If babies are constantly placed on their backs without any restrictions, what will happen to their development?
A. they suffer from weakness in certain muscle groups.
B. they learn to roll over, crawl, and eventually walk on their own.
c. their ability to roll over, crawl, and eventually walk is hindered.
D. they suffer brain damage from the pressure on the back of their head.

Answers

Answer 1

Answer:

A

Explanation:


Related Questions

The Thomas Supply Company Inc. Is a distributor of gas-powered generators. As with any business, the length of time customers take to pay their invoices is important. Listed below, arranged from smallest to largest, is the time, in days, for a sample of the Thomas Supply Company Inc. Invoices.

Answers

Answer:

(a) 31 , 54

(b) 48

Explanation:

Data set : 13 13 13 20 26 29 31 33 34 34 35 35 36 37 38 41 41 41 45 45 47 47 48  52 54 56 56 62 67 82Part a requires you to find second decile and 8th decileFor second decile there are 30 elements for second decile:

(a) Locator: 0.2*30 = 6

    Round up to 7

    20% decile = 31

For 8th decile

    Locator: 0.8*30 = 24

    Round up to 25

    80% decile = 54

(b) To determine 67th percentile

    Locator : 0.67^30 = 20.1

    Round up to 22

    67% percentile = 48

 

A recently televised broadcast of a popular television show had a 15 share, meaning that among 5000 monitored households with TV sets in use, 15% of them were tuned to the show. A 0.01 significance level is used to test an advertiser's claim that among the households with TV sets in use, less than 20% were tuned in to the show. Find the P-value.

Answers

Answer:

The p-value of the test is approximately 0.

Explanation:

The hypothesis can be defined as:

H₀: The proportion of TV sets tuned in to the show is not less than 20%, p ≥ 0.20.

Hₐ: The proportion of TV sets tuned in to the show is less than 20%, p < 0.20.

Given:

[tex]n=5000\\\hat p=0.15\\\alpha =0.01[/tex]

The test statistic is:

[tex]z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}} }=\frac{0.15-0.20}{\sqrt{\frac{0.20(1-0.20)}{5000} }}= -8.77[/tex]

The p-value of test is:

[tex]p-value=P(Z<-8.77)\approx0[/tex]

*Use a standard normal table.

Thus, the p-value of the test is approximately 0.

Answer:

The answer is 0.0001.

Explanation:

I promise!

during the ___ development stage children are drawing their thoughts instead of merely observations.

A. scribbling
B. circular
C. pre-schematic
D. schematic

Answers

Answer:

A. scribbling

Explanation:

- Scribbling stage refers to the first stage in children's art development. At this stage, kid will scribble and manipulate drawing tools just to move their arms around freely, not concerning the appearance of what they make. However, at this stage, there is changes from thinking in terms of motion to imaginative thinking in terms of images.

- Pre-schematic stage is when children starts producing representatives symbols for surrounding objects with visual idea developed.

- Schematic stage is when kids have already developed specific schemas to symbolize objects. This refers to repeated symbol for each object.

Which of the following contributes to infants developing a sense of basic trust?
A. varied sleep, feeding, and play schedules
B. infant groups of at least four infants per adult caregiver
C. responding to each infants needs individually
D. rotating caregivers to provide diverse and comprehensive care.

Answers

Answer:

C

Explanation:

C. Hope this helps :)

At what age does trust usually begins to develop?
A. 25 weeks
B. 20 weeks.
C. 10 weeks
D. 15 weeks

Answers

Answer:

a. 25 weeks

Explanation:

What are the variance (to 2 decimals) and standard deviation (to 4 decimals) for the number of these tweets with no reaction?

Answers

Answer:

The variance is 20.59; and the standard deviation is 4.5376.

Explanation:

First of all, there are 71% of tweets with no reaction in the study. Thus, the probability (p) is 0.71. Therefor, sample x follows binomial distribution

Secondly, if we randomly select 100 tweets, the sample size (n) will be 100.

The variance is [tex]n*p*(1 - p) = 100*0.71*(1 - 0.71) = 20.59[/tex]

The standard deviation is the root-square of variance. Then, it is sqrt (20.59) = 4.5376

What are the variance (to 2 decimals) and standard deviation (to 4 decimals) for the number of these tweets with no reaction?

Answers

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What is the expected number of these tweets with no reaction?

There are 100 tweets (n = 100) each with a 71% chance of having no reaction
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