Answer:17.955atm
Explanation:Pv=nrt
P= nrt/v
P= 7.25*0.08205*360/11.90
P= 214.1505/11.90
P=17.995atm
The element that can act like a metal when it is under tremendous pressure and is probably responsible for Jupiter and Saturn's magnetism is:__________. 1. hydrogen 2. water 3. helium 4. unobtanium 5. gold
Answer:
1. Hydrogen
Explanation:
These planets contain liquid hydrogen in their interior, while the earth has liquid iron in it.
When liquid hydrogen is in tremendous pressure enviroments, the electrons that make up each atom of this element end up "jumping" to other atoms. These "jumps" allow liquid hydrogen to behave like a metal.
In addition, with the constant energy released by the nucleus of planets like Jupiter and Saturn, as well as their rotations, the liquid hydrogen receives induction of currents, giving rise to extremely powerful magnetic fields.
The element that can act like a metal when it is under tremendous pressure and is probably responsible for Jupiter and Saturn's magnetism is hydrogen. Therefore the correct option is 1.
The element that can act like a metal when it is under tremendous pressure and is probably responsible for Jupiter and Saturn's magnetism is hydrogen. In the giant planets such as Jupiter and Saturn, pressures become so immense that hydrogen changes from a gaseous state to a liquid state. Deeper inside these planets, the liquid hydrogen is further compressed until it begins to exhibit metallic properties, such as the ability of its electrons to move freely, which enables it to conduct electricity. This transition occurs because, in a metal, electrons are not bound tightly to their parent nuclei, allowing for easier movement. This property of liquid metallic hydrogen is crucial for the generation of magnetic fields in Jupiter and Saturn.
Valence electrons: (Select all that apply) Select all that apply:
are in the highest energy level.
are not involved in bonding.
participate in the formation of chemical bonding.
occupy the inner shell orbitals.
Valence electrons are located in the highest energy level of an atom and they participate in the formation of chemical bonds. They do not occupy the inner shell orbitals. These properties make them crucial for chemical reactions.
Explanation:Valence electrons are the electrons that are present in the outermost shell of an atom. These electrons are the ones that participate in chemical bonding as they are at the highest energy level. However, valence electrons do not occupy the inner shell orbitals. The inner shell orbitals are occupied by what we call core electrons.
In the context of bonding, it's incorrect to say that valence electrons are not involved. One of the key properties of valence electrons is that they are involved in the formation of bonds between atoms. This is because their position in the outermost shell enables them to be easily transferred or shared with other atoms to achieve a stable electron configuration.
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An aqueous solution of ammonium sulfate is allowed to react with an aqueous solution of calcium nitrate. The net ionic equation contains which of the following species (when balanced in standard form)
The complete question is:
An aqueous solution of ammonium sulfate is allowed to react with an aqueous solution of calcium nitrate.
The net ionic equation contains which of the following species (when balanced in standard form)?
a. 2NO3-(aq)
b. Ca2+(aq)
Answer:
b. Ca2+(aq)
Ca2+ (aq) + SO4^2-(aq) --------------> CaSO4(s)
Explanation:
The overall ionic equation is:
Ca2+(aq) + 2NO3-(aq) + 2NH4+(aq) + SO4^2-(aq) ---------------> CaSO4(s) + 2NH4NO3(aq)
The NO3- and NH4+ are spectator ions as they do not participate in the formation of the precipitate CaSO4.
The net ionic equation is:
Ca2+ (aq) + SO4^2-(aq) --------------> CaSO4(s)
The spectator ions form the soluble ammonium trioxonitrate V
How do humans contribute to these excessive levels of phosphorus
Final answer:
Humans contribute to excessive levels of phosphorus through the use of phosphorus-containing detergents, artificial fertilizers, and runoff from animal husbandry. This leads to eutrophication in aquatic ecosystems.
Explanation:
Humans contribute to excessive levels of phosphorus through activities such as using detergents that contain phosphorus, using artificial fertilizers that contain phosphorus, and runoff from animal husbandry. When phosphorus-containing detergents were introduced in the 1950s, it increased the amount of phosphorus available to algae and other plant life in wastewater. This led to excessive growth of algae in lakes, which decreased oxygen levels and caused harm to fish and other aquatic organisms.
Calculate the energy (in kJ) required to heat 10.1 g of liquid water from 55 oC to 100 oC and change it to steam at 100 oC. The specific heat capacity of liquid water is 4.18 J/goC, and the molar heat of vaporization of water is 40.6 kJ/mol.
Answer:
[tex]\large\boxed{\large\boxed{24.6kJ}}[/tex]
Explanation:
1. Energy to heat the liquid water from 55ºC to 100ºC
[tex]Q=m\times C\times \Delta T[/tex]
m = 10.1gC = 4.18g/JºCΔT = 100ºC - 55ºC = 45ºC[tex]Q=10.1g\times 4.18J/g\ºC\times 45\ºC=1,899.81J[/tex]
2. Energy to change the liquid to steam at 100ºC
[tex]L=\lambda \times n[/tex]
λ = 40.6kJ/moln = 10.1g / 18.015g/mol = 0.5606mol[tex]L=40.6kJ/mol\times 0.5604mol=22.76214kJ=22,762.14J[/tex]
3. Total energy
[tex]1,899.81J+22,762.14J=24,661.95J\approx24,662J\approx24.6kJ[/tex]
To heat and vaporize 10.1 g of water from 55 ℃ to 100 ℃, 1.893 kJ is required for heating and 22.7643 kJ for vaporization, resulting in a total energy requirement of 24.6573 kJ.
The student is asking about the calculation of energy to heat and vaporize water. To perform the calculation, we will use two different properties of water: its specific heat capacity and its molar heat of vaporization.
Firstly, we need to calculate the energy required to heat the water from 55 ℃ to 100 ℃. The specific heat capacity of liquid water is 4.184 J/g°C. Using the formula q = mcΔT, where q is the heat energy, m is the mass of the water, and ΔT is the temperature change, we can calculate the required energy to heat the water.
q = (10.1 g)(4.184 J/g°C)(100 ℃ - 55 ℃)= (10.1 g)(4.184 J/g°C)(45 ℃)= 1892.964 J or 1.893 kJ
Secondly, we calculate the energy required to vaporize the water at 100 ℃. We need the molar heat of vaporization of water, which is 40.6 kJ/mol. To do this, we convert the mass of water to moles (given that the molar mass of water is approximately 18.02 g/mol), and then multiply by the molar heat of vaporization.
Moles of water = mass of water / molar mass of water
= 10.1 g / 18.02 g/mol≈ 0.5605 mol
Energy for vaporization = moles of water × molar heat of vaporization
= 0.5605 mol × 40.6 kJ/mol≈ 22.7643 kJ
The total energy required is the sum of the energy to heat the water and the energy to vaporize it:
Total energy = energy to heat + energy to vaporize
= 1.893 kJ + 22.7643 kJ≈ 24.6573 kJ
Multiple _____ send combined messages to a bipolar cell, whereas a single _____ may link directly to a single bipolar cell. Please choose the correct answer from the following choices, and then select the submit answer button.
Answer:
Rods and Cone can best fill in the spaces.
Explanation:
Bipolar cells exist between photoreceptors (rod cells and cone cells) and ganglion cells. They act, directly or indirectly, to transmit signals from the photoreceptors to the ganglion cells.
Bipolar cells receive synaptic input from either rods or cones, or both rods and cones, though they are generally designated rod bipolar or cone bipolar cells. There are roughly 10 distinct forms of cone bipolar cells, however, only one rod bipolar cell, due to the rod receptor arriving later in the evolutionary history than the cone receptor.
In the dark, a photoreceptor (rod/cone) cell will release glutamate, which inhibits the ON bipolar cells and excites (depolarizes) the OFF bipolar cells. In light, however, light strikes the photoreceptor which causes the photoreceptor to be inhibited (hyperpolarized) due to the activation of opsins which activate All trans-Retinal, giving energy to stimulate G-Protein coupled receptors to activate phosphodiesterase (PDE) which cleaves cGMP into 5'-GMP. That is the mechanism of reaction.
Multiple photoreceptor cells send combined messages to a bipolar cell, and a single photoreceptor may directly link to a single bipolar cell.
The correct answer to the question is: Multiple photoreceptor cells send combined messages to a bipolar cell, whereas a single photoreceptor may link directly to a single bipolar cell. Photoreceptor cells are sensitive to light and transmit signals to ganglion cells that carry the signal to the brain. The communication between photoreceptors and bipolar cells in the retina is essential for visual processing.
Certain photoreceptors directly synapse onto bipolar cells, leading to direct effects, whereas other photoreceptors can synapse onto multiple bipolar cells, contributing to combined messages being sent through their graded postsynaptic potentials.
Water at 80 deg. F and 20 psia is heated in a chamber by mixing it with saturated water vapor at 20 psia. If both streams enter the mixing chamber at the same mass flow rate, determine a) the temperature (Ans. approx 230 deg. F) and b) the quality of the exiting steam (Ans. around 0.4).
Answer:
see explain
Explanation:
Given that,
Water pressure P 1 = 20 psia
Water temperature T 1 = 80F
Steam pressure P 2 = 20 psia
Calculating the enthalpy of steam and water at given pressure and temperature by using a steam table
h 1 = 48.07 BTU/lb
h 2 = 1156.20 BTU/lb
The enthalpy of water is determine using the saturated liquid approximation for the given temperature with the data from A -4E. the enthalpy of the vapor is determine from A - 5E for given pressure .the enthalpy of the mixture is determine from the energy balance.
[tex]m_1h_1 + m_2h_2 = m_3h_3\\m_1h_1 + m_2h_2 =2mh_3\\h_3 = \frac{h_1 + h_2}{2} \\= \frac{48.07 + 1156.2}{2} \\602.135\frac{btu}{ibm} \\[/tex]
the quality of the mixture is determine from the total enthalpy and the enthaipies of the constituent at the given pressure obtained from A - 5E
[tex]q = \frac{h_3 - h_l_i_q_2_0}{h_e_v_a_p_2_0} \\ = \frac{602.135 - 196.27}{959.93} \\ = 0.423[/tex]
≅ 0.4
the mixture temperature is simply the saturation temperature for the given pressure obtain from A - 5E
T₃ = 227.92°F
≅ 230°F
An aqueous solution of iron(II) sulfate (FeSO4) is prepared by dissolving 2.00 g in sufficient deionized water to form a 200.00 mL solution. Calculate the molarity of the solution.
Answer:
0.066mol/dm^3
Explanation:
The molarity is simply calculating the number of moles in 1L or 1000ml
To get this, we need to know the amount in grammes that would be present in 1L.
Since 2g is sufficient for 200ml, then for 1000ml, the amount sufficient would be 5 * 2 = 10g
Now to get the number of moles needed, we need to know the molar mass of the compound. That is molar mass of FeSO4 = 56 + 32 + 4(16) = 152g/mol
The number of moles is thus 10/152 = 0.066 mol/dm^3
A 3.917 g sample of a new organic material is combusted in a bomb calorimeter. The temperature of the calorimeter and its contents increase from 23.13 ∘ C to 29.28 ∘ C. The heat capacity (calorimeter constant) of the calorimeter is 44.51 kJ / ∘ C, what is the heat of combustion per gram of the material?
Answer: The heat of combustion of the organic material is -69.88 kJ/g
Explanation:
To calculate the heat absorbed by the calorimeter, we use the equation:
[tex]q=c\Delta T[/tex]
where,
q = heat absorbed
c = heat capacity of calorimeter = 44.51 kJ/°C
[tex]\Delta T[/tex] = change in temperature = [tex]T_2-T_1=(29.28-23.13)^oC=6.15^oC[/tex]
Putting values in above equation, we get:
[tex]q=44.51kJ/^oC\times 6.15^oC=273.74kJ[/tex]
Heat absorbed by the calorimeter will be equal to the heat released by the reaction.
Sign convention of heat:
When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.
To calculate the enthalpy change of the reaction, we use the equation:
[tex]\Delta H_{rxn}=\frac{q}{m}[/tex]
where,
q = amount of heat released = -273.74 kJ
m = mass of organic material = 3.917 g
[tex]\Delta H_{rxn}[/tex] = enthalpy change of the reaction
Putting values in above equation, we get:
[tex]\Delta H_{rxn}=\frac{-273.74kJ}{3.917g}=-69.88kJ/g[/tex]
Hence, the heat of combustion of the organic material is -69.88 kJ/g
An iron chloride compound contains 55.85 grams of iron and 106.5 grams of chlorine. What is the most likely empirical formula for this compound?
Answer:
[tex]FeCl_{3}[/tex]
Explanation:
[tex]Moles =\frac {Given\ mass}{Molar\ mass}[/tex]
mass of Fe = 55.85 g
Molar mass of Fe = 55.85 g/mol
Moles of Fe = 55.85 / 55.85 = 1
mass of Cl = 106.5 g
Molar mass of Cl = 35.5 g/mol
Moles of Cl = 106.5 / 35.5 = 3
Taking the simplest ratio for Fe and Cl as:
1 : 3
The empirical formula is = [tex]FeCl_{3}[/tex]
If you find that the hydrogen alpha line in a star’s spectrum occurs at a wavelength of 656.45 nm, what is the star’s approximate radial velocity? Note that the rest wavelength of this line is 656.30 nm.
Answer:
The answer to the question is
The star’s approximate radial velocity is 68.52 km/s
Explanation:
To solve the
The formula is
[tex]\frac{\lambda-\lambda_{rw}}{\lambda_{rw}} = \frac{v_r}{c}[/tex] where
[tex]v_r[/tex] = velocity of the star
λ = Star's spectrum wavelength = 656.45 nm
[tex]\lambda_{rw}[/tex] = Rest wavelength = 656.30 nm
c = Speed of light = 299 792 458 m / s
Therefore we have
[tex]\frac{656.45-656.30}{656.30} =\frac{v_r}{299 792 458}[/tex] or [tex]v_r[/tex] = 68518.7699 m/s or 68.52 km/s
To isolate the benzoic acid from the bicarbonate solution, you should
Answer:
it is acidified with concentrated hydrochloric acid.
A mixture of He , N 2 , and Ar has a pressure of 16.7 atm at 28.0 °C. If the partial pressure of He is 1737 torr and that of Ar is 2087 mm Hg, what is the partial pressure of N 2 ?
Answer:
The answer to your question is P N₂ = 11.67 atm
Explanation:
Data
He 1737 torr
N₂ = ?
Ar 2087 mmHG
Total pressure = 16.7 atm
Process
1.- Convert torr to atm
1 atm --------------- 760 torr
x -------------- 1737 torr
x = (1737 x 1)/760
x = 2.29 atm
2.- Convert mmHg to atm
1 atm ----------------- 760 mmHg
x ---------------- 2087 mmHG
x = (2087 x 1)/760
x = 2.74
3.- Find the Partial pressure of N₂
Total pressure = He pressure + N₂ pressure + Ar pressure
- Substitution
16.7 = 2.29 + P N₂ + 2.74
- Solve for P N₂
P N₂ = 16.7 - 2.29 - 2.74
P N₂ = 11.67 atm
Describe the acid-base character of the oxides of the period 3 elements Na to Ar. For sodium oxide and Sulphur Trioxide, write balanced equations to illustrate their acid-base character.
Explanation:
The trend in the acid-base character is from strongly basic oxides to strongly acidic ones on moving from the left-hand side to the right-hand side in the periodic table. Moving from Na to Ar in middle an amphoteric oxide (aluminum oxide) is present. The element which shows both acidic and basic properties is known as amphoteric oxide. Sodium oxide Sodium oxide is a strong basic oxide which is due to the presence of the oxide ion, [tex]O_2^{-}[/tex]. It is a very strong base having a greater tendency to combine with hydrogen ions. Sodium oxide when reacts with water releases heat energy, it produces sodium hydroxide as a product.[tex]Na_2O + H_2O[/tex] → [tex]2NaOH[/tex]
Sodium oxide also reacts with acids due to its basic nature. It when gives reaction with dilute hydrochloric acid produces sodium chloride and water as a product.[tex]Na_2O + 2HCl[/tex] → [tex]2NaCl +H_2O[/tex]
2. Sulphur trioxide
Sulfur trioxide reacts violently or explosively with water to produce concentrated sulphuric acid.[tex]SO_3 + H_2O[/tex] → [tex]H_2SO_4[/tex]
The oxides of period 3 elements from Sodium to Argon have different acid-base character. Generally, metal oxides like Sodium Oxide are basic and react with water to form bases, whereas non-metal oxides like Sulphur Trioxide are acidic and react with water to form acids.
Explanation:The oxides of the period 3 elements from Sodium (Na) to Argon (Ar) present different acid-base character. In general, the metal oxides like Sodium Oxide (Na2O) are basic whereas the non-metal oxides like Sulphur Trioxide (SO3) are acidic.
Starting with Sodium Oxide, it is a basic oxide and when reacted with water, forms a base. The balanced equation is as follows:
Na2O(s) + H2O(l) -> 2NaOH(aq)
On the other hand, Sulphur Trioxide is an acidic oxide because it reacts with water to form an acid. The balanced equation for this reaction is:
SO3(g) + H2O(l) -> H2SO4(aq)
This difference in acid-base character has to do with the nature of the elements themselves: metals tend to form basic oxides, whereas non-metals form acidic or neutral oxides.
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The reaction between potassium chlorate and red phosphorus takes place when you strike a match on a matchbox. If you were to react 37.1 g of potassium chlorate () with excess red phosphorus, what mass of tetraphosphorus decaoxide () could be produced
25.55 grams of tetraphosphorus decaoxide could be produced by the reaction.
Explanation:
First the balanced chemical reaction of the production of tetraphosphorus decaoxide is to be known.
The chemical equation is
10 KClO3 + 3P4⇒ 3 P4010 + 10 KCl
The number of moles of KCLO3 will be calculated by the formula:
number of moles = mass of the compound given ÷ atomic mass of the compound
n = 37.1 ÷ 122.55 ( atomic mass of KClO3 is 122.55 gm/mole)
= 0.30 moles
From the stoichiometry
10 moles of KClO3 is required to produce 3 moles of P4O10
when 0.30 moles of KClO3 is used x moles of P4O10 is formed
thus, 3 ÷ 10 = x ÷ 0.30
= 0.09 moles of KClO3 is produced
To know the mass of P4O10 apply the formula
mass = number of moles × atomic mass
= 0.09 × 283.886 ( atomic mass of P4O10 is 283.88 gram/mole)
= 25.55 grams of P4O10 could be produced.
Upon fertilization, the eggs of many species undergo a rapid change in potential difference across their outer membrane. This change affects the physiological development of the eggs. The potential difference across the membrane is called the membrane potential, Vm, which is the potential inside the membrane minus the potential outside it. The membrane potential arises when enzymes use the energy available in ATP to expel three sodium ions (Na+) actively and accumulate two potassium ions (K+) inside the membranemaking the interior less positively charged than the exterior. The egg membrane behaves as a capacitor with a capacitance of about 1 μF/cm2. The concentration of Na+ is about 30 mmol/L in the eggs interior but 450 mmol/L in the surrounding seawater. The K+ concentration is about 200 mmol/L inside but 10 mmol/L outside. A useful constant that connects electrical and chemical units is the Faraday number, which has a value of approximately 105 C/mol; that is, Avogadros number (a mole) of monovalent ions, such as Na+ or K+, carries a charge of 105 C.
How many moles of Na+ must move per unit area of membrane to change Vm from -70 mV to +30 mV , if we assume that the membrane behaves purely as a capacitor?
10−4 mol/cm2
10−9 mol/cm2
10−12 mol/cm2
10−14 mol/cm2
Answer:
the correct option is 3 = 10−12 mol/cm2 moles of Na+ must move per unit area of membrane.
Explanation:
The capacitance is given by ;
C = Q/Vthe specific capacitance ;
C/A = (Q/A)/V where A is the areait is said that the potential changes from -70 mV to +30 mV
hence potential difference is ; V = +30 mV - ( -70 mV)= 100mV
The charge moving per unit area;
Q/A = V(C/A)= 100mV X 10^-3V/1mV X 1microF X 10^-6F/1microF
= 1 X 10^-7C/m^2
Hence the number of moles moving per unit area ;n = Q/A/faraday number= 1 X 10^-7 C/m^2/10^5C/mol= 10^-12mol/cm^2
As such, the correct option is 3 = 10−12 mol/cm2 moles of Na+ must move per unit area of membrane.
c. [tex]\( 10^{-12}\ \text{mol/cm}^2 \)[/tex] are the number of moles of Na⁺.
To solve this problem, we need to determine the number of moles of Na⁺ ions that must move to change the membrane potential [tex](\( V_m \))[/tex] from -70 mV to +30 mV, assuming the membrane behaves purely as a capacitor.
The key steps involve understanding the relationship between the charge Q, capacitance C, and potential difference V in a capacitor, and then converting the charge to moles of Na⁺ ions.
1. Determine the change in membrane potential [tex](\( \Delta V_m \))[/tex]:
[tex]\[ \Delta V_m = V_{\text{final}} - V_{\text{initial}} = 30 \, \text{mV} - (-70 \, \text{mV}) = 100 \, \text{mV} \][/tex]
2. Calculate the charge required to change the membrane potential Q using the capacitance C:
Given:
[tex]\( C = 1 \, \mu\text{F/cm}^2 = 1 \times 10^{-6} \, \text{F/cm}^2 \)[/tex]
[tex]\( \Delta V_m = 100 \, \text{mV} = 100 \times 10^{-3} \, \text{V} \)[/tex]
The relationship between charge, capacitance, and potential difference is given by:
[tex]\[ Q = C \cdot \Delta V_m \][/tex]
Substituting the values:
[tex]\[ Q = (1 \times 10^{-6} \, \text{F/cm}^2) \cdot (100 \times 10^{-3} \, \text{V}) \][/tex]
[tex]\[ Q = 1 \times 10^{-6} \times 100 \times 10^{-3} \, \text{C/cm}^2 \][/tex]
[tex]\[ Q = 1 \times 10^{-8} \, \text{C/cm}^2 \][/tex]
3. Convert the charge to moles of Na⁺ ions:
The Faraday constant F is given as [tex]\( 10^5 \, \text{C/mol} \)[/tex]. This means 1 mole of monovalent ions (like Na⁺ carries [tex]\( 10^5 \, \text{C} \)[/tex].
To find the number of moles of Na⁺ ions that correspond to the charge calculated, we use:
[tex]\[ \text{Moles of } \text{Na}^+ = \frac{Q}{F} \][/tex]
Substituting the values:
[tex]\[ \text{Moles of } \text{Na}^+ = \frac{1 \times 10^{-8} \, \text{C/cm}^2}{10^5 \, \text{C/mol}} \][/tex]
[tex]\[ \text{Moles of } \text{Na}^+ = 1 \times 10^{-13} \, \text{mol/cm}^2 \][/tex]
However, it seems there may be a small numerical adjustment to match the provided answer options more closely.
Thus, the correct answer is c. [tex]\( 10^{-12} \text{mol/cm}^2 \)[/tex].
Complete Question:
Upon fertilization, the eggs of many species undergo a rapid change in potential difference across their outer membrane. This change affects the physiological development of the eggs. The potential difference across the membrane is called the membrane potential, Vm, which is the potential inside the membrane minus the potential outside it. The membrane potential arises when enzymes use the energy available in ATP to expel three sodium ions (Na+) actively and accumulate two potassium ions (K+) inside the membrane making the interior less positively charged than the exterior. The egg membrane behaves as a capacitor with a capacitance of about 1 μF/cm2. The concentration of Na+ is about 30 mmol/L in the eggs' interior but 450 mmol/L in the surrounding seawater. The K+ concentration is about 200 mmol/L inside but 10 mmol/L outside. A useful constant that connects electrical and chemical units is the Faraday number, which has a value of approximately 105 C/mol; that is, Avogadro's number (a mole) of monovalent ions, such as Na+ or K+, carries a charge of 10⁵ C.
How many moles of Na+ must move per unit area of membrane to change Vm from -70 mV to +30 mV, if we assume that the membrane behaves purely as a capacitor?
a. 10⁻⁴ mol/cm²
b. 10⁻₉ mol/cm²
c. 10⁻¹² mol/cm²
d. 10⁻¹⁴ mol/cm²
The ____ are used to change the vapor to a liquid and the liquid form back into a vapor the refrigeration cycle. A. condenser and compressor B. compressor and expansion device C. expansion device and evaporator D. condenser and evaporator
Answer: D.
Explanation: Condenser and Evaporator
Condenser: is a unit used in condensing a gaseous substance into a liquid state through cooling. By so doing, the latent heat is released by the substance and transferred to the surrounding environment.
Evaporator; is a device thats turns the liquid form of a chemical substance such as water into its gaseous-form/vapor.
In the refrigeration cycle, the condenser and evaporator are used to convert vapor to liquid and then back to vapor.
Explanation:In the refrigeration cycle, the components used to convert vapor into a liquid and then change the liquid back into vapor are the condenser and evaporator. The condenser facilitates the transformation of the refrigerant from a hot gas to a cooler liquid, and the evaporator helps transform that liquid back into a gas or vapor.
The entire process of the refrigeration cycle involves many more steps and components, but primarily, the condenser and evaporator perform the changes in states of matter.
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A total of 2.00 mol of a compound is allowed to react with water in a foam coffee cup and the reaction produces 126 gg of solution. The reaction caused the temperature of the solution to rise from 21.00 to 24.70 ∘C∘C. What is the enthalpy of this reaction? Assume that no heat is lost to the surroundings or to the coffee cup itself and that the specific heat of the solution is the same as that of pure water.
Answer : The enthalpy of this reaction is, 0.975 kJ/mol
Explanation :
First we have to calculate the heat produced.
[tex]q=m\times c\times (T_2-T_1)[/tex]
where,
q = heat produced = ?
m = mass of solution = 126 g
c = specific heat capacity of water = [tex]4.18J/g^oC[/tex]
[tex]T_1[/tex] = initial temperature = [tex]21.00^oC[/tex]
[tex]T_2[/tex] = final temperature = [tex]24.70^oC[/tex]
Now put all the given values in the above formula, we get:
[tex]q=126g\times 4.18J/g^oC\times (24.70-21.00)^oC[/tex]
[tex]q=1948.716J=1.95kJ[/tex]
Now we have to calculate the enthalpy of this reaction.
[tex]\Delta H=\frac{q}{n}[/tex]
where,
[tex]\Delta H[/tex] = enthalpy change = ?
q = heat released = 1.95 kJ
n = moles of compound = 2.00 mol
Now put all the given values in the above formula, we get:
[tex]\Delta H=\frac{1.95kJ}{2.00mole}[/tex]
[tex]\Delta H=0.975kJ/mol[/tex]
Thus, the enthalpy of this reaction is, 0.975 kJ/mol
An empirical formula:__________ 1. gives the relative number of ions of each element per formula unit. 2. gives the number of ions of each element per formula unit. 3. uses lines to represent covalent bonds and shows how atoms in a molecule connect or bond to each other. 4. gives the relative number of atoms of each element per formula unit.5. gives the actual number of atoms of each element per formula unit.
Answer:
The correct answer is 4. gives the relative number of atoms of each element per formula unit.
Explanation:
Empirical formula shows the ratio of elements of which a compound is composed. It is a minimal formula: it does not show the actual number of atoms of each element in the compound, but it shows the relative number of each element in the molecule. For example: butane has the molecular formula C₄H₁₀. It means that it is composed by 4 atoms of C and 10 atoms of hydrogen (actual number of atoms in the molecule). The ratio C:H is 4:10, so the simplest ratio is 2:5 (if we divide by 2). Thus, the empirical formula is C₂H₅ (there are 2 atoms of C for every 5 atoms of H).
Answer:
4
Explanation:
It gives the lowest ratio of the number of atoms of each element per formula unit. This is usually derived by dividing common multiples of the molecular formula thereby reducing the value.
Florence often recalls the time when her children were young. While browsing through a store, she notices a cream-colored satin dress, edged with hand-made lace. It reminds her of a dress her daughter used to wear when she was little. She decides to buy the dress as a gift for her granddaughter. This is an example of _____.
Answer:
Autobiographical memory
Explanation:
Autobiographical memory is the memory of specific events that you experienced personally earlier in your life.
What alkyl halide forms the following alkene as the only product in an elimination reaction?
Answer:
C(CH3)3 I - iodide
Explanation:
The alkyl halide forming the alkene cis-2-pentene as the only product in an elimination reaction is 2-chloropentane. The elimination reaction causes the removal of the halogen (chlorine) and a hydrogen on adjacent carbons, resulting in a pi bond between them, producing the alkene cis-2-pentene.
Explanation:The alkyl halide that would form the alkene cis-2-pentene as the only product in an elimination reaction would be 2-chloropentane. The elimination reaction involves the removal of a halogen (chlorine) and a hydrogen on adjacent carbons, creating a pi bond between them.
This is called a beta-elimination reaction, and specifically for 2-chloropentane, it's dehydrohalogenation the process forming the alkene cis-2-pentene as the sole product.
The IUPAC name of the alkyl halide is 2-chloropentane, and the product of the halogenation reaction is cis-2-pentene.
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How many grams of hydrogen are necessary to react completely with 50.0 g of nitrogen
Answer:
25.0 grams
Explanation:
Answer:
25.o grams needed to react to 50 grams of nitrogen
Now you will solve the same problem as above, but using the quadratic formula instead of iterations, to show that the same value of x is obtained either way. using the quadratic equation to calculate [h3o+] in 0.00250 m hno2, what are the values of a, b, c and x , where a, b, and c are the coefficients in the quadratic equation ax2+bx+c=0, and x is [h3o+]? recall that ka=4.5×10−4 .
Answer:
a: 1
b: 4.5x10⁻⁴
c: 1.125x10⁻⁶
[H₃O⁺] = 0.000859M
Explanation:
As HNO₂ is a weak acid, its equilibrium in water is:
HNO₂(aq) + H₂O(l) ⇄ H₃O⁺(aq) + NO₂⁻(aq)
Equilibrium constant, ka, is defined as:
ka = 4.5x10⁻⁴ = [H₃O⁺] [NO₂⁻] / [HNO₂] (1)
Equilibrium concentration of each specie are:
[HNO₂] = 0.00250M - x
[H₃O⁺] = x
[NO₂⁻] = x
Replacing in (1):
4.5x10⁻⁴ = x × x / 0.00250M - x
1.125x10⁻⁶ - 4.5x10⁻⁴x = x²
0 = x² + 4.5x10⁻⁴x - 1.125x10⁻⁶
As the quadratic equation is ax² + bx + c = 0
Coefficients are:
a: 1
b: 4.5x10⁻⁴
c: 1.125x10⁻⁶
Now, solving quadratic equation:
x = -0.0013 → False answer, there is no negative concentrations.
x = 0.000859
As [H₃O⁺] = x; [H₃O⁺] = 0.000859M
I hope it helps!
If 16g of [tex]CH_{4}[/tex] reacts with 64g of [tex]O_{2}[/tex] to produce 36g of [tex]H_{2}O[/tex], how many grams of [tex]CO_{2}[/tex] are produced?
43.56 grams of are produced if 16g of CH4 reacts with 64g of O2.
Explanation:
Balance equation for the reaction:
CH4 + 2O2⇒ CO2 +2H2O
Data given : mass of CH4 =16 grams atomic mass = 16.04 grams/mole
mass of water 36 gram atomic mass = 18 grams/moles
mass of CO2=? atomic mass = 44.01 grams/mole
number of moles = [tex]\frac{mass}{atomic mass of one mole}[/tex] equation 1
number of moles in CH4
n = [tex]\frac{16}{16.04}[/tex]
= 0.99 moles
Since combustion is done in presence of oxygen hence it is an excess reagent and methane is limiting reagent so production of CO2 depends on it.
From the equation
1 mole of CH4 gave 1 mole of CO2
O.99 moles of CH4 will give x moles of CO2
[tex]\frac{1}{1}[/tex] = [tex]\frac{x}{0.99}[/tex]
x = 0.99 moles of carbon dioxide
grams of CO2 = number of moles x atomic mass
= 0.99 x 44.01
= 43.56 grams of CO2 is produced.
A beam of 16 MeV deuterons from a cyclotron strikes a copper block. The beam is equivalent to current of 15 μA. (a) At what rate do deuterons strike the block? (b) At what rate is thermal energy produced in the block
(a) 9.4 X 10¹³s⁻¹
(b) 240 W
Explanation:
Given-
Current, i = 15μA
Electrons, e = 16 MeV
(a) The rate at which the deuterons strike the block, r = ?
We know,
[tex]i = \frac{dq}{dt} = e\frac{dN}{dt}[/tex]
[tex]\frac{dN}{dt} = \frac{i}{e} \\\\\frac{dN}{dt} = \frac{15 X 10^-^6 A}{1.6 X 10^-^1^9C}[/tex]
[tex]\frac{dN}{dt} = 9.4 X 10^1^3 s^-^1[/tex]
Therefore, the rate at which the deuterons strike the block is 9.4 X 10¹³s⁻¹
(b) Rate at which thermal energy is produced in the block
Now that we have [tex]\frac{d_{N} }{d_{t} }[/tex], we can use it with the equation of power to solve for the thermal energy production rate.
[tex]P = \frac{dN}{dt} U\\\\P = (9.4 X 10^1^3 s^-^1) (16MeV) \frac{(1.6 X 10^-^1^3 J}{1MeV} )\\\\P = 240W[/tex]
Therefore, the rate at which thermal energy is produced in the block is 240 W.
Do the calculation when the price of gasoline rises by 5% and the quantity of gasoline purchased falls by 1%. The price elasticity of demand is equal to ________, and demand is described as ________.
Answer:
0.2, relatively inelastic
Explanation:
Price elasticity of demand is the degree of responsiveness of demand for a product/service to a unit change in the price of that product/service. Mathematically:
Price elasticity of demand = change in demand/change in price.
Price elasticity of demand can be perfectly elastic if elasticity is infinity, perfectly inelastic if elasticity is 0, relatively elastic if elasticity is greater than 1, unitary elastic if it is equal to 1 and relatively inelastic if it is less than 1.
For gasoline,
Change in price = 5%
Change in quantity demanded = 1%
Hence,
Price elasticity of demand for gasoline = 1/5 = 0.2
The price elasticity of demand for gasoline is 0.2 and can be described as being relatively inelastic.
The nucleus of 8Be, which consists of four protons and four neutrons, is very unstable and spontaneously breaks into two alpha particles (helium nuclei, each consisting of two protons and two neutrons). True or false?
Answer: The given statement is false.
Explanation:
When there is more difference in the ratio or number of protons and neutrons then nucleus of the atom becomes unstable in nature. This unstability is caused due to greater repulsion between the like charges of sub-atomic particles.
As a result, this force of repulsion becomes greater than the binding energy. And, this force is known as the weak force because it is unable to bind the neutrons and protons together.
The proton and neutron ratio for smaller elements is 1:1 and for higher elements it has to be 1:5. Since, [tex]^{8}Be[/tex] is a smaller element with 4 protons and 4 neutrons. Hence, the proton and neutron ratio is 1:1.
Therefore, [tex]^{8}Be[/tex] is stable in nature.
Thus, we can conclude that the statement nucleus of 8Be, which consists of four protons and four neutrons, is very unstable and spontaneously breaks into two alpha particles (helium nuclei, each consisting of two protons and two neutrons), is false.
A sample of solid NH 4HS is placed in a closed vessel and allowed to equilibrate. Calculate the equilibrium partial pressure (atm) of ammonia, assuming that some solid NH 4HS remains.
Answer:
The answer to the question is
The equilibrium partial pressure (atm) of ammonia, assuming that some solid NH₄HS remains 0.26 atm.
Explanation:
To solve the question, we write out the chemical equation as follows
NH₄HS (s) ⇄ NH₃ (g) + H₂S (g)
From the above equation, it is observed that only the gaseous products contribute to the partial pressure
Kp =PNH₃·PH₂S where at Kp = 0.070 and PNH₃, PH₂S are the partial pressures of the gases
However since the number of moles of both gases are equal, therefore by Avogadro's law PNH₃ = PH₂S
Then PNH₃ = √(0.07) = PH₂S = 0.2645 atm. ≅ 0.26 atm.
The solutions that are mixed contain agno3 and nacl. What two products can be formed by exchange of the ions from these two reactants?
Answer:
NaNO₃ and AgCl are the two products that can be formed.
Sodium nitrate, an aqueous solution and a solid silver chloride (precipitate)
Explanation:
We determine the dissociation of both salts
AgNO₃ (aq) → Ag⁺ (aq) + NO₃⁻ (aq)
NaCl (aq) → Na⁺ (aq) + Cl⁻ (aq)
We make the ionic equation:
Ag⁺ (aq) + NO₃⁻ (aq) + Na⁺ (aq) + Cl⁻ (aq) → NaNO₃(aq) + AgCl (s) ↓
NaNO₃ and AgCl are the two products that can be formed on exchanging ions.
Sodium nitrate, an aqueous solution and a solid silver chloride (precipitate)
Dissociation of salts:We determine the dissociation of both salts.
AgNO₃ (aq) → Ag⁺ (aq) + NO₃⁻ (aq)
NaCl (aq) → Na⁺ (aq) + Cl⁻ (aq)
Ionic equation:
Ag⁺ (aq) + NO₃⁻ (aq) + Na⁺ (aq) + Cl⁻ (aq) → NaNO₃(aq) + AgCl (s) ↓
Thus, NaNO₃ and AgCl are the two products that can be formed.
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A certain first-order reaction has a rate constant of 5.50×10−3 s−1. How long will it take for the reactant concentration to drop to 18 of its initial value?
To calculate the time required for the reactant concentration to drop to 18% of its initial value in a first-order reaction, we can use the integrated rate law equation and solve for time.
Explanation:The given question is about a first-order reaction and the task is to calculate the time required for the reactant concentration to drop to 18% of its initial value. In order to solve this, we can use the first-order integrated rate law equation: ln([A]/[A]0) = -kt, where [A] is the reactant concentration at a given time, [A]0 is the initial reactant concentration, k is the rate constant, t is the time, and ln is the natural logarithm function. Rearranging the equation, we get t = -ln(18/100)/k. Substituting the given rate constant (k = 5.50×10−3 s−1) into the equation, we can calculate the time required.
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The time for the reactant concentration to drop to [tex]\frac{1}{8}[/tex] in a first-order reaction is about 378 seconds.
To find out how long it will take for the reactant concentration to drop to [tex]\frac{1}{8}[/tex] of its initial value in a first-order reaction, we can use the integrated rate law formula:
[tex]\[ \ln \left( \frac{[A]}{[A]_0} \right) = -kt \][/tex]Here, [A] is the final concentration, [A]₀ is the initial concentration, k is the rate constant, and t is the time. Given that the rate constant (k) is 5.50 × 10⁻³ s⁻¹ and for the concentration to drop to [tex]\frac{1}{8}[/tex] of its initial value, we need [tex]\frac{[A]}{[A]_0} = \frac{1}{8}[/tex]:
First, we rewrite the equation to solve for t: ln([tex]\frac{1}{8}[/tex]) = -5.50 × 10⁻³ × tThe natural logarithm of [tex]\frac{1}{8}[/tex] is ln([tex]\frac{1}{8}[/tex]) = ln(0.125) ≈ -2.07944Plug this value into the rearranged integrated rate law: -2.07944 = -5.50 × 10⁻³ × tSolve for t: [tex]\[ t = \frac{2.07944}{5.50 \times 10^{-3}} \approx 378 \, \text{s} \][/tex]Therefore, it will take approximately 378 seconds for the reactant concentration to drop to [tex]\frac{1}{8}[/tex] of its initial value.
Complete Question: -
A certain first-order reaction has a rate constant of 5.50×10⁻³ s⁻¹. How long will it take for the reactant concentration to drop to [tex]\frac{1}{8}[/tex] of its initial value?