Answer:
If a 1% level of significance is used to test a null hypothesis, there is a probability of ____ less than 1%______ of rejecting the null hypothesis when it is true
Step-by-step explanation:
Given that a hypothesis testing is done.
Level of significance used is 1%
i.e. alpha = 1%
When we do hypothesis test, we find out test statistic Z or t suitable for the test and find p value
If p value is < 1% we reject null hypothesis otherwise we accept null hypothesis.
So p value can be atmost 1% only for accepting null hypothesis.
So the answer is 1%
If a 1% level of significance is used to test a null hypothesis, there is a probability of ____less than 1%______ of rejecting the null hypothesis when it is true.
jonesville and smithville each have a population of size 2600 at time t = 0, where t is measured in years. Suppose jonesville's population grows by 170 people per year. Suppose the population of smithville grows by 7% per year.
1. Which is true? (Circle one)
A. Both towns are growing exponentially.
B. Jonesville is growing linearly and Smithville is growing exponentially.
C. Jo nesville is growing exponentially and Smithville is growing linearly
D. Both towns are growing linearly.
Answer: B. Jonesville is growing linearly and Smithville is growing exponentially.
Step-by-step explanation:
Linear growth :
Population grow by a constant amount after each time period.The rate of change of dependent variable with respect to independent variable is a constant.It is represented by line on graph.Equation for linear growth : [tex]y=mx+c[/tex] , c = initial value and m is the rate of change of y with respect to x.Exponential growth :
Population grow by a constant ratio .It is represented by a curve on graph.Equation for exponential growth : [tex]y=a(1+r)^x[/tex] , a = initial value and r is rate of growth ( in decimal ) and x is time period.Given : Jonesville's population grows by 170 people per year.
i.e .Population grow by a constant amount per year.
⇒ Jonesville is growing linearly.
The population of smithville grows by 7% per year.
i.e. Population grow by a constant ratio.
⇒Smithville is growing exponentially.
Hence, the true statement is "B. Jonesville is growing linearly and Smithville is growing exponentially."
Final answer:
Jonesville is experiencing linear growth with a constant increase of 170 people per year, while Smithville is experiencing exponential growth, with its population growing by 7% yearly. The correct answer is B, signifying two different types of growth for the towns.
Explanation:
The correct answer to the question is B: Jonesville is growing linearly and Smithville is growing exponentially. This can be determined by looking at the type of growth each town is experiencing. Jonesville's population increases by a fixed amount each year (170 people), which is characteristic of linear growth. Conversely, Smithville's population increases by a percentage (7%) of the population each year, which is a key feature of exponential growth as the rate of growth increases with an increasing population base.
Linear growth occurs when a quantity increases by the same fixed amount over equal increments of time. In the case of Jonesville, it grows by 170 people every year, resulting in a straight line if graphed over time. On the other hand, exponential growth refers to an increase that is proportional to the quantity's current value, leading to faster and faster growth as time goes on. For Smithville, a 7% growth rate implies that each year the town will grow by 7% of its population at the end of the previous year, meaning the actual number of people added each year will continue to increase as the population grows.
Suppose you toss a fair coin 10,000 times. Should you expect to get exactly 5000 heads? Why or why not? What does the law of large numbers tell you about the results you are likely to get? a. You shouldn't expect to get exactly 5000 heads, because you cannot predict precisely how many heads will occur. b. You should expect to get exactly 5000 heads, because the proportion of heads should be 50% for such a large number of tosses. c. You should expect to get exactly 5000 heads, because for a fair coin, the proportion of heads is exactly 50%. d. You shouldn't expect to get exactly 5000 heads, because it is not easy to count precisely the number of heads that occurred.
The answer is:
You shouldn't expect to get exactly 5000 heads, because you cannot predict precisely how many heads will occur.
The outcome in tossing a fair coin is based on chance.
However, according to the law of large numbers, the frequencies of events with the same likelihood of occurrence even out, given enough trials or instances.
For example, in the case of a fair coin, where both head and tail have equal probability of occurrence, as the number of tosses becomes sufficiently large (say 1 million tosses), the ratio heads to tails in the outcome will be extremely close to 1:1.
So according to the law, we should expect to approach a point where half of the outcomes are heads and the other half are tails, as the number of tosses become very large.
The answer is (a). You should not expect to get exactly 5000 heads, because you cannot predict precisely how many heads will occur.
The law of large numbers states that as the number of independent trials of a random experiment increases, the observed frequency of each outcome approaches the expected frequency. In other words, the more times you toss a fair coin, the closer the proportion of heads will get to 50%.
However, the law of large numbers does not guarantee that you will get exactly 5000 heads even if you toss a fair coin 10,000 times. It is still possible to get more or fewer than 5000 heads, even though it is unlikely.
For example, if you toss a fair coin 100 times, you might get 55 heads and 45 tails. This is within the normal range of variation, even though it is not exactly 50 heads and 50 tails.
As the number of tosses increases, the probability of getting exactly 50/50 heads and tails decreases. However, the probability of getting close to 50/50 heads and tails increases.
In conclusion, you should not expect to get exactly 5000 heads even if you toss a fair coin 10,000 times. However, you can expect the proportion of heads to be close to 50%.
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A researcher is interested in studying the perceived life satisfaction among younger adults and hypothesizes that life satisfaction among younger adults is different than the general public. She did a pilot study and gave a life satisfaction test (known to have high reliability and validity) to nine younger adults (between 20 and 30). Scores on the measure range from 0 to 5 with 5 indicative of high life satisfaction, and 0 indicative of no life satisfaction.
The data are presented below. Assume that life satisfaction for general public is 2.5, conduct the appropriate test and answer the questions. 4, 3, 3, 4, 5, 2, 2, 2, 2.
What would be the null hypothesis of this study?
A.H0: Mean= 3
B.H0: Mean = 2.5
C.H0: Mean < 5
D.H0: Mean >2.5
E.None of the above
Answer:
Option B) [tex]H_0: \text{Mean} = 2.5[/tex]
Step-by-step explanation:
We are given the following in the question:
A researcher is interested in studying the perceived life satisfaction among younger adults.
The hypothesis is conducted to check that life satisfaction among younger adults is different than the general public.
Life satisfaction for general public = 2.5
Data:
4, 3, 3, 4, 5, 2, 2, 2, 2
We have to design the null hypothesis.
The researcher claims that life satisfaction is different for younger adult and general public.
But the null hypothesis always state equality between the population and the sample.
Thus, the null hypothesis will be
Option B) [tex]H_0: \text{Mean} = 2.5[/tex]
A negative linear relationship implies that larger values of one variable will result in smaller values in the second variable. T/F
Answer:
True
Step-by-step explanation:
The negative linear relationship means that there is inverse relationship between two variables. It means that if the independent variable increases the dependent variable decreases and if the independent decreases the dependent variable increases. It means that due to larger values of independent variable there occurs the smaller values for dependent variable.
Data were collected on a sample of 500 business students and the mean number of course credits taken was 18. How many course credits did the total sample take collectively?
Answer:
Collectively, the total sample took 9000 course credits.
Step-by-step explanation:
The mean number of course credits taken is the total number of credits which the sample took collectively divided by the size of sample. Mathematically
[tex]M = \frac{T}{N}[/tex]
In which
M is the mean number of course credits taken
T is the total number of course credits taken
N is the size of the sample.
In this problem, we have that:
[tex]M = 18, N = 500[/tex]
We have to find T. So
[tex]M = \frac{T}{N}[/tex]
[tex]18 = \frac{T}{500}[/tex]
[tex]T = 500*18[/tex]
[tex]T = 9000[/tex]
Collectively, the total sample took 9000 course credits.
Find all values of x such that (4, x, −6) and (2, x, x) are orthogonal. (Enter your answers as a comma-separated list.)
Answer:
The values of x that makes these vectors orthogonal are x = 2 and x = 4.
Step-by-step explanation:
Orthogonal vectors
Suppose we have two vectors:
[tex]v_{1} = (a,b,c)[/tex]
[tex]v_{2} = (d,e,f)[/tex]
Their dot product is:
[tex](a,b,c).(d,e,f) = ad + be + cf[/tex]
They are ortogonal is their dot product is 0.
Solving quadratic equations:
To solve this problem, we are going to need tosolve a quadratic equation.
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = (x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}[/tex]
[tex]\bigtriangleup = b^{2} - 4a[/tex]
Find all values of x such that (4, x, −6) and (2, x, x) are orthogonal.
[tex](4,x,-6)(2,x,x) = 8 + x^{2} - 6x[/tex]
These vectors are going to be orthogonal if:
[tex]x^{2} -6x + 8 = 0[/tex]
This is a quadratic equation, in which [tex]a = 1, b = -6, c = 8[/tex]. So
[tex]\bigtriangleup = 6^{2} - 4*1*8 = 4[/tex]
[tex]x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4[/tex]
[tex]x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2[/tex]
The values of x that makes these vectors orthogonal are x = 2 and x = 4.
The values of x that make the vectors (4, x, −6) and (2, x, x) orthogonal are x = 2 and x = 4, determined by setting their dot product to zero and factoring the resulting quadratic equation.
Explanation:To find all values of x such that the vectors (4, x, −6) and (2, x, x) are orthogonal, we need to perform the dot product of the vectors and set it equal to zero. Two vectors are orthogonal if their dot product is zero.
The dot product is calculated as follows:
(4)(2) + (x)(x) + (−6)(x) = 08 + x² − 6x = 0x² − 6x + 8 = 0Next, we factor the quadratic equation:
(x − 2)(x − 4) = 0Hence, the two values of x that make the vectors orthogonal are x = 2 and x = 4.
Given f(x)=x2, after performing the following transformations: shift upward 60 units and shift 29 units to the right, the new function g(x)
Answer:
[tex] y=(x-29)^2 +60[/tex]
Step-by-step explanation:
For this case we have the original function [tex] y =x^2[/tex]
So let's do the transformations one by one.
The general expression for a parabola like the formula given is:
[tex] y = (x-h)^2 +k[/tex]
If we want to do a shift on the vertical axis we need to modify the value of k, since we want 60 units upward the value of k =60, and then the formula after the first transformation would be:
[tex] y = x^2 + 60[/tex]
For the other part related to the movement on the x axis 29 units to the right we need to modify the value of h in the general expression , since is a translation to the right the value of h = 29 and if we replace we got:
[tex] y=(x-29)^2 +60[/tex]
And that would be our final expression after the transformations on the y and x axis.
On the figure attached we see the original function in red, the blue function represent the shift upward and the green one the two tranformations at the sam time to check that we did the procedure right.
An admiral, captain, and commander, all different, are to be chosen from a group of 10 Starfleet officers. How many different choices of officers are possible if (a) there are no restrictions? (b) Worf and Troi will not serve together?
Answer:
720 different choices of officers are possible if there are no restrictions.
The number of ways in which Worf and Troi will not serve together is 672.
Step-by-step explanation:
Consider the provided information.
We have 3 post admiral, captain, and commander, and 10 Starfleet officers.
Part (A) there are no restrictions?
We need to select 3 people out of 10. And these 3 people can again rearranged into different rank.
Thus, the number of ways are: [tex](^{10}C_3)3!=\left(\dfrac{10!}{3!7!}\right)3!=720[/tex]
Hence, 720 different choices of officers are possible if there are no restrictions.
Part (B) Worf and Troi will not serve together?
Subtract those cases in which both of them are selected from total number of ways.
If both of them selected then we need to select only 1 person out of 8. And further they can rearranged into 3 different rank.
Thus, the number of ways are: [tex]720-(^{8}C_1)3!=720-8\times3!=672[/tex]
Hence, the number of ways in which Worf and Troi will not serve together is 672.
A tank in the shape of a right rectangular prism has a height of 5 feet, width of 3 feet, and length of 2 feet. It is full of a liquid weighing 50 pounds per cubic foot. How much work does it take to pump all of the liquid out of the top of the tank
Answer:
Step-by-step explanation:
Given
height of tank [tex]h=5\ ft[/tex]
Width of tank [tex]w=3\ ft[/tex]
length of tank [tex]L=2\ ft[/tex]
suppose a layer of water at height h of thickness dh from bottom needed to be pump out
So distance moved by this layer to come out of tank is [tex]\Delta h=5-h[/tex]
weight density of water [tex]\rho =50\ pounds/ft[/tex]
Force required to hold this layer up [tex]F_s=2\times 3\times \Delta h\times 50=300\Delta h[/tex]
Work done to remove the water
[tex]W=\int_{0}^{5}300\Delta hdh[/tex]
[tex]W=\int_{0}^{5}300\left ( 5-h\right )dh[/tex]
[tex]W=3750\ Pound-ft[/tex]
The work does it take to pump all of the liquid out of the top of the tank is 3750-pound feet.
Given that
A tank in the shape of a right rectangular prism has a height of 5 feet, width of 3 feet, and length of 2 feet.
It is full of a liquid weighing 50 pounds per cubic foot.
We have to determineHow much work does it take to pump all of the liquid out of the top of the tank?
According to the questionA tank in the shape of a right rectangular prism has a height of 5 feet, width of 3 feet, and length of 2 feet.
The distance moved by this layer to come out of the tank is;
[tex]\rm \triangle h = 5-h[/tex]
The force required to hold this layer up is;
[tex]\rm Force = \triangle Height \times Width \times length \times liquid \ weighing\\ \\ Force = 2 \times 3 \times (5-h) \times 50\\ \\ Force = 300 (5-h)[/tex]
The work does it take to pump all of the liquid out of the top of the tank is calculated by;
[tex]\rm Work = \int\limits^5_0 {300(5-h)} \, dh\\ \\ Work = 300(5\int\limits^5_0 {} \, dh - \int\limits^5_0 {h} \, dh) \\ \\ Work = 300(5[h]^5_0- [\dfrac{h^2}{2}]^5_0)\\ \\ Work = 300(5(5-0)-\dfrac{5^2}{2}-\dfrac{0^2}{2})\\ \\ Work = 300(25-\dfrac{25}{2})\\ \\ Work = 300\times \dfrac{50-25}{2}\\ \\ Work = 300 \times \dfrac{25}{2}\\ \\ Work = 300 \times (12.5)\\ \\ Work = 3750 \ pounds \ feet[/tex]
Hence, The work does it take to pump all of the liquid out of the top of the tank is 3750-pound feet.
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Bryan has a balance of $320 in his checking account. He spends $15 each week for
next eight weeks. If you were to graph the linear relationship, what would be the
numerical value of the slope? What would the slope mean?
Answer:
The numerical value of the slope is 15, and it is by how much his balance decreases each week.
Step-by-step explanation:
Bryan's balance y after x weeks is given by a first degree function in the following format:
[tex]y = a - bx[/tex]
In which a is his initial balance and b is how much he spends a week. The slope is b., that is, how much is deducted from his balance each week.
In this problem, we have that:
Bryan has a balance of $320 in his checking account. This means that [tex]a = 320[/tex].
He spends $15 each week for next eight weeks. This means that [tex]b = 15[/tex]
So the equation for Bryan's balance is
[tex]y = 320 - 15x[/tex]
The numerical value of the slope is 15, and it is by how much his balance decreases each week.
The table below shows a
proportional relationship. Fill
in the missing values.
Servings
12
4
16
18
the last one it wouldnt fit plesse I need help will mark brainest ounces 21 ? ? ?
Answer:the missing values are 7, 28 and 31.5
Step-by-step explanation:
What makes the relationship between two variables to be proportional is the constant of proportionality. With the constant of proportionality determined, if there is a change in the value of one variable, the corresponding change in value of the other variable is easily determined.
The variables given are servings and ounces.
Let the missing values be represented by a,b and c.
Therefore,
21/12 = a/4
a = 1.75 × 4
a = 7
21/12 = b/16
b = 1.75 × 16
b = 28
21/12 = c/18
c = 1.75 × 18
c = 31.5
(a) identify the independent variable and the dependent variable of each equation (use 't' for the independent variable if an independent variable is not given explicitly): (b) give the order of each differential equation (enter '1' for first order. '2' for second order and so on: do not include the quotes); and (C) state whether the equation is linear or nonlinear If your answer to (C) is nonlinear, make sure that you can explain why this is true
Answer:
You didn't give the differential equations, but I'll explain how to identify the independent variable, dependent variable, how to know the order, linearity, and nonlinearity of a differential equation.
Step-by-step explanation:
DIFFERENTIAL EQUATION
This is any equation that involves differential coefficients. It is a relationship between an independent variable, x, a dependent variable, y, and one or more derivatives of y with respect to x.
Examples
(1) xd²y/dx² + 7dy/dx = 0
(2) y²dy/dx + 2x = 0
(3) xd³y/dx³ = y½ + 1
(4) 2xy'' - 3y' + 5y = 0
(5) (y''')² + 30xy = 0
Note that the dependent variable is always the numeratior, and the independent, denominator, in a different coefficient. In the case of our examples, y is the dependent variable, and x is the independent.
Example (4) is another way of writing a differential coefficient, y' (read as y-prime) is the same as dy/dx (read as dee-y dee-x). In some cases when the independent variable is time t, it is written as ÿ, which is the same as d²y/dt² (read as dee-two-y dee-t-squared)
ORDER
This is the order of the highest derivative in a differential equation. You need not consider other derivatives, just the highest.
In the examples, the orders are
(1) two
(2) one
(3) three
(4) two
(5) three
LINEAR DIFFERENTIAL EQUATION
This is the kind of differential equation in which the functions of the dependent variable are linear. There are no powers of the dependent variable and/or its derivatives, there are no products of the dependent variable and its derivative, there are no functions of the dependent variable like cos, sin, exp, etc.
NONLINEAR DIFFERENTIAL EQUATION
If any condition for linearity is not met, then it is nonlinear.
(1) Linear
(2) Nonlinear because y is the dependent variable, and y² is nonlinear, and even still, it multiplies a derivative.
(3) Nonlinear because y½ is nonlinear
(4) Linear
(5) Nonlinear because (y''')² in nonlinear.
Understanding this, you can determine the order, linearity or nonlinearity of any differential equation. Cheers!
Equations 1 and 3 are nonlinear due to their respective terms, while Equation 2 is linear. The orders are first for Equations 1 and 2, and second for Equation 3.
Let's analyse each of the given differential equations step by step.
Equation 1: y' = y - x²
Independent Variable: xEquation 2: xy' = 2y
Independent Variable: xEquation 3: x'' + 5x = e-x
Independent Variable: t (since no specific variable is given, it's common practice to use 't')Dependent Variable: xOrder: 2 (Second order, because x'' involves the second derivative of x)Linearity: This equation is nonlinear because the term e-x is an exponential nonlinear function of x.Thus,
1. [tex]\( y' = y - x^2 \)[/tex]
(a) Independent variable: x, Dependent variable: y
(b) First order
(c) Nonlinear because of the term -x².
2. xy' = 2y
(a) Independent variable: x, Dependent variable: y
(b) First order
(c) Nonlinear because of the product xy.
3. [tex]\( x'' + 5x = e^{-x} \)[/tex]
(a) Independent variable: t (not explicitly given), Dependent variable: x
(b) Second order
(c) Linear because it has no products or powers of x other than x and x''.
Complete question: In problems below
(a) identify the independent variable and the dependent variable of each equation (use 't' for the independent variable if an independent variable is not given explicitly): (b) give the order of each differential equation (enter '1' for first order. '2' for second order and so on: do not include the quotes); and (C) state whether the equation is linear or nonlinear If your answer to (C) is nonlinear, make sure that you can explain why this is true
Equation:
1. y' = y-x²
2. xy' = 2y
3. [tex]\( x'' + 5x = e^{-x} \)[/tex]
People's scores on a test of extraversion are likely to be most strongly correlated with the number of social conversations they initiate during the course of a single a hour. b semester. c month. d day. e week.
Answer:
MARK ME BRAINIEST OR ILL BREAK MY KEYBOARD
Step-by-step explanation:
BBBBBBBBBBBBB
In an albatross colony the wingspan of the birds is approximately normally distributed with standard deviation 0.43 metres. In this colony, 67% of the birds have wingspan less than 3.21 metres. Find the average wingspan of the birds in this colony. Give your answer as a decimal, rounded to two decimal places. Do not include the unit.
To find the average wingspan, the z-score for 67% of the normal distribution was found to be 0.44. Using the formula with the given standard deviation and wingspan less than 3.21 meters, the average wingspan was calculated to be approximately 3.02 meters.
Explanation:In order to find the average wingspan of the birds in the albatross colony given the standard deviation of 0.43 meters and that 67% of the birds have a wingspan less than 3.21 meters, we apply concepts from normal distribution.
From the properties of the normal distribution, we know that 67% corresponds to an area under the curve to the left of the mean. Using the standard normal distribution table (z-table), we can find the z-score that corresponds to 0.67 (67%). The z-score close to this area under the curve is approximately 0.44.
The formula to convert a z-score to an actual score is given as:
X = μ + (z × σ)
Where:
X is the raw scoreμ is the mean (average)z is the z-score corresponding to the desired cumulative probabilityσ is the standard deviation.We are given X (3.21), z (0.44), and σ (0.43), and we need to find the mean μ.
Substituting the known values into the formula, we get:
3.21 = μ + (0.44 × 0.43)
Now we solve for μ:
3.21 = μ + 0.1892
μ = 3.21 - 0.1892
μ ≈ 3.02
So, the average wingspan of the albatrosses is approximately 3.02 meters rounded to two decimal places.
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What are the latitude and longitude coordinates of the entrance to the Mount Rushmore parking area?Latitude: 43.8753972, Longitude: -103.4523083
Answer:
The answer is already in the question. The coordinates of the entrance to the Mount Rushmore parking area are given by latitude 43.8753972 and longitude -103.4523083.
Step-by-step explanation:
I believe the person asking the question wants some other detail that s/he did not state explicitly.
Final answer:
The coordinates for the entrance to the Mount Rushmore parking area are Latitude: 43.8753972 and Longitude: -103.4523083, used for precise geographical positioning on Earth.
Explanation:
The latitude and longitude coordinates of the entrance to the Mount Rushmore parking area are as follows: Latitude: 43.8753972, Longitude: -103.4523083. These coordinates provide precise location details required to pin-point specific places on Earth using geographic positioning systems.
Latitude and longitude are measured in degrees, minutes, and seconds, with latitude representing the distance north or south of the equator and longitude representing the distance east or west of the Prime Meridian. When you search for landmarks such as the Washington Monument or use GPS coordinates to find a specific location, such as the Grand Canyon, you are utilizing these two fundamental geographic references to navigate and observe various parts of the world.
Determine whether the underlined value is a parameter or a statistic. The average age of men who had walked on the moon was 39 years, 11 months, 15 days.
Is the value a parameter or a statistic?
A. The value is a parameter because the men who had walked on the moon are a population.
B. The value is a parameter because the men who had walked on the moon are a sample.
C. The value is a statistic because the men who had walked on the moon are a sample.
D. The value is a statistic because the men who had walked on the moon are a population.
Answer:
A. The value is a parameter because the men who had walked on the moon are a population.
Correct option the value reported represent the mean for all the individuals in the population of interest and for this reason represent a parameter.
Step-by-step explanation:
For this case we know that the average age of men who had walked on the moon was 39 years, 11 months, 15 days.
So then we need to assume that this value was calculated from the average of all the mean who walked on the moon, so then we have a population represented by a parameter.
And let's analyze one by one the possible options given:
A. The value is a parameter because the men who had walked on the moon are a population.
Correct option the value reported represent the mean for all the individuals in the population of interest and for this reason represent a parameter.
B. The value is a parameter because the men who had walked on the moon are a sample.
The value represent a parameter but the reason is not because represent a sample, is a parameter because represent the population of interest.
C. The value is a statistic because the men who had walked on the moon are a sample.
False the men who had walked on the moon are a population since they know the information about the men who walked on the moon and not represent a sample for this case.
D. The value is a statistic because the men who had walked on the moon are a population.
False the men who had walked on the moon are a population since they know the information about the men who walked on the moon, and if is a population then can't be a statistic.
The average age of men who had walked on the moon represents a parameter because it describes a characteristic of a specific population: all men who have walked on the moon.
Explanation:In the context of statistical study, a parameter refers to a characteristic of a population, while a statistic is a measure that describes a sample. In this case, the group referred to is 'all men who had walked on the moon,' which is a population, not a sample, because it includes every individual of interest that fits a specific criteria. Therefore, the average age of men who walked on the moon is a parameter, not a statistic. So, the correct response is:
A. The value is a parameter because the men who had walked on the moon are a population.
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Let z = ln(x 2 + y), x = ret . and y = ter . Use the Chain Rule to compute ∂z ∂r and ∂z ∂t at the point where (r, t) = (1, 2).\
By the chain rule,
[tex]\dfrac{\partial z}{\partial u}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial u}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial u}[/tex]
where [tex]u\in\{r,t\}[/tex].
We have component partial derivatives
[tex]\dfrac{\partial z}{\partial x}=\dfrac{2x}{x^2+y}=\dfrac{2re^t}{r^2e^{2t}+te^r}[/tex]
[tex]\dfrac{\partial z}{\partial y}=\dfrac1{x^2+y}=\dfrac1{r^2e^{2t}+te^r}[/tex]
[tex]\dfrac{\partial x}{\partial r}=e^t[/tex]
[tex]\dfrac{\partial x}{\partial t}=re^t[/tex]
[tex]\dfrac{\partial y}{\partial r}=te^r[/tex]
[tex]\dfrac{\partial y}{\partial t}=e^r[/tex]
Putting the appropriate pieces together and setting [tex](r,t)=(1,2)[/tex], we get
[tex]\dfrac{\partial z}{\partial r}(1,2)=\dfrac{2e^3+2}{e^3+2}[/tex]
[tex]\dfrac{\partial z}{\partial t}(1,2)=\dfrac{2e^3+1}{e^3+2}[/tex]
Customers filter into a record shop at an average of 1 per minute (exponential interarrivals) where the service rate is 15 per hour (exponential service times). What is the minimum number of servers needed to keep the average time in the system under 6 minutes?
A minimum of 10 servers is needed to keep the average time in the system under 6 minutes.
What is the utilization factor?The utilization factor is the ratio of the power station's maximum demand to its rated capacity. The time that equipment is in use./ The total time that it could be in use.
Given, In a record store with a service rate of 15 per hour, customers typically enter at a rate of 1 per minute (exponential interarrivals) (exponential service times).
Customers Per Minute into record shop = 1 per minute
Per Hour = 1 * 60 = 60
Number of Customers > Per Hour/(Server)
6 > 60/ server
server > 10
Therefore, as per the utilization factor, a minimum of 10 servers should be installed to keep the average time under 6 minutes.
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The given scenario can be modeled as a queuing system, where the arrival rate (\(\lambda\)) and service rate (\(\mu\)) are given.
From the information provided:
- The arrival rate, \(\lambda\), is 1 customer per minute, hence \(\lambda = 1\).
- The service rate, \(\mu\), is 15 customers per hour. Since we are working with minutes, we need to convert this to minutes. There are 60 minutes in an hour, so \( \mu = \frac{15}{60} = 0.25 \) customers per minute.
The goal is to keep the average time in the system, \( W \), under 6 minutes. The average time in the system for a M/M/c queue (which is the kind we're dealing with since both arrival and service rates are exponentially distributed) can be calculated using the formula for the average time in a system with \(c\) servers:
\[ W = \frac{W_q + 1}{\mu} \]
where:
- \(W_q\) is the average time a customer spends waiting in the queue.
- \(\mu\) is the service rate per server.
- The term \( \frac{1}{\mu} \) is the average service time.
The queue time \(W_q\) depends on the number of servers \(c\) and the utilization factor \(\rho = \frac{\lambda}{c\mu}\). The queue time increases with the utilization factor. The formula for \( W_q \) in an M/M/c queue is complex as it involves Erlang B formulas and iterative methods to solve for different values of \(c\).
However, for the practical purposes of this problem, we can use the approximation for \( W \) without explicitly calculating \( W_q \) as:
\[ W = \frac{1}{\mu - \lambda} \]
provided that this system is stable, which occurs only if \( \lambda < c \cdot \mu \).
We need to find the minimum number of servers \( c \) such that the average time in the system \( W \) is less than 6 minutes:
\[ W < 6 \]
Using the approximate formula:
\[ \frac{1}{c\mu - \lambda} < 6 \]
Therefore:
\[ c\mu - \lambda > \frac{1}{6} \]
Solving for the number of servers \( c \):
\[ c > \frac{\lambda + \frac{1}{6}}{\mu} \]
Plugging in the values of \(\lambda\) and \(\mu\):
\[ c > \frac{1 + \frac{1}{6}}{0.25} \]
\[ c > \frac{\frac{6}{6} + \frac{1}{6}}{{0.25}} \]
\[ c > \frac{\frac{7}{6}}{0.25} \]
\[ c > \frac{7}{6} \cdot \frac{1}{0.25} \]
\[ c > \frac{7}{6} \cdot 4 \]
\[ c > \frac{7 \cdot 2}{3} \]
\[ c > \frac{14}{3} \]
As we cannot have a fraction of a server, we need to round up to the nearest whole number:
\[ c > 4.67 \]
So we need a minimum of 5 servers to keep the average time in the system under 6 minutes.
A communications circuit is known to have an availability of 0.99 (that is, 99% of the time, the circuit is operational). A total of n such circuits are going to be set up by the FAA between San Francisco and Los Angeles in such a way that the circuits will fail indepen- dently of each other. How many such parallel circuits must be set up to attain an overall availabililty of 0.99999
Answer:
Assume that for the communication to be available means that at least one of the [tex]n[/tex] circuits is operational. It would take at least 3 circuits to achieve a [tex]0.99999[/tex] overall availability.
Step-by-step explanation:
The probability that one circuit is not working is [tex]1 - 0.99 = 0.01[/tex].
Since the circuits here are all independent of each other, the probability that none of them is working would be [tex]\displaystyle \underbrace{0.01 \times 0.01 \times \cdots \times 0.01}_{\text{$n$ times}}[/tex]. That's the same as [tex]0.01^n[/tex].
The event that at least one of the [tex]n[/tex] circuits is working is the complement of the event that none of them is working. To find the probability that at least one of the [tex]n[/tex] circuits is working, simply subtract the probability that none of the circuit is working from one. That is:
[tex]\begin{aligned}&P(\text{At least one working}) \cr &= 1 - P(\text{None is working}) \cr &= 1- 0.01^n\end{aligned}[/tex].
The question requests that
[tex]P(\text{At least one working}) \ge 0.99999[/tex].
In other words,
[tex]1- 0.01^n \ge 0.99999[/tex].
[tex]0.01^n \le 1 - 0.99999 = 0.000001 = 10^{-6}[/tex].
Note that [tex]0.01 = 10^{-2}[/tex]. Hence, the inequality becomes
[tex]\left(10^{-2}\right)^n \le 10^{-6}[/tex].
[tex]10^{-2\,n} \le 10^{-6}[/tex]
Take the natural log of both sides of the equation:
[tex]\ln\left(10^{-2\, n}\right) \le \ln \left(10^{-6}\right)[/tex].
[tex](-2\, n)\ln\left(10\right) \le (-6) \ln\left(10\right)[/tex].
[tex]10 > 1[/tex], hence [tex]\ln(10) > 0[/tex]. Divide both sides by [tex]\ln(10)[/tex]:
[tex]-2\,n \le -6[/tex].
[tex]n \ge 3[/tex].
In other words, at least three parallel circuits must be set up to achieve that availability.
A 10-lb block sits on a plane that is inclined at 60◦above the horizontal. The heightof the plane decreases from left to right. The gravitational force acting on the blockis~F.Make an illustration and work with 2-D vectors to answer the following:
What is a unit vector that points down the plane (parallel to the plane)?
Answer:
It is shown in the pic.
Step-by-step explanation:
We can call this unit vector u, that points down the plane (parallel to the plane) and v is an unit vector that points in a direction that is normal to the plane.
Find the equations that describe the circle of radius 2 centered at (4, 7, 6) that is parallel to the xy-plane. (Enter your answers as a comma-separated list of equations.)
Answer:
[tex](x-4)^2+(y-7)^2=4[/tex]
z=6
Step-by-step explanation:
The equation of a circle is satisfied by every point on it. The equation of a circle of radius r and point (h,k,l) parallel to the xy-plane is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
we can just substitute values into the equation:
[tex](x-4)^2+(y-7)^2=r^2[/tex] where z=6
The radius is 2. Therefore:
[tex](x-4)^2+(y-7)^2=4[/tex]
Final answer:
The equations describing the circle with a radius of 2 that is centered at (4, 7, 6) and parallel to the xy-plane are (x - 4)² + (y - 7)² = 4 and z = 6.
Explanation:
The equation that describes a circle of radius 2 centered at (4, 7, 6) that is parallel to the xy-plane can be found using the general equation of a circle in three dimensions, considering that the circle lies in a plane parallel to the xy-plane, hence the z-coordinate will remain constant. The standard equation for a circle in two dimensions is (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is its radius.
For a circle of radius 2, the equation becomes (x - 4)² + (y - 7)² = 2². Since the circle is parallel to the xy-plane and the center has a z-coordinate of 6, the equation does not change with respect to z, remaining constant at z = 6. Therefore, the complete set of equations describing the circle are (x - 4)² + (y - 7)² = 4 and z = 6.
Find the sample standard deviation of the following data set, using the statistical functions on your calculator. 508 657 214 958 765 449 338 497
Answer:
The sample standard deviation for given data is 222.69
Step-by-step explanation:
We are given the following data set:
508, 657, 214, 958, 765, 449, 338, 497
Formula:
[tex]\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}[/tex]
where [tex]x_i[/tex] are data points, [tex]\bar{x}[/tex] is the mean and n is the number of observations.
[tex]Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}[/tex]
[tex]Mean =\displaystyle\frac{4386}{8} = 548.25[/tex]
Sum of squares of differences =
1620.0625 + 11826.5625 + 111723.0625 + 167895.0625 + 46980.5625 + 9850.5625 + 44205.0625 + 2626.5625 = 396727.5
[tex]\text{Sample standard Deviation} = \sqrt{\dfrac{396727.5}{7}} =222.69[/tex]
The sample standard deviation for given data is 222.69
To calculate the sample standard deviation using a calculator, enter the data points in statistical mode, use the function labeled as 'sx' or 'σx' for the sample, not the population, then calculate and round to the nearest tenth. The symbol for sample standard deviation is typically 's' or 'sx' on most calculators.
Explanation:To find the sample standard deviation of the dataset {508, 657, 214, 958, 765, 449, 338, 497}, you will need to use your calculator's statistical functions. Use the statistical mode in your calculator that corresponds to Equation 4.1.1 for calculating the standard deviation of a sample, not the population. Here are the typical steps for calculating it:
Enter the data points into your calculator's statistical function. This is often done by pressing a "STAT" or "DATA" key, then entering each value followed by the "Enter" or "+=" key.After inputting all data points, use the calculator function for the sample standard deviation, commonly labeled as sx or σx, depending on your model of calculator.Calculate the sample standard deviation, and round the result to the nearest tenth as per the instruction.The symbol s or sx represents the sample standard deviation on most calculators, while σ and σx are typically used for a population's standard deviation (which is not needed in this question).
As an example, if your calculated variance is .5125, the standard deviation would be the square root of the variance: S = √.5125 = .715891, and when rounded to two decimal places, s = .72. Always consult your calculator's manual for specific instructions, as they can vary between models.
One tire manufacturer claims that his tires last an average of 42,000 miles with a standard deviation of 7800 miles. A random sample of 100 of his tires is taken. What is the probability that the average of these 100 tires will last greater than 41,000 miles?
Answer:
89.97% probability that the average of these 100 tires will last greater than 41,000 miles.
Step-by-step explanation:
The solve this problem, it is important to know the Normal Probability distribution and the Central Limit Theorem.
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], a large sample size can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]
In this problem, we have that:
[tex]\mu = 42000, \sigma = 7800, n = 100, s = \frac{7800}{\sqrt{100}} = 780[/tex]
What is the probability that the average of these 100 tires will last greater than 41,000 miles?
This is 1 subtracted by the pvalue of Z when X = 41000.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem, we use s instead of [tex]\sigma[/tex].
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{41000 - 42000}{780}[/tex]
[tex]Z = -1.28[/tex]
[tex]Z = -1.28[/tex] has a pvalue of 0.1003.
So there is a 1-0.1003 = 0.8997 = 89.97% probability that the average of these 100 tires will last greater than 41,000 miles.
the ration of 28 hours to 42 hours is
Answer:
2:3
Step-by-step explanation:
the ratio of 28 hours to 42 hours is 28:42
28/42
7 divides both the numerator and denominator into small terms
4/6
2 divides both the numerator and denominator into small terms
2/3 = 2:3
If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11? y = StartFraction 5 Over 18 EndFraction (11) y = StartFraction 18 Over 5 EndFraction (11) y = StartFraction (18) (5) Over 11 EndFraction y = StartFraction 11 Over (18) (5) EndFraction
Answer: (18/5) * 11
Step-by-step explanation:
In equations of proportion, to proceed, we need to determine the constant of proportion, let's denote as "k"
Since y ~ x
Means y=kx.
To determine the value of k, we input initial values of y and x.
Initial value of y = 18
Initial value of x = 5
The equation becomes :
18 = 5k
k = 18/5.
Now, If given the value of x as 11,to determine the value of y we go back to the equation.
y= kx
y = 18/5 * 11.
The correct expression to find the value of y when x is 11 is [tex]\( y = \frac{18}{5} \times 11 \)[/tex].
Given that y varies directly as x, we can express this relationship using the formula [tex]\( y = kx \)[/tex], where k is the constant of proportionality. To find the value of k, we use the given values of y and x when [tex]\( y = 18 \)[/tex] and [tex]\( x = 5 \)[/tex]. Thus, we have:
[tex]\[ k = \frac{y}{x} = \frac{18}{5} \][/tex]
Now, we want to find the value of y when [tex]\( x = 11 \)[/tex]. Using the direct variation formula with our calculated k:
[tex]\[ y = kx = \frac{18}{5} \times 11 \][/tex]
This expression will give us the value of y when x is 11. The other options provided are incorrect because they either divide by 11 or use the inverse relationship, which does not apply in the case of direct variation.
Please help!!! I suck at math and this just makes my brain stop working
Answer:
We have 4.25 quarts of gasoline.
4 quarts = 1 gallon
.25 quarts = one sixteenth of a gallon.
1 / 16 = 0.0625 gallons
So, we have 1.0625 gallons of gasoline
We need 2.4 fluid ounces for every gallon of gasoline.
So, we need 1.0625 times 2.4 ounces per gallon which equals
2.55 fluid ounces.
Step-by-step explanation:
Answer:you should add 2.52 fluid ounce of oil
Step-by-step explanation:
You have to mix the oil and gas together in a specific ratio of 2.4 fluid ounce for every gallon of gasoline.
Since you have 4.2 quarts of gas, the first step is to 4.2 quarts of gas to gallons.
1 US liquid quart = 0.25 US liquid gallon.
Therefore, 4.2 quarts of gas would be
0.25 × 4.2 = 1.05 gallon of gasoline.
Therefore,
Since you use 2.4 fluid ounce of oil for every gallon of gasoline, then the amount of oil that you would add to 1.05 gallon of gasoline would be
2.4 × 1.05 = 2.52
Solve the system of equations. x1 + x2 + x3 = 7 x1 - x2 + 2x3 = 7 5x1 + x2 + x3 = 11
Answer:
x1 =1
x2 =2
x3 =4
Step-by-step explanation:
Given is a systems of equations in 3 variables.
No of equations given = 3
[tex]x1 + x2 + x3 = 7 ... I\\x1 - x2 + 2x3 = 7 ... II\\5x1 + x2 + x3 = 11 ... III[/tex]
subtract equation 1 form equation 3
We get
[tex]4x1=4\\x1=1[/tex]
Substitute this value in 2 and 3
[tex]x2-2x3 = -6 ... iv\\x2+x3 =6 ... v[/tex]
subtract iv from v
3x3 = 12
x3=4
Substitute in v
x2 =2
solution is
x1 =1
x2 =2
x3 =4
In manufacturing, convenience sampling could be used to determine if the machines are operating correctly. Which of the following best describes this type of sampling?
Every 10th product in the line is selected
Samples are randomly selected throughout the day
Products are put into groups and all are included from several randomly selected groups
Products are put into groups and some are randomly selected from each group
Answer:
Every 10th product in the line is selected
Step-by-step explanation:
Convenience sampling also available sampling, or nearest in reach sampling.
it is a type of non-probability sampling that involves the sample being drawn from a population that is in reach or that is easily at hand.
example. A questionnaire being distributed to people met in a mall.
for the manufacturing company in question, the first 10 product in line were the first set of product the machine will produce (at hand).
it is normally use to test run the operation of the machine.
Convenience sampling in manufacturing is best described as selecting every 10th product in the line for testing. It is a simple, quick, and cost-effective way to identify potential issues.
Explanation:In the context of manufacturing, convenience sampling represents a type of sampling where samples are chosen because they are readily available or easy to obtain. In the provided choice list, the best description of convenience sampling is 'Every 10th product in the line is selected'. This method is chosen for its simplicity and speed. While it may not provide a comprehensive result since it won't cover all the various different scenarios, it is a cost-effective and time-efficient way of identifying potential issues in machine operations.
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Which equation best represent Fallon’s earning in term of Donald’s earnings?
Answer:
C. y=x+7
Step-by-step explanation:
If you add 7 to the values on the left, you'll get the values on the right.
Answer: I think c is the answer
Step-by-step explanation:
The sum of three consecutive integers is 237. Find the integers.
Answer:
78,79,80
Step-by-step explanation:
use algebraic values. in this case, x, x+1, x+2
Final answer:
The three consecutive integers that sum up to 237 are 78, 79, and 80. To find these, an algebraic equation is set up and solved step by step to identify the smallest integer followed by the next two consecutive ones.
Explanation:
The sum of three consecutive integers is 237. To find these integers, you can set up an algebraic expression for the problem. Let the smallest integer be x. Then the next two consecutive integers would be x + 1 and x + 2. The sum can be written as:
x + (x + 1) + (x + 2) = 237
Combine like terms to solve for x:
3x + 3 = 237
3x = 234
x = 78
Now we have the smallest integer. The next two consecutive integers are:
x + 1 = 79
x + 2 = 80
Therefore, the three consecutive integers are 78, 79, and 80.