In clinIcal study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability that a person carries the gene is 0.1.
a) what is the probability four or more people will have to be tested before two with the gene are detected?b) How many people are expected to be tested before two with gene are detected?

Answer:

4 minutes

Step-by-step explanation:

There are two hours from 11:30 a.m. to 1:30 p.m

The hourly rate of service is:

[tex]r=\frac{300}{2}=150\ customers/hour[/tex]

If the average number of customers in the system (n) is 10, the time that a customer spends in process is given by:

[tex]t=\frac{n}{r} =\frac{10}{150}=0.06667\ hours[/tex]

Converting it to minutes:

[tex]t= 0.066667\ hours*\frac{60\ minutes}{1\ hour}\\t=4\ minutes[/tex]

A customer spends, on average, 4 minutes in process.

The question is missing the options. The options are:

(A) (-8, 8) and (2, 2)

(B) (-5, -1) and (0, 2)

(C) (-3, 6) and (6.-9)

(D) (-2, 1) and (3,-2)

(E) (0, 2) and (5,5)

Answer:

Options (A) and (D)

Step-by-step explanation:

Given:

A line with slope (m) = [tex]-\frac{3}{5}[/tex]

Now, a parallel line to the given line will have the same slope.

So, let us check each of the given options.

Option (A)

(-8, 8) and (2, 2)

The slope of line passing through two points [tex](x_1,y_1)\ and\ (x_2,y_2)[/tex] is given as:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

Now, the slope of a line passing through (-8, 8) and (2, 2) is given as:

[tex]m_1=\frac{2-8}{2-(-8)}=\frac{-6}{10}=-\frac{3}{5}[/tex]

So, [tex]m=m_1[/tex]

Therefore, option (A) is correct.

Option (B): (-5, -1) and (0, 2)

The slope of a line passing through (-5, -1) and (0, 2) is given as:

[tex]m_2=\frac{2-(-1)}{0-(-5)}=\frac{3}{5}[/tex]

So, [tex]m\ne m_2[/tex]

Therefore, option (B) is not correct.

Option (C): (-3, 6) and (6, -9)

The slope of a line passing through (-3, 6) and (6, -9) is given as:

[tex]m_3=\frac{-9-6}{6-(-3)}=\frac{-15}{9}=-\frac{5}{3}\ne m[/tex]

Therefore, option (C) is not correct.

Option (D): (-2, 1) and (3, -2)

The slope of a line passing through (-2, 1) and (3, -2) is given as:

[tex]m_4=\frac{-2-1}{3-(-2)}=-\frac{3}{5}=m[/tex]

Therefore, option (D) is correct.

Option (E): (0, 2) and (5, 5)

The slope of a line passing through (0, 2) and (5, 5) is given as:

[tex]m_5=\frac{5-2}{5-0}=\frac{3}{5}\ne m[/tex]

Therefore, option (E) is not correct.

Hence, only options (A) and (D) are correct.

Answer:

Ordinal level

Step-by-step explanation:

The variable of interest is opinion on homosexual relations and the frequency distribution for opinion on homosexual relations is given.

The opinion of people is categorized from wrong to not wrong at all. There exists order in the categorizes and measurement of variable indicates the ordinal level of measurement.

Thus, variable is measured at ordinal level.

Answer:

0.62% probability that the sample mean weight of these 100 bags is less than 10.45 ounces.

Step-by-step explanation:

To solve this question, the concepts of the normal probability distribution and the central limit theorem are important.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], a large sample size can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\frac{\sigma}{\sqrt{n}}[/tex]

In this problem, we have that:

[tex]\mu = 10.5, \sigma = 0.2, n = 100, s = \frac{0.2}{\sqrt{100}} = 0.02[/tex]

Find the probability that the sample mean weight of these 100 bags is less than 10.45 ounces

This is the pvalue of Z when X = 10.45. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{10.45 - 10.5}{0.02}[/tex]

[tex]Z = -2.5[/tex]

[tex]Z = -2.5[/tex] has a pvalue of 0.0062.

So there is a 0.62% probability that the sample mean weight of these 100 bags is less than 10.45 ounces.

The probability of the sample mean weight being less than 10.45 ounces can be found by calculating the Z-score and referencing a standard normal distribution table. The calculated Z-score (-2.5) corresponds to a probability of approximately 0.62%.

The problem is about determining the probability that the sample mean weight of corn chip bags is less than 10.45 ounces. This is a problem of finding a probability in a sampling distribution when the population parameters are known. Given the data, we can use the Central Limit Theorem, which states that if the sample size is large enough (usually >30), the sampling distribution approximates a normal distribution.

To solve this, you can use the formula Z = (X - μ) / (σ/√n), where X is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size.

Plugging in the given values: Z = (10.45 - 10.5) / (0.2 / √100) = -2.5. The Z-score tells us how many standard deviations away our data point is from the mean. To find the probability that the Z is less than -2.5, you can refer to a standard normal distribution table or use statistical software. According to the Z table, the probability is approximately 0.0062 or 0.62% that the sample mean weight of these 100 bags is less than 10.45 ounces.

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Using the Malthusian law for population growth and the given data, the estimated population of splake in a lake in 2020 is approximately 21,485.

The question involves estimating the population of splake in a lake in 2020 using the Malthusian law for population growth. The Malthusian law indicates that populations grow exponentially under ideal conditions. Given that the population increased from 1000 to 3000 splake between 1990 and 1997, we can calculate the rate of growth and then apply this rate to predict the population in 2020.

To begin, we identify the years of growth as 1997 - 1990 = 7 years. The formula for exponential growth is P = P0ert, where P is the final population, P0 is the initial population, r is the rate of growth, and t is the time in years. With P = 3000, P0 = 1000, and t = 7, we can solve for r.

3000 = 1000e7r, which simplifies to 3 = e7r. Taking the natural logarithm of both sides gives us ln(3) = 7r, and solving for r gives r ~ 0.1487. Now, to find the population in 2020, which is 30 years from 1990, we use the formula with P0 = 1000, r = 0.1487, and t = 30: P = 1000e0.1487*30.

Upon calculation, the predicted population of splake in the year 2020 is approximately 21,485.

Answer:

20 inches and 5 inches

Step-by-step explanation:

Let the diameter of the largest and the smallest pizza be Y and X respectively.

Then,

Y+X = 25 ........................... Equation 1

Y-X = 15 ............................ Equation 2

Solve equation 1 and equation 2 simultaneously.

Add equation 1 and equation 2

Y+Y = +X+(-X)+25+15

2Y = 40

Y = 40/2

Y = 20 inches.

Also,

Substitute the value of Y into equation 1

20+X=25

X = 25-20

X = 5 inches.

Hence the diameter of the largest and the smallest pizzas = 20 inches and 5 inches

Final answer:

The smallest pizza has a diameter of 5 inches, and the largest pizza has a diameter of 20 inches.

Explanation:

The diameters of the largest and smallest pizzas are 20 inches and 5 inches, respectively.

To find the diameters of the pizzas:

Let x be the diameter of the smallest pizza and y be the diameter of the largest pizza.

We have the system of equations x + y = 25 and y - x = 15.

Solving these equations simultaneously, we get y = 20 and x = 5.

Answer:

Null hypothesis: The American Society for Certified Public Accountants says the average starting salary of accountants who graduated in 2018 is $57,413

Alternate hypothesis: The American Society for Certified Public Accountants says the average starting salary of accountants who graduated in 2018 is less than or equal to $57,413

Step-by-step explanation:

A null hypothesis is a statement from a population parameter that is subject to testing. It is expressed with equality.

An alternate hypothesis is also a statement from the population parameter that negates the null hypothesis. It is expressed with inequality

Answer:

P-value or Probability value is the exact percentage where test statistics lie.The criterion for rejecting the null hypothesis using the​ P-value approach is that if P-value < Level of significance , then we reject our null hypothesis

Step-by-step explanation:

P-value or Probability value is the exact percentage where test statistics lie.

It also tells the probability of obtaining extreme results corresponding to our level of significance keeping in state that our null hypothesis is true or correct.

The criterion for rejecting the null hypothesis using the​ P-value approach is that if P-value < Level of significance , then we reject our null hypothesis i.e.  

Suppose P-value is 2.33% and Level of significance is 5%, then we will reject our null hypothesis as 2.33% < 5%.

On the other hand, if P-value > Level of significance , then we cannot reject or accept our null hypothesis.

A p-value is a measure of the strength of evidence against the null hypothesis in a statistical hypothesis test. The criterion for rejecting the null hypothesis using the p-value approach is to compare the calculated p-value to a predetermined significance level.

A p-value is a measure of the strength of evidence against the null hypothesis in a statistical hypothesis test. It represents the probability of observing a test statistic as extreme or more extreme than the one observed, assuming that the null hypothesis is true. In other words, it quantifies how likely it is for the observed data to have occurred by chance if the null hypothesis is true.

The criterion for rejecting the null hypothesis using the p-value approach is to compare the calculated p-value to a predetermined significance level (usually denoted as alpha). If the p-value is smaller than alpha, we reject the null hypothesis, indicating that there is enough evidence to support the alternative hypothesis. Alternatively, if the p-value is greater than or equal to alpha, we fail to reject the null hypothesis, suggesting that there is not enough evidence to support the alternative hypothesis.

Answer:

a) Yes

b) (2,0.8)

c)[tex](2\sqrt2,1), (-2\sqrt2,1)[/tex]

d) [tex]x \in (-\infty,\infty)[/tex]

e) (0,0)

f) (0,0)  

Step-by-step explanation:

We are given the following function in the question:

[tex]f(x) = \displaystyle\frac{16x^2}{x^4 + 64}[/tex]

a) We have to check whether given point lies on the function or not.

[tex](-2\sqrt2,1)\\\\f(-2\sqrt2) = \displaystyle\frac{16(-2\sqrt2)^2}{(-2\sqrt2)^4 + 64} = \frac{128}{128} = 1[/tex]

b) Find value of f(x) at x = 2

[tex]f(2) = \displaystyle\frac{16(2)^2}{(2)^4 + 64} =\frac{64}{80}= 0.8[/tex]

Thus, (2,0.8) lies on the graph of given function.

c) We have to find the value of x, when f(x) = 1

[tex]1 = \displaystyle\frac{16x^2}{x^4 + 64}\\\\x^4 -16x^2 + 64 = 0\\(x^2-8)^2 = 0\\x^2 - 8 = 0\\x = \pm 2\sqrt2[/tex]

[tex](2\sqrt2,1), (-2\sqrt2,1)[/tex] lies on he graph of function.

d) Domain is the collection of all values of x for which the function is defined.

[tex]x \in (-\infty,\infty)[/tex]

e)  x-intercepts

This is the value of x such that the function is zero.

[tex]0 = \displaystyle\frac{16x^2}{x^4 + 64}\\\\16x^2 = 0\\x = 0[/tex]

f) y-intercept

It is the value of function when x is zero.

[tex]f(0) = \displaystyle\frac{16(0)^2}{(0)^4 + 64} = 0[/tex]

The function passes trough origin.

The solution involves determining if a specific coordinates exist on the graph, calculating the function value for specific x-values, determining x-values for a specific function value, finding the domain of the function, and identifying the x and y intercepts of the function.

The function is f(x) = 16x²/(x⁴ + 64).

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Answer:

a) 62

b) 24

Step-by-step explanation:

For A, add the students who watched only one movie: 18+24+20=62

For B, look at how many students only watched Star Wars: 24

The integrals for the volume of the solids

a.) V = ∫[0 to 1] π(3 - 3√x)² dx

b.) V = ∫[0 to 27] π(5 - [tex]x^{2/3}[/tex]))² dx

We have,

To set up the integral using the method of disks/washers to find the volume V of the solid obtained by rotating the region bounded by the curves y = 3√x, y = 3, and x = 0 about the specified lines, follow these steps:

Given curves: y = 3√x, y = 3, x = 0

a.)

Rotating about the line y = 3:

- Draw the region bounded by the curves y = 3√x, y = 3, and x = 0.

- The solid will be formed by revolving this region around the line y = 3.

- For the method of disks/washers, consider a vertical slice (dx) of thickness dx at a distance x from the y-axis.

- The radius of the disk is the distance between the curve y = 3√x and the line y = 3, which is (3 - 3√x).

- The area of the disk is π(radius)^2 = π(3 - 3√x)².

- The volume of the infinitesimally thin disk is dV = π(3 - 3√x)² dx.

- Integrate the volume from x = 0 to x = (3/3)² = 1:

V = ∫[0 to 1] π(3 - 3√x)² dx

b)

Rotating about the line x = 5:

- Draw the region bounded by the curves y = 3√x, y = 3, and x = 0.

- The solid will be formed by revolving this region around the line x = 5.

- For the method of disks/washers, consider a vertical slice (dx) of thickness dx at a distance x from the y-axis.

- The radius of the disk is the distance between the line x = 5 and the curve y = 3√x, which is (5 - [tex]x^{2/3}[/tex]).

- The area of the disk is π(radius)^2 = π(5 - [tex]x^{2/3}[/tex])².

- The volume of the infinitesimally thin disk is dV = π(5 - [tex]x^{2/3}[/tex])² dx.

Integrate the volume from x = 0 to x = 3³ = 27:

V = ∫[0 to 27] π(5 - [tex]x^{2/3}[/tex])² dx

These integrals will give you the volumes of the solid obtained by rotating the region about the specified lines. You can evaluate these integrals to find the exact values of the volumes.

Thus,

The integrals for the volume of the solids

a.) V = ∫[0 to 1] π(3 - 3√x)² dx

b.) V = ∫[0 to 27] π(5 - [tex]x^{2/3}[/tex]))² dx

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Answer:

Assuming population data

[tex] \sigma = \sqrt{0.000354}=0.0188[/tex]

Assuming sample data

[tex] s = \sqrt{0.000425}=0.0206[/tex]

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

[tex]\mu = \frac{\sum_{i=1}^6 X_i}{6}[/tex]

The value for the mean would be:

[tex]\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359[/tex]

And the population variance would be given by:

[tex] \sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}[/tex]

And we got [tex] \sigma^2 =0.000354[/tex]

And the deviation would be just the square root of the variance:

[tex] \sigma = \sqrt{0.000354}=0.0188[/tex]

Assuming sample data

[tex]\bar X = \frac{\sum_{i=1}^6 X_i}{6}[/tex]

The value for the mean would be:

[tex]\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359[/tex]

And the population variance would be given by:

[tex] s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}[/tex]

And we got [tex] s^2 =0.000425[/tex]

And the deviation would be just the square root of the variance:

[tex] s = \sqrt{0.000425}=0.0206[/tex]

To determine the standard deviation of given length measurements, calculate the mean, find squared differences, average them, and take the square root. The standard deviation of the measurements is 0.01879 feet.

Determining the Standard Deviation of Measurements

To find the standard deviation of the given length measurements, follow these steps:

Calculate the mean of the measurements.

Find the squared differences between each measurement and the mean.

Compute the average of the squared differences.

Take the square root of that average.

Step-by-Step Calculation

→ List of measurements: 736.352, 736.363, 736.375, 736.324, 736.358, 736.383.

→ Calculate the mean:

= (736.352 + 736.363 + 736.375 + 736.324 + 736.358 + 736.383) / 6

= 736.3591667

Find the squared differences:

→ Calculate the average of the squared differences:

= (0.00005256 + 0.00001464 + 0.00024811 + 0.00123264 + 0.00000136 + 0.00057044) / 6

= 0.000353292

Take the square root to find the standard deviation:

= √(0.000353292)

= 0.01879 feet

Answer:

A. Stratification

Step-by-step explanation:

Stratified random sampling is used when the researcher wants to highlight a specific subgroup within an entire population.

Stratification technique is mainly used to reduce the population differences and to increase the efficiency of the estimates. In this method the population is divided into a number of subgroups or strata.

Each strata should be so formed such that they are homogeneous as far as possible.

Final answer:

When examining the hypothesis about drug side effects in different populations, Randomization is the most appropriate statistical technique. It helps in reducing bias and ensures equal chances of group assignment, providing more reliable results in comparing the effects across populations.(Option D)

Explanation:

A researcher examining the hypothesis that a specific drug may exhibit a higher prevalence of side effects among the African American population compared to the Caucasian population could employ several statistical techniques to design the study. However, the most appropriate option provided is Randomization. Randomization helps in mitigating bias and ensures that each participant has an equal chance of being assigned to either the experimental or control group. This process decreases the likelihood of systematic differences between groups and allows any effects observed to be more confidently attributed to the drug under study rather than external factors.

Other options like Stratification, Crossover matching, and Matching could also play roles in different aspects of study design, but when testing a hypothesis about a drug's effects across different populations, randomization is crucial. It aligns with principles of experimental design that seek to control, to the extent possible, for variables that could influence the outcome, ensuring that the treatment group and control group are comparable at the beginning of the study.

Answer:

An adult male blue whale is 18.7 times heavier  than an adult male African elephant.

Step-by-step explanation:

As the weight of an adult male African elephant weighs about

And the weight of an adult blue whale is

Determining the ratio of adult male African elephant to the weight of an adult blue whale as:

                         [tex]\:\:\frac{1.7\:\times\:10^5}{9.07\:\times\:10^3}[/tex]

[tex]\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}[/tex]

                       [tex]=\frac{10^{5-3}\times \:1.7}{9.07}[/tex]

                       [tex]=\frac{10^2\times \:1.7}{9.07}[/tex]

  As  [tex]10^2\times \:1.7=170[/tex], So

                        [tex]=\frac{170}{9.07}[/tex]

                        [tex]=18.74310\dots[/tex]

Round the answer to the nearest tenth

                         [tex]=18.7[/tex]

Therefore, an adult male blue whale is 18.7 times heavier  than an adult male African elephant.

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Answer:

(a) 7.69%

(b) 25%

(c) 2.78%

Step-by-step explanation:

(a)

In a deck of 52 cards there are 4 aces.

The odds in favor or the probability of selecting an ace is:

[tex]P(Ace) = \frac{Number\ of\ aces}{Number\ of\ cards\ in\ total}\\ =\frac{4}{52}\\ =0.076923\\\approx7.69\%[/tex]

Thus, the probability of selecting an ace from a random deck of 562 cards is 7.69%.

(b)

The outcomes of each toss of a coin is independent of the other, since the result of the previous toss does not affect the result of the current toss.

The probability that both the tosses will end up in heads is:

[tex]P(2\ Heads)=P(1^{st}\ Head)\times P(2^{nd}\ Head)\\=\frac{1}{2}\times \frac{1}{2}\\ =\frac{1}{4}\\ =0.25\ or\ 25\%\\[/tex]

Thus, the probability that both the tosses will end up in heads is 25%.

(c)

The sample space of two dice consists of 36 outcomes in total.

Out of these 36 outcomes there is only 1 Boxcar, i.e. two sixes.

The probability of a boxcar when two dice are rolled is:

[tex]P(Boxcar)=\frac{Favorable\ outcomes}{Total\ no.\ of\ outcomes}\\= \frac{1}{36}\\ =0.027777\\\approx2.78\%[/tex]

Thus, the probability of a boxcar when two dice are rolled is 2.78%.

Final answer:

To find the odds in favor of specific events in probability theory, one must compare the number of successful outcomes to the number of unsuccessful ones. For selecting an ace from a deck of cards, the odds are 1:12; for getting two heads from two coin tosses, the odds are 1:3; and for rolling two sixes with two dice, the odds are 1:35.

Explanation:

The question asks for the odds in favor of several different probabilistic events, which relate to the field of probability theory within mathematics. Here's how to calculate the odds for each of the requested scenarios:

(a) Odds in favor of a card being an ace: There are 4 aces in a standard 52-card deck. The odds in favor are the number of ways the event can occur (4 aces) to the number of ways the event can fail to occur (52 - 4 = 48 non-aces), which simplifies to 1:12.

(b) Odds in favor of two heads when a coin is tossed twice: The probability of getting a head on one coin toss is 1/2, and since the two tosses are independent, the probability of getting two heads is (1/2) * (1/2) = 1/4. The odds in favor are calculated by taking the probability of the event occurring (1 chance) against the probability of it not occurring (3 chances), which gives us odds of 1:3.

(c) Odds in favor of rolling boxcars (two sixes) with two dice: Each die has a 1/6 chance of rolling a six, so the probability of rolling two sixes is (1/6) * (1/6) = 1/36. The odds in favor are the number of successful outcomes (1) against the number of all other outcomes (35), resulting in odds of 1:35.

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

[tex]{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1[/tex]

The number of ways of selecting 3 cards from 13 clubs is:

[tex]{13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286[/tex]

The number of ways of selecting 5 cards from 13 diamonds is:

[tex]{13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287[/tex]

The number of ways of selecting 0 cards from 13 spades is:

[tex]{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1[/tex]

Compute the number of ways to select 5 diamonds and 3 clubs as:

[tex]{13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082[/tex]

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

Answer:The same number of names and 4 predicates

Step-by-step explanation:

Answer:

The same number of names and 4 predicates

Step-by-step explanation:

Answer:

The probability that there will be more than one Phillips head screw = 0.1803 .

Step-by-step explanation:

We are given that there are 11 two-inch screws in a box of which 4 have a Phillips head and 7 have a regular head.

We are selecting 3 screws randomly from the box with replacement, so the probability that there will be more than one Phillips head screw is given by :

Now P(selecting 2 Phillips head screw with replacement) is given by :

 Selecting 2 Phillip head screw = [tex]\frac{4}{11}[/tex] *  [tex]\frac{4}{11}[/tex] = [tex]\frac{16}{121}[/tex]

      P(selecting three Phillips head screw) = [tex]\frac{4}{11}[/tex] *  [tex]\frac{4}{11}[/tex] *  [tex]\frac{4}{11}[/tex] = [tex]\frac{64}{1331}[/tex]

Therefore, Probability that there will be more than one Phillips head screw

                        =   [tex]\frac{16}{121}[/tex] + [tex]\frac{64}{1331}[/tex] = [tex]\frac{240}{1331}[/tex] = 0.1803 .

Answer:

D. 3.35

Step-by-step explanation:

First we need to form an equation and solve it to find the number of weeks when the prices were the same. Because the prices were the same we can say that b = c, and therefore form the equation:

2.35 + 0.25x = 1.75 + 0.4x - Now we nee to solve it and find x.

2.35 - 1.75 = 0.4x - 0.25x

0.6 = 0.15x

x = 0.6 ÷ 0.15

x = 4 weeks

So now we substitute x into the equation for beef and find the price.

b = 2.35 + (0.25 × 4)

b = 2.35 + 1

b = $3.35 per pound

The price per pound of beef when it was equal to the price of chicken is $3.35 per pound.

The prices of beef and chicken are represented by the following linear equations :

Price of beef, B :

B = 2.35 + 0.25x

Price of chicken, C :

C = 1.75 + 0.40x

Where x in both equations represents x weeks after July 1 of last summer :

Firstly :

We find the week in which the price of beef and chicken are the same :

Beef = Chicken

2.35 + 0.25x = 1.75 + 0.40x

We solve for x

2.35 - 1.75 = 0.40x - 0.25x

0.60 = 0.15x

x = 0.60 / 0.15

x = 4

Therefore, 4 weeks after July 1 of last summer, the price of beef and chicken were the same.

Therefore, the price per pound of beef in the 4th week is :

B = 2.35 + 0.25(4)

B = 2.35 + 1

B = 3.35

The price per pound of beef when it was equal to the price of chicken is $3.35 per pound.

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a) The probability that he or she has at least one food allergy and a history of severe reaction is 0.0287.

b) The probability that he or she is allergic to multiple foods is, 0.021

Given that;

A certain study found that 7% of children younger than 18 in the United States have at least one food allergy.

a. Since the probability that a child younger than 18 has at least one food allergy is given as 7%.

Among those with food allergies, the probability of having a history of severe reaction is 41%.

Hence for the probability that a child has both at least one food allergy and a history of severe reaction, multiply these probabilities together:

7% × 41% = 0.07 × 0.41

= 0.0287.

Therefore, the probability is 0.0287.

b) For the probability that a randomly selected child younger than 18 is allergic to multiple foods, consider the information given.

The probability of having at least one food allergy among children younger than 18 is 7%.

And among those with allergies, 30% are allergic to multiple foods.

Hence for the probability, multiply the probability of having at least one food allergy (7%) by the probability of being allergic to multiple foods (30% of those with allergies):

Probability = 7% × 30%

                  = 0.07 × 0.30

                  = 0.021.

Therefore, the probability that a randomly selected child younger than 18 is allergic to multiple foods is 0.021.

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The probability that a child younger than 18 has at least one food allergy and a history of severe reaction is approximately 0.029. The probability that a child younger than 18 is allergic to multiple foods is approximately 0.021.

To find the probability that a child younger than 18 has at least one food allergy and a history of severe reaction, we can use the information provided. We know that 7% of children younger than 18 have at least one food allergy and among those with food allergies, 41% had a history of severe reaction. To calculate the probability, we multiply these two probabilities together: 0.07 (the probability of having a food allergy) multiplied by 0.41 (the probability of having a severe reaction given a food allergy). So, the probability is 0.07 * 0.41 = 0.0287, which can be rounded to 0.0287 or approximately 0.029.

To find the probability that a child younger than 18 is allergic to multiple foods, we use the information that 30% of those with an allergy are allergic to multiple foods. So, the probability is 0.07 (the probability of having a food allergy) multiplied by 0.30 (the probability of being allergic to multiple foods given a food allergy). Hence, the probability is 0.07 * 0.30 = 0.021, which can be rounded to 0.021 or approximately 0.021.

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the quantity that minimizes Shaki's cost is [tex]\( \frac{200}{3} \)[/tex], or approximately [tex]\( 66.67 \)[/tex] danglies.

To find the quantity that minimizes Shaki's cost function [tex]\( c(q) = 75 + 2q + 0.015q^2 \)[/tex], we need to find the value of q where the derivative of [tex]\( c(q) \)[/tex] with respect to [tex]\( q \)[/tex] is zero.

Given the cost function:

[tex]\[ c(q) = 75 + 2q + 0.015q^2 \][/tex]

We'll find the derivative [tex]\( c'(q) \)[/tex] with respect to q and set it equal to zero to find the critical points.

[tex]\[ c'(q) = \frac{d}{dq} (75 + 2q + 0.015q^2) \][/tex]

[tex]\[ c'(q) = 2 + 0.03q \][/tex]

Now, we'll set [tex]\( c'(q) \)[/tex] equal to zero and solve for q:

[tex]\[ 2 + 0.03q = 0 \][/tex]

[tex]\[ 0.03q = -2 \][/tex]

[tex]\[ q = \frac{-2}{0.03} \][/tex]

[tex]\[ q = -\frac{200}{3} \][/tex]

Since the quantity q must be positive in this context, we disregard the negative solution. Therefore, the critical point occurs at [tex]\( q = \frac{200}{3} \)[/tex].

To determine whether this critical point corresponds to a minimum, we'll analyze the second derivative [tex]\( c''(q) \)[/tex]. If [tex]\( c''(q) > 0 \)[/tex] at [tex]\( q = \frac{200}{3} \)[/tex], then it's a local minimum.

[tex]\[ c''(q) = \frac{d^2}{dq^2} (2 + 0.03q) \][/tex]

[tex]\[ c''(q) = 0.03 \][/tex]

Since [tex]\( c''(q) \)[/tex] is positive, the critical point [tex]\( q = \frac{200}{3} \)[/tex] corresponds to a minimum.

Therefore, the quantity that minimizes Shaki's cost is [tex]\( \frac{200}{3} \)[/tex], or approximately [tex]\( 66.67 \)[/tex] danglies.

Answer:

The radius r of this circle as a function of the time t :

[tex]r(t)=35\times t[/tex]

Step-by-step explanation:

Speed of the circular ripple = S = 35 cm/s

Radius of the ripple at time t = r

[tex]Speed=\frac{Distance}{Time} [/tex]

[tex]35cm/s=\frac{r}{t}[/tex]

[tex]r=35 cm/s \times t[/tex]

The radius r of this circle as a function of the time t :

[tex]r(t)=35\times t[/tex]

The radius r of this circle is a function of the time t (in seconds) is 35t.

Given that

A stone is dropped into a lake, creating a circular ripple that travels outward at a speed of 35 cm/s.

The radius r of this circle is a function of the time t (in seconds).

Speed of the circular ripple = S = 35 cm/s

Radius of the ripple at time t = r

Then

The radius r of this circle is a function of the time t (in seconds) is determined by the following formula;

[tex]\rm Speed = \dfrac{Distance}{Time}[/tex]

Substitute all the values in the formula;

[tex]\rm Speed = \dfrac{Distance}{Time}\\ \\ 35 = \dfrac{r}{t}\\ \\ r = 35 \times t\\ \\ r = 35t[/tex]

Hence, The radius r of this circle is a function of the time t (in seconds) is 35t.

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Answer:

Equations of tangent lines are

y= 2 x

y = 0

Step-by-step explanation:

x = sin t -- (1)

y = sin(t + sin(t)) -- (2)

Differentiating both equations w.r.to t to find slopes.

[tex]\frac{dx}{dt}=\frac{d(sin(t))}{dt}\\\\\frac{dx}{dt}=cos(t)--(3)[/tex]

[tex]\frac{dy}{dt}=\frac{d}{dt}(sin(t+sin(t))\\\\\frac{dy}{dt}=cos(t+sin(t))\frac{d}{dt}(t+sin(t))\\\\\frac{dy}{dt}=cos(t+sin(t)(1+cos(t))\\\\\frac{dy}{dt}=(1+cos(t))cos(t+sin(t))--(4)[/tex]

Dividing (2) by (1) to find slope

[tex]\frac{dy}{dx}=\frac{(1+cos(t))cos(t+sin(t))}{cos(t)}\\[/tex]

at tangent point x=y=0

From (1)

sin (t) = 0

⇒ t = 0, π

At t = 0

[tex]\frac{dy}{dx}\Big|_{t=0}=\frac{(1+cos(t))cos(t+sin(t))}{cos(t)}\\\\\\\frac{dy}{dx}\Big|_{t=0}=\frac{(1+cos(0))cos(0+sin(0))}{cos(0)}\\\\\\\frac{dy}{dx}\Big|_{t=0}=\frac{(1+1)cos(0+0)}{1}\\\\\\\frac{dy}{dx}\Big|_{t=0}=2\\[/tex]

At t= π

[tex]\frac{dy}{dx}\Big|_{t=\pi}=\frac{(1+cos(t))cos(t+sin(t))}{cos(t)}\\\\\\\frac{dy}{dx}\Big|_{t=\pi}=\frac{(1+cos(\pi))cos(\pi+sin(\pi))}{cos(\pi)}\\\\\\\frac{dy}{dx}\Big|_{t=\pi}=\frac{(1-1)cos(\pi+0)}{-1}\\\\\\\frac{dy}{dx}\Big|_{t=\pi}=0\\[/tex]

Equation of tangent

[tex](y-y_o)=m_t(x-x_o)\\[/tex]

[tex]Tangent\,\,point=(x_o,y_o)=(0,0)\\\\For\,\,t=0\\\\(y-0)=(2)(x-0)\\\\y=2x\\\\for\,\,t=\pi\\\\(y-0)=(0)(x-0)\\\\y=0[/tex]

Answer:

(a) 0.06681

(b) 0.86638

(c)  [tex]\sigma[/tex] = 0.000214

Step-by-step explanation:

We are given that the diameter of the dot produced by a printer is normally distributed with a mean diameter of 0.002 inch and a standard deviation of 0.0004 inch i.e.;   [tex]\mu[/tex] = 0.002 inch        and        [tex]\sigma[/tex] = 0.0004

Also,   Z = [tex]\frac{X -\mu}{\sigma}[/tex] ~ N(0,1)

(a) Let X = diameter of a dot

    P(X > 0.0026 inch) = P( [tex]\frac{X -\mu}{\sigma}[/tex] > [tex]\frac{0.0026 -0.002}{0.0004}[/tex] ) = P(Z > 1.5) = 1 - P(Z <= 1.5)

                                                                          = 1 - 0.93319 = 0.06681

(b) P(0.0014 < X < 0.0026) = P(X < 0.0026) - P(X <= 0.0014)

    P(X < 0.0026) = P( [tex]\frac{X -\mu}{\sigma}[/tex] < [tex]\frac{0.0026 -0.002}{0.0004}[/tex] ) = P(Z < 1.5) = 0.93319

    P(X <= 0.0014) = P( [tex]\frac{X -\mu}{\sigma}[/tex] <= [tex]\frac{0.0014 -0.002}{0.0004}[/tex] ) = P(Z <= -1.5) = 1 - P(Z <= 1.5)

                                                                     = 1 - 0.93319 = 0.06681

Therefore, P(0.0014 < X < 0.0026) = 0.93319 - 0.06681 = 0.86638 .

(c) P(0.0014 < X < 0.0026) = 0.995

    P( [tex]\frac{0.0014 -0.002}{\sigma}[/tex] < [tex]\frac{X -\mu}{\sigma}[/tex] < [tex]\frac{0.0026 -0.002}{\sigma}[/tex] ) = 0.995

    P( [tex]\frac{ -0.0006}{\sigma}[/tex] < Z < [tex]\frac{0.0006}{\sigma}[/tex] ) = 0.995

    P(Z < [tex]\frac{0.0006}{\sigma}[/tex] ) - P(Z <= [tex]\frac{-0.0006}{\sigma}[/tex] ) = 0.995

    P(Z < [tex]\frac{0.0006}{\sigma}[/tex] ) - (1 - P(Z < [tex]\frac{0.0006}{\sigma}[/tex] ) ) = 0.995

     2 * P(Z < [tex]\frac{0.0006}{\sigma}[/tex] ) - 1 = 0.995

           P(Z < [tex]\frac{0.0006}{\sigma}[/tex] ) = 0.9975

On seeing the z table we observe that at critical value of x = 2.81 we get the probability area of 0.9975 i.e.;

                  [tex]\frac{0.0006}{\sigma}[/tex] = 2.81      ⇒  [tex]\sigma[/tex] = 0.000214

Therefore, 0.000214 standard deviation of diameters is needed so that the probability in part (b) is 0.995 .

The probabilities of obtaining a given diameter is found from the z-table,

given that the dot produced by the printer are normally distributed.

Reasons:

The mean diameter, μ = 0.002

The standard deviation, σ = 0.0004

A. The probability that the diameter exceeds 0.0026 inch

Solution;

[tex]\displaystyle z-score,\ Z= \mathbf{\dfrac{x-\mu }{\sigma }}[/tex]

At x = 0.0026 inch, we have;

[tex]\displaystyle Z=\dfrac{0.0026-0.002 }{0.0004 } = 1.5[/tex]

P(Z > 1.5) = 1 - P(Z < 1.5) = 1 - 0.9332 = 0.0668

The probability that the diameter of a dot exceeds 0.0026 inch = 0.0668

B. The probability that the diameter is less than 0.0026 inch = 0.9332

The z-score for a diameter of x = 0.0014 inch is given as follows;

[tex]\displaystyle Z=\mathbf{\dfrac{0.0014-0.002 }{0.0004 }} = -1.5[/tex]

P(Z < -1.5) = 0.0668

Therefore, the probability that the diameter is between 0.0014 and 0.0026 inch is given as follows;

P(0.0014 < x < 0.0026) = 0.9332 - 0.0668 = 0.8664

The probability that the diameter is between 0.0014 and 0.0026 = 0.8664

C. For the probability in part (b) to be 0.995, we have;

For a probability of 0.995, the z-score ≈ 2.575

[tex]\displaystyle P\left(Z < \dfrac{0.0026-0.002 }{\sigma } \right)- P\left(Z < \dfrac{0.0014-0.002 }{\sigma } \right)= 0.995[/tex]

Therefore;

[tex]\displaystyle \mathbf{ P\left(Z < \dfrac{0.0026-0.002 }{\sigma } \right)} = 0.995 + \frac{1 - 0.995}{2} = 0.9975[/tex]

From the z-table, we get;

[tex]\displaystyle P\left(Z < \dfrac{0.0026-0.002 }{\sigma } \right) = 0.9975[/tex]

The z-score with a probability of 0.9975 = 2.81

Which gives;

[tex]\displaystyle \left( \dfrac{0.0026-0.002 }{\sigma } \right) = 2.81[/tex]

[tex]\displaystyle \sigma = \left( \dfrac{0.0026-0.002 }{2.81} \right) = \mathbf{2.135 \times 10^{-4}}[/tex]

The standard deviation of the diameters needed so that the probability in part (b) is 0.995 is 2.135 × 10⁻⁴

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Answer:

Step-by-step explanation:

you have $4000 to invest and you invest x dollars at 10% and the remainder at 8℅.

a) an expression in x that represent the amount invested at 8% is

4000 - x

b) The The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time in years

I = interest after t years

From the information given

P = $x

R = 10%

Assuming the investment is for 1 year, then interest,

I = (x × 10 × 1)/100

I = $0.1x

c) P = 4000 - x

R = 8℅

I = [(4000 - x) × 8 × 1)]/100

I = (32000 - 8x)/100

I = 320 - 0.08x

d) the total interest earned is

I = 0.1x + 320 - 0.08x

I = 0.02x + 320

Question Continuation

5 2 5 5 2 1 0 5 7 5 8 9 3 7 2

Options

A. A Tale of Two Cities, Huckleberry Finn, A Tale of Two Cities

B. A Tale of Two Cities, Huckleberry Finn, The Sun Also Rises

C. A Tale of Two Cities, Huckleberry Finn, Crime and Punishment

D. Huckleberry Finn, Crime and Punishment, The Jungle

E. Crime and Punishment, The Jungle, The Sun Also Rises

Book List

1. Crime and Punishment

2. Huckleberry Finn

3. The Sun Also Rises

4. As I Lay Dying

5. A Tale of Two Cities

6. Death of a Salesman

7. The Jungle

8. Pride and Prejudice

9. The Scarlet Letter

Answer:

C. A Tale of Two Cities, Huckleberry Finn, Crime and Punishment

Step by step explanation

Counting from the left, the selected numbers are 5 , 2 and 1

The books are

5. A Tale of two cities

2. Huckleberry Finn

1. Crime and Punishment

Note that the numbers on the list are 5 2 5 5 2 1

After book 5 and 2 have been selected, the next series of numbers (5 5 2) can not be considered because they've already been selected.

So, the next number after 5 2 5 5 2 is then selected, which is 1

The selected books are:

The books are: A Tale of two cities, Huckleberry Finn, Crime and Punishment

The simple random selection of three books using the random number generated will include the books : The Sun also rises, The Scarlet letter, Crime and Punishment.

The random number generated using technology include :

7, 2, 7, 2, 2, 6, 7, 0, 8, 3, 2, 8, 5, 3, 1

From the list of number books attached below :

7. The Sun also rise

2. The Scarlet letter

6. Crime and Punishment

Hence, the randomly selected books will be :

The Sun also rises, The Scarlet letter, Crime and Punishment.

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Answer:

B. 0.50.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability of a measure X being between two values c and d, in which d is larger than c, is given by the following formula:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

Uniformly distributed with a minimum of 120 minutes and a maximum of 150 minutes.

This means that [tex]a = 120, b = 150[/tex]

What is the probability that a flight is between 125 and 140 minutes?

This is

[tex]P(125 \leq X \leq 140) = \frac{140 - 125}{150 - 120} = 0.5[/tex]

So the correct answer is:

B. 0.50.

Final answer:

Explaining the polar coordinates for given Cartesian coordinates.

Explanation:

Polar Coordinates of Points:

Point A(2, 2√3): Polar coordinates are (4, π/6).

Point B(-4, 7π/6): Wrong polar coordinates as it should be (4, 11π/6).

Point C(4, 13π/6): Wrong polar coordinates.

Final answer:

The weighted mean number of days to maturity for dollars invested in the 5 money market funds is approximately 11.35 days. This is calculated by taking the product of the days to maturity and the corresponding money value for each fund, summing these products, and then dividing by the total money value invested.

Explanation:

The question asks to calculate the weighted mean of days to maturity for dollars invested in several money market funds with varying maturities and dollar values. To compute this, we multiply each fund's days to maturity by its dollar value (in millions), sum these products, and then divide by the total of the dollar values. Here's the calculation:

(20 days * $20 million) + (12 days * $30 million) + (7 days * $10 million) + (5 days * $15 million) + (6 days * $10 million) = $400 million-days + $360 million-days + $70 million-days + $75 million-days + $60 million-days

Total million-days = $965 million-days

Total value of all funds = $85 million

Weighted mean days to maturity = Total million-days / Total value of all funds = $965 million-days / $85 million = 11.35 days

So, the weighted mean number of days to maturity for the dollars invested in these 5 money market funds is approximately 11.35 days.

Answer:

(a) The proportion of students taking the MCAT had a score over 519 is 0.0367.

(b) The percentage of students who scored more than 519 in the MCAT is 3.67%.

Step-by-step explanation:

Assuming that the sample size or the number of students taking the MCAT in 2015 is large, the sampling distribution of scores follow a normal distribution.

Let X = score of a student

Given:

Mean = [tex]\mu=500[/tex]

Standard deviation = [tex]\sigma=10.6[/tex]

(a)

Compute the probability of students who scored more than 519 as follows:

[tex]P(X>519)=P(\frac{X-\mu}{\sigma}> \frac{519-500}{10.6})\\=P(Z>1.7925)\\=1-P(Z<1.7925)[/tex]

Use the z-table to determine the probability.

[tex]P(X>519)=P(\frac{X-\mu}{\sigma}> \frac{519-500}{10.6})\\=P(Z>1.7925)\\=1-P(Z<1.7925)\\=1-0.9633\\=0.0367[/tex]

Thus, the probability of students who scored more than 519 is 0.0367.

(b)

Convert the probability of students who scored more than 519 to percentage

[tex]=0.0367\times100\\=3.67\%[/tex]

Thus, the percentage of students who scored more than 519 is 3.67%.

Final answer:

The z-score for 519 is approximately 1.79, which correlates to about 3.67% of students scoring higher than 519.

Explanation:

To find the proportion of students scoring over 519 on the MCAT, first, we must calculate the z-score. The z-score tells us how many standard deviations an element is from the mean. Since the mean score is 500.0 and the standard deviation is 10.6, the z-score formula is z = (X - μ) / σ, where X is the score, μ is the mean, and σ is the standard deviation. For a score of 519, the z-score would be z = (519 - 500.0) / 10.6 ≈ 1.79. To find the proportion of students scoring above this z-score, we would look up the z-score in a standard normal distribution table (Table A), or use a statistical software to find that the area to the right of z=1.79. This area corresponds to the proportion of students scoring higher than 519. Since standard normal distribution tables are commonly used and we don't have one provided here, let's assume that the area to the right of z=1.79 is approximately 3.67%.