Sure, what do you need help finding?
Answer:
to find a percentage of a number u multiply/divide 100
There is a sale on computers at your local Comp2u. The gaming system that you are interested in has the latest Intel Quad core processor and duel NVIDIA GeForce 9800S graphics card. The sale price on the computer is $1,500.00 plus 5.1% sales tax. Your monthly gross salary is $2,500. How much will you have saved over a two month period and will you be able to afford the computer, given your monthly expenses total $1,250, Social Security is 6.2% of your biweekly income, Medicare is 1.45% of your biweekly income, and you pay State and Federal taxes in the amount of $45.00 and $89.51 biweekly respectively?
Answer:
$1,579.44; yes
Step-by-step explanation:
The student will have saved $2500 over the two month period and will be able to afford the computer.
Explanation:In order to calculate the amount saved over a two month period, we need to calculate the monthly savings. To do this, we subtract the monthly expenses from the monthly gross salary:
$2,500 - $1,250 = $1,250
So the monthly savings is $1,250. To find the savings over a two month period, we multiply the monthly savings by 2:
$1,250 x 2 = $2,500
The cost of the computer is $1,500 plus 5.1% sales tax. To find the total cost, we multiply $1,500 by 1.051:
$1,500 x 1.051 = $1,576.50
Since the savings over a two month period is $2,500, and the total cost of the computer is $1,576.50, the student will be able to afford the computer and have savings left over.
A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are C(x) = 73,000 + 70 x and [tex]p(x) = 250 - (\frac{x}{20}), 0 \leq x \leq 5000[/tex].(A) Find the maximum revenue.
(B) Find the maximum profit, the production level that will realize the maximum profit, and the price the company should charge for each television set.
(C) If the government decides to tax the company $55 for each set it produces, how many sets should the company manufacture each month to maximize its profit? What is the maximum profit? What should the company charge for each set?
(A) The maximum revenue is $_________.
(B) The maximum profit is when sets are manufactured and sold for each.
(C) When each set is taxed at $55, the maximum profit is when sets are manufactured and sold for each.
Answer:
a) The maximum revenue is $312500
b) The maximum profit is $89000, the production level that will realize the maximum profit is 1800, and the price the company should charge for each television set is $160.
C) If the government decides to tax the company $55 for each set it produces, the sets should the company manufacture each month to maximize its profit is 1250. the maximum profit is $70825 What should the company charge for each set is $187.5
Step-by-step explanation:
a) Revenue R(x)
R(x) = p(x) * x = x * [tex](250-\frac{x}{20})[/tex] = [tex](250x-\frac{x^{2} }{20})[/tex]
For maximum revenue, the first derivative of R(x) = R'(x) = 0
R'(x) = [tex](250-\frac{2x}{20}) = 0[/tex]
[tex](250-\frac{2x}{20}) = 0\\[/tex]
[tex]250=\frac{2x}{20}[/tex]
x = 2500
the second derivative of R(x)=R''(x)
R''(x) = -1/10 which is less than 0.
Maximum revenue is at x = 2500
R(2500) = [tex](250*2500-\frac{2500^{2} }{20})=312500[/tex]
b) Profit P(x)
P(x) = R(x) - C(x) = [tex](250x-\frac{x^{2} }{20})-(73000+70x) = -73000+180x-\frac{x^{2} }{20}[/tex]
For maximum profit, the first derivative of P(x) = P'(x) = 0
P'(x) = [tex]180-\frac{2x }{20}=0[/tex]
[tex]180=\frac{2x }{20}[/tex]
x = 1800
the second derivative of P(x)=P''(x)
P''(x) = -1/10 which is less than 0.
For maximum profit, x = 1800
Therefore P(1800)[tex]=-73000+180*1800-\frac{1800^{2} }{20}[/tex] = 89000
The price the company should charge for each television set is p(1800) =[tex](250-\frac{1800}{20}) = 160[/tex]
c) f the government decides to tax the company $55 for each set it produces, the new cost C(x) = 73000 + 125x
Profit P(x)
P(x) = R(x) - C(x) = [tex](250x-\frac{x^{2} }{20})-(73000+125x) = -73000+125x-\frac{x^{2} }{20}[/tex]
For maximum profit, the first derivative of P(x) = P'(x) = 0
P'(x) = [tex]125-\frac{2x }{20}=0[/tex]
[tex]125=\frac{2x }{20}[/tex]
x = 1250
the second derivative of P(x)=P''(x)
P''(x) = -1/10 which is less than 0.
For maximum profit, x = 1250 hence 1250 sets should the company manufacture each month to maximize its profit
Therefore P(1800) =[tex]-73000+125*1250-\frac{1250^{2} }{20}[/tex] = 70825
The price the company should charge for each television set is p(1250) =[tex](250-\frac{1250}{20}) = 187.5[/tex]
A right triangle has legs with the lengths of 2 and 5, find the length of the hypotenuse
Answer Choices:
√21
√3
√7
√29
Answer:
[tex]\sqrt{29}\ units[/tex]
Step-by-step explanation:
we know that
In a right triangle
Applying the Pythagorean Theorem
[tex]c^2=a^2+b^2[/tex]
where
c is the hypotenuse (the greater side)
a and b are the legs (perpendicular sides)
In this problem we have
[tex]a=2\ units\\b=5\ units[/tex]
substitute
[tex]c^2=2^2+5^2[/tex]
[tex]c^2=29[/tex]
[tex]c=\sqrt{29}\ units[/tex]
The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated by a normal distribution with a mean value of 115 seconds and a standard deviation of 20 seconds. The fastest 10% are to be given advanced training. What task times qualify individuals for such training
The time for the fastest 10 % is less than 89.4 seconds
Here's how to find the qualifying task times:
Calculate the z-score for the 10th percentile:
A z-score represents the number of standard deviations a specific point is away from the mean. In this case, we want the z-score for the lower 10th percentile, which can be found using a z-score table or online calculators. The approximate z-score for the 10th percentile is -1.28.
Translate the z-score to task time:
We know the z-score for the 10th percentile (-1.28) and the standard deviation (20 seconds). We can use the formula to find the corresponding task time (t):
t = mean + (z-score) * standard deviation
t = 115 seconds + (-1.28) * 20 seconds
t ≈ 89.4 seconds
Therefore, task times less than 89.4 seconds qualify individuals for advanced training, as they fall within the lower 10th percentile of the normal distribution.
Complete question:
The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated by a normal distribution with a mean value of 115 sec and a standard deviation of 20 sec. The fastest 10% are to be given advanced training. What task times qualify individuals for such training? (Round the answer to one decimal place.)
A local pizza restaurant surveyed a random sample of 150 people that live in their town about their favorite type of pizza. Of the people surveyed, 40 said that pepperoni pizza was their favorite type of pizza. There are 2,800 residents that live in the town. Based on the data, is 750 a reasonable estimate for the number of residents in the town whose favorite pizza is p
Answer:
756 is a reasonable estimate because the proportion of the sample whose favorite pizza is pepperoni is about 27 %
Step-by-step explanation:
given data
random sample = 150 people
favorite pepperoni pizza = 40
total of residents = 2800
number of residents favorite pizza = 750
solution
we get here first Proportion favorite pizza that is
Proportion = [tex]\frac{40}{150}[/tex]
Proportion = 0.27 = 27%
and now we get 27% of total of residents that is = 27% × 2800
= 756
so we can say 756 is a reasonable estimate because here proportion of an sample whose favorite pizza are pepperoni pizza about 27 %
Wu rolls two fair, six-sided dice. You are not told what the rolls were, but you are told that the sum of the two rolls is a prime. What is the probability that the sum of the two rolls is $5$?
The probability of rolling a sum of 5 when rolling two fair, six-sided dice is 1/18.
Explanation:The probability that the sum of the two rolls is 5 can be found by considering the possible outcomes. There are a total of 36 equally likely outcomes when rolling two fair, six-sided dice.
Out of these, the prime sums are 5, 7, 11, and 17. The sum of 5 can only be obtained by rolling a 1 and a 4 or a 2 and
a 3. Since each die has 6 sides, the probability of rolling a 1 and a 4 is 1/6 × 1/6 = 1/36.
Similarly, the probability of rolling a 2 and a 3 is also 1/36. Therefore, the overall probability of rolling a sum of 5 is
1/36 + 1/36 = 2/36 = 1/18.
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We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty 18-20 year olds. 1. How many people would you expect to have consumed alcoholic beverages? (round to one decimal place) 2. What is the standard deviation? (round to two decimal places) 3. Would you be surprised, if there were 45 or more people who have consumed alcoholic beverages? _
Answer:
(1) The expected number of people who would have consumed alcoholic beverages is 34.9.
(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.
(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.
Step-by-step explanation:
Let X = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.
The probability of the random variable X is, p = 0.697.
A random sample of n = 50 adults in the age group 18 - 20 years is selected.
An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.
The random variable X follows a Binomial distribution with parameters n = 50 and p = 0.697.
The probability mass function of a Binomial random variable X is:
[tex]P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...[/tex]
(1)
Compute the expected value of X as follows:
[tex]E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9[/tex]
Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.
(2)
Compute the standard deviation of X as follows:
[tex]SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56[/tex]
Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.
(3)
Compute the probability of X ≥ 45 as follows:
P (X ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)
[tex]=\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006[/tex]
The probability that 45 or more have consumed alcoholic beverages is 0.0006.
An unusual or surprising event is an event that has a very low probability of success, i.e. p < 0.05.
The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.
Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.
HELP PLEASE 98 points
Given: BD¯¯¯¯¯ is an altitude of △ABC .
Prove: sinAa=sinCc
Triangle A B C with an altitude B D where D is on side A C. side A C is also labeled as small b. Side A B is also labeled as small c. Side B C is also labeled as small a. Altitude B D is labeled as small h.
Select from the drop-down menus to correctly complete the proof.
Statement Reason
BD¯¯¯¯¯ is an altitude of △ABC . Given
△ABD and △CBD are right triangles. Definition of right triangle
sinA=hc and sinC=ha
csinA=h and asinC=h
csinA=asinC
csinAac=asinCac Division Property of Equality
sinAa=sinCc Simplify.
Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
Answer:
For the people on Edge the answers are:
a/f
cf
c/b
cf + ec
c
PLEASE i need help ASAP i beg of you!! due today!!! 50 points! and brainliest!!!!!!!
1. Anthony has a sink that is shaped like a half-sphere. The sink has a volume of
660 pi in^3. One day, his sink clogged. He has to use one of two
cylindrical cups to scoop the water out of the sink. The sink is completely full
when Anthony begins scooping.
(a) One cup has a diameter of 5 in, and a height of 8 in. How many cups of
water must Anthony scoop out of the sink with this cup to empty it?
Round the number of scoops to the nearest whole number.
(b)One cup has a diameter of 10 in, and a height of 8 in. How many cups of
water must he scoop out of the sink with this cup to empty it? Round the
number of scoops to the nearest whole number.
THE ANSWER FOR CUP A IS 660 divided by 157
the answer to cup b is 660 divided by 628.319
brainliest plz
According to the Fisher effect, if a lender and a borrower would agree on an interest rate of 8 percent when no inflation is expected, they should set a rate of _______ when an inflation rate of 3 percent is expected.
Answer:
5%
Step-by-step explanation:
According to fisher equation
Nominal rate = Real rate + Inflation
N = R + I
N is calculated when there is no inflation and for the current year = 8%
The Real rate is calculated from the base year
Real rate is consider "Inflation factor" and R is unknown
Inflation rate (I) = 3%
Hence, N = R + I
8 = R + 3
R = 8 - 3
R = 5%
Jorge is setting up his tent. He is using two nylon ropes to pull the tent taut and stabilize it at each end. If the tent is 5 feet tall, and Jorge stakes the ropes into the ground 3 feet from the tent. What is the total length of nylon rope he will use,
Answer:
Total length of the Nylon rope will be 5.8 feet.
Step-by-step explanation:
Given:
Height of the tent = 5 ft
ground Distance from stake to tent = 3 ft
We need to find the Total length of the nylon rope.
Solution:
Now we can say that the total length of the nylon rope, the height of the tent, the ground distance from the stake to the tent, forms a right angle triangle.
From above we can see that;
the height of the tent, the ground distance from the stake to the tent are the two legs of the right angled triangle.
While the Total length of the nylon rope is the hypotenuse.
Now using Pythagoras theorem we get;
[tex]h^2=l_1^2+l_2^2[/tex]
[tex]l_1[/tex] ⇒ the height of the tent
[tex]l_2[/tex] ⇒ the ground distance from the stake to the tent
[tex]h[/tex] ⇒ the Total length of the nylon rope
substituting the values we get;
[tex]h^2=5^2+3^2\\\\h^2=25+9\\\\h^2=34[/tex]
Taking square root on both side we get;
[tex]\sqrt{h^2} =\sqrt{34} \\\\h=5.8\ ft[/tex]
Hence Total length of the Nylon rope will be 5.8 feet.
Answer:
Just find the hypotenuse by doing a^2 + B^2 = C^2
Step-by-step explanation:
Cole has 4 regular dice and 1 unique dice that has the value 1 on each of the 6 faces. He picks one at random and rolls 3 ones in a row. What is the probability he picked the unique dice
Answer:
0.008
Step-by-step explanation:
The probability of having chosen the unique dice three times in a row would be the multiplication of the probability of each event.
The event is always repeated. Take the single dice of 5 dice in total. Therefore the probability is 1/5.
Then the final probability would be:
(1/5) * (1/5) * (1/5), and that is equal to 0.008.
The probability that Cole picked the unique die given that he rolled three ones in a row is approximately 49.1%. This is calculated using Bayes' Theorem with the probabilities of rolling three ones with both the unique and regular dice.
Cole has 4 regular dice and 1 unique die that always rolls a 1. Let's calculate the probability that he picked the unique die given that he rolled three ones in a row.
First, find the probability of rolling three ones in a row using a regular die:
Probability of rolling a 1 on a regular die = 1/6Probability of rolling three ones in a row = (1/6) × (1/6) × (1/6) = 1/216Second, since the unique die always rolls a 1, the probability of rolling three ones in a row with it is 1.
Using Bayes' Theorem, we calculate the probability that Cole picked the unique die:
Let A be the event that Cole picked the unique die.
Let B be the event that Cole rolled three ones in a row.
P(A) = 1/5 (since there's 1 unique die out of 5 dice)P(B|A) = 1 (probability of B given A)P(B|A') = 1/216 (probability of B given not A)P(A') = 4/5 (probability of not picking the unique die)P(B) = P(B|A)P(A) + P(B|A')P(A') = 1 × (1/5) + (1/216) × (4/5)P(B) = 1/5 + 4/1080 = 0.2 + 0.0037 = 0.2037Finally, P(A|B) = (P(B|A)P(A)) / P(B) = (1 × 1/5) / 0.2037 ≈ 0.491Thus, the probability that Cole picked the unique die is approximately 0.491 or 49.1%.
A rectangle that is x feet wide is inscribed in a circle of radius 25 feet. Express the area of the rectangle as a function of x. Give the function and state its domain.
Answer:
[tex]A(x)=x(\sqrt{2500-x^{2} } )[/tex] is the area expressed as function of x,
and x: >0, <50 is the domain of the function.
Step-by-step explanation:
Draw an appropriate figure and then express the area of the rectangle as a function of x.
We know that the diagonal of a rectangle inscribed in a circle, will be equal to the diameter of the circle. 50 feet
let w = the width of the rectangle
therefore
[tex]x^2 + w^2 = 50^2\\w^2 = 2500 - x^2\\w = \sqrt{2500-x^{2} }[/tex]
recall
Area = x*w
replace w
[tex]A(x)=x(\sqrt{2500-x^{2} } )[/tex] is the area expressed as function of x
b)state the domain of the function
x: >0, <50
To find the area of the rectangle inscribed in a circle, we can use the Pythagorean theorem to find the length of the rectangle. Then, we can calculate the area by multiplying the width and length. The function that represents the area of the rectangle as a function of x is A(x) = x * sqrt(2500 - x^2), and the domain is x >= 0 and x <= 50.
Explanation:To find the area of the rectangle, we need to consider that the diagonal of the rectangle is equal to the diameter of the circle, which is twice the radius. Therefore, the diagonal measures 50 feet.
We can use the Pythagorean theorem to find the length of the rectangle. Let's denote the length as y. We have:
x^2 + y^2 = 50^2
This equation represents the relationship between the width and length of the rectangle. By solving for y, we can express the length as a function of x.
Once we have the width and length of the rectangle, we can calculate the area by multiplying them:
A = x * y = x * sqrt(50^2 - x^2)
The function that represents the area of the rectangle as a function of x is A(x) = x * sqrt(2500 - x^2). The domain of this function is x >= 0 and x <= 50.
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Find the angle of the rotations for the graphs below. The center of rotation is the origin, and the darker image is the preimage. Your answer will be 90°, 270 degrees, or 180 degrees.
Answer:
a. 90°
b. 180°
c. 180°
Step-by-step explanation:
For these problems there is a bit of a shortcut you can take. Each figure is entirely within one quadrant, and the rotation is said to be by 90° (one quadrant), 180° (two quadrants), or 270° (three quadrants) clockwise.
a. The image is in the adjacent clockwise quadrant, so rotation is 90°.
b, c. The image is in the diagonally opposite quadrant, so rotation is 180°.
Select the TRUE statements.
For the function 48(1.25)x, the parameter for the growth factor is 1.25.
For the function f(x) = 75x + 250, the parameter for the beginning value is 75.
For the function 28(0.5)x, the parameter for the decay factor is 50%.
For the function y = 18x + 72, the parameter for the average rate of change is 18.
Answer:
a) For the function [tex]48(1.25)^x[/tex], the parameter for the growth factor is 1.25
c) For the function [tex]28(0.5)^x[/tex], the parameter for the decay factor is 50%.
d) For the function y = 18x + 72, the parameter for the average rate of change is 18.
Step-by-step explanation:
We are given the following in the question:
a) the parameter for the growth factor is 1.25.
[tex]f(x) = 48(1.25)^x[/tex]
Comparing it to
[tex]y(x) = a(1+r)^x[/tex]
The growth factor is
[tex]1+r = 1.25[/tex]
Thus, the given statement is true
b) the parameter for the beginning value is 75.
We are given the equation
[tex]f(x) = 75x + 250[/tex]
The beginning value is given when x = 0. Putting value, we get
[tex]f(0) = 75(0) + 250 = 250[/tex]
Thus, the beginning value is 250.
Hence, the given statement is false.
c) the parameter for the decay factor is 50%.
[tex]f(x) = 28(0.5)^x[/tex]
Comparing it to
[tex]y(x) = a(1-r)^x[/tex]
The growth factor is
[tex]1-r = 0.5 = 50\%[/tex]
Thus, the given statement is true
d) the parameter for the average rate of change is 18.
[tex]y = 18x + 72[/tex]
Comparing to general form of equation:
[tex]y = mx + c[/tex]
where m is the slope and gives the average rate of change.
Thus, the average rate of change is 18.
Hence, the given statement is true.
Parents wish to have 160,000 available for a child's education. If the child is now 8 years old, how much money must be set aside at 3 % compounded semiannually to meet their financial goal when the child is 18?
Answer:
$118,791.2985
Step-by-step explanation:
Given that,
A = 160,000
T = 18 - 8 = 10 years
Rate = 3%
since it is semi annual, n = 2
A = P ( 1 + R/2) ∧ 2T
160000 = P ( 1 + 3/2*100) ∧ 2 * 10
160000 = P ( 1 + 3/200) ∧20
160000 = P( 1 + 0.015) ∧20
160000 = P(1.015)∧20
P= 160000/ (1.015)∧20
P = 160000/ 1.3469
= $118,791.2985
A body of water is being drained it begins with 700 gallons of water and is draining 6.5 gallons each hour .If there are now 388 gallons then for how many hours has it been draining
Answer:
Therefore it has been draining 48 hours.
Step-by-step explanation:
Given that a water body is being drained it begins with 700 gallons of water.
Let after x hours the amount of water in the water body will 388 gallons.
The water body is draining 6.5 gallons each hour
It means
The amount of water that drain in 1 hour is 6.5 gallons.
The amount of water that drain in 2 hour is (6.5+6.5) gallons.
=(2×6.5)gallons.
The amount of water that drain in 3 hour is( 6.5+6.5+6.5) gallons.
=(3×6.5) gallons.
Therefore
The amount of water that drain = time ×6.5
The amount of water that drain in x hour is (x×6.5) gallons=6.5x gallons.
Therefore the remaining water
= initial amount of water- drainage water
=(700-6.5x)gallons
According to the problem,
700-6.5x= 388
⇒ -6.5x = 388-700
⇒ - 6.5x = - 312
[tex]\Rightarrow x=\frac{-312}{-6.5}[/tex]
⇒ x= 48
Therefore it has been draining 48 hours.
x2 + y2 – 8x + 12y- 8 = 4
Answer:
3x-7y=-6
Step-by-step explanation:
Which of the following are ordered pairs for the equation y = 1/8x + 11?
(0,11) (5,12) (7,13)
(0,11) (8,12) (16,13)
(0,11) (7,13) (8,15)
(0,11) (6,12) (8,13)
Final answer:
The set of ordered pairs that correctly satisfies the equation y = 1/8x + 11 is (0,11) (8,12) (16,13). This is determined by substituting the x-values into the equation to check if the y-values correspond.
Explanation:
The question is asking which set of ordered pairs satisfies the equation y = 1/8x + 11. To determine the correct set, we will plug in the x-values from each ordered pair into the equation and see if the resulting y-value matches the one provided in the ordered pair. Let's examine each set:
(0,11) - If we plug in x=0, we get y=1/8*0+11=11. This matches the ordered pair, so (0,11) is correct.
(5,12) - With x=5, y becomes 1/8*5+11=11.625. This does not match the ordered pair (5,12), so this set is incorrect.
(7,13) - With x=7, y is 1/8*7+11=11.875. This does not match the ordered pair (7,13), so this set is also incorrect.
(8,12) - With x=8, y is 1/8*8+11=12. This matches the ordered pair, so (8,12) is correct.
(16,13) - With x=16, y is 1/8*16+11=13. This matches the ordered pair, so (16,13) is correct.
(6,12) - With x=6, y is 1/8*6+11=11.75. This does not match the ordered pair (6,12), so this set is incorrect.
(8,13) - Again, with x=8, y should be 12, not 13, so the ordered pair (8,13) is incorrect.
The only set with all matching ordered pairs for the equation y = 1/8x + 11 is (0,11) (8,12) (16,13).
5. Richard is flying a kite. The kite string makes an angle of 57 with the ground. If
Richard is standing 100 feet from the point on the ground directly below the kite, find
the length of the kite string
So
Answer: the length of the kite string is 183.6 feet
Step-by-step explanation:
The string of the kite forms an angle of 57° with the ground thus, a right angle triangle is formed. Richard's distance from the point on the ground directly below the kite represents the adjacent side of the right angle triangle. The length of the kite, h represents the hypotenuse of the right angle triangle. To determine h, we would apply the cosine trigonometric ratio.
Cos θ = adjacent side/hypotenuse. Therefore,
Cos 57 = 100/h
h = 100/Cos57
h = 100 /0.5446
h = 183.6 feet
Simplify this expression.
3^5/3^3
Answer:
3^2
Step-by-step explanation:
3^5/3^3=3^(5-3)=3^2
Answer:
[tex] \frac{ {3}^{5} }{ {3}^{3} } = {3}^{5 - 3} = {3}^{2} = 9[/tex]
Step by step explanation :
When dividing two fraction we subtract the powers if the bases are same.
fewer students can afford to attend college. Some commentators have suggested that a heightened sense of patriotism may increase military enlistments, while others think that the existence of actual hostilities may deter young people from choosing a military path. A polling organization wants to investigate what this year’s high school seniors are planning to do after they graduate.
1) During the ‘90s about 63% of high school graduates enrolled in college. The pollsters hope to estimate the percentage of this year’s seniors planning to attend college with a margin of error no greater than 4%. What size sample would suffice if they want to have 90% confidence in the estimate?
The pollsters randomly select 5 cities in Upstate New York and then randomly selected on high school in each city. The guidance office at each of the chosen schools is instructed to ask 100 randomly selected seniors what their current plans are, and to report the results back to the pollsters. The data collected from the 5 schools are summarized in the following table.
Plans
Count
College
289
Employment
112
Military
26
Other (travel, parenting, etc.)
51
Undecided / No response
22
2) Determine a 90% confidence interval for the percentage of seniors planning to go to college this year. Explain in context what your interval means. Make sure you include your checks that the conditions for inference have been met.
3) During the 90’s about 4.5% of high school seniors enlisted in the military. Do these data suggest that the percentage who enlist is different this year? Test an appropriate hypothesis and state your conclusion. Make sure you state your null and alternative hypothesis, the test statistic, the P-value, your alpha level, and your conclusion.
4) A few of the seniors did not respond to the guidance queries, and others said they were undecided. Some of the people might eventually decide to enlist in the military. Suppose that half of this small group also enlist. Would that cause you to change your conclusion in Question 3? Make sure you perform another hypothesis test and make sure you state your null, alternative hypothesis, the test statistic, the P-value, your alpha level, and your conclusion.
To estimate the percentage of seniors attending college with a 4% margin of error and 90% confidence, a sample size of 424 is needed. For constructing a confidence interval and hypothesis testing about military enlistment, various statistical formulas are applied, including adjustments for undecided responses.
Explanation:To estimate the percentage of this year’s seniors planning to attend college with a margin of error no greater than 4% and 90% confidence, we use the formula for determining sample size for a proportion, which is n = (Z^2 * p * (1-p)) / E^2, where Z is the Z-score corresponding to the confidence level, p is the estimated proportion, and E is the margin of error. With a 90% confidence level, the Z-score is approximately 1.645, and assuming we don't have a preliminary estimate, we use p = 0.5 for maximum variability, thus maximizing the required sample size.
To calculate: n = (1.645^2 * 0.5 * 0.5) / 0.04^2 = 423.3. Therefore, a sample size of 424 is required to achieve the desired margin of error and confidence level.
For the second question regarding the confidence interval for the percentage of seniors planning to go to college this year, the total sample size is the sum of students from all categories, which is 500. The proportion planning to go to college is 289/500. Using a formula for constructing a confidence interval for a proportion, C.I. = p ± (Z*sqrt(p(1-p)/n)), we can find our interval.
Testing the hypothesis regarding military enlistment involves setting up a null hypothesis (H0: p = 0.045) and an alternative hypothesis (H1: p ≠ 0.045), where p is the proportion of high school seniors enlisting in the military. The test statistic is calculated using a formula, and the P-value associated with this statistic is compared against the alpha level to decide whether to reject H0.
If considering undecided or no response students as potential enlistees changes this calculation significantly, we reassess by including an adjusted number of potential enlistees.
Amanda spent a total of 70 minutes competing her chores this week. Write and solve an equation to represent the number of minutes Amanda spent washing the dishes
Answer:
28 minutes spent in washing the dishes.
Step-by-step explanation:
Given the table
Chore time in minutes
Sweeping 42
Dishes ?
Amanda spent a total of 70 minutes competing her chores this week
Total of 70 minutes spent
42 minutes spent in sweeping . to find the number of minutes Amanda spent in washing the dishes , subtract 42 minutes from the total time spent
let x be the number of minutes spent washing the dishes
[tex]42+x=70[/tex]
To solve for x , subtract 42 from both sides
[tex]42+x=70\\x= 70-42\\x=28[/tex]
28 minutes spent in washing the dishes.
If f(x) = 2x - 4 and g(x) = x^2+3, find each value.
19. (f - g)(x)
20. (f • g)(x)
Step-by-step explanation:
[tex](f - g)(x) = f(x) - g(x) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (2x - 4) - ( {x}^{2} + 3) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2x - 4 - {x}^{2} - 3 \\ \red{ \boxed{\therefore (f - g)(x) = - {x}^{2} + 2x - 7}}[/tex]
Factor the expression. 48g2 – 22gh – 15h2
A. (6g – 5h)(8g + 3h)
B. (6g – 5)(8g + 3)
C. (6g + 5)(8g + 3h2)
D. (6g + 5h)(8g – 3h)
Answer:
A
Step-by-step explanation:
FOIL:First,Inner,Outer,Last
After the polynomial operations are done we can see that A is the answer.
6g*8g=48g^2
6g*3h=18gh
8g*-5h=-40gh
-5h*3h=-15h
After combining like terms we get :
48g^2-22gh-15h^2
The number of defects in the first five cars to come through a new production line are 9, 7, 10, 4, and 6, respectively. If the sixth car through the production line has either 3, 7, or 12 defects, for which of theses values does the mean number of defects per car for the first six cars equal the median?
I. 3
II. 7
III. 12
A. I only
B. II only
C. III only
D. I and III only
E. I, II, and III
Answer:
D
Step-by-step explanation:
Depending on the number of defects in 6th car, we have 3 cases:
3,4,6,7,9,10 (median 13/2 =6.5) 4,6,7,7,9,10 (median 14/2 = 7) 4,6,7,9,10,12 (median 16/2 = 8)To find mean we can use the sum of numbers given (= 36) and add either 3, 7, or 12 to it and then divide by 6 (number of cars).
(36 + 3) /6 = 39/6 = 6.5 (== median above)
(36 + 7) /6 = 43/6 = 7.1 (does not equal median above)
(36 + 12) /6 = 48/6 = 8 (== median above)
Answer: D (I and III only).
As a business person you need to visit each of the following cities once. You need to start in Atlanta and end in Atlanta. Use the "Nearest Neighbor" Algorithm to find one of the cheaper routes to visit each city and return home again.
Group of answer choices
A
B
C
D
Answer:
it was B
Step-by-step explanation:
The algorithm employing "Nearest Neighbour" to determine one of the cheaper routes to visit every city and get back home again would be:
B). ATL-CHI-BOS-DEN-ATL
Algorithm is described as the compilation of sequenced steps that assist in resolving a mathematical problem. This involves a step-by-step organization that assists in determining the final value post following the steps. In the given scenario, the cheaper route to visit all the given cities once and returning home again would be beginning from Atlanta via Chicago, Boston, Denver, and returning back to Atlanta.
Thus, option B is the correct answer.
Learn more about "Algorithm" here
brainly.com/question/17780739
We have two fair three-sided dice, indexed by i = 1, 2. Each die has sides labeled 1, 2, and 3. We roll the two dice independently, one roll for each die. For i = 1, 2, let the random variable Xi represent the result of the i-th die, so that Xi is uniformly distributed over the set {1, 2, 3}. Define X = X2 − X1. 1. Calculate the numerical values of following probabilities:____________. (a) P(X = 0) = (b) P(X = 1) = (c) P(X = −2) = (d) P(X = 3) = Let Y = X2 . Calculate the following probabilities:_________. (a) P(Y = 0) =(b) P(Y = 1) = (c) P(Y = 2) =
Answer:
(a) P(X = 0) = 1/3
(b) P(X = 1) = 2/9
(c) P(X = −2) = 1/9
(d) P(X = 3) = 0
(a) P(Y = 0) = 0
(b) P(Y = 1) = 1/3
(c) P(Y = 2) = 1/3
Step-by-step explanation:
Given:
- Two 3-sided fair die.
- Random Variable X_1 : Result on 1st die.
- Random Variable X_2: Result on 2nd die.
- Random Variable X = X_2 - X_1.
Solution:
- Possible outcomes of X : { - 2 , -1 , 0 ,1 , 2 }
- The corresponding probabilities for each outcome are:
( X = -2 ): { X_2 = 1 , X_1 = 3 }
P ( X = -2 ): P ( X_2 = 1 ) * P ( X_1 = 3 )
: ( 1 / 3 ) * ( 1 / 3 )
: ( 1 / 9 )
( X = -1 ): { X_2 = 1 , X_1 = 2 } + { X_2 = 2 , X_1 = 3 }
P ( X = -1 ): P ( X_2 = 1 ) * P ( X_1 = 3 ) + P ( X_2 = 2 ) * P ( X_1 = 3)
: ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )
: ( 2 / 9 )
( X = 0 ): { X_2 = 1 , X_1 = 1 } + { X_2 = 2 , X_1 = 2 } + { X_2 = 3 , X_1 = 3 }
P ( X = -1 ):3*P ( X_2 = 1 )*P ( X_1 = 1 )
: 3*( 1 / 3 ) * ( 1 / 3 )
: ( 3 / 9 ) = ( 1 / 3 )
( X = 1 ): { X_2 = 2 , X_1 = 1 } + { X_2 = 3 , X_1 = 2 }
P ( X = 1 ): 2* P ( X_2 = 2 ) * P ( X_1 = 1 )
: 2* ( 1 / 3 ) * ( 1 / 3 )
: ( 2 / 9 )
( X = 2 ): { X_2 = 1 , X_1 = 3 }
P ( X = 2 ): P ( X_2 = 3 ) * P ( X_1 = 1 )
: ( 1 / 3 ) * ( 1 / 3 )
: ( 1 / 9 )
- The distribution Y = X_2,
P(Y=0) = 0
P(Y=1) = 1/3
P(Y=2) = 1/ 3
- The probability for each number of 3 sided die is same = 1 / 3.
In this exercise we have to use the knowledge of probability to calculate the chance of an event to occur, so:
A) P(X = 0) = 1/3
B) P(X = 1) = 2/9
C) P(X = −2) = 1/9
D) P(X = 3) = 0
A) P(Y = 0) = 0
B) P(Y = 1) = 1/3
C) P(Y = 2) = 1/3
organizing the following information given in the text we have that:
Two 3-sided fair die.Random Variable X_1 : Result on 1st dieRandom Variable X_2: Result on 2nd die.Random Variable X = X_2 - X_1.Possible outcomes of X : { - 2 , -1 , 0 ,1 , 2 }Then calculating the probability we find that:
A) For P(X = 0) we have
[tex]( X = -2 ): { X_2 = 1 , X_1 = 3 } \\P ( X = -2 ): P ( X_2 = 1 ) * P ( X_1 = 3 ) \\ : ( 1 / 3 ) * ( 1 / 3 ) \\ : ( 1 / 9 )[/tex]
B) For P(X = 1) er have:
[tex]( X = -1 ): { X_2 = 1 , X_1 = 2 } + { X_2 = 2 , X_1 = 3 }\\ P ( X = -1 ): P ( X_2 = 1 ) * P ( X_1 = 3 ) + P ( X_2 = 2 ) * P ( X_1 = 3)\\ : ( 1 / 3 ) * ( 1 / 3 ) + ( 1 / 3 ) * ( 1 / 3 )\\ : ( 2 / 9 )[/tex]
C) For P(X = −2) we have:
[tex]( X = 0 ): { X_2 = 1 , X_1 = 1 } + { X_2 = 2 , X_1 = 2 } + { X_2 = 3 , X_1 = 3 }\\ P ( X = -1 ):3*P ( X_2 = 1 )*P ( X_1 = 1 )\\ : 3*( 1 / 3 ) * ( 1 / 3 )\\ : ( 3 / 9 ) = ( 1 / 3 )[/tex]
D) For P(X = 3), we have:
[tex]( X = 1 ): { X_2 = 2 , X_1 = 1 } + { X_2 = 3 , X_1 = 2 }\\ P ( X = 1 ): 2* P ( X_2 = 2 ) * P ( X_1 = 1 )\\ : 2* ( 1 / 3 ) * ( 1 / 3 )\\ : ( 2 / 9 )\\ ( X = 2 ): { X_2 = 1 , X_1 = 3 }\\ P ( X = 2 ): P ( X_2 = 3 ) * P ( X_1 = 1 ) \\ : ( 1 / 3 ) * ( 1 / 3 ) \\ : ( 1 / 9 )[/tex]
In this next case we have to take into account that the number will be the probability of falling 3, that is:
A) P(Y=0) = 0
B) P(Y=1) = 1/3
C) P(Y=2) = 1/ 3
See more about probability at brainly.com/question/795909
Scores on the Critical Reading part of the SAT exam in a recent year were roughly Normal with mean 496 and standard deviation 115. You choose an SRS of 100 students and average their SAT reading scores. If you do this many times, the mean of the average scores will be close to:_______. A. 115.
B. 115 / square root of 100 = 1.15.
C. 115 / square of 100 = 11.5.
Answer:
Option C) 115 / square of 100 = 11.5
Step-by-step explanation:
We are given the following in the question:
Mean, μ = 496
Standard Deviation, σ = 115
Sample size, n = 100
a) Mean of scores
[tex]\bar{x} = \mu = 496[/tex]
b) The standard Deviation
[tex]s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{115}{\sqrt{100}} = \dfarc{115}{10} = 11.5[/tex]
Thus, the correct answer is
Option C) 115 / square of 100 = 11.5
Answer:
Option C. 115 / square of 100 = 11.5.
Step-by-step explanation:
We are given that Scores on the Critical Reading part of the SAT exam in a recent year were roughly Normal with mean 496 and standard deviation 115.
An SRS of 100 students is chosen and average their SAT reading scores.
The z score normal probability is given by;
Z = [tex]\frac{xbar-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
So, the mean of the average scores will be close to [tex]\frac{\sigma}{\sqrt{n} }[/tex] i.e.;
= 115 / square root of 100 = [tex]\frac{115}{\sqrt{100} }[/tex] = 115/10 = 11.5
Why do we use two supply curves in the aggregate goods and services market? What is the difference between them, and why do they have different slopes?
Answer:
Supply curve vs Aggregate Supply
Step-by-step explanation:
- Supply express a direct relationship between what producers supply and how that relationship affects the price of a specific product or service. Hence, expresses a linear increase - or a constant slope
- Aggregate supply are the total supply in an economy at a particular period of time and a particular price threshold. Aggregate supply is an economy's gross domestic product (GDP), the total amount a nation produces and sells.
- Aggregate supply convey how much firms are willing to produce at a specific price point.
- Aggregate supply is a response to increasing prices that drive firms to utilize more inputs to produce more output. The incentive is that if the price of inputs remains the same but if the price of outputs increase, the firm will generate larger profits and margins by producing and selling more. The aggregate supply curve is represented by a curve that slopes upward, which indicates that as the price per unit goes up, a firm will supply more. Increasing slope - Not constant.
- The supply curve eventually becomes vertical, indicating that at a certain price point a firm cannot produce anymore, as they are limited by certain inputs, e.g. number of employees and number of factories.