Answer:
89.6 L.
Explanation:
For the balanced reaction:CS₂ + 3O₂ → CO₂ + 2SO₂.
It is clear that 1.0 mole of CS₂ with 3.0 moles of O₂ to produce 1.0 mole of CO₂ and 2.0 moles of SO₂.Using cross multiplication:
1.0 mole of CS₂ produces → 2.0 moles of SO₂.
2.0 mole of CS₂ produces → ??? moles of SO₂.
∴ The no. of moles of SO₂ produced = (2.0 mol)(2.0 mol)/(1.0 mol) = 4.0 mol.
It is known that 1.0 mole of any gas at STP occupies 22.4 L.∴ 4.0 moles of SO₂ occupy = (4.0)(22.4 L) = 89.6 L.
Answer:
89.6 L.
Explanation:
Sports trainers treat sprains and soreness with ethyl bromide. it is manufactured by reacting ethylene with hydrogen bromide: h5sil9512 use bond energies to find the enthalpy change for this reaction
-59 kj/mol exothermic
The enthalpy change for the reaction of ethylene with hydrogen bromide to form ethyl bromide is -59 kJ/mol. This means that the reaction is exothermic, meaning that it releases heat.
What's the information aboutThe bond energies of the relevant bonds are as follows:
C-C bond energy: 347 kJ/mol
C-H bond energy: 413 kJ/mol
H-Br bond energy: 363 kJ/mol
C-Br bond energy: 276 kJ/mol
Reactants:
Ethylene: 2 C-H bonds + 1 C-C bond
Hydrogen bromide: 1 H-Br bond
Products:
Ethyl bromide: 3 C-H bonds + 1 C-C bond + 1 C-Br bond
Enthalpy change:
ΔH = Σ(bond energies broken in reactants) - Σ(bond energies formed in products)
ΔH = (2 × 413 kJ/mol + 1 × 347 kJ/mol) - (1 × 363 kJ/mol + 3 × 413 kJ/mol + 1 × 276 kJ/mol)
ΔH = -59 kJ/mol
Therefore, the enthalpy change for the reaction of ethylene with hydrogen bromide to form ethyl bromide is -59 kJ/mol. This means that the reaction is exothermic, meaning that it releases heat.
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What happens with the atomic numbers in nuclear equations?
Increase
Decrease
Conserved
Nothing
Answer:
Conserved
Explanation:
In balancing nuclear reaction equations, there is conservation of mass numbers and atomic numbers, i.e the sum of the mass number on the product side must be equal to the sum of mass numbers on the reactant side.
Also, the sum of the atomic numbers on the product side must be equal to the sum of the atomic numbers on the reactant side.
Note: A nuclear reaction is a process in which a nucleus reacts with an elementary particle.
What happens to the atoms that make up ethanol as it burns?
the burning of ethanon is an exothermic reaction.
exothermic = releases heat.
knowing this, we can see that the atoms are released into the atmosphere, it then reacts with oxygen, producing cardon dioxide, water, and heat.
The positive crankcase ventilation (PCV) system helps reduce _______ exhaust gas emissions. A. CO2 (carbon dioxide) B. HC (hydrocarbon) C. oxygen D. NOx (oxides of nitrogen)
Answer:
[tex]\boxed{\text{B. HC}}[/tex]
Explanation:
The blow-by gases that escape past the piston rings and get into the crankcase are mostly unburned fuel-air mixture.
The fuel is largely a mixture of hydrocarbons (HCs) .
The PCV system captures these gases and feeds them back to the cylinder for further combustion.
A. is wrong. Carbon dioxide exits through the exhaust.
C. is wrong. Most of the oxygen in the incoming air is used for combustion in the cylinders.
D is wrong. The NOx gases exit via the exhaust and are trapped by the catalytic converter.
Place the following in order of decreasing molar entropy at 298 k. H2 cl2 f2
cl2>F2>H2
we can do this by molar mass
Hydrogen - 1
clorine - 35 x2 = 70
flourine- 18 x 2 = 36
flourine - 18
Molar mass has a direct relationship with entropy. The order of decreasing molar entropy at 298K is F[tex]_2[/tex]> Cl[tex]_2[/tex] > H[tex]_2[/tex].
What is entropy?Entropy is a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty. It has several applications in physics and chemistry, as well as in biological systems as well as how they relate to life.
The phrase and the idea are employed in many different contexts, including information theory and classical thermodynamics. Molar mass has a direct relationship with entropy. The order of decreasing molar entropy at 298K is F[tex]_2[/tex]> Cl[tex]_2[/tex] > H[tex]_2[/tex].
Therefore, the order of decreasing molar entropy at 298K is F[tex]_2[/tex]> Cl[tex]_2[/tex] > H.
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Cu ag and au are all in what group number
Answer:
Cu, Ag, and Au are all in the group number 11Explanation:
To answer this question you must look at your periodic table.
The elements in the periodic table are ordered in increasing order of atomic number and elements with similar chemical properties, due to the same number of valence eletrons, lay in the same column.
The column in the periodic table corresponds to the chemical group, and, in the most modern version, is identified with a number 1 through 18.
The elments Cu (copper), Ag (silver), and Au (gold), all metals, are in the same group (column) number 11.
The elements in the columns 3 trough 12 are transition metals. The atomic numbers of thise elements, which let you to find them easily in your periodic table, are:
Cu: 29 (it is the first element in the group)Ag: 47 (it is directly below Cu)Au: 79 (79 ( it is directly below Ag)Those elements, along with platinum are paladium, are the metals with the lowest reactivity, which is the reason why they are found in nature in its pure form (not combined with other elements).
Cu, Ag, and Au are all in Group 11 of the periodic table, known for having eleven valence electrons and being part of the d-block transition metals. They appear in various transition series (Cu in the first, Ag in the second, and Au in the third) and can form d10 coordination complexes.
The elements Cu (Copper), Ag (Silver), and Au (Gold) all belong to Group 11 of the periodic table. These metals are collectively known as the coinage metals and are characterized by having eleven valence electrons. They are part of the d-block elements, specifically included in the transition metals category. Copper is in the first transition series, silver is part of the second, and gold falls within the third. The properties of these metals, such as their high conductivities and malleability, make them highly valuable and extensively used in coins, jewelry, and electronics.
Moreover, when these elements form complexes with coordination number 2, as seen with d10 metal ions like Cut, Ag+, and Aut, they typically exhibit a linear L-M-L structure. Such configurations can be useful in various applications including the extraction of gold from its ores.
During a combustion reaction, 8.00 grams of oxygen reacted with 4.00 grams of CH4.
What is the amount of the leftover reactant?
2.78 grams of oxygen
2.10 grams of oxygen
1.99 grams of methane
1.78 grams of methane
Answer:
1.99 grams of methane
Explanation:
A combustion reaction always produces the product carbon dioxide and water. So the chemical equation for this reaction would be:
CH₄ + O₂ → CO₂ + H₂O
To answer this question, you need to first determine which is the excess reactant. First step is to balance the equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Next we get the number of moles of each reactant we actually have:
8.00 g of O₂ = ? moles of O₂
You can get the number of moles, by first computing how many grams of the molecule is present in 1 mole.
O = 15.999g/mole. Since there are 2 oxygens in one mole of O₂, all you need to do is add up the atomic mass of 2 oxygens. You will get:
O₂= 31.998 g/mole
You can use this then to determine how many moles of O₂ there are in 8.00g.
[tex]8.00g\times\dfrac{1mole}{31.998g}=0.250moles[/tex]
So there are 0.250 moles of O₂ in 8.00 g of O₂.
We do the same for CH₄
4.00g of CH₄=? moles of CH₄
C H₄
CH₄= 12.011 + 1.008(4) = 16.043 g/mole
[tex]4.00g\times\dfrac{1mole}{16.043g}=0.249moles[/tex]
So let's sum up our new given. We now have:
0.250 moles of O₂
0.249 moles of CH₄
Next we look at the molar ratio of reactants to produce products:
CH₄ + 2O₂ → CO₂ + 2H₂O
According to this equation we can assume the following:
We need 1 mole of CH₄ for every 2 moles of O₂ in this reaction. Using what we have, we will see how much of reactant of the other reactant we need to use up the other.
[tex]0.25molesofO_{2}\times\dfrac{1moleofCH_{4}}{2molesofO_{2}}=0.125molesofCH_{4}\\\\0.249molesofCH_{4}\times\dfrac{2molesofO_{2}}{1moleofCH_{4}}=0.498molesofO_{2}[/tex]
Compare the results with what we have:
What we have What we need
0.250 moles of O₂ < 0.498 moles of O₂
0.249 moles of CH₄ > 0.125 moles of CH₄
This means that since we have less O₂ that what we need to use up CH₄, then O₂ is the limiting reactant and CH₄ is the excess.
To compute how much we have in excess, we use the number of moles produced when we use up limiting reactant which we did earlier and convert it into grams to determine how much in grams we used up.
Earlier we solved that we need 0.125 moles of CH₄ to use up all the O₂. Now convert that value into grams:
[tex]0.125molesofCH_{4}\times\dfrac{16.043gofCH_{4}}{1moleofCH_{4}}=2.005g of CH_{4}[/tex]
This means that 2.005g of CH₄ will be used up.
Subtract that from the CH₄ we already have:
4.00 g - 2.005 g =1.99 g of CH₄
Which chemical reaction would result in the greatest release of energy?
a.adp + p --> atp
b.atp + oxygen --> adp + p
c.pyruvic acid + nadh --> lactic acid + nad+
d.carbon dioxide + water --> glucose + oxygen?
The answer is B.
ATP + Oxygen ---> ADP + P
The freezing point and the boiling point of water can be altered by a variety of techniques. Which of the following has little or no effect on the boiling point of water? A: Increasing the air pressure above the liquid B: Adding alcohol to the water C: Adding sodium chloride to the water D: Increasing the amount of water
Answer:
D: Increasing the amount of water.
Explanation:
Choice A: increasing the pressure can force the liquid to stay a liquid and affect the boiling point (decrease it).
Choice B and C: both involve colligative properties, adding a solute to water will increase the boiling point of water.
Choice D: just having more water does not change the boiling point of the water as this minimize the effect of any external factor.
So, the right choice is: D: Increasing the amount of water.
Jamie had $37 in his bank account on Sunday.
Answer:
where's the question... ?
An oxide of niobium has a cubic unit cell in which there are oxide ions at the middle of each edge and niobum atoms at the center of each face. what is the empirical formula of this oxide?
Question 1:
1. One form of niobium oxide crystallizes in the unit cell shown above.
A. How many niobium atoms per unit cell? 3
B. How many oxygen atoms per unit cell? 3
C. What is the formula of niobium oxide? Nb2O5
Answer: A) 3 B) 3 C) Nb205
Question 2:
2. Quartz (left) and glass (right) are both forms of silicon dioxide. A piece of quartz breaks into a collection of smaller regular crystals with smooth faces. A piece of glass breaks into irregular shards. Use molecular structures to explain why the two solids break so differently. Select all that apply.
1. the bonding and geometry in quartz shows regular repeating patterns *
2. the bonding and geometry in quartz shows irregular repeating patterns
3. the bonding and geometry in glass shows irregular repeating patterns *
4. the atomic geometries of the two solids can explain why they break so differently *
5. the atomic geometries of the two solids cannot explain why they break so differently
6. the bonding and geometry in glass shows regular repeating patterns
Answer: 1,3,4
3. Solid silver adopts a face-centered cubic lattice. The metallic radius of a silver atom is 144 pm.
a. How many silver atoms occupy one unit cell of solid silver? 4
b. Calculate the length (in pm) of one side of the unit cell. 407
c. Calculate the volume (in m3) of one the unit cell. 6.74 x10^-29
d. What percentage (expressed to four significant figures) of the volume is empty? 25.95
Answer: a)4 b)407 c)6.74 x10^-29 d)25.95
4. Why hexane is insoluble in water? Select all that apply.
1. Water is polar solvent. *
2. Polar solvents dissolve both polar and non-polar compounds.
3. Polar solvents dissolve only polar compounds. *
4. Solubility does not depends on the polarity of the solvents and reagents.
5. Hexane is non-polar compound. *
Answer: 1,3,5
<3 goodluck
Final answer:
The empirical formula for the niobium oxide with oxide ions at the middle of each edge and niobium atoms at the center of each face is Nb2O, obtained by counting the ions per unit cell and adjusting for their location in the structure.
Explanation:
To determine the empirical formula of the niobium oxide, first, we need to consider how many ions are associated with each other in the cubic unit cell structure. A cubic unit cell with oxide ions at the middle of each edge and niobium atoms at the center of each face can be described as follows: each edge has 1/4 of an oxide ion since it is shared by 4 cubes, resulting in 1 oxide ion per unit cell (there are 12 edges, thus 12 x 1/4 = 3, but each oxygen is set twice, thus 3 / 2 = 1.5 but oxygen only gives 1 charge so we only take half). Each face-centered niobium contributes 1/2 of an atom to the unit cell since each face is shared between two unit cells, leading to 3 niobium atoms per unit cell (6 faces x 1/2 = 3). Therefore, for every 1 niobium atom, there is 0.5 of an oxide ion, and by multiplying both the niobium and oxide amounts by 2 to get whole numbers, we obtain the empirical formula Nb2O.
The coordination number of an ion in a crystalline structure is the number of counterions that surround it. In the niobium oxide unit cell described, the oxide ions are at the midpoint of each edge, and niobium atoms are at the center of each face. Without additional information, however, it is not possible to determine the exact coordination number, as this would depend on the 3D arrangement of the atoms within the cell.
What is the pH of a solution with a pOH of 10?
6
4
10
14
Answer:
= 4
Explanation:
The pH of a solution is given by;
pH = - log [H+] , while
pOH = - log [OH-]
But; pH + pOH = 14
Therefore;
pH = 14 - pOH
= 14 - 10
= 4
4 is the correct answer
Silver tarnishing is an example of what type of change?
Physical change
Chemical change
Alchemical change
Temperature change
Answer:
that a chemical change
Explanation:
because it changing properties
It’s Chemical change
Which solution below has the highest concentration of hydroxide ions?a. pH= 3.21b. pH= 7.00c. pH= 7.93d. pH= 12.59e. pH= 9.82
Answer:
The solution that has the highest concentration of hydroxide ions is d. pH = 12.59.Explanation:
You can solve this question using just some chemical facts:
pH is a measure of acidity or alkalinity: the higher the pH the lower the acidity and the higher the alkalinity.The higher the concentration of hydroxide ions the lower the acidity or the higher the alkalinity of the solution, this is the higher the pH.Hence, since you are asked to state the solution with the highest concentration of hydroxide ions, you just pick the highest pH. This is the option d, pH = 12.59.
These mathematical relations are used to find the exact concentrations of hydroxide ions:
pH + pOH = 14 ⇒ pOH = 14 - pHpOH = - log [OH⁻] ⇒ [tex][OH^-]=10^{-pOH}[/tex]Then, you can follow these calculations:
Solution pH pOH [OH⁻]
a. 3.21 14 - 3.21 = 10.79 antilogarithm of 10.79 = 1.6 × 10⁻¹¹
b. 7.00 14 - 7.00 = 7.00 antilogarithm of 7.00 = 10⁻⁷
c. 7.93 14 - 7.93 = 6.07 antilogarithm of 6.07 = 8.5 × 10⁻⁷
d. 12.59 14 - 12.59 = 1.41 antilogarithm of 1.41 = 0.039
e. 9.82 14 - 9.82 = 4.18 antilogarithm of 4.18 = 6.6 × 10⁻⁵
From which you see that the highest concentration of hydroxide ions is for pH = 12.59.
The pH with the highest hydroxide ion is 12.59
What is pH?pH is the degree of acidity or alkalinity in a solution.
The lower the pH, the higher the acidity.The higher the pH the higher the basicity.
When the concentration is higher, it has more hydroxide ion.
Therefore, The pH with the highest hydroxide ion is 12.59 because the higher the pH the higher the concentration of the hydroxide ion.
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If you are given a chemical equation and specific amounts for each reactant in grams, how would you determine how much product can possibly be made? if you are given a chemical equation and specific amounts for each reactant in grams, how would you determine how much product can possibly be made? 1. convert each reactant into moles of the product. 2. determine which reactant is the limiting reactant. 3. convert the moles of product, from the limiting reactant, to grams. 1. determine which reactant is the limiting reactant. 2. convert each reactant into moles of the product. 3. convert the moles of product, from the limiting reactant, to grams. 1. determine which reactant is the limiting reactant. 2. using conversion factor, convert grams of the limiting reactant to grams of the product.
1. Find the mole of each reactant present and determine the limiting reactant 2. determine the mole of product produced through the mole ratio of the equation 3. convert to grams if the 'amount' refers to grams
Predict which molecule will show a similar relationship between its heat of fusion and its heat of vaporization that water does.
A) C6H6
B) CH3CH2CH2CH2CH2COH6
C) NaCl
D) NH3
Specific heat capacity of a substance is the amount of heat required to raise the temperature by one degree Celsius of one gram of a substance. Therefore, the correct option is option A.
What is Enthalpy?Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances.
Mathematically,
q = n ×ΔH
where
q = amount of heat
n = no of moles
ΔH = enthalpy
n = w / M.M
w = given mass
M.M = molar mass
A) C₆H₆
melting point =5.5° C
boiling point =80.1 ° C
Heat of fusion = 9.92 kJ/mol
Heat of vaporization =30.8kJ/mol
B) CH₃CH₂CH₂CH₂CH₂COH₆ is solid
C) NaCl is solid
D) NH₃
melting point = -77.73 °C
boiling point = -33.34 °C
Therefore, the correct option is option A.
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Heat measures the average kinetic energy a substance's molecules.
TRUE
FALSE
Answer:
False this is like the definition of temperature
Explanation:
HURRY PLS!
What is the name of this molecule? (4 points) A straight chain of four carbons. There is a triple bond between the first and second carbons when counting from left to right.
4 carbon chain is butane. With a triple bond it is butane. Since the triple bond is on the first carbon it can be called 1-butyne, or but-1-yne.
When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the reaction below. How many grams of water were formed? (Hint: This answer will have 3 SF.)
2H2+O2 ⇒ 2H2O
54.0 g
6.01 g
0.0185 g
0.167 g
Answer:
54.0 g.
Explanation:
From the given data and the balanced reaction:2H₂ + O₂ → 2H₂O.
When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the balanced reaction.
∴ The no. of grams in 3.0 moles of water = no. of moles x molar mass = (3.0 mol)(18.0 g/mol) = 54.0 g.
Answer:
A) 54.0 g
Explanation:
Hello! The answer to your question is 54.0 grams.
2H2 + O2 --> 2H2O
Because of that, we know our result will possess 3 significant figures.
The only sensible answer here (without the calculations) would be 54.0, due to the decimal placement. Hope this helps you!
A mixture of gases with a pressure of 800.0 mm hg contains 60% nitrogen and 40% oxygen by volume. What is the partial pressure of oxygen in this mixture?
The partial pressure of oxygen in a mixture with a total pressure of 800.0 mm Hg, where oxygen makes up 40% of the mixture, is 320.0 mm Hg.
Explanation:To find the partial pressure of oxygen in a mixture of gases, you can use the formula P = (Patm) X (percent content in mixture). Given that the total pressure of the mixture is 800.0 mm Hg and oxygen makes up 40% of this mixture by volume, the partial pressure of oxygen can be calculated as follows:
PO2 = (800.0 mm Hg) X (0.40)
PO2 = 320.0 mm Hg
Therefore, the partial pressure of oxygen in this mixture is 320.0 mm Hg.
Which statements are true of the reaction below? 2na(s) + cl2(g) 2nacl(s) Check all that apply. A - NaCl is a product B - Na(s) is a product C - A chemical reaction does not happen D - Cl2 is a gas
Answer:
A - NaCl is a product
D - Cl2 is a gas
Explanation:
Based on the chemical reaction;
2Na(s) + Cl2(g) → 2NaCl2
Sodium metal reacts with chlorine gas to form sodium chloride. Sodium is in solid state, chlorine is in gaseous state and Sodium chloride is in solid state.In the chemical reaction, sodium and chlorine are reactants while sodium chloride is the product.Additionally the chemical reaction above is balanced so as to obey the law of conservation of mass.The true statements for the reaction 2Na(s) + Cl2(g) → 2NaCl(s) are that NaCl is a product and Cl2 is a gas. Sodium (Na) is a reactant, not a product, and a chemical reaction does occur in this equation.
Explanation:The reaction given is 2Na (s) + Cl2(g) → 2NaCl (s). This chemical equation is balanced, indicating that the same number and types of atoms appear on both sides of the equation. The equation demonstrates the reaction of solid sodium (Na) with chlorine gas (Cl2) to form sodium chloride (NaCl), a solid.
For the statements provided:
NaCl is a product: This is true because NaCl appears on the right side of the arrow, indicating it is the result of the reaction.Na(s) is a product: This is false because Na appears on the left side of the arrow, meaning it is a reactant, not a product.A chemical reaction does not happen: This is false as the equation clearly shows a chemical reaction taking place.Cl2 is a gas: This is true as indicated by the (g) after Cl2, denoting it is in the gaseous state before the reaction.Key Notes to Remember:
Chlorine is one of the seven elements that exist in nature as diatomic molecules, which include H2, N2, O2, Cl2, Br2, and I2—this is important for balancing chemical equations correctly.
How many chlorine atoms are there in the reactants: 2Al+3Cl2→2AlCl3??
A. 2
B. 1
C. 3
D. 6
The answer is D. 6 you multiply 2 and 3
Answer:
The correct answer is D
Explanation:
because you would take 2 and 3 and multiply them and get 6 or
3×2=6
An atom of tin has an atomic number of 50 and a mass number of 119. How many protons, electrons, and neutrons are found in one neutral atom of tin?
Answer:
2.38
Explanation:
119 divided by 50 =2.38
i hope you get it right :)
A neutral atom of tin has 50 protons, 50 electrons, and 69 neutrons. The number of protons and electrons is determined by the atomic number, while the number of neutrons is calculated by subtracting the atomic number from the mass number.
Explanation:An atom of tin (Sn) is described by its atomic number and its mass number. The atomic number refers to the number of protons in the nucleus of the atom, and in a neutral atom, it also equals the number of electrons. Therefore, a neutral tin atom has 50 protons and 50 electrons.
The mass number, on the other hand, is the sum of protons and neutrons in the nucleus. Therefore, to find out the number of neutrons, you have to subtract the atomic number from the mass number: 119 - 50 = 69. So, a neutral tin atom has 69 neutrons.
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Thirty points to who ever can answer this problem
During an experiment, 104 grams of calcium carbonate reacted with an excess amount of hydrochloric acid. If the percent yield of the reaction was 80.15%, what was the actual amount of calcium chloride formed?
CaCO3 + HCl → CaCl2 + CO2 + H2O
A. 90.1 grams
B. 92.4 grams
C. 109.2 grams
D. 115.3 grams
Answer:
B. 92.4 g
Explanation:
the balanced equation for the reaction is as follows
CaCO₃ + 2HCl ---> CaCl₂ + CO₂ + H₂O
molar ratio of CaCO₃ to CaCl₂ is 1:1
number of CaCO₃ moles reacted - 104 g / 100 g/mol = 1.04 mol
therefore number of CaCl₂ moles reacted - 1.04 mol
mass of CaCl₂ expected to be formed = 1.04 mol x 111 g/mol = 115.44 g
percentage yield = actual yield / theoretical yield x 100 %
theoretical yield = 115.44 g
percentage yield = 80.15 %
substituting these values in the above equation
80.15 % = actual yield / 115.44 g x 100 %
actual yield = 92.5 g
therefore answer is B. 92.4 g
write a balanced equation that describes the dissociation of chromium(III) nitrate in water
The balanced equation for the dissociation of chromium(III) nitrate in water is Cr(NO3)3 (s) → Cr3+ (aq) + 3 NO3- (aq), illustrating the separation into chromium(III) ions and nitrate ions.
Explanation:The balanced equation that describes the dissociation of chromium(III) nitrate in water is as follows:
Cr(NO3)3 (s) → Cr3+ (aq) + 3 NO3− (aq)
When chromium(III) nitrate dissolves in water, it separates into chromium(III) ions and nitrate ions. Each formula unit of the solid compound yields one chromium(III) ion and three nitrate ions. The equation is balanced with respect to both mass and charge, fulfilling the law of conservation of mass and the principle of electroneutrality.
To describe the process, it is important to note that chromium(III) nitrate is a salt, and like most salts, it dissociates completely in water to give its constituent ions.
The formula H2SO4 is representative of which of the following?A. an acid B. a catalyst C. an organic compound D. a base
Absolutely an acid ,because:
1)we it is sulfuric acid s molecular formula
2) in its shape H atom bonded with (O),not central atom
Answer:
A. An acid
Explanation:
Hello,
In inorganic chemistry, oxyacids are characterized by the presence of hydrogen, a nonmetal and oxygen as they are formed when an acid oxide (formed with a nonmetal and oxygen) reacts with water. In this case, as the molecule has hydrogen, sulfur and oxygen, such constituting atoms match with the definition of an oxyacid, that is why H₂SO₄ is an acid.
Best regards.
Fill in the missing mass number and atomic number for each of these particles or types of radiation.
alpha (?) He
beta (?) e
gamma y
neutron n
Answer:
Particle / mass number atomic number
type of radiation
alpha / ⁴₂ He 4 2
beta / e⁰ 0 - 1
gamma / γ 0 0
neutron / n 1 0
Explanation:
These are the basic types of radiation: alpha (α), beta (β), gamma (γ), and neutrons (n).
The radiation is emitted by unstable nuclei when undergo radiactive decay or by nuclei that are shooted by other particles.
Alpha radiation (⁴₂ He):
They are nuclei of helium-4 atoms: 2 protons and 2 neutrons.
Hence, the atomic number, which is the number of protons, of these particles, is 2; and the mass number, which is the sum of protons and neutrons, is 2 + 2 = 4.
The symbol of this radiation is ⁴₂ He, where the superscript to the left of the chemical symbol is the mass number and the subscript to the left of the chemical symbol is the atomic number.
Beta (⁰₋ ₁ e)
These are electrons emiited from an unstable nucleus. The symbols used for this particle are either ⁰₋ ₁β or ⁰₋ ₁e.
The superscript 0 indicates that the relative mass of this particle is practically zero and the subscript -1 tells that the emission of electrons increases the atomic number of the nucleus that emits it.
Gamma (⁰₀γ)
The gamma rays are electromagnetic radiation of high (the highest) energy.
The both superscript and subscript are zero, meaning that this radiation does not change either the mass or atomic numbers of the nucleus.
Neutron (¹₀n):
Neutrons are also emiited from the nucleus and so they may be considered a radiation.
The atomic number of neutrons is 0 (since it does not have protons) and its mass number is 1.
Radioactive rays are divided into three, namely alpha rays, beta rays, and gamma rays.
Check the picture below!
Further Explanation
Types of Radioactive Rays
Based on the constituent particles, radioactive rays are divided into three, namely alpha rays, beta rays, and gamma rays.
Alfa ray (α ray)
Alpha rays are rays emitted by radioactive elements. This ray was discovered simultaneously with the discovery of the phenomenon of radioactivity, which is the decay of the nucleus which takes place spontaneously, uncontrolled, and produces radiation. Alpha rays consist of two protons and two neutrons. The following are the nature of alpha rays.
Beta Rays (β Rays)
Beta rays are high-energy electrons that originate from the nucleus. Here are some of the nature of beta rays.
Has a smaller ionization power than alpha rays. Has a greater penetrating power than alpha rays. Can be deflected by electric or magnetic fields.
Gamma Rays (Rays ˠ)
Gamma rays are radiation from electromagnetic waves that emanate from very high energy nuclei that have no mass or charge. Gamma rays also emit when a core emits alpha rays and beta rays. Gamma-ray decay does not cause changes in atomic number or atomic mass.
Gamma rays have the following natural properties:
Gamma rays do not have maximum coverage in the air, the farther away from the source the intensity is smaller. Has the weakest ionization power. Has the greatest penetrating power. Do not turn in the electric and magnetic fields.
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Radioactive Rays https://brainly.com/question/12538910
Rays of Alpha, Beta, and Gamma https://brainly.com/question/12538910
Detail
Class: High School
Subject: Chemistry
Keyword: Alpha, Beta, Gamma
a) What is the change in the cell voltage when the ion concentrations in the cathode half-cell are increased by a factor of 10?b) What is the change in the cell voltage when the ion concentrations in the anode half-cell are increased by a factor of 10?
Answer:
(a) The change in cell voltage is 0.05V
(b) The change in cell voltage is 0.03V
Explanation:
Redox reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.
Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases.
Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases.
Further explanation:
The image taken in context is attached below.
The standard reduction potentials for iron and silver are:
[tex]E^o_{(Fe^{2+}/Fe)}=-0.44V\\E^o_{(Ag^{+}/Ag)}=+0.80V[/tex]
In the given cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.
From the standard reduction potentials we conclude that, the substance having highest positive [tex]E^o[/tex] potential will always get reduced and will undergo reduction reaction.
So, silver will undergo reduction reaction will get reduced. Iron will undergo oxidation reaction and will get oxidized.
The given cell reactions are:
Oxidation half reaction (anode): [tex]Fe\rightarrow Fe^{2+}+2e^-[/tex]
Reduction half reaction (cathode): [tex]Ag^{+}+e^-\rightarrow Ag[/tex]
Thus, the anode and cathode will be [tex]E^o_{(Fe^{2+}/Fe)}[/tex]
and [tex]E^o_{(Ag^{+}/Ag)}[/tex] respectively.
The overall cell reaction will be,
[tex]2Ag^{+}+Fe\rightarrow Fe^{2+}+2Ag[/tex]
To calculate the [tex]E^o_{cell}[/tex] of the reaction, we use the equation:
[tex]E^o_{cell}=E^o_{cathode}-E^o_{anode}[/tex]
[tex]E^o=E^o_{(Ag^{+}/Ag)}-E^o_{(Fe^{2+}/Fe)}[/tex]
[tex]E^o=(+0.80V)-(-0.44V)=1.24V[/tex]
Now we have to calculate the cell potential.
Using Nernst equation :
[tex]E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Fe^{2+}]}{[Ag^{+}]^2}[/tex]
where,
n = number of electrons in oxidation-reduction reaction = 2
[tex]E_{cell}[/tex] = emf of the cell = ?
Now put all the given values in the above equation, we get:
[tex]E_{cell}=1.24-\frac{0.0592}{2}\log \frac{(1M)}{(1M)^2}[/tex]
[tex]E_{cell}=1.24V[/tex]
Thus, the emf of cell potential is 1.24 V
Part (a):
The ion concentrations in the cathode half-cell [tex](Ag^+/Ag)[/tex] are increased by a factor of 10 from 1 M to 10 M.
The emf of the cell potential will be,
Using Nernst equation :
[tex]E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Fe^{2+}]}{[Ag^{+}]^2}[/tex]
where,
n = number of electrons in oxidation-reduction reaction = 2
[tex]E_{cell}[/tex] = emf of the cell = ?
Now put all the given values in the above equation, we get:
[tex]E_{cell}=1.24-\frac{0.0592}{2}\log \frac{(1M)}{(10M)^2}[/tex]
[tex]E_{cell}=1.29V[/tex]
The change in cell voltage will be,
[tex]E_{cell}=1.29V-1.24V=0.05V[/tex]
Thus, the change in cell voltage is 0.05V
Part (b):
The ion concentrations in the anode half-cell [tex](Fe^{2+}/Fe)[/tex] are increased by a factor of 10 from 1 M to 10 M.
The emf of the cell potential will be,
Using Nernst equation :
[tex]E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Fe^{2+}]}{[Ag^{+}]^2}[/tex]
where,
n = number of electrons in oxidation-reduction reaction = 2
[tex]E_{cell}[/tex] = emf of the cell = ?
Now put all the given values in the above equation, we get:
[tex]E_{cell}=1.24-\frac{0.0592}{2}\log \frac{(10M)}{(1M)^2}[/tex]
[tex]E_{cell}=1.27V[/tex]
The change in cell voltage will be,
[tex]E_{cell}=1.27V-1.24V=0.03V[/tex]
Thus, the change in cell voltage is 0.03V
Learn more:
Spontaneity of reaction; https://brainly.com/question/13151873 (answer by Kobenhavn)
Standard reduction potential; https://brainly.com/question/8739272 (answer by RomeliaThurston)
Keywords:
Nernst equation, standard reduction potential, spontaneity of the reaction.
The change in the cell voltage when the ion concentrations in the ANODE half-cell are increased by a factor of 10 is 0.030 V
Further explanationWhat is the change in the cell voltage when the ion concentrations in the ANODE half-cell are increased by a factor of 10?
The Nernst equation
[tex]E=E^o - \frac{RT}{nF} lnQ[/tex]
E ∘ is the cell potential at standard conditions R is the ideal gas constant T is the absolute temperature n is the number of electrons transferred per mole of reaction F is the Faraday constant Q is the reaction quotient of the reactionThe given electrochemical cell has both aqueous species Fe 2 + and Ag + at 1 M concentration
If the anode concentration is increased by a factor of 10 , the cell potential will change by the correction term:
[tex]\Delta E = -\frac{RT}{nF} lnQ[/tex]
Now we determine the overall reaction
[tex]Fe(s) -> Fe^{2+}(aq)+2e [anode]\\2*(Ag^+(aq)+e -> Ag(s)) [cathode]\\Fe(s)+2Ag^+(aq)->Fe^{2+}(aq)+2Ag(s) [overall][/tex]
n=2 electrons were transferred
[tex]Q=\frac{[Fe^{2+}]}{[Ag^+]^2}[/tex]
The change in cell potential is
[tex]\Delta E = - \frac{RT}{nF} ln \frac{[Fe^{2+}]}{[Ag^+]^2}[/tex]
Note that [tex][Fe^{2+}]=10M[/tex] and assume that T=298.15 K
[tex]\Delta E = - \frac{8.314J/molK*298.15K}{2*96485C/mol} ln \frac{10M}{1M^2}\\\Delta E = -0.030 V[/tex]
Therefore the cell potential will decrease by 0.030 V
Learn moreLearn more about the cell voltage https://brainly.com/question/2326679Learn more about the ion concentrations https://brainly.com/question/11480712 Learn more about the cathode half-cell https://brainly.com/question/9502656Answer detailsGrade: 9
Subject: chemistry
Chapter: the ion concentrations
Keywords: the cell voltage, the ion concentrations, the cathode half-cell, the anode, factor
the pressure of a sample of helium in a 0.2 L container is 2.0atm. if the helium is compressed to a volume of 10.0 ml ,what would be the pressure of the gas?
Answer:
The pressure of the gas is 40atm
Explanation:
Given parameters:
P₁ = 2.0atm
V₁ = 0.2L
V₂ = 10.0mL = 10 x10⁻³L = 0.01L
P₂ =?
We apply Boyle's law to solve this kind of problem
Boyle's law states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".
It is expressed as P₁V₁ = P₂V₂
Making P₂ the subject of the formula gives:
P₂ = P₁V₁/V₂
Inserting the values of the parameters:
P₂ = 2x0.2/0.01
P₂ = 40atm
Why is the answer C for this problem?
Answer:
[tex]\boxed{\text{(C) X}$_{3}$P$_{2}}[/tex]
Explanation:
Step 1. Identify the Group that contains X
We look at the consecutive ionization energies and hunt for a big jump between them
[tex]\begin{array}{crc}n & IE_{n} & IE_{n} - IE_{n-1}\\1 & 730 & \\2 & 1450 & 720\\3 & 7700 & 6250\\4 & 10500 & 2800\\\end{array}[/tex]
We see a big jump between n = 2 and n = 3. This indicates that X has two valence electrons.
We can easily remove two electrons, but the third electron requires much more energy. That electron must be in the stable, filled, inner core.
So, X is in Group 2 and P is in Group 15.
Step 2. Identify the Compound
X can lose two valence electrons to reach a stable octet, and P can do the same by gaining three electrons.
We must have 3 X atoms for every 2 P atoms.
The formula of the compound is [tex]\boxed{\text{X}$_{3}$P$_{2}}$}[/tex].