Answer:
-5/6
Step-by-step explanation:
covert the mixed number into a improper fraction
4/3 + (- 13/6) =
Find LCD which is 6 so
[tex]\frac{4}{3} * 2[/tex]
8/6 + (-13/6) =
Which is -5/6
For the following linear equations, determine which inverse operation allows you to determine the solution of the equation. In your final answer, also include the solution to each equation.
1) n/5 = -0.3
2) -2n = 4 1/3
Answer:
see explanation
Step-by-step explanation:
(1)
Given
[tex]\frac{n}{5}[/tex] = - 0.3
Since n is divided by 5 then use the inverse operation, multiplication.
Multiply both sides by 5 to clear the fraction
n = 5 × - 0.3 = - 1.5
(2)
Given
- 2n = 4 [tex]\frac{1}{3}[/tex] ← change to an improper fraction
- 2n = [tex]\frac{13}{3}[/tex]
Since n is multiplied by - 2 then use the inverse operation, division.
Divide both sides by - 2
n = [tex]\frac{13}{-6}[/tex] = - [tex]\frac{13}{6}[/tex]
2x – 6y = 5
x – 3y = -12
show all the steps to solve the system of equations below using substitution.
You can use any of the available methods for solving system of linear equations like method of elimination or method of substitution etc.
There are no solutions to the given system of equations.
How to find the solution to the given system of equation?For that , we will try solving it first using the method of substitution in which we express one variable in other variable's form and then you can substitute this value in other equation to get linear equation in one variable.
If there comes a = a situation for any a, then there are infinite solutions.
If there comes wrong equality, say for example, 3=2, then there are no solutions, else there is one unique solution to the given system of equations.
Using the above method to solve the given system of equationsThe given system of equations is
[tex]2x - 6y = 5\\x - 3y = -12[/tex]
Using second equation to get x in terms of y
[tex]x - 3y - 12\\x = 3y - 12[/tex]
Substituting this expression for x in place of x in first equation,
[tex]2x - 6y = 5\\2( 3y - 12) - 6y = 5\\6y - 24 - 6y = 5\\-24 = 5[/tex]
The last statement we got is incorrect.
That conclusion above shows that the given system of equation has no solution.
We could've detected it from the fact that
[tex]2x - 6y = 5\\\text{dividing both sides by 2}\\x - 3y = 2.5[/tex]
Converting both equations to slope intercept form, we get:
[tex]x - 3y = 0.5\\\\y = \dfrac{1}{3}x - \dfrac{1}{6}[/tex]
and
[tex]x - 3y = -12\\\\y = \dfrac{1}{3}x + 4[/tex]
We see that both lines have same slope but different y intercept, which tells that both lines are parallel but not coincident, thus, not intersecting and thus, no common point(common points are solutions).
The graph of this system of linear equation is given below where lines represented by both linear equations are plotted.
Thus,
There are no solutions to the given system of equations.
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Final answer:
To solve the system of equations using substitution, rearrange one of the equations to solve for a variable and substitute that expression into the other equation. In this case, the system of equations is inconsistent and has no solutions.
Explanation:
To solve the system of equations using substitution, we rearrange one of the equations to solve for a variable, then substitute that expression into the other equation. Let's solve the system of equations:
Equation 1: 2x - 6y = 5
Equation 2: x - 3y = -12
In Equation 2, solve for x: x = 3y - 12Substitute this expression for x into Equation 1:2(3y - 12) - 6y = 56y - 24 - 6y = 5-24 = 5This is a contradiction, which means there is no consistent solution for x and y in this system of equations.Therefore, the system of equations is inconsistent, and there are no solutions.
A frequency distribution lists the ______ of occurrences of each category of data, while a relative frequency distribution lists the __________ of occurrences of each category of data.
Answer:
number ,proportion
Step-by-step explanation:
Data is a collection of facts, such as numbers, words, measurements, observations. Data is organised in graphs or charts for analysis and conclusions.
A frequency distribution lists the number of occurrences of each category of data.
A relative frequency distribution lists the proportion of occurrences of each category of data.
A frequency distribution lists the number of occurrences, and a relative frequency distribution lists the proportion of occurrences of each category of data. Frequency tables compile occurrences, while relative frequencies are calculated as a ratio of the frequency to the total number of observations. Histograms and bar graphs visually represent these distributions.
A frequency distribution lists the number of occurrences of each category of data, while a relative frequency distribution lists the proportion of occurrences of each category of data. When we compile a frequency table, the data are organized so that we know how many times a particular value or category occurs. For example, a frequency distribution can inform us that 15 students spend five hours or more studying for an exam.
Conversely, a relative frequency distribution provides us with a ratio or fraction that represents how often a value appears relative to the entire set of data. To calculate relative frequency, one would divide each frequency by the total number of observations. If 20 students were surveyed, and 5 studied for more than five hours, the relative frequency would be 5/20 or 0.25 (which can also be expressed as 25%).
Graphical representations such as histograms and bar graphs are valuable for visualizing both frequency and relative frequency. A histogram is suitable for displaying the distribution of interval or ratio variables, particularly with a large number of cases. Bar graphs are more commonly used for nominal or ordinal data, which usually involves fewer categories.
Which of the following combinations of fishing lures and duck decoys is unobtainable to Big Lake Bob in one week's worth of carving? 80 fishing lures and 5 duck decoys 40 fishing lures and 20 duck decoys 50 fishing lures and 10 duck decoys 20 fishing lures and 24 duck decoys c. Which of the following combinations of fishing lures and duck decoys is an efficient combination? 20 fishing lures and 24 duck decoys 50 fishing lures and 0 duck decoys 10 fishing lures and 40 duck decoys 16 fishing lures and 30 duck decoys?
Answer:
b) 40 fishing lures and 20 duck decoys
c) 20 fishing lures and 24 duck decoys
Question:
Attached is the graph to be used to answer the questions.
Step-by-step explanation:
b) Any point above the straight line graph PPF is unobtainable, while points below or on the line graph are obtainable.
Finding each of the points on the graph and determine whether it is above, on or below the line graph.
- Only one point is above the graph (40 fishing lures and 20 duck decoys )
Therefore, 40 fishing lures and 20 duck decoys is unobtainable.
c) for an efficient combination the points must be on the line of the graph (PPF).
The only point that falls on the line of the graph is (20 fishing lures and 24 duck decoys)
Therefore, 20 fishing lures and 24 duck decoys is an efficient combination.
The universally accepted film size for movies has a width of 35 millimeters. If you want to project a movie onto a square sheet that has an area of 100 square meters, what is the scale factor that is needed for the projection of the movie? Explain
Answer:
The scale factor is 285.7143 ≅ 286.Step-by-step explanation:
The square sheet has an area of 100 square meters.
Hence, the width of the sheet is [tex]\sqrt{100} = 10[/tex] meters.
The scale factor is needs to be in such a way, so that the film's wide will be match perfectly with the square sheet. Hence, 35x millimeters = 10 meters = 10000 millimeters .
[tex]x = \frac{10000}{35} = 285.7143[/tex].
There are 8 fish tanks in the pet shop. They just received an order of 216 goldfish. The owner of the pet shop wants each tank to have the same number of fish. How many goldfish will each rank have in it?
Answer:
Each tank would have 27 gold fish in it.
Step-by-step explanation:
Given:
Number of fish tanks = 8
Number of gold fish = 216
We need to find the number of goldfish in each tank.
Solution:
Now we know that;
Number of gold fish must be equal in each tank.
To find the number of gold fish in each tank we will divide Number of gold fish by Number of fish tanks.
framing in equation form we get;
number of gold fish in each fish tank = [tex]\frac{216}{8} = 27 \ fish[/tex]
Hence Each tank would have 27 gold fish in it.
Why is there no commutative property for subtraction or division
Answer:
Because order matters when performing subtraction or division.
Step-by-step explanation:
Consider the provided information.
We need to determine why there no commutative property for subtraction or division.
Commutative property states that although the numbers in an expression are interchanged, there is no change in result.
Let us understand with the help of an example
For addition: The commutative rule is a + b = b + a.
An example in numbers would be 5 + 2 = 2 + 5
Both give 7 as result.
For Subtraction: 4 – 2 = 2, but 2 – 4 = –2
So, in the case of subtraction, moving the numbers around produces a different answer.
For division: 4 ÷ 2 = 2, 2 ÷ 4 = [tex]\frac{1}{2}[/tex]
So, in the case of division, moving the numbers around produces a different answer.
Hence, order matters when performing subtraction or division.
A deck of cards contains 52 cards, of which 4 are aces. You are offered the following. Draw one card at random from the deck. You win $11 if the card drawn is an ace, otherwise you lose $1. If you make this wager very many times, what will the mean outcome be_____________.
Answer:
[tex] E(X) = 11 *\frac{4}{52} - 1*\frac{48}{52} = -\frac{1}{13}[/tex]
So we expect to lose approximately [tex] 1/13[/tex] for this game.
Step-by-step explanation:
For this case we can find the probability of win like this:
[tex] p_w = \frac{4}{52}[/tex]
Since we have 4 aces each time in a total of 52.
And the probability of loss is given by:
[tex] p_l = \frac{48}{52}[/tex]
In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".
And we can find the expected value with this formula:
[tex] E(X) = \sum_{i=1}^n X_i P(X_i) [/tex]
Where X on this case represent the random variable "Amount of money win or loss in the game", for this case we can replace and we got:
[tex] E(X) = 11 *\frac{4}{52} - 1*\frac{48}{52} = -\frac{1}{13}[/tex]
So we expect to lose approximately [tex] 1/13[/tex] for this game.
The mean outcome of this wager is -$0.62, indicating an expected average loss of $0.62 per game.
Explanation:To determine the mean outcome of this wager, we need to calculate the expected value. The probability of drawing an ace from the deck is 4/52, since there are 4 aces out of 52 cards. The payoff for drawing an ace is $11, while the payoff for not drawing an ace is -$1. The expected value is calculated by multiplying the probability of each outcome by its corresponding payoff and summing them up:
Expected value = (Probability of outcome 1 x Payoff for outcome 1) + (Probability of outcome 2 x Payoff for outcome 2)
Expected value = (4/52 x $11) + (48/52 x -$1)
Expected value = -$0.62
Therefore, if you play this game repeatedly, you would expect to lose $0.62 per game, on average. The expected value indicates an expected average loss, so it is not advisable to play this game to win money.
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Ajar contains 8 blue marbles, 6 red marbles, and 10 green marbles. You pick one marble
from the jar. Find the theoretical probability, P(blue or green). Write your answers as a
decimal rounded to nearest hundredth place.
Answer:
.75 is your answer
Step-by-step explanation:
Ms. Vargas owns 4/5 of an acre of land in Tupelo Township. She wants to sell 2/3 or her land to her neighbor. What fraction of an acre does Ms. Vargas want to sell
Final answer:
Ms. Vargas wants to sell 2/3 of her 4/5 acre of land. By multiplying the fractions, we find that she intends to sell 8/15 of an acre to her neighbor.
Explanation:
Ms. Vargas owns 4/5 of an acre of land and wants to sell 2/3 of her land. To find out what fraction of an acre Ms. Vargas wants to sell, we need to multiply these two fractions together.
Here is the step-by-step calculation:
Multiply the numerators (top numbers) of the fractions: 4 × 2 = 8.
Multiply the denominators (bottom numbers) of the fractions: 5 × 3 = 15.
Combine the products to get the fraction of the land she wants to sell: 8/15 of an acre.
Therefore, Ms. Vargas wants to sell 8/15 of an acre of her land to her neighbor.
Volume is the: Select the correct answer below: 1. basic unit for measuring distance 2. amount of matter in an object force per unit 3. area space occupied by any sample of matter
Answer:
Option 3) area space occupied by any sample of matter
Step-by-step explanation:
We define volume of an object as:
It is defined as the space occupies by an object.It is measured in cubic units.It is the quantity of three-dimensional space enclosed by a closed surface.It is different from mass occupied by the object.Thus, it is defined as:Option 3) area space occupied by any sample of matter
It is not a unit for measuring distance.
It cannot be defined as amount of matter in an object force per unit
Find the measure of angle A. Round your answer to the nearest hundredth.
59.00 degrees
49.40 degrees
40.60 degrees
31.00 degrees
Answer:
The answer to your question is 40.60°
Step-by-step explanation:
Data
Right triangle
Opposite side = 6
Adjacent side = 7
Process
1.- To find angle A, use trigonometric functions.
The trigonometric function that relates the opposite side and the adjacent side is tangent
tanA = [tex]\frac{Opposite side}{Adjacent side}[/tex]
2.- Substitution
tan A = [tex]\frac{6}{7}[/tex]
3.- Find tan⁻¹A
tan⁻¹ A = A = 40.60°
They are 13 sales people at a car dealership last year they each sold the same number of cars together they sold 1157 how many cars did each salesperson sell
Answer: each salesperson sold 89 cars last year.
Step-by-step explanation:
The total number of sales people at the dealership shop is 13.
Last year they each sold the same number of cars. The total number of cars that they sold together last year was 1157. Therefore, the number of cars that each salesperson sold would be
Total number of cars sold/ number of salespersons
It becomes
1157/13 = 89
Given this information, in order to use his 4 hours of study time to get the best exam score possible, how many hours should he have spent working on problems and how many should he have spent reading?
Answer:
2 hours working on problems, 2 hours reading
Step-by-step explanation:
The question is incomplete. Here is the complete question:
Ben is a hard-working college senior. One Thursday, he decides to work nonstop until he has answered 150 practice problems for his math course. He starts work at 8:00 AM and uses a table to keep track of his progress throughout the day. He notices that as he gets tired, it takes him longer to solve each problem.
Time | Total Problems Answered
8:00 AM | 0
9:00 AM | 60
10:00 AM | 105
11:00 AM | 135
Noon | 150
The marginal, or additional, gain from Ben's first hour of work, from 8:00 AM to 9:00 AM, is 60 problems.
The marginal gain from Ben's third hour of work, from 10:00 AM to 11:00 AM, is 30 problems.
Later, the teaching assistant in Ben's math course gives him some advice. Based on past experience, the teaching assistant says, "working on 40 problems raises a student's exam score by about the same amount as reading the textbook for 1 hour". For simplicity, assume students always cover the same number of pages during each hour they spend reading.
Given this information, in order to use his 4 hours of study time to get the best exam score possible, how many hours should he have spent working on problems, and how many should he have spent reading?
The marginal or additional gain in the above question is calculated by obtaining the difference in problems solved between two selected time frames . For example, the marginal or additional gain from Ben's 11 AM to Noon work is :
Additional gain from 11 AM to Noon = 150 - 135 = 15 problems
Ben should therefore make his decision at the margin. Each hour, he should select the option that will improve his exam grade by the largest amount. If he can do more than 40 problems in an hour, working on problems will help raise his grade more for that hour than reading would.The marginal gain from the first hour is 60 problems. The marginal gain from the second hour is 45 problems. He will stop there, because he will get only 30 problems done if he spends the third hour working on problems. Therefore, he should stop working on problems and spend his remaining 2 hours reading instead.
Observe the line segments in the word below:MATHList the number of line segments that have a positive slope, negative slope, zero slope and undefined slope.
Answer:
Segments with positive slope, negative slope, zero slope and undefined slope are indicated in the attach.
Step-by-step explanation:
When you represent or consider a segment in a coordinate axis system, the slope of the segment is the variation in "x" axis in relation to variation in "y" axis, it means the quotient Δx/Δy. If we select two different pairs of points (x1, y1) (x2, y2) ⇒slope = Δx/Δy ⇒ slope = (x2 - x1)/(y2 - y1).
There four main options:
- If Δx/Δy > 0 ⇒ Positive slope (In this case: Δx >0 and Δy> 0 or Δx˂ 0 and Δy ˂ 0).
- If Δx/Δy ˂ 0 ⇒Negative slope (this happens when Δx > 0 and Δy˂0 or
Δx˂0 and Δy>0)
- If Δx/Δy = 0 ⇒ zero slope (This happens when Δx =0).
-If Δx/Δy =∅ ⇒ undefined slope (only when Δy = 0).
Given this explanation and considering the word MATH in a coordinated system, we clasiffied the segments as you can see in the attach. Segments denoted by: 1 have positive slopes, 2 negative slopes, 3 zero slope and 4 unddefined slope.
please help! I don't understand.
Answer:
1. Given
2. Alternate interior angle theorem
3. Alternate interior angle theorem
4. Reflexive property of congruence
5. ASA
Step-by-step explanation:
1. JK || LM, JL || KM
This is the information given in the problem statement.
2. ∠JKL ≅ ∠MLK
∠JKL and ∠MLK are alternate interior angles. Since JK and LM are parallel, the alternate interior angles are congruent.
3. ∠JLK ≅ ∠MKK
∠JLK and ∠MKL are alternate interior angles. Since JL and KM are parallel, the alternate interior angles are congruent.
4. KL ≅ LK
According to reflexive property, a segment is always congruent to itself.
5. ΔJKL ≅ ΔMLK
We have two triangles with two pairs of congruent angles, and a pair of congruent sides between those angles. Therefore, the triangles are congruent by ASA.
To qualify for the championship a runner must complete the race in less than 55 minutes ....... Use "t" to represent the time in minutes of a runner who qualifies for the championship
The inequality required is t < 55.
Given:
To qualify for the championship, a runner must complete the race in less than 55 minutes.
In this question, we are dealing with the time taken by runners to complete a race. Let's use 't' to represent the time in minutes of a runner who qualifies for the championship. The condition for qualification is that the runner must complete the race in less than 55 minutes.
So, the inequality that represents this situation is: t < 55.
Any runner who completes the race in less than 55 minutes will qualify for the championship.
The points obtained by students of a class in a test are normally distributed with a mean of 60 points and a standard deviation of 5 points.
About what percent of students have scored more than 75 points?
0.15
2.5
15.5
34
Answer:
Option A) is correct.
Step-by-step explanation:
We need to use normalcdf command to find the probability that the variable would fall into a certain interval that we would supply.
As
The points obtained by students of a class in a test are normally distributed with a mean of 60 pointsand
a standard deviation of 5 pointsAnd we have to determine the percent of students have scored more than 75 points.
So,
Mean = μ = 60
Standard Deviation = σ = 5
As we have to determine the percent of students have scored more than 75 points.
Hence,
normalcdf(75,100,60,5) = .0013
Converting on percentage → .0013 × 100 = 0.1
Therefore, option A) is correct as 0.1 percent of students have scored more than 75 points.
Keywords: distribution, mean, median
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What is the mathematical meaning of each symbol below? Give an example of each using numbers and/or algebraic expressions. ∼ ∪ ∩ ∅ ≠ !
Answer:
∼ : This symbol denotes similarity
∪ : This symbol means union
∩ : This symbol means Intersection
∅ : means an empty set
≠ : this symbol mean not equal to
! : This symbol means factorial
Step-by-step explanation:
Given symbols in the question:
∼ : This symbol denotes similarity
i.e the resemblance or likeness.
∪ : This symbol means union
i.e
A∪B element that belong to set A or set B
∩ : This symbol means Intersection
i.e
A∩B = Element that belong to set A and set B
∅ : means an empty set
For example
if A = { 1, 2, 3 } B = { 4, 5, 6 }
Then,
A∩B = ∅
≠ : this symbol mean not equal to
i.e
LHS is not equal to RHS
! : This symbol means factorial
i.e
If we write 3!
we solve it as 3! = 3 × 2 × 1
The math club makes 35 bars of laundry soap a week and sells these at $20 each before the soap could be sold , the pupils found that 6 bars were destroyed by mice. How much will the total sale at the end of a four week month?
Answer:
Step-by-step explanation:
The math club makes 35 bars of laundry soap a week and sells these at $20 each. This means that the total number of bars of laundry soap made in a 4 week month would be
4 × 35 = 140 bars
If the pupils found that 6 bars were destroyed by mice, the total number of bars of soap left would be
140 - 6 = 134 bars
Therefore, the total sale at the end of a four week month would be
134 × 20 = $2680
The total sales at the end of a 4-week month, given that 6 out of 35 soap bars were destroyed by mice every week and the price of each soap bar is $20, would be $2320.
Explanation:The math club initially makes 35 bars of soap every week. However, due to the unforeseen mouse problem, 6 bars are rendered unsalable each week. Therefore, the club is effectively selling only 29 bars per week. Because the selling price of each bar is $20, each week's sales amount to 29 bars x $20/bar = $580.
Over 4 weeks, the total sales would then be $580/week x 4 weeks = $2320. So, the total amount of sales at the end of a 4-week month, after accounting for the mice damage, would be $2320.
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Find the exact value of cot theta if csc theta = -4/3 and the terminal side of theta lies in Quadrant III.
Answer:
The exact value of cotФ is [tex]\frac{\sqrt{7}}{3}[/tex]
Step-by-step explanation:
Given as:
The value of cosec Ф = [tex]\frac{-4}{3}[/tex]
Let the value of cotФ = x
Now, According to question
∵ sinФ = [tex]\frac{1}{cosec\Theta }[/tex] .....1
Put the value of cosec Ф = [tex]\frac{-4}{3}[/tex] in eq 1
i.e sinФ = [tex]\frac{1}{\frac{-4}{3} }[/tex]
Or, sinФ = [tex]\frac{-3}{4}[/tex]
Again
∵ cosФ = [tex]\sqrt{1-sin^{2}\Theta }[/tex]
So, cosФ = [tex]\sqrt{1-(\frac{-3}{4})^{2}}[/tex]
Or, cosФ = [tex]\sqrt{1-(\frac{9}{16})}[/tex]
Or, cosФ = [tex]\sqrt{\frac{16 - 9}{16})}[/tex]
∴ cosФ = [tex]\frac{\sqrt{7}}{4}[/tex]
Again
we know that cotФ = [tex]\frac{cos\Theta }{sin\Theta }[/tex]
So, cotФ = [tex]\frac{\frac{\sqrt{7}}{4}}{\frac{-3}{4}}[/tex]
Or, cotФ = [tex]\frac{-\sqrt{7}}{3}[/tex]
As according to question sinФ lies in third quadrant
So, cotФ = [tex]\frac{\sqrt{7}}{3}[/tex]
Hence, The exact value of cotФ is [tex]\frac{\sqrt{7}}{3}[/tex] . Answer
Paul has $30000 to invest. His intent is to earn 10% interest on his investment. He can invest part of his money at 6% interest and part at 13% interest. How much does Paul need to invest in each option to make get a total 10% return on his $30000?
Investing for 6% return: $
.
Investing for 13% return: $
Thanks a ton! :)
Answer:
The amount invested at 6% is $12,857.14
The amount invested at 13% is $17,142.86
Step-by-step explanation:
Let
x ----> the amount invested at 6%
30,000-x -----> the amount invested at 13%
we know that
The interest earned by the amount invested at 6% plus the interest earned by the amount at 13% must be equal to the interest earned by the total amount of $30,000 at 10%
Remember that
[tex]6\%=6\100=0.06[/tex]
[tex]13\%=13\100=0.13[/tex]
[tex]10\%=10\100=0.10[/tex]
so
The linear equation that represent this situation is
[tex]0.06x+(30,000-x)0.13=0.10(30,000)[/tex]
solve for x
[tex]0.06x+3,900-0.13x=3,000\\0.13x-0.06x=3,900-3,000\\0.07x=900\\x=\$12,857.14$[/tex]
[tex]x-\$30,000=\$17,142.86[/tex]
therefore
The amount invested at 6% is $12,857.14
The amount invested at 13% is $17,142.86
A firecracker in a coconut blows the coconut into three pieces. Two pieces of equal mass fly off south and west, perpendicular to each other, at 23 m/s . The third piece has twice the mass as the other two.
Answer:
Step-by-step explanation:
How many ways can 2 Geometry books, 8 Algebra books and 2 Pre-Calculus books be arranged on a shelf if all the books of each respective subject are identical?
Answer: 2,970
Step-by-step explanation:
The number of ways to arrange n things such that a things are identical , b things are identical , and so on is [tex]\dfrac{n!}{a!\cdot b!\cdot ....}[/tex] .
As per given , we have
Number of Geometry books = 2
Number of Algebra books = 8
Number of Pre-Calculus books =2
Total books = 2+8+2=12
Then, the number of ways to arrange them : [tex]\dfrac{12!}{2!\cdot 8!\cdot 2!}[/tex]
[tex]=\dfrac{12\times11\times10\times9\times8!}{2\times8!\times2}=2970[/tex]
Hence, the total number of ways to arrange 2 Geometry books, 8 Algebra books and 2 Pre-Calculus books is 2,970.
To find the number of arrangements of different books on a shelf, we use the concept of permutations of multiset in combinatorics. For 12 books (2 Geometry, 8 Algebra, 2 Pre-Calculus), the number of arrangements is the factorial of the total (12!) divided by the product of factorials for each group of identical items (2!, 8!, 2!).
Explanation:The question is asking how many ways you can arrange identical books of different subjects on a shelf. Here, we need to use the concept of permutations of multiset, often used in combinatorics. For 12 books in which 2 are Geometry, 8 are Algebra and 2 are pre-Calculus, the number of permutations is given by 12! / (2! * 8! * 2!). This formula is derived from the general principle of permutations of multisets where you divide the factorial of the total number of items by the product of factorials for each group of identical items.
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Use the four-step procedure to solve the following problem. Brine is a solution of salt and water. If a tub contains 50 pounds of 5% solution of brine, how much water (to the nearest tenth lb.) must evaporate to change it to an 8% solution?
Answer:
18.3 pounds of water must evaporate to make it 8% solution
Step-by-step explanation:
Brine is a solution containing water & salt
Weight of brine solution = 50 pounds
amount of salts = 5% of 50 pounds = (5 ÷ 100) × 50 = 2.5 pounds.
Amount of water = 50 - 2.5 = 47.5 pounds
The new solution is to be made 8%, which indicates that 2.5 pounds of salt is going to be equivalent to 8% of the new salt and some amount of water has to be evaporated for the amount of salt to increase
Using direct relation expression
8% of the solution equivalent to 2.5 pounds of salt
100% will be equivalent to X pounds of solution
Upon cross multiplication,
X = (100 × 2.5) ÷ (8) = 31.25 pounds of solution
There amount of water that must evaporate is difference between weight of initial solution & final solution
Amount of water to be evaporated = 50 - 31.25 = 18.25 pounds ∞ 18.3 lbs
Solve the equation, if possible. (If all real numbers are solutions, enter REALS. If there is no solution, enter NO SOLUTION.) x2 = (x + 3)(x − 3) + 9
Answer:
REALS. all real numbers are solution for the equation
Step-by-step explanation:
for the equation
x² = (x + 3)*(x − 3) + 9
distributing the terms in the parenthesis
x² = (x + 3)*(x − 3) + 9 = [x² - 3*x + 3*x - 3*3 ] + 9
x² = x² - 9 + 9
0 = 0
since this statement will be true regardless of the value of x , then the equation has solution for all real numbers .
What is the solution of the equation (x – 5)2 + 3(x – 5) + 9 = 0? Use u substitution and the quadratic formula to solve.
x = StartFraction negative 3 plus-or-minus 3 i StartRoot 3 EndRoot Over 2 EndFraction
x = StartFraction 7 plus-or-minus 3 i StartRoot 3 EndRoot Over 2 EndFraction
x = 2
x = 8
Answer:
Option 2 - [tex]x=\frac{7\pm3\sqrt{3}i}{2}[/tex]
Step-by-step explanation:
Given : Equation [tex](x-5)^2+3(x-5)+9=0[/tex]
To find : What is the solution of the equation ?
Solution :
Using substitution method,
Let y=x-5
[tex]y^2+3y+9=0[/tex]
Using quadratic formula, [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Here, a=1, b=3 and c=9
[tex]y=\frac{-3\pm\sqrt{3^2-4(1)(9)}}{2(1)}[/tex]
[tex]y=\frac{-3\pm\sqrt{-27}}{2}[/tex]
[tex]y=\frac{-3\pm3\sqrt{3}i}{2}[/tex]
Substitute back,
[tex]x=\frac{-3\pm3\sqrt{3}i}{2}+5[/tex]
[tex]x=\frac{-3\pm3\sqrt{3}i+10}{2}[/tex]
[tex]x=\frac{7\pm3\sqrt{3}i}{2}[/tex]
Therefore, option 2 is correct.
Answer:
Option 2
Step-by-step explanation:
I just took the test and got it right.
A wildlife biologist determines that there are approximately 200 deer in a region of a national park. The population grows at a rate of 7% per year. What is an exponential function that models the expected population?
Answer:
The exponential function is Y = 200 [1.07]ˣ
Step-by-step explanation:
Let Y represent the expected population
Let P represent the current population
Let r represent the population growth rate
let x represent the number of years or nth year.
The compound interest expression can used to derive the exponential function can be represented as follows
Y = P [1 + (r ÷ 100)]ˣ
Y = 200 [ 1 + (7 ÷ 100)]ˣ
Y = 200 [ 1 + (0.07)]ˣ
Y = 200 [1.07]ˣ
Final answer:
To model the population growth of deer in a national park, an exponential function P(t) = 200 * (1 + 0.07)^t is used. This reflects a starting number of 200 deer, with growth at a rate of 7% per year, allowing for future population predictions.
Explanation:
A wildlife biologist determines that there are approximately 200 deer in a region of a national park. The population grows at a rate of 7% per year. To model the expected population using an exponential function, we use the general formula for exponential growth P(t) = P0 * (1 + r)^t, where:
P(t) represents the population at time t years,P0 is the initial population size,r is the annual growth rate as a decimal,t is the number of years.Given that the initial population (P0) is 200 deer and the annual growth rate (r) is 7% or 0.07, the exponential growth model to predict future population sizes can be written as P(t) = 200 * (1 + 0.07)^t.
This function can be used to calculate the expected number of deer in this region of the national park for any number of years into the future, allowing biologists and park management to make informed decisions regarding wildlife conservation and management.
The member of the student council are selling raffle tickets. The school decides that the top three raffle ticket sellers will share portion of the profits. The second place winner will receive 8 more dollars then the third place. The first place seller will receive twice as much as the second place seller. The profit portion they will share is $ 104. How much will each of the top three sellers receive?
Answer:the first place seller receives $56
The second place seller receives $28
The third place seller receives $20
Step-by-step explanation:
Let x represent the amount that the first place seller would receive.
Let y represent the amount that the second place seller would receive.
Let z represent the amount that the third place seller would receive.
The second place winner will receive 8 more dollars than the third place winner. This means that
z = y - 8
The first place seller will receive twice as much as the second place seller. It means that
x = 2y
The profit portion they will share is $ 104. It means that
x + y + z = 104 - - - - - - - - - - - 1
Substituting z = y - 8 and x = 2y into equation 1, it becomes
2y + y + y - 8 = 104
4y = 104 +8 = 112
y = 112/4 = 28
x = 2x = 2 × 28
x = 56
z = y - 8 = 28 - 8
z = 20
The inventor of a new game believes that the variable cost for producing the game is $0.90 per unit and the fixed costs are $6200. The inventor sells each game for $1.69. Let x be the number of games sold. The total cost for a business is the sum of the variable cost and the fixed costs. Write the total cost C as a function of the number of games sold.
The total cost function based on the number of games sold can be written as C(x) = $6200 + $0.90x. This equation depicts that for every game produced and sold, the total cost increases by $0.90 from a base cost of $6200.
Explanation:In this particular scenario, fixed costs are constant and turnover does not affect them, hence, a fixed cost of $6200. Variable costs, on the other hand, depend on the quantity produced, which in this case, is $0.90 per unit.
Therefore, as the production output - denoted as 'x' - increases, variable costs also increase, forming a direct relationship. According to the given information, the cost function, denoted as 'C', which represents the total cost, will be the sum of both fixed and variable costs.
So, the total cost function based on the number of games sold, can be written algebraically as: C(x) = $6200 + $0.90x.
This equation implies that for each game produced and sold, the total cost increases by $0.90, with a starting cost of $6200, the fixed costs.
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