____________occurs when an object travels in a curved path.

Answer:

The characteristics of water waves is that it travels through the waver, the particles travel in clockwise circles. The radius of the circles decreases as the depth into the water increases.

Explanation:

Answer:

Energy cannot be created or destroyed.

Explanation:

Energy cannot be created or destroyed, it can only be altered from one from to another.

Answer:

C. Energy cannot be created or destroyed but it can change form.

Energy can be converted from one form to another. The law of conservation of energy says that energy is neither created nor destroyed. When you consume energy, it is not gone forever. Instead, it is changed from one form of energy to another. So, energy is not manufactured and it doesn't go away after you use it. It is just transformed, or stored.

Answer:

ΔU = -70 J

Explanation:

ΔU = Q − W

where ΔU is the change in internal energy,

Q is the heat absorbed by the system,

and W is the work done by the system (on the surroundings).

30 J of thermal energy is released, so Q = -30 J.

40 J of work is done by the system, so W = 40 J.

Therefore, the change in internal energy is:

ΔU = -30 J − 40 J

ΔU = -70 J

Final answer:

The change in internal energy of the system is calculated using the formula
ΔU = Q - W. With 30 J of thermal energy released and 40 J of work done by the system, the internal energy decreases by 70 J.

Explanation:

Change in Internal Energy Calculation

To calculate the change in internal energy (ΔU) of a system, the first law of thermodynamics is often used, which is expressed as ΔU = Q - W, where Q is the heat added to the system, and W is the work done by the system on its surroundings. In this scenario, Q is a negative value since 30 J of thermal energy is released (or removed) from the system, which makes Q = -30 J. The system does 40 J of work on the surroundings; hence, W is also 40 J.

The change in internal energy is therefore calculated as follows:

ΔU = Q - W
ΔU = (-30 J) - (40 J)
ΔU = -30 J - 40 J
ΔU = -70 J

Thus, the change in internal energy of the system is -70 J, indicating that the internal energy of the system has decreased by 70 joules.

The acceleration of the car is 1.067 m/[tex]s^{2}[/tex].

Explanation:

Acceleration is the measure of change in velocity experienced by any object for a given time period. So it is determined as the ratio of difference in the velocity to the time period.

As here the initial velocity is stated as zero, so u = 0. And the final velocity is termed as 50 km/h. Then we have to determine the acceleration in 13 s. So here we have to convert the units as common units. Thus, 50 km/h should be converted to m/s as [tex]\frac{50*1000}{3600}=13.88 m/s[/tex]

So now, the initial velocity u = 0 and final velocity v = 13.88 m/s and the time period is given as t = 13 s.

[tex]Acceleration = \frac{v-u}{t}=\frac{13.88-0}{13}=1.067 m/s^{2}[/tex]

So the acceleration of the car is 1.067 m/[tex]s^{2}[/tex].

Answer:

variable that scientist change

Explanation:

Answer:

1st blank - amplitude

2nd blank - frequency

3rd blank - hertz

The amount of energy a wave carries corresponds to its amplitude. Frequency is equal to the number of wavelengths that pass a fixed point in a second. Frequency is typically expressed in hertz

Answer:

352.8 N

Explanation:

= 36

= 9.8

⁄ = ? = = 36 × 9.8 = 352.8

Answer:

360 N

Explanation:

mass = 36 kg

g = 10m/s²

W = mg

W = 36 × 10

W = 360 N

Due to rising demand for higher bandwidth and faster speed connections, fiber optic transmission is becoming more and more common in the developing world. Optical fiber has had a great impact on the way we receive and transmit signals. They have largely replaced copper wire communications in core networks in the developed world, because of its advantages over electrical transmission. But they brought some difficulties as well.

Following are the advantages and disadvantages of optical fiber:

Advantages

Disadvantages

Keywords: fiber optics, bandwidth, transmission, impact, advantages, disadvantages

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Answer:

E1 =  2996.667N/C E2 = 11237.5N/C

Explanation:

E1 = kQ1/r^2

  =8.99 x 10^9 x 30 x 10^-9/(30x10^-2)^2

  = 2996.667N/C

E2 = kQ2/r^2

      = 8.99 x 10^9 x 50 x 10^-9/(20x10^-2)^2

      = 11237.5N/C

The direction are towards the point a

Need more details, what is the slope of the line, etc.

It depends.

In order to answer the question, a person has to know:

-- the velocity (speed and direction) of the ball WHEN it's released

-- whether the ball has any net electric charge

-- whether there's any other net electric charge in the neighborhood

-- the mass of the ball, if any net charges are involved

-- what planet is nearest to the ball

-- the acceleration of gravity on that planet

Each of these details has an influence on the answer.  That is, if one of them changes, then the answer changes.  Now, it hasn't escaped my notice that you neglected to provide ANY of this information, so there's no way to even begin to concoct an answer.

Right now, the question is a lot like me asking you "How much will I weigh 8 seconds after I finish eating the steak ?".

Answer:

Explanation:

The force is a vector magnitude, it has direction, course and intensity.

Suppose that you have given two forces at a certain angle and that you need to find the resultant force then you apply the Parallelogram of force low.

You represent the two forces in the drawing as vectors and connect their origin to the same point and then construct a parallelogram over them.

The longer diagonal represents the resultant force.

God is with you!!!

A) The maximum height is 31.9 m

B) The speed of the ball is 17.7 m/s

Explanation:

A)

We can solve this problem by using the law of conservation of energy. In fact, in abcense of air resistance, the mechanical energy of the ball (sum of potential energy + kinetic energy) must be conserved.

Mathematically:

[tex]U_i +K_i = U_f + K_f[/tex]

where :

[tex]U_i[/tex] is the initial potential energy, at the bottom

[tex]K_i[/tex] is the initial kinetic energy, at the bottom

[tex]U_f[/tex] is the final potential energy, at the top

[tex]K_f[/tex] is the final kinetic energy, at the top

We can rewrite it as

[tex]mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2[/tex]

where:

m is the mass of the ball

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

[tex]h_i = 0[/tex] is the initial height  of the ball

u = 25 m/s is its initial speed

[tex]h_f[/tex] is the maximum height reached by the ball

v = 0 is the final speed (which is zero at the maximum height)

Solving for [tex]h_f[/tex], we find: the maximum height:

[tex]\frac{1}{2}mu^2 = mgh_f\\h_f = \frac{u^2}{2g}=\frac{(25)^2}{2(9.8)}=31.9 m[/tex]

B)

When the ball is halfway up to its maximum height, it means that its height is

[tex]h_f = \frac{31.9}{2}=15.9 m[/tex]

Therefore we can re-apply again the equation of the conservation of energy:

[tex]mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2[/tex]

where this time v is not zero, but it is the speed of the ball at the height of 15.9 m

Re-arranging the equation and solving for v, we find:

[tex]v=\sqrt{u^2-2gh_f}=\sqrt{25^2-2(9.8)(15.9)}=17.7 m/s[/tex]

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The maximum height the baseball can reach when thrown at an initial speed of 25 m/s is 31.9 meters. When the ball is halfway to this height, its speed is 17.67 m/s.

The subject matter of the question is physics, specifically the concepts of motion, velocity, and gravitational forces.  

Given the initial velocity of the baseball is 25 m/s and the acceleration due to gravity is -9.8 m/s², we can find the maximum height using the equation v² = u² + 2gs, where v is the final velocity, u is the initial velocity, g is acceleration due to gravity, and s is displacement.  

Substituting in the given values gives us 0 = (25 m/s)² + 2*(-9.8 m/s²)*s, so s = (25 m/s)² / (2 * 9.8 m/s²) = 31.9 meters. This is the maximum height the ball reaches.  

When the ball is halfway to its maximum height, it is still subject to the laws of physics, so we cannot simply divide the initial velocity by two. Instead, we can find the velocity at the halfway height (15.95 meters) using the equation v = u + 2gs. Substituting the known values, we get v = sqrt((25 m/s)² + 2*(-9.8 m/s) * (-15.95 m) ) = 17.67 m/s.

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Answer:

B goes up faster

if x=0, then A=0

if x=1 then B=6

Explanation:

Formulas Or Equations

We have two different formulas

A = 3x

B = 5x + 1.

They both are equations of lines. The number beside the X (coefficient) is also known as the slope of the line. The greater the slope, the faster the function goes up as X increases. We can clearly see that the equation B has a greater slope, which means it goes up faster than A as X increases

When x=0, A=3(0)=0

When x=1, B=5(1)+1=6

Answer:

It will have a certain kinetic energy at the beginning, but it will be lost by resistant work done by friction. Thus, itsmotion wil be uniformly decelerating.

Explanation:

The gain in gravitational potential energy of the mass = 100 kg m^2 / s^2.

Explanation:

Gravitational potential energy is an energy in which an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the Earth's surface where the gravitational acceleration can be assumed to be constant at about 9.8 m/s2.

The formula for the gravitational potential energy is the product of mass, gravity, and height.

             GPE = m *g *h

where m represents mass in kg,

           g represents the gravity,

           h represents the height.

          GPE    = 5 * 10 * 2 = 100 kg m^2 / s^2.

Answer:

24 m

Explanation:

initial velocity is u = 3.5 m/sec

final velocity is v = 0 m/sec

distance traveled is S = 1.5 m

From kinematic equation [tex]v^{2}-u^{2} = 2as[/tex]

Making acceleration the subject,

[tex]a=\frac {v^{2}-u^{2}}{2s}[/tex]

Acceleration [tex]a = \frac {0^2-3.5^2}{(2*1.5)}= -4.083333333m/s^{2}[/tex]

When the initial velocity is quadrupled= u = 3.5*4 = 14 m/s

V = 0 m/s

[tex]a = -4.083333333m/s^{2}[/tex]

then [tex]S = \frac {v^{2}-u^{2}}{2} = \frac {0^{2}-14^{2}}{2\times -4.083333333} = 24 m[/tex]

Answer:

A

Explanation: This isn't Physics, but there's your answer.

The number of revolutions the tire makes during this motion is 169.265 revolution.

Explanation:

Given:

Car’s initial velocity, u = 0

Car’s final velocity, v = 33.5 m/s

Time required t = 11.9 s

Hence, car’s acceleration ‘a’ can be given by the first equation of motion as

[tex]v=u+(a \times t)[/tex]

[tex]33.5=0+(a \times 11.9)[/tex]

[tex]11.9 \times a=33.5[/tex]

[tex]a=\frac{33.5}{11.9}=2.815 \mathrm{m} / \mathrm{s}^{2}[/tex]

The distance covered by the car during this time is given by the second equation of motion

[tex]s=(u \times t)+\left(\frac{1}{2} \times a \times t^{2}\right)[/tex]

[tex]s=0+\left(0.5 \times 2.815 \times 11.9^{2}\right)[/tex]

[tex]s=0.5 \times 2.815 \times 141.61=199.31 m[/tex]

Now as in each revolution a wheel rolling without slipping covers a distance equal to its periphery ([tex]2 \pi R[/tex]), if the total numbers of revolution of each tire be n, then we have

[tex]s=n \times 2 \pi R[/tex]

Given diameter, d = 37.5 cm = 0.375 m

Radius of the wheel, R =  [tex]\frac{d}{2}=\frac{0.375}{2}=0.1875 \mathrm{m}[/tex]

Total numbers of revolution,

[tex]n=\frac{s}{2 \pi R}=\frac{199.31}{2 \times 3.14 \times 0.1875}=\frac{199.31}{1.1775}=169.265 \text { revolution }[/tex]

The car's tires make approximately 917 revolutions during the motion.

To find the number of revolutions the tire makes during this motion, we need to first find the distance the car travels. We can use the formula s =[tex]ut + 1/2at^2[/tex]the distance, u is the initial velocity, a is the acceleration, and t is the time. In this case, the initial velocity is 0 m/s, the acceleration is the same as the car's acceleration, and the time is 11.9 s. Plugging in these values, we get:

s = 0(11.9) + 1[tex]/2(33.5)(11.9)^2[/tex]

The distance traveled is equal to the circumference of the tire multiplied by the number of revolutions. The circumference of the tire is equal to π times the diameter. Plugging in the values, we get:

2π(0.375) = 2.35619 m

Let's assume the number of revolutions is N. Therefore, the distance traveled can also be calculated as N times the circumference. Setting up the equation, we have:

N(2.35619) = 2156.29

Solving for N, we get:

N = 2156.29 / 2.35619 = 916.67

Therefore, the tire makes approximately 917 revolutions during this motion.

Answer:

55 m/s

Explanation:

If all kinetic energy is converted to heat:

½ mv² = mCΔT

v = √(2CΔT)

v = √(2 × 128 J/kg/K × (36.9°C − 25°C))

v = 55.2 m/s

Rounded to two significant figures, the speed is 55 m/s.

The problem involves using the principles of conservation of angular momentum and kinetic energy to find the student's final angular speed and the change in kinetic energy of the system when the radius at which weights are held is changed.

The problem involves calculating the final angular speed of a student who pulls two objects closer while rotating on a stool and then determining the change in kinetic energy of the system. Using the principle of conservation of angular momentum, we can solve for the student's final angular speed after changing the radius at which the objects are held. The kinetic energy change relies on calculating the initial and final kinetic energies and finding their difference.

Without the complete calculations for this scenario, a precise final angular speed and kinetic energy change cannot be provided here. Typically, you would use the formula for angular momentum (L = Iω) where I is the moment of inertia and ω is the angular speed, and the formula for kinetic energy (KE = 0.5 * I * ω²) to solve these problems.

Answer:

Two objects are identical except that on is hotter than the other. Thus, when an equal force acts on them the hotter one will move faster or will get displaced more or stop slower than the other one. This is because the hotter object has comparatively more mobile particles than the other

Hope this helps!

Final answer:

Identical forces exerted on two objects with different temperatures will affect them equally according to Newton's third law, but their responses, such as stress and expansion, may differ due to properties like thermal expansion coefficients. Also, at thermal equilibrium, the final temperature is closer to the object with greater heat capacity. The hotter star of two identical stars will be significantly brighter.

Explanation:

Response to the Student's Question

When two objects are identical except for temperature and they are exposed to identical forces, the forces they experience will be the same due to Newton's third law. However, the effect of the force may differ if their temperatures lead to different physical properties like thermal expansion. If object A has a higher thermal expansion coefficient than object B and both are heated identically, A will likely feel greater stress because it will expand more, which could create internal strain if constrained. For the question about the heat capacities, when two objects—one hot, one cold—are brought into contact, the final temperature at thermal equilibrium will be closer to the object with the higher heat capacity, in this case, the colder object. Therefore, it will not be exactly halfway between the two initial temperatures.

In the context of stars, brightness is related to temperature. The star with a temperature of 8700 K will be brighter than the star at 2900 K due to Wien's Law and the Stefan-Boltzmann Law, which relate temperature to luminosity and energy output. The hotter star is, therefore, significantly brighter.

Answer:

3seconds

Explanation:

it will take 3 seconds

Answer:

10520 N

Explanation:

m = 1,052 kg

g = 10 m/s²

F = W = mg

F = 1052 × 10

F = 10520 N

The weight of an object is defined as the force of gravity on the object and may be calculated as the mass times the acceleration of gravity,

w = mg.

Since the weight is a force, its SI unit is the

newton.

For an object in free fall, so that gravity is the only force acting on it, then the expression for weight follows from Newton's second law: F = ma

For calculating work, the force and the distance must be in the same direction

Explanation:

The work done by a force on an object is given by the equation

[tex]W=Fd cos \theta[/tex]

where

F is the magnitude of the force

d is the displacement

[tex]\theta[/tex] is the angle between the direction of the force and of the displacement

The equation can be rewritten as

[tex]W=(F cos \theta) d[/tex]

where [tex]F cos \theta[/tex] is the component of the force parallel to the displacement of the object. This means that when calculating the work, only the component of the force parallel to the motion of the object contributes to the work: in this sense, we can say then for work to be different from zero, the force must have a component in the same direction as the motion of the object.

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Answer:

Direction

Explanation:

The displacement of the book is 5 meters

Explanation:

The work done by a force when moving an object is given by:

[tex]W=Fd cos \theta[/tex]

where :

F is the magnitude of the force

d is the displacement

[tex]\theta[/tex] is the angle between the direction of the force and the displacement

In this problem, we have:

W = 500 J is the work done by Maria

F = 100 N is the force applied by Maria

[tex]\theta=0^{\circ}[/tex], assuming the direction of the force is parallel to the displacement

So we can rearrange the equation to solve for d, the displacement:

[tex]d=\frac{W}{F cos \theta}=\frac{500}{(100)(cos 0)}=5 m[/tex]

So, the book was moved 5 meters.

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a) Change in momentum: -300 kg m/s

b) Force felt by the jumper: -300 N

Explanation:

a)

The change in momentum of an object is given by

[tex]\Delta p = m(v-u)[/tex]

where

m is the mass of the object

v is the final velocity

u is the initial velocity

For the jumper in this problem, we have

m = 60 kg (mass of the jumper)

v = 0 (final velocity is zero)

u = 5.0 m/s (initial velocity before he hits the mat)

Substituting,

[tex]\Delta p = (60)(0-5.0)=-300 kg m/s[/tex]

Where the negative sign means that the direction of the change in momentum is opposite to the direction of motion.

b)

According to the impulse theorem, the change in momentum of an object is equal to the impulse exerted on it:

[tex]\Delta p = F\Delta t[/tex]

where

F is the force exerted on the object

[tex]\Delta t[/tex] is the time interval

In this problem, we have

[tex]\Delta p = -300 kg m/s[/tex] (change in momentum)

[tex]\Delta t = 1 s[/tex] (duration of the  collision)

Solving for F,

[tex]F=\frac{\Delta p}{\Delta t}=\frac{-300}{1}=-300 N[/tex]

Where the negative sign means that the direction of the force is opposite to the direction of motion.

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Politics is important as it governs decision making within societies and manages conflict, while political science provides an understanding of these processes and systems, enabling informed citizenship.

Politics and political science are important for several reasons. Firstly, politics is how societies make collective decisions. It determines the distribution of power, resources, and responsibilities within a society. Additionally, politics also manages conflict and ensures social order. Secondly, political science is the systematic study of politics and government. It equips individuals with the knowledge and analytical skills to understand political behavior and policymaking processes, which is essential for informed citizenship.

Through political science, we can understand how different political systems work, compare them, and analyze their impacts on their constituents. Whether intending to participate directly in politics or just wanting to be a well-informed citizen, understanding politics and political science is integral.

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Final answer:

Politics and political science are crucial as they determine resource allocation and decision-making within societies. Understanding and participating in politics can shift power toward ordinary people and reflect public interests. Political science uses empirical evidence and analytical tools to interpret political actions and systems.

Explanation:

Importance of Politics and Political Science

Politics and political science are pivotal because they deal with critical questions like who gets what, when, and how. Politics fundamentally addresses the allocation of resources and the mechanisms of decision-making within societies.

Political science is the systematic study of these processes, providing insights into government policies, institutional arrangements, and collective behaviors.

Knowledge in this field empowers citizens to engage meaningfully in their governance and to advocate for fairer, more representative systems.

Citizen engagement is essential for a functioning democracy, as it ensures that the government reflects the public interest. Understanding politics is not just for students at elite universities; it is crucial for all to recognize that political systems and conflicts deeply affect their lives.

Politics is not a spectator sport; active involvement and collective action can shift the balance of power towards ordinary people.

Political science students and scholars endeavor to answer why certain political actors behave as they do and to infer cause-effect relationships from empirical evidence.

The study of politics involves using tools such as probability, statistics, and logic to extract meaningful inferences from qualitative and quantitative data. For faculty, imparting this knowledge to students is a dual task of nurturing civic engagement and fostering academic inquiry into political behaviors and systems.