QUESTION 1: Using the experimental data, calculate the standard reduction potential for each metal, and organise them into a standard reduction table. Assume E° for B is 0V.
QUESTION 2: Deduce which two metals would produce the highest cell potential in a galvanic cell. Give reasons for your conclusion.
Answers
Final answer:
To calculate the standard reduction potential for each metal and organize them into a standard reduction table, we can use the formula Ecell = Ered - Eox. The standard potential for Q is -0.38V and for G is +0.72V.
Explanation:
To calculate the standard reduction potential for each metal, we can use the formula Ecell = Ered - Eox. Given the reduction potentials for Q and G, we can assume the reduction potential for Q is +0.38V and the reduction potential for G is -0.72V. Since Q is oxidized when connected to the standard hydrogen electrode, its standard potential is negative (-0.38V). On the other hand, since G is reduced when connected to the standard hydrogen electrode, its standard potential is positive (+0.72V).
Organizing the metals into a standard reduction table:
MetalStandard Reduction Potential (E°)Q-0.38VG+0.72V
Metal B has the highest standard reduction potential (0.85 V), and metal E follows closely (0.63 V). B-E galvanic cell would yield the highest potential due to their strong reduction tendencies.
To calculate the standard reduction potential for each metal, you can use the Nernst equation:
[tex]E_{\text {cell }}^{\circ}=E_{\text {cathode }}^{\circ}-E_{\text {anode }}^{\circ}[/tex]
where [tex]E_{\text {cell }}^{\circ}[/tex] is the standard cell potential, [tex]E_{\text {cathode }}^{\circ}[/tex] is the standard reduction potential of the cathode, and [tex]E_{\text {anode }}^{\circ}[/tex] is the standard oxidation potential of the anode.
First, let's assign oxidation numbers and write the balanced half-reactions for each cell:
1. [tex]\mathrm{A}(\mathrm{s})+\mathrm{B}^{2+}(\mathrm{aq}) \rightarrow \mathrm{A}^{2+}(\mathrm{aq})+\mathrm{B}(\mathrm{s})[/tex]
Reduction half-reaction: [tex]\mathrm{B}^{2+}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{B}(\mathrm{s})[/tex]
[tex]E_{\text {cathode }}^{\circ}[/tex] = 0.85
[tex]E_{\text {anode }}^{\circ}[/tex] = 0
2. [tex]\mathrm{B}^{2+}(\mathrm{aq})+\mathrm{C}(\mathrm{aq}) \rightarrow \mathrm{B}(\mathrm{s})+\mathrm{C}^{2+}(\mathrm{aq})[/tex]
Reduction half-reaction: [tex]\mathrm{C}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{C}^{2+}(\mathrm{aq})[/tex]
[tex]E_{\text {cathode }}^{\circ}[/tex] = −0.24
[tex]E_{\text {anode }}^{\circ}[/tex] = 0
3. [tex]2 \mathrm{D}^{+}(\mathrm{aq})+\mathrm{C}(\mathrm{s}) \rightarrow 2 \mathrm{D}(\mathrm{s})+\mathrm{C}^{2+}(\mathrm{aq})[/tex]
Reduction half-reaction: [tex]\mathrm{C}(\mathrm{s})+2 e^{-} \rightarrow \mathrm{C}^{2+}(\mathrm{aq})[/tex]
[tex]E_{\text {cathode }}^{\circ}[/tex] = 0
[tex]E_{\text {anode }}^{\circ}[/tex] = 0.58
4. [tex]\mathrm{B}(\mathrm{s})+\mathrm{B}^{2+}(\mathrm{aq}) \rightarrow \mathrm{B}^{2+}(\mathrm{aq})+\mathrm{B}(\mathrm{s})[/tex]
Reduction half-reaction: [tex]\mathrm{B}^{2+}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{B}(\mathrm{s})[/tex]
[tex]E_{\text {cathode }}^{\circ}[/tex] = 0
[tex]E_{\text {anode }}^{\circ}[/tex] = 0
5. [tex]\mathrm{B}(\mathrm{s})+\mathrm{E}^{2+}(\mathrm{aq}) \rightarrow \mathrm{B}^{2+}(\mathrm{aq})+\mathrm{E}(\mathrm{s})[/tex]
Reduction half-reaction: [tex]\mathrm{E}^{2+}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{E}(\mathrm{s})[/tex]
[tex]E_{\text {cathode }}^{\circ}[/tex] = 0.63
[tex]E_{\text {anode }}^{\circ}[/tex] = 0
Now, let's calculate the standard reduction potentials for each metal:
[tex]\begin{aligned}& E_{\mathrm{B}}^{\circ}=0.85-0=0.85 \\& E_{\mathrm{C}}^{\circ}=-0.24-0=-0.24 \\& E_{\mathrm{D}}^{\circ}=0-0.58=-0.58 \\& E_{\mathrm{B}}^{\circ}=0 \\& E_{\mathrm{E}}^{\circ}=0.63-0=0.63\end{aligned}[/tex]
The two metals that would produce the highest cell potential in a galvanic cell are the ones with the highest standard reduction potentials. In this case, metals B and E have the highest reduction potentials, so a galvanic cell composed of B and E would have the highest cell potential. The reason is that a higher standard reduction potential indicates a stronger tendency to be reduced, and therefore, a higher cell potential in a galvanic cell.
Related Questions
What is required in order to determine whether or not an object moves?
a reference point
distance
Odisplacement
standard units
Mark this and return
Save and Exit
Save and Exit
Next
Next
Subenit
Answers
The correct answer is a reference point.
To determine whether or not an object moves, one must have a reference point. A reference point is a fixed point that is used to determine if an object has changed its position. Without a reference point, it is impossible to ascertain whether an object is moving or at rest because motion is relative. An object may appear to be moving when observed from one reference point, but it could be stationary when observed from a different reference point.
Distance alone does not indicate motion; it only specifies the amount of space between two points. Displacement is the change in position of an object, which requires a reference point to be measured. Standard units are necessary for quantifying distance or displacement but do not themselves indicate motion.
In summary, while distance, displacement, and standard units are important for describing the motion of an object, a reference point is the fundamental requirement to determine whether an object is moving.
Explain how thermal energy added to a sample of matter affects the motion of the particles?
Answers
Answer:
When heat is added to a substance the molecules and atoms vibrate faster. As atoms vibrate faster the space between atoms increases. The motion spacing of the particles determines the state of matter of the substance. The end result of increased molecule emotion is that the object expands and takes up more space.
Convert
375 m/s to ft/min
Answers
Answer:
73818.9
Explanation:
for an approximate result, multiply the speed value by 197
A sample of gas has a volume of 3.75 L at a temperature of 25°C and a pressure of 1.15 atm. What will the volume be at a temperature of 35°C and a pressure of 620 torr?
Answers
Answer: V = 5.1 L
Explanation: To find the new volume, we will use the formula of Combined Gas Law and derive V2. We also need to convert first the temperature in Kelvin and convert torr to atm ( 1 atm = 760 torrs ).
Solution attached.
Definition: For all real numbers a, b, and c: if a=b, then a + c = b + c. This is the ____ ____ of Equality.
Answers
Answer: Addition Property of Equality
Explanation:
The addition property of equality says that if we add same value or quantity on both sides of an equation, the values on both the sides remain equal. Consider an equality a = b. Addition property of equality is a + x = b + x. Add the same number to both the sides of an equation.
Steve works at a gas station in an urban area. He is constantly exposed to particulate material emitted from vehicles. For this reason, Steve is likely to suffer from which of these? A. asthma B. obesity C. diabetes D. hearing defect
Answers
Answer:
asthma
Explanation:
asthma is a respiratory problem which causes difficulty in breathing which is usually because of allergic reactions or hypersensitivity to something else. so as it's written in the question that materials are emitted from vehicles, there is a big chance that they will cause an allergic reactions (asthma) in Steve.
Which of the following will result from increasing the temperature of a gas?
O
A. The number of gas molecules will increase.
O
B. The molecules will be forced into a smaller space together.
O
C. The molecules will slow down.
O
D. The volume of the gas will increase.
Answers
Answer:
The correct answer is D) The volume of the gas will increase.
Explanation:
According to Charles's Law, at constant pressure, as the temperature (T) of a gas increases, the volume (V) increases and vice versa. This is observed according to the formula:
V1 / T1 = V2 / T2
Explain why groups 14 and 15 are better representatives of mixed groups than groups 13 and 16.
Answers
Answer:
Explanation:
Mixed groups are groups on the periodic table that contain more than one class (as in metals, non-metals or metalloids) of elements. Groups 13 to 16 form the mixed groups of the periodic table because they contain at least two different classes of elements.
However, groups 14 and 15 contain more classes (three classes) than groups 13 and 16 (two classes). Group-14 contains metals (examples include tin), non-metals (examples include carbon) and metalloids (examples include silicon) while group-15 also contains metals (such as bismuth), non-metals (such as nitrogen) and metalloids (such as arsenic). Whereas group 13 and 16 only contain two classes of elements; group-13 contains metalloid (boron) and metals (such as aluminium) while group-16 contains metalloids (such as tellurium) and non-metals (such as oxygen).
Final answer:
Groups 14 and 15 exemplify a broad range of chemical behaviors, including metal, nonmetal, and metalloid elements, making them more representative of mixed groups than Groups 13 and 16.
Explanation:
Groups 14 and 15 are better representatives of mixed groups than groups 13 and 16 because they include both metals and nonmetals, thus displaying a wider range of physical and chemical properties. Groups 14 and 15, which include the carbon group and the pnictogens, respectively, have elements that are essential to life and industry and exhibit diverse chemical behaviors. Lewis structures show that these groups can form neutral compounds with four and three bonded atoms, respectively, reflecting a trend where the number of bonds decreases across the period. In contrast, Group 13 elements are largely metals and Group 16 elements are largely nonmetals or metalloids, showing less diversity.
How many grams of sodium sulfide are formed in 1.6 g of hydrogen sulfide is bubbled into a solution containing 2.13 g of sodium‘s hydroxide assuming that the sodium sulfite is made and 94% yield?
Answers
Answer:
Find the Molar mass of each, find the limiting reagent, if there is one, and then multiply by .94. This is the quick way.
Explanation:
Which sample of ocean water would be the most likely to have the highest salinity?
Ocean water taken from the surface of the ocean
The warmest sample of ocean water
The ocean water taken from an area near the polar ice caps
Ocean water taken from the bottom of the ocean
Answers
Answer:
Ocean water taken from the surface of the ocean
Explanation:
Attached is a plot of ocean salinity vs. depth. It shows the highest salinity ocean water is surface water. A world-wide map of ocean salinity shows the highest salinity to be in mid-latitude regions in the middle of the ocean. Water near the North Pole has lower salinity than that for lower latitudes.
Probably the main reason for higher salinity at the surface is the high evaporation rate of water there, leaving behind the salt.
COMPLETE
How many grams of CaCl2 are in 250 mL of 2.0 M CaCl2?
Answers
Answer:
There are 55, 49 g of CaCl2
Explanation:
We calculate the weight of 1 mol of CaCl2:
Weight CaCl2=Weight Ca + 2x(Weight Cl)= 40,08g+ 2x 35, 45g=110,98 g/mol
1000ml-----2 mol of CaCl2
250ml------x= (250 ml x 2 mol of CaCl2)/1000ml= 0,5 mol of CaCl2
1mol -----110,98g
0,5mol ---x= (0,5molx110,98g)/1 mol= 55,49 g
What caused wind to blow
Answers
Answer:
Different atmospheric pressure. When there is a different atmospheric pressure, air moves from the higher pressure to the lower pressure area which results in what you call WIND but can result in various speeds and pressure.
Hope this helped and if it did, please give my answer a brainliest.
Answer:
Wind is caused by differences in the atmospheric pressure.
Explanation:
When a difference in atmospheric pressure exists, air moves from the higher to the lower pressure area, resulting in winds of various speeds.
What substances devolve in water
Answers
Answer:
Two types of substances will dissolve in water: ionic compounds, such as sodium chloride (NaCl, or table salt) and compounds composed of larger molecules that have a net charge due to the arrangement of their atoms. Ammonia (NH3) is an example of the second type.
Explanation:
Answer:
sugar
salt
Explanation:
1.00 mole of an ideal gas at STP is cooled to -41°C while the
pressure is increased to 805 mmHg. What is the new volume
of the gas in liters?
Answers
Answer:
V₂ = 18.13 L
Explanation:
Given data:
Mole of gas = 1 mol
Initial temperature = 273 K
Initial pressure = 1 atm
Final volume = ?
Final temperature = -41°C (-41+273 = 232 K)
Final pressure = 805 mmHg (805/760 = 1.05 atm)
Solution:
First of all we will calculate the initial volume of gas.
PV = nRT
V = nRT/P
V = 1 mol × 0.0821 mol.L/atm.K × 273 K / 1 atm
V = 22.4 L/atm / 1 atm
V = 22.4 L ( initial volume)
Now we will determine the final volume by using equation,
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Now we will put the values.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1 atm × 22.4 L × 232 K / 273 K × 1.05 atm
V₂ = 5196.8 atm .L. K / 286.65 atm.K
V₂ = 18.13 L
Need help with this chemistry stoichiometry worksheet any help is appreciated with work shown!
Answers
1) The mass of iron III oxide is 3.92 g and the mass of water is 1.32 g
2) The mass of the Mg is 19.44 g
3) The mass of calcium phosphate is 109 g
What is stoichiometry?
1) The equation is;
[tex]2Fe(OH)_3 - > Fe_2O_3 + 3H_2O[/tex]
Number of moles of iron III hydroxide
Moles = Mass/Molar mass
= 5.25 g/107 g/mol
= 0.049 moles
2 moles of iron III hydroxide produces 1 mole of iron III oxide
0.049 moles of iron III hydroxide produces 0.049 moles * 1 mole/2 moles
=0.0245 moles
Mass iron III oxide = 0.0245 moles * 160 g/mol
= 3.92 g
2 moles of of iron III hydroxide produces 3 moles of water
0.049 moles of iron III hydroxide produces 0.049 moles * 3 moles/ 2 moles
= 0.0735 moles
Mass of water = 0.0735 moles * 18 g/mol
= 1.32 g
2) Moles of magnesium fluoride = 50 g/62 g/mol
= 0.81 moles
[tex]Mg + F_2 -- > MgF_2[/tex]
1 mole of Mg produces 1 mole of magnesium fluoride
x moles of Mg produces 0.81 moles of magnesium fluoride
x = 1 * 0.81/1
= 0.81 moles of Mg
Mass of the Mg = 0.81 moles * 24 g/mol
= 19.44 g
3) [tex]3CaO + P_2O_5 --- > Ca_3(PO_4)_2[/tex]
Moles of calcium oxide = 100 g/56 g/mol
= 1.79 moles
Moles of phosphorus pentaoxide = 100 g/284 g/mol
= 0.35 moles
If 3 moles of calcium oxide reacts with 1 mole of phosphorus pentaoxide
1.79 moles of calcium oxide reacts with 1.79 * 1/3
= 0.596 moles
Thus phosphorus pentaoxide is the limiting reactant
1 mole of phosphorus pentaoxide produces 1 mole of calcium phosphate
0.35 moles of phosphorus pentaoxide produces 0.35 moles of calcium phosphate
Mass of calcium phosphate produced = 0.35 moles * 310 g/mol
= 109 g
Find the mass of a 50.p ml quantity of liquid of liquid is 1.64 g/ml
Answers
Answer:
The mass of liquid comes out to be 82 g.
Explanation:
Given density of liquid = 1.64 g/mL
Given volume of liquid = 50 mL
The relation between density and volume is shown below
[tex]\textrm{ Density} = \frac{\textrm{Mass of liquid}}{\textrm{ Volume of liquid}}[/tex]
Mass of liquid = [tex]1.64 \textrm{ g/mL}\times 50 \textrm{ mL} = 82 \textrm{ g}[/tex]
Mass of 50 mL liquid = 82 g
Select the correct answer.
The presence of which phenomenon proved the predictability of the big bang theory?
O A.
death of large, ancient stars
B.
cosmic microwave background (CMB)
O c. formation of the Orion nebula
D. formation of new stars
Racet
N
.
Answers
Answer: your answers are between d or b
Explanation:
The Cosmic Microwave Background (CMB), a remnant heat from the Big Bang, supports the theory's predictability. Its discovery provided strong evidence for the beginning of the universe as theorized in the Big Bang Theory.
Explanation:The predictability of the Big Bang Theory was proven by the presence of the Cosmic Microwave Background (CMB). The CMB refers to the thermal radiation that is presumed to be leftover from the 'Big Bang' – the explosion that marked the beginning of the universe approximately 13.8 billion years ago. This residual heat was predicted by the Big Bang Theory, and its eventual discovery provided strong evidence supporting the theory. Thus, it is the CMB that validated the predictability of the Big Bang Theory more than the other phenomena listed in your options.
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3.2 moles of H3PO4 to grams
Answers
Answer:
313, 6grams of H3PO4
Explanation:
We calculate the weight of 1 mol of H3PO4:
Weight 1 mol H3PO4= (Weight H)x3+ (Weight P)+(Weight 0)x4 =1gx3+31g+16gx4
Weight 1 mol H3PO4=98 g /mol
1 mol-----98 grams H3PO4
3,2mol----x= (3,2molx 98 grams H3PO4)/ 1mol=313,6 grams H3PO4
What is the molar mass for N5O9
Answers
Answer:
The molar mass of N5O9
is 214.0245g/mol
Explanation:
To solve this problem, we need to know each number of mole of each element present in the compound
N has 5 moles
O has 9 moles
Then, we multiple each number of mole by its number of mass of each element present
N - 14.0067
O - 15.999
Multiplying by mole
N - 5 * 14.0067 = 70.0335
O - 9 * 15.999 = 143.991
Therefore,
Molar mass of N5O9 = 70.0335 + 143.991
= 214.0245g/mol
Describe the movement of particles in a solid substance as it is heated to its boiling point.
Answers
Answer:
in a solid particles or still but as it gets hot the particles will move around rapidly
As a solid heats to its boiling point, it undergoes phase changes from solid to liquid to gas. At each stage, the particles' movement changes from fixed vibrations to free movement. These changes occur at constant temperatures known as the substance's melting and boiling points.
Explanation:The movement of particles in a solid substance as it is heated to its boiling point involves different states of matter: the solid, liquid, and gas phases. In the solid phase, the particles of the substance are closely packed together and vibrate about fixed positions. As the temperature of the solid rises due to the heat, the vibrations of the particles increase. Upon reaching the melting point, the solid begins to transform into a liquid, a process known as melting.
The temperature remains constant during this phase transition until the entire solid has melted. In the liquid phase, the particles are not as closely packed as in a solid and can move more freely. As the temperature continues to rise, the liquid will eventually reach the boiling point, where it starts transforming into a gas in a process called vaporization. During this phase change, the temperature again remains constant until all the liquid has become a gas.
In the gas phase, the particles move most freely, colliding with each other and filling the available space. The behavior of these phase transitions is determined by the substance's unique melting and boiling points, which are affected by the environment's pressure. Phase changes also involve changes in the amount of heat in the substance, with heat absorbed during melting and vaporization, and released during condensation and freezing.
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If I have 2.9 L of gas at a pressure of 5.0 atm and a temperature of 50.0 °C, what will be the
temperature of the gas if I decrease the volume of the gas to 2.4 L and decrease the
pressure to 3.0 atm?
Answers
Answer:
160.4K
Explanation:
Given parameters:
Initial volume of gas = 2.9L
Initial pressure of gas = 5atm
Initial temperature = 50°C
Final volume = 2.4L
Final pressure of gas= 3atm
Unknown:
Final temperature = ?
Solution:
To solve this problem, we have to apply the combined gas laws.
Mathematically, the law is expressed as;
[tex]\frac{P_{1}V_{1} }{T_{1} } = \frac{P_{2}V_{2} }{T_{2} }[/tex]
where P₁ is the initial pressure
V₁ is the initial volume
T₁ is the initial temperature
P₂ is the final pressure
V₂ is the final volume
T₂ is the final temperature
Since T₂ is the unknown, we must solve for it.
convert T₁ from °C to K;
T₁ = 273 + 50 = 323K
Now insert the parameters;
[tex]\frac{5 x 2.9}{323} = \frac{3 x 2.4}{T_{2} }[/tex]
[tex]T_{2}[/tex] = 160.4K
According to Boyle's Law, when the volume of a gas decreases at constant temperature, the pressure of the gas increases. Using the formula P1V1 = P2V2, we can calculate the final temperature of the gas. In this case, the final temperature would be approximately 29.0 °C.
Explanation:According to Boyle's Law, when the volume of a gas decreases at constant temperature, the pressure of the gas increases. This is expressed mathematically as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
In this case, the initial pressure is 5.0 atm, the initial volume is 2.9 L, the final volume is 2.4 L, and the final pressure is 3.0 atm. Plugging these values into the equation, we can solve for the final temperature. Rearranging the equation to solve for temperature gives T2 = (P2V2/T1) * (V1/P1).
Using the given values, we find T2 = (3.0 atm * 2.4 L) / (5.0 atm * 2.9 L) * (50.0 °C). Solving this equation gives T2 ≈ 29.0 °C.
PLEASE ANSWERRRRRRRRR
Larry is looking through a lens at a grasshopper. He wants to get a better look at the grasshopper's back legs, but instead of looking larger the legs look smaller. What happened?
A. Larry must have grabbed a concave lens since the legs look smaller.
B. Larry must have grabbed a concave lens since the legs are upside down.
C. Larry must have grabbed a convex lens since the legs look smaller.
D. Larry must have grabbed a convex lens since the light rays are diverging (spreading out).
Answers
Answer: A. Larry must have grabbed a concave lens since the legs look smaller.
Explanation:
I'm not sure. I did some research and it seems that this is the correct one because, universe today.com said; "A concave lens is a lens that possesses at least one surface that curves inwards. It is a diverging lens, meaning that it spreads out light rays that have been refracted through it. A concave lens is thinner at its centre than at its edges, and is used to correct short-sightedness (myopia)." and passmyexams.co.uk said; "Convex lenses are thicker at the middle. Rays of light that pass through the lens are brought closer together (they converge). A convex lens is a converging lens. When parallel rays of light pass through a convex lens the refracted rays converge at one point called the principal focus. The distance between the principal focus and the centre of the lens is called the focal length." and so, this lead me to believe that the answer is; A. Larry must have grabbed a concave lens since the legs look smaller.
During a 4 hour trip, a boat sailed 70 km in 2 h. Then the boat did not move for 1 hour and traveled 26 km in the last hour. What was the boat’s average speed ?
Answers
Answer:
32km/hr
Explanation:
The question asks to calculate the average speed for a boat.
Mathematically, the average speed is the total distance divided by the total time
Let’s get the total distance traveled:
That would be 70km + 26km = 96km
Now the total time taken would be 3 as the boat did not move at all for an hour.
The average speed is thus 96/3 = 32km/hr
Which is an ionic compound and which is a molecular compound? (picture #9)
Answers
Answer:OK. One of the properties of an ionic compound is that it conducts a current in aqueous (water) solution.
The ionic compound is held together by virtue of the opposing charges; plus and minus. In water, they may just crumble away into solution! But if you Heat a solid piece of a salt, an ionic compound, it takes a great deal of Energy! So look at Compound Y.
WOW! 455°C to melt. That is high. To boil it? 1550°C. That is very high! Especially compared to compound X!
It melts at -90°C, and boils at 82°C. So it is X that is your molecular compound, one of covalent bonding, or sharing electrons, VERY different than the ionic compound held together by opposing charges.
Explanation:
Ionic compounds consist of ions held together by electrostatic attraction, while molecular compounds are formed by the sharing of electrons between nonmetal atoms.
Explanation:An ionic compound consists of ions held together by electrostatic attraction, while a molecular compound consists of molecules held together by covalent bonds. Ionic compounds typically consist of a metal cation and a nonmetal anion, such as NaCl (sodium chloride). Molecular compounds, on the other hand, are formed by the sharing of electrons between two or more nonmetal atoms, such as H2O (water).
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Question 4 (1 point)
In an endothermic reaction products are
than reactants
in potential energy and ___stable
higher more
Answers
In an endothermic reaction products are HIGHER than reactants in potential energy and LESS stable.
Explanation:
Energy is input into the reaction in an endothermic reaction. This means the products are of a higher energy level than the reactants. Therefore the reaction increases Gibb's free energy and reduces entropy. Remember in thermodynamic stability involves an increase in entropy and a decrease in Gibbs free energy. Therefore the products are less stable than the reactants. This is why endothermic reactions do not occur spontaneously like exothermic reactions.
What is the advantage in using a simple machine?
Reduces the amount of work needed to move on object
Increase the mechanical advantage by increasing the effort force that is applied
Reduce the amount of energy required
Reduce the work needed to effort force applied rotion
Answers
The advantage in using a simple machine is to reduce the amount of work needed to move on object
Option A
Explanation:
A Simple machine is a device with less moving parts used to change motion and force to perform work. Some of the simple machines are the inclined plane, lever, wedge, wheel and axle, pulley, and screw which we all use in our daily life.
These simple machines make our work fast and accurate and also does not require much effort for the work to be done. In other words, we can tell simple machines make our work simpler. For eg: If we take the simple machine wheel and axle, in a bicycle, instead of moving the whole wheel, if we apply force on the pedals, the wheel starts moving. Thus, only less effort is required to move an object.
Answer:
The second one is the CORRECT answer.
Explanation:
How many electrons can fit in the fourth energy level on an atom?
Answers
Thus, the fourth level can hold up to 32 electrons: 2 in the s orbital, 6 in the three p orbitals, 10 in the five d orbitals, and 14 in the seven f orbitals. The sublevels of the first four principal energy levels and the maximum number of electrons that the sublevels can contain are summarized in Table 5.1.
The fourth energy level of an atom can accommodate a maximum of 32 electrons, calculated with the formula 2n^2 for the fourth level (n=4), which results in 2 * 16 = 32.
Explanation:The fourth energy level of an atom can hold a maximum of 32 electrons. This is because the number of electrons that can fit in a given energy level is determined by the formula 2n2, where n is the principal quantum number corresponding to the energy level. For the fourth energy level (n=4), we calculate 2 * 42 = 2 * 16 = 32. Therefore, there are 32 positions for electrons in the fourth energy level, which means 32 electrons can be accommodated when this level is fully occupied.
It's important to note that energy levels are like concentric circles around the nucleus where electrons reside. The fourth energy level is the furthest out compared to the first three levels and therefore, electrons located here will have the most energy. Each orbital within these levels can hold a maximum of two electrons.
Calculate the approximate number of molecules in a drop of water with a mass of 0.10 g.
A.
3 × 1021 molecules
B.
2 × 1023 molecules
C.
6 × 1021 molecules
D.
4 × 1023 molecules
Answers
Answer:
your answer is D -_- bc they want the approximate
Answer:
Option A. 3 × 10^21 molecules
Explanation:
From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules. This means that 1mole of H20 also contains 6.02x10^23 molecules.
1mole of H2O = (2x1) + 16 = 2 + 16 = 18g
If 1mole(i.e 18g) of H2O contains 6.02x10^23 molecules,
Therefore 0.1g of H2O will contain = (0.1 x 6.02x10^23) /18 = 3 x 10^21 molecules
Which is an example of a chemical change?
ripping paper
chopping wood
baking a cake
stretching a rubber band
Answers
Answer:
Baking a cake is a chemical change
Explanation:
Any collection of things that have some influence on one another can be thought of as a system. When we talk about a system, we are also talking about all the parts that should be included, how those parts interact with one another, and to how the system as a whole relates to other systems. Consider the water cycle on Earth. Scientists have hypothesized about how climate change, specifically global warming, could impact the water cycle and therefore life on Earth. Scientists might consider specific research questions regarding this topic. They would include which questions listed above? A) I and II B) I, II, IV C) I and III D) I, II, III, IV
Answers
The questions listed above relate to Earth systems and their interactions, especially in relation to climate change and global warming.
The questions listed above relate to the study of Earth systems and their interactions:
The parts that should be included.How those parts interact with one another.How the system as a whole relates to other systems.Scientists researching climate change and global warming focus on these aspects to understand the impact on the water cycle and life on Earth.
Scientists consider various research questions about how global warming affects the water cycle, investigating the effects on evaporation, precipitation, ocean currents, and ecosystems.
When considering how global warming may impact the water cycle, and thus life on Earth, scientists are likely to focus on a wide range of research questions. These could include questions such as:
How does an increase in atmospheric temperatures affect evaporation rates?What impact does climate change have on precipitation patterns and the frequency of extreme weather events?How do changes in the water cycle affect ocean salinity and currents?What are the implications of altered water cycles for terrestrial and aquatic ecosystems? These questions all relate to the complex interactions within the Earth's climate system, including the roles of feedback mechanisms in either amplifying or dampening the effects of climate variables on one another. Understanding these interactions and the feedback loops, both positive and negative, is essential to predict and mitigate the impacts of climate change on Earth's systems.