Answer:
None of these
Explanation:
Using the dilution formula;
M1V1 = M2V2
where M1 is the initial concentration, V1 is the initial volume, M2 is the concentration attained while V2 is the new volume.
Therefore;
M2 = M1V1/V2
= (400 mL × 0.5) / 200 mL
= 1 M
Therefore, the resulting concentration is 1M
Thus, the correct answer is "none of these"
If 200 mL of water is evaporated from 400 mL of 0.5 M aqueous salt solution, the resulting concentration is 1.0 M.
What is evaporation?Evaporation is a type of vaporization that occurs on the surface of a liquid as it changes into the gas phase.
A 400 mL solution has a concentration of 0.5 M. After 200 mL of water evaporate, 200 mL of solution remain. We can calculate the final concentration using the following expression.
C1 . V1 = C2 . V2
C2 = C1 . V1 / V2
C2 = 0.5 M . 400 mL / 200 mL = 1.0 M
where,
C1 and V1 are the initial concentration and volume.C2 and V2 are the final concentration and volume.If 200 mL of water is evaporated from 400 mL of 0.5 M aqueous salt solution, the resulting concentration is 1.0 M.
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What is the expected change in the freezing point of water for a 0.015 m aqueous solution of alcl3?
Answer:
- 0.028 °C
Explanation:
The depression in freezing point of water (ΔTf) due to adding a solute to it is given by: ΔTf = Kf.m.Where, ΔTf is the depression in water freezing point (ΔTf = ???°C).
Kf is the molal freezing point depression constant of the solvent (Kf = 1.86 °C/m).
m is the molality of AlCl₃ (m = 0.015 m).
∴ ΔTf = Kf.m = (1.86 °C/m)(0.015 m) = 0.0279 °C ≅ 0.028 °C.
∵ ΔTf = freezing point of pure water - freezing point of the solution in presence of AlCl₃.
∴ freezing point of the solution in presence of AlCl₃ = freezing point of pure water - ΔTf = 0.0 °C - 0.028 °C = - 0.028 °C.
For the baeyer–villiger oxidation of cyclohexyl methyl ketone
just be postice and you will find the answer
How do you do this question?
Answer:
[tex]\boxed{\text{(D) 2 HCHO}_{2}}[/tex]
Explanation:
HCOOH + H₂O ⇌ H₃O⁺ + HCOO⁻
HCHO₂ is a weak acid. It dissociates only to a few percent, so there will be more HCHO₂ than H₃O⁺ present.
After H₂O, the most abundant species will be undissociated HCHO₂, so the answer will be either (B) or (D).
We can use an ICE table to organize the calculation of the pH.
HCOOH +H₂O ⇌ H₃O⁺ + HCOO⁻
I/mol·L⁻¹: 0.5 0 0
C/mol·L⁻¹: -x +x +x
E/mol·L⁻¹: 0.5 - x x x
[tex]K_{\text{a}} = \dfrac{\text{[H}_{3}\text{O}^{+}]\text{HCOO}^{-}]} {\text{[HCOOH]}} = 2 \times 10^{-4}\\\\\dfrac{x^{2}}{0.5-x} = 2 \times 10^{-4}[/tex]
Check for negligibility of x
[tex]\dfrac{ 0.5 }{2 \times 10^{-4}} = 2500 > 400.[/tex]
∴ x ≪ 0.5
[tex]\dfrac{x^{2}}{0.5} = 2 \times 10^{-4}[/tex]
x² = 0.5 × 2 × 10⁴ = 1 × 10⁻⁴
x = √(1 × 10⁻⁴) = 1 × 10⁻²
[H₃O⁺] = x mol·L⁻¹ = 1 × 10⁻² mol·L⁻¹
pH = -log[H₃O⁺] = -log(1 × 10⁻²) = 2
The correct answer is [tex]\boxed{\textbf{(D) 2 HCHO}_{2}}[/tex].
The muscles of the body are part of the muscular system but would not operate without the _______ system providing the impulses that cause the muscles to act.
Answer:
The nervous system
Explanation:
The nervous system send messages from the brain to the muscles to move.
The nervous system, particularly the somatic nervous system, provides the impulses that enable the muscular system to function, allowing for a wide range of both voluntary and involuntary movements.
Explanation:The muscles of the body, part of the muscular system, would not function without the nervous system providing the impulses that cause the muscles to act. This is particularly true for the skeletal muscles, which completely depend on signaling from the nervous system to work properly.
Our nervous system is divided into the somatic nervous system (SNS) and the autonomic nervous system, with the SNS responsible for the contraction of our skeletal muscles. This mechanism enables a wide range of voluntary and involuntary movements, like standing, walking, running, grasping items, and reflex actions; some of which happen automatically due to habit learning or procedural memory.
Responses can be voluntary, such as the contraction of skeletal muscles, or involuntary like the contraction of smooth muscles, regulation of cardiac muscles, and activation of glands.
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