the compound benzamide has the following percent composition. What is the empirical formula? C=69.40% H=5.825% O=13.21% N=11.57%

Answer:

An unsaturated solution can dissolve more solute at the given temperature. If you add more solute until the solution will dissolve no more at that temperature, it is saturated solution.

Explanation:

In unsaturated solution, there is capacity of solution to dissolve more solute inside the solution. In saturated solution, there is no capacity of a solution to dissolve any further solute at a given temperature. This capacity is increased by heating the solution so more solute will be dissolved. This is called supersaturated solution.

Answer:

The final temperature of the water mixture is 47.85°C

Explanation :

Given,

For Warm Water

mass = 10grams

Temperature = 105°C

For Cold Water

mass = 25grams

Temperature = 25°C

When a sample of warm water is mixed with a sample of cool water,

The energy amount going out of the warm water is equal to the energy amount going into the cool water. This means:

However,

Q = (mass) (ΔT) (Cp)

Cp = Specific heat of water = 4.184 J/Kg°C

So,

(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

We start by calling the final, ending temperature 'x.' Keep in mind that BOTH water samples will wind up at the temperature we are calling 'x.' Also, make sure you understand that the 'x' we are using is FINAL temperature. This is what we are solving for.  

The warmer water goes down from to 105°C to x, so this means its Δt equals 105°C − x. The colder water goes up in temperature, so its Δt equals x − 25℃

Substituting the values,

(10)( 105°C − x)(4.184) = (25)(x − 25℃)(4.184)

Solving for x, we get

x = 47.85°C

Therefore, The final temperature of the water mixture is 47.85°C.

Answer:

After 28 sec 7.5 grams of Be will be left

Explanation:

Given data:

Total amount of Be = 30 g

Half life of Be = 14 sec

Mass left after 28 sec = ?

Solution:

First of all we will calculate the number of half lives in 28 sec.

Number of half lives = T elapsed / half life

Number of half lives = 28 sec / 14 sec

Number of half lives = 2

AT time zero = 30 g

At first half life = 30 g/2 = 15 g

At second half life = 15 g/ 2 = 7.5 g

So after 28 sec 7.5 grams of Be will be left.

Answer: D is wrong

Explanation: The charges go from positive in the left to negative to the right.

Final answer:

The CaO bond in CaO is ionic, the CC bond in C13CCC13 is nonpolar covalent, the CCl bond in C13CCC13 is polar covalent, and the SeCl bond in SeCl2 is polar covalent.

Explanation:

The classification of bonds as ionic, polar covalent, or nonpolar covalent is based on the electronegativity difference between the bonded atoms. The greater the electronegativity difference, the more ionic the bond is.

(a) The CaO bond in CaO is an ionic bond. Calcium (Ca) is a metal and has a low electronegativity, while oxygen (O) is a nonmetal with a high electronegativity. The difference in electronegativity is large, resulting in an ionic bond.

(b) The CC bond in C13CCC13 is a nonpolar covalent bond. Both carbon (C) atoms have the same electronegativity, resulting in a nonpolar bond.

(c) The CCl bond in C13CCC13 is a polar covalent bond. Chlorine (Cl) has a higher electronegativity than carbon (C), resulting in a polar bond.

(d) The SeCl bond in SeCl2 is a polar covalent bond. Selenium (Se) and chlorine (Cl) have different electronegativities, resulting in a polar bond.

Answer: Metal

Explanation: Potassium is a soft, silvery-white metal, member of the alkali group of the periodic chart. Potassium is silvery when first cut but it oxidizes rapidly in air and tarnishes within minutes, so it is generally stored under oil or grease.

Potassium is a metal, specifically an alkali metal, identified as part of Group 1 on the periodic table. Metals are characterized as shiny, malleable, ductile, and excellent conductors of heat and electricity.

Potassium, denoted by the symbol 'K' on the periodic table, falls into the category of metals. As part of Group 1, it is an alkali metal. Metals are characterized by their shininess, silvery color (in most cases), excellent conductivity of heat and electricity, malleability, and ductility. To classify an element as a metal, nonmetal or metalloid, it's important to examine its location on the periodic table. Generally, metals occupy the left three-fourths of the periodic table while nonmetals are clustered in the upper right-hand corner. Metalloids, or semimetals, have intermediate properties and lie adjacent to the line dividing metals and nonmetals on the right-hand portion of the periodic table.

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Answer:

C₂ = 0.02 M

Explanation:

Given data:

Initial volume of solution = 0.1 L

Initial molarity = 0.1 M

Final volume = 0.5 L

Final concentration = ?

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Initial volume of solution

V₁ = Initial molarity / concentration

C₂ = Final concentration

V₂ = Final volume

Now we will put the values in formula.

C₁V₁ = C₂V₂

0.1 M × 0.1 L =  C₂ × 0.5 L

0.01 M.L = C₂ × 0.5 L

C₂ = 0.01 M.L /  0.5 L

C₂ = 0.02 M

Final answer:

Using the dilution formula M1V1 = M2V2, we determined that the final concentration of the solution that was initially 0.1 M and dilutes from 0.1 L to 0.5 L is 0.02 M.

Explanation:

To determine the concentration of a solution that started out as 0.1 L of a 0.1 M solution and ended with a final volume of 0.5 L, we use the concept of dilution, which is expressed with the formula M1V1 = M2V2, where M1 and V1 are the concentration and volume of the initial solution, respectively, and M2 and V2 are the concentration and volume of the final solution, respectively.

In this case, we plug our known values into the formula:

M1 = 0.1 M (initial concentration)

V1 = 0.1 L (initial volume)

V2 = 0.5 L (final volume)

We want to solve for M2, the final concentration.

Substituting in:

0.1 M * 0.1 L = M2 * 0.5 L

We isolate M2 by dividing both sides of the equation by 0.5 L:

M2 = (0.1 M * 0.1 L) / 0.5 L = 0.02 M

Therefore, the final concentration of the solution is 0.02 M.

Final answer:

An acid is a compound that releases hydrogen ions in water. Strong acids fully ionize, releasing all their hydrogen ions, whereas weak acids only partially ionize. Examples are hydrochloric acid (strong) and acetic acid (weak).

Explanation:

Definitions of Acids, Strong Acids, and Weak Acids:

Acids can be described as molecular compounds that release hydrogen ions (H+) when dissolved in water, which are responsible for the characteristic properties of acids in aqueous solutions. These properties include the ability of the solution to conduct electricity, due to the presence of ions.

Strong acids are those that completely ionize in solution, releasing all of their hydrogen ions into the water. An example of a strong acid is hydrochloric acid (HCl), which dissociates into hydrogen and chloride ions as follows:

HCl → H+ + Cl¯

On the other hand, weak acids only partially ionize in water, which means not all of their hydrogen ions are released into the solution. Acetic acid, found in vinegar, is a common example of a weak acid. Its ionization is represented by the following chemical equation:

CH3COOH → CH3COO¯ + H+

The strength of an acid can be quantitatively represented by its acid ionization constant (Ka), which is higher for strong acids and lower for weak acids.

Answer:

The only one that makes sense IF the model behaves as the Earth is D.

Explanation:

Answer

D. Some parts of the model Earth will have daytime and some will have night.

Explanation:

i got it right~

I believe it would be the last one. It just amplified the acid, which is (2. Al)(2.Cl3)-> Al2Cl6

Hope it helps!

A neutralization reaction, such as between hydrochloric acid and sodium hydroxide, is not considered a Lewis acid-base reaction as it does not involve the transfer of electron pairs.

A Lewis acid-base reaction refers to a reaction involving the transfer of an electron pair. The Lewis acid accepts the electron pair, while the Lewis base donates it. An example that does not fit the definition of a Lewis acid-base reaction would be the neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH), which produces water (H2O) and salt (NaCl). This reaction does not involve the transfer of electron pairs, and hence, is not a Lewis acid-base reaction.

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Answer:

The density of the substance is 2.357 g/mL

Explanation:

Given that the substance has a mass of 165 g and occupies a volume of 70 mL, I'm assuming that the question missing is: What is its density?

Density (ρ) is computed as follows:

ρ = mass/volume

ρ = 165 g/ 70 mL

ρ = 2.357 g/mL

8 moles of CaO produced from 4 moles O2.

Explanation:

Balanced chemical equation for the reaction:

2 Ca + O2 --> 2 CaO

Data given:

moles of O2 = 4

Moles of CaO =?

From the reaction it is seen that 1 mole of O2 is used in the reaction to produce 2 moles of CaO

hence, 4 moles of O2 will give x moles of CaO

[tex]\frac{2}{1}[/tex] = [tex]\frac{x}{4}[/tex]

x =8

So, 8 moles of CaO will be produced when 4 moles of O2 will be used in the reaction. Since oxygen is the limiting reagent in the reaction.

[A] + [B] ⇌ [C] + [D]

MnS ⇌ Mg + S

Ksp = [C][D]

Ksp = (Mn)(S)

2.3*10^-13 = (x)(x)

2.3*10^-13 = x^2

x = 4.8*10^-7

Concentration of sulfide is x.

Today, my son asked "Can I have a book, Mark?" and I burst into tears. 11 years old and he still doesn't know my name is Brian.

Answer:

Wavelength is 10m

Explanation:

To solve this problem, we use the formula for wavelength

Wavelength = wave velocity / frequency

Wavelength = 50m/s / 5Hz

= 10m

Answer:

10 m

Explanation:

Answer:

0.635 grams

Explanation:  

Equation for the reaction

[tex]Cu + 2 AgNO_3 -----> Ag^{2+} + CuNO_3[/tex]

mass of Cu = 5.00 g

molar mass = 63.5 g/mol

number of moles = [tex]\frac{mass}{molar mss}[/tex]

number of moles of Cu = [tex]\frac{5.00g}{63.5g/mol}[/tex]

number of moles of Cu = 0.0787 moles

To determine the moles of Ag formed; we have:

0.00588 moles of AgNO₃ × [tex]\frac{2 moles of Ag}{2 moles of AgNO_3}[/tex]

= 0.00588 moles of Ag are  produced

Molar mass of Ag = 108 g/mol

Then mass of Ag that will be produced = number of moles of Ag × molar mass of Ag

= 0.00588 moles × 108 g/mol

= 0.635 grams of Ag are produced.

Answer:

0.635 g of Ag

Explanation:

Below are attachments containing the solution

Answer:

The volume is 1143,78 L

Explanation:

We use the formula PV=nRT. The conditions STP are 1 atm of pressure and 273K of temperature. We calculate the weight of 1 mol of CH4.

Weight 1 mol CH4= weight C+ (weight H)x4= 12 g + 1 g x4= 16 g/mol

16 g----1 mol CH4

817,5g--x=(817,5gx1 mol CH4)/16g= 51, 1 mol CH4

PV=nRT V=(nRT)/P  

V= (51,1 mol x 0,082 l atm/K mol x 273 K)/1 atm

V= 1143,78 liters

Answer:

The number of moles of oxygen gas comes out to be 0.0548 mole

Explanation:

Given volume of gas = V = 3.0 L

The mixture contains 30 % oxygen gas by mole.

Pressure of mixture of gas =  P = 2.0 atm

Temperature = T = 400 K

Assuming n be the total number of moles of the mixture of gas.

The ideal gas equation is shown below

[tex]\textrm{PV} = \textrm{nRT} \\2.0 \textrm{ atm}\times 3.0\textrm{ L} = n \times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1} \times 400 \textrm{ K} \\n = 0.18270 \textrm{ mole}[/tex]

The mixture contains 30% oxygen gas by mole

[tex]\textrm{ Number of moles of oxygen gas} = \displaystyle \frac{30\times 0.18270 \textrm{ mole}}{100} = 0.0548 \textrm{ mole}[/tex]

Number of moles of oxygen gas is 0.0548 mole

Final answer:

At 2.0 atm and 400 K, there are 0.9 moles of oxygen in the 3.0-L gas mixture that contains 30.% oxygen and 70.% nitrogen, as determined using the ideal gas law.

Explanation:

To calculate the number of moles of oxygen, we first need to find the total number of moles in the mixture using the ideal gas law:

n = PV / RT

where n is the number of moles, P is the pressure in atmospheres, V is the volume in liters, R is the ideal gas constant (8.31 J/mol·K), and T is the temperature in kelvins.

Substituting our values into this equation, we get:

n = (2.0 atm)(3.0 L) / (8.31 J/mol·K)(400 K) = 0.069 moles total

we need to find the fraction of moles that is oxygen:

x = (mass of oxygen) / (total mass) = (30.%)(0.069 moles total) = 0.021 moles oxygen

we can use this fraction to find the number of moles of oxygen:

n(O₂) = x(n total) = (0.021 moles oxygen) / (total moles) = (0.9 moles oxygen) / (total moles) = 0.9 moles oxygen

Residual soil and transported  soil differ by as follows:

Residual soil stays over its parent rock and transported soil forms from particles from another place.

Explanation:

Soil forms from weathering of rock. When a rocks get weathered it creates small paiticles. That forms different kind of soil. Soil varies in texture, structure, colour, composition and in pH level. Each and every soil type produced from parent rock. Depending upon the character of parent rock soil type is determined like basalt the igneous rock forms black soil.

Residual soil stays over parent rock it does not get off by the activities of natural agents like air, water, wind and glacier. Transported soil comes from hilly area to flat topped ground by transportation through some transporting agents of nature. It is immature soil.

Answer:

Celiac disease occurs in the intestines as an allergic response to Gluten in certain cereal grains.

Explanation:

Answer:

Celiac disease is genetic and if one person of the family has it you might have it too. Also if one of the parents have a certain gene and is passed on to the child the risk of celiac disease is high.

Explanation:

Hope it Helps

Answer: really hard

Explanation: I wish I knew how to help you

Water's chemical properties remain the same as it changes states from vapor to liquid to ice because it retains its molecular structure of two hydrogen atoms bonded to an oxygen atom (H₂O) throughout the transformations.

As water changes states from water vapor to liquid water, and then to ice, what remains consistent is (A) its chemical properties. This is because, in each state, water is still composed of Hydrogen and Oxygen atoms in a 2:1 ratio, represented as H₂O. Even though its physical properties like density, temperature, and appearance change, the fundamental molecular structure remains the same.

For instance, consider liquid water freezing into ice. Though the physical arrangement of the water molecules changes (which accounts for ice's unique property of being less dense than the liquid water), the water molecules themselves remain unchanged. Each water molecule is still composed of two hydrogen atoms bonded to an oxygen atom.

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Answer:

3. I don’t have a chart, but this is the

most salt per volume. It is all I have.

Explanation:

Answer:

324.6g

Explanation:

From this given problem, it is desirable to solve from the known specie to the unknown.

The balanced chemical combination is given as:

          SrBr₂   +     (NH₄)₂CO₃    →     SrCO₃   +    2NH₄Br

Given;

           2.1993 mole of (NH₄)₂CO₃  ;

Unknown:

           Mass of  SrCO₃ produced;

From the balanced equation, we see that;

                1 mole of  (NH₄)₂CO₃ reacted to produce 1 mole of   SrCO₃

                2.1993 mole of (NH₄)₂CO₃ will produce 2.1993 mole of SrCO₃

Mass of SrCO₃ produced = number of moles x molar mass of SrCO₃

Molar mass of SrCO₃ = 87.6 + 12 + 3(16) = 147.6g/mol

Mass of SrCO₃ = 2.1993 x 147.6 = 324.6g

2.1993 moles of (NH4)₂CO₃ reacted will produce approximately 324.74 grams of SrCO₃.

The question asks how many grams of SrCO3 will be produced if 2.1993 moles of (NH4)₂CO₃ are reacted according to the chemical equation:

SrBr₂ + (NH4)₂CO₃ → SrCO₃ + 2 NH₄Br

Firstly, it's essential to note that the balanced chemical equation indicates a 1:1 mole ratio between (NH4)₂CO₃ and SrCO₃. Given this ratio, the moles of (NH4)₂CO₃ reacted will equal the moles of SrCO₃ produced. Hence, 2.1993 moles of (NH4)₂CO₃ will produce 2.1993 moles of SrCO3.

The molar mass of SrCO₃ (strontium carbonate) is approximately 147.63 g/mol. To convert moles of SrCO₃ to grams, multiply the moles by the molar mass:

2.1993 moles of SrCO₃ × 147.63 g/mol = 324.74 grams of SrCO₃

Therefore, 2.1993 moles of (NH4)₂CO₃ reacted will produce approximately 324.74 grams of SrCO₃.

Answer:

B. Gas formation

Explanation:

When you combine baking soda and vinegar - which I'm assuming happened to create this reaction - it forms carbon dioxide, a gas.

The bubbling and fizzing in a science fair volcano is a result of gas formation due to the chemical reaction between baking soda and vinegar which produces carbon dioxide gas.

When a science fair volcano bubbles and fizzes, a chemical reaction takes place, specifically a gas formation. In a typical science fair volcano, baking soda (a base) and vinegar (an acid) are combined. This results in the formation of carbon dioxide gas which is what causes the 'bubbling' and 'fizzing' effect. It's a common demonstration of how some chemical reactions result in the production of gas. The gas then escapes the liquid in the form of bubbles causing the eruption we see.

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Answer:

Because it is closer to earth than the other blue giant stars.

Explanation:

The sun is closer to earth than any other big star which means we see it bigger.

Answer:

Explanation:

Sodium chromate has the chemical formula Na2CrO4, and a molar mass of 161.97 g/mol. It is a salt made of two sodium cations (Na+) and the chromate anion (CrO4-) in which the chromium atom is attached to four oxygen atoms.

Answer:

Dipole-Dipole attraction

Explanation:

Dipole-dipole attraction is a type of vander waals forces found in the molecules of sulfur dioxide.

Vander waals forces are weak attractions joining non-polar and polar molecules together. They are of two types:

London dispersion forces which are weak attractions found between non-polar molecules.

Dipole-Dipole attraction are the forces of attraction which exists between polar molecules. Such molecules have permanent dipoles. This implies that the positive pole of one molecule attracts the negative pole of another. This is what happens between the oxygen and sulfur molecules.

Answer:

Explanation:

After fossils are buried, how do they get to the surface to be discovered? That's right, the only way for those sediments to reach the surface is for them to be pushed up during the process of mountain making and then worn away by the forces of erosion.

Fossils form in sedimentary layers or rock layers from specific periods when favorable conditions permit preservation of bones, teeth, and sometimes impressions of the organism. Geological activities, such as erosion and plate tectonics, along with climate change, can eventually bring these fossils back to the surface.

Fossils, which provide solid evidence of organisms from the past, are typically found in sedimentary layers located next to bodies of water or in rock layers dating back to periods such as the Permian period. Upon death, an organism's body decomposes, leaving mostly teeth and bones, which under specific conditions can become fossilized through processes involving materials like volcanic ash, limestone, and mineralized groundwater.

Geological activity, such as erosion, weathering surface layers, and plate tectonics can eventually bring these fossils back to the surface. Climate change can also expose fossils, as seen when perennial snow covering Greenland melted to reveal geologic evidence of ancient life. These methods allow us to discover fossils of organisms ranging from bivalves and trilobites to early vertebrate bones.

The study and categorization of these fossils from all over the world allows scientists to determine when these organisms lived relative to each other, creating a fossil record that narrates the story of life's evolution on our planet.

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0.16 moles of Aluminum hydroxide are needed to react with 25 grams of sulfuric acid.

Explanation:

In order to find the number of moles we first need to write down the balanced equation as,

[tex]3 H_{2} S O_{4}+2 A l(O H)_{3} \stackrel{\text { yiek }}{\longrightarrow} \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}+6 \mathrm{H}_{2} \mathrm{O}[/tex]

Now as mentioned above,For 3 moles of sulfuric acid , we need 2 moles of Aluminum hydroxide to balance the equation,

Thus we can balance it as,

[tex]\begin{aligned}25 \mathrm{g} \text { of } \mathrm{H}_{2} \mathrm{SO}_{4} & \times \frac{1 \mathrm{mol} \text { of } \mathrm{H}_{2} \mathrm{SO}_{4}}{98.079 \frac{\mathrm{g}}{\mathrm{mol}}} \times \frac{2 \mathrm{mol} \mathrm{Al}(\mathrm{OH})_{3}}{3 \mathrm{mol} \mathrm{H}_{2} \mathrm{SO}_{4}} \\\\&=0.16 \mathrm{mol} \mathrm{Al}(\mathrm{OH})_{3}\end{aligned}[/tex]

Thus it is now clearly known that 0.16 moles of Aluminum hydroxide are needed to react with 25 grams of sulfuric acid.