find the value of x in the isosceles triangle shown
​

Answer:

4(5+6) = Distribute

20 + 24 = Add

44

Step-by-step explanation:

Answer:

4 * (5 + 6)

Step-by-step explanation:

Step 1:  Convert words into an expression

Four times the sum of 5 and 6

4 * (5 + 6)

Answer:  4 * (5 + 6)

Answer:

∠ 6 = 38°

Step-by-step explanation:

∠6 and 38° are vertical and congruent, thus

∠ 6 = 38°

Answer:

(x - 10)(x + 10)

Step-by-step explanation:

x² - 100 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

Thus

x² - 100

= x² - 10²

= (x - 10)(x + 10)

The expression x² - 100 can be factored using the difference of squares rule in algebra. The factors are (x - 10) and (x + 10).

The question asks for the factors of the polynomial expression x² – 100. This is a special kind of polynomial that can be factored using the difference of squares rule, a powerful tool in algebra which states that any expression in the form a² - b² can be rewritten as (a - b)(a + b).

In our case, a would be x (since x² is the first term) and b will be 10 (since 10² equals 100, the second term).

Applying the difference of squares rule to your expression, we get:

x² – 100 = (x - 10)(x + 10)

The factors of the expression are therefore x - 10 and x + 10.

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Answer:

The number is 4

Step-by-step explanation:

Write algebraically:

n-5=-1

n=4

The number is 4

To find the number when the difference of a number and five is negative one, substitute the given values into an equation and solve for the unknown variable.

To solve the problem, let's assign a variable to the unknown number. Let's call it 'x'. The difference of a number and five can be represented as 'x - 5'. According to the problem, this expression is equal to -1. So, we can write the equation x - 5 = -1. To find x, we need to isolate it on one side of the equation. Adding 5 to both sides, we get x = 4. Therefore, the number is 4.

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Answer:

80°

Step-by-step explanation:

A triangle = 180° total.

Because it is a parallelogram, 40° is also the measure of BCE.

180° - 60° - 40° = 80°

BEC = 80°

Answer:

Calvin withdraws $ 60 each week

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Calvin's account balance difference than 8 weeks ago = - $ 360

Weekly amount Calvin deposits = $ 15

Number of weeks to compare = 8

2. What was his average withdrawal  each week?

Let's calculate the weekly average withdrawal this way:

Weekly average withdrawal = [Calvin's account balance difference than 8 weeks ago - (Weekly amount Calvin deposits * Number of weeks to compare)]/Number of weeks to compare

Replacing with the values given:

Weekly average withdrawal = [-360 - (15 * 8)]/8

Weekly average withdrawal = -360 - 120 / 8

Weekly average withdrawal = -480 / 8

Weekly average withdrawal = -60

Calvin withdraws $ 60 each week

Answer: It is only one can that can be filled up.

Step-by-step explanation: If 1 gas can can hold 10 L of gas and you only have 7 L then how can you fill up more than 1 gas can with only 7 L?  You don't have enough gas to fill up more than 1 gas can. So you are left with only 1 gas can filled but only with 7 L.  

Final answer:

To find the average density of a full gasoline can, both the mass of the gasoline (20.0 L multiplied by 0.75 kg/L for 15.0 kg) and the mass of the can (2.50 kg) are added to get a total mass of 17.5 kg. This is divided by the volume of gasoline the can holds (20.0 L) to yield an average density of 0.875 kg/L.

Explanation:

The question centers on calculating the average density of a gasoline can when it is full. To do this, we need to consider the total mass of the can and the gasoline together and the total volume they occupy.

The mass of the gasoline can itself is 2.50 kg. When full, the can holds 20.0 L of gasoline. Assuming the density of gasoline is 0.75 kg/L, we can calculate the mass of the gasoline as:

Mass of gasoline = 20.0 L × 0.75 kg/L = 15.0 kg

Then, we add the mass of the gasoline to the mass of the can to get the total mass:

Total mass = Mass of steel can + Mass of gasoline

Total mass = 2.50 kg + 15.0 kg = 17.5 kg

To find the average density, we use the formula:

Density = Total mass / Total volume

The volume here is the volume of gasoline the can holds since we typically ignore the thickness of the container in such calculations unless otherwise specified. Hence the average density is calculated based on the volume of gasoline only.

Average density = 17.5 kg / 20.0 L

Average density = 0.875 kg/L

This value represents the combined density of the steel can and the gasoline within it.

Answer:

36 inches

Step-by-step explanation:

since there are 12 inches in one foot, just do 12 x 3 which equals 36.

Answer:

reeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Step-by-step explanation:

Answer:

350 Miles

Step-by-step explanation:

140/40   =    x/100

x = 350

350 Miles

Let's denote the time Charlene left City A as [tex]\( t \).[/tex]

Since Charlene took 50 minutes (or [tex]\(\frac{50}{60} = \frac{5}{6}\) hours)[/tex] to reach City B, and she arrived at the same time as Hillary, we can set up the equation based on the distances traveled by both:

For Hillary:

[tex]\[ \text{Distance}_\text{Hillary} = \text{Speed}_\text{Hillary} \times \text{Time}_\text{Hillary} \]\[ \text{Distance}_\text{Hillary} = 120 \times (t + 1) \][/tex]

For Charlene:

[tex]\[ \text{Distance}_\text{Charlene} = \text{Speed}_\text{Charlene} \times \text{Time}_\text{Charlene} \]\[ \text{Distance}_\text{Charlene} = 144 \times \left(t + \frac{5}{6}\right) \][/tex]

Since they traveled the same distance, we can equate these two expressions:

[tex]\[ 120 \times (t + 1) = 144 \times \left(t + \frac{5}{6}\right) \][/tex]

Now, solve for \( t \):

[tex]\[ 120t + 120 = 144t + 120 \]\[ 24t = 120 \]\[ t = 5 \][/tex]

So, Charlene left City A at 5:00 a.m.

Answer: 1,000

First, you have to find how much 7.5% is coming out of 10,000. So in this case it's 750. Multiply 750 by 12 years. Thats 9000, you then subtract 9000 and 10,000 to get 1,000.

The future value of a $10,000 investment at a 7.5% annual interest rate compounded daily after 12 years is $22,589.67.

To calculate the future value of an investment that is compounded daily, we use the formula: FV = P ((1 + (r/n))^{nt}, where:

Given that the principal amount P is $10,000, the annual interest rate r is 7.5% (or 0.075 in decimal form), the number of times the interest is compounded per year n is 365, and the time t is 12 years, we plug these values into the formula:

FV = $10,000 ((1 + (0.075/365))^{365 * 12}

By calculating this amount, we find that the future value of the investment, to the nearest cent, would be $22,589.67.

Answer:

B

Step-by-step explanation:

STN is the alt exterior angle of angle 73 which means that it is congruent. STN is the vertical angle is MTQ which means that it is also equal to 73. Then you can use linear pair to find MTS. 180 - 73 which is 107.

Answer:

A

Step-by-step explanation:

Answer:

-0.259 or (√2 - √6) / 4

Step-by-step explanation:

Sin (195) using sum and difference formula.

Let's break the figure for convenience.

It becomes sin ( 135 + 60)

Invoking the sin formula we have

sin (A + B) = sin (A) cos (B) + cos (A) sin(B)

Where A = 135, B = 60

Therefore it becomes

sin(135) cos(60) + cos(135) sin (60)

From reference angle relationship we have:

(sin (45))cos (60) + cos (135) sin (60)

From trigonometric ratios, sin (45) = √2/2

Therefore, the equation becomes,

(√2/2) cos(60) + cos (135)sin (60)

(√2/2) (0.5) + cos (135) sin (60)

= (√2/2) (1/2) + ( - √2/2) ( √3/2)

Simplifying the equation

√2/4 + ( -√2/2) ( √3/2)

= √2/4 - √6/4

= (√2 - √6) / 4

OR

=( 1.414 - 2.449 ) / 4

= -1.035/4

= -0.25875

Answer:

x = [tex]\frac{1}{11}[/tex]; y = [tex]\frac{-60}{11}[/tex]

Step-by-step explanation:

x = -2y + 11 so x + 2y = 11                                                        (1)

12x - 6y = 12 so 6x - y = 6                                                            (2)

(1) - 2(2) ↔ (x + 2y) - 2(6x - y) = 11 - 2(6)

↔ - 11x = - 1

↔ x = [tex]\frac{1}{11}[/tex]

(2) ↔ y = 6x - 6 = 6([tex]\frac{1}{11}[/tex]) - 6 = [tex]\frac{6}{11}[/tex] - 6 = [tex]\frac{-60}{11}[/tex]

Brainliest???

Answer: the number is -7

-angie:)             pls mark me brainnliest!

Step-by-step explanation:

Explanation:

The easiest way to solve this equation is to write an equation and solve for the unknown number. This is the equation:

10

+

6

x

=

4

x

−

4

Subtract each side by 4x.

10

+

2

x

=

−

4

Subtract both sides by 10.

2

x

=

−

14

Divide by 2 on each side to isolate

x

.

x

=

−

7

So you have your answer: the number is

−

7

. To double-check your answer, you can plug this number back into the equation and see if it comes out to be true:

10

+

6

(

−

7

)

=

4

(

−

7

)

−

4

10

−

42

=

−

28

−

4

−

32

=

−

32

This equation is true, so you know

−

7

has to be the unknown number .

Answer:

-7

Step-by-step explanation:

10+6x=4x-4

-4x   -4x

10+2x=-4

-10    -10

2x=-14

/2     /2

x=-7

Answer:

angle AOC is what i think it is but please dont go on my word wait to see what other people say first sorry

Answer:

x=15

Step-by-step explanation:

x/5 =3

Multiply each side by 5

x/5 *5 = 3*5

x = 15

Answer:

Step-by-step explanation:

5+8(3+x)=5+24+8x=29+8x

x+3+5x=3+6x

5(z+4)+5(2-z)=5z+20+10-5z=30

Answer:

Part A = 64 feet

Part B = 79 feet

Step-by-step explanation:

Part A

10 × 2 = 20 = Diameter

Formula is C = π × diameter

20 × π = 62.8318530718 feet = 64 feet

Part B

25 × 2 = 50

Same formula

50 × π = 157.079632679 feet

157.079632679 ÷ 2 = 78.5398163395 feet = 79 feet

divide by 2 because it is a semi circle

Hope his helped :)

For the circular garden with a radius of 10 feet, 63 feet of edging is required. For the semicircular garden with a radius of 25 feet, 129 feet of edging is needed. These figures are obtained by calculating the circumference of a circle and a semicircle, then rounding to the nearest whole number.

To find out how much edging is needed for the gardens, we need to calculate the circumference of the circles.

Part A

The formula for the circumference of a circle (which is the distance around the edge) is 2πr, where π (pi) is approximately 3.14, and r is the radius. For a circle with a radius of 10 feet, the circumference is:

2 × 3.14 × 10 feet = 62.8 feet

Rounded to the nearest whole number, we need 63 feet of edging for the garden.

Part B

For a semicircle with a radius of 25 feet, the circumference is half that of a whole circle, plus the diameter (which is 2 × radius). So, first calculate the circumference of the whole circle and then divide by 2 and add the diameter:

(2 × 3.14 × 25 feet) / 2 + 2 × 25 feet = 78.5 feet + 50 feet = 128.5 feet

Rounded to the nearest whole number, we need 129 feet of edging for the semicircular garden.

Answer:

4

Step-by-step explanation:

Answer:

2+2 = 4

Step-by-step explanation:

2 + 2 = 4...

Answer:

154

Step-by-step explanation:

This ones tough so im not sure but try it. I hope this helps

Answer:

5741.11 m^2

Step-by-step explanation:

The formula for circumference is C=2(pi)r. Solve for r with the given info of the the circumference. r= 268.53/(2*3.14) r=42.76. The formula for area is (pi)r^2. Knowing r, substitute and solve.

Answer:

w = 10  

Step-by-step explanation

Answer:

53 = w        OR    10.6=w

 5

Step-by-step explanation:

-3(2w+5)+7w=5(w-11)

-6w-15+7w=5w-55

+6w    +6w

     -15+13=5w-55

     +15            +15

            13=5w-40

            +40    +40

            53=5w

             5     5

            53 = w        OR    10.6=w

              5

Hope that helps!! PLEASE GIVE ME BRAINLIEST!!!

Answer: No Solutions

Step-by-step explanation:

Define Variables:

​

May choose any letters.

\text{Let }d=

Let d=

\,\,\text{the number of dimes}

the number of dimes

\text{Let }q=

Let q=

\,\,\text{the number of quarters}

the number of quarters

\text{\textquotedblleft at most 25 coins"}\rightarrow \text{25 or fewer coins}

“at most 25 coins"→25 or fewer coins

Use a \le≤ symbol

Therefore the total number of coins, d+qd+q, must be less than or equal to 25:25:

d+q\le 25

d+q≤25

\text{\textquotedblleft a minimum of \$4.45"}\rightarrow \text{\$4.45 or more}

“a minimum of $4.45"→$4.45 or more

Use a \ge≥ symbol

One dime is worth $0.10, so dd dimes are worth 0.10d.0.10d. One quarter is worth $0.25, so qq quarters are worth 0.25q.0.25q. The total 0.10d+0.25q0.10d+0.25q must be greater than or equal to \$4.45:$4.45:

0.10d+0.25q\ge 4.45

0.10d+0.25q≥4.45

\text{Plug in }\color{green}{17}\text{ for }d\text{ and solve each inequality:}

Plug in 17 for d and solve each inequality:

Isabella has 17 dimes

\begin{aligned}d+q\le 25\hspace{10px}\text{and}\hspace{10px}&0.10d+0.25q\ge 4.45 \\ \color{green}{17}+q\le 25\hspace{10px}\text{and}\hspace{10px}&0.10\left(\color{green}{17}\right)+0.25q\ge 4.45 \\ q\le 8\hspace{10px}\text{and}\hspace{10px}&1.70+0.25q\ge 4.45 \\ \hspace{10px}&0.25q\ge 2.75 \\ \hspace{10px}&q\ge 11 \\ \end{aligned}

d+q≤25and

17+q≤25and

q≤8and

​

0.10d+0.25q≥4.45

0.10(17)+0.25q≥4.45

1.70+0.25q≥4.45

0.25q≥2.75

q≥11

​

\text{It is not possible to have }q\le 8\text{ AND to have }q\ge 11\text{.}

It is not possible to have q≤8 AND to have q≥11.

\text{Therefore there is NO SOLUTION}

Therefore there is NO SOLUTION

Isabella has to have a minimum of 11 but could have as many as 19 quarters to meet the criteria given in the question.

Isabella has 17 dimes which equates to $1.70 ($.10 x 17 = $1.70). We know she has to have a minimum of $4.45, so let's subtract the value of the dimes from this total ($4.45 - $1.70), resulting in $2.75. This remaining value must come from the quarters Isabella has. Since quarters are worth $0.25 each, we divide $2.75 by $0.25 to discover Isabella must have at least 11 quarters to reach the target dollar amount.

However, since Isabella could have 'at most 25 coins', we realize that she could also have potentially more quarters. We've established she has 17 dimes, so subtract that from the total of 25, resulting in 8. This means she could have in total between 11 (minimum requirement to reach the dollar amount) and 19 (maximum limitation placed by the coin total) quarters.

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Answer:

[tex]a_{n}[/tex] = - 4[tex](4)^{n-1}[/tex]

Step-by-step explanation:

Note the common ratio r between consecutive terms in the sequence, that is

- 16 ÷ - 4 = - 64 ÷ - 16 = - 256 ÷ - 64 = 4

This indicates the sequence is geometric with n th term ( explicit formula )

[tex]a_{n}[/tex] = a[tex](r)^{n-1}[/tex]

where a is the first term and r the common ratio

Here a = - 4 and r = 4, thus

[tex]a_{n}[/tex] = - 4 [tex](4)^{n-1}[/tex] ← explicit formula

Answer:

The length and the width of the rectangle are 11 units and 5 units

Step-by-step explanation:

Let us use the factorization to find the length and the width of the rectangle

∵ The trinomial is r² - 6r - 55

∵ r² = (r)(r)

∵ -55 = (-11)(5)

- Multiply r by -11 and r by 5, then add the products, the sum

   must be equal the middle term of the trinomial

∵ (r)(-11) = -11r

∵ (r)(5) = 5r

∵ -11r + 5r = -6r ⇒ the middle term of the trinomial

∴ r² - 6r - 55 = (r - 11)(r + 5)

- Equate each factor by 0 to find the value of r

∵ r - 11 = 0

- Add 11 to both sides

∴ r = 11

OR

∵ r + 5 = 0

- Subtract 5 from both sides

∴ r = -5 ⇒ rejected because no negative dimensions

∴ The length of the rectangle is 11 units

∵ The area of the rectangle is 55 units²

∵ Area of a rectangle = length × width

∴ 55 = 11 × width

- Divide both sides by 11

∴ 5 = width

∴ The width of the rectangle is 5 units

Answer: [tex]tan(x)^{2}[/tex]

Step-by-step explanation:

We will use the trigonometric identities to solve this problem:

[tex]\frac{sec(x)^{2}}{cot(x)^{2}+1}[/tex] (1)

Let's begin by the following trigonometric identity:

[tex]sec(x)^{2}=tan(x)^{2}+1[/tex] (2)

An substitute it in (1):

[tex]\frac{tan(x)^{2}+1}{cot(x)^{2}+1}[/tex] (3)

Then, taking into account [tex]tan(x)^{2}=\frac{sin(x)^{2}}{cos(x)^{2}}[/tex] and [tex]cot(x)^{2}=\frac{cos(x)^{2}}{sin(x)^{2}}[/tex], we rewrite (3):

[tex]\frac{\frac{sin(x)^{2}}{cos(x)^{2}}+1}{\frac{cos(x)^{2}}{sin(x)^{2}}+1}[/tex] (4)

[tex]\frac{\frac{sin(x)^{2}+cos(x)^{2}}{cos(x)^{2}}}{\frac{cos(x)^{2}+sin(x)^{2}}{sin(x)^{2}}}[/tex] (5)

Then, applying the trigonometric identity [tex]sin(x)^{2}+cos(x)^{2}=1[/tex]

[tex]\frac{1}{cos(x)^{2}}}{\frac{1}{sin(x)^{2}}}[/tex] (6)

Finally

[tex]\frac{sin(x)^{2}}{cos(x)^{2}}}=tan(x)^{2}[/tex] (7)

Answer:

28

Step-by-step explanation:

Answer:

Peter picked 28.

Step-by-step explanation:

1/3 of 84 is 28 because 84 divided 3 and multiplied by 1 is 28.