Students who attend Washington Middle School are either in seventh or eighth grade. At the end of the first semester 25% of the students at Washington Middle School were on the honor roll. Seventh graders represented 60% 60 % of the students on the honor roll. If 124 124 students on the honor roll were in eighth grade, how many students attend Washington Middle School? ​ ​ There are students who attend Washington Middle School.

Answers

Answer 1

Answer:

There are 1240 students who attended Washington Middle School.

Step-by-step explanation:

Given:

Students who attend Washington Middle School are either in seventh or eighth grade.

At the end of the first semester 25% of the students at Washington Middle School were on the honor roll.

Seventh graders represented 60% of the students on the honor roll.

If 124 students on the honor roll were in eighth grade.

Now, to find the students attend Washington Middle School.

Let the total number of students be [tex]x.[/tex]

So, the students at Washington Middle School were on the honor roll:

25% of [tex]x[/tex]

[tex]=\frac{25}{100} \times x[/tex]

[tex]=\frac{25x}{100}[/tex]

[tex]=\frac{x}{4}[/tex]

As, given seventh graders represented 60% of the students.

So, the students on the honor roll represented as seventh graders:

[tex]60\%\ of\ \frac{x}{4}[/tex]

[tex]=\frac{60}{100} \times \frac{x}{4}[/tex]

[tex]=0.6\times \frac{x}{4}[/tex]

[tex]=\frac{0.6x}{4}[/tex]

As, 124 students on the honor roll were in eighth graders.

Thus,

According to question:

[tex]\frac{x}{4} -\frac{0.6x}{4} =124[/tex]

[tex]\frac{x-0.6x}{4} =124[/tex]

[tex]\frac{0.4x}{4} =124[/tex]

Multiplying both sides by 4 we get:

[tex]0.4x=496[/tex]

Dividing both sides by 0.4 we get:

[tex]x=1240.[/tex]

Therefore, there are 1240 students who attended Washington Middle School.


Related Questions

A motorcyclist heading east through a small Iowa town accelerates after he passes a signpost at x=0 marking the city limits. His acceleration is constant (4.0 m/s2). At time t =0 he is 5 m east of the signpost and has a velocity of 15 m/s. (a) find his position and velocity at time t=2 sec. (b) where is the motor cyclist when his velocity is 25 m/s?

Answers

Answer:

a) 43 m b) 55 m

Step-by-step explanation:

a) From question at t = 0, initial velocity [tex]V_{o}[/tex] = 15 m/s

   Using equation of motion, [tex]S = V_{o}t + \frac{1}{2} at^{2}[/tex] ; at t = 2 secs , a = 4 m/[tex]s^{2}[/tex]

    S = (15 x 2) + (0.5 X 4 x [tex]2^{2}[/tex])

    S = 30 + 8 = 38 m , Therefroe;

  car is (38 + 5)m from the sign post

  car is 43 m from the sign post at t = 2 secs

b) Also from equation of motion, [tex]V^{2} = V_{o} ^{2} + 2aS[/tex]

    [tex]25^{2} = 15^{2}[/tex] + (2 x 4 x S)

     625 - 225 = 8S

S = 50 m

 Car is (50 + 5) m from the sign post

Car is 55 m from the sign post at V = 25 m/s

 

Final answer:

At t=2s, the motorcyclist is at position 29m east of the signpost with a velocity of 23m/s. When his velocity is 25m/s, he is at a position 38.75m east of the signpost.

Explanation:

Given that the motorcyclist starts 5 m east of the signpost with an initial velocity of 15 m/s and a constant acceleration of 4.0 m/s2, we can use the equation of motion to find his position and velocity at any given time.

(a) At t=2s, the motorcyclist's position (x) and velocity (v) can be determined using the following two equations respectively:

Position (x) = x0 + v0*t + 0.5*a*t2 = 5 m + 15 m/s*2s + 0.5*4.0 m/s2* (2s)2 = 29 mVelocity (v) = v0 + a*t = 15 m/s + 4.0 m/s2*2s = 23 m/s

(b) When the velocity is 25 m/s, the time can be calculated using the equation v = v0 + a*t. By setting v=25m/s, v0=15m/s, and a=4.0m/s2, we get t = (25m/s-15m/s) / 4.0m/s2 = 2.5s. Substituting this time into the position equation gives x = 5m + 15m/s*2.5s + 0.5*4.0m/s2*(2.5s)2, which results in the motorcyclist being at position 38.75 m.

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These two ways of setting up a String yield identical results: a) String string = new String("123.45"); b) String string = "" + 123.45; Group of answer choices True False

Answers

Answer:

Step-by-step explanation:

Simplify.

4n + 12 + 7n  

16n + 7

23n

11n + 12

4n + 19

Kenneth measured a hotel and made a scale drawing the scale he used was 1 inch= 4 feet the actual length of a room in the hotel is 20 feel how long is the room in the drawing

Answers

Answer:

The length of the room in the drawing is 5 inches.

Step-by-step explanation:

Given:

Kenneth measured a hotel and made a scale drawing the scale he used was 1 inch= 4 feet.

The actual length of a room in the hotel is 20 feet.

Now, to find the length of the room in the drawing.

Let the length of the room in the drawing be [tex]x.[/tex]

The actual length of the room = 20 feet.

The scale used in drawing is 1 inch = 4 feet.

As, 1 inch is equivalent to 4 feet.

Thus, [tex]x[/tex] is equivalent to 20 feet.

Now, to get the length of the room in the drawing we use cross multiplication method:

[tex]\frac{1}{4} =\frac{x}{20}[/tex]

By cross multiplying we get:

[tex]20=4x[/tex]

Dividing both sides by 4 we get:

[tex]5=x[/tex]

[tex]x=5\ inches.[/tex]

Therefore, the length of the room in the drawing is 5 inches.

Significant Figures PracticeName________________________ Date_____________ Section________________
1. State the number of significant digits in each measurement. 1) 2804 m2) 2.84 km3) 5.029 m4) 0.003068 m5) 4.6 x 105 m 6) 4.06 x 10-5 m7) 750 m8) 75 m 9) 75,000 m 10) 75.00 m 11) 75,000.0 m 12) 10 cm 2. Round the following numbers as indicated:To four figures:3.68241721.860051375.6523112.51145.4673To one decimal place:1.35112.4735.6875247.5558.235To two decimal places:22.49479.25880.030623.412541.866323. Solve the following problems and report answers with appropriate number of significant digits.1) 6.201 cm + 7.4 cm + 0.68 cm +12.0 cm =
2) 1.6 km + 1.62 km +1200 km =
3) 8.264 g - 7.8 g =
4) 10.4168 m - 6.0 m =
5) 12.00 m+15.001 kg=
6) 1.31 cm x 2.3 cm =
7) 5.7621 m x 6.201 m = 8) 20.2 cm / 7.41 s =

Answers

Answer:1)2804m^2=4s.f

2)84Km^3=2s.f

3)5.029m=4s.f

4)0.00003068m=4s.f

5)4.6×10^5m=2s.f

6)4.06×10^-5m=3s.f

7)750m=3s.f

8)75m=2s.f

9)75,000.0m=5s.f

10)75.00m=2s.f

11)75,000.00m=5s.f

12)10cm=2s.t

B) to four significant figures

1)3.682

2)860100

3)375.7

4)51150

5)4673

C to 1 decimal places

1)1.4

2)4735.0

3)687524.0

4)7.6

5)235.0

Dto 2d.p

1)22.49

2)25880.00

3)30623.00

4)412541.00

5)866323.00

E)

1)6.201cm+7.4cm+0.68cm+12.0cm=26.281cm

2)1.6km+1.62km+1200km=1203.22km

3)8.264g-7.8g=0.464g

4)10.4168m-6m=4.4168m

5)12.00m+15.001kg=12.00m+15.001kg

6)1.31cm×2.3cm=3.013cm^2

7)5.7621m×6.201m=35.7308m^2

8)20.2cm/7.41s=2.726cm/s

Step-by-step explanation:

S.f means significant figures or Digits.

2)cm +kg is impossible because they are unlike termsi.e they do not have any thing in common, hence 12.00m+15.001kg cannot be added up.

Final answer:

This detailed answer involves the concept of significant figures, rounding off significant figures, and performing calculations while maintaining the appropriateness of significant figures in measurement.

Explanation:

Number of significant digits

Significance figures involve the digits in a number that carry meaningful information about its precision.

2804 m - 4 significant digits2.84 km - 3 significant digits5.029 m - 4 significant digits0.003068 m - 4 significant digits4.6 x 10^5 m - 2 significant digits4.06 x 10^-5 m - 3 significant digits750 m - 2 significant digits75 m - 2 significant digits75,000 m - 2 significant digits (trailing zeros in a whole number do not count as significant figures)75.00 m - 4 significant digits (trailing zeros in a decimal number do count as significant figures)75,000.0 m - 6 significant digits.10 cm - 1 significant digit

Rounding off to Significant Figures

To round to a certain number of significant figures, start from the first non-zero number and count the number of digits required, rounding the last one if necessary. Here are your rounded numbers:

To four figures: 3.6825; 21.86; 375.7; 112.5; 45.67.To one decimal place: 1.4; 2.5; 5.7; 248; 8.2.To two decimal places: 22.49; 79.26; 80.03; 23.41; 41.87.

Performing Calculations

In adding or subtracting numbers, the result should retain the smallest number of decimal places in the input values. In multiplication or division, the result should retain the smallest number of significant figures in the input values. Here are your answers:

6.2 cm + 7.4 cm + 0.68 cm +12.0 cm = 26.3 cm.1.6 km + 1.62 km +1200 km = 1204 km.8.264 g - 7.8 g = 0.46 g.10.4168 m - 6.0 m = 4.4 m.Cannot add metres and kilograms - invalid calculation.1.31 cm x 2.3 cm = 3.0 cm^2.5.7621 m x 6.201 m = 35.728 m^2.20.2 cm / 7.41 s = 2.7 cm/s.

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PLZ HURRY IT'S URGENT!!
Which fraction represents the ratio 9 to 6 in simplest form?


1/6

6/9

3/2

9/2

Answers

Answer:

3/2

Step-by-step explanation:

Answer:

3/2

Step-by-step explanation:

9 to 6 means  

                                                          [tex]\dfrac{9}{6}[/tex]

Now we will cancel that fraction - we will divide numerator and denominator both by 3:

9 divided by 3 equals 3

6 divided by 3 equals 2

Hence,

                                        [tex]\dfrac{9}{6} = \dfrac{3\cdot 3}{2\cdot 3} = \dfrac{3}{2}[/tex]

Maytag wants to administer a satisfaction survey to its current customers. Using their customer​ database, the company randomly selects 6060 customers and asks them about their level of satisfaction with the company. What type of sampling is​ used?
a. Simple random
b. Cluster
c. Systematic
d. Stratified
e. Convenience

Answers

Answer:

Correct answer is (a). Simple random sampling

Step-by-step explanation:

Simple random sampling (SRS) is a statistical techniques used in choosing subset of members of the population randomly without given special priority to anyone to be chosen. It gives every members of the population equal chance.

By randomly selecting 6060 customers from the customer's database, Maytag has employed Simple Random Sampling method of survey.

The ratio of the weight of an object on Mars to its weight on Earth is 9 to 25. If a person weighs 120 pounds on Earth, how much would the person weigh on Mars?

Answers

Answer:

Wm = 43.2 pounds

Step-by-step explanation:

If the ratio of the weight of an object on Mars to its weight on Earth is 9 to 25, this means that what on Mars weighs 9 units on earth weighs 25 units, therefore:

Data

ratio = 9/25

Weight on Mars (Wm) = ?

Weight on Earth (We) = 120 pound

Wm = (9/25)*120 pound = 43.2 pounds

Since the ratio of the object on Mars to Earth is 9:25 (or can be written as 9/25), it is indicated already that the person whom is 120 pounds, weighs far less on mars. Therefore, to figure out their weight, multiply the given ratio, 9/25, to 120, which will give you the answer of 43.2 pounds.

If six cookies cost the same as 2 brownies, and four brownies cost the same as 10 cupcakes, how many cupcakes can Bob buy for the price of eighteen cookies?

Answers

Bob can buy 15 cupcakes for the price of 18 cookies.

Step-by-step explanation:

Assume the cost of a cookie is $x, the cost of a brownie is $y and the cost of a cupcake is $z.It is given that 6 cookies and 2 brownies cost the same, so 6x = 2y, take this as equation 1.It is also given that 4 brownies cost the same as 10 cupcakes, so           4y = 10z, take this as equation 2.If we divide equation 2 by 2 we get, 2y = 5z so that the y value is the same as equation 1 and we can equate equation 1 and 3.We get 6x = 2y = 5z, 6x = 5z, dividing both sides by 5, we get  1.2x = z.We need to calculate how many cupcakes Bob can buy for the price of 18 cookies, So we must find the z value when the x = 18.If we multiply 1.2 with 15 we get 18 so we the last equation is multiplied with 12 so that 18x = 15z. 18 cookies and 15 cupcakes cost the same.

PLEASE HELPPP!!! QUESTION AND ANSWERS IN PICTURE !

Answers

answer is C: [tex]\frac{EF}{DF}[/tex]

Answer:option C is the correct answer

Step-by-step explanation:

Triangle DEF is a right angle triangle.

From the given right angle triangle,

DF represents the hypotenuse of the right angle triangle.

With m∠θ as the reference angle,

EF represents the adjacent side of the right angle triangle.

DE represents the opposite side of the right angle triangle.

To determine Cos ∠θ, we would apply

the cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos θ = EF/DF

A researcher records the family relationship (brother, son, father, cousin, etc.) of the

people who stay in regular contact with loved ones in a nursing home. What type of measure

is family relationship?

A) Quantitative and discrete

B) Qualitative and discrete

C) Qualitative and continuous

D) Quantitative and continuous

Answers

Answer:

The correct option is B) Qualitative and discrete.

Step-by-step explanation:

Consider the provided information.

Quantitative variable is the variables that can be determined by counting or measuring something.

Qualitative variable is the variables that can't be determined by counting or measuring something.

If the value is obtained by counting then it is called discrete variable, If the value obtained by measuring then it is called continuous variable.

Since the relationship can't be measure by counting so it it qualitative variable.

We can calculate the regular contact days so it is discrete variable.

Therefore, the correct option is B) Qualitative and discrete.

PLZ HELP THIS IS TIMED!!!!
Which formula can be used to describe the sequence? Negative two-thirds, −4, −24, −144,... f(x) = 6(negative two-thirds) Superscript x minus 1 f(x) = −6(Two-thirds) Superscript x minus 1 f(x) = Negative two-thirds(6)x − 1 f(x) = Two-thirds(−6)x − 1

Answers

Answer:

For the sequence is [tex]-\frac{2}{3}[/tex] ,-4 ,-24 ,-144 ,...

Hence the formula [tex]f(x)=-\frac{2}{3}(6)^{x-1}[/tex] for x=1,2,3,... represents the given geometric sequence

Step-by-step explanation:

Given sequence is [tex]-\frac{2}{3}[/tex] ,-4 ,-24 ,-144 ,...

To find the formula to describe the given sequence :

Let [tex]a_1=\frac{-2}{3}[/tex] ,[tex]a_2=-4[/tex] ,[tex]a_3=-24[/tex],...

First find the common ratio

[tex]r=\frac{a_2}{a_1}[/tex] here  [tex]a_1=\frac{-2}{3}[/tex] and,[tex]a_2=-4[/tex]

[tex]=\frac{-4}{\frac{-2}{3}}[/tex]

[tex]=\frac{4\times 3}{2}[/tex]

[tex]=\frac{12}{2}[/tex]

[tex]r=6[/tex]

[tex]r=\frac{a_3}{a_2}[/tex] here  [tex]a_2=-4[/tex] and [tex]a_3=-24[/tex]

[tex]=\frac{-24}{-4}[/tex]

[tex]=6[/tex]

[tex]r=6[/tex]

Therefore the common ratio is 6

Therefore the given sequence is geometric sequence

The nth term of the geometric sequence is

[tex]a_n=a_1r^{n-1}[/tex]

The formula which describes the given geometric sequence is

[tex]f(x)=a_1r^{x-1}[/tex] for x=1,2,3,...

[tex]=\frac{-2}{3}6^{x-1}[/tex] for x=1,2,3,...

Now verify that [tex]f(x)=a_1r^{x-1}[/tex] for x=1,2,3,... represents the given geometric sequence or not

put x=1 and the value of [tex]a_1[/tex] in [tex]f(x)=a_1r^{x-1}[/tex] for x=1,2,3,...

we get [tex]f(1)=-\frac{2}{3}(6)^{1-1}[/tex]

[tex]=-\frac{2}{3}(6)^0[/tex]

[tex]=-\frac{2}{3}[/tex]

Therefore [tex]f(1)=-\frac{2}{3}[/tex]

put x=2 we get [tex]f(2)=-\frac{2}{3}(6)^{2-1}[/tex]

[tex]=-\frac{2}{3}(6)^1[/tex]

[tex]=-\frac{12}{3}[/tex]

Therefore [tex]f(2)=-4[/tex]

put x=3 we get [tex]f(3)=-\frac{2}{3}(6)^{3-1}[/tex]

[tex]=-\frac{2}{3}(6)^2[/tex]

[tex]=-\frac{2(36)}{3}[/tex]

Therefore [tex]f(3)=-24[/tex]

Therefore the sequence is f(1),f(2),f(3),...

Therefore  the sequence is [tex]-\frac{2}{3}[/tex] ,-4 ,-24 ,-144 ,...

Hence the formula [tex]f(x)=a_1r^{x-1}[/tex] for x=1,2,3,... represents the given geometric sequence is verified

Therefore the formula [tex]f(x)=-\frac{2}{3}(6)^{x-1}[/tex] for x=1,2,3,... represents the given geometric sequence

Answer:

a

Step-by-step explanation:

Which of the following is the image of the point for the given rotation, r (120°) (F)?

Answers

Answer:

B

Step-by-step explanation:

360/6

6 is number of sides

You get 60

Rotate twice to reach 120

Moving F Counter clockwise twice is where B was

The image of point F after the rotation of 120°, r(120°), will be point B.

Which point will represent the given rotation of F?

So, we need to rotate point F a total angle of 120°.

As you can see, in the image we have 6 sections, and equally distributed in these 6 sections we will have an angle of 360° (a complete rotation). So each section has an angle of:

360°/6 = 60°.

Then a rotation of 120°  (two times 60°) will rotate the point F two sections counterclockwise. Then the image of the point after the rotation will be point B.

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TRY IT! Simplity
x(x + 5)
2x2 - 50

Answers

x(x+5) is equal to x exponent 2 +5x

A jar contains 11 green marbles, 7 red marbles, and 6 blue marbles. A marble is selected at random, not replaced, and then a second marble is selected. What is the probability of selecting a blue marble followed by a green marble?
Write In a fraction.

Answers

Answer:

11/92

Step-by-step explanation:

G = 11

R = 7

B = 6

P(b) = 6/24 = 1/4

P(g) = 11/23

P(blue first and then green(without replacement)) = 1/4 * 11/23

= 11/92

Final answer:

The probability of randomly selecting a blue marble followed by a green marble from a jar of 24 marbles (6 blue, 7 red, 11 green) is 11/92.

Explanation:

The number of outcomes considered favorable or desired is compared to the total number of outcomes possible. In this situation, we're interested in choosing a blue marble first, then a green marble. The total number of marbles is 11 green + 7 red + 6 blue = 24 marbles.

Initially, the probability of selecting a blue marble is 6/24 = 1/4

because there are 6 blue marbles out of a total of 24.

After taking one marble out (assuming it's blue), you have 23 marbles left, with 11 of them being green. So, the probability of selecting a green marble next is 11/23.

Therefore, the probability of both of these events happening (selecting a blue marble followed by a green marble) is found by multiplying these two probabilities together, which gives (1/4) * (11/23) = 11/92.

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Please help, I was absent for this day so I don't know how to do this.

Answers

Answer:

Step-by-step explanation:

An arc is a portion of the circle's circumference bounded by 2 radii

The formula for determining the length of an arc is expressed as

Length of arc = θ/360 × 2πr

Where

θ represents the central angle or angle which the 2 radii subtends at the center of the circle.

r represents the radius of the circle.

π is a constant whose value is 3.14

From the information given,

Radius, r = 5 inches

θ = 170 degrees

Therefore,

Length of arc = 170/360 × 2 × π × 5

Length of arc = 4.7222π feet

rounding up to 2 decimal places, it becomes

4.72π feet

You are designing a staircase to reach a second floor that is 113" above the ground floor of a building. The owner of the building wants you to make a staircase as close as possible to a 7.25" rise to meet their specifications

Answers

Answer:

Step-by-step explanation:

total height, H = 113 inches

height of each stair case, h = 7.25 inches

Number of stair case, n = total height / height of each stair case

n = 113 / 7.25 = 15.6

Right △EFG has its right angle at G, EF=8 , and FG=6 .

What is the value of the trigonometric ratio of an angle of the triangle?

Drag a value to each box to match the trigonometric ratio with its value.

Answers

Answer:

[tex]sec\ E = \frac{4\sqrt{7} }{7}[/tex]

[tex]Cos\ F = \frac{3}{4}[/tex]

[tex]Tan\ F =\frac{\sqrt{7}}{3}[/tex]

Step-by-step explanation:

Given

EF = 8

FG = 6

We need to find the trigonometric ratios.

Solution:

First we will find the length of the third side.

Now we know that;

△EFG is a right angled triangle with right angle at G.

Now applying Pythagoras theorem which states.

"The sum of square of the two legs of the triangle is equal to square of the hypotenuse."

so we can say that;

[tex]FG^2=EF^2+EG^2\\\\EG^2=FG^2-EF^2[/tex]

Substituting the given values we get;

[tex]EG^2=8^2-6^2=64-36=28[/tex]

Taking square roots on both side we get;

[tex]\sqrt{EG^2} =\sqrt{28}=\sqrt{4\times7}\\ \\EG = 2\sqrt{7}[/tex]

Now we will find the trigonometric values.

[tex]secE=\frac{Hypotenuse}{Adjacent\ side}[/tex]

Here Hypotenuse = EF = 8

Adjacent side of E = EG = [tex]2\sqrt{7}[/tex]

[tex]secE=\frac{8}{2\sqrt{7}} =\frac{4}{\sqrt{7}}[/tex]

Now rationalizing the denominator by multiplying numerator and denominator by [tex]\sqrt{7}[/tex] we get;

[tex]secE=\frac{4\times \sqrt{7} }{\sqrt{7}\times \sqrt{7} }\\\\secE = \frac{4\sqrt{7} }{7}[/tex]

Now,

[tex]Cos F = \frac{Adjacent \ side}{Hypotenuse}[/tex]

Adjacent side to F =GF = 6

Hypotenuse = EF = 8

[tex]Cos\ F = \frac{6}{8}\\\\Cos\ F = \frac{3}{4}[/tex]

Now,

[tex]Tan F = \frac{opposite \ side}{adjacent\ side}[/tex]

Here Opposite side of F = EG = [tex]2\sqrt{7}[/tex]

Adjacent side of F = GF = 6

[tex]Tan\ F= \frac{2\sqrt{7}}{6}\\\\Tan\ F =\frac{\sqrt{7}}{3}[/tex]

Hence Below are required details.

[tex]sec\ E = \frac{4\sqrt{7} }{7}[/tex]

[tex]Cos\ F = \frac{3}{4}[/tex]

[tex]Tan\ F =\frac{\sqrt{7}}{3}[/tex]

The value of the trigonometric ratio of an angle of the triangle is;

[tex]\rm SecE=\dfrac{8}{2\sqrt{7}}=\dfrac{4}{\sqrt{7} }\\\\CosF = \dfrac{6}{8}=\dfrac{3}{4}\\\\Tan F =\dfrac{2\sqrt{7}}{3}=\dfrac{\sqrt{7} }{3}\\[/tex]

Given

Right △EFG has its right angle at G, EF=8, and FG=6.

Pythagoras theorem

The Pythagoras theorem states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of the other two sides of the right-angled triangle.

In right-angle △EFG, in which E is a right angle.

[tex]\rm EF^2=FG^2-EG^2\\\\8^2=6^2-EG^2\\\\EG^2=8^2-6^2\\ \\EG^2=64-36\\\\EG^2=28\\\\EG = 2\sqrt{7}[/tex]

The value of the trigonometric ratio of an angle of the triangle is;

[tex]\rm SecE=\dfrac{8}{2\sqrt{7}}=\dfrac{4}{\sqrt{7} }\\\\CosF = \dfrac{6}{8}=\dfrac{3}{4}\\\\Tan F =\dfrac{2\sqrt{7}}{3}=\dfrac{\sqrt{7} }{3}\\[/tex]

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Use differentiation to show that the given function is a solution of the equation for all values of the constants. (Enter your answers in terms of x.) equation: x'' + x = 2et, function x = C1 sin(t) + C2 cos(t) + et

Answers

Answer with Step-by-step explanation:

We are given that

DE

[tex]x''+x=2e^t[/tex]

Function:[tex]x=C_1sint+C_2cost+e^t[/tex]

We have to show that given function is  a solution of the equation for all values of the constants.

If given function is  solution of DE then it satisfied the given DE.

Differentiate  function w.r.t.t

[tex]x'=C_1cost-C_2sint+e^t[/tex]

Again differentiate w.r.t. t

[tex]x''=-C_1sint-C_2cost+e^t[/tex]

Substitute the values in the given DE

[tex]-C_1sint-C_2cost+e^t+C_1sint+C_2cost+e^t=2e^t[/tex]

LHS=RHS

Given function satisfied the given DE.Therefore, it is solution of given DE for all values of the constants.

How do you do this problem?

Answers

Answer:

A) g is increasing, and the graph of g is concave up.

Step-by-step explanation:

g'(x) = ∫₀ˣ e^(-t³) dt

Since e^(-t³) is always positive, ∫₀ˣ e^(-t³) dt is positive when x > 0.  So the function is increasing.

Find g"(x) by taking the derivative using second fundamental theorem of calculus:

g"(x) = e^(-x³)

g"(x) is always positive, so the function is always concave up.

Help plz if you know this then plz answer back! How do you solve (x to the power of -1) (x to the power of -5) The lesson is multiplying and dividing expressions with exponents.

Answers

Answer:

(x⁻¹)(x⁻⁵) = x⁻⁶

Step-by-step explanation:

When multiplying number with the same base, you add up their exponent.

(x⁻¹)(x⁻⁵) =

= x⁽⁻¹⁾ ⁺ ⁽⁻⁵⁾

= x⁻⁶

you can also write x⁻⁶ as 1/x⁶. The negative sign in the exponent just flip the numerator and denominator with each others.

Answer:

The answer to your question is   x⁻⁶ or 1/x⁶

Step-by-step explanation:

Multiplying exponents

-To multiply exponents they must have the same base and the result will be the base and the exponents will add.

Ex

              (a³)(a²)

base = a

exponents = 3 and 2

result     a³ ⁺ ²  = a⁵

In your question

             (x⁻¹)(x⁻⁵) = x⁻¹⁻⁵ = x⁻⁶ = 1/x⁻⁶

Please help me, Geometry is really hard for me.

Answers

Answer:

Step-by-step explanation:

the answers c.

How many days are there in one month? It is measured in the
A. thousands
B. tens
O ooo
c. ones
D. hundreds

Answers

I would guess the ones? That’s kind of a weird question lol

Tens is the correct answer

The explicit formula for a sequence is

an=−1+3(n−1)

What is the 55th term of the sequence?

Answers

Step-by-step explanation:

[tex] \because \: a_n = - 1 + 3(n - 1) \\ \\ \therefore \: a_{55} = - 1 + 3(55 - 1) \\ \\ \therefore \: a_{55} = - 1 + 3 \times 54 \\ \\ \therefore \: a_{55} = - 1 + 162\\ \\ \huge \blue { \boxed{\therefore \: a_{55} = 161}}\\ \\ [/tex]

Hence, the 55th term of the sequence is 161.

FIND THE INVERSE OF -5 + 7i

Answers

Answer:

Additive inverses for complex numbers are just like they are for real numbers: they mean the number you'd add to get back to 0. Just like real numbers, this means that you change the signs. Thus, the additive inverse of -4+7i is 4-7i

hope it helps

Step-by-step explanation:

The Sweet Shoppe wishes to sell a special mix for Valentine’s Day that consists of Dark Chocolate that costs $4.00 per lb and Milk Chocolate that costs $2.00 per lb. How much of each should be used to get a 50 lb mix that costs $2.60 per lb?

Answers

Answer: Quantity of Dark Chocolate used = 15 lb

 Quantity of Milk Chocolate used  = 35 lb

Step-by-step explanation:

Let x = Quantity of Dark Chocolate.

y =  Quantity of Milk Chocolate.

As per given , we have the following system of equations:

[tex]x+y= 50-------------(1)\\\\ 4x+2y=50\times2.60\\\\ 4x+2y=130-----------(2)[/tex]

Multiply equation (1) by 2 , we get

[tex]2x+2y= 100-------(3)[/tex]

Eliminate equation (3) from equation (2) , we get

[tex]2x=30\\\Rightarrow\ x=15[/tex]

Put x= 15 in (1) , we get [tex]15+y=50[/tex]

⇒ y=35

Therefore , Quantity of Dark Chocolate used = 15 lb

 Quantity of Milk Chocolate used  = 35 lb

In AABC, 2B= 2C, and m_A= 349. Find mzo
A. 56°
B. 730
c. 112°
1460

Answers

Answer:

i think it' =-8abc(a+b-c)

Step-by-step explanation:

If you were going to apply statistical methods to analyze teacher evaluations, which question form, A or B, would be better? Form A: In your own words, tell how this teacher compares with other teachers you have had. Form B: Use the following scale to rank your teacher as compared with other teachers you have had.a. Form B would be better because statistical methods can be applied to the ordinal data. b. Form B would be better because statistical methods can be applied to the nominal data. c. Form A would be better because statistical methods can be applied to the nominal data. e. Form A would be better because statistical methods can be applied to the ordinal data.

Answers

Answer:

a. Form B would be better because statistical methods can be applied to the ordinal data.

Step-by-step explanation:

Ordinal data can be ranked. This teacher evaluation can be ranked on a scale of 1-10 for example. Ordinal data can  provide good information about the choice of the person who is responding. And these informations are quantitative in nature.

The longest human power sporting event is the tour de France cycling race in a particular year the average speed for the winner of the this race was 23.66 mph in that same year of the race was 2292 miles long how long did it take the winner to complete the race

Answers

Answer:

The winner completed the race in 96 hours and 52 minutes.

Step-by-step explanation:

Given:

Distance of the cycling race = 2292 miles

Average speed of the winner = [tex]23.66\ mph[/tex]

We need to find time required by winner to complete the race.

Solution:

Now we know that;

Time required can be calculated by dividing Total Distance from the Average speed.

framing in equation form we get;

time required by winner to complete the race = [tex]\frac{2292}{23.66} = 96.87\ hrs[/tex]

Now converting [tex]0.87\ hrs[/tex] into minutes we get;

[tex]0.87\times 60= 52.2\approx 52\ mins[/tex]

Hence the winner completed the race in 96 hours and 52 minutes.

The variables x and y are proportional.Use the vaules to find the constant aof proportonality.Then write the equation that relates x and y. When y=72, and x=3

Answers

Answer:

Constant of proportionality = 24

Equation: [tex]y=24x[/tex]

Step-by-step explanation:

Given:

'x' and 'y' are proportional to each other.

At [tex]x=3,y=72[/tex]

Now, for a proportional relationship, the constant of proportionality is given as the ratio of the two values of the two variables that are in proportion.

Here, 'x' and 'y' are in proportion. So, the constant of proportionality is given as:

[tex]k=\frac{y}{x}\\\\k=\frac{72}{3}=24[/tex]

Therefore, the constant of proportionality is 24.

Now, a proportional relationship in 'x' and 'y' is given as:

[tex]y=kx[/tex]

Now, plug in the given value of 'k' and complete the equation. This gives,

[tex]y=24x[/tex]

Therefore, the equation that relates 'x' and 'y' is [tex]y=24x[/tex]

Alden paid to have some programs printed for the football game last weekend. The printing cost per program was 54 cents, and the plan was to sell them for 75 cents each. Poor weather kept many fans away from the game, however, so unlucky Alden was left with 100 unsold copies, and lost $12 on the venture. How many programs did Alden have printed?

Answers

Answer:

300 programs

Step-by-step explanation:

Let’s work with cents to make this easier. We convert the $12 to cents, making 1200 cents

Let the number of copies Alden printed be x. His total printing cost would be x * 54 = 54x cents.

He sold at 75 cents each and still had left 100 copies. This means his total sale would be (x - 100)75

He lost $12 on the venture. This means his cost price minus his selling price is $12 since it’s a loss.

Computing this:

54x - 75(x - 100) = 1200

54x - 75x + 7500 = 1200

-21x = 1200 - 7500

-21x = -6,300

x = 6300/21 = 300 programs

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