Answer:
The code is given below with appropriate comments for better understanding
Explanation:
#include <bits/stdc++.h>
using namespace std;
enum Digits {
zero,
one
} ;
struct CellType
{
Digits bit;
CellType* next;
};
class Minimum
{
public:
struct CellType* head,*temp; // head to point MSB
Minimum(string s)
{
int sz = s.size(); // binary size as per question it indicates n.
for(int i=0;i<sz;i++)
{
if(s[i] == '0') // if the bit is zero , we add zero at the end of stream
addAtEnd(zero);
else // if the bit is one , we one zero at the end of stream
addAtEnd(one);
}
addOne();
showlist();
}
CellType* create(Digits x) // to create a node of CellType*
{
CellType* t = new CellType();
t->bit = x;
t->next = NULL;
return t;
}
void addAtEnd(Digits x)
{
if(head == NULL) // if list is empty , then that will be the only node
{
CellType* t;
t = create(x);
head = temp = t;
}
else
{ // other wise we add the node at end indicated by the temp variable
CellType* t ;
t = create(x);
temp->next = t;
temp=temp->next;
}
}
void showlist()
{
// this is just a normla method to show the list
CellType* t = head;
while(t!=NULL)
{
cout<<t->bit;
t=t->next;
}
}
void addOne()
{
/*
here since we need to add from the end and it is a singly linked list we take a stack
and store in last in ,first out format .
Then we keep on changing all ones to zeroes until we find a zero int he list,
The moment a zero is found it should be changed to one.
If everything is one in the sequence , then we add a new zero digit node at the beginning of the list.
*/
stack<CellType*> st;
CellType* t = head;
while(t!=NULL)
{
st.push(t);
t=t->next;
}
while(st.size()>0 && (st.top())->bit == one )
{
CellType* f = st.top();
f->bit = zero ;
st.pop();
}
if(st.size())
{
CellType* f = st.top();
f->bit = one ;
}
else
{
t = create(one);
t->next = head;
head = t;
}
}
};
int main()
{
/*
Here i am taking an integer as input and then converting it to binary using a string varaible s
if you want to directly take the binary stream as input , remove the comment from "cin>>s" line.
*/
long long int n,k;
cin>>n;
string s;
k = n;
while(k>0)
{
s = s + (char)(k%2 +48);
k=k/2;
}
reverse(s.begin(),s.end());
//cin>>s;
Minimum* g = new Minimum(s);
return 0;
}
You will be given a string, containing both uppercase and lowercase alphabets(numbers are not allowed).
You have to print all permutations of string with the added constraint that you can’t change the uppercase alphabets positions.
Example: (puNeeTgUlia)
Answer:
The Java code is given below with appropriate comments
Explanation:
import java.util.*;
class Main {
static Set<String> set = new HashSet();
static void printPerms(char ch[], int ind){
//If end of string is reached, add it to set
if(ind==ch.length){
set.add(new String(ch));
return;
}
for(int i=ind;i<ch.length;i++){
//Only swap if lower case
if((ch[i]>='a' && ch[i]<='z')&&((ch[ind]>='a' && ch[ind]<='z'))){
char t = ch[i];
ch[i] = ch[ind];
ch[ind] = t;
}
printPerms(ch,ind+1);
if((ch[i]>='a' && ch[i]<='z')&&((ch[ind]>='a' && ch[ind]<='z'))){
char t = ch[i];
ch[i] = ch[ind];
ch[ind] = t;
}
}
}
public static void main(String[] args) {
printPerms("aBbCc".toCharArray(),0);
System.out.println(set);
}
}
Final answer:
The question involves creating an algorithm to generate permutations of a given string without altering the positions of uppercase alphabets, a problem suitable for Computers and Technology at the college level.
Explanation:
The task requires generating all permutations of a given string while maintaining the original positions of the uppercase alphabets. This is typically a problem that can be approached algorithmically, falling under the category of Computers and Technology. To solve it, you would need to find permutations of the lowercase letters only and then insert them back into the string at the positions not occupied by uppercase letters.
One way to achieve this is to extract all lowercase letters and use a permutation algorithm, such as Heap's algorithm, to generate all permutations while the uppercase letters act as anchors, holding their respective positions fixed. As each permutation of the lowercase letters is generated, it's interlaced with the uppercase ones to construct a full-string permutation that meets the condition. This process is repeated until all permutations of the lowercase characters are exhausted.
Write a program that keeps asking the user for new values to be added to a list until the user enters 'exit' ('exit' should NOT be added to the list). These values entered by the user are added to a list we call 'initial_list'. Then write a function that takes this initial_list as input and returns another list with 3 copies of every value in the initial_list. Finally, inside main(), print out all of the values in the new list. For example: Input: Enter value to be added to list: a Enter value to be added to list: b Enter value to be added to list: c Enter value to be added to list: exit Output: a b c a b c a b
Answer:
def new_list_function(initial_list):
new_list = initial_list*3
return new_list
def main():
initial_list = []
while True:
item = input("Enter value to be added to list: ")
item = item.rstrip()
if item.lower() == "exit" and "EXIT" and "Exit":
break
initial_list.append(item)
new_list = new_list_function(initial_list)
for item in new_list:
print(item)
main()
Explanation:
Define the function new_list_function(). Compute the new_list and then return the new_list. Define the main() function. Inside the main function, loop to ask users for values.Finally print the new list.Some variables have been assigned for you and the output statements have been written. Read the starting code carefully before you proceed to the next step. Write the Python code needed to perform the following: Calculate state withholding tax (stateTax) at 6.5 percent Calculate federal withholding tax (federalTax) at 28.0 percent. Calculate dependent deductions (dependentDeduction) at 2.5 percent of the employee’s salary for each dependent. Calculate total withholding (totalWithholding) as stateTax + federalTax + dependentDeduction. Calculate take-home pay (takeHomePay) as salary - totalWithholding Execute the program by clicking the Run button at the bottom. You should get the following output: State Tax: $81.25 Federal Tax: $350.00000000000006 Dependents: $62.5 Salary: $1250.0 Take-Home Pay: $756.25 In this program, the variables named salary and numDependents are initialized with the values 1250.0 and 2. To make this program more flexible, modify it to accept interactive input for salary and numDependents.
Answer:
salary = 1250
numofDependents = 2
stateTax = (6.5/100)*salary
federalTax = (28/100)*salary
dependentDeduction = ((2.5/100)*salary)*(numofDependents)
totalWithHolding = stateTax+federalTax+dependentDeduction
takeHomePay = salary - totalWithHolding
print('State Tax: {}'.format(stateTax))
print('Federal Tax: {}'.format(federalTax))
print('Dependents: {}'.format(dependentDeduction))
print('Salary: {}'.format(salary))
print('Take Home: {}'.format(takeHomePay))
MODIFIED TO ACCEPT FOR SALARY AND NUMBER OF DEPENDENTS
salary = float(input("Please enter your salary: "))
numofDependents = int(input("How many dependents do you have "))
stateTax = (6.5/100)*salary
federalTax = (28/100)*salary
dependentDeduction = ((2.5/100)*salary)*(numofDependents)
totalWithHolding = stateTax+federalTax+dependentDeduction
takeHomePay = salary - totalWithHolding
print('State Tax: {}'.format(stateTax))
print('Federal Tax: {}'.format(federalTax))
print('Dependents: {}'.format(dependentDeduction))
print('Salary: {}'.format(salary))
print('Take Home: {}'.format(takeHomePay))
Explanation:
See the attached screen shot for the input and program output
The input Statement in python is used to receive and store the values for salary and number of dependents
Final answer:
To calculate the taxes and take-home pay in Python, modify the code to accept user input for salary and dependents, then calculate state and federal tax, dependent deductions, total withholding, and take-home pay. The input is processed to dynamically produce the specified outputs, including taxes and deductions.
Explanation:
To calculate the taxes and take-home pay in Python, we would start by modifying the initial code to accept user input for the salary and the number of dependents. This can be done using the input() function in Python. After obtaining these inputs, we apply the specified rates to calculate state withholding tax, federal withholding tax, and dependent deductions. Finally, we calculate the total withholding and take-home pay.
Here is an example of how the code could look:
salary = float(input('Enter your salary: '))
numDependents = int(input('Enter the number of dependents: '))
stateTax = salary * 0.065
federalTax = salary * 0.28
dependentDeduction = salary * 0.025 * numDependents
totalWithholding = stateTax + federalTax + dependentDeduction
takeHomePay = salary - totalWithholding
print(f'State Tax: $',stateTax)
print(f'Federal Tax: $',federalTax)
print(f'Dependents: $',dependentDeduction)
print(f'Salary: $',salary)
print(f'Take-Home Pay: $',takeHomePay)
This code snippet will dynamically calculate the taxes and take-home salary based on the user's input, making the program more useful and interactive.
TV stations in the U.S. normally broadcast horizontally-polarized signals. Is this TV antenna mounted correctly, or should it be rotated?
It would be best to start positioning the antenna horizontally because the majority of TV transmitters are horizontally polarized. Antennas from One For All can pick up both horizontal and vertical signals.
What TV networks horizontally polarized programming?The most used antennas for television broadcasting emit signals that are horizontally polarized. In other words, the TV signal's plane is perpendicular to the earth's surface.
Aside from this, however, evidence suggests that using horizontal polarization at UHF gives benefits due to the higher directivity achievable at the receiving antennas, which lessens the impact of reflected waves, especially in urban areas.
Therefore, Outdoor TV antennae are placed horizontally rather than vertically because of this.
Learn more about polarized signals here:
https://brainly.com/question/14428334
#SPJ5
A TV antenna should be oriented horizontally for optimal reception of horizontally-polarized signals. Aligning a straight wire antenna or a loop antenna correctly ensures the strongest possible reception. Short wave antennas have a different orientation to utilize the ionosphere for long-distance signal transmission.
For optimal reception of horizontally-polarized signals, a TV antenna should be oriented horizontally. This alignment maximizes the pickup of the electric component of the electromagnetic wave, which is crucial for a clear signal. Conversely, if signals are broadcast using a vertical transmitter antenna, a straight wire antenna should be vertical to best receive the radio waves. This is essential because the strongest signal radiates perpendicularly to the antenna, ensuring equal signal distribution in all horizontal directions. A loop antenna should be aligned so that its plane is perpendicular to the direction of the incoming signal for the best reception. This plane orientation allows the loop antenna to maximize the induction of current by the electromagnetic waves, enhancing the received signal's strength.
In the context of signal reception at long distances, short wave antennas may be oriented horizontally so the signal can bounce off the ionosphere and travel a greater distance back to Earth. For TV signals, the video component is usually transmitted as amplitude modulation (AM), while the audio is frequency modulation (FM). It's important to note that these are characteristics of over-the-air broadcasting using traditional rooftop antennas, as opposed to satellite dishes or cable systems, which operate at significantly higher frequencies and use different technologies such as high-definition (HD) formats.
Task 1 (25 points): In database [your Pitt username], create the following entity tables: movies actors locations Each tables logical structure should correspond to the descriptions provided in this assignment. Use CREATE TABLE statement. Task 2 (20 points): In your database, create the following junction tables: movies_actors movies_locations Use CREATE TABLE statement to create junction tables. Task 3 (20 points): For each entity table, insert at least 3 rows using INSERT statement: At least 3 movies in the movies table At least 3 actors in the actors table At least 3 locations in the locations table You can make up your own data for the INSERT statements. Task 4 (10 points): For each junction table, create at least 2 relationships (insert at least two rows of appropriate IDs).
Answer:
Following is given the detailed solution for each part.
I hope it will help you!
Explanation:
Write code that prints: Ready! firstNumber ... 2 1 Run! Your code should contain a for loop. Print a newline after each number and after each line of text Ex: firstNumber = 3 outputs:
Final answer:
The task requires a Python code using a for loop to count down from a specified starting number, printing 'Ready!', each number on a new line, and 'Run!' at the end.
Explanation:
To write code that counts down from a given number and prints 'Ready!', followed by each number, and ending with 'Run!', we can use a for loop. Here is a sample Python code snippet that accomplishes this:
firstNumber = 3
print('Ready!')
for num in range(firstNumber, 0, -1):
print(num)
print('\n')
print('Run!')
This code starts by printing 'Ready!', then it enters a for loop that counts down from firstNumber to 1, printing each number followed by a newline. Finally, it prints 'Run!' after exiting the loop. Remember to replace firstNumber with the actual starting number you wish to count down from.
write a program that takes 10 numbers as input and displays the mode of the numbers using parallel arrays and a method that takes an array of numbers as a parameter and returns the value that appears most often in the array
Answer:
The Java program is explained below
Explanation:
public class ArrayMode {
public static int mode(int arr[]) {
int maxValue = 0, maxCount = 0;
for (int i = 0; i < arr.length; ++i) {
int count = 0;
for (int j = 0; j < arr.length; ++j) {
if (arr[j] == arr[i])
++count;
}
if (count > maxCount) {
maxCount = count;
maxValue = arr[i];
}
}
return maxValue;
}
public static void main(String args[]) {
int arr[] = { 9, 5, 3, 8, 5, 12, 19, 5, 11 };
System.out.println("The set of numbers are: ");
for (int i = 0; i < arr.length; i++)
System.out.print(arr[i] + " ");
System.out.println("\nThe mode of the set is: " + mode(arr));
}
}
Define a function print total inches, with parameters num_feet and num_inches, that prints the total number of inches. Note: There are 12 inches in a foot. Sample output with inputs: 5 8 Total inches: 68
Answer:
public static void printTotalInches(double num_feet, double num_inches){
double inches = 12*num_feet;
System.out.println("Total value in feets is: "+(inches+num_inches));
}
This function is written in Java Programming Language. Find a complete program with a call to the function in the explanation section
Explanation:
public class ANot {
public static void main(String[] args) {
//Calling the function and passing the arguments
printTotalInches(5,8);
}
public static void printTotalInches(double num_feet, double num_inches){
double inches = 12*num_feet;
System.out.println("Total value in feets is: "+(inches+num_inches));
}
}
Answer:
def calc_total_inches(num_feet, num_inches):
return num_feet*12+num_inches
Explanation:
Which of the following greedy strategies results in an optimal solution for the activity selection problem? Select all that applies. a. Earliest start time b. Latest finish time c. Earliest finish time d. Latest start time
Answer:
Option C and Option D.
Explanation:
When the title indicates, a greedy algorithm often makes the decision which imply to be the best overall. Which obviously makes a locally-optimal choice throughout the expectation that such a option can contribute to an answer that is generally optimal.
so, Earliest finish time and latest start time are the greedy methods resulting in an effective solution for the problems of operation selection.
What is the largest numeric value that could be represented with three bytes if each digit were encoded using one ASCII pattern per byte? What if binary notation were used?
The largest numeric value that can be represented in 3 bytes is 224
Explanation:
commonly, to represent a 999 number, 10 bits are used.But with 3 bytes, it can save or store integer with the range from 0 to 224-1 in the 24 bits. (3 * 8 bits =24 bits).Then the binary notation is used for encoded numeric data in order to store in the computer storage device.Final answer:
The largest value with three bytes using ASCII is 127127127, but for practical numerical storage in binary notation, the largest value with three bytes is 16777215, represented as 11111111 11111111 11111111 in binary.
Explanation:
The largest numeric value that could be represented with three bytes using one ASCII pattern per byte depends on the ASCII printable characters range. ASCII characters are represented within the range of 0 to 127, therefore in three bytes, the largest decimal values you could represent would be 127127127. However, this is not typically how numeric values are stored.
When using binary notation, each byte consists of 8 bits, and the maximum value for each bit is 1. Therefore, the largest value in a single byte is 11111111, which is 255 in decimal. Hence, in three bytes, the largest decimal number that can be stored is 16777215 (which is 11111111 11111111 11111111 in binary).
Cipher Block Chaining (CBC) is similar to Electronic Code Book (ECB) but it uses an initialization vector (IV) to add security. True False
Answer:
The correct answer to the following question will be "True".
Explanation:
The most common heritage authentication mode is the CBC (Common legacy encryption) mode. Implementation around an internal ECB style cipher is simple and easy to understand and marginal.An initial value (IV) must be selected at random, even for the CBC function, but this doesn't have to be hidden.Therefore, the given statement is true.
Implement the make change algorithm you designed in the previous problem. Your program should read a text file "data.txt" where each line in "data.txt" contains three values c, k and n. Please make sure you take your input in the specified order c, k and n. For example, a line in "data.txt" may look like the following:3 4 38
where c = 3,k = 4,n = 38. That is, the set of denominations is {30,31,32,33,34} = {1,3,9,27,81}, and we would like to make change for n = 38. The file "data.txt" may include multiple lines like above.
The output will be written to a file called "change.txt", where the output corresponding to each input line contains a few lines. Each line has two numbers, where the first number denotes a de- nomination and the second number represents the cardinality of that denomination in the solution. For example, for the above input line ‘3 4 38’, the optimal solution is the multiset {27, 9, 1, 1}, and the output in the file "change.txt" is as follows:
27 1 91 12
which means the solution contains 1 coin of denomination 27, one coin of 9 and two coins of denomination
Answer:
Answer explained below
Explanation:
Below is the code for Greedy change algorithm in C++. Please let me know what does c ,k and represent in the question. so that i can update according to requirement
#include <bits/stdc++.h>
using namespace std;
int deno[] = { 1, 3,9,27,81 };
int n = sizeof(deno) / sizeof(deno[0]);
void findMin(int V)
{
// Initialize result
vector<int> ans;
// Traverse through all denomination
for (int i = n - 1; i >= 0; i--) {
// Find denominations
while (V >= deno[i]) {
V -= deno[i];
ans.push_back(deno[i]);
}
}
// Print result
for (int i = 0; i < ans.size(); i++)
cout << ans[i] << " ";
}
int main()
{
int n = 38;
cout << "Following is minimal number of change for " << n << ": ";
findMin(n);
return 0;
}
Discuss what technologies you might see in use at an enterprise. For example, where would you most likely see fiber-optic Ethernet technologies? Or where might wireless technologies be deployed?
There are various connectivity technologies that we use to connect. They are Ethernet, Internet (Wireless Connection), Bluetooth, Wi-Fi and Cellular.
Explanation:
Ethernet is the direct connection among the devices that are located close to each other in a building. This is used for small scale enterprises.Wi-Fi lets wireless connections among multiple devices without any physical connection. And it is most extensively used in most of the corporate companies.Bluetooth is used to transfer the data from one device to the other when they are near.Cellular is used to connect people across the globe. And it is used widely in every enterprises.Final answer:
In an enterprise, fiber-optic Ethernet is used for its high bandwidth and long-distance capabilities, typically in the network backbone, while wireless technologies like Wi-Fi are deployed for their convenience and mobility in offices and meeting spaces. The use and impact of technology can vary across different contexts, and strategic decisions must be made when developing IT infrastructures to ensure efficiency and security.
Explanation:
In an enterprise, you might see a range of technologies in use, each tailored to specific needs and applications. Fiber-optic Ethernet technologies, for instance, are often found in the backbone of an enterprise’s network infrastructure where high bandwidth and long-distance communication are essential.
They might be used to connect data centers, mainframes, or to handle high-speed internet connections for the entire organization.
Wireless technologies, on the other hand, are typically deployed in areas where mobility is important or where it is impractical to run physical cabling.
This includes offices for Wi-Fi connections to laptops and smartphones, warehouses for barcode scanning devices, and meetings or conference rooms to facilitate presentations and collaborative work without the need for physical connections.
Wi-Fi is an example of a wireless service that has become indispensable in both professional and personal contexts, offering convenience and mobility.
When considering the integration of technology, it's important to assess the impact it has on communication across various contexts, such as academic, professional, and personal.
Engagement with technology can vary greatly; for example, the use of sophisticated online platforms may be prevalent in professional settings, while personal communication might still favor traditional methods like phone calls or face-to-face interactions in certain contexts.
Additionally, the development of efficient and secure physical IT infrastructures to facilitate public e-services requires a strategic approach, weighing options such as outsourcing versus in-house development based on criteria like security and transmission capacity.
According to a study by Merrill Lynch and Gartner, what percentage of all corporate data is captured and stored in some sort of unstructured form?
Answer:
85 %
Explanation:
Historically, data warehouses had been formed using structured repetitive data that was filtered before entering the data warehouse. However, in recent years, the data warehouse has evolved due to contextual information that can now be attached to unstructured data and that can also be stored.
Those first structured relational data could not be mixed and matched for analytical subjects with unstructured textual data. But with the advent of contextualization, these types of analyzes can now be done naturally and easily.
Classic analytical processing of transaction-based data is performed in the data warehouse as it has always been done. Nothing has changed there. But now you can become analytical about contextualized data, and that form of analysis is new. Most organizations, until now, did not have to base their decision making on unstructured textual data. And now there is a new way of analysis possible in a Data Warehouse: the possibility of mixing analysis. The combined analysis is performed by a combination of structured transactional data and unstructured contextual data.
According to a research by Merrill Lynch indicates that 85 % of all coporate date is stored in some sort of unstructured form like data warehouse.
Web crawlers or spiders collect information from Web pages in an automated or semi-automated way. Only the text of Web pages is collected by crawlers. True False
Answer:
The correct answer to the following question will be "False".
Explanation:
Web crawlers make copies of google search recovery pages that index the streamed pages to allow subscribers to more effectively search. It collects details of Web pages in an automatically generated or semi-automated form.The code of HTML and Hyperlink can be checked by crawlers. They could be used for scraping of the web.Therefore, the given statement is false.
Describe the benefits of digital technology. Eric reads interesting information about MP3 players and wants to buy one. Which of the following tasks can he perform by using an MP3 playera. Send e-mail messages b. Play music c. Capture movies d. Create graphics
Answer:
b. Play music
Explanation:
Digital technology helps improve an existing process and makes things better. In this scenario of an MP3 player, digital technology takes care of music. Before a portable MP3 player came into the picture, people had to carry large physical records or multiple CD packs but now, a small device can hold thousands of those same songs in it.
Suppose two hosts, A and B, are separated by 15,000 kilometers and are connected by a direct link of R = 5 Mbps. Suppose the propagation speed over the link is 2.5 * 108 meters/sec.How long does it take to send a 1,500,000 bit file, assuming it is sent continuously?
Answer:
360 msec
Explanation:
Data provided in the question:
Distance between the two hosts = 15,000 kilometer
= 1.5 × 10⁷ m [ ∵ 1 km = 1000 m ]
Transmission rate, R = 5 Mbps = 5 × 10⁶ bits per second
Propagation speed over the link = 2.5 × 10⁸ meters/sec
Size of file to be sent = 1,500,000 bit
Now,
Propagation delay (dprop)
= Distance ÷ Speed
= ( 1.5 × 10⁷ ) ÷ (2.5 × 10⁸)
= 0.06 sec
= 60 msec [ ∵ 1 sec = 1000 millisecond ]
Transmission delay (dtrans)
= Size of file ÷ Rate of transmission
= 1500000 ÷ ( 5 × 10⁶ )
= 0.3 sec
= 300 msec
Therefore,
Time required for transmitting the file
= Propagation delay + Transmission delay
= 60 msec + 300 msec
= 360 msec
Final answer:
The total time to send a 1,500,000-bit file from host A to host B over a distance of 15,000 kilometers at a rate of 5 Mbps is 0.36 seconds, which is the sum of the transmission time (0.3 seconds) and the propagation delay (0.06 seconds).
Explanation:
To calculate the time taken to send a 1,500,000-bit file from host A to host B separated by 15,000 kilometers at a rate of 5 Mbps, you need to consider both the transmission time and the propagation delay. The transmission time is the time required to push all the file's bits onto the wire and is given by the file size divided by the transmission rate. The second part is the propagation delay, which is the time it takes for the first bit to travel from the source to the destination.
The transmission time can be calculated as: Transmission Time = File size / Rate = 1,500,000 bits / (5 x 10⁶ bits/sec) = 0.3 seconds.
The propagation delay is the distance divided by the speed of light in the medium, which is: Propagation Delay = Distance / Speed of light = 15,000 km / (2.5 x 10⁸ m/s) = 0.06 seconds. Since the distance needs to be in meters, we convert it by multiplying by 1,000: Propagation Delay = 15,000,000 m / (2.5 x 10⁸ m/s) = 0.06 seconds.
The total time to send the file is the sum of transmission time and propagation delay: Total Time = Transmission Time + Propagation Delay = 0.3 s + 0.06 s = 0.36 seconds.
_____ verifies that an individual demonstrated a certain level of knowledge and skill on a standardized test.
Answer:
Certification
Explanation:
Certification verifies that a person has appropriate experience and skills to carry out their task or job.
This is achieved through some test or examination, through some professional training or by gaining some work experience.
This provides with the credentials required to perform their jobs efficiently with proficient skills that can be trusted by companies and customers.
For example having an IT certification means having necessary skills to perform IT related tasks. IT field is a vast field which keeps evolving with time so being an IT certified refers to having updated knowledge about dynamic computer and information technologies.
In this recitation assignment, will write a complete C program that accepts as input any two integers from the user and swaps both integers using bitwise operators only without a third variable. E
Answer:
#include<iostream>
using namespace std;
int main()
{int num1,num2;
cout<<"enter 2 numbers:"<<endl;
cinn>>num1;
cinn>>num2;
cout<<("value without swapping of num1",num1);
cout<<("value without swapping of num2",num2);
num1 ^= num2;
num2 ^= num1;
num1 ^= num2;
cout<<("num1 after swapping",num1);
cout<<("num2 after swapping,num2);
return 0;
}
You are the manager of a midsized company that assembles personal computers. You purchase most components—such as random access memory (RAM)—in a competitive market. Based on your marketing research, consumers earning over $80,000 purchase 1.5 times more RAM than consumers with lower incomes. One morning, you pick up a copy of The Wall Street Journal and read an article indicating that input components for RAM are expected to rise in price, forcing manufacturers to produce RAM at a higher unit cost. Based on this information, what can you expect to happen to the price you pay for random access memory? Would your answer change if, in addition to this change in RAM input prices, the article indicated that consumer incomes are expected to fall over the next two years as the economy dips into recession? Explain.
Answer:
Explanation:
In this case, the price of the RAM can rise because cost increase, assume the news of the Wall Street Journal, people with earning lower $80,000 they won't buy RAM because is too expensive, and people with over these earnings will buy less RAM, in addition, the incomes will fall, and the demand of RAM will fall too, but for the same reason the price could fall for the poor demand.
Universal containers wants to provide a different view for its users when they access an Account record in Salesforce1 instead of the standard web version. How can this be accomplished
Answer:
There are four options for this question: A and D are correct.
A. By adding a mobile layout and assigning it to a profile.
B. By adding quick actions in the publisher section
C. By adding actions in the Salesforce1 action bar section.
D. By adding Visualforce page to the mobile cards section.
Explanation:
We can add a different view for the users instead of the standard web, we can use a mobil design and assign a different profile, addition, we can implement the visualforce page to create a new view, with this option we make a better and interesting user interface with interaction with different views.
The Internet has made going global easier than it has ever been, but the promise of "borderless commerce" remains restrained because of the a. cultural variations of the people visiting a website. b. old brick-and-mortar rules, regulations, and habits. c. system of floating exchange rates. d. demographic makeup of various people accessing a website.
Answer:
The correct option is B: Old brick-and-mortar rules, regulations, and habits
Explanation:
Globalization has been made possible because of the internet. However, the promise of what is considered "borderless commerce" is limited due to the old brick and mortar rules, regulations, and habits. Brick and mortar is considered the traditional businesses offering products and services to customer in a rented or owned store and requires face-to-face business. Hence globalization via the internet is limited because companies have to sort out their building and stores, follow every law and regulation to opening offices and other habits practiced by these brick-and-mortar businesses.
Describe the basic features of the relational data model and discuss their importance to the end user and the designer. Describe the Big Data phenomenon.
Answer:
The answer to this question can be described as follows:
Explanation:
Relational data model:
The use of data tables to organize sets of entities into relationships requires a relational data model. this model work on the assumption, which is a primary key or code, that is included in each table configuration. The symbol for "relational" data links and information is used by other tables.
Model Design:
This model is used for database management, it consists of structure and language consistency. It is design in 1969.
Importance of data model:
This provides a common standard for processing the potentially sound data in machines, that was usable on almost any one device.
Big Data:
It moves to locate new and innovative ways to handle large volumes of authentication tokens and to gather business insights when offering high efficiency and usability at an affordable cost at the same time.
An internet service provider has three different subscription packages for its customers. Package A: For $9.95 per month 10 hours of access are provided. Additional hours are $2.00 per hour. Package B: For $14.95 per month 20 hours of access are provided. Additional hours are $1.00 per hour. Package C: For $19.95 per month unlimited access is provided. Your task is to write a program that calculates a customer's monthly bill. The program must ask the user which package the customer has purchased and how many hours were used for the current month. It must then display the total amount due. In addition to calculating the monthly bill for the user's current package, your program must do the following: display how much money Package A customers would save if they purchased packages B or C, and how much money Package B customers would save if they purchased Package C. If there would be no savings, no message will be printed for a particular case.
Answer:
C++.
Explanation:
int main() {
const float package_A = 9.95;
const float package_B = 14.95;
const float package_C = 19.95;
const int package_A_extra = 2;
const float package_B = 1;
/////////////////////////////////////////////////////////////////////////////
int user_package_choice;
int hours_used;
cout<<"Your package? Enter option number,"<<endl;
cout<<"1. Package A"<<endl<<"2. Package B"<<"3. Package C";
cout<<endl;
cin<<user_package;
cout<<endl;
cout<<"Hours used?: ";
cin<<hours_used;
/////////////////////////////////////////////////////////////////////////////
cout<<endl;
float total_amount;
if (user_package_choice == 1) {
total_amount = package_A + ((hours_used - 10) * package_A_extra));
if (total_amount - (package_B + ((hours_used - 20) * package_B_extra)) > 0)
cout<<"If you had opted for Package B, you would have saved $"<<total_amount - (package_B + (hours_used * package_B_extra))<<endl;
if (total_amount - package_C > 0)
cout<<"If you had opted for Package C, you would have saved $"<<total_amount - package_C;
}
else if (user_package_choice == 2) {
total_amount = package_B + ((hours_used - 20) * package_B_extra);
if (total_amount - package_C > 0)
cout<<"If you had opted for Package C, you would have saved $"<<total_amount - package_C;
}
else {
total_amount = package_C;
}
return 0;
}
Final answer:
A program is needed to compute a customer's monthly internet bill based on their subscription package and calculate potential savings for switching to other packages.
Explanation:
The task involves writing a program to calculate a customer's monthly bill based on the subscription package for internet access. There are three packages: Package A offers 10 hours for $9.95 with additional hours at $2 each, Package B provides 20 hours for $14.95 with additional hours at $1 each, and Package C offers unlimited access for $19.95. The program will also calculate potential savings for customers of Package A if they switch to Package B or C, and for Package B customers if they switch to Package C, provided switching would result in savings.
In this exercise we examine in detail how an instruction is executed in a single-cycle datapath. Problems in this exercise refer to a clock cycle in which the processor fetches the following instruction word:
10101100100001010000000000010100
Assume that the data memory is all zeros and that the processor’s registers have the following values at the beginning of the cycle in which the above instruction word is fetched:
R0 R1 R2 R3 R4 R5 R6 R8 R12 R31
0 1 -2 3 -4 5 -6 -8 -12 31
a, What are the outputs of the sign-extend and the jump "Shift-Left-2" (near the top of Figure 4.24) for this instruction word?
b, What are the values of ALU control unit’s inputs (ALUOp and Instruction operation) for this instruction?
c, What is the new PC address after this instruction is executed? Highlight the path through which this value is determined.
d, For the ALU and the two add units, what are their data input values?
e, What are the values of all inputs for the "Registers" unit?
Following are the responses to the given question:
Given instruction:
[tex]10101100100001010000000000010100[/tex]
For point A)
Sign extend and leap "shift left 2": The sign extend can be determined by taking the LSB 16 bits and expanding it to 32 bits.
Sign Extend
[tex]00000000000000000000000000010100[/tex]
A jump command "shift left 2" can be discovered by extracting the LSB 26 bit and shifting left by 2 bits.
Jump Shift Left 2
[tex]0010000101000000000001010000[/tex]
For point B)
ALU control units' inputs are as follows:
Its ALUop has two LSBs.
[tex]ALUop\\\\00[/tex]
The instructions are a 6 bit LSB instruction.
Instruction
[tex]010100[/tex]
For point C)
New PC address:
[tex]New PC Address \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Path \\\\ PC+4 \ \ \ \ \ \ \ \ PC \to Add (PC +4) \to Branch MUX \to Jump MUX \to PC[/tex]
For point D)
Input values:
[tex]ALU \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Add (PC+4) \ \ \ \ \ \ \ \ \ \ \ Add (Branch)[/tex]
[tex]In put \#1 \ \ \ In put \# 2 \ \ \ \ In put \# 1 \ \ \ In put \# 2 \ \ \ \ In put \# 1 \ \ \ In put \# 2\\\\[/tex]
[tex]-4 \ \ \ \ 20 \ \ \ \ \ \ PC \ \ \ \ 4 \ \ \ \ \ \ PC+4 \ \ \ \ 20*4[/tex]
For point E)
Calculating the inputs into the "Registers" units:
[tex]\text{Bits\ 25-21 specify the Read Reg#1} \\\\\text{Bits\ 20-16 specify the Read Reg#2}[/tex]
[tex]Read \ \ \ \ \ \ Read \\\\Reg\#1 \ \ \ \ \ \ Reg\#2 \ \ \ \ \ \ WriteReg \ \ \ \ \ \ WriteData\ \ \ \ \ \ RegWrite[/tex]
[tex]4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ X \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ X \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0[/tex]
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brainly.com/question/25222612
Assume you have a byte-addressable machine that uses 32-bit word (integers are 32-bit) and you are storing the following information: the string Inventory followed by a value (569)10 followed by another string Price followed by a value (49.75)10. Also, assume that floating point numbers are stored as single-precision IEEE 754 with 127 excess. a) Show (as hex numbers with word boundary) how this is stored on a big-endian machine. b) Show (as hex numbers with word boundary) how this is stored on a little-endian machine.
Final answer:
The question involves displaying how a string and numerical data will be stored in hexadecimal format in memory on a machine with both big-endian and little-endian architectures. The storage pattern involves converting ASCII strings and numbers into hexadecimal format and then storing them sequentially in memory according to the endianess. Exact hexadecimal values would require ASCII and IEEE 754 format conversions.
Explanation:
The given question involves storing textual and numerical data on a byte-addressable machine that uses 32-bit integers and single-precision floating-point format, according to the IEEE 754 standard. The data to be stored includes a string 'Inventory', a decimal integer value (569)10, a string 'Price', and a decimal floating-point number (49.75)10. We are asked to show how this information would be stored in both big-endian and little-endian representation. Firstly, we need to translate the ASCII strings and numerical values into hexadecimal, suitable for storage in memory:
The string 'Inventory' is broken into 32-bit words and converted to hexadecimal.
The integer value 569 is represented in hexadecimal as 0x00000239.
The string 'Price' is similarly broken into 32-bit words and converted to hexadecimal.
The floating-point number 49.75 is converted into IEEE 754 single-precision format and represented in hexadecimal.
For big-endian representation, the most significant byte (MSB) is stored at the lowest memory address:
Each character of 'Inventory' and 'Price' is represented by its ASCII hexadecimal value and stored in sequential memory addresses, starting with the MSB.
The integer and floating-point numbers are stored with their MSB first in the 32-bit word boundary.
For little-endian representation, the least significant byte (LSB) is stored at the lowest memory address:
Each character of 'Inventory' and 'Price' is represented in reverse order compared to big-endian.
The integer and floating-point numbers are also reversed, with the LSB first.
The exact hexadecimal values in memory would depend on the binary representations of the strings and the specifics of the IEEE 754 conversion process for the number 49.75.
Write a program that dynamically allocates an array large enough to hold a user-defined number of test scores. Once all the scores are entered, the array should be passed to a function that sorts them in ascending order. Another function should be called that calculates the average score. The program should display the sorted list of scores and averages with appropriate headings. Use pointer notation rather than array notation whenever possible. Input Validation: Do not accept negative numbers for test scores.
Answer:
C++ Program
Explanation:
#include <iostream>
#include <iomanip>
using namespace std;
void arrSelectSort(double *, int);
void showArrPtr(double *, int);
void showAverage(double, int);
int main()
{
//dynamically allocate an array
//acumulator
//averge scores
//number of test scores
double *scores,
total = 0.0;
//average;
int nScores;
//Get how many test scores the users wants to enter.
cout << "How many test scores would you like to process?";
cin >> nScores;
//condition about the scores
scores = new double[nScores];
if (scores == NULL)
return 0;
//Get the number of each test
cout << "Enter the test scores below.\n";
for (int count = 0; count < nScores; count++)
{
cout << "Test score #" << (count + 1) << ": ";
cin >> *(scores + count);
}
//total score operation
for (int count = 0; count < nScores; count++)
{
total += *(scores + count);
}
showAverage(total, nScores);
//the array pointers
arrSelectSort(scores, nScores);
cout << "the ascending order is: \n";
showArrPtr(scores, nScores);
//free memory.
delete[] scores;
scores = 0;
return 0;
}
// bubble sort
void arrSelectSort(double *array, int size)
{
int temp;
bool swap;
do
{
swap = false;
for (int count = 0; count < (size - 1); count++)
{
if (*(array + count) > *(array + count + 1))
{
temp = *(array + count);
*(array + count) = *(array + count + 1);
*(array + count + 1) = temp;
swap = true;
}
}
} while (swap);
}
// sort function
void showArrPtr(double *array, int size)
{
for (int count = 0; count< size; count++)
cout << *(array + count) << " ";
cout << endl;
}
// average function
void showAverage(double total, int nScores)
{
double average;
//average operation
average = total / nScores;
//Display the results.
cout << fixed << showpoint << setprecision(2);
cout << "Average Score: " << average << endl;
}
Create an E-R Diagram for the following:An art museum owns a large volume of artworks. Each artwork is described by an item Id (identifier), title, type, and size; size is further composed of height, width, and weight. A work of art is developed by an artist, but the artist for some works is unknown. An artist is described by an artist ID (identifier), name, date of birth, and date of death (which is null for still living artists). Notice that the name of the artist is a composite attribute, composed of first, last and preferred names and it cannot be empty. The artist DOB is also required). Data about both artists of works currently owned by the museum and artists that have otherwise been featured in the museum are kept in the database. At any point in time, a work of art is either on display at the museum, held in storage, away from the museum as part of a traveling show, or on loan to another gallery. If on display at the museum, a work of art is also described by its location within the museum. A traveling show is described by a show ID (identifier), and the start and end dates of the show. Many of the museum works may be part of a given show, and only active shows with at least one museum work of art need be represented in the database. Every show may be visiting multiple cities and therefore has a schedule associated with it, listing the city visited, the start and end dates and the contact phone number. There may be more than 1 contact phone numbers and all the attributes are required. Notice that there is only one schedule associated with each show but the same schedule can be used more than once for shows that are travelling together. Only schedules that have been used for shows are stored in the database. Finally, another gallery is described by a gallery ID (identifier), name, and city. The museum wants to retain a complete history of loaning a work of art to other galleries, and each time a work is loaned, the museum wants to know the date the work was loaned and the date it was returned. As you develop the ERD for this problem, follow good data naming guidelines.
An ER Diagram can be created for an art museum scenario, including entities like Artwork, Artist, Show, ShowCity, ShowSchedule, Gallery, and Loan.
Explanation:ER Diagram for Art MuseumThe ER Diagram for the given scenario can be created with the following entities:
Artwork (itemId, title, type, height, width, weight)Artist (artistId, firstName, lastName, preferredName, dateOfBirth, dateOfDeath)ArtworkArtist (itemId, artistId)Show (showId, startDate, endDate)ShowCity (showId, city)ShowSchedule (showId, startDate, endDate, contactPhone)Gallery (galleryId, name, city)Loan (itemId, galleryId, loanDate, returnDate)The relationships between the entities can be represented as follows:
Artwork is developed by Artist (1 to many relationship)Show has Artwork (many to many relationship)Show has ShowCity (1 to many relationship)Show has ShowSchedule (1 to many relationship)Artwork can be on Loan to Gallery (many to many relationship)Select the correct statement(s) regarding cellular control and traffic channels. a. When a mobile device in turned on, it connects to the nearest available base station through an available traffic channel b. Control and traffic channels are only allocated when a mobile device begins the process of making a phone call c. When a mobile device is turned on, it connects to the nearest available base station through a control channel d. All statements are correct
Answer:
c. When a mobile device is turned on, it connects to the nearest available base station through a control channel
Explanation:
A network is the communication and interconnection between Computer devices for sharing of data resources. The connection of these devices could be wireless or wired.
Wired network connection is the use of cables to connect devices, while wireless connection requires no wire.
Wireless communication could be electromagnetic, microwave, cellular etc. Cellular is mainly used for cell phone communication.
The cell phone has a database of cell tower connections and automatically connects to the nearest one through a control channel, when it's turned on.
"online privacy alliance (opa) is an organization of companies dedicated to protecting online privacy. members of opa agree to create a privacy policy for a customer that is easy to read and understand. which of the following provisions is not included in the policy?
(a) the option of choosing who sees
(b) the datatypes of data collected
(c) how data is used
(d) how collected data is secured
Answer:
Option A.
Explanation:
It is a business association working to protect your online privacy. Opa members agree to establish a User privacy Policy that is readable and understandable. So, the option of choosing who sees the data is the provision is not available in the policy because It has data types policy gathered and how data collected is protected.