Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the high temperature of 90 degrees occurs at 4 PM and the average temperature for the day is 70 degrees. Find the temperature, to the nearest degree, at 9 AM

Answer:

So, 22 batches of cookies can the baker make.

Step-by-step explanation:

A baker has 15 cups of flour.

He sets aside 4 cups.

So, the remaining cups = 15 - 4 = 11

A cookie recipe that calls for 1/2 cup of flour.

So, x batches of cookies can the baker make with 11 cups

Use the ratio and proportional

1 : 1/2 = x : 11   ⇒ multiply both sides by 2

2 : 1 = 2x : 22

solve for x

2x = 2 * 22

x = 22

So, 22 batches of cookies can the baker make.

She can make 22 batches of cookies.

Given that there are 15 cups of flour. The baker sets aside 4 cups.

So remaining (15 - 4) = 11 cups.

Let she can make x batches.

Given each batch takes 1/2 cup.

That means she will need [tex]x\cdot\frac{1}{2}=\frac{x}{2}[/tex] cups.

According to the question:

[tex]\frac{x}{2}=11\\x=22[/tex]

So she can make 22 batches of cookies.

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Answer:

57

Step-by-step explanation:

(f•g)(x) = f(x)•g(x)

= (4x+3)(2x-5)

= 8x²-20x+6x-15

= 8x²-14x-15

(f•g)(4) = [4(4)+3] [2(4)-5]

= (16+3)(8-5)

= 19 • 3

= 57

Answer:

57

Step-by-step explanation:

got it correct on test. :)

Answer:

Step-by-step explanation:

This is an exponential function:

[tex]y=16(\frac{2}{3})^x[/tex] that tells us that the initial height of the ball is 16 feet and that after each successive bounce the ball comes up to 2/3 its previous height.  We are looking for y when x = 2, so

[tex]y=16(\frac{2}{3})^2[/tex] and

[tex]y=16(\frac{4}{9})[/tex] and

[tex]y=\frac{64}{9}[/tex] so

y = 7.1 feet

Answer:

a) (5,0)

b) (2,0)

Step-by-step explanation:

(a) A particle that lies 5.0 m directly above the origin would have its x-coordinate be 5 and its y-coordinate be 0. So (5,0).

(b) A particle that lies 2.0 m directly below the origin would have its x-coordinate be 2 and its y-coordinate be 0. So (2,0).

In a coordinate system with the positive x-axis directed upward, a particle located 5.0 m directly above the origin has a position of +5.0 m, and a particle 2.0 m below the origin has a position of -2.0 m.

In this coordinate system, the position of a particle is indicated by its vertical position relative to the origin. Therefore:

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Answer:

9.6

Step-by-step explanation:

The question is :

Solution;

Let total distance from school to home = 'x' meters

Issa jogged 2/3rd of 'x'= [tex]\frac{2x}{3}[/tex]

So total distance from school to home = [tex]\frac{2x}{3} +3200[/tex]

But total distance from school to home = [tex]x[/tex]

[tex]==> \frac{2x}{3} + 3200 = x[/tex]

[tex]==> 3200= \frac{x}{3}[/tex]

[tex]==> 9600=x[/tex]

So total distance from school to home is 9600 meters

We convert it into km now

we know 1000 meters = 1km

==> 9600 meters = 1/100 x 9600= 9.6 km

Answer:

9.6 or (48\5

Step-by-step explanation:

Answer: the length of Maria's piece of string is 45 inches.

the length of Katy's piece of string is 39 inches

Step-by-step explanation:

Let x represent the length of Maria's piece of string.

Let y represent the length of Katy's piece of string.

When they put the two pieces of string together end to end, the total length is 84inches. This means that

x + y = 84 - - - - - - - - - - - -1

Maria's string is 6 inches longer than Katy's. This means that

x = y + 6

Substituting x = y + 6 into equation 1, it becomes

y + 6 + y = 84

2y + 6 = 84

2y = 84 - 6 = 78

y = 78/2 = 39

x = y + 6 = 39 + 6

x = 45

Answer:142

2

+2

Step-by-step explanation:

Answer:

The required inequality is [tex]0.0001 x^2 - 0.089 x - 7<0[/tex].

Step-by-step explanation:

The given inequalities are

[tex]A(x) = 0.0051x^2 - 0.319x + 15[/tex]

[tex]V(x)= 0.005x^2 - 0.23x + 22[/tex]

where, x is the driver's age (in years), A(x) is driver’s reaction time to audio stimuli and V(x) is his or her reaction time to visual stimuli, 16 ≤ x ≤ 70.

We need to find an inequality that can be use to find the x-values for which A(x) is less than V(x).

[tex]A(x)<V(x)[/tex]

[tex]0.0051x^2 - 0.319x + 15< 0.005x^2 - 0.23x + 22[/tex]

[tex]0.0051x^2 - 0.319x + 15- 0.005x^2 + 0.23x- 22<0[/tex]

Combine like terms.

[tex]0.0001 x^2 - 0.089 x - 7<0[/tex]

where, 16 ≤ x ≤ 70.

Therefore, the required inequality is [tex]0.0001 x^2 - 0.089 x - 7<0[/tex].

Answer: the rate of the wind is 6.2 mph

Step-by-step explanation:

Let x represent the rate of the wind.

Joe traveled against the wind in a small plane for 3hours. If the speed of the plane in still air is 180 mph, then the total speed with which the plane flew is

(180 - x) mph

Distance = speed × time

Therefore, distance travelled against the wind is

3(180 - x)

= 540 - 3x - - - - - - - - - - - - - -1

The return trip with the wind took 2.8 hours.

the total speed with which the plane flew is

(180 + x) mph

Therefore, distance travelled with the wind is

2.8(180 + x)

= 504 + 2.8x - - - - - - - - - - - - - -2

Since the distance is the same, then

540 - 3x = 504 + 2.8x

540 - 504 = 2.8x + 3x

5.8x = 36

x = 36/5.8 = 6.2

Answer:

Total magnification of microscope at this setting is 40X

Step-by-step explanation:

Total magnification of microscope is determined by multiplying the magnification power of individual lenses.

So if eyepiece has magnification power of 10X and objective lense has magnification power of 4X , the total magnification of microscope would be

10 × 4 = 40

which means the object will appear 40 times larger than actual object.

The total magnification of the microscope at this setting is 40X.

To determine the total magnification of a compound microscope, one needs to multiply the magnification power of the eyepiece by the magnification power of the objective lens. In this case, the eyepiece has a magnification power of 10X and the objective lens has a magnification power of 4X.

The formula for the total magnification [tex]\( M_{total} \)[/tex] is given by:

[tex]\[ M_{total} = M_{eyepiece} \times M_{objective} \][/tex]

Substituting the given values:

[tex]\[ M_{total} = 10X \times 4X \][/tex]

[tex]\[ M_{total} = 40X \][/tex]

Therefore, the total magnification of the microscope when using the 10X eyepiece and the 4X objective lens is 40X. This means that the image seen through the microscope will appear 40 times larger than its actual size.

Answer:

C. f(x) = 2^x+2 - 3

Step-by-step explanation:

Looking at the graph and answer choices, it's obvious that the only change is the vertical shift. Since we know that the smallest value of 2^x+2 is 0, we can infer that the vertical shift will be -3 to match the horizontal asymptote of y=-3.

Answer:

94

Step-by-step explanation:

Jen has

Answer:

h = 6 units.

Step-by-step explanation:

Given:

Area of the parallelogram = [tex]54\ units^2[/tex].

Base = 9 units.

We need to find the missing height.

Solution:

We know that the area of the parallelogram is represented by below formula.

[tex]A = bh[/tex] -----------(1)

Where:

A = Area of the parallelogram.

h = height of the parallelogram.

b = Base

Since, base and area is known. So, we substitute these values in equation 1.

[tex]54 = 9\times h[/tex]

[tex]h = \frac{54}{9}[/tex]

h = 6 units.

Therefore, height of the parallelogram h = 6 units.

This does NOT represent a function.

There should only be one pair per input and output, but this graph has multiple.

Answer:

Area = 823 * 534 = 439,482 ft^2

Step-by-step explanation:

Answer:

C. 2

Step-by-step explanation:

Given:

[tex]\frac{5}{12}x-\frac12=\frac13[/tex]

We need to solve the equation to find the value of x.

Solution:

[tex]\frac{5}{12}x-\frac12=\frac13[/tex]

Combining like terms we get;

[tex]\frac{5}{12}x=\frac13+\frac12[/tex]

Now Using LCM for making the denominators same we get;

[tex]\frac{5}{12}x=\frac{1\times2}{3\times2}+\frac{1\times3}{2\times3}\\\\\frac{5}{12x}=\frac{2}{6}+\frac{3}{6}[/tex]

Now Denominators are common so we solve the number we get;

[tex]\frac{5}{12}x=\frac{2+3}{6}\\\\\frac{5}{12}x=\frac{5}{6}[/tex]

Now Dividing both side by [tex]\frac{12}{5}[/tex] we get;

[tex]\frac{5}{12}x\times \frac{12}{5}=\frac{5}{6}\times \frac{12}{5}\\\\x=2[/tex]

Hence the value of x is 2.

Answer:

[tex]50w+100 \ge 18000[/tex]

Step-by-step explanation:

Each seven-letter word is worth 50 points. [tex]w[/tex] words are then worth [tex]w\times50=50w[/tex].

Since Sal gets 100 points for playing the game, his points total after [tex]w[/tex] words is [tex]50w +100[/tex]. If he wants to break the record, he must get, at least, 18000 points. "At least" in inequality means [tex]\ge[/tex] (just as "at most" means [tex]\le[/tex]). Then the required inequality is

[tex]50w+100 \ge 18000[/tex].

Note that the question says "18000 or more", which is why we used the [tex]\ge[/tex] symbol. If the phrase had been "more than 18000", we would have used [tex]>[/tex].

After 10 s, the bucket has rotated [tex]180^{\circ}[/tex]

Step-by-step explanation:

The motion of the bucket on the water wheel is a periodic motion, which means that it repeats itself periodically. The period of the motion is the time it takes for the bucket to returns to its original position: it can be found from the graph by looking at after how much time the graph has again the same shape.

We see that if we  start from x = 0 seconds, then the graph has the same shape again (=it has completed one full cycle) at x = 20 seconds, so the period is

T = 20 s

This also means that in a time of 20 seconds, the bucket has covered a full revolution, so an angle of

[tex]\theta=360^{\circ}[/tex]

Therefore, in order to find how many degrees x the bucket has rotated in

t = 10 s

We  can use the rule of three:

[tex]\frac{\theta}{T}=\frac{x}{t}[/tex]

And solving for x, we find

[tex]x=\frac{\theta t}{T}=\frac{(360)(10)}{20}=180^{\circ}[/tex]

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Yo sup??

This question can be solved by applying the properties of similar triangles

the triangle with sides 5x and 20 is similar to the triangle with sides 45 and 36

therefore we can say

5x/45=20/36

x=5 units

Hope this helps

Answer:

The shark are fed [tex]\frac16 \ ton[/tex] of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = [tex]\frac{2}{15}\ ton[/tex]

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = [tex]\frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton[/tex]

Total fish fed in whole day = [tex]\frac12 \ ton[/tex]

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = [tex]\frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}[/tex]

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = [tex]\frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}[/tex]

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = [tex]\frac{3-2}{6}=\frac16 \ ton[/tex]

Hence The shark are fed [tex]\frac16 \ ton[/tex] of fish during the night.

Answer:

  (n -4)(n +1)^2 = n^3 -2n^2 -7n -4

Step-by-step explanation:

The least common denominator is the smallest denominator that lets you write the sum as a single fraction.

  [tex]\dfrac{n^5}{n^2+2n+1}+\dfrac{-4}{n^2-3n-4}=\dfrac{n^5}{(n+1)^2}+\dfrac{-4}{(n+1)(n-4)}\\\\=\dfrac{n^5}{(n+1)^2}\cdot\dfrac{n-4}{n-4}+\dfrac{-4}{(n+1)(n-4)}\cdot\dfrac{n+1}{n+1}=\dfrac{n^5(n-4)-4(n+1)}{(n+1)^2(n-4)}\\\\=\dfrac{n^6-4n^5-4n-4}{n^3-2n^2-7n-4}[/tex]

The least common denominator is ...

  (n-4)(n+1)^2 = n^3 -2n^2 -7n -4

Answer:

Side length = [tex]\sqrt{\frac{A}{3} }[/tex] cm ,   Height =  [tex]\frac{1}{2} \sqrt{\frac{A}{3} }[/tex] cm  ,  Volume = [tex]\frac{A\sqrt{A}}{6\sqrt{3} }[/tex]  cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( [tex]\frac{A - x^{2} }{4x}[/tex] )

V =  [tex]\frac{Ax - x^{3} }{4}[/tex]

To find max volume put V' = 0

So taking derivative equation becomes

[tex]\frac{A - 3 x^{2} }{4} = 0[/tex]

A = 3 [tex]x^{2}[/tex]

[tex]x^{2}[/tex] = [tex]\frac{A}{3}[/tex]

x = [tex]\sqrt{\frac{A}{3\\} }[/tex]

put value of x in equation 1

y = [tex]\frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }[/tex]  

y = [tex]\frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }[/tex]

y = [tex]\frac{1}{2} \sqrt{\frac{A}{3} }[/tex]

So the volume will be

V = [tex]x^{2}[/tex] × y

Put values of x and y from equation 2 & 3

V = [tex]\frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )[/tex]

V = [tex]\frac{A\sqrt{A}}{6\sqrt{3} }[/tex]

The side length is [tex]\mathbf{l =\sqrt{ \frac A3}}[/tex], the height is [tex]\mathbf{h = \frac{1}{2}\sqrt{\frac A3}}[/tex] and the maximal volume is  [tex]\mathbf{V = \frac A6 \sqrt{\frac A3}}[/tex]

Let the dimensions of the box be l and h, where l represents the base length and h represents the height.

The volume is calculated as:

[tex]\mathbf{V = l^2h}[/tex]

The surface area is:

[tex]\mathbf{A= l^2 + 4lh}[/tex]

Make h the subject

[tex]\mathbf{h = \frac{A- l^2}{4l}}[/tex]

Substitute [tex]\mathbf{h = \frac{A- l^2}{4l}}[/tex] in [tex]\mathbf{V = l^2h}[/tex]

[tex]\mathbf{V = l^2 \times \frac{A- l^2}{4l}}[/tex]

[tex]\mathbf{V = l \times \frac{A- l^2}{4}}[/tex]

[tex]\mathbf{V = \frac{Al- l^3}{4}}[/tex]

Split

[tex]\mathbf{V = \frac{Al}{4}- \frac{l^3}{4}}[/tex]

Differentiate

[tex]\mathbf{V' = \frac{A}{4}- \frac{3l^2}{4}}[/tex]

Set to 0

[tex]\mathbf{\frac{A}{4}- \frac{3l^2}{4} = 0}[/tex]

Multiply through by 4

[tex]\mathbf{A- 3l^2 = 0}[/tex]

Add 3l^2 to both sides

[tex]\mathbf{3l^2 = A}[/tex]

Divide both sides by 3

[tex]\mathbf{l^2 = \frac A3}[/tex]

Take square roots

[tex]\mathbf{l =\sqrt{ \frac A3}}[/tex]

Recall that: [tex]\mathbf{h = \frac{A- l^2}{4l}}[/tex]

So, we have:

[tex]\mathbf{h = \frac{A - \frac{A}{3}}{4\sqrt{A/3}}}[/tex]

[tex]\mathbf{h = \frac{\frac{2A}{3}}{4\sqrt{A/3}}}[/tex]

Divide

[tex]\mathbf{h = \frac{2\sqrt{A/3}}{4}}[/tex]

[tex]\mathbf{h = \frac{\sqrt{A/3}}{2}}[/tex]

Rewrite as:

[tex]\mathbf{h = \frac{1}{2}\sqrt{\frac A3}}[/tex]

Recall that:

[tex]\mathbf{V = l^2h}[/tex]

So, we have:

[tex]\mathbf{V = \frac A3 \times \frac{1}{2}\sqrt{\frac A3}}[/tex]

[tex]\mathbf{V = \frac A6 \sqrt{\frac A3}}[/tex]

Hence, the side length is [tex]\mathbf{l =\sqrt{ \frac A3}}[/tex], the height is [tex]\mathbf{h = \frac{1}{2}\sqrt{\frac A3}}[/tex] and the maximal volume is  [tex]\mathbf{V = \frac A6 \sqrt{\frac A3}}[/tex]

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Answer:

The correct answer for this equational ratio is x = 5

Step-by-step explanation:

In order to calculate for x, we must create the necessary ratios

[tex]\frac{16}{20} = \frac{45-5x}{5x}[/tex]

Cross multiply to get

900 - 100x = 80x

900 = 180x

x = 5

Answer:

[tex]A = 5 {x}^{2} + 6x + 1[/tex]

Step-by-step explanation:

[tex]A = \frac{(a + b)h}{2} = \frac{(6x - 5 + 4x + 7)(x + 1)}{2} = \frac{(10x + 2)(x + 1)}{2} = \frac{2(5x + 1)(x + 1)}{2} = 5 {x}^{2} + 6x + 1[/tex]

There are 85 candy bars in each box, and he will have 340 candy bars left after he gives three boxes to a friend.

Answer: he has 340 candy bars left.

Step-by-step explanation:

The total number of candy bars that

Miguel ordered is 595.

They come in 7 boxes. Assuming each box contains equal number of candy bars. This means that the number of candy bars in each box would be

595/7 = 85 candy bars

If he gives 3 boxes of candy bars to his friend, it means that the number of candy bars that he gave to his friend is

85 × 3 = 255 candy bars

Therefore, the number of candy bars that he has left is

595 - 255 = 340

Final answer:

By substituting x with 14 in each option, it is determined that option D, which is f(x) = x + 9, is the correct function where f(14) equals 23.

Explanation:

The student is asking to find the function for which f(14)=23. To answer this, we substitute x with 14 in each of the given options and see which one results in f(x) being equal to 23.

Substitute x=14 in f(x)=12x−20: f(14)=12(14)−20=168−20=148, which is not 23.

Substitute x=14 in f(x)=14x+23: f(14)=14(14)+23=196+23=219, which is not 23.

Substitute x=14 in f(x)=3x−7: f(14)=3(14)−7=42−7=35, which is not 23.

Substitute x=14 in f(x)=x+9: f(14)=14+9=23, which is the correct answer.

The correct function is D. f(x)=x+9.

Answer:

98 degrees

Step-by-step explanation:

m<H = 45, m<F = 53

180 = 45 + 53 + (180-x)

82 = 180-x

x+82 = 180

x = 98

Answer:

Step-by-step explanation:

The sum of the angles in a triangle is 180 degrees. This means that

Angle F + angle G + angle H = 180

Therefore,

53 + 45 + angle G = 180

98 + angle G = 180

Subtracting 98 from the left hand side and the right hand side of the equation, it becomes

98 - 98 + angle G = 180 - 98

angle G = 82 degrees

The sum of angles on a straight line is 180 degrees. Therefore,

x + 82 = 180

Subtracting 82 from the left hand side and the right hand side of the equation, it becomes

x + 82 - 82 = 180 - 82

x = 98 degrees

Answer:

  64

Step-by-step explanation:

10 ft is 4 times 2 1/2 ft, so the larger container has dimensions of 4 crates in every direction. That is, it will hold 4^3 crates, or 64 crates.

Answer:

δhsoln will be close to zero.

Step-by-step explanation:

In calculus, the symbol d represents a large or significant increment in a value. For example, say the change in the volume of a liquid in a tank depends upon the change of the height h.

The above statement can be written like this:

dV/dh

This means that the volume of the tank (V) depends with a significant change in the height of the liquid (h).

It is also possible to compute small changes in physical quantities. The symbol δ simply presents a small increment or small change. Using the same expression above, if a very large tank was to have a very very small leak, the change would be: δV/δh

In other words, the change in the volume will be almost negligible and will be close to zero.  

Answer: The height of the tree is 12.57 ft.

Step-by-step explanation:

The height of a thing is proportional to the its shadow.

Let H = Height and S = length of shadow

Then by equation direct proportion , [tex]\dfrac{H_1}{S_1}=\dfrac{H_2}{S_2}[/tex]       (i)

Given : A tree that casts a 22 ft shadow at the same time a 4 ft postpost casts a shadow which is 7-ft ​long.

Put [tex]S_1=22 ,\ H_2= 4,\ \ S_2=7[/tex]  in (i), we get

[tex]\dfrac{H_1}{22}=\dfrac{4}{7}\\\\ H_1=\dfrac{4}{7}\times22\approx12.57[/tex]

Hence, the height of the tree is 12.57 ft.

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