x 10^14 Hz, corresponding to one of the transitions in iodine-127. How many wavelengths of electromagnetic waves with this frequency could fit across a dot on a book page? Assume the dot is 2.00 x 10^-4m in diameter.
λ = 5.7 X 10⁻⁷m
On using quantum dot, it is 351
Explanation:
Given-
Frequency, f = 5.20 x 10^14 Hz
Speed of light, c = 3 X 10⁸ m/s
Wavelength, λ = ?
We know,
λ f = c
λ = c / f
λ = [tex]\frac{3 X 10^8}{5.2 X 10^1^4}[/tex]
λ = 5.7 X 10⁻⁷m
Dot = 2 X 10⁻⁴
So,
2 X 10⁻⁴ / 5.7 X 10⁻⁷m = 351
A ray in diamond (n = 2.42) has a critical angle of 41.7 deg when trying to enter benzene. What is the index of refraction in benzene?
Answer: 1.50
Explanation:
Given that:
C (critical angle) = 41.7°
n (index of refraction in benzene) = 2.42
n (index of refraction in benzene) = ?
To get the index of refraction in benzene, Apply the formula n = 1/sineC,
n = 1/sine41.7°
n = 1/sine 41.7°
n = (1/0.6652)
n = 1.50
Thus, the index of refraction for the ray in benzene is 1.50
Answer:
1.61 is the answer
Explanation:
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Which occurrence would lead you to conclude that lights are connected in a
parallel circuit?
O
A. When one bulb burns out, a small section of lights goes out.
O
B. When one bulb burns out, all the other lights stay lit.
O
C. When one bulb burns out, a circuit breaker is tripped.
O
D. When one bulb burns out, all the lights go out.
Answer:
B
Explanation:
When one bulb burns out, all the other lights stay lit.In a parallel circuit, each component is connected to the power source directly.
a swing has a period of 3 seconds. what is it’s frequency?
f = 1/3 swings per second
or
f = 1 swing per 3 seconds
The frequency of a swing with a period of 3 seconds is approximately 0.33 Hz, calculated using the relationship f = 1/T.
The question is asking us to calculate the frequency of a swing given its period. The known period of the swing is 3 seconds. To find the frequency, which is the number of cycles the swing completes in one second, we can use the relationship between period (T) and frequency (f), which is f = 1/T. Thus, for a period of 3 seconds, the frequency is simply f = 1/3 seconds = 0.333... cycles per second, or approximately 0.33 Hz when rounded to two decimal places.
Label the parts of the transverse wave.
Amplitude:
Crest :
Trough:
Wavelength:
Answer:
Amplitude: B
Crest: A
Trough: C:
Wavelength: D
Explanation:
The amplitude of the wave is defined as the distance from the equilibrium position of the wave to its crest or troughs; therefore,
Amplitude: B
The Crest of a wave is its highest point from its equilibrium position; therefore,
Crest: A
The trough of a wave is its lowest point measured from equilibrium position; therefore,
Trough: C
The wavelength of a wave is the distance between two identical points on a wave; therefore,
Wavelength: D.
The parts of a transverse wave are the amplitude, crest, trough, and wavelength.
Explanation:Amplitude: The amplitude of a transverse wave is the maximum displacement of a point on the wave from its equilibrium position. It represents the intensity or strength of the wave. For example, in a water wave, the amplitude would be the height of the wave from the water's surface.
Crest: The crest of a transverse wave is the highest point of the wave above the equilibrium position. It is the point where the displacement is maximum in the upward direction.
Trough: The trough of a transverse wave is the lowest point of the wave below the equilibrium position. It is the point where the displacement is maximum in the downward direction.
Wavelength: The wavelength of a transverse wave is the distance between two consecutive crests or troughs of the wave. It is usually represented by the symbol λ (lambda) and is measured in meters. It determines the spatial extent of the wave.
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NEED ANSWERS ASAPP
Charges of +3 uC and -5 uC are 2 mm from each other.
The-5 uC charge is replaced with a +5 C charge.
How will the electrical force between the charges compare
with the original force?
same force, but in the opposite direction
same force, but in the same direction
greater force, but in the opposite direction
greater force, but in the same direction
Answer:
same force, but in the opposite direction
Explanation:
As we know that the electrostatic force between two charges is given by Coulomb's law of electrostatics
It is given by
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
so here we can say that the initial force between the given charges is
[tex]F = \frac{(9\times 10^9)(3\mu C)(-5\mu C)}{(0.002)^2}[/tex]
nowwe replace the charge -5 uC to another charge which is + 5 uC
so here new force will be
[tex]F = \frac{(9\times 10^9)(3\mu C)(5\mu C)}{(0.002)^2}[/tex]
now from above equation we can say that magnitude of the force will be same only the nature of the force will change as initially two opposite charges were there so they will attract each other while in new position there are two similar charges so they will repel each other
so correct answer will be
same force, but in the opposite direction
Answer:
A. same force, but in the opposite direction
Explanation:
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A plan has a mass of 2000kg and is traveling 100 meters above the ground. What is the planes potential Energy
Answer:
2000000j
Explanation:
m*g*h
2000*100*10
=2000000
describe the relationship between the direction of the velocity vector and the direction of the acceleration for a body moving in a circle at constant speed
The direction of the velocity vector in circular motion at constant speed is tangent to the circle, while the acceleration vector, known as centripetal acceleration, points toward the center of the circle.
Explanation:In the specific scenario of a body moving in a circle at a constant speed, the relationship between the direction of the velocity vector and the direction of the acceleration vector is vital to understand. The velocity vector is always tangent to the circle, which means it is drawn along the direction that the body is moving at any point on the circle. The acceleration vector, on the other hand, points toward the center of the circle; this is known as centripetal acceleration. Thus, while the speed remains constant, the direction of the velocity is continuously changing as the body moves along the circular path, resulting in an acceleration towards the center of that path.
Which of the following best describes what occurs in a fusion reaction?
Answer:
In the process some of the mass of the hydrogen is converted into energy. ... The sun and stars do this by gravity.
Explanation:
a needle 5cm long can just rest on the surface of the water without wetting. what is it's weight? surface tension of the water is 0.07N/m
The weight of the needle = 0.007 N
Explanation:
Step 1 :
Given,
Length of the needle = 5 cm = 5 × [tex]10^{(-2)}[/tex] m
Surface tension of the water =0.07 N/m
We need to find the weight of the needle.
Step 2 :
We have
weight = (surface tension) × 2l
where l is the length of the object
The total contact length between the needle and water is 2 times the length of the needle.
Therefore
weight of the needle = 0.07 × 2 × 5 × [tex]10^{(-2)}[/tex] = 0.007 N
Step 3 :
Answer :
The weight of the needle = 0.007 N
The weight of the needle is 0.0035N
Explanation:In order for a needle to rest on the surface of water without wetting, the force due to the weight of the needle must be balanced by the surface tension of the water. The weight of the needle can be calculated using the formula:
Weight = Mass x Acceleration due to gravity
Given that the length of the needle is 5cm and the surface tension of the water is 0.07N/m, we can find the weight of the needle by converting the length into meters and multiplying by the surface tension.
Weight of the needle = Length x Surface tension = 0.05m x 0.07N/m = 0.0035N.
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Which of the following is not a necessary condition for seeing a magnified image with a
lens?
A. The object and image are on the same side of the lens
B. The lens must be converging
C. The observer must be placed within the focal length
D. The object must be placed within the focal length of the lens
The option stating that the observer must be placed within the focal length is false or not a necessary condition for magnification.
Explanation:
Lens are used for magnification provided the nature of the lens is known and by positioning the object at correct position. So the object should be placed in the focal point of the lens for perfect magnification, it can also be kept within the focal point or focal length. But the object should not be kept beyond the focal length of the lens.
So among the given options, the object and image should be on the same side of the lens for magnification is true. Then the nature of lens should be converging for magnification is also true. And the most important point that the object should be placed within the focal length of the lens is the most mandatory for obtaining magnification. So the option stating that the observer must be placed within the focal length is false or not a necessary condition for magnification.
A book has a mass of 50 grams and an
acceleration of 5 m/s/s. What is the force on
the book?
220 N
20 N
250 N
10 N
The force on the book that has a mass of 50 grams and an acceleration of 5 m/s² is 250N.
How to calculate force?The force of an object can be calculated by multiplying the mass by its acceleration as follows:
Force = mass × acceleration
According to this question, a book has a mass of 50 grams and an acceleration of 5 m/s². The force is as follows:
Force = 50 × 5
Force = 250N
Therefore, the force on the book that has a mass of 50 grams and an acceleration of 5 m/s² is 250N.
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The correct force on the book is 2.5 N.
To find the force on the book, we can use Newton's second law of motion, which states that force is equal to mass times acceleration (F = m × a).
Given:
- The mass of the book (m) is 50 grams. To convert grams to kilograms (since the standard unit of mass in the SI system is kilograms), we divide by 1000. Thus, m = 50 / 1000 kg = 0.05 kg.
- The acceleration (a) of the book is 5 m/s².
Using Newton's second law, we calculate the force (F) as follows:
F = m × a
F = 0.05 kg × 5 m/s²
F = 0.25 kg × m/s²
Since 1 Newton is equal to 1 kgm/s², the force on the book is 0.25 Newtons, or 2.5 N.
Therefore, the correct answer is 2.5 N, which is not listed in the given options. It seems there was a typo in the provided options, as the correct calculation does not result in any of the listed forces. The closest option to the correct answer is 20 N, but it is still incorrect. The correct force is 2.5 N.
Of the following telescopes, which one would best be able to pierce through the Earth's atmosphere and function on the surface of the Earth?
Answer:
D
Explanation:
The Earth's atmosphere interferes with radio waves less than any other wavelength, so the best kind of telescope to build on the Earth's surface would be a radio telescope. Although visible light telescopes are often built on Earth, they are usually put as high up as possible, such as on mountaintops, where there is less atmosphere to get in their way. Radio telescopes are usually put as far down as possible, such as in valleys, to block out human-generated radio signals coming from other parts of the surface of the Earth.
The telescope that would best be able to pierce through the Earth's atmosphere and function on the surface of the Earth is radio telescope. The correct option is A.
What is radio telescope?Radio telescopes detect and amplify radio waves from space, converting them into signals that astronomers can use to learn more about the Universe.
Because the Earth's atmosphere interferes with radio waves less than with other wavelengths, a radio telescope would be the best type of telescope to build on the Earth's surface.
Although visible light telescopes are frequently built on Earth, they are typically placed as high up as possible, such as on mountaintops, where there is less atmospheric interference.
Radio telescopes are typically placed as low as possible, such as in valleys, to block out human-generated radio signals from other parts of the Earth's surface.
Thus, the correct option is A.
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Your question seems incomplete, the missing options are:
A. an x-ray telescope
B. an infrared telescope
C. a radio telescope
D. a visible-light telescope
PLEASE HELP
Please explain to me what longitudinal and transverse wave are!
Answer:
In a transverse wave the particles of the medium move perpendicular to the wave's direction of travel.
In a longitudinal wave, the particles of the medium move parallel to the wave's direction of travel.
How does increasing the wavelength by 50 percent affect the frequency of a wave on a rope?
Answer:
It decreases the frequency by 33.33%
Explanation:
The frequency of a wave is given by the division between its velocity and its wavelength:
f = v/L, where f is the frequency in hertz, v is the velocity in m/s, and L is the wavelength in meter
If we increase the wavelength by 50 percent, we have that L' = 1.5*L (L' is the new wavelength)
Keeping the same velocity, we have the new frequency (f') as:
f' = v/L' = v/1.5*L = (1/1.5)*v/L = 0.6667*f
The new frequency is 66.67% of the old frequency, that is, the old frequency decreased 33.33%.
So, increasing the wavelength by 50% decreases the frequency by 33.33% or 1/3
Increasing the wavelength by 50 percent reduces the frequency of a wave by half.
Explanation:Increasing the wavelength by 50 percent affects the frequency of a wave on a rope by reducing the frequency by half. The wavelength and frequency of a wave are inversely proportional, meaning that as the wavelength increases, the frequency decreases and vice versa. This relationship is represented by the equation: frequency = speed / wavelength.
For example, let's say the original wavelength of a wave on a rope is 2 meters and the frequency is 10 Hz. If we increase the wavelength by 50 percent, it becomes 3 meters. Using the equation, the new frequency would be: frequency = speed / 3 meters = 10 Hz / 3 = 3.33 Hz.
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You lift a large bag of flour from the floor to a 2.5m high counter, doing 400J of work in 2 seconds. How much force did you apply?
Explanation:
The work done to lift the bag of weight mg through height 2.5 m is 400 J
The work done can be found by relation W = mg x h
Thus mg = [tex]\frac{W}{h}[/tex] = [tex]\frac{400}{2.5}[/tex] = 160 N
Therefore the man have to apply the force of 160 N
Answer:160newtons
Explanation:
Work=400J
Distance=2.5m
Time=2 seconds
Force=?
Force=work/distance
Force=400/2.5
Force=160
Force=160 newtons
Which feature forms at this plate boundary?
There are three plate boundaries: Constructive, Destructive and transform plate boundary. At constructive plate boundary mountains form, at destructive plate boundaries earthquake and volcanism occurs and at transform boundary faults occur.
Explanation:
Plates are solid and rigid mass. It mainly floats over asthenosphere which is a part of upper mantle. There are seven major plates and twenty minor plates. The zone between two plates are known as plate boundary and the edge of a plate is known as plate margin.
There are three plate boundaries: Conservative, destructive and transform plate boundary. Where two plates collide with each other known as destructive plate boundary and where two plates move in opposite direction from each other known as constructive plate boundary. Where two plates slide each other called transform fault.
Answer:
Volcanoes are one kind of feature that forms along convergent plate boundaries, where two tectonic plates collide and one moves beneath the other.
Explanation:
A boy ties a stone to the end of a string which he then whirles above his head round a circular path of radius 15cm. if the stone makes 20 oscillations in 10 seconds calculate the angular and linear speeds of the stone.
Answer:
W = 12.568rads
V = 1.8852m/s
Explanation:
Data:
r = 15cm = 0.15m
t = 10s
Revolutions = 20
Frequency (F) = number revolutions/ time take complete it
F = 20 / 10 = 2Hz
Angular velocity (w) = 2 * 3.142 * F
Note: 3.142 = value of pi
W = 2*3.142*2 = 12.568 rads
Linear velocity (v) = w*r
V = 12.568*0.15 = 1.8852m/s
A 7.0kg skydiver is descending with a constant velocity
Answer:
Air resistance: 68.6 N
Explanation:
For the skydiver falling down, there are two forces acting on him:
- The force of gravity, of magnitude
[tex]W=mg[/tex]
where
m = 7.0 kg is the mass of the skydiver
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
This force acts in the downward direction
- The air resistance, R, in the upward direction
So the net force on the skydiver is:
[tex]\sum F=mg-R[/tex]
According to Newton's second law of motion, the net force is also equal to mass times acceleration:
[tex]\sum F=ma[/tex]
However, in this problem the skydiver is falling at constant velocity, so his acceleration is zero:
[tex]a=0[/tex]
Therefore, the net force is zero:
[tex]\sum F=0[/tex]
And so we can find the magnitude of the air resistance, which is equal to the weigth of the skydiver:
[tex]mg-R=0\\R=mg=(7.0)(9.8)=68.6 N[/tex]
This question involves the physics concept of terminal velocity. It's the constant speed a skydiver descends when the force of gravity equals the upward force of air resistance.
Explanation:The subject of this question involves a concept in physics known as terminal velocity. When a skydiver jumps out of a plane, gravity pulls them downwards, while air resistance pushes upwards. As the skydiver falls faster, air resistance increases until it is equal to the pull of gravity. At this point, the skydiver no longer accelerates and falls at a constant velocity. This is the terminal velocity. In this particular case, the fact that the 7.0kg skydiver is descending at a constant velocity tells us that he has reached his terminal velocity.
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20 POINTS!!!!!!!!
An electromagnet is a temporary magnet made by coiling wire around an iron core which becomes a magnet when an electric current flows through the wire.
How could the strength of an electromagnet be increased?
A) Use fewer coils of wire around the nail.
B) Use more coils of wire around the nail.
C) Use a battery with less voltage.
D) Use a smaller nail.
USE MORE COILS OF WIRE AROUND THE NAIL
Explanation:
To increase the strength of an electromagnet, the following strategy is adopted in order to have better efficiency.
The best method which suits for increasing the strength of electromagnet is to increase the number of turns around the nail.
If we increase the number of turns up to a specific value the magnetizing property of magnet is enhanced. So that to increase the strength , add more number of turns to the existing turns of coil.
A box sliding down a hill going 3m/s accelerates at 2m/s2. How fast is going 4 seconds?
Final answer:
The box sliding down the hill with an initial velocity of 3 m/s and accelerating at 2 m/s² will be going 11 m/s after 4 seconds.
Explanation:
The question involves a box sliding down a hill with an initial velocity of 3 m/s, which then accelerates at 2 m/s². To find out how fast the box will be going after 4 seconds, we apply the kinematic equation:
v = u + at,
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Plugging in the values, we get:
v = 3 m/s + (2 m/s² * 4 s) = 3 m/s + 8 m/s = 11 m/s.
The box will be going 11 m/s after 4 seconds.
A current of 1.41 A in a long, straight wire produces a magnetic field of 5.61 uT at a certain distance from the wire. Find
this distance.
Answer:
0.050 m
Explanation:
The strength of the magnetic field produced by a current-carrying wire is given by
[tex]B=\frac{\mu_0 I}{2\pi r}[/tex]
where
[tex]\mu_0=4\pi \cdot 10^{-7} H/m[/tex] is the vacuum permeability
I is the current in the wire
r is the distance from the wire
And the magnetic field around the wire forms concentric circles, and it is tangential to the circles.
In this problem, we have:
[tex]I=1.41 A[/tex] (current in the wire)
[tex]B=5.61\mu T=5.61\cdot 10^{-6} T[/tex] (strength of magnetic field)
Solving for r, we find the distance from the wire:
[tex]r=\frac{\mu_0 I}{2\pi B}=\frac{(4\pi \cdot 10^{-7})(1.41)}{2\pi (5.61\cdot 10^{-6})}=0.050 m[/tex]
1. As telescopes improve, astronomers are able to detect planets orbiting other stars. One such planet orbits its star at a distance of 2.897 x 109 km. (This is far enough from the star that radius of the star can be ignored.) The star has 1.9 times the mass of our sun (msun = 2 x 1030 kg). If the planet has a mass of 5.4 x 1027 kg, what is the force of gravity it experiences
Answer:
The planet will experience a force of [tex]1.72*10^{23}N[/tex]
Explanation:
The force of gravity [tex]F[/tex] experienced by the planet is of mass [tex]m[/tex] at a distance [tex]R[/tex] from a star of mass [tex]M[/tex] is given by
[tex]F = G\dfrac{mM}{R^2},[/tex]
where [tex]G= 6.7*10^{-11}Nm^2 /kg^2[/tex] is the gravitational constant.
The mass of the star is two times that of the sun:
[tex]M = 2*M_{sun} = 2*(2* 10^{30}kg) = 4*10^{30}kg[/tex],
the mass [tex]m[/tex] of the planet is
[tex]m = 5.4*10^{27}kg[/tex],
the distance [tex]R[/tex] of the planet form the star is
[tex]R =2.897*10^9km = 2.897*10^{12} m[/tex];
therefore, the force of gravity on the planet will be
[tex]F = (6.7*10^{-11})\dfrac{(5.4*10^{27}kg)(4*10^{30}kg)}{(2.897*10^{12}m)^2}[/tex]
[tex]\boxed{F = 1.72*10^{23}N }[/tex]
which is the force that the planet will experience.
is is false or true The closer objects are, the stronger the gravitational force between them.
Answer:
TRUE
Explanation:
The gravitational force between two objects becomes weaker if the two objects are moved apart and stronger if they are brought closer together; that is, the force depends on the distance between the objects
In this example, the bottle, made of plastic, has solid matter that allows for conduction of heat. What happens if in between the juice and the ice water there are no molecules? (Hint, think Yeti)
Answer:
Conduction of heat would not happen.Explanation:
Heat transfer by conduction only happens by direct contact of the molecules or atoms of a substance: in a solid, particles cannot travel but only vibrate; the heat conduction happens because the vibration of a particle causes adjacent particles to vibrate.
Also, in that system heat transfer by convection would not happen, since convection requires that the particles travel to transfer the heat.
Only heat transfer by radiation can happen when there are no particles, since infrared radiation travels through the empty space.
an astronaut weighs 199 lb. what is his weight in newtons?
1 lb = 4.45 Newtons (rounded)
199 lbs = approx 885 Newtons
how does friction affect the motion of an object
Answer:
#See solution for details.
Explanation:
-Friction is the force exerted on an object moving against it.
-Friction acts in the opposite direction to the object's motion.
-As such, friction reduces the motion of an object. The object is usually slowed down. The resultant motion of the object is less than the force applied on it.
What is the ability to complete extended periods of physical activity?
Which forms of energy are involved when you turn on a desk lamp and the bulb becomes hot?
Answer:
Electric energy moves through the wire to the lamp's bulb. In the bulb's filament, electric energy transforms into thermal energy and light energy.
Explanation:
what has to happen for a feather and ball to fall at the same time