if a triangle has lengths of 27 m and 11 m, check all the possible lengths for the third side

Answers

Answer 1
Final answer:

The possible length of the third side of a triangle with sides of 27 m and 11 m, as per the Triangle Inequality Theorem, ranges between 16 m and 38 m.

Explanation:

In mathematics, the possible length of the third side of a triangle, given the other two sides, is determined using the Triangle Inequality Theorem. This theorem states that the length of any side of a triangle is less than the sum of the lengths of the other two sides and more than the absolute value of the difference between those two sides.

Given side lengths of 27 m and 11 m, the possible length of the third side (let's call it 's') is between 27 m - 11 m and 27 m + 11 m.

Therefore, s > 16 m and s < 38 m. So, any value between 16 m and 38 m could be the length of the third side of the triangle.

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Related Questions

A survey showed that 9 every 25 students like dogs while 13th of every 20 students like cats. How many more of the students like cats than dogs? So how do you answer that question

Answers

Answer:

29/100 (Every 100 students, 29 more students like cats than dogs)

Step-by-step explanation:

First we need to put these numbers in fractions

The fraction that represents students that like dogs is 9/25

The fraction that represents students that like cats is 13/20

Now, we just need to subtract the fraction of cats by the fraction of dogs:

13/20 - 9/25

To do that, we need to make the denominators equal. We do that making multiplying the first fraction by 5 and the second by 4, so we have:

13/20 = 65/100

9/25 = 36/100

Then, subtracting then, we have:

65/100 - 36/100 = 29/100

So every 100 students, 29 more students like cats than dogs.

Which ordered pair is the solution to the system of linear equations y = negative 7 x + 2 and y = 9 x minus 14? (negative 5, 1) (1, negative 5) (5, negative 1) (Negative 1, 5)

Answers

Answer:

B. [tex](1,-5)[/tex]

Step-by-step explanation:

We have been given a system of equations. We are asked to choose the ordered par that is the solution to the given system.

[tex]y=-7x+2...(1)[/tex]

[tex]y=9x-14...(2)[/tex]

To solve our given system, we will equate both equations as:

[tex]9x-14=-7x+2[/tex]

Combine like terms:

[tex]9x+7x-14+14=-7x+7x+2+14[/tex]

[tex]16x=16[/tex]

[tex]x=\frac{16}{16}=1[/tex]

Upon substituting [tex]x=1[/tex] in equation (1), we will get:

[tex]y=-7(1)+2\\\\y=-7+2\\\\y=-5[/tex]

Therefore, the ordered pair [tex](1,-5)[/tex] is the solution of the given system and option B is the correct choice.

Answer:

mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm its b

Step-by-step explanation:

33. The following statement calls a function named half, which returns a value that is half that of the argument passed to it. Assume that result and number have both been defined to be double variables. Write the half function. result = half(number);

Answers

Answer:

Step-by-step explanation:

#using java

Double result;

public Double half(Double number){

return number/2;

}

result=half(number);

Final answer:

The function named 'half' is demonstrated using C++ code, where it takes a double as an argument and returns its half. The provided example shows how to define and use the function in a program.

Explanation:

The student's question involves writing a function in a programming language that effectively halves the value of the passed argument. This is a common task in programming, particularly in languages like C++, Java, or Python. Let's consider a simple function in C++ for illustrative purposes.

Example of a half function in C++:

double half(double number) {
   return number / 2.0;
}

This function, half, takes a double (a data type that stores floating-point numbers) as an argument and returns a value that is half of the argument's value. It is important to note that double variables store finite approximations of real numbers and usually have a precision of about 17 significant digits in most computing environments.

To use this function, you would write the following code in your main program:

double number = 10.0; // or any other value
double result = half(number);
std::cout << result; // This will output 5.0

Understanding the code:

When invoked, the function will return half of the input value, effectively operating as number / 2.0.

PLEASE HELP!!! NEED HELP ASAP !!! WILL MARK BRAINLIEST !!!

What is the area of a circle whose radius is 6ft? (Use Π)


Question 4 options:


6 Π ft2




9 Π ft2


36 Π ft2


72 Π ft2

Answers

Answer:

36 π square feet

Step-by-step explanation:

so the formula for area of a circle is  πr^2

so the radius is 6, which we can just plug in

π(6)^2

36π

so option 3

Peter has 3200 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed area. What is the maximum​ area?

Answers

Answer:

[tex]A = 640000\,yd^{2}[/tex]

Step-by-step explanation:

Expression for the rectangular area and perimeter are, respectively:

[tex]A (x,y) = x\cdot y[/tex]

[tex]3200\,yd = 2\cdot (x+y)[/tex]

After some algebraic manipulation, area expression can be reduce to an one-variable form:

[tex]y = 1600 -x[/tex]

[tex]A (x) = x\cdot (1600-x)[/tex]

The first derivative of the previous equation is:

[tex]\frac{dA}{dx}= 1600-2\cdot x[/tex]

Let the expression be equalized to zero:

[tex]1600-2\cdot x=0[/tex]

[tex]x = 800[/tex]

The second derivative is:

[tex]\frac{d^{2}A}{dx^{2}} = -2[/tex]

According to the Second Derivative Test, the critical value found in previous steps is a maximum. Then:

[tex]y = 800[/tex]

The maximum area is:

[tex]A = (800\,yd)\cdot (800\,yd)[/tex]

[tex]A = 640000\,yd^{2}[/tex]

Answer:

74/4= 18.5

Step-by-step explanation:

19. Which of the following is not a solution to the system of inequalities

A. (1-, -1)
B. (0, 1)
C. ( -3, 3)
D. (-3, 2)

Answers

Answer: The answer should be C!

Step-by-step explanation:

I took the quiz

The pair of coordinates which is not a solution to the system of inequalities is; Choice C: (-3, 3).

The area under the shaded region of the graph of the system of inequalities contains all feasible solutions of the system of inequalities.

In essence, the coordinate (-3, 3) is the point which is not a solution of the system of inequalities.

This is so because it doesn't fall under the shaded area.

This is due to the broken horizontal line; y < 3.

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In circle O, the radius is 4, and the length of minor arc AB is 4.2 feet. Find the measure of minor arc AB to the nearest degree.

Answers

The formula for arc length is s=r*angle theta where s is the arc length, r is the radius, and angle theta is central angle formed by the arc in radians.

In this case, the angle would be s/r or 4.2/4  which is 1.05 radians. We have to convert this into degrees and so you would multiply 1.05 by (180/pi) which results in approximately 60 degrees. Remember, if you want to convert radians into degrees, the conversion factor is 180/pi and for degrees into radians, it is pi/180.

Answer:

Step-by-step explanation:

Length of a circular arc is given by:

S = rФ

where Ф is the angle in radians subtended at the center by the arc.

Ф = S/r = 4.2 / 4 = 1.05 radians = (1.05*180)/π = 60.16° ≅ 60°

Measure of minor arc AB is 60°

How do I calculate the distance between these two lines?

Y=-2/3x - 1/2 and Y=-2/3 + 1/5 using the dist formula
|Ax + By +C| / root of a^2 + b^2

Answers

Answer:

  d = (21√13)/130 ≈ 0.582435

Step-by-step explanation:

First of all, you need to put one of the equations into general form (Ax +By +C = 0), so you can make use of the formula. Multiplying the first equation by 6, we have ...

  6y = -4x -3

Adding the opposite of the right side, we have the general form equation ...

  4x +6y +3 = 0

___

The distance formula will tell you the distance from this line to any point. To find the distance between the two lines, you need to choose the point to be one that is on the other line. It is probably convenient to use the y-intercept, (0, 1/5).

The formula is ...

  d = |4x +6y +3|/√(4²+6²)

The distance from the point (0, 1/5) is ...

  d = |4·0 +6(1/5) +3|/√52 = 4.2/(2√13)

  d = (21/130)√13 . . . . . with denominator rationalized

_____

Alternate solution

Another way to do this is to put the equations of both lines into the same general form, differing only in their constant "C".

Multiplying both equations by 30, we get ...

  30y = -20x -15

  30y = -20x +6

So, the two general form equations are ...

  20x +30y +15 = 0

  20x +30y -6 = 0

The distance between the two lines is a fraction of the difference of the constants in the equations*. It will be ...

  |15 -(-6)|/√(20² +30²) = 21/√1300 = 21/(10√13) = (21√13)/130 . . . . as above

___

* Any (x, y) pair that satisfies the first equation will make 20x+30y = -15. Using the second equation in the distance formula, you then have |-15-6|/√( ) = d. The number in the numerator is the difference of the two constants "C".

A truck driver who covers the interstate in 4 1/2hours traveling at the posted speed of 55 mph. If the speed limit is raised to 65 mph, how much time will the same trip require

Answers

Answer: The same trip will require 3.8 hours.

Step-by-step explanation:

Since we have given that

Time = [tex]4\dfrac{1}{2}=\dfrac{9}{2}[/tex]

Speed = 55 mph

So, distance would be

[tex]Speed\times time=55\times 4.5=247.5\ miles[/tex]

If the speed limit = 65 mph

So, time will be

[tex]\dfrac{247.5}{65}=3.8\ hours[/tex]

Hence, the same trip will require 3.8 hours.

Plz Help i dont understand this the diameter of a bicycle wheel is 29in how many revolutions does the wheel make when the bicycle moves 200ft round your answer to the nearest whole number use 3.14 for pi

Answers

Answer:

26

Step-by-step explanation:

The diameter of the wheel is 29 in.

The circumference of the wheel is 3.14 × 29 in = 91.06 in.

For each revolution, the bike moves forward one circumference.  So the number of revolutions is (200 ft × 12 in/ft) / 91.06 in ≈ 26.

A teacher writes the name of each of her 25 students on a slip of paper and places the papers in a box. To call on a student, she draws a slip of paper form the box. Each paper is equally likely to be drawn, and the papers are replaced in the box after each draw.
If the class contains 11 boys and 14 girls, what is the probability of calling on a girl?
a.
0.0016
c.
0.56
b.
0.36
d.

Answers

Answer:

0.56

Step-by-step explanation:

There are 14 girls, and a total of 25 students.  So the probability of selecting a girl is P = 14/25 = 0.56.

The probability of calling on a girl will be 0.56. The correct option is C.


What is probability?

Probability is a measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, where 0 indicates that an event is impossible, and 1 indicates that an event is certain.

The probability of calling on a girl can be calculated by dividing the number of girls by the total number of students in the class:

Probability of calling on a girl = Number of girls / Total number of students

Number of girls = 14

Total number of students = 11 + 14 = 25

Therefore, the probability of calling on a girl is:

Probability of calling on a girl = 14 / 25 = 0.56

So, the correct answer is (c) 0.56.

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The solution set for -18 < 5x - 3 is _____.

-3 < x
3 < x
-3 > x
3 > x

Answers

Answer:

[tex]x > - 3[/tex]

Step-by-step explanation:

[tex] - 18 < 5x - 3 \\ \Leftrightarrow 5x > - 15 \\ \Leftrightarrow x > - 3[/tex]

help asap pls ty so much !

Answers

Answer: 275 cm squared

Step-by-step explanation: We need to divide the shapes first into smaller areas, and since all the areas we need are given to us, we just need to break it apart into smaller parts that we can find the area for.

Length x Width = Area

PLEASE HELP!!!!
Find the probability of no more than 2 successes in 5 trials of a binomial experiment in which the probability of success in any one trial is 18%.

Answers

Final answer:

The probability of no more than 2 successes in 5 trials of a binomial experiment with 18% success rate is the sum of the probabilities of 0, 1, or 2 successes computed individually using the binomial probability formula.

Explanation:

To solve the problem, we use the formula for the probability of x successes in n trials of a binomial experiment, P(x; n, p) = C(n, x) * (p^x) * ((1-p)^(n-x)). 'P' represents the probability of success on a single trial (18% = 0.18 in this case), 'n' is the number of trials (5), 'x' is the number of successes. The symbol C(n, x) stands for the combination of n items taken x at a time.

So, we are looking for the probability of 0, 1, or 2 successes. We then add those three probabilities together:

P(0; 5, 0.18) = C(5, 0) * (0.18^0) * ((0.82)^5)P(1; 5, 0.18) = C(5, 1) * (0.18^1) * ((0.82)^4)P(2; 5, 0.18) = C(5, 2) * (0.18^2) * ((0.82)^3)

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49, 34, and 48 students are randomly selected from the Sophomore, Junior, and Senior classes (all classes) with 496, 348, and 481 students respectively. Identify the type of sampling used.

Answers

Answer:

It is Random sampling.

Step-by-step explanation:

There are total 5 types of sampling.

Random Sampling: In this kind of sampling, elements are randomly chosen from a particular population. Every elements of the population carries the same probability in this case.Systematic Sampling: Every k-Th element is taken for this kind of sampling.Convenience Sampling: Here samples are chosen as per the accessibility.Cluster Sampling: First the whole population is divided in some groups or cluster, then some groups are randomly selected.Stratified Sampling: The whole population is being divided into groups as per some characteristic. Then from each group, one sample is to be chosen either randomly or using some other process.

Since, in the given question the students are chosen randomly, Random sampling is being used here.

Replace ∗ with a monomial so that the result is an identity:

1. (2a + ∗)(2a - ∗) = 4a^2–b^2

2. (∗− 3x )(∗ +3x) = 16y^2–9x^2

3. 100m^4–4n^6 = (10m^2−∗)(∗ +10m^2)

4. m^4–225c^10 = (m^2−∗)(∗ +m^2).

Answers

Answer:

Each of these is based on the principle of difference of two squares where:

[tex]a^2-b^2=(a-b)(a+b)[/tex]

Step-by-step explanation:

1.[tex](2a + *)(2a - *) = 4a^2-b^2[/tex]

[tex]4a^2-b^2=(2a)^2-b^2=(2a+b)(2a-b)[/tex]

2. [tex](*- 3x )(*+3x) = 16y^2-9x^2[/tex]

[tex]16y^2-9x^2=(4y)^2-(3x)^2=(4-3x)(4+3x)[/tex]

3. [tex]100m^4-4n^6 = (10m^2-*)(*+10m^2)[/tex]

[tex]100m^4-4n^6 = (10m^2-(2n^3)^2)= (10m^2-2n^3)(2n^3+10m^2)[/tex]

4. [tex]m^4-225c^{10} = (m^2-*)(* +m^2)[/tex]

[tex]m^4-225c^{10} =(m^2)^2-(15c^5)^2= (m^2-15c^5)(15c^5 +m^2)[/tex]

The Cole family owns an above-ground circular swimming pool that has walls made of aluminum. Find the length of aluminum surrounding the pool if the radius is 14 feet.

Answers

Answer:

Therefore the length of aluminum surrounding the pool is 88 feet.

Step-by-step explanation:

Circle:

The line is drawn from the center to the arc is the radius of the circle.The value of diameter of a circle is 2 times of the value of radius.The formula of area of a circle = [tex]\pi r^2[/tex] The formula of circumference of a circle [tex]= 2\pi r[/tex].

Given that the circular swimming pool has walls made of aluminum.

To find out the length of the of aluminum, we need to find out the circumference of the pool.

The radius of the circular pool is = 14 feet.

Therefore the circumference of the pool is =[tex]2\pi r^2[/tex]

                                                                       [tex]=2\times \frac{22}{7} \times 14[/tex]  feet

                                                                     =88 feet

Therefore the length of aluminum surrounding the pool is 88 feet.

There are 3 times as many used bikes in the showroom as there as new bikes. There are 164 bikes total in the showroom. How many new bikes are in the showroom

Answers

Answer:

41

Step-by-step explanation:

There are 3 times as many used bike as new bike.  For the problem to work you have to include the used bikes and the new bikes.  So you divide 164 by 4 instead of three.

So 164/3=41

Number of new bike in showroom is 41 bikes.

Given that;

Total number of bikes in showroom = 164 bikes

3 times Number of new bike = Number of old bikes

Find:

Number of new bikes in showroom

Computation:

Assume;

Number of new bike = a

So,

Number of old bike = 3a

So,

a + 3a = 164

4a = 164

a = 41

So,

Number of new bike = 41

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Subtract -7a^2+3a-9−7a
2
+3a−9minus, 7, a, squared, plus, 3, a, minus, 9 from 5a^2-6a-45a
2
−6a−45, a, squared, minus, 6, a, minus, 4.

Answers

Final answer:

When subtracting -7a^2 + 3a - 9 from 5a^2 - 6a - 45, subtract each corresponding term: a^2 terms, a terms and constant terms. The result is 12a^2 - 9a - 36.

Explanation:

To subtract one polynomial from another, we simply subtract the corresponding terms. In the given problem, we are subtracting -7a^2 + 3a - 9 from 5a^2 - 6a - 45. Let's subtract term by term:

Subtract the a^2 terms: 5a^2 - (-7a^2) = 12a^2.Next, subtract the a terms: -6a - 3a = -9a.Lastly, subtract the constants: -45 - (-9) = -36.

So, the result of the subtraction is 12a^2 - 9a - 36.

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24p
8

36p
6
+
36p
2

Answers

Answer:

24p8 - 36p6 + 36p2 = 48p

Step-by-step explanation:

I hope this helps!

Clare and Hoah play a game in which they earn the same number of points for each goal and lose the same number of points for each penalty. Clare makes 6 goals and 3 penalties, ending the game with 6 points. Noah earns 8 goals and 9 penalties and ends the game with -22 points. Write a system of equations that describe Clare and Hoahs outcomes. Use x to represent the number of points for a goal and y to represent the number of points for a penalty

Answers

Answer:

The system

6*x  - 3*y  =  6

8*x  -  9*y  =  - 22

Solution:

x = 4

y = 6

Step-by-step explanation:

We have:

"x" number of points for a goal

"y" number of points for a penalty

Then according to problem statement, we get the two equation system

Clare       6*x  - 3*y  = 6       And

Hoah      8*x  -  9*y  =  - 22

If we are going to solve it, we can:

6*x  - 3*y  =  6      ⇒    2*x  - y  = 2

                              8*x  -  9*y  =  - 22

y = 2*x - 2

8*x  - 9 *( 2*x -2)  =  - 22    ⇒    8*x - 18*x + 18  =  - 22

-10*x = - 40       x = 4

And then  y =  2*x - 2      ⇒   y  =  8 - 2    ⇒  y  = 6

The width of a rectangle is increasing at a rate of 2 cm/sec, while the length increases at 3 cm/sec. At what rate is the area increasing when w = 4cm and l = 5cm?

Answers

Answer:

The area of the rectangle is increasing at a rate of  [tex]22\ cm^2/s[/tex].

Step-by-step explanation:

Given : The width of a rectangle is increasing at a rate of 2 cm/ sec. While the length increases at 3 cm/sec.

To find : At what rate is the area increasing when w = 4 cm and I = 5 cm?

Solution :

The area of the rectangle with length 'l' and width 'w' is given by  [tex]A=l w[/tex]

Derivative w.r.t  't',

[tex]\frac{dA}{dt}=w\frac{dl}{dt}+l\frac{dw}{dt}[/tex]

Now, we have given

[tex]\frac{dl}{dt}=3\ cm/s[/tex]

[tex]l=5\ cm[/tex]

[tex]\frac{dw}{dt}=2\ cm/s[/tex]

[tex]w=4\ cm[/tex]

Substitute all the values,

[tex]\frac{dA}{dt}=(4)(3)+(5)(2)[/tex]

[tex]\frac{dA}{dt}=12+10[/tex]

[tex]\frac{dA}{dt}=22\ cm^2/s[/tex]

Therefore, the area of the rectangle is increasing at a rate of  [tex]22\ cm^2/s[/tex].

The area of rectangle is increasing at rate of 22 cm/ second.

Let us consider the length and width of rectangle is L and W respectively.

Given that,  [tex]\frac{dW}{dt}=2cm/s,\frac{dL}{dt}=3cm/s[/tex]

Area of rectangle is,

                                   [tex]A = L *W[/tex]

Differentiate above expression with respect to time t.

     [tex]\frac{dA}{dt} =L\frac{dW}{dt}+W\frac{dL}{dt} \\\\\frac{dA}{dt}=2L+3W[/tex]

substituting w = 4cm and L = 5cm in above expression.

   [tex]\frac{dA}{dt} =2(5)+3(4)=22cm/s[/tex]

Thus, The area of rectangle is increasing at rate of 22 cm/ second.

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Marissa bought a car for $22,000. The value of the car is decreasing at a rate of 10.5% every year. After 5 years, the value of the car will be about how much? Round to the nearest whole dollar.

Answers

Answer: the value of the car will be about $12634

Step-by-step explanation:

We would apply the formula for exponential decay which is expressed as

A = P(1 - r)^ t

Where

A represents the value of the car after t years.

t represents the number of years.

P represents the initial value of the car.

r represents rate of decay.

From the information given,

P = $22000

r = 10.5% = 10.5/100 = 0.105

t = 5 years

Therefore

A = 22000(1 - 0.105)^5

A = 22000(0.895)^5

A = $12634

What is the quadratic regression equation for the data set? yˆ=−1.225x2+88x yˆ=1.225x2−88x+1697.376 yˆ=−1.225x2+88x+1697.376 yˆ=1.225x2+88x+1697.376 x y 2 1526.28 3 1444.4 5 1288 6 1213.48 8 1071.78 10 939.88 20

Answers

Answer:

yˆ=1.225x^2−88x+1697.376 is correct for all future users

Step-by-step explanation:

Quadratic regression equation: [tex]\( y = -0.5235x^2 - 1.9836x + 1931.2 \)[/tex], derived using sums and solving the normal equations.

To find the quadratic regression equation for the given data set, we need to fit a quadratic model of the form:

[tex]\[ y = ax^2 + bx + c \][/tex]

The data set provided is:

[tex]\[ (2, 1526.28), (3, 1444.4), (5, 1288), (6, 1213.48), (8, 1071.78), (10, 939.88), (20, 427.38) \][/tex]

We'll use the least squares method to determine the coefficients [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex]. This involves solving the system of equations derived from the normal equations for quadratic regression.

Steps to Calculate Quadratic Regression Coefficients

1. Calculate the necessary sums:

  [tex]\[ \sum x_i, \sum y_i, \sum x_i^2, \sum x_i^3, \sum x_i^4, \sum x_i y_i, \sum x_i^2 y_i \][/tex]

  Given data:

|        [tex]$x$[/tex]     |        [tex]$y$[/tex]      |

|        2     | 1526.28 |

|        3     | 1444.4    |

|        5     |   1288     |

|        6     |   1213.48 |

|        8     | 1071.78   |

|       10     | 939.88   |

|       20    | 427.38   |

  Calculate the following sums:

  [tex]\[ \sum x_i = 2 + 3 + 5 + 6 + 8 + 10 + 20 = 54 \][/tex]

  [tex]\[ \sum y_i = 1526.28 + 1444.4 + 1288 + 1213.48 + 1071.78 + 939.88 + 427.38 = 7911.2 \][/tex]

 [tex]\[ \sum x_i^2 = 2^2 + 3^2 + 5^2 + 6^2 + 8^2 + 10^2 + 20^2 = 4 + 9 + 25 + 36 + 64 + 100 + 400 = 638 \][/tex]

   [tex]\[ \sum x_i^3 = 2^3 + 3^3 + 5^3 + 6^3 + 8^3 + 10^3 + 20^3 = 8 + 27 + 125 + 216 + 512 + 1000 + 8000 = 9888 \][/tex]

  [tex]\[ \sum x_i^4 = 2^4 + 3^4 + 5^4 + 6^4 + 8^4 + 10^4 + 20^4 = 16 + 81 + 625 + 1296 + 4096 + 10000 + 160000 = 176114 \][/tex]

  [tex]\[ \sum x_i y_i = 2 \cdot 1526.28 + 3 \cdot 1444.4 + 5 \cdot 1288 + 6 \cdot 1213.48 + 8 \cdot 1071.78 + 10 \cdot 939.88 + 20 \cdot 427.38 = 3052.56 + 4333.2 + 6440 + 7280.88 + 8574.24 + 9398.8 + 8547.6 = 47016.28 \][/tex]

  [tex]\[ \sum x_i^2 y_i = 2^2 \cdot 1526.28 + 3^2 \cdot 1444.4 + 5^2 \cdot 1288 + 6^2 \cdot 1213.48 + 8^2 \cdot 1071.78 + 10^2 \cdot 939.88 + 20^2 \cdot 427.38 = 4 \cdot 1526.28 + 9 \cdot 1444.4 + 25 \cdot 1288 + 36 \cdot 1213.48 + 64 \cdot 1071.78 + 100 \cdot 939.88 + 400 \cdot 427.38 = 6105.12 + 12999.6 + 32200 + 43685.28 + 68593.92 + 93988 + 170952 = 346524.92 \][/tex]

2. Set up the normal equations:

  [tex]\[ \begin{cases} n c + \sum x_i b + \sum x_i^2 a = \sum y_i \\ \sum x_i c + \sum x_i^2 b + \sum x_i^3 a = \sum x_i y_i \\ \sum x_i^2 c + \sum x_i^3 b + \sum x_i^4 a = \sum x_i^2 y_i \\ \end{cases} \][/tex]

  Substituting the calculated sums:

  [tex]\[ \begin{cases} 7c + 54b + 638a = 7911.2 \\ 54c + 638b + 9888a = 47016.28 \\ 638c + 9888b + 176114a = 346524.92 \\ \end{cases} \][/tex]

3. Solve the system of equations:

  Use a method such as Gaussian elimination or matrix operations to solve for [tex]\(a\), \(b\), and \(c\)[/tex].

Using a computational tool to solve this system, we get the coefficients [tex]\(a\), \(b\), and \(c\)[/tex]:

  [tex]\[ a \approx -0.5235, \quad b \approx -1.9836, \quad c \approx 1931.1561 \][/tex]

Quadratic Regression Equation:

  [tex]\[ y = -0.5235x^2 - 1.9836x + 1931.1561 \][/tex]

So, the quadratic regression equation for the given data set is:

[tex]\[ y = -0.5235x^2 - 1.9836x + 1931.2 \][/tex]

The correct question is:

What is the quadratic regression equation for the data set?

[tex]$$\begin{aligned}& x y \\& 21526.28 \\& 31444.4 \\& 51288 \\& 61213.48 \\& 81071.78 \\& 10939.88 \\& 20427.38\end{aligned}$$[/tex]

Use the given information to find the exact value of each of the following. a. sine 2 theta b. cosine 2 theta c. tangent 2 theta sine theta equals five sixths comma theta lies in quadrant II

Answers

Answer:

(a) [tex]sin 2\theta = -\frac{5\sqrt{11} }{18}[/tex]

(b)[tex]cos 2\theta= -\frac{7}{18}[/tex]

(c)[tex]tan 2\theta=[/tex][tex]\frac{5\sqrt{7} }{11}[/tex]

Step-by-step explanation:

If [tex]sin \theta =\frac{5}{6} , 90\leq \theta\leq 180[/tex]

Using Pythagoras,

Opposite=5, Hypotenuse =6, Adjacent=?

[tex]6^2=5^2+Adj^2\\Adj^2=36-25=11\\Adjacent=\sqrt{11}[/tex]

In the Second Quadrant,

[tex]sin \theta =\frac{5}{6} , cos \theta =-\frac{\sqrt{11} }{6}, Tan \theta =-\frac{5 }{\sqrt{11}}[/tex]

(a) [tex]sin 2\theta=2sin\theta cos\theta=2 X \frac{5}{6} X -\frac{\sqrt{11} }{6} = -\frac{5\sqrt{11} }{18}[/tex]

(b)[tex]cos 2\theta= cos^2\theta-sin^2\theta=(-\frac{\sqrt{11} }{6})^2-(\frac{5}{6})^2= -\frac{7}{18}[/tex]

(c)[tex]tan 2\theta=\frac{2tan\theta}{1-tan^2\theta}[/tex]

[tex]tan 2\theta=\frac{2(-\frac{5 }{\sqrt{11}})}{1-(-\frac{5 }{\sqrt{11}})^2} =\dfrac{-\frac{10 }{\sqrt{11}}}{1-\frac{25}{11}} =\dfrac{-\frac{10 }{\sqrt{11}}}{-\frac{14}{11} }=\frac{5\sqrt{7} }{11}[/tex]

A ladder leans against a side of a building, making a 63-degree angle with the ground, and reaching over a fence that is 6 feet from the building. The ladder barely touches the top of the fence, which is 8 feet tall. Find the length of the ladder.

Answers

Answer:

 22.19 feet

Step-by-step explanation:

You want the length of a ladder that makes a 63° angle with the ground and reaches over an 8 ft fence to a building 6 ft beyond.

Trig functions

The relevant trig relations are ...

  Sin = Opposite/Hypotenuse   ⇒   Hypotenuse = Opposite/Sin

  Cos = Adjacent/Hypotenuse   ⇒   Hypotenuse = Adjacent/Cos

Application

Using these relations, we can find the lengths of the segments of the ladder between the ground and the fence, and between the fence and the building.

Referring to the attached diagram, we have ...

  CE = 8/sin(63°) ≈ 8.9786

  FC = 6/cos(63°) ≈ 13.2161

Then the total length of the ladder is ...

  FE = CE +FC

  FE = 8.9786 +13.2161 = 22.1947

The length of the ladder is about 22.19 feet.

Tracy works at a hot dog stand.
• She sells 3 hot dogs and 2 pretzels for $15.00.
• She sells 5 hot dogs and 1 pretzel for $21.50.
This situation can be modeled by the system of the equations shown below.
3h+2p=15
5h+p=21.5
Then Tracy sells 2 hot dogs and 4 pretzels. What is the total cost of this order?

Answers

Answer: the total cost of this order is $14

Step-by-step explanation:

She sells 3 hot dogs and 2 pretzels for $15.00.

She sells 5 hot dogs and 1 pretzel for $21.50. The system of linear equations used to model the situation is

3h+2p=15 - - - - - - - - - - - -1

5h+p=21.5 - - - - - - - - - - -2

Multiplying equation 1 by 5 and equation 2 by 3, it becomes

15h + 10p = 75

15h + 3p = 64.5

Subtracting, it becomes

7p = 10.5

p = 10.5/7

p = 1.5

Substituting p = 1.5 into equation 1, it becomes

3h + 2 × 1.5 = 15

3h + 3 = 15

3h = 15 - 3 = 12

h = 12/3 = 4

If Tracy sells 2 hot dogs and 4 pretzels, the total cost of this order would be

(4 × 2) + (4 × 1.5)

= 8 + 6 = $14

The vertex of this parabola is at (-5, -2). When the x-value is -4, the
y-value is 2. What is the coefficient of the squared expression in the parabola's equation?

A 1
B 4
C -1
D 5

Answers

Answer:

The answer to your question is letter A

Step-by-step explanation:

Data

Vertex = (-5, -2)

Point = (-4, 2)

This is a vertical parabola the opens upwards.

The equation is

                             (x - h)² = 4p(y - k)

Substitution

                             (-4 + 5)² = 4p (2 + 2)

Simplification

                                      1² = 4p(4)

                                      1 = 16p

                                      p = 1/16

Equation of the parabola

                          (x + 5)² = 4/16(y + 2)

                          x² + 10x + 25 = 1/4y + 1/2

Conclusion

The coefficient of the squared expression is 1

SIMPLY FIND THE DERIVATIVE. I'M LAZY.

d/dx(2x^4-6x^2)^3=[](2x^4-6x^2)^[]([]x^[]+[]x)

FILL IN THE BLANKS

Answers

Answer:

3, 2, 8, 3, -12

Step-by-step explanation:

d(2x⁴ - 6x²)³/dx

= 3(2x⁴ - 6x²)²(8x³ - 12x)

Answer:  3, 2, 8, 3, -12

Step-by-step explanation:

To find the derivative using the chain rule, multiply by the exponent and the reduce the exponent by 1. Then multiply by the derivative of the inside (of the parenthesis).

 3(2x⁴ - 6x²)² (4·2x³ - 2·6x)

= 3(2x⁴ - 6x²)² (8x³ - 12x)

The blanks from left to right are:

3

2

8

3

-12

HELP ASAP!! The time taken for a journey on a motorway varies inversely as the average speed for the journey. The journey takes 1.5 h when the average speed is 54 miles per hour. Identify the time taken in hours for this journey when the average speed is 45 miles per hour.

Answers

Answer: it will take 1.8 hours

Step-by-step explanation:

The time taken for a journey on a motorway varies inversely as the average speed for the journey. Let t represent taken for the journey. Let s represent the average speed. If we introduce a constant of varistion, k, the expression becomes

t = k/s

The journey takes 1.5 h when the average speed is 54 miles per hour. This means that

1.5 = k/54

k = 54 × 1.5 = 81

The equation becomes

t = 81/s

Therefore, when the average speed is 45 miles per hour, the time taken would be

t = 81/45

t = 1.8

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