I really need help but I keep getting my question taken down. Please help.

2. Draw a right triangle with side lengths of 3, 4, and 5 units (cm or inches – your choice). Make sure to label all parts including side lengths, vertices, and the right angle. You may insert an actual picture of your drawing below or upload the picture in the Unit 2 TGA submission area.

Step-by-step explanation:

[tex]0.031 \times 1000000 \\ = 31000 \\ moves \: 4 \: places \: to \: the \: right[/tex]

Answer:

angle AOC is what i think it is but please dont go on my word wait to see what other people say first sorry

Answer:

She needs to work 8 hours

Answer:

-2

Step-by-step explanation:

f(x) = –2x^2 + 5x – 4.

            A        B     C

Leading coefficient is always a which is -2x^2

Answer:

Option 1

Step-by-step explanation:

1/6 × 5/3

Step-by-step explanation:

[tex] \frac{1}{6} \div \frac{3}{5} [/tex]

[tex] \frac{1}{6} \times \frac{5}{3} [/tex]

a= 6,b=5,c=3 option A

Answer:

The length and the width of the rectangle are 11 units and 5 units

Step-by-step explanation:

Let us use the factorization to find the length and the width of the rectangle

∵ The trinomial is r² - 6r - 55

∵ r² = (r)(r)

∵ -55 = (-11)(5)

- Multiply r by -11 and r by 5, then add the products, the sum

   must be equal the middle term of the trinomial

∵ (r)(-11) = -11r

∵ (r)(5) = 5r

∵ -11r + 5r = -6r ⇒ the middle term of the trinomial

∴ r² - 6r - 55 = (r - 11)(r + 5)

- Equate each factor by 0 to find the value of r

∵ r - 11 = 0

- Add 11 to both sides

∴ r = 11

OR

∵ r + 5 = 0

- Subtract 5 from both sides

∴ r = -5 ⇒ rejected because no negative dimensions

∴ The length of the rectangle is 11 units

∵ The area of the rectangle is 55 units²

∵ Area of a rectangle = length × width

∴ 55 = 11 × width

- Divide both sides by 11

∴ 5 = width

∴ The width of the rectangle is 5 units

Answer:

4

Step-by-step explanation:

Answer:

2+2 = 4

Step-by-step explanation:

2 + 2 = 4...

Answer:

-0.259 or (√2 - √6) / 4

Step-by-step explanation:

Sin (195) using sum and difference formula.

Let's break the figure for convenience.

It becomes sin ( 135 + 60)

Invoking the sin formula we have

sin (A + B) = sin (A) cos (B) + cos (A) sin(B)

Where A = 135, B = 60

Therefore it becomes

sin(135) cos(60) + cos(135) sin (60)

From reference angle relationship we have:

(sin (45))cos (60) + cos (135) sin (60)

From trigonometric ratios, sin (45) = √2/2

Therefore, the equation becomes,

(√2/2) cos(60) + cos (135)sin (60)

(√2/2) (0.5) + cos (135) sin (60)

= (√2/2) (1/2) + ( - √2/2) ( √3/2)

Simplifying the equation

√2/4 + ( -√2/2) ( √3/2)

= √2/4 - √6/4

= (√2 - √6) / 4

OR

=( 1.414 - 2.449 ) / 4

= -1.035/4

= -0.25875

Answer:

V≈44602.24

Step-by-step explanation:

The volume of a sphere is  V=4/3πr^3. All you have to do is replace 22 for r and calculate it

Answer:

5575.28

Step by step explanation:

Answer:

Calvin withdraws $ 60 each week

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Calvin's account balance difference than 8 weeks ago = - $ 360

Weekly amount Calvin deposits = $ 15

Number of weeks to compare = 8

2. What was his average withdrawal  each week?

Let's calculate the weekly average withdrawal this way:

Weekly average withdrawal = [Calvin's account balance difference than 8 weeks ago - (Weekly amount Calvin deposits * Number of weeks to compare)]/Number of weeks to compare

Replacing with the values given:

Weekly average withdrawal = [-360 - (15 * 8)]/8

Weekly average withdrawal = -360 - 120 / 8

Weekly average withdrawal = -480 / 8

Weekly average withdrawal = -60

Calvin withdraws $ 60 each week

Answer:

reeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Step-by-step explanation:

Answer:  [tex](-9,-3)[/tex]

Step-by-step explanation:

Given the following system of equations:

[tex]\left \{ {{2x=-78-20y} \atop {-x=-51-20y}} \right.[/tex]

In order to solve the System of equations, you can use the Substitution method. The steps are:

1. You can solve for "x" from the second equation:

[tex]-x=-51-20y\\\\x=51+20y[/tex]

2. Substitute the equation obtained into the first original equation:

[tex]2x=-78-20y\\\\2(51+20y)=-78-20y[/tex]

3. Now you must solve for "y":

[tex]102+40y=-78-20y\\\\40y+20y=-78-102\\\\60y=-180\\\\y=\frac{-180}{60}\\\\y=-3[/tex]

4. Substitute the value of "y" into the equation [tex]x=51+20y[/tex] and evaluate:

[tex]x=51+20(-3)\\\\x=51-60\\\\x=-9[/tex]

Then, the solution is:

[tex](-9,-3)[/tex]

Answer:

Step-by-step explanation:

5+8(3+x)=5+24+8x=29+8x

x+3+5x=3+6x

5(z+4)+5(2-z)=5z+20+10-5z=30

Answer:

w = 10  

Step-by-step explanation

Answer:

53 = w        OR    10.6=w

 5

Step-by-step explanation:

-3(2w+5)+7w=5(w-11)

-6w-15+7w=5w-55

+6w    +6w

     -15+13=5w-55

     +15            +15

            13=5w-40

            +40    +40

            53=5w

             5     5

            53 = w        OR    10.6=w

              5

Hope that helps!! PLEASE GIVE ME BRAINLIEST!!!

Answer: No Solutions

Step-by-step explanation:

Define Variables:

​

May choose any letters.

\text{Let }d=

Let d=

\,\,\text{the number of dimes}

the number of dimes

\text{Let }q=

Let q=

\,\,\text{the number of quarters}

the number of quarters

\text{\textquotedblleft at most 25 coins"}\rightarrow \text{25 or fewer coins}

“at most 25 coins"→25 or fewer coins

Use a \le≤ symbol

Therefore the total number of coins, d+qd+q, must be less than or equal to 25:25:

d+q\le 25

d+q≤25

\text{\textquotedblleft a minimum of \$4.45"}\rightarrow \text{\$4.45 or more}

“a minimum of $4.45"→$4.45 or more

Use a \ge≥ symbol

One dime is worth $0.10, so dd dimes are worth 0.10d.0.10d. One quarter is worth $0.25, so qq quarters are worth 0.25q.0.25q. The total 0.10d+0.25q0.10d+0.25q must be greater than or equal to \$4.45:$4.45:

0.10d+0.25q\ge 4.45

0.10d+0.25q≥4.45

\text{Plug in }\color{green}{17}\text{ for }d\text{ and solve each inequality:}

Plug in 17 for d and solve each inequality:

Isabella has 17 dimes

\begin{aligned}d+q\le 25\hspace{10px}\text{and}\hspace{10px}&0.10d+0.25q\ge 4.45 \\ \color{green}{17}+q\le 25\hspace{10px}\text{and}\hspace{10px}&0.10\left(\color{green}{17}\right)+0.25q\ge 4.45 \\ q\le 8\hspace{10px}\text{and}\hspace{10px}&1.70+0.25q\ge 4.45 \\ \hspace{10px}&0.25q\ge 2.75 \\ \hspace{10px}&q\ge 11 \\ \end{aligned}

d+q≤25and

17+q≤25and

q≤8and

​

0.10d+0.25q≥4.45

0.10(17)+0.25q≥4.45

1.70+0.25q≥4.45

0.25q≥2.75

q≥11

​

\text{It is not possible to have }q\le 8\text{ AND to have }q\ge 11\text{.}

It is not possible to have q≤8 AND to have q≥11.

\text{Therefore there is NO SOLUTION}

Therefore there is NO SOLUTION

Isabella has to have a minimum of 11 but could have as many as 19 quarters to meet the criteria given in the question.

Isabella has 17 dimes which equates to $1.70 ($.10 x 17 = $1.70). We know she has to have a minimum of $4.45, so let's subtract the value of the dimes from this total ($4.45 - $1.70), resulting in $2.75. This remaining value must come from the quarters Isabella has. Since quarters are worth $0.25 each, we divide $2.75 by $0.25 to discover Isabella must have at least 11 quarters to reach the target dollar amount.

However, since Isabella could have 'at most 25 coins', we realize that she could also have potentially more quarters. We've established she has 17 dimes, so subtract that from the total of 25, resulting in 8. This means she could have in total between 11 (minimum requirement to reach the dollar amount) and 19 (maximum limitation placed by the coin total) quarters.

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Answer:

B

Step-by-step explanation:

STN is the alt exterior angle of angle 73 which means that it is congruent. STN is the vertical angle is MTQ which means that it is also equal to 73. Then you can use linear pair to find MTS. 180 - 73 which is 107.

Answer:

A

Step-by-step explanation:

Answer:

5741.11 m^2

Step-by-step explanation:

The formula for circumference is C=2(pi)r. Solve for r with the given info of the the circumference. r= 268.53/(2*3.14) r=42.76. The formula for area is (pi)r^2. Knowing r, substitute and solve.

Answer:

y = 1/5x

Graph Below:  

Answer:

Model B is wider car I think for the question which ones wider

Answer:

(x - 10)(x + 10)

Step-by-step explanation:

x² - 100 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

Thus

x² - 100

= x² - 10²

= (x - 10)(x + 10)

The expression x² - 100 can be factored using the difference of squares rule in algebra. The factors are (x - 10) and (x + 10).

The question asks for the factors of the polynomial expression x² – 100. This is a special kind of polynomial that can be factored using the difference of squares rule, a powerful tool in algebra which states that any expression in the form a² - b² can be rewritten as (a - b)(a + b).

In our case, a would be x (since x² is the first term) and b will be 10 (since 10² equals 100, the second term).

Applying the difference of squares rule to your expression, we get:

x² – 100 = (x - 10)(x + 10)

The factors of the expression are therefore x - 10 and x + 10.

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Answer: [tex]tan(x)^{2}[/tex]

Step-by-step explanation:

We will use the trigonometric identities to solve this problem:

[tex]\frac{sec(x)^{2}}{cot(x)^{2}+1}[/tex] (1)

Let's begin by the following trigonometric identity:

[tex]sec(x)^{2}=tan(x)^{2}+1[/tex] (2)

An substitute it in (1):

[tex]\frac{tan(x)^{2}+1}{cot(x)^{2}+1}[/tex] (3)

Then, taking into account [tex]tan(x)^{2}=\frac{sin(x)^{2}}{cos(x)^{2}}[/tex] and [tex]cot(x)^{2}=\frac{cos(x)^{2}}{sin(x)^{2}}[/tex], we rewrite (3):

[tex]\frac{\frac{sin(x)^{2}}{cos(x)^{2}}+1}{\frac{cos(x)^{2}}{sin(x)^{2}}+1}[/tex] (4)

[tex]\frac{\frac{sin(x)^{2}+cos(x)^{2}}{cos(x)^{2}}}{\frac{cos(x)^{2}+sin(x)^{2}}{sin(x)^{2}}}[/tex] (5)

Then, applying the trigonometric identity [tex]sin(x)^{2}+cos(x)^{2}=1[/tex]

[tex]\frac{1}{cos(x)^{2}}}{\frac{1}{sin(x)^{2}}}[/tex] (6)

Finally

[tex]\frac{sin(x)^{2}}{cos(x)^{2}}}=tan(x)^{2}[/tex] (7)

Answer:

28

Step-by-step explanation:

Answer:

Peter picked 28.

Step-by-step explanation:

1/3 of 84 is 28 because 84 divided 3 and multiplied by 1 is 28.

Answer:

4(5+6) = Distribute

20 + 24 = Add

44

Step-by-step explanation:

Answer:

4 * (5 + 6)

Step-by-step explanation:

Step 1:  Convert words into an expression

Four times the sum of 5 and 6

4 * (5 + 6)

Answer:  4 * (5 + 6)

Answer:

[tex] \frac{1}{ {4}^{3} } [/tex]

Step-by-step explanation:

[tex] \frac{ {4}^{2} }{ {4}^{5} } = \frac{1}{ {4}^{ - 2} \times {4}^{5} } = \frac{1}{ {4}^{(5 - 2)} } = \frac{1}{ {4}^{3} } [/tex]

Answer:

5 peices of pizza for $4 each

and 4 drinks for $2

Step-by-step explanation:

Answer:

angle 1

Step-by-step explanation:

[tex] \angle \: 1 \: is \: complementary \: to \: \angle \: 2 \\ [/tex]

Answer: A 1 million

Step-by-step explanation:

The amount of the lump sum that the insurance company must put

into a bank account is $1 million.

Option A is the correct answer.

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

We can use the present value formula for an annuity to find the lump sum that the insurance company must put into a bank account:

PV = PMT / r

where PV is the present value, PMT is the annual payment, and r is the interest rate.

Substituting the given values, we get:

PV = 40,000 / 0.04

= $1,000,000

Therefore,

The amount of the lump sum that the insurance company must put

into a bank account is $1 million.

Learn more about expressions here:

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Answer: 11/30

Step-by-step explanation: looking at this question that was given to us and to find the probability, then we will go by saying that;

Probability of an event (E) = number of outcome of Event E/total number of all event

Prob(Basebase player)=11/30

Going by this, then we are going to have our answer as 11/30

The probability that a randomly selected person from the group is a Toronto Blue Jays fan is 11/30.

The question asks for the probability that a randomly selected person from the group of 30 people at a baseball game is a Toronto Blue Jays fan, given that 11 out of the 30 people are fans of that team. To calculate the probability, you divide the number of Blue Jays fans by the total number of people in the group.

Probability = Number of Toronto Blue Jays fans ÷ Total number of people

Probability = 11 ÷ 30

The probability can be simplified into the simple fraction form of:

Probability = 11/30

Answer: It is only one can that can be filled up.

Step-by-step explanation: If 1 gas can can hold 10 L of gas and you only have 7 L then how can you fill up more than 1 gas can with only 7 L?  You don't have enough gas to fill up more than 1 gas can. So you are left with only 1 gas can filled but only with 7 L.  

Final answer:

To find the average density of a full gasoline can, both the mass of the gasoline (20.0 L multiplied by 0.75 kg/L for 15.0 kg) and the mass of the can (2.50 kg) are added to get a total mass of 17.5 kg. This is divided by the volume of gasoline the can holds (20.0 L) to yield an average density of 0.875 kg/L.

Explanation:

The question centers on calculating the average density of a gasoline can when it is full. To do this, we need to consider the total mass of the can and the gasoline together and the total volume they occupy.

The mass of the gasoline can itself is 2.50 kg. When full, the can holds 20.0 L of gasoline. Assuming the density of gasoline is 0.75 kg/L, we can calculate the mass of the gasoline as:

Mass of gasoline = 20.0 L × 0.75 kg/L = 15.0 kg

Then, we add the mass of the gasoline to the mass of the can to get the total mass:

Total mass = Mass of steel can + Mass of gasoline

Total mass = 2.50 kg + 15.0 kg = 17.5 kg

To find the average density, we use the formula:

Density = Total mass / Total volume

The volume here is the volume of gasoline the can holds since we typically ignore the thickness of the container in such calculations unless otherwise specified. Hence the average density is calculated based on the volume of gasoline only.

Average density = 17.5 kg / 20.0 L

Average density = 0.875 kg/L

This value represents the combined density of the steel can and the gasoline within it.

Answer:

23

Step-by-step explanation:

log27(9) can be interpreted as " 27 to what power is equal to 9 . Since 2723=32=9,log27(9)=23

Answer:

2/3

Step-by-step explanation: