To which layer can geologists apply the principle of faunal succession to determine the age of the layer?

A. Layer C
B. Layer A
C. Layer D
D. Layer B

To Which Layer Can Geologists Apply The Principle Of Faunal Succession To Determine The Age Of The Layer?

Answers

Answer 1
This question looks familiar. Maybe layer A?
Answer 2

Answer:

Layer C

Explanation:

The Principle of faunal succession also is the study of fossils

Their for making the answer A


Related Questions

Micah knows that a car had a change in velocity of 15 m/s. To determine acceleration, Micah also needs the_______________

of the total trip in seconds.

Answers

Answer:

Duration of the total trip

Explanation:

Acceleration is defined as the rate of change of velocity of an object:

[tex]a=\frac{\Delta v}{\Delta t}[/tex]

where

[tex]\Delta v[/tex] is the change in velocity

[tex]\Delta t[/tex] is the duration of the change in velocity

Acceleration is measured in meters per squared seconds, [tex]m/s^2[/tex]. Also, we should note that acceleration is a vector quantity, so in order to completely define acceleration we also need to specify the direction.

Answer: Time

Explanation: Took the test and got it right! :)

How do you increase capacitance in a capacitor?

Answers

If you want to increase the Capacitance of Parallele Plate Capacitor then increase the surface area, reduce the separation between the plate and use a dielectric material in between the plate which have higher dielectric breakdown strength.

The amplitude of a system moving in simple harmonic motion is doubled. Determine by what factor the following change.
(a) the total energy
(b) the maximum speed
(c) the maximum acceleration
(d) the period

Answers

(a) The total energy increases by a factor 4

The total energy of a simple harmonic system is given by:

[tex]E=\frac{1}{2}kA^2[/tex]

where

k is the spring constant

A is the amplitude of the motion

In this part of the problem, the amplitude is doubled:

A' = 2A

So the new total energy is

[tex]E=\frac{1}{2}k(A')^2=\frac{1}{2}k(2A)^2=4(\frac{1}{2}kA^2)=4E[/tex]

So, the energy quadruples.

(b) The maximum speed increases by a factor 2

The maximum speed in a simple harmonic motion is given by

[tex]v=\omega A[/tex]

where

[tex]\omega=\sqrt{\frac{k}{m}}[/tex] is the angular frequency, with k being the spring constant and m the mass

A is the amplitude

In this part of the problem, k and m do not change, so the angular frequency does not change. Instead, the amplitude is doubled:

A' = 2A

So the new maximum speed is

[tex]v'=\omega (A')=\omega (2A)=2 (\omega A)=2 v[/tex]

so, the maximum speed doubles.

(c) The maximum acceleration increases by a factor 2

The maximum acceleration in a simple harmonic motion is given by

[tex]a=\omega^2 A[/tex]

where

[tex]\omega=\sqrt{\frac{k}{m}}[/tex] is the angular frequency, with k being the spring constant and m the mass

A is the amplitude

In this part of the problem, k and m do not change, so the angular frequency does not change. Instead, the amplitude is doubled:

A' = 2A

So the new maximum acceleration is

[tex]a'=\omega^2 (A')=\omega^2 (2A)=2 (\omega^2 A)=2 a[/tex]

so, the maximum acceleration doubles.

(d) The period does not change

The period in a simple harmonic motion is given by

[tex]T=2\pi \sqrt{\frac{m}{k}}[/tex]

where m is the mass and k is the spring constant.

In this problem, the amplitude is doubled:

A' = 2A

However, we notice that the period does not depend on the amplitude, and since both m and k do not change, then the period will remain constant.

Final answer:

Doubling the amplitude in simple harmonic motion quadruples the total energy, doubles both the maximum speed and maximum acceleration, while the period remains unchanged. If the spring constant is doubled, the mass must be doubled to keep the same frequency.

Explanation:

Impact of Doubling the Amplitude on Simple Harmonic Motion

When the amplitude A of a system undergoing simple harmonic motion (SHM) is doubled, the following changes occur:

(a) Total energy of the system, which includes both kinetic and potential energy, is proportional to the square of the amplitude. Therefore, doubling the amplitude results in quadrupling the total energy (a factor of 4).

(b) Maximum speed (Vmax) of the system in SHM is directly proportional to the amplitude. As a result, doubling the amplitude doubles the maximum speed (a factor of 2).

(c) Maximum acceleration is also directly proportional to the amplitude. By doubling the amplitude, the maximum acceleration is also doubled (a factor of 2).

(d) The period of oscillation (T) is independent of the amplitude and will remain unchanged.

If the spring constant (k) of a simple harmonic oscillator is doubled, the mass (m) of the system needs to be doubled as well, in order to maintain the same frequency of motion, based on the formula for the frequency f = 1/(2π√(m/k)).

What would happen to the two balls if one of them were kept positively charged and the charge on the other ball were slowly increased, making it more and more positive?

Answers

Final answer:

Two positively charged balls will repel with greater force as the charge on one of them is increased. Grounding the second ball would cause it to lose its charge, making both balls positively charged after the process, with reduced repulsion between them.

Explanation:

When one ball is kept positively charged and the charge on the other ball is increased, making it more positive, the two balls will repel each other with greater force. This phenomenon is due to Coulomb's Law, which states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

If the second ball, which is also positively charged, is momentarily grounded while a negatively charged rod is nearby, it would lose its negative charge to the ground. This is because grounding provides a path for the charge to dissipate into the Earth, effectively neutralizing the charged object. After being ungrounded, if the negatively charged rod is still present, the second ball will have a positive charge due to the removal of its excess electrons. Therefore, both balls would end up with a positive charge, but the magnitude of the charge on the second ball would be reduced by the grounding process, potentially changing the dynamics of their interaction.

The charge on the first ball will remain positive throughout this process, as the presence of the negatively charged rod induces the transfer of electrons from the first ball to the second ball when they are in contact, leaving the first ball positively charged.

Astronomers use the _______ of stars to determine how hot they are and their _______ to estimate how far away they are. A. brightness; size B. temperature; position C. size; temperature D. color; brightness

Answers

Answer:

color; brightness

Explanation:

Astronomers use the color of stars to determine how hot they are and their brightness to estimate how far away they are.

Astronomers use the color of stars to determine how hot they are and their brightness to estimate how far away they are.

Who are astronomer?

A scientist who concentrates their research on a particular issue or area outside the purview of Earth is called an astronomer in the science of astronomy.

They perform observational (by evaluating the data) or theoretical astronomy when observing astronomical objects including stars, planets, moons, comets, and galaxies.

Planetary science, solar astronomy, the creation or evolution of stars, or the formation of galaxies are a few examples of subjects or domains that astronomers investigate.

Therefore, Astronomers use the color of stars to determine how hot they are and their brightness to estimate how far away they are.

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Explain the difference in how current flows through two light bulbs connected in series circuit and in two light bulbs connected in parallel circuit.

Answers

Current flow in light bulbs varies between series and parallel circuits; in a series, the current is consistent but the voltage is divided, while in parallel, each bulb receives the full voltage with the total current being split among them.

When two light bulbs are connected in a series circuit, the current flows through the first light bulb and then into the second. This means that the same current flows through both bulbs. However, the voltage across each bulb is divided, which may result in both bulbs being dimmer than if they were connected separately to a voltage source. Thus, in a series circuit with a single battery source, two light bulbs would appear half as bright compared to if they were connected individually to the battery.

In contrast, two light bulbs connected in a parallel circuit have the same voltage applied to them as the source voltage. This is because each bulb is connected directly to the power supply on its own parallel path. Therefore, each light bulb receives the full voltage from the source and they will shine as bright as they would individually. However, the current drawn from the source is divided between the bulbs, with each having its separate current flow. This parallel arrangement will cause the battery to drain more quickly as it is supplying full energy to both bulbs concurrently.

Using the analogy of water flowing through hoses, a series circuit is akin to water traveling through a single hose where the current (amount of water) remains constant, whereas a parallel circuit is like having multiple hoses with the same pressure (voltage) applied, causing more water (current) to flow overall.

Two physics question need quick help

Answers

Answer:

2.14 kW, I₂ < I₁

Explanation:

The three resistors are in parallel.  The net resistance is:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/20 + 1/8 + 1/500

1/R = 0.177

R = 5.65

The power is:

P = IV

P = (V/R) V

P = V²/R

P = (110)² / 5.65

P = 2140 W

P = 2.14 kW

For two resistors in parallel, the one with the higher resistance has the smaller current.  I₂ < I₁.

Calculate the number of moles of oxygen in a 12.5-l tank if the pressure is 25325 kpa and the temperature is 22°c

Answers

Answer:

= 129.06 moles

Explanation:

Using the ideal gas equation;

PV = nRT

Where; P is the pressure, V is the volumes, n is the number of moles, R is the ideal gas constant and T is the temperature.

In this case; V = 12.5 L, P = 25325 kpa or 249.94 atm, T = 22 + 273 = 295 K and R= 0.08206L atm/mol K

n = PV/RT

 = (12.5 × 249.94)/(0.08206 × 295)

 = 129.06 moles

A long, slender structural steel [E = 29,000 ksi] HSS8 x 4 x 1/4 shape (see Appendix B for its cross-sectional properties) is used as a L = 43.50-ft-long column. The column is supported in the x direction at base A and pinned at ends A and C against translation in the y and z directions. Lateral support is provided to the column so that deflection in the x–z plane is restrained at mid-height B; however, the column is free to deflect in the x–y plane at B. Determine the maximum compressive load that the column can support if a factor of safety of 1.90 is required. In your analysis, consider the possibility that buckling could occur about either the strong axis (i.e., the z axis) or the weak axis (i.e., the y axis) of the steel column.

Answers

Answer:44(,5 v

Explanation:

Ggthnu

Diffraction and interference demonstrate which concept?
A) particle nature of light
B) wave nature of light
C) polarization of light
D) refraction of light

Answers

Answer: B) wave nature of light

The velocity of an object is equal to the distance divided by time. The equation is velocity = distance/time. If you wanted to calculate the TIME required for an object to travel a distance and you knew the velocity, you would A) multiply: velocity X distance. B) subtract: velocity – distance. C) divide: distance ÷ velocity D) add: velocity + distance

Answers

Answer: C) divide: distance ÷ velocity

Explanation:

The velocity [tex]V[/tex] equation is distance [tex]d[/tex] divided by time [tex]t[/tex]:

[tex]V=\frac{d}{t}[/tex]

If we isolate [tex]t[/tex] we will have:

[tex]t=\frac{d}{V}[/tex]

Hence, the correct option is C: distance divided by velocity.

Is it possible for one sound wave to cancel another?

Answers

yes it is just like a sonar ping can cancel another ping it works the same way as a normal soundwave

hope this helps you

As more resistors are added in parallel across a constant voltage source, the power supplied by the source as more resistors are added in parallel across a constant voltage source, the power supplied by the source increases for a time and then starts to decrease. increases. decreases. does not change.

Answers

Answer:

increases

Explanation:

In a circuit, the power supplied by the source is given by:

[tex]P=VI[/tex] (1)

where V is the voltage of the source and I is the current in the circuit.

Using Ohm's law, we can rewrite the current as:

[tex]I=\frac{V}{R}[/tex]

where R is the equivalent resistance of the circuit. Substituting into (1), we can rewrite the power as

[tex]P= \frac{V^2}{R}[/tex] (2)

so we see that the power is inversely proportional to the resistance.

For resistors added in parallel, the equivalent resistance is given by the formula

[tex]\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_n}[/tex]

so we see that when adding new resistors in parallel, the term [tex]\frac{1}{R}[/tex] increases, so the equivalent resistance R will decreases. As a result, the power supplied by the source (given by eq.(2)) wil increase.

As more resistors are added in parallel across a constant voltage source the power will; increase

Formula for Poweer across a circuit with constant voltage is;

P = I²R

Where;

P is Power I is currentR is resistance

Now, when resistors are connected in parallel, the total resistance is usually;

1/R = 1/R1 + 1/R2 + 1/R3....

Where R is total resistance.

This means that the more resistors you add in parallel, the greater the value of R.

Thus, from the Power equation, when R increases, then P will also increase.

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Describe the direction of the electric force between two opposite charges, between two like charges, and when a charge is in an electric field.

Answers

- Two opposite charges:

The electrostatic force between two opposite charges is attractive. This means that if we have a positive charge and a negative charge, the electrostatic force between them is attractive.

- Two like charges:

The electrostatic force between two like charges is repulsive. This means that if we have two positive charges, or two negative charges, the force exerted by one charge on the other one is repulsive.

- A charge in an electric field:

The direction of the electric force on a charge in an electric field depends on the sign of the charge. In fact, we have

[tex]F=qE[/tex]

where F is the electric force, q is the charge, and E the electric field. We have the two following situations:

- If the charge is positive, q > 0, then the electric force has the same direction as the electric field (so the charge will be accelerated in the same direction as the electric field)

- If the charge is negative, q < 0, then the electric force has opposite direction to the electric field (so the charge will be accelerated in the opposite direction to the electric field)

Final answer:

Like charges repel each other and unlike charges attract each other. The direction of the force when a charge is placed in an electric field depends on whether the charge is positive (same direction as the field) or negative (opposite direction as the field).

Explanation:

The electric force that exists between two charges can be determined by their nature. If the charges are similar, that is, both are either positive or negative, then the direction of the electric force will be repulsive, and they push each other away. The electric field lines in this case would emanate away from the charges.

On the other hand, if the charges are dissimilar (that is, one positive and one negative), then the direction of the electric force is attractive—they pull towards each other. The electric field lines in this case would point from the positive charge towards the negative one.

When a charge is placed in an electric field, the direction of the force it experiences depends on its nature. If the charge is positive, it will experience a force in the direction of the field. If it's negative, the force will be in the opposite direction to the field.

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Two charged objects separated by some distance attract each other. If the charges on both objects are doubled with no change in distance between them, what happens to the magnitude of the force between the objects?

a. the force between them quadruples
b. the between them doubles
c. the between them is halved
d. the force between them is quartered
e. the force between them is unchanged

Answers

Answer:

a. the force between them quadruples

Explanation:

The electrostatic force between two charges is given by

[tex]F=k\frac{q_1 q_2}{r^2}[/tex]

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two charges

In this problem, the charges on both objects are doubled, so

[tex]q_1' = 2q_1\\q_2' = 2q_2[/tex]

While the distance does not change, so the new force will be

[tex]F'= k \frac{(2q_1)(2q_2)}{r^2}=4 (k\frac{q_1 q_2}{r^2})=4 F[/tex]

so, the force will quadruple.

Consider an object with s=12cm that produces an image with s′=15cm. Note that whenever you are working with a physical object, the object distance will be positive (in multiple optics setups, you will encounter "objects" that are actually images, but that is not a possibility in this problem). A positive image distance means that the image is formed on the side of the lens from which the light emerges.Part AFind the focal length of the lens that produces the image described in the problem introduction using the thin lens equation.Express your answer in centimeters, as a fraction or to three significant figures.f = 6.67 cm SubmitMy AnswersGive UpCorrectPart BConsidering the sign of f, is the lens converging or diverging?Considering the sign of , is the lens converging or diverging?convergingdivergingSubmitMy AnswersGive UpCorrectPart CWhat is the magnification m of the lens?Express your answer as a fraction or to three significant figures.m = -1.25SubmitMy AnswersGive UpCorrectPart DThink about the sign of s′ and the sign of y′, which you can find from the magnification equation, knowing that a physical object is always considered upright. Which of the following describes the nature and orientation of the image?Think about the sign of and the sign of , which you can find from the magnification equation, knowing that a physical object is always considered upright. Which of the following describes the nature and orientation of the image?real and uprightreal and invertedvirtual and uprightvirtual and invertedSubmitMy AnswersGive UpCorrectNow consider a diverging lens with focal length f=−15cm, producing an upright image that is 5/9 as tall as the object.Part EIs the image real or virtual? Think about the magnification and how it relates to the sign of s′.Is the image real or virtual? Think about the magnification and how it relates to the sign of .realvirtualSubmitMy AnswersGive UpCorrectPart FWhat is the object distance? You will need to use the magnification equation to find a relationship between sand s′. Then substitute into the thin lens equation to solve for s.Express your answer in centimeters, as a fraction or to three significant figures.s = 12.0 cm SubmitMy AnswersGive UpCorrectPart GWhat is the image distance?Express your answer in centimeters, as a fraction or to three significant figures.s′ = 24 cm SubmitMy AnswersGive UpIncorrect; Try Again; 12 attempts remaining; no points deductedA lens placed at the origin with its axis pointing along the x axis produces a real inverted image at x=−24cmthat is twice as tall as the object.Part HWhat is the image distance?Express your answer in centimeters, as a fraction or to three significant figures.s′ = 24.0 cm

Answers

A. 6.67 cm

The focal length of the lens can be found by using the lens equation:

[tex]\frac{1}{f}=\frac{1}{s}+\frac{1}{s'}[/tex]

where we have

f = focal length

s = 12 cm is the distance of the object from the lens

s' = 15 cm is the distance of the image from the lens

Solving the equation for f, we find

[tex]\frac{1}{f}=\frac{1}{12 cm}+\frac{1}{15 cm}=0.15 cm^{-1}\\f=\frac{1}{0.15 cm^{-1}}=6.67 cm[/tex]

B. Converging

According to sign convention for lenses, we have:

- Converging (convex) lenses have focal length with positive sign

- Diverging (concave) lenses have focal length with negative sign

In this case, the focal length of the lens is positive, so the lens is a converging lens.

C. -1.25

The magnification of the lens is given by

[tex]M=-\frac{s'}{s}[/tex]

where

s' = 15 cm is the distance of the image from the lens

s = 12 cm is the distance of the object from the lens

Substituting into the equation, we find

[tex]M=-\frac{15 cm}{12 cm}=-1.25[/tex]

D. Real and inverted

The magnification equation can be also rewritten as

[tex]M=\frac{y'}{y}[/tex]

where

y' is the size of the image

y is the size of the object

Re-arranging it, we have

[tex]y'=My[/tex]

Since in this case M is negative, it means that y' has opposite sign compared to y: this means that the image is inverted.

Also, the sign of s' tells us if the image is real of virtual. In fact:

- s' is positive: image is real

- s' is negative: image is virtual

In this case, s' is positive, so the image is real.

E. Virtual

In this case, the magnification is 5/9, so we have

[tex]M=\frac{5}{9}=-\frac{s'}{s}[/tex]

which can be rewritten as

[tex]s'=-M s = -\frac{5}{9}s[/tex]

which means that s' has opposite sign than s: therefore, the image is virtual.

F. 12.0 cm

From the magnification equation, we can write

[tex]s'=-Ms[/tex]

and then we can substitute it into the lens equation:

[tex]\frac{1}{f}=\frac{1}{s}+\frac{1}{s'}\\\frac{1}{f}=\frac{1}{s}+\frac{1}{-Ms}[/tex]

and we can solve for s:

[tex]\frac{1}{f}=\frac{M-1}{Ms}\\f=\frac{Ms}{M-1}\\s=\frac{f(M-1)}{M}=\frac{(-15 cm)(\frac{5}{9}-1}{\frac{5}{9}}=12.0 cm[/tex]

G. -6.67 cm

Now the image distance can be directly found by using again the magnification equation:

[tex]s'=-Ms=-\frac{5}{9}(12.0 cm)=-6.67 cm[/tex]

And the sign of s' (negative) also tells us that the image is virtual.

H. -24.0 cm

In this case, the image is twice as tall as the object, so the magnification is

M = 2

and the distance of the image from the lens is

s' = -24 cm

The problem is asking us for the image distance: however, this is already given by the problem,

s' = -24 cm

so, this is the answer. And the fact that its sign is negative tells us that the image is virtual.

The correct answers to the questions are:

A. 6.67 cmB. ConvergingC. -1.25D. Real and invertedE. VirtualF. 12.0 cmG. -6.67 cmH. -24.0 cm

Calculations

To find the image distance for the question in question G is by the use of the magnification equation which is:

s1= -Ms

=> -5/9(12cm)

=>  -6.67cm.

Because the value is negative, we know that the image is virtual.

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What causes the radio pulses of a pulsar?

a. The star vibrates.
b. As the star spins, beams of radio radiation from it sweep through space. If one of these beams points toward the Earth, we observe a pulse.
c. The star undergoes nuclear explosions that generate radio emission.
d. The star's dark orbiting companion periodically eclipses the radio waves emitted by the main star.
e. A black hole near the star absorbs energy from it and re-emits it as radio pulses.

Answers

Answer: As the star spins, beams of radio radiation from it sweep through space. If one of these beams points toward the Earth, we observe a pulse.

A pulsar (pulsating star)   is a neutron star that emits very intense jets of electromagnetic radiation in the range of radio waves, X-rays or gamma rays, at short and periodic intervals due to its intense magnetic field that induces this emission.

This jet is "observable" on Earth, when the magnetic pole of the star "points" to our planet and then stops pointing a thousandth of a second later due to the fast rotation of the star, appearing again when the same pole returns to point towards Earth.

Then, what is observed in the terrestrial sky are pulses of radiation with a very exact period, which are repeated again and again.

Final answer:

The radio pulses of a pulsar are produced due to its spinning action. As the star spins, it emits beams of radio radiation that sweep through space. We observe these as pulses when they point towards Earth.

Explanation:

The radio pulses of a pulsar are produced by the spinning of the star. As the star spins, it emits beams of radio radiation that sweep through space. If one of these beams points toward Earth, we observe it as a pulse.

The other options provided are not the reasons behind the radio pulses of a pulsar. These radio pulses are not due to the star vibrating or undergoing nuclear explosions. Similarly, it's not the star's dark orbiting companion periodically eclipsing the radio waves nor a black hole near the star absorbing energy and re-emitting it as radio pulses.

So, the correct answer to this question is option (b): As the star spins, beams of radio radiation from it sweep through space. If one of these beams points toward Earth, we observe a pulse.

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Steve is whirling a rubber cork, tied with a string to his finger, over his head as shown in the figure. The motion of the cork is similar to the motion of a planet in the solar system around the sun. Which force in the solar system is similar to the tension in the string?

Answers

The tension in the string corresponds to the gravitational attraction between the Sun and any planet.

Answer:

Gravitational Force.

Explanation:

While Steve is whirling a rubber cork, it developes a situation which is similar to the Solar System. In the rubber cork movement, there's "circular" motion which is possible thanks to the string, that is, the string works as "attraction force", allowing the system to maintain its movement.

Now, in the Solar System, the graviational force is like the string, it's the physical magnitude that maintains planets on their movements, attached to the Sun someway.

Work is only being done when what happens to an object?

A) the object does not move

B) the object disappears without explanation

C) it moves in the same direction as the force

D) The object moves in the opposite direction of the force

Ik it's not A or B

Answers

Answer:

C) it moves in the same direction as the force  

D) The object moves in the opposite direction of the force

Explanation:

As we know by work energy theorem that when work is done on the system of mass then

[tex]W_{net} = KE_f - KE_i[/tex]

now as per the definition of work done we know that

[tex]W = F.d[/tex]

[tex]W = Fdcos\theta[/tex]

so here we will say that when force is applied in the direction of the displacement of the object then it is always positive work and if work is applied in the opposite direction of the displacement of object then it is always negative work.

So here when force is applied then the point of application must move either in the direction of force or in the opposite direction of the force.

so correct answer will be

C) it moves in the same direction as the force  

D) The object moves in the opposite direction of the force

1. All of the following would employee ocean engineers EXCEPT?
A. The military
B. Coastal Regions
C. Weather services
D. Scuba gear companies

2. Agriculture is to grain as aquaculture is to
A. Science
B. Seaweed
C. Fish Food
D. Aqueduct

3. How did American captain William Anderson eliminate the problem of ice packs when exploring the arctic?
A. He designed the ship to melt the ice
B. He went under the ice packs with a submarine
C. He developed a particularity narrow ship
D. He went when temperatures were warmer

4. The first echo sounder was used in a German submarine
True or False

5. Supporting all stakeholders means that?
A. Any solution benefits for all stakeholders equally
B. The solution favors human needs over environmental
C. One stakeholder is supported by the expense of the others
D. All needs are taken into account and solutions are designed to consider them all

6. ROVs can play an important role in managing man made disasters in the ocean
True or False

7. One of the biggest challenges in exploring polar regions is
A. Ice packs
B. Hurricanes
C. Polar bears and walruses
D. Lack of latitude and longitude

8. Regardless of the scientific question being asked, scientific research will include all of the following EXCEPT?
A. Use of the scientific method
B. A single approach in every situation
C. Exploration of work by previous scientists
D. Sharing results with the scientific community

9. Chemical oceanographers often study pollution because
A. Most pollution occurs in the ocean
B. Pollution creates chemical changes
C. No other field examines the implications of pollution
D. Only chemical oceanography uses the scientific method

10. Which of the following is a pinniped?
A. Walrus
B. Penguin
C. Arctic fox
D. Polar bear

11. The national oceanic and Atmospheric administration use to buoys to monitor
A. Ship traffic
B. Weather patterns via satellite
C. Movement of tectonic plates
D. Water conditions around coral reefs

12. Most marine science jobs that involve conducting research will require an advanced degree?
True or False

13. Offshore drilling is the concern of
A. Coastal regions
B. Freshwater lakes
C. Inland rivers and streams
D. The deeper parts of the ocean

Answers

Your Answers:

1: C. Weather Services

2: B. Seaweed

3: C. He developed a particularity narrow ship (I think.)

4:  True The founder/creator of the first echo sounder was German inventor, Alexander Behm.

5: B. The solution favors human needs over environmental. (I think.)

6: True (I think)

7: C. Polar bears and Walruses (I think.)

8: B. A single approach in every situation (I think)

9: A. Most pollution occurs in the ocean

10: A. Walrus Definition of a pinniped: a carnivorous aquatic mammal of the order <i>Pinnipedia</i>, such as a seal or walrus.

11: D. Water conditions around coral reefs (I think)

12: True

13: A. Coastal regions (I think)

Sorry if any of them are incorrect. Some of these I am unsure of how to answer. Hope I helped you,

-Anime.

Answer:

1.C.

2: B.

3: C.

4:  ?

5: B.

6: True

7: C.

8: B.

9: A.

10: A..

11: D.

Explanation:

PLEASE HELP

A 10.0 kg cart and a 15 kg cart are locked together with a compressed spring between them. They are then released so that the spring pushes the two carts apart. The 15 kg cart is moving at 3.0 m/s afterward. How fast is the 10.0 kg cart moving?

A) 3.0 m/s

B) 4.5 m/s

C) 5.0 m/s

Answers

Answer:

4.5 m/s

Explanation:

Initial momentum = final momentum

0 kg m/s = (15 kg) (3.0 m/s) + (10.0 kg) v

v = -4.5 m/s

The negative sign means it's moving in the opposite direction.

Answer:

4.5

Explanation:

4.5

geothermal pumps can be used for cooling, but not heating. true or false?

Answers

Answer:

False

Explanation:

Geothermal pumps can be used for cooling and heating.

hich of the following is NOT true? (1 point)

Hypotheses can be tested.

Theories can be proven.

Theories can be disproven.

Two people can interpret the same facts differently.

Answers

Answer:

Theories can be proven.

Explanation:

A theory in physics is formed by a group of hypothesis based on experimentation, it can never be proven. As much as you experience many times and in all agree the results with the theory, you can never be sure that the next time the result will not contradict it. Rather, a theory can be refuted by finding a single observation that disagrees with its predictions.

Consider a sample of water at 0 degrees C. If the temperature is slightly increased, the volume of the water

A) increases

B) decreases

C) remains the same

Answers

Answer:

B) decreases

Explanation:

The density of water is maximum at a temperature of [tex]4^{\circ} C[/tex]. This means that:

- For temperatures between 0 and 4 degrees C, as the temperature increases, the density increases

- For temperatures above 4 degrees C, as the temperature increases, the density decreases

The density is related to the volume by the formula:

[tex]d=\frac{m}{V}[/tex]

where m is the mass and V the volume. Therefore, density is inversely proportional to the volume. This means that, for a constant amount of mass:

- For temperatures between 0 and 4 degrees C, as the temperature increases, the volume decreases

- For temperatures above 4 degrees C, as the temperature increases, the volume increases

Therefore, for a sample of water at 0 degrees C, if the temperature is slightly increased, the volume of the water will decreases, because its density will increase.

Final answer:

If the temperature of water slightly increases from 0 degrees Celsius, the volume decreases because of the anomalous expansion of water until it approaches 4 degrees Celsius, where it begins to expand normally again.

Explanation:

When considering a sample of water at 0 degrees Celsius, if the temperature is slightly increased, the volume of water decreases. This is due to the anomalous expansion of water, which is a unique property where water expands as it cools down from 4 degrees Celsius to 0 degrees Celsius and reaches its maximum density at 4 degrees Celsius. As the temperature rises slightly above 0 degrees Celsius, water begins to contract until it approaches 4 degrees Celsius, where it will start expanding again. This is in contrast to most substances which expand when heated.

Use the following half-life graph to answer the following question:

A graph titled half-life graph of a radioactive isotope is shown with mass remaining on the y axis from 0 to 60 grams and time on the x axis from o to 6 minutes. A curve connects the points 0, 50 and 1, 25 and 2, 12.5 and 3, 6.25 and 4, 3.125 and 5, 1.562.

The graph is attached.

When you are left with 6.25 mg of the radioactive isotope, how many half-lives have occurred from time equals zero? (5 points)


A. 1

B. 3

C. 6

D. 12

Answers

Answer:

B. 3

Explanation:

The half-life of a radioisotope is the time it needs for the mass of the radioisotope to halve with respect to its original value.

In this problem, the initial mass of the radioisotope at t=0 is

m0 = 50.0 mg

We see that after t = 1 min, the mass of the isotope is

m(1 min) = 25.0 mg

so, exactly half the initial mass: this means that 1 minute is exactly the half-life of this radioisotope.

So, the amount of mass left after each minute is the following:

m (1 min ) = 25.0 mg (1 half-life)

m (2 min) = 12.5 mg (2 half-lives)

m (3 min) = 6.25 mg (3 half-lives)

so, when we are left with 6.25 mg of isotope, 3 minutes have passed, which means that 3 half-lives have passed.

Your bathroom shower curtain swings toward you in the shower when the water is on full blast. Explain.

Answers

The water pushes the shower curtain. Push is a force. The water basically thrusts the shower curtain and the curtain will then not stop immediately as it has a bit of braking distance. Then braking distance differs on the total force the water has on the curtain. Simple way: The curtain moves because the water acts as a push to propel the curtain forwards.

Final answer:

Your shower curtain swings towards you when the water is on full blast due to a principle of physics involving pressure variations in rapidly moving fluids. The high-velocity water and air create lower pressure inside the shower, and with standard atmospheric pressure outside the shower, a net inward force results, causing the curtain to swing in.

Explanation:

This phenomenon is explained with the principles of physics and more specifically, fluid dynamics. When you have the shower on full blast, a high-velocity stream of water and air is created, which result in a region of lower pressure inside the shower. On the other side of the curtain, the pressure remains at standard atmospheric pressure. This difference in pressure results in a net force that pushes the curtain inward. This interaction with rapidly moving fluids and pressure is the reason why your shower curtain swings or bulges towards you when the water is at full blast. It is similar to the effect observed when passing a truck on the highway, where your car tends to veer towards it - the high velocity of air between the car and the truck creates a region of lower pressure, and the vehicles are pushed together by greater pressure from the outside.

Learn more about Pressure Variations in Fluids here:

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Which portion of the electromagnetic spectrum is used in a television? a) infrared waves b) X rays c) radio waves d) gamma waves

Answers

Answer:

C

Explanation:

When you watch television it is a form of radiation and radio waves is radiation.

Television uses radio waves, specifically those in the radio frequency (RF) range of the electromagnetic spectrum. Option C is correct.

What is wavelength?

Wavelength is a fundamental property of waves, including electromagnetic waves like light and radio waves, as well as other types of waves, such as sound waves or water waves.

Here,
Television uses radio waves, specifically those in the radio frequency (RF) range of the electromagnetic spectrum.

Television signals are transmitted from a broadcasting station to a television set via radio waves that are modulated to carry audio and video information. These radio waves fall in the range of frequencies between 47 MHz and 862 MHz for terrestrial television broadcasts. Cable and satellite television transmissions use higher frequencies in the gigahertz (GHz) range.

Infrared waves are used in remote controls, X-rays are used in medical imaging, and gamma waves are used in cancer treatments and industrial applications. None of these are used in television broadcasting.

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1. a metal spoon can be classified as which of the following

A)CONDUCTOR
B)ELECTRIC FIELD
C)INSULATOR
D)ELECTRIC CHARGE

2.which of the following describes why lighting rods are put on top of houses

A) INSULATING THE HOUSE
B) CONDUCT THE LIGHTING AWAY FROM THE HOUSE
C) REDUCE THE AMOUNT OF STATIC DISCHARGE
D) REDUCE THE LOUDNESS OF THUNDER

Answers

1.) D.electric charge 2.) B. Conduct the lighting away from the house

The first answer is actually A, conductor

Low pH means that the hydrogen-ion concetration is ________.
in the middle
equal to the pH number
high
low

Answers

Final answer:

Low pH indicates a high hydrogen-ion concentration, showcasing that the environment is acidic.

Explanation:

Low pH means that the hydrogen-ion concentration is high. The pH scale is a logarithmic representation of hydrogen ion concentration, where a low pH number indicates a higher concentration of H+ ions, creating an acidic environment. In contrast, a high pH suggests a lower concentration of hydrogen ions and a basic or alkaline condition. For example, a pH of 3 is ten times more acidic than a pH of 4 due to the logarithmic scale of pH, where each whole number change represents a tenfold change in ion concentration.

State two advantages of a lead-acid accumulator over a leclanche cell​

Answers

Answer:

They are rechargeable

They have a longer life span

They are reusable

Explanation:

Lead acid accumulators and leclanche cells are types of electrochemical cells.

Leclanche cells are primary cells. Primary cells produce chemical reactions through which the electric current generated is irreversible.

Lead Acid Accumulators are secondary cells in which electric current generated is reversible.

This makes lead acid accumulators reusable, more durable and they have a longer life span.

Final answer:

The two advantages of a lead-acid accumulator over a Leclanché cell are its rechargeability and its higher current output, which makes it suitable for applications such as starting car engines.

Explanation:

There are two main advantages of a lead-acid accumulator (also known as a lead-acid battery) over a Leclanché cell.  

Rechargeability: One of the key advantages of a lead-acid accumulator is that it is rechargeable. This means that after the battery has been discharged (used), it can be recharged again with an external power source. This is in contrast to a Leclanché cell, which is typically not rechargeable. The ability to recharge a lead-acid battery prolongs its lifespan and makes it more cost-effective over the long term. Higher Current Output: Lead-acid accumulators can produce a high current output, which is necessary for starting automobile engines. Because of this, they are commonly utilized in vehicles. This is an advantage over the Leclanché cell, as it typically does not produce as high a current output.

It is important to note that, despite these advantages, lead-acid batteries contain a significant amount of lead and a caustic liquid electrolyte, both of which must be handled and disposed of properly due to their environmental impact.

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