Find the values of x and y for which the lines are parallel.
a)x = 47, y = 79
b)x = 58, y = 57
c)x = 79, y = 49
d)x = 79, y = 47

The behavior of the function f(x) as x becomes a very small negative number depends on the function's specific characteristics, such as decreasing values on a curve, a linear relationship, or asymptotic behavior.

When considering what happens to the function f(x) as x becomes a very small negative number, it depends on the behavior described by the function's equation. If the graph of the function shows a declining curve starting with a maximum at x = 0, as x becomes more negative, f(x) tends to decrease assuming that this behavior continues beyond the given graph. If the graph of f(x) shows a horizontal line between x = 0 and x = 20, this would typically indicate that for small negative values of x, the function would not be defined unless otherwise specified that the function's behavior extends with the same horizontal trend outside the given interval.

Situations such as the behavior of a spring force, described by a function like f(x) = -kx, might lead to a linear decrease as x becomes a small negative number, consistent with Hooke's Law. On the other hand, the presence of asymptotes would indicate that the function's value could grow without bounds as x approaches certain critical values, as seen in the case of a function like y = 1/x.

F(x) when x is a very small positive number then F(x) is a negative number with a small absolute value.

The correct option is (D).

The question shows a graph of a function[tex]\( f(x) \)[/tex]and asks what happens to[tex]\( f(x) \)[/tex] when [tex]\( x \)[/tex] is a very small negative number.

To answer this question, we do not need calculations but rather an interpretation of the graph. When [tex]\( x \)[/tex] is a very small negative number (approaching zero from the left), we need to look at the behavior of the graph as it approaches the y-axis from the left-hand side.

From the graph, it appears that as [tex]\( x \)[/tex] becomes a very small negative number (close to zero), [tex]\( f(x) \)[/tex] increases without bound. This suggests that[tex]\( f(x) \)[/tex]approaches positive infinity.

So, based on the graph, the answer would be:

[tex]\( f(x) \)[/tex] is a very large positive number.

This corresponds to option D on the multiple-choice answers provided.

The simplification of the expression -196 is -14 because the square root of 196 is 14 and the initial expression has a negative sign, option b) is the correct answer.

The question is asking us to simplify the expression -196. When it says 'simplify', and it's giving us a numerical value, it's most likely referring to finding the square root of a number, since the square root is a number that, when multiplied by itself, gives the original number. In this case, we are looking for the square root of 196, but we must keep in mind the negative sign, which indicates that we are dealing with negative square roots.

Normally, the square root of 196 is 14. However, because there is a negative sign (-) in front of the 196 in this problem, we are actually looking for the negative square root. Therefore, the 'simplified' version of -196 in this case would be -14, which is option (b).

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To find two positive real numbers whose product is a maximum, we need to use a mathematical technique called optimization. By solving the given equation and substituting the values back, we can find the two positive real numbers with a maximum product.

To find two positive real numbers whose product is a maximum, we need to use a mathematical technique called optimization. Let's define the two numbers as x and y.

Since the sum of the first number and three times the second number is 30, we can write the equation:

x + 3y = 30

To find the maximum product, we need to express the product of x and y in terms of a single variable. We can do this by substituting x = 30 - 3y into the product equation xy = (30 - 3y)y.

Now, we have a quadratic equation: y^2 - 10y + 15. Finding the maximum product corresponds to finding the vertex of this quadratic equation, which occurs when y = 5.

Substituting y = 5 back into the equation x + 3y = 30, we can solve for x: x + 3(5) = 30, x + 15 = 30, x = 15. Therefore, the two positive real numbers with a maximum product are x = 15 and y = 5.

Answer:

64000

Step-by-step explanation:

so, you have to double it every three months, so you are doubling is 8 times total. so, when you double 250 the first time you get 500 so then you double that, and you get 1000 the you double that to get 2000 then  you double that to get 4000 then you double that again and get 8000 then you double that again  to get 16000 then again to get 32000 and the one more time  to get your answer 64000

Answer:

$1486.41.

Step-by-step explanation:

Purchase price = $309,900

Down payment percent = 20 %

Remaining amount Percentage  = 100-20 = 80%

Mortgage amount = [tex]309900 \times 0.80[/tex]

                              =[tex]247920[/tex]

Formula of monthly payment : [tex]P =\frac{\frac{rM}{1 -(1 +\frac{r}{n})^-{nt}}}{n}[/tex]

where P = the payment,

r = the annual rate =6% = 0.06

M = the mortgage amount = $247920

t = the number of years=30

n = the number of payments per year= 12

Substitute the values.

[tex]P =\frac{\frac{0.06 \times 247920}{1 -(1 +\frac{0.06}{12})^-{12\times 30}}}{12}[/tex]

[tex]P=1486.40566196[/tex]

Hence the monthly payment is $1486.41.

Thus Option C is correct.

Answer:

C

Step-by-step explanation:

Edge 2020 says i was right for the quiz

Answer:

$6000

Step-by-step explanation:

Let recall

Given the formula I = P*r*t  or principal x rate x time

Where I=Interest earned

P=principal, the amount deposited or borrowed

R=the annual interest rate

T=Time frame

Therefore $1200 = Px0.04x5

P = 1200/(0.2)

P = 12000/2 = $6000

The amount of the initial investment id $6000

Answer:

the answer is 46 inches

Step-by-step explanation:

i got this question wrong when i put 140 then it told me the answer so i had to redo the question this is the write answer listen to me and get it right the first time :)

Answer: Option 'a' is correct.

Step-by-step explanation:

Since we have given that

When the midpoints of adjacent sides of quadrilateral are connected by segments.

These segments form a parallelogram.

These segments  form parallelogram irrespective of kind of quadrilateral.

Since all sides of these segments are opposite to each other.

So, Option 'a' is correct.

Solution:

Debt Ratio= (Total liabilities which includes debts, and other expenses) ÷ (Total amount of worth possessed)

A debt ratio of approximately 0.5 is considered to be reasonable.

Money Owed by you = $ 3450.00

[tex]0.5=\frac{3450}{\text{Credit limit}}\\\\ {\text{Credit limit}}= 3450 \times \frac{10}{5}\\\\ {\text{Credit limit}}= 6900[/tex]$

So, the Credit limit which gives Acceptable Debt of $ 3450.00 when debt ratio is approximately more or less than 0.5 is

Out of the following four options

Option (D) $ 7,000 is true, regarding Credit limit.

The student should understand how to use the concept of ratios to solve the problem. With a 56-foot length of rope and a ratio of 3:1, each unit is worth 14 feet. Thus, the longer piece, representing 3 units, is 42 feet.

The question is essentially asking for one to utilize the concept of ratios in problem solving. Given that a 56-foot rope is cut into two pieces in the ratio 3:1, the lengths of the two pieces would be divided in line with the said ratio. To obtain the lengths of the pieces in feet, you have to add the two parts of the ratio (3+1=4) and then divide the total length by this sum. In this case, 56/4 equals 14 feet. Therefore, one unit of the ratio is equivalent to 14 feet.

Following on, you multiply the first part of the ratio which is 3 by 14 to get the longer piece's length. Thus, the length of the longer piece is 42 feet.

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Answer:

13 cars

Step-by-step explanation:

There are 5 fewer trucks than cars in the parking lot. There are 8 trucks in total.

5 less trucks than cars. we need to find number of cars in the parking lot.

Cars are more than trucks. To find the number of cars, we add 5 with the total trucks .

8 trucks + 5 = 13

So there are total of 13 cars .

The position x where the object comes to rest (momentarily) is

Acceleration is rate of change of velocity.

[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]

[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]

a = acceleration (m / s²)v = final velocity (m / s)

u = initial velocity (m / s)

t = time taken (s)

d = distance (m)

Let us now tackle the problem!

This problem is about Kinematics.

Given:

vo = (-14.0i - 7.0j) m/s

a = (6.0i + 3.0j) m/s²

Unknown:

r = ? → v = 0 m/s

Solution:

To solve this problem, we need to use the following integral formula.

[tex]v = v_o + \int {a} \, dt[/tex]

[tex]v = (-14.0 \, \widehat{i} - 7.0 \, \widehat{j}) + \int {(6.0 \, \widehat{i} + 3.0\, \widehat{j})} \, dt[/tex]

[tex]v = (-14.0 + 6.0t) \, \widehat{i} + ( -7.0 + 3.0t ) \, \widehat{j}[/tex]

If the object comes to rest (momentarily) , then :

[tex]v_x = 0[/tex]

[tex](-14.0 + 6.0t) = 0[/tex]

[tex]6.0t = 14[/tex]

[tex]t = 14 \div 6.0[/tex]

[tex]\boxed {t = \frac {7}{3} ~ s}[/tex]

or

[tex]v_y = 0[/tex]

[tex]( -7.0 + 3.0t ) = 0[/tex]

[tex]3.0t = 7[/tex]

[tex]t = 7 \div 3.0[/tex]

[tex]\boxed {t = \frac {7}{3} ~ s}[/tex]

[tex]r = r_o + \int {v} \, dt[/tex]

[tex]r = 0 + \int { (-14.0 + 6.0t) \, \widehat{i} + ( -7.0 + 3.0t ) \, \widehat{j} } \, dt[/tex]

[tex]r = ( -14.0t + 3.0t^2 ) \, \widehat{i} + ( -7.0t + 1.5t^2 ) \, \widehat{j}[/tex]

At t = 7/3 s , then :

[tex]r = ( -14.0(\frac{7}{3}) + 3.0(\frac{7}{3})^2 ) \, \widehat{i} + ( -7.0(\frac{7}{3}) + 1.5(\frac{7}{3})^2 ) \, \widehat{j}[/tex]

[tex]r = [ (-16\frac{1}{3}) \, \widehat{i} + (-8\frac{1}{6}) \, \widehat{j} ] ~ m[/tex]

[tex]r \approx (-16.3 \, \widehat{i} - 8.2 \, \widehat{j} ) ~ m[/tex]

Grade: High School

Subject: Mathematics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Sperm , Whale , Travel

To solve the equation 24+?=120 divided by 3, subtract 24 from 40 to find the missing number, which is 16.

To solve the equation 24+?=120 divided by 3, we need to find the value of the missing number. We can do this by using the inverse operation of division, which is multiplication. Since 120 divided by 3 is equal to 40, we can subtract 24 from 40 to find the missing number. Therefore, the missing number is 16.

To increase 72 by 130 percent, convert the percentage to a decimal (1.3), multiply 72 by this number to get 93.6, and then add it back to the original number to get the result of 165.6.

To calculate the result of increasing 72 by 130 percent, you multiply 72 by 130% (which is the same as 1.3 in decimal form) and then add it to the original number.

Calculation steps:

Convert the percentage increase to decimal form: 130% = 1.3.

Multiply the original number by this decimal: 72 × 1.3 = 93.6.

Add this value to the original number: 72 + 93.6 = 165.6.

Therefore, when you increase 72 by 130 percent, you get 165.6.

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Gerry needs to pay $150 for 6 choco-lava cakes which cost $25 each.

The subject here is Mathematics, particularly dealing with proportionality. If Gerry sees that 2 choco-lava cakes cost $50, we can say that the price of each choco-lava cake is $50 divided by 2, which is $25 per choco-lava cake. Then, if Gerry needs 6 choco-lava cakes, we take the price of one choco-lava cake ($25) and multiply it by how many cakes he needs, which is 6. So, 6 cakes at $25 per cake give us $150.

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To convince me that they're not guessing on a true-false test, a student needs to get significantly more than half of the questions right.

A true-false test consists of 50 questions. To convince me that he is not merely guessing, a student would need to get significantly more than half of the questions right. If the student gets exactly half of the questions right, that would be the result we would expect from guessing. However, if the student consistently gets more than half of the questions right, it would indicate that they have some knowledge or understanding of the material.

Let's say a student gets 30 out of 50 questions correct. This would be 60% of the questions, which is higher than 50%, indicating that the student is not merely guessing.