George is 3 time as old as chun. Chun is 1/2 as old as elizabeth. Waneta is 4/7 as old as elizabeth. Waneta is 8 years old. How many years old is george

Answer:

  12.37 square inches

Step-by-step explanation:

The area of the dartboard can be figured from the diameter as ...

   A = (π/4)d² = (π/4)(17.75 in)² ≈ 247.4495 in²

There are 20 sectors, all the same size, so the area of one of them is ...

  sector area = (1/2)(247.4495 in²) ≈ 12.37 in²

Answer:

-471,861

Step-by-step explanation:

The sum of 9 terms in the sequence –9, 36, –144, 576, ... is -471861.

An ordered collection of objects that allows repetitions is referred to as a sequence. It has members, just like a set does. The length of the sequence is determined by the number of items.

Given:

–9, 36, –144, 576, ...

Calculate the ratio of the sequence as shown below,

ratio = 36 / -9

ratio = -4

Calculate the sum of 9 terms as shown below,

S₉ = -9 (1 - (-4)⁹) / (1 - (-4))

S₉ = -9 (1 + 262144) / 5

S₉ = -9 (262145) / 5

S₉ = -2359305 / 5

S₉ = -471861

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The slope of Line m that is parallel to Line l is also 4/9.

The slope of a line determines its steepness and direction. When two lines are parallel, they have the same slope. In this case, Line l is parallel to Line m, and the slope of Line l is 4/9. Therefore, the slope of Line m is also 4/9.

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is [tex]y = 2 ^n[/tex]

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒[tex]y = 2^2 = 2^n[/tex]

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, [tex]y = 2^ n = 2^7 = 128[/tex]

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, [tex]y = 2^ n = 2^{11} = 2048[/tex]

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is [tex]y = 2 ^n[/tex]

Answer:The answer is B. 160 + 20d

Step-by-step explanation: first find out the total for how much he makes at the first job. 20 x 8 = 160 then you just write out the equation

Answer:

  see below

Step-by-step explanation:

In the attachment, the points are listed in the order given in the problem statement. (They are listed to the right of the "rotation matrix", with x-coordinates above y-coordinates.)

__

I really don't like to do repetitive calculations, so I try to use a graphing calculator or spreadsheet whenever possible. Angles are measured CCW.

As always, the rotation transformations are ...

  180° — (x, y) ⇒ (-x, -y)

  270° — (x, y) ⇒ (y, -x)

The decay factor of the exponential function represented by the provided table is 1/3 as the ratio of the consecutive y-values of the function is consistently 1/3.

The decay factor of an exponential function can be found by comparing the ratio of the y-values of the function.

In the given question, a table of x/f(x) values is provided.

A decay happens if the ratios of the consecutive y-values (outputs) are consistently less than 1.

Let's find the ratio between successive y-values. Between 18 and 6, the ratio is 6/18 = 1/3. Going from 6 to 2, the ratio is 2/6 = 1/3. Lastly, transitioning from 2 to 2/3, the ratio is (2/3)/2 = 1/3.

Since we find the ratio of successive outputs (y-values) to consistently be 1/3, it is safe to say that 1/3 is the decay factor for the exponential function represented by the given table.

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Answer:

Correct option is (a) equal to the population mean.

Step-by-step explanation:

According to the Central limit theorem if a large sample is selected from an unknown population with mean μ and standard deviation σ then the sampling distribution of sample means follows a normal distribution.

The mean and standard deviation of this sampling distribution is:

[tex]\mu_{\bar x}=\mu[/tex]

[tex]\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}[/tex]

This standard deviation of the sampling distribution of mean is known as the standard error.

Thus, the correct option is (a) equal to the population mean.

The mean of the sampling distribution of the sample mean is equal to the population mean, as stated by the Central Limit Theorem, when the sample size is sufficiently large.

The correct answer to the student's question is: a. equal to the population mean. This principle is a key concept in statistics, known as the Central Limit Theorem. According to the theorem, if the size (n) of the sample is sufficiently large, the distribution of the sample means will be approximately normal, with the mean of these sample means equalling the population mean. Another important point to note is that the standard deviation of this distribution, called the standard error of the mean, is the population standard deviation divided by the square root of the sample size (n). Therefore, as the sample size increases, the standard deviation of the sampling distribution of the means decreases, leading to more precise estimations of the population mean.

Answer:

= 1

Step-by-step explanation:

The demand for that college will be equal to 1 or it can be said as unit elastic demand over the tuition range. This means that the demand for the college would move proportionately with the tuition range of that college, since the change in revenue is due to the change in tuition only.

Hope this helps.

Good luck and cheers.

Answer:

demand for the college is equal to 1

Step-by-step explanation:

- We know that the change in Total Revenue is only the function of change in tuition fee only.

- The change in tution fee is subjected to 15% last year multiplied by the corresponding change in demand for the college will lead to a change in total revenue.

- The relation can be expressed as:

                                         ΔTR =  Δ P *ΔD

Where,

         ΔTR : Change in Total Revenue

         Δ P : Change in tuition fee

         ΔD : Change in demand.

- For TR to remain unchanged then ΔTR = 0. Hence,

                                         ΔTR = 0 = Δ P *ΔD

- We are given a change in Δ P = 15%, so that means for ΔTR = 0, the change in demand ΔD = 0.

- ΔD = 0, also means that the elasticity of the demand curve is perfectly elastic or in other words the demand for the college is equal to 1.

The well is 35 feet deep.

Step-by-step explanation:

Given,

Length of rope = 50 feet

Length of remaining rope = 15 feet

Let,

x be the depth of well.

Total length of rope = Length of remaining + Depth of well

[tex]50=15+x\\50-15=x\\x=35[/tex]

The well is 35 feet deep.

Step-by-step explanation:

ok so your gonna need to set up a proportion, specifically

25 is to x as x is to 16

mathematically, it's a cross multiplying problem:

25                X

           =          

X                   16

cross multiply and you get 400 = x²

which when solved is 20.

Have a good night dude.

Answer: the lengths are 20 feet, 23 feet and 37 feet

Step-by-step explanation:

Let x represent the length of the shorter side of the triangular deck.

The second side of a triangular deck is 3 feet longer than the shortest​ side. This means that the length of the second side is (x + 3) feet.

The third side is 3 feet shorter than twice the length of the shortest side. This means that the length of the third of the triangle is (2x - 3) feet.

If the perimeter of the deck is 80 ​feet, it means that

x + x + 3 + 2x - 3 = 80

4x = 80

x = 80/4

x = 20

The length of the second side is

20 + 3 = 23 feet

The length of the third side is

20 × 2 - 3 = 40 - 3 = 37 feet

Answer:

2.7%.

Step-by-step explanation:.

Given:

Net profit margin ( profitability rate) =  15%

Total sales = $155 million

Total assets = $312 million

Total equity = $223 million.

Dividend rate = 10%

Question asked:

What is the firm's sustainable growth rate ?

First of all we will find these thing.

1. Asset utilization rate = [tex]\frac{Total \ sales}{Total \ assets}[/tex]

                                     = [tex]\frac{155}{312} = 0.496\ million= 0.5\%[/tex]

2. Financial utilization rate   =   [tex]\frac{Total\ debt}{Total\ equity} \\[/tex]

  Total debt = Total asset - Total equity

                   = $312 million -   $223 million = $89 million

                                           = [tex]\frac{89}{223} = 0.4\%[/tex]

3. Return on equity rate = Asset utilization rate [tex]\times[/tex] profitability rate

Return on equity rate = [tex]0.5\times15\times0.4=3\%[/tex]

4. Business retention rate = 100 - Dividend rate

                                           = 100 - 10 = 90%

Now, finally we will calculate sustainable growth rate :

Sustainable growth rate =  Return on equity rate [tex]\times[/tex]  Business retention rate

                                        = [tex]3\%\times90\%=2.7\%[/tex]

Therefore, firm's sustainable growth rate is 2.7%

Option B:

Point R on the number line best represents [tex]\frac{-6}{2}[/tex]

Solution:

In the number line,

The numbers which are left side of 0 are -1, -2, -3, -4, -5, -6, -7, -8.

The numbers which are right side of 0 are 1, 2, 3, 4, 5, 6, 7, 8.

Q is 6 points left of 0. That is Q = -6

R is 3 points left of 0. That is R = -3

S is 2 points left of 0. That is s = -2

T is 3 points right of 0. That is T = 3

[tex]$\frac{-6}{2}=-3[/tex]

In the number line -3 is the point of R.

Therefore point R on the number line best represents [tex]\frac{-6}{2}[/tex].

Option B is the correct answer.

Answer:

  see below

Step-by-step explanation:

The rotation transformations are ...

  90° : (x, y) ⇒ (-y, x)

  180° : (x, y) ⇒ (-x, -y)

  270° : (x, y) ⇒ (y, -x)

Applying these to the given points, you get ...

9) A'(6, 9)

10) A'(15, 11)

11) A'(9, 6)

12) A'(-11, 15)

13) A'(6, -9)

14) A'(15, -11)

Answer:

[tex]f(x)=x^{4}+x^{3}-10x^{2} +8x[/tex]

Step-by-step explanation:

A number is a factor of f(x) if and only if f(x) is zero for that value/number.

For the factors of a function we write the factors as x-a where a is the zero of function i.e. value at which f(x) is zero.

To write the polynomial function of minimum degree with real coefficients whose zeros include 2, -4, and 1, 3i, we find the f(x) is the product of all factors i.e x-a where a will represent the given zeros.

[tex]f(x)=(x-2)(x-(-4))(x-1)(x-3i)\\f(x)=(x-2)(x+4))(x-1)(x-3i)\\f(x)=(x^{2} +4x-2x-8)(x^{2} -3xi-x+3i )\\f(x)=(x^{2} +2x-8)(x^{2} -x-(3x+3)i)\\[/tex]

As it is stated that polynomial should have real coefficients so skipping the terms with 'i' we get

[tex]f(x)=(x^{2} +2x-8)(x^{2} -x)\\f(x)=x^{4}-x^{3}+2x^{3}-2x^{2} -8x^{2} +8x\\f(x)=x^{4}+x^{3}-10x^{2} +8x[/tex]

Answer:

f(x) = x4 - 2x2 + 36x - 80

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

The angles of a pentagon sum to 180(5-2) = 540 degrees, so each angle of a regular pentagon is 540/5 = 108. Therefore, three of these angles sum to $3 * 108 = 324, which means the indicated angle measures 360 - 324 = 36.

Answer:

36

Step-by-step explanation:

The angles of a pentagon sum to 180(5-2) = 540 degrees, so each angle of a regular pentagon is 540/5 = 108. Therefore, three of these angles sum to 3* 108 = 324, which means the indicated angle measures 360 - 324 = 36

The probability of an eighth-grade student using the Internet, based on the data provided, is approximately 0.62, or simply 8/13 as a fraction.

To calculate the probability that a student uses the Internet given he or she is in eighth grade, we look at the eight graders' behaviors in the table. There are 13 students in total in the eighth grade, and 8 of these use the Internet.

So, the probability can be expressed as P(Internet|8th grader) = number of internet users in 8th grade / total number of 8th graders = 8 / 13.

When rounded to two decimal places, this probability would be approximately 0.62. In terms of fractions, it can simply be left as 8/13.

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The probability that a student uses the Internet, given that he or she is in eighth grade, is 2/3.

We are asked for the probability that a student uses the Internet, given that he or she is in eighth grade. This is the conditional probability [tex]$P({\text{Internet}} | {\text{8th Grade}})$[/tex], which can be calculated using Bayes' Theorem: \begin{align*}

[tex]P({\text{Internet}} | {\text{8th Grade}}) &= \frac{P({\text{8th Grade}} | {\text{Internet}})P({\text{Internet}})} {P({\text{8th Grade}})} \\&= \frac{\frac{8}{28} \cdot \frac{14}{28}} {\frac{13}{28}} \\&= \frac{2}{3}[/tex]

\end{align*}

Therefore, the probability that a student uses the Internet, given that he or she is in eighth grade, is [tex]$\boxed{\frac{2}{3}}$[/tex].

Here is a more detailed explanation of how we arrived at our answer:

Step 1: Calculate the probability of being in eighth grade, given that the student uses the Internet. This is the conditional probability [tex]$P({\text{8th Grade}} | {\text{Internet}})$[/tex], which can be calculated from the table as follows: [tex]$P({\text{8th Grade}} | {\text{Internet}}) = \frac{8}{14}$[/tex]

Step 2: Calculate the probability of using the Internet.** This is the marginal probability [tex]$P({\text{Internet}})$[/tex], which can be calculated from the table as follows: [tex]$P({\text{Internet}}) = \frac{14}{28}$[/tex].

Step 3: Calculate the probability of being in eighth grade.This is the marginal probability [tex]$P({\text{8th Grade}})$[/tex], which can be calculated from the table as follows: [tex]$P({\text{8th Grade}}) = \frac{13}{28}$[/tex].

Step 4: Apply Bayes' Theorem to calculate the conditional probability [tex]$P({\text{Internet}} | {\text{8th Grade}})$[/tex].

Therefore, the probability that a student uses the Internet, given that he or she is in eighth grade, is[tex]$\boxed{\frac{2}{3}}$[/tex].

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Answer:

y=-2x

Step-by-step explanation:

First you want to remember rise over run. Your rise is -2 and your run is 1. So -2/1 is your answer. And -2/1 is equal to -2.

Answer:

[tex]\frac{2} {-1}[/tex]=-2

Step-by-step explanation:

Answer:

14.375 pounds

Step-by-step explanation:

Jesse's dog: 23 lb

Cat: 5/8*23=115/8

Therefore, Jesse's cat weighs 14.375 pounds

Answer:

See attached picture.

Step-by-step explanation:

See attached picture.

For remaining parts resubmit question.  

Answer:

O(n2)

Step-by-step explanation:

the first iteration algorithm of the i-for loop (the outer loop), the j-for loop (the inner loop) will run 2 to

n times which is represented as

(n − 1 times).

the second iteration algorithm of the i-for loop, the j-for loop will run 3 to n times represented as

(n − 2 times).

the third to the last iteration algorithm of the i-for loop, the j-for loop will run n − 1 to n times (2 times).

And the second to the last iteration of the i-for loop, the j-for loop will run from n to n times (1 time)

For the last iteration of the i-for loop, the j-for loop will run 0 times because i + 1 > n.

Now we know that the number of times the loops are run is

1 + 2 + 3 + . . . + (n − 2) + (n − 1) = n(n − 1)/2

So we can express the number of total iterations as n(n − 1)/2.

Since we have two operations per loop (one comparison and one multiplication), we have

2 ·n(n−1)/2 = n

2 − n operations.

So f(n) = n2 − n

f(n) ≤ n2

for n > 1.

Therefore, the algorithm is O(n2) with

C = 1 and k = 1.

The mean of the top five test scores is 96. Then the mean absolute deviation is zero.

It is the average distance between each data point and the mean.

The top five test scores in Mr. Rhodes's class were: 98, 92, 96, 97, and 97.

Then the mean (μ) will be

[tex]\mu = \dfrac{98+92+96+97+97}{5}\\\\\mu = \dfrac{480}{5}\\\\\mu = 96[/tex]

Then the mean absolute deviation will be

[tex]\rm MAD = \dfrac{\Sigma (X_i - \mu)}{n}\\\\MAD = \dfrac{(98-96)+(92-96)+(96-96)+(97-96)+(97-96)}{5}\\\\MAD = \dfrac{2-4+0+1+1}{5}\\\\MAD = 0[/tex]

The mean absolute deviation is zero and the mean is 96.

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Final answer:

Calculating the mean absolute deviation of the top five test scores in Mr. Rhodes's class involves finding the mean score and then the average of the absolute deviations from this mean. The result is a MAD of 1.6, indicating the average dispersion of the top scores from the class mean.

Explanation:

The question involves calculating the mean absolute deviation (MAD) of the top five test scores in Mr. Rhodes's class, which are 98, 92, 96, 97, and 97. First, we find the mean (average) of these scores by adding them together and dividing by the number of scores, which gives us (98 + 92 + 96 + 97 + 97) / 5 = 96. Next, we calculate the absolute deviation of each score from the mean, which are 2, 4, 0, 1, and 1 respectively. The mean absolute deviation is then the average of these absolute deviations, calculated as (2 + 4 + 0 + 1 + 1) / 5 = 1.6.

The result of these calculations shows that the mean absolute deviation of the test scores is 1.6. This value represents how much, on average, each of the top five scores deviates from the mean score of the class, providing an understanding of the variability or dispersion within the top scores. The MAD is a useful measure in understanding how spread out the scores are from the mean.

Answer:

[tex]2\frac{1}{6}[/tex] pounds.

Step-by-step explanation:

We have been given that Gina's literacy bucket weighs 6 pounds. Her novel weighs 1 4/6 pounds, and her chrome book weighs 2 1/6.

To find weight of bucket after taking out the two items, we will subtract weight of each item from 6 pounds as:

[tex]\text{Weight of bucket}=6-1\frac{4}{6}-2\frac{1}{6}[/tex]

Let us convert mixed fractions into improper fractions as:

[tex]1\frac{4}{6}=\frac{6\cdot 1+4}{6}=\frac{10}{6}\\\\2\frac{1}{6}=\frac{6\cdot 2+1}{6}=\frac{12+1}{6}=\frac{13}{6}[/tex]

[tex]\text{Weight of bucket}=6-\frac{10}{6}-\frac{13}{6}[/tex]

[tex]\text{Weight of bucket}=\frac{6\cdot 6}{6}-\frac{10}{6}-\frac{13}{6}[/tex]

[tex]\text{Weight of bucket}=\frac{36}{6}-\frac{10}{6}-\frac{13}{6}[/tex]

Combine numerators:

[tex]\text{Weight of bucket}=\frac{36-10-13}{6}[/tex]

[tex]\text{Weight of bucket}=\frac{13}{6}[/tex]

[tex]\text{Weight of bucket}=2\frac{1}{6}[/tex]

Therefore, the weight of the bucket is [tex]2\frac{1}{6}[/tex] pounds.

Answer:

Answer:

a) k = 0.1875 m

b) r2 = 0.46875 m

c) q = -1.125*10^-8 C

Step-by-step explanation:

Given:

- The total Length of rod L = 1.5 m

- The total charge of the rod Q = -9 * 10^8 C

- Total section of a rod n = 8

Find:

1. What is the length of one of these pieces?

2. What is the location of the center of piece number 2?

3. How much charge is on piece number 2?

Solution:

- The entire rod is divided into 8 pieces, so the length of each piece would be k:

                                     k = L / n

                                     k = 1.5 / 8

                                     k = 0.1875 m

- The distance from center of entire rod and center of section 2 is 2.5 times the section length

                                     r2 = 2.5*k

                                     r2 = 2.5*(0.1875)

                                     r2 = 0.46875 m

- Assuming the charge on the rod is uniformly distributed. The the charge for each section of rod is given by q:

                                     q = Q / n

                                     q = -9 * 10^8 / 8

                                     q = -1.125*10^-8 C

The length of one of the eight pieces of the rod is 0.1875 m. The center of piece number 2 is at <0.28125, 0, 0> m. The charge on piece number 2 is -1.125e-08 Coulombs.

The problem involves the concepts of electric field, charge distribution, and coordinate system in Physics. Let's answer the question part by part:

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Answer:

area = 8a^2 +4ab

Step-by-step explanation:

Area = (4a)(2a + b)

= 8a^2 +4ab

Step-by-step explanation:

[tex]Area of rectangle \\ = base \times height \\ = (4a) \times (2a + b) \\ = 4a \times 2a + 4a \times b \\ = 8 {a}^{2} + 4ab \\ [/tex]

Answer:

4.6

Step-by-step explanation:

Use the distance formula:

d = [tex]\sqrt{(x-x)^{2}-(y-y)^{2} }[/tex]

plug in the numbers

[tex]\sqrt{(6-1)^{2} -(5-3)^{2} }\\[/tex]

PEMDAS says do parenthisee first

[tex]\sqrt{(5)^{2} -(2)^{2} }[/tex]

now square it

[tex]\sqrt{25-4}[/tex]

subtract

[tex]\sqrt{21}[/tex]

do the calculator for this part

4.582575695

round it to get

4.6

Option A: [tex]y=\frac{3}{4}x+1[/tex] is the equation of the line.

Option E: [tex]y+2=\frac{3}{4}(x+4)[/tex] is the equation of the line.

Explanation:

Given that the line is [tex]3 x-4 y=7[/tex] and passes through the point [tex](-4,-2)[/tex]

We need to determine the equation of the line.

Formula:

The equation of the line can be determined using the formula,

[tex]y-y_1=m(x-x_1)[/tex]

Slope:

Since, the lines are parallel, from the equation [tex]3 x-4 y=7[/tex], we shall determine the slope.

Thus, we have,

[tex]-4 y=-3x+7[/tex]

   [tex]y=\frac{3}{4} x+\frac{7}{4}[/tex]

Thus, the slope of the equation is [tex]m=\frac{3}{4}[/tex]

Equation of line:

Substituting [tex]m=\frac{3}{4}[/tex] and the point [tex](-4,-2)[/tex] in the formula, we get,

[tex]y+2=\frac{3}{4}(x+4)[/tex]

Hence, the equation of line is [tex]y+2=\frac{3}{4}(x+4)[/tex]

Thus, Option E is the correct answer.

Let us write the equation of line [tex]y+2=\frac{3}{4}(x+4)[/tex] in slope - intercept form.

Thus, we have,

[tex]y+2=\frac{3}{4}x+3[/tex]

     [tex]y=\frac{3}{4}x+3-2[/tex]

     [tex]y=\frac{3}{4}x+1[/tex]

Thus, the equation of the line is [tex]y=\frac{3}{4}x+1[/tex]

Hence, Option A is the correct answer.

Answer:

C

Step-by-step explanation:

The x-axis is more than 7.0 and the y-axis is less than 7.0.

Cheers

Answer: the distance of the boat from the base of the lighthouse is 192.9 m

Step-by-step explanation:

The scenario is represented in the right angle triangle shown in the attached photo.

Looking at triangle ABC, the height of the light house operator above sea level represents the opposite side of the right angle triangle.

Angle A = 10° because it is alternate to the angle of depression.

To determine AB, the distance of the boat from the base of the lighthouse, we would apply

the tangent trigonometric ratio which is expressed as

Tan θ, = opposite side/adjacent side. Therefore,

Tan 10 = 34/AB

AB = 34/Tan 10 = 34/0.1763

AB = 192.9 m