Final answer:
The corrected C++ program calculates total ticket sales and the total number of tickets sold, with results written to an output file, properly accumulating sales using += and outputting with fixed precision.
Explanation:
The student's question is about writing a C++ program to calculate total ticket sales after a football game, formatting the output to show the total number of tickets sold and the total sale amount with two decimal places. A critical mistake in the original program is the calculation of total sales, where the total should accumulate all sales rather than being overwritten on each iteration. Below is the corrected version of the program.
Corrected C++ Program:
#include
#include
#include
using namespace std;
int main() {
double total = 0;
int nTickets = 0, a, b;
ifstream infile("tickets.txt");
while (infile >> a >> b) {
total += a * b; // Correct accumulation of total sales
nTickets += b;
}
infile.close();
ofstream outfile("sales_summary.txt");
outfile << fixed << setprecision(2);
outfile << "Total Sale amount: " << total << endl;
outfile << "Number of tickets sold: " << nTickets << endl;
outfile.close();
return 0;
}
This program reads ticket data from a file, calculates both the total number of tickets sold and the total sales amount, and writes these results to an output file. Note that the setprecision function is used to format the output as required.
This C++ program reads ticket data from a file, calculates total ticket sales and total number of tickets sold, and outputs the results to a file with proper formatting.
To calculate the total ticket sales for a football stadium, we can write a C++ program that reads ticket data from a file and computes the total number of tickets sold as well as the total sales amount. Below is the corrected version of the program:
#include <iostream>This program reads the ticket price and the number of tickets sold from the input file "tickets.txt" and calculates the total sales amount in dollars and the total number of tickets sold. The results are then written to an output file "sales.txt" formatted to two decimal places for the sales amount.
Read the PIC Data sheet Chapter 2.0 and 3.0 2. List at least 3 big differences between the Flash and RAM 3. How many RAM locations are there and how many bits in each location 4. How many Flash locations are there and how many bits in each location 5. Based on the diagram in figure 2-1, what memory are the configuration words associated with 6. In section 3.5.2 there is a description of Linear Data Memory". This is accessed using indirect addressing via the registers FS0 or FSland it allows one to have an array or buffer that is more than 80 bytes long. Explain why this is needed. 7. When you access data RAM, you must always make sure that the BSR is pointing to the right memory bank if you are using the normal mode of direct addressing. Are there any locations in data RAM where you don't have to worry about having the right bank selected? Explain your answer.
Flash and RAM are two types of memory used in microcontrollers like PIC, with differences such as Flash being non-volatile and RAM being volatile. Configuration words are usually stored in Flash memory, and special linear data memory can be used for larger structures. Even while accessing data RAM, the Bank Select Register should typically be set to the correct bank, but some common areas are accessible from all banks.
Explanation:1. Flash and RAM are two types of memories used in microcontrollers like PIC, with significant differences. Flash Memory, being non-volatile, retains its information even when power is turned off, generally used for storing the program. On the other side, RAM (Random Access Memory) is volatile and loses its information when power is removed, typically used for temporary storage during program execution.
2+3. The specific number of RAM and Flash locations, as well as the bit size at each location, depends on the specific PIC microcontroller model. In general, one could read these details from the datasheet for the specific part.
4. Configuration words are usually associated with the Flash memory, as they are used to set up certain parameters for the chip that remain constant during operation.
5. Linear Data Memory is important for larger data structures such as arrays or buffers that require more than 80 bytes. Having this extra memory space allows more complex calculations and data manipulations.
6. Lastly, when accessing data RAM with direct addressing, the correct memory bank that includes our desired memory location should be selected into the BSR (Bank Select Register). However, there are ‘common’ areas in data RAM accessible from all banks, typically which include Special Function Registers (SFRs) and some general purpose registers.
Learn more about Memory Management in Microcontrollers here:https://brainly.com/question/33223494
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Write a SELECT statement that returns two columns based on the Vendors table. The first column, Contact, is the vendor contact name in this format: first name followed by last initial (for example, "John S.") The second column, Phone, is the VendorPhone column without the area code. Only return rows for those vendors in the 559 area code. Sort the result set by first name, then last name.
The answer & explanation for this question is given in the attachment below.
The SQL query selects vendor contacts' first names followed by last initials and phone numbers without area codes from the Vendors table. It filters vendors with the 559 area code and sorts results alphabetically by first name and last name.
Below is the SQL SELECT statement that fulfills your requirements:
```sql
SELECT
CONCAT(SUBSTRING_INDEX(ContactName, ' ', 1), ' ', LEFT(SUBSTRING_INDEX(ContactName, ' ', -1), 1), '.') AS Contact,
SUBSTRING(VendorPhone, 5) AS Phone
FROM
Vendors
WHERE
VendorPhone LIKE '559%'
ORDER BY
SUBSTRING_INDEX(ContactName, ' ', 1),
SUBSTRING_INDEX(ContactName, ' ', -1);
```
This query selects the ContactName column from the Vendors table, concatenates the first name and the first letter of the last name, followed by a period, to create the Contact column.
It then extracts the phone number without the area code from the VendorPhone column and stores it in the Phone column.
Finally, it filters the results to include only vendors with the 559 area code and sorts the result set by first name and last name.
Search online for a Request for Proposal relating to IT. Critically evaluate the proposal. If you were a vendor receiving this proposal, do you have enough information to reply with a quote. What is good? What is missing? What would you change?
Answer and Explanation:
The company of that same Pasadena area thereafter named as "Center" allows RFP to apply regarding contracts for Contractor, but should not be restricted to providing the information infrastructure facilities to complement the Centre's in-house development solutions at either the optimum level of benefits.The contractor or provider shall offer the best facilities on just the basis of the services listed in the preceding documentation by sending two formal submissions no earlier than noon 14 December 2016 to certain stakeholders are encouraged to react towards this RFP.Sure I would also have bought that if I were a dealer since it is worth the investment.So, it's the right answer.
Create a java program using the following instructions:GymsRUs has a need to provide fitness/health information to their clients including BMI, BMI category and maximum heart rate. Your task is to write a console program to do this. Body Mass Index (BMI) is a measure of body fat based on a person’s height and weight. BMI can be used to indicate if you are overweight, obese, underweight, or normal. The formula to calculate BMI is BMI = weight(lb) x 703 / (height(inches))^2.The following BMI categories are based on this calculation:Category BMI RangeUnderweight less than 18.5Normal 18.5 to less than 25Overweight 25 to less than 30Obese 30 or moreMax heart rate is calculated as 220 minus a person’s age.FUNCTIONAL REQUIREMENTS: This problem will have TWO classes. Design and code a class called HealthProfile (your "cookie cutter") to store information about clients and their fitness data. The following attributes are private instance variables:a. Nameb. Agec. Weightd. Height (total inches)
Answer:
See attached file for detailed code.
Explanation:
See attached file for explanation.
What term is defined as a private data placed in a packet with a header containing routing information that allows the data to travel across a network, such as the Internet?
Answer:
Data encapsulation
Explanation:
When we send data to someone else across another network, this data travels down a stack of layers of the TCP/IP model. Each layer of the TCP/IP layer encapsulates data or hides the data by adding headers and sometimes trailers. This packaging is what is known as data encapsulation. The data starts at the application layer and trickles down beneath. As it moves down the layers, it is encoded or compressed to a standard format and sometimes encrypted for security purposes.
So far we have worked on obtaining individual digits from 4 digits of 5 digit numbers. The added them to find the sum of digits. However, now we know about the loop and we can remove the limit of having a specific number of digits. Write a program to print out all Armstrong numbers between 1 and n where n will be an user input. If the sum of cubes of each digit of the number is equal to the number itself, then the number is called an Armstrong number. For example, 153 = (1 * 1* 1)+ ( 5 * 5* 5 ) + ( 3*3*3) In order to solve this problem we will implement the following function: sumDigitCube(): write a function sumDigitCube() that takes a positive integer as a parameter and returns the sum of cube of each digit of the number. Then in the main function, take an integer n as input and generate each number from 1 to n and call the sumDigitCube() function. Based on the returned result, compares it with the value of the generated number and take a decision and print the number if it is Armstrong number
Answer:
#include<stdio.h>
int sumDigitCube(int n);
int main(){
int n, i;
printf("Enter number: ");
scanf("%d", &n);
printf("The Armstrong numbers are:" );
for(i=1; i<=n; i++){
if(sumDigitCube(i)==i){
printf(" %d", i);
}
}
printf("\n");
return 0;
}
int sumDigitCube(int n){
int s = 0;
int digit;
while(n>0){
digit = n%10;
s += digit * digit *digit;
n = n/10;
}
return s;
}
Explanation:
Given a integer, convert to String, using String Builder class. No error checking needed on input integer, However do read in the input integer using Scanner API. This program requires you to use a loop.
Answer:
The program in Java will be:
// Java program to demonstrate working parseInt()
public class GFG
{
public static void main(String args[])
{
int decimalExample = Integer.parseInt("20");
int signedPositiveExample = Integer.parseInt("+20");
int signedNegativeExample = Integer.parseInt("-20");
int radixExample = Integer.parseInt("20",16);
int stringExample = Integer.parseInt("geeks",29);
// Uncomment the following code to check
// NumberFormatException
// String invalidArguments = "";
// int emptyString = Integer.parseInt(invalidArguments);
// int outOfRangeOfInteger = Integer.parseInt("geeksforgeeks",29);
// int domainOfNumberSystem = Integer.parseInt("geeks",28);
System.out.println(decimalExample);
System.out.println(signedPositiveExample);
System.out.println(signedNegativeExample);
System.out.println(radixExample);
System.out.println(stringExample);
}
}
The shipping charges per 500 miles are not prorated. For example, if a 2-pound package is shipped 550 miles, the charges would be $2.20. Write a program that asks the user to enter the weight of a package and then displays the shipping charges.
Answer:
The solution code is written in Python:
COST_PER_500MI = 1.1 weight = float(input("Enter weight of package: ")) total_cost = weight * COST_PER_500MI print("The shipping charges is $" + str(round(total_cost,2)))Explanation:
Based on the information given in the question, we presume the cost per 500 miles is $1.10 per pound ($2.20 / 2 pound).
Create a variable COST_PER_500MI to hold the value of cost per 500 miles (Line 1). Next, prompt user input the weight and assign it to variable weight (Line 3). Calculate the shipping charge and display it using print function (Line 4-5).
Final answer:
A program to calculate shipping charges can be created by converting the weight of a package to ounces and using the provided rate structure. For a 2-pound package, the cost to ship would be $6.88, following the given rate system where the first 3 ounces cost $1.95 and each additional ounce costs $0.17. The per 500-mile charges are not prorated.
Explanation:
The given scenario requires the creation of a simple program that calculates shipping charges based on the weight of a package and the distance it needs to be shipped. According to the details, there's a flat rate for the first 3 ounces, and then an additional, per ounce charge after that. If a 2-pound package is shipped, we can calculate the cost based on the conversion of pounds to ounces, and then apply the pricing rules provided. Since there are 16 ounces in one pound, a 2-pound package would be equivalent to 32 ounces. The cost would then be computed as follows:
Total Cost = Base cost for first 3 ounces + (Number of additional ounces x Cost per additional ounce)
For a 32 ounce package, this would be:
Total Cost = $1.95 + (29 x $0.17) = $1.95 + $4.93 = $6.88
There is no need to prorate the charge per 500 miles as the example provided indicates a flat charge is applied per 500-mile increment. Handling user input correctly in a program is also essential to ensure the right calculations are made based on what the user enters for the package weight and distance.
Write a script that will:
• Call a function to prompt the user for an angle in degrees.
• Call a function to calculate and return the angle in radians. (Note: π radians = 180°)
• Call a function to print the resultWrite all of the functions, also. Put the script and all functions in separate code files.
Answer:
The solution code is written in Python:
import math def getUserInput(): deg = int(input("Enter an angle in degree: ")) return deg def calculateRad(deg): return (deg * math.pi) / 180 def printResult(deg, rad): print(str(deg) + " is equal to " + str(round(rad,2)) + " radian") degree = getUserInput() radian = calculateRad(degree) printResult(degree, radian)Explanation:
Since we need a standard Pi value, we import math module (Line 1).
Next, create a function getUserInput to prompt user to input degree (Line 3-5).
Next, create another function calculateRad that take one input degree and calculate the radian and return it as output (Line 7-8).
Create function printResult to display the input degree and its corresponding radian (Line 10-11).
At last, call all the three functions and display the results (Line 13-15).
A company is utilizing servers, data storage, data backup, and software development platforms over an Internet connection.
Which of the following describes the company’s approach to computing resources?
a. Cloud computing
b. Client-side virtualization
c. Internal shared resources
d. Thick client computing
Answer:
The answer is A. Cloud computing
Explanation:
Cloud computing is the process of using the internet to store, mange and process data rather than using a local server or a personal computer.
The term cloud computing is generally used to describe data centers available to many users over the Internet.
Therefore the company's approach to computing resources can be said to be cloud computing because it uses the internet for data storage, data backup, and software development
Choose the correct code assignment for the following scenario:
15-year-old seen in the ER after being kicked by another soccer player today on a soccer field at the state soccer play-off tournament game.
a) W50.0XXA, Y92.213, Y93.66
b) W50.0XXA, Y92.322, Y93.6A
c) W50.1XXA, Y92.322, Y93.66
d) W50.1XXA, Y92.213, Y93.6A.
Answer:
C
Explanation:
W50.1XXA, Y92.322, Y93.66
Cheers
In this chapter, you saw an example of how to write an algorithm that determines whether a number is even or odd. Write a program that generates 100 random numbers and keeps a count of how many of those random numbers are even, and how many of them are odd.]
Answer:
// Program is written in Java Programming Language
// Comments are used for explanatory purpose
// Program starts here
public class RandomOddEve {
/** Main Method */
public static void main(String[] args) {
int[] nums = new int[100]; // Declare an array of 100 integers
// Store the counts of 100 random numbers
for (int i = 1; i <= 100; i++) {
nums[(int)(Math.random() * 10)]++;
}
int odd = 0, even = 0; // declare even and odd variables to 0, respectively
// Both variables will serve a counters
// Check for odd and even numbers
for(int I = 0; I<100; I++)
{
if (nums[I]%2 == 0) {// Even number.
even++;
}
else // Odd number.
{
odd++;
}
}
//.Print Results
System.out.print("Odd number = "+odd);
System.out.print("Even number = "+even);
}
Answer:
Complete python code along with comments to explain the whole code is given below.
Python Code with Explanation:
# import random module to use randint function
import random
# counter variables to store the number of even and odd numbers
even = 0
odd = 0
# list to store randomly generated numbers
random_num=[]
# A for loop is used to generate 100 random numbers
for i in range(100):
# generate a random number from 0 to 100 and append it to the list
random_num.append(random.randint(0,100))
# check if ith number in the list is divisible by 2 then it is even
if random_num[i] % 2==0:
# add one to the even counter
even+=1
# if it is not even number then it must be an odd number
else:
# add one to the odd counter
odd+=1
# finally print the count number of even and odd numbers
print("Total Even Random Numbers are: ",even)
print("Total Odd Random Numbers are: ",odd)
Output:
Total Even Random Numbers are: 60
Total Odd Random Numbers are: 40
Total Even Random Numbers are: 54
Total Odd Random Numbers are: 46
Given three dictionaries, associated with the variables, canadian_capitals, mexican_capitals, and us_capitals, that map provinces or states to their respective capitals, create a new dictionary that combines these three dictionaries, and associate it with a variable, nafta_capitals.Use python and dictionary. Write code in simplest form.
Answer:
canadian_capitals = {"Alberta":"Edmonton", "British Columbia":"Victoria", "Manitoba":"Winnipeg"}
mexica_capitals ={"Aguascalientes":"Aguascalientes", "Baja California":"Mexicali", "Baja California Sur":"La Paz"}
us_capitals ={"Alabama":"Montgomery", "Alaska":"Juneau", "Arizona":"Phoenix"}
nafta_capitals = {}
nafta_capitals.update(canadian_capitals)
nafta_capitals.update(mexica_capitals)
nafta_capitals.update(us_capitals)
print(nafta_capitals)
Explanation:
The code is written in python.
canadian_capitals = {"Alberta":"Edmonton", "British Columbia":"Victoria", "Manitoba":"Winnipeg"} I created the first dictionary with the variable name called canadian_capital. Notice the province of Canada is mapped to to their respective capitals.
mexica_capitals ={"Aguascalientes":"Aguascalientes", "Baja California":"Mexicali", "Baja California Sur":"La Paz"} I created the second dictionary with the variable name called mexican_capital. The states are also mapped to their respective capitals.
us_capitals ={"Alabama":"Montgomery", "Alaska":"Juneau", "Arizona":"Phoenix"} I created the third dictionary with the variable name called us_capital. The states are also mapped to their respective capitals.
nafta_capitals = {} This is an empty dictionary with the variable name nafta_capitals to combine the 3 dictionaries.
nafta_capitals.update(canadian_capitals) I updated the empty dictionary with the canadian_capitals dictionary.
nafta_capitals.update(mexica_capitals) I also added the mexica_capitals dictionary to the nafta_capitals dictionary.
nafta_capitals.update(us_capitals) I also added the us_capitals dictionary to the nafta_capitals dictionary.
print(nafta_capitals) The whole 3 dictionaries have been combined to form the nafta_capitals dictionary. The print function displays the already combine dictionaries.
A __________ grants the authority to perform an action on a system. A __________ grants access to a resource. right, permission login, password permission, right password, login
Answer:
A right grants the authority to perform an action on a system. A permission grants access to a resource.
Explanation:
In System administration there are different rights and permissions are given to the user as per the requirement to perform some actions and accessing some resources.
Rights are given to the users may be at admin level to perform some action or make some changes in the system. The users who have rights of the system can add, edit or delete data from the system as per requirement of the company.
Many peoples granted by permissions by providing them some passwords to access the resources of the systems. These users did not have the right to change, add, edit or delete any data. They just can use the information.
A right grants the authority to perform an action on a system. A permission grants access to a resource.
In the context of system security and access control:
- A right is a privilege granted to a user or process that allows them to perform a specific action on a system. For example, a right might allow a user to shut down the computer or to modify system settings.
- A permission is a rule that grants access to a specific resource, such as a file, directory, or network resource. Permissions determine what actions (such as read, write, or execute) can be performed on that resource.
Thus, a right defines the actions a user can perform, while a permission defines what resources a user can access and what they can do with those resources.
Consider the following architecture. 1 cache block = 16 words. Main memory latency is the time delay for each data transfer, which = 10 memory bus clock cycles. A memory transfer time = 1 memory bus clock cycle, which is also called bandwidth time. For any memory access, it consists of latency time plus the bandwidth time. The cache miss penalty is the time to transfer one block from main memory to the cache. In addition, it takes 1 clock cycle to send the address to the main memory. Compute the miss penalty for the following configurations. Configuration (a): Requires 16 main memory accesses to retrieve a cache block and words of the block are transferred one at a time. Configuration (b): Requires 4 main memory accesses to retrieve a cache block and words of the block are transferred four at a time. Configuration (c): Requires 4 main memory accesses to retrieve a cache block and words of the block are transferred one at a time.
Answer:
The answers are A)176 B)44 C)56.
Explanation:
According to the information given in the question about the architecture that is used and its communication times;
For option A: The goal is to retrieve one cache block which consists of 16 words. Doing this one word at a time over a period of 16 main memory accesses and the miss penalty for this configuration is 10*16 = 160 bus clock cycles for data transfer and 1*16 = 16 bus clock cycles for memory transfer time which comes up to 176.
For option B: The goal is to retrieve one cache block which consists of 16 words. Doing this four words at a time over a period of 4 main memory accesses and the miss penalty for this configuration is 10*4 = 40 bus clock cycles for data transfer and 1*4 = 4 bus clock cycles for memory transfer which comes up to 44.
For option C: The goal is to retrieve one cache block which consists of 16 words. Doing this 4 words at a time over a period of 4 main memory accesses and the miss penalty for this configuration is 10*4 = 40 bus clock cycles for data transfer and 1*16 = 16 bus clock cycles for memory transfer since words of the block are transferred not 4 but 1 at a time which comes up to 56.
I hope this answer helps.
Write a test program that creates two Rectangle objects—one with width 4 and height 40 and the other with width 3.5 and height 35.7. Display the width, height, area, and perimeter of each rectangle in this order.
Answer:
public class Rectangle {
private double width;
private double heigth;
public Rectangle(double width, double heigth) {
this.width = width;
this.heigth = heigth;
}
public double getWidth() {
return width;
}
public void setWidth(double width) {
this.width = width;
}
public double getHeigth() {
return heigth;
}
public void setHeigth(double heigth) {
this.heigth = heigth;
}
public double perimeter(double width, double heigth){
double peri = 2*(width+heigth);
return peri;
}
public double area(double width, double heigth){
double area = width*heigth;
return area;
}
}
class RectangleTest{
public static void main(String[] args) {
//Creating two Rectangle objects
Rectangle rectangle1 = new Rectangle(4,40);
Rectangle rectangle2 = new Rectangle(3.5, 35.7);
//Calling methods on the first Rectangel objects
System.out.println("The Height of Rectangle 1 is: "+rectangle1.getHeigth());
System.out.println("The Width of Rectangle 1 is: "+rectangle1.getWidth());
System.out.println("The Perimeter of Rectangle 1 is: "+rectangle1.perimeter(4,40));
System.out.println("The Area of Rectangle 1 is: "+rectangle1.area(4,40));
// Second Rectangle object
System.out.println("The Height of Rectangle 2 is: "+rectangle2.getHeigth());
System.out.println("The Width of Rectangle 2 is: "+rectangle2.getWidth());
System.out.println("The Perimeter of Rectangle 2 is: "+rectangle2.perimeter(4,40));
System.out.println("The Area of Rectangle 2 is: "+rectangle2.area(4,40));
}
}
Explanation:
Firstly A Rectangle class is created with two fields for width and heigth, a constructor and getters and setters the class also has methods for finding area and perimetersThen a RectangleTest class containing a main method is created and two Rectangle objects are created (Follow teh comments in the code)Methods to get height, width, area and perimeter are called on each rectangle object to print the appropriate valueWrite a switch statement that checks nextChoice. If 0, print "Rock". If 1, print "Paper". If 2, print "Scissors". For any other value, print "Unknown". End with newline.
Answer:
case 0:
System.out.println("Rock");
break;
case 1:
System.out.println("Paper");
break;
case 2:
System.out.println("Scissors");
break;
default:
System.out.println("Unknown");
break;
}
Explanation:
In this exercise we have to use the knowledge of computational language in python to describe a code, like this:
The code can be found in the attached image.
To make it easier the code can be found below as:
case 0:
System.out.println("Rock");
break;
case 1:
System.out.println("Paper");
break;
case 2:
System.out.println("Scissors");
break;
default:
System.out.println("Unknown");
break;
}
See more about python at brainly.com/question/26104476
You are asked by your supervisor to export NPS configuaration from a server. Your supervisor contacts you and tells you it is missing the log files. What must you do to provide your supervisor with the NPS log files?
Answer:
You must import the NPS configurations, then manually cnfigure the SQL Server Logging on the target machine.
Explanation:
The SQL Server Logging settings are not in anyway exported. If the SQL Server Logging was designed on the root machine, the a manually configure of SQL Server Logging has to be done on the target machine after the NPS configurations must have been imported.
Although administrator rights is needed at least to import and export NPS settings and configurations, while that isn’t the issue in this case. NPS configurations are moved to a XML file that is non-encrypted by default. There is no wizard or tool whatsoever to export or import the configuration files.
Insect population An insect population doubles every generation. Write a while loop that iterates numGeneration times. Inside the while loop, write a statement that doubles currentPopulation in each iteration of the while loop. Function Save Reset MATLAB DocumentationOpens in new tab function currentPopulation = CalculatePopulation(numGeneration, initialPopulation) % numGeneration: Number of times the population is doubled % currentPopulation: Starting population value i = 1; % Loop variable counts number of iterations currentPopulation = initialPopulation; % Write a while loop that iterates numGeneration times while ( 0 ) % Write a statment that doubles currentPopulation in % each iteration of the while loop % Hint: Do not forget to update the loop variable end end 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 Code to call your function
Answer:
function currentPopulation = CalculatePopulation(numGeneration, initialPopulation)
i = 1;
currentPopulation = initialPopulation;
while(i <= numGeneration)
currentPopulation = 2* currentPopulation;
i= i+1;
end
end
Explanation:
Assign 1 to i as an initial loop value .Assign initialPopulation to currentPopulation variable.Run the while loop until i is less than numGeneration.Inside the while loop, double the currentPopulation variable.Inside the while loop, Increment the i variable also.
In this exercise we have to use the knowledge of computational language in python to describe a code, like this:
The code can be found in the attached image.
To make it easier the code can be found below as:
function currentPopulation = CalculatePopulation(numGeneration, initialPopulation)
i = 1;
currentPopulation = initialPopulation;
while(i <= numGeneration)
currentPopulation = 2* currentPopulation;
i= i+1;
end
end
See more about python at brainly.com/question/26104476
Modify the URL_reader.py program to use urllib instead of a socket. This code should still process the incoming data in chunks, and the size of each chunk should be 512 characters.
Answer:see the picture attached
Explanation:
Consider the following program:
void fun1(void); /* prototype */
void fun2(void); /* prototype */
void fun3(void); /* prototype */
void main() {
int a, b, c;
...
}
void fun1(void) {
int b, c, d;
...
}
void fun2(void) {
int c, d, e;
...
}
void fun3(void) {
int d, e, f;
...
}
Given the following calling sequences and assuming that dynamic scoping is used, what variables are visible during the execution of the last subprogram activated? Include with each visible variable the name of the unit where it is declared.
1. main calls sub1; sub1 calls sub2; sub2 calls sub3.
2. main calls sub1; sub1 calls sub3.
3. main calls sub2; sub2 calls sub3; sub3 calls sub1.
4. main calls sub3; sub3 calls sub1.
5. main calls sub1; sub1 calls sub3; sub3 calls sub2.
Answer:
Following are the variables which is visible in when the last module is called:
d,e,fd,e,fb,c,db,c,dc,d,eExplanation:
Missing information :
The above question option needs to holds the function name as fun1,fun2 or fun3, but the options are holding the sub1,sub2, and sub3.The above question asked about the variable when the last function is called. The explanation of the visible variable is as follows:For the first option, the last function is called is fun3 which holds the variable as d,e, and f, and no variable is passed as the argument, So currently visible variable are d,e, and f.For the second option, the last function is called is fun3 which holds the variable as d,e, and f, and no variable is passed as the argument, So currently visible variable are d,e, and f.For the third option, the last function is called is fun1 which holds the variable as b,c and d and no variable is passed as the argument, So currently visible variable are b,c, and d.For the fourth option, the last function is called is fun1 which holds the variable as b,c and d and no variable is passed as the argument, So currently visible variable are b,c, and d.For the fifth option, the last function is called is fun2 which holds the variable as c,d and e and no variable is passed as the argument, So currently visible variable are c,d, and e.Write a program that generates a random integer number in the range of 1 through 100 inclusively, and then asks the user to guess what the number is (User should be informed at the beginning that the number is between 1 to 100). If the user’s guess (input) is higher than the random number, the program should display "Too high, try again." If the user’s guess is lower than the random number, the program should display "Too low, try again." If the user guesses the number, the program should congratulate the user with a message as well as to display the number of guesses to get the right number. Next asking the user if he/she wants to play one more time. If yes, then generate a new random number so the game can start over
Answer:
Here is the Python program:
import random #to generate random numbers
low = 1 #lowest range of a guess
high = 100 #highest range of a guess
attempts=0 # no of attempts
def guess_number(low, high, attempts): #function for guessing a number
print("Guess a number between 1 and 100")
#prompts user to enter an integer between 1 to 100 as a guess
number = random.randint(low, high)
#return randoms digits from low to high
for _ in range(attempts): #loop to make guesses
guess = input("Enter a number: ") #prompts user to enter a guess
num = int(guess) #reads the input guess
if num == number: # if num is equal to the guess number
print('Congratulations! You guessed the right number!')
command= input("Do you want to play another game? ")
#asks user if he wants to play another game
if command=='Y': #if user enters Y
guess_number(low,high,attempts) #starts game again
elif command=='N': #if user types N
exit() #exits the program
elif num < number: #if user entered a no less than random no
print('Too low, Try Higher') # program prompts user to enter higher no
elif num > number: #if user entered a no greater than random no
print('Too high, Try Lower') # program prompts user to enter lower no
else: #if user enters anything else
print("You must enter a valid integer.")
#if user guessed wrong number till the given attempts
print("You failed to guess the number correctly in {attempts} attempts.".format(attempts=attempts))
exit() # program exits
Explanation:
The program has a function guess_number which takes three parameters, high and low are the range set for the user to enter the number in this range and attempts is the number of tries given to the user to guess the number.
random.randint() generates integers in a given range, here the range is specified i.e from 1 to 100. So it generates random number from this range.
For loop keeps asking the user to make attempts in guessing a number and the number of tries the user is given is specified in the attempts variable.
If the number entered by the user is equal to the random number then this message is displayed: Congratulations! You guessed the right number! Then the user is asked if he wants to play one more time and if he types Y the game starts again but if he types N then the exit() function exits the game.
If the number entered as guess is higher than the random number then this message is displayed Too high, Try Lower and if the number entered as guess is lower than the random number then this message is displayed Too low, Try Higher.
If the user fails to guess the number in given attempts then the following message is displayed and program ends. You failed to guess the number correctly in {attempts} attempts.
You can call this function in main by passing value to this function to see the output on the screen.
guess_number(1, 100, 5)
The output is shown in screenshot attached.
Consider the following code: // Linked Lists: TRAVERSE
struct ListNode { int data; struct ListNode *next; };
Assume that a linked list has been created and head points to a sentinel node. A sentinel node is an empty data node in the beginning of the list. It sometimes holds a sentinel value. The use of sentinel nodes is a popular trick to simplify the insert and delete operations.
You may also assume that the list is not empty. Each node in the list contains an integer representing a digit in a number. The data in the sentinel node is -1.
For instance, n = 234 will be stored as {-1, 4, 3, 2} in the linked list.
Write a function based on the list traversal named computeNumFromList that is passed the pointer to the first node in the list, it prints the digits in the list one per line, and it returns a long integer, the number calculated from its digits in the list (234 see the above example). You may assume that long int will hold the converted number (no need to check for numeric overflow).
Answer:
See attached file for detailed code.
Explanation:
See attached file.
Consider a point to point link 50 km in length. At what speed would propagation delay (at a speed 2 x 108 meters/second) equal transmit delay for 100 byte packets.
Answer:
The bandwidth is 3200 Kbps
Explanation:
Given:
The length of the point to point link = 50 km = 50×10³ = 50000 m
Speed of transmission = 2 × 10⁸ m/s
Therefore the propagation delay is the ratio of the length of the link to speed of transmission
Therefore, [tex]t_{prop} = \frac{distance}{speed}[/tex]
[tex]t_{prop} = \frac{50000}{2*10^{8} }=2.5*10^{-4}[/tex]
Therefore the propagation delay in 25 ms
100 byte = (100 × 8) bits
Transmission delay = [tex]\frac{(100*8)bits }{(x)bits/sec}[/tex]
If propagation delay is equal to transmission delay;
[tex]\frac{(100*8)bits }{(x)bits/sec}= \frac{50000}{2*10^{8} }[/tex]
[tex]x=\frac{100*8*2*10^{8} }{50000}[/tex]
[tex]x=\frac{100*8}{2.5*10 ^-4}=3200000[/tex]
x = 3200 Kbps
Answer:
The complete question is here:
Consider a point-to-point link 2 km in length. At what bandwidth would propagation delay (at a speed of 2 x 108 m/s) equal transmission delay for
(a) 100-byte packets?
(b) 512-byte packets?
Explanation:
Given:
Length of the link = 50 km
Propagation delay = distance/speed = d/s
To find:
At what speed would propagation delay (at a speed 2 x 10^8 meters/second) equal transmit delay for 100 byte packets?
Solution:
Propagation Delay = t prop
= 50 * 10^3 / 2 * 10^8
= 50000 / 200000000
= 0.00025
= 25 ms
(a) When propagation delay is equal to transmission delay for 100 packets:
Transmission Delay = packet length / data rate = L / R
So when,
Transmission Delay = Propagation Delay
100 * 8 / bits/sec = 50 * 10^3 / 2 * 10^8
Let y denotes the data rate in bit / sec
speed = bandwidth = y bits/sec
100 * 8 / y bits/sec = 50 * 10^3 / 2 * 10^8
y bit/sec = 100 * 8 / 25 * 10^ -5
= 800 / 0.00025
y = 3200000 bit/sec
y = 3200 Kbps
(b) 512-byte packets
512 * 8 / y bits/sec = 50 * 10^3 / 2 * 10^8
y bit/sec = 512 * 8 / 25 * 10^ -5
= 4096 / 0.00025
y = 16384000 bit/sec
y = 16384 Kbps
A university begins Year 1 with 80 faculty. They hire 4 faculty each year. During each year 10% (rounded to the nearest integer) of the faculty present at the beginning of the year leave the university. For example, in a year where there are 73 faculty at the beginning of the year, 7 would leave the university at the end of the year. The university wants to know how many faculty they will have at the end of year 10. The resulting spreadsheet can be found below. In cell G9 the first cell address referred to was cell E9. If the formula is entered in cell G9 and is copied down to G10:G18, what is it followed by?
Answer:
The correct answer to the following question will be "B9:B18-ROUND(0.1*B9:B18,0) +C9:C18".
Explanation:
The ROUND function of Excel seems to be an adaptive feature in excel that calculates the first round amount of a specific number with either the numerical value or digits to be given as just a statement.
For rounding rolling quantities to a defined degree of accuracy you can use this function named ROUND.
The description of the above statement is as follow :
The formula will be used in that manner B9 along with colon B18 after that subtract (-) and using the round function (In this we pass the range i.e B9:B18,0) Plus C9 :C18.
The factorial of an integer N is the product of the integers between 1 and N, inclusive. Write a while loop that computes the factorial of a given integer N.
the function and loop will be
def factorial(x):
total = 1
if x != 1 and x != 0:
for i in range(x,1,-1):
total *= i
return total
The program is an illustration of loops
Loops are program statements that are used to perform repeated operations
The program in python, where comments are used to explain each line is as follows:
#This gets input for N
N = int(input())
#This initializes factorial to 1
factorial = 1
#This opens the while loop
while N >1:
#This calculates the factorial
factorial*=N
N-=1
#This prints the factorial
print(factorial)
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construct an AVL tree. For each line of the database and for each recognition sequence in that line, you will create a new SequenceMap object that contains the recognition sequence as its recognition_sequence_ and the enzyme acronym as the only string of its enzyme_acronyms_ main function
Answer:
Explanation:
AVL trees are used frequently for quick searching as searching takes O(Log n) because tree is balanced. Where as insertion and deletions are comparatively more tedious and slower as at every insertion and deletion, it requires re-balancing. Hence, AVL trees are preferred for application, which are search intensive.
The attached diagramm further ilustrate this
What is wrong with line 1?
public class G
{
private int x;
public G() { x=3;}
public void setX(int val){
x=val;
}
public String toString(){
return ""+x;
}
}
public class H extends G
{
private int y;
public H() { y=4;}
public void setY(int val){
y=val;
}
public String toString() {
return ""+y+super.toString();
}
}
//test code in the main method
G bad = new H();
bad.setY(9); //line 1
Answer:
The set is a object of the class 'H' and the setY method is a member of G class which is not called by the object of H class.
Explanation:
If a user calls the G function which is not a private by the help of H class objects then it can be called. It is because all the public and protected methods of A class can be accessed by the B class if B extends the A-class.If any class is extended by the other class then the derived class holds the property of the base class and the public and protected method can be accessed by the help of a derived class object.The derived class object can be created by the help of base class like written in the "line 1".But the base class can not call the member of the derived class.Write the definition of a method printAttitude, which has an int parameter and returns nothing. The method prints a message to standard output depending on the value of its parameter. If the parameter equals 1, the method prints disagree. If the parameter equals 2, the method prints no opinion. If the parameter equals 3, the method prints agree. In the case of other values, the method does nothing.
Answer:
void printAttitude (int pint){
if (pint == 1){
System.out.println("disagree");
}
if (pint == 2){
System.out.println("no opinion");
}
if (pint == 3){
System.out.println("agree");
}
}
Explanation:
Answer:
public class num4 {
public static void main(String[] args) {
int para =2;
printAttitude(para);
}
static void printAttitude( int para){
if(para==1){
System.out.println("disagree");
}
else if (para == 2){
System.out.println("no option");
}
else if (para==3){
System.out.println("agree");
}
}
}
Explanation:
Using Java Programming language:
Three if and else if statements are created to handle the conditions as given in the question (1,2,3) The output of disagree, no option and agree respectively is displayed using Java's output method System.out.println When these conditions are true
No else statement is provided to handle situations when the parameter value is neither (1,2,3), as a result, then program will do nothing and simply exits.
We have seen in class that the sets of both regular and context-free languages are closed under the union, concatenation, and star operations. We have also seen in A2 that the regular languages are closed under intersection and complement. In this question, you will investigate whether the latter also holds for context-free languages.
(a) Use the languages A = {a^mb^nc^n \ m, n greaterthanorequalto 0} and B = {a^nb^nc^m \ m, n greaterthanorequalto 0} to show that the class of context-free languages is not closed under intersection. You may use the fact that the language C = {a^nb^nc^n | n greaterthanorequalto 0} is not context-free.
(b) Using part (a) above, show now that the set of context-free languages is not closed under complement.
Answer:
Attached is the solution. Hope it helps:
a) The class of context-free languages is not closed under intersection, as shown by the example of[tex]A = [ a^m b^n c^n | m, n \geq 0 ][/tex] and [tex]B = [a^n b^n c^m | m, n \geq 0 ][/tex]
Given that;
We have seen in class that the sets of both regular and context-free languages are closed under the union, concatenation, and star operations.
(a) We're given two languages A and B:
[tex]A = [ a^m b^n c^n | m, n \geq 0 ][/tex]
[tex]B = [a^n b^n c^m | m, n \geq 0 ][/tex]
We want to show that the intersection of A and B is not context-free.
To do this, we can use the fact that the language [tex]C = [a^n b^n c^n | n \geq 0 ][/tex] is not context-free.
Assume for contradiction that the intersection of A and B, which we'll call D, is context-free.
Since context-free languages are closed under intersection, we'd have D = A ∩ B is also a context-free language.
Now, notice that D is a subset of C (if a string belongs to D, it must belong to C as well).
However, C is not context-free, as given.
This contradicts our assumption that D is context-free.
Therefore, we can conclude that the class of context-free languages is not closed under intersection, as shown by the example of[tex]A = [ a^m b^n c^n | m, n \geq 0 ][/tex] and [tex]B = [a^n b^n c^m | m, n \geq 0 ][/tex]
(b) Using the result from part (a), we can now show that the set of context-free languages is not closed under complementation.
Let's consider the complement of a context-free language.
If the complement of a context-free language were always context-free, we could take the complement of C and obtain a context-free language.
However, as established earlier, C is not context-free.
Hence, we can conclude that the set of context-free languages is not closed under complementation.
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