Answer:
Typhus fever: Rickettsia prawazekii
strep throat: Streptococcus pyogenes
diarrhea: Escherichia coli
staph infections: Staphylococcus aureus
tuberculosis: Mycobacterium tuberculosis
Lyme disease: Borrelia burgdorferi
Explanation:
Typhus fever is a bacterial disease which spread through a vector usually lice. The epidemic thymus is caused by Rickettsia prawazekii.
Strep throat is caused by bacterium Streptococcus pyogenes which is a highly contagious bacterium.
E. coli O157: H7 is a virulent strain of Escherichia coli which is responsible for foodborne diseases and diarrhea.
Staphylococcus aureus is responsible for spreading staph infection. It can become dangerous if it gets into blood.
Mycobacterium tuberculosis is responsible for causing tuberculosis. This bacteria usually affects the lungs but able to damage other body parts.
Borrelia burgdorferi bacteria is responsible for spreading Lyme disease. The bacteria is transmitted through a bite of blacked legged tick.
A teratogen: a) May be a virus, a drug, a chemical, radiation, or environmental pollutants Is usually inherited from the mother b) Cannot cross the placenta during the period of the embryonic stage c) Can be counteracted by good nutrition most of the time.
Answer:
Option-A
Explanation:
A teratogen refers to a agent which can cause abnormal development of the foetus during pregnancy. A teratogen affect the growth of the foetus usually during after 10 to 14 days of conception.
A teratogen is a substance which is usually found in the environment to which the pregnant lady is exposed therefore there are four types of teratogens found: the biological agents which could cause infection, the physical agents like chemicals, metals heat and radiation and the drugs and chemicals from the environment.
Thus, Option-A is the correct answer.
teratogens found in the environment and in extraordinary circumstances can include metals, chemicals, radiation, and even heat. Examples of these teratogens can include mercury, potassium iodide, nuclear fallout radiation, and even high-temperature hot tubs!
eratogens are classified into four types: physical agents, metabolic conditions, infection, and finally, drugs and chemicals.
Imagine you genetically engineered a neuron to produce voltage-gated Na" and K channels that opened at the same time in response to a change in voltage. How would that change the recording shown in the figure? eacitation 1 4 Resting potential A) Threshold values would increase B) The peak voltage would be higher. C) The peak would occur over a longer period of time. D) The period of hyperpolarization would be longer. E) No action potential would be generated.
Answer:
E) No action potential would be generated.
Explanation:
As we know the voltage gated Na and K channels has specific roles in the generation of action potential. When both the channels are opened at the same time sodium will move inside and potassium will move outside no action potential would be generated.
At the peak of action potential , area of the neuron is about 40 mV positive. Now when the voltage becomes positive , sodium channels close and the potassium channels open.
When the potassium channels open , they cause the potassium ions to rush out of the cell thus causing the voltage to become negative again.
Hence E) No action potential would be generated is the right answer.
A scientist conducted an investigation about the effects of diet on disease resistance in rats and made surprising observations. The mice with a genetic ear mutation seemed to show similar patterns of resistance compared to mice with normal ears.
Based on this information, what will most likely occur?a. She will perform a second investigation on the role of certain genes in disease resistance.b. She will revise her hypothesis to pertain to mutations rather than diet, and update her data accordingly.c. She will use this information to determine that her original question was nonscientific, so she will revise it.d. She will determine that her hypothesis was invalid because resistance must be genetic.
Answer:
B
Explanation:
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The nurse reviews the medication history of a postoperative patient, which shows carbidopa-levodopa with selegiline, along with meperidine for pain, with instructions to begin taking entacapone with each dose of carbidopa-levodopa after 10 days. What is the appropriate nursing action?
1
Hold the meperidine and call the health care provider.
2
Administer all medications and monitor blood pressure hourly.
3
Administer the meperidine as ordered and hold the entacapone.
4
Administer the meperidine as ordered and hold the carbidopa-levodopa through the postoperative period.
Answer:
Hold the meperidine and call the health care provider.
Explanation:
Parkinson's disease may be defined as the medical condition in which the movement of the individual gets affected. This is a progressive disorder that might also causes stiffness.
Carbidopa-levodopa and selegiline medication is given to the patient suffering from Parkinson's disease. Selegiline and meperidine can be given together as it may cause disorientation in the patient. The nurse will give meperidine for the proper treatment of the patient. The nurse calls the health care provider to provide emergency and extra medical care to the patient.
Thus, the correct answer is option (1).
Which statement is true?
a. G-C base pairs have three hydrogen bonds while A-T base pairs have two hydrogen bonds.
b. A-T base pairs have three hydrogen bonds while G-C base pairs have two hydrogen bonds.
Answer: The correct answer is option A)
G-C base pairs have three hydrogen bonds while A-T base pairs have two hydrogen bonds.
Explanation:
The double helix of DNA is held together by hydrogen bonds between pairs of bases. . Guanine pair with Cytosine base with three hydrogen bonds while Adenine pair with Thymine with two hydrogen bonds.
This makes the base sequence of the DNA complimentary
. In pea plants, the allele for tall plants (T) is dominant to the allele for short plants (t). You observe that the offspring of a cross include 78 tall plants and 27 short plants. a. What was the probable allele combination of the two parent plants? b. How would your answer change if the offspring included 121 tall plants and 118 short plants?
Answer:
a) Genotype of each parent plant= Tt
b) Genotypes of parent plants= Tt and tt
Explanation:
a) In the first cross, the tall and short progeny was obtained in almost a 3:1 ratio (78: 27). This means that both the parent plants were heterozygous for the gene of plant height. The genotype of each of the parents was Tt. A cross between Tt and Tt gives following progeny ratio=
Tt x Tt = 3 tall (1/2 TT and 1/4 Tt) : 1 short (1/4 tt)
b) In the second cross, tall and short progeny was obtained in almost a 1: 1 ratio (121: 118). This means that one parent plant was homozygous recessive (tt) and the other was heterozygous dominant (Tt).
Tt x tt = 1 tall: 1 short.
A student creates a gram stain on a bacterial sample that has a mix of gram-negative and gram-positive organisms. The student accidentally forgets the decolorizer step. What would the outcome of the gram stain be?
Answer:
All the bacteria would appear purple(gram- positive)
Explanation:
Gram stain is used for distinguishing gram-positive and gram-negative bacteria. Gram-positive bacteria appear purple because it does not gets destain after decolorizing step and gram-negative bacteria appears read or pink because it gets decolorized after decolorizing step and then it gets stained by safranin which provides a pink color to gram-negative bacteria.
So if a student forgot the decolorizing step then gram-negative bacteria will not get decolorized and will not take safranin stain so even gram-negative cells will appear violet. Therefore all the bacteria will appear violet or purple(gram-positive).
In a Gram Stain procedure, if the decolorizer is not applied, both gram-positive and gram-negative bacteria will retain the primary violet dye and appear as gram-positive, thereby hindering the differentiation between the two types. All the bacteria would appear purple under a microscope.
Explanation:The process of Gram Staining involves the application of a series of dyes that differentiate bacteria into two large groups, gram-positive and gram-negative, based on their cell wall composition. In this procedure, a purple crystal violet stain is applied to the bacterial sample after heat-fixing, followed by the application of Gram's iodine, a mordant. A crucial step where a decolorizer is applied is meant to wash out the dye from certain types of bacterial cells, leaving them colorless. A counterstain, usually safranin, is then added which dyes these decolorized cells pink. Gram-positive cells have thick peptidoglycan layers in their cell walls that retain the violet dye and appear purple.
If the student forgets to apply the decolorizer, both gram-positive and gram-negative bacteria will retain the crystal violet dye applied in the primary step and hence will appear gram-positive. This will prevent the differentiation between the two types, and all the bacteria in the sample will appear purple under a microscope.
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John Needham performed an experiment testing spontaneous generation. He boiled chicken broth, placed it in a sterile flask, and then sealed the flask. After a few days, Needham observed microorganisms in the flask. Based on current understanding, how was his experiment flawed?
A. Boiling activated dormant microorganisms present in the broth.
B. Boiling the broth did not kill all microorganisms present.
C. Microorganisms entered the broth from the flask itself after the flask was sealed.
D. After Needham boiled the broth, microorganisms entered from the air.
Answer:
D
Explanation:
John Needham may not have aseptically transferred the broth after it was boiled which might have allow air to enter after the broth was boiled. The experiment has been repeated with control that were not boil; the broth was sealed in the flask and properly boiled; no grow was noticed in the broth plus flask that was boiled properly and sealed while the control which was not sealed ( exposed to air) had growth suggesting that the microorganism or their spore in the air was responsible for the growth.
John Needham's experiment was flawed because he did not boil the broth long enough to kill all the microorganisms, which led to their growth and the mistaken inference of spontaneous generation. So the correct option is B.
Explanation:John Needham's experiment was flawed because boiling the broth did not kill all the microorganisms present. Based on current scientific understanding, Needham likely did not boil his chicken broth long enough to eradicate all the microscopic life forms it contained. Subsequently, these surviving organisms multiplied, leading to the clouding of the broth that Needham observed. This mistake led him to mistakenly support the hypothesis of spontaneous generation, the idea that life could emerge from non-living matter automatically.
Other scientists, such as Lazzaro Spallanzani and Louis Pasteur, would later design more rigorous experiments that avoided such flaws. Spallanzani's experiments involved extended boiling, which contradicted Needham's findings by showing that microbes did not appear if the flasks remained sealed after boiling. Pasteur improved upon this with his swan-neck flask experiment, definitively proving that the microorganisms came from the air, and not from a hypothetical 'life force', thus discrediting the theory of spontaneous generation and supporting the concept that 'life only comes from life'.
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are mutations in dna advantageous or disadvantageous
Answer: Both
Explanation: it is advantageous in a way that it increases the chances for organism to be adjusted in the environment such as survival chance is increased sometimes by positive mutations. Sometimes replacing the wrong gene with right gene by the mutation is advantageous.
Sometimes, mutations in DNA doesn't have any effect, means it has neutral effects.
It is disadvantageous sometimes that it results in the occurrence of disease which may be serious disease like heart disease. Tiny mutations also results in disorders.
If the bacterium Staphylococcus aureus experiences a cost for maintaining one or more antibiotic-resistance genes, then what should happen in environments from which antibiotics are missing?
A) These genes should continue to be maintained in case the antibiotics ever appear.B) These bacteria should be outcompeted and replaced by bacteria that have lost these genes.C) The bacteria should try to make the cost worthwhile by locating, and migrating to, microenvironments where traces of antibiotics are present.D) The bacteria should start making and secreting their own antibiotics.
Answer:
The correct answer is B) These bacteria should be outcompeted and replaced by bacteria that have lost these genes.
Explanation:
If a bacteria experience a cost of maintaining some antibiotic-resistant gene, then they will able to flourish more in that environment which contains the antibiotic against which the antibiotic-resistant gene is present in the bacteria.
But if this bacteria is grown in medium that lack antibiotic then this bacteria will be outcompeted replaced by those bacteria who have lost these genes because these new bacteria are more adapted to this condition than the antibiotic-resistant bacteria. Therefore the correct answer is B.
Antibiotics are missing B) These bacteria should be outcompeted and replaced by bacteria that have lost these genes Therefore , B) These bacteria should be outcompeted and replaced by bacteria that have lost these genes is correct .
In environments where antibiotics are absent or not present, the cost associated with maintaining antibiotic-resistance genes becomes a significant factor.
If a bacterium like Staphylococcus aureus carries antibiotic-resistance genes but does not encounter antibiotics in its environment, it will likely face a fitness disadvantage due to the energy and resources it expends to maintain these genes.
Natural selection favors traits that enhance an organism's survival and reproduction in its specific environment.
If the environment does not contain antibiotics or selective pressure for antibiotic resistance, the cost associated with maintaining resistance genes becomes a burden. Bacteria constantly strive to optimize resource allocation and maximize their fitness.
Bacteria with antibiotic-resistance genes may replicate at a slower rate or utilize resources less efficiently due to the cost of maintaining these genes.
In contrast, bacteria without these genes can allocate resources more effectively and may outcompete the resistant bacteria in a non-antibiotic environment.
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Six-month-old Eva dropped her teething ring in a fairly rigid way, simply letting go and watching it with interest. This example demonstrates Piaget's belief that at first, schemes are __________.
A) sensorimotor action patternsB) deliberate and creativeC) preoperational thoughtD) disorganized and random
Option A
This example demonstrates Piaget's belief that at first, schemes are sensorimotor action patterns
Explanation:
When a kid is born, he/she begins growing both bodily and cognitively. As newborns improve cognitive abilities, they begin reminiscing about their habits and responding to various provocations such as sounds, action, and tremors. This is termed as the sensorimotor stage.
During this stage, babies acquire a perception of the environment by analysis and fault managing their minds and functions. The chief growth through the sensorimotor stage is the recognition that things exist and incidents happen in the context autonomously of one's individual efforts.
What pigment molecule absorbs blue and red light to provide energy for photosynthesis
Answer:
chlorophyll a
Explanation:
This is the pigment s that absorbs light in blue and red light wavelengths when illuminated by sunlight with all wavelength.However it reflects green light. This explains the reason why green plants appears green to our eyes,
the pigments are located in leave and stem of green plant.
Blue light has a wave length of 430nm, while Red wave length is 662nm
Untreated diabetes mellitus can lead to a condition in which the blood is more acidic. True or False
Answer:
TRUE as diabetic ketoacidosis
Explanation:
It is more common in individual with diabetes type 1, because they do not produce insulin than type 2 who produce Insulin.
The elevated acid is due to untreated diabetes, excess glucose is wasted in urine(polyuria), and dehydration sets in,because no insulin to facilitate glucose entry into cells through GLUT transporters. Elevated glucagon(in absence of Insulin) facilitated the breakdown of glycogen by the liver to glucose which is further excreted in the urine ( Glycogenlysis)
Therefore the body is depleted of glucose.To make up for this the body withdrawal free fatty acids from adipose tissues and break it down to glucose,(beta oxidation) in the liver(the process is called GLUCONEOGENESIS formation of glucose from non carbohydrate molecules).
The above produces KETONES in the body. Ketones has a very low pH;therefore building up of KETONES in the blood leads to KETOACIDOSIS.
The first stage of neural communication, _____, refers to the movement of the signal within a single neuron, while _____ refers to the movement of a signal between neurons.
Answer:
Conduction
Transmission
Explanation:
Neuronal Conduction is the first stage of neural communication in which communication occurs through electrochemical channels. Electrical signals produced via chemical molecules are passed to the cell body via the dendrites and through synapses, bracing and invigorating the neuron to generate their own stimuli as it is being relayed down to the axon terminal of a neuron. The neurons in the electrochemical channels helps to coordinate and monitor the flow of these electrical charges through the membrane mediated channel in order to conduct nerve impulses.
Neuronal transmission talks about the transference of signals or stimuli via the neurotransmitters(signaling molecules). They are relayed down by the axon terminal of a neuron as earlier stated above. At the terminal end, they coupled at receptors site with other dendrites of another neurons to transfer the signal across.
While a relatively inefficient mode of transmission, _____________ accounts for 90% of HIV infections worldwide.
Answer:
The correct answer is - sexual transmission.
Explanation:
HIV infections can be transmitted by the various mode. Sexual transmission is one of the major mode of transmission which is comprise almost 90 % of HIV infection, according to the reports. These are relatively inefficient mode, unprotected or unnatural sex is the major mode for the HIV transmission worldwide. Cases are now comparatively less than when it was discovered due to awareness.
Thus, the correct answer is - sexual transmission.
A population of rabbits introduced to an island grows rapidly for a few years, and then growth slows and stabilizes. The population becomes stable because:
A) the intrinsic rate of increase has declined.
B) environmental resistance declined.
C) immigration was reduced.
D) the carrying capacity has been reached.
Answer:
The correct answer is D) the carrying capacity has been reached.
Explanation:
The carrying capacity of an ecosystem is determined by the maximum number of individuals of a species it can support indefinitely without significantly depleting the natural resource required for species survivability like food, water, etc.
So when a species is introduced in an area it can grow with the intrinsic rate until the environment reaches its carrying capacity. After carrying capacity has been reached then the number of individuals will not grow further and will become stabilized due to environmental resistance. Therefore the correct answer is D.
Final answer:
The rabbit population stabilized because it d) reached the carrying capacity of the environment, which is the maximum number of individuals that the resources can support.
Explanation:
The stable population of rabbits on the island became such due to the fact that d) the carrying capacity of the environment had been reached. After the initial period of exponential growth, where resources are plentiful and the birth rates exceed death rates, population growth slows and follows a logistical growth curve due to the limiting resources. This logistic growth leads to an S-shaped curve characteristic of populations approaching their carrying capacity. At this point, birth and death rates become stable, and the growth rate hits zero, indicating that the population size has stabilized at the maximum number the environment can manage. If the population were to go above this level, it would face intraspecific competition for the scarce resources and the number of individuals would decline until it stabilizes back at the carrying capacity again.
How does carbon move through biotic and abiotic sources?
Answer:
Thus, an abiotic factor (carbon dioxide) helps create a biotic factor (the plants made out of carbohydrates). Once cellular respiration starts in the organism, it releases Carbon dioxide back into the atmosphere, and the cycle repeats
Explanation:
Nutrients move through the ecosystem in biogeochemical cycles. ... The chemicals travel not only through the biotic and abiotic components of an ecosystem, but they also travel through an organism. The abiotic factors of an ecosystem include: (1) water (hydrosphere), (2) land (lithosphere), and (3) air (atmosphere).
A resident of a long-term care facility refuses to eat until the client has had hair combed and makeup applied. In this case, what client need should have priority.
Answer: They should make sure his/hers hair combed and makeup applied then given the food. As fast as possible!
Explanation: brainly pls
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The resident's need for grooming before eating should be prioritized as it addresses their psychosocial needs and self-consciousness. Meeting this need may improve their willingness to eat and overall mental well-being.
In this scenario, the primary client need should be psychosocial support. The resident's refusal to eat until they have had their hair combed and makeup applied suggests a high level of self-consciousness. People who are self-conscious often spend more time on their appearance to feel better about themselves.
To address this, the care facility should prioritize fulfilling this grooming need before mealtime. This approach respects the resident's dignity and can significantly improve their mental and emotional well-being, potentially increasing their willingness to eat and participate in other activities.
The two strands in a DNA helix are described as being antiparallel, or in opposite orientations. If one DNA strand is in the 5' to 3' orientation, the complementary DNA strand is orientated in which direction?
Answer: The answer is 3' - 5' direction
Explanation:
Since the template strand runs in 5' - 3' direction, antiparallel nature of the DNA double helix explains that the complimentary strand (non-template strand) runs in a 3' - 5' direction
Answer:3' to 5'
Explanation:DNA consist of two strands that runs anti-parallel. the first called the leading strand and its runs from 5' to 3' orientation meaning it runs from carbon 5 to carbon 3 while the second strand is called the lagging strand or the ozazaki fragment it runs from 3' to 5' i.e from carbon 3 to carbon 5.
The two strands cannot be replicated in a row hence the need for the break into the leading that replicates towards the replication fork and lagging strand replicates towards the opposite direction.
\Archaea and bacteria * 3 points have mitochondria and chloroplasts have similar cell structures have similar genetics and biochemical composition square
Answer:
have similar cell structures
Explanation:
Archaea and bacteria are single-cell organisms that are classified as prokaryotes. They both possess similar cell structures as they tend to both have the same shape and size when viewed with a microscope. They both do not have a nucleus or other membrane-bound organelles like mitochondria and chloroplasts. One of the structures they share in common is the thread-like structure called flagella, which they use as in navigation around their environment.
Irrespective of the fact that they have similar cell structure, advanced studies have shown that archaea and bacteria have different genetic coding made of different proteins. Both cells also differ in the composition of their cell walls.
An adaptation is a structure or function that is common in a population because it enhances the ability to survive and reproduce in a particular environment. Provide one example and an explanation of one adaptation in the Anolis lizards.
Answer:
The legs of the lizard
Explanation:
Some Anolis species have different sizes of legs according to what part of the tree they inhabit and forage. An ancestral Anolis lizard species might have gave rise of different species nowadays. Anolis species that lives on twigs have shorter legs than the Anolis lizards that live on the trunk of a tree. This observation is explained by adaptive radiation, which lead to lizards with long and short legs to survive specially in the trunk and twigs, respectively. The lizards with long legs could survive and reproduce more than short legs lizards in the trunks of trees, therefore a population of long legs gained more individuals throughout generations and became more predominant on those areas.
An adaptation in Anolis lizards is their varying limb lengths, with some species having longer legs for ground movement and others having shorter limbs for navigating narrow branches, which aids in survival and reproduction.
Explanation:An adaptation is a heritable trait that improves an organism's ability to survive and reproduce in a specific environment. One example of an adaptation in the Anolis lizards is their different limb lengths, which correlate with the habitat they occupy. For instance, some species have evolved longer legs to facilitate better movement on the ground, whereas others have shorter limbs that are advantageous for navigating narrow branches.
This limb variation is directly related to the Anolis lizards' ability to exploit different ecological niches and avoid competition. Lizards with longer legs can run faster on open ground to escape predators and cover more territory, enhancing their survival and reproductive success. In contrast, those with shorter legs have a better grip and can move more agilely among twigs and leaves, which also increases their chances of survival and reproduction in their respective habitats.
The plasma membrane is involved in which activities? Choose one or more:
1. import and export of nutrients and wastes
2. cell signaling
3. cell recognition
4. cell growth and motility
5. RNA interference
6. DNA replication and repair
Answer:
1. import and export of nutrients and wastes
2. cell signaling
3. cell recognition
4. cell growth and motility
Explanation:
Plasma membranes are selectively permeable which means it only allows selective molecules to cross through it. So the plasma membrane helps in the import and export of nutrients by simple diffusion, facilitated diffusion or through active transport.
There are membrane protein embedded in the plasma membrane which have different role. Some help in cell signaling like GPCR, some help in cell recognition and some act and transporter proteins.
The plasma membrane is also responsible for cell growth and motility because it allow the raw materials and signals to pass through it which is required by the cell to metabolize and grow. So 1,2,3,4 is the correct answer.
The plasma membrane plays a fundamental role in import/export of substances, cell signaling, cell recognition, and cell growth/motility. It does not directly contribute to RNA interference or DNA replication/repair.
Explanation:The plasma membrane is responsible for a number of vital cellular activities. It plays a crucial role in the import and export of nutrients and wastes. This mechanism allows for the exchange of substances vital for cellular activity and the elimination of waste generated by the cell. The membrane is also involved in cell signaling, allowing cells to communicate with each other. It does this through the use of specific receptor proteins embedded in the membrane. Another important function is cell recognition, which helps the body distinguish between its own cells and foreign cells. Lastly, it plays a role in cell growth and motility by expanding and aiding cell movements. It does not directly contribute to RNA interference, DNA replication, or repair, as these processes occur within the cellular interior.
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Muscle cells make different proteins than nerve cells because they have different sequences of dna. True or False
Answer:
False
Explanation:
All the cells of a multicellular organism such as humans are derived from the zygote. Therefore, all the cells share identical DNA sequences irrespective of the tissues or the organs in which they are present. Muscle cells and nerve cells have identical DNA sequences but make different types of proteins due to tissues or organ-specific expression of some genes.
Muscle cells express specific genes and do not express the other genes which are otherwise expressed in the neuron cells. This spatial and tissue-specific expression of specific sets of genes allows the expression of different proteins in the different types of the cells of an organism despite the presence of identical DNA sequences in them.
The claim that muscle cells and nerve cells make different proteins because they have different sequences of DNA is false. The differing proteins stem from different genes in the same DNA sequence being expressed.
Explanation:The statement is false. Every cell in a single organism, including muscle cells and nerve cells, has the exact same DNA sequence. The difference in the proteins they make is due to a process called gene expression. Through gene expression, certain genes in the DNA are 'turned on' or 'turned off'. This process is what allows the cells to fulfil different functions in the body. Hence, muscle cells and nerve cells create different proteins not because they have different DNA sequences, but because they express different sections of the same DNA sequence.
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A client who has undergone a colostomy several days ago is reluctant to leave the hospital and has not yet looked at the ostomy site. Which measures will most likely promote coping?
The question is incomplete. The complete question is as follows:
A client who has undergone a colostomy several days ago is reluctant to leave the hospital and has not yet looked at the ostomy site. Which measures are most likely to promote coping? Select all that apply.
a.Remind the client frequently that he will be responsible for caring for the colostomy at home
b.Ask a member of the local ostomy club to visit with the client before discharge
c.Ask the enterostomal nurse specialist to consult with the client before discharge
d.Remind the client frequently that infection is a major complication of a colostomy
e.Ask the client to begin doing one part of the ostomy care and increase tasks daily
Answer:
Colostomy may be defined as the surgical procedure in which the large whole is created in the large intestine. This provides the alternative means to throw feces out of the body.
The medical assistant must cope positively with the patient. The attendant must visit the client before the discharge of the patient. The proper medicine and prevention from infection must be instructed to the patient. The enterostomal nurse must visit the patient.
Answer:
Call for the ostomy nurse to teach them how to change their appliance, and let them see their new stoma. Set them up with an appointment with an ostomy nurse that soon, so they can get scripts for supplies, and resolve any post-op ostomy product or leakage problems later on, since the products they are given inpatient may not be the right one for them once the swelling goes down. Let the nurse explain things, they may step out to gather supplies that are more appropriate for the patient to take home. Once the nurse is done educating, the patient will be ready for discharge.
A client has a history of sickle cell anemia with several sickle cell crises over the past 10 years. What blood component results in sickle cell anemia?
Answer:
Answer is hemoglobin S.
Explanation:
Hemoglobin S is considered as an abnormal type of hemoglobin which a child can be inherited from the parents. This cause the red blood cells to have distinct shapes from their normal shape. The red blood cells will have a sickle shape which is different from their normal round disk shape.
The correct order of the taxonomic groups from most inclusive to most specific is species, genus, family, order, class, phylum, kingdom. True / False.
The statement is false; the correct order from most inclusive to most specific is Domain, Kingdom, Phylum, Class, Order, Family, Genus, and Species. Species is the most specific, and Domain is the most inclusive.
The statement given is false. The correct order of the taxonomic groups from most inclusive to most specific is actually the opposite. The hierarchy of biological classification's eight major taxonomic ranks can be remembered by the following: Domain, Kingdom, Phylum, Class, Order, Family, Genus, and Species, with Domain being the most inclusive and Species the most specific. In other words, species are grouped within genera, genera are grouped within families, families are grouped within orders, and so on up to the domain.
Using the taxa provided, the correct order from most specific to most inclusive is:
Species
Genus
Family
Order
Class
Phylum
Kingdom
Domain
Each level represents a more general grouping of organisms. At each classification category, organisms become more similar because they are more closely related. As we move up the ranks, the number of shared characteristics decreases, making the groups more inclusive.
Describe the components that should be included in a well-written scientific abstract and what should be excluded.
PLEASE HELP NEED ANSWER ASAP.
Answer:
The components of abstracts that should be included are as follows: " introduction, Description, limitations, conclusion". Other than these components anything else should be excluded.
Explanation:
The various components of an scientific abstract that should be included are as follows:
Introduction: In this part of the abstract it should contain the brief idea about the research.
Description: In the second part it should contain the research and the objective of the research and also about the analytical methodologies that has been applied in the research.
Critical: This is part in which the limitation for the research are present.
Language: The most important factor, the language used should be very formal type.
Conclusion: The things and ideas that had been learnt during the period of research. It should also contain the new findings and the trends that has came out during the research.
You want to test whether duration of light exposure affects fish reproduction. What would be your control group and experimental group?
Answer and Explanation:
During an experiment, data from an experimental group are compared with the data of a control group. These two sets are identical in all aspects except for the independent variable that the researcher changes in the experimental group to observe how they affect the individuals. This variable keeps constant in the control group.
The experimental group is the one that receives the experimental procedure, with changes in the independent variable. There can be several experimental groups.
In the control group, the variable measured keeps constant, not influencing the results. This isolates the effect of the independent variable on the experiment and helps to find alternative explanations to the different results.
In the exposed example:
Control group: Certain amounts of fishes exposed to a normal number of light hours per day. For example, if under natural conditions in its original environment the species is exposed to 12 hour light, then the control group should be exposed constantly to 12 hours light a day to maintain its normal reproductive levels.Experimental group: Certain amounts of fishes, equal to the control group, exposed to a different number of light hours per day. For example, there might be 5 experimental groups: one of them exposed to 4 hours light, a second group exposed to 8 hours light, the third group exposed to 12 hours light (The same as the control group), the fourth group exposed to 16 hours light, and the fifth group exposed to 20 hours light.Except for light, the rest of the variables should be the same for all the groups.
The fact that protein-based hormones are hydrophilic means that they:___________
a. are lipid-soluble.
b. do not cause conformational changes.
c. can diffuse across the membrane.
d. have to bind to receptors to cross the membrane.
Answer: The answer is that have to bind to receptors to cross the membrane.
Explanation:
A hydrophilic substance can easily dissolve or absorbed in a water containing vessel, not a fat or lipid vessel like biological membranes.
Now, protein-based hormones like dopamine or serotonin ARE NOT LIPID-SOLUBLE; so, have to bind to receptors positioned in the membrane and MAY also require energy in form of ATP for across the membrane before they would exert their function on the target cell or organelles.
You are an archaeologist who has just found an ancient fire ring containing charcoal fragments. You send these fragments to the lab for Carbon-14 analysis. The report you receive from the lab states that these fragments have 25% of the amount of Carbon-14 compared to modern wood. Using 5730 years as the half-life of Carbon-14, you conclude that these charcoal fragments are about ________ years old. Can you explain how you get an answer of 11460? Thank you!
Answer:Thus we can conclude that these charcoal fragments are about 11460 years old.
Explanation:
a) for completion of half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]
[tex]k=\frac{0.693}{5730years}=1.21\times 10^{-4}years^{-1}[/tex]
Expression for rate law for first order kinetics is given by:
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant = 100
a - x = amount left after decay process = 25
b) for completion of 75 % of reaction
[tex]t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{100}{25}[/tex]
[tex]t=11460years[/tex]
Thus we can conclude that these charcoal fragments are about 11460 years old.