Can someone help with these 8 problems and show your work please.

Can Someone Help With These 8 Problems And Show Your Work Please.
Can Someone Help With These 8 Problems And Show Your Work Please.
Can Someone Help With These 8 Problems And Show Your Work Please.

Answers

Answer 1

Answer:

Part 1) option a. [tex]y=(x+1)^{2}[/tex]

Part 2) option c. [tex]y(x)=10x+1[/tex]

Part 3) option a. Yes , d=-2

Part 4) option b.  [tex]y=2x+4[/tex]

Part 5) option b. [tex]m=-2[/tex]

Part 6) option c. [tex]y=4x+14[/tex]

Part 7) option c. [tex]y=4x+5[/tex]

Part 8) option a. y=2x-1 and y=x+1

Step-by-step explanation:

Part 1)

we know that

If a ordered pair satisfy a function, then the function pass through the ordered pair

Verify each function with the points (1,4), (2,9) and (3,16)

case a) we have

[tex]y=(x+1)^{2}[/tex]

For x=1, y=4

[tex]4=(1+1)^{2}[/tex]

[tex]4=4[/tex] ----> is true

For x=2, y=9

[tex]9=(2+1)^{2}[/tex]

[tex]9=9[/tex] ----> is true

For x=3, y=16

[tex]16=(3+1)^{2}[/tex]

[tex]16=16[/tex] ----> is true

therefore

The function pass through the three points

case b) we have

[tex]y=(x+3)^{2}[/tex]

For x=1, y=4

[tex]4=(1+3)^{2}[/tex]

[tex]4=16[/tex] ----> is not true

therefore

The function not pass through the three points

case c) we have

[tex]y=7x-5[/tex]

For x=1, y=4

[tex]4=7(1)-5[/tex]

[tex]4=2[/tex] ----> is not true

therefore

The function not pass through the three points

Part 2)

Let

y------> the number of laps

x-----> the number of hours

we know that

The linear equation that represent this situation is

[tex]y(x)=10x+1[/tex]

Part 3) we have

{4,2,0,-2,-4,-6,...}

Let

a1=-4

a2=2

a3=0

a4=-2

a5=-4

a6=-6

we know that

a2-a1=2-4=-2 -----> a2=a1-2

a3-a2=0-2=-2 ----> a3=a2-2

a4-a3=-2-0=-2 -----> a4=a3-2

a5-a4=-4-(-2)=-2----> a5=a4-2

a6-a5=-6-(-4)=-2----> a6=a5-2

therefore

Is an arithmetic sequence, the common difference is -2

Part 4) we know that

The y-intercept of the graph is (0,4)

The x-intercept of the graph is (-2,0)

therefore

the function is [tex]y=2x+4[/tex]

because

For x=0 -----> y=2(0)+4 -----> y=4

For y=0 ----> 0=2x+4 --------> x=-2

Part 5) we know that

The formula to calculate the slope between two points is equal to

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

we have

[tex]A(3,5)\ B(2,7)[/tex]

substitute the values

[tex]m=\frac{7-5}{2-3}[/tex]

[tex]m=-2[/tex]

Part 6) we know that

The equation of the line into slope point form is equal to

[tex]y-y1=m(x-x1)[/tex]

we have

[tex]m=4[/tex]

[tex]point(-3,2)[/tex]

substitute the values

[tex]y-2=4(x+3)[/tex]

Convert to slope intercept form

[tex]y=4x+12+2[/tex]

[tex]y=4x+14[/tex]

Part 7) we know that

If two lines are parallel, then their slopes are the same

The equation of the given line is [tex]y=4x-2[/tex]

so

The slope of the given line is [tex]m=4[/tex]

therefore

The line [tex]y=4x+5[/tex] is parallel to the given line

Because the slope is equal to [tex]m=4[/tex]

Part 8) we know that

If a ordered pair is a solution of a system of equations, then the ordered pair must satisfy both equations of the system

Verify each case for (2,3)

case a)

y=2x-1 -----> equation 1

y=x+1 -----> equation 2

Substitute the value of x and the value of y in each equation and then compare the results

Verify equation 1

3=2(2)-1

3=3 -----> is true

Verify equation 2

3=2+1

3=3 -----> is true

therefore

The point (2,3) is a solution of the system of equations case a

case b)

y=2x+1 -----> equation 1

y=x-1 -----> equation 2

Substitute the value of x and the value of y in each equation and then compare the results

Verify equation 1

3=2(2)+1

3=5 -----> is not true

therefore

The point (2,3) is not a solution of the system of equations case b

case c)

y=4x-5 -----> equation 1

y=2x -----> equation 2

Substitute the value of x and the value of y in each equation and then compare the results

Verify equation 1

3=4(2)-5

3=3 -----> is true

Verify equation 2

3=2(2)

3=4 -----> is not true

therefore

The point (2,3) is not a solution of the system of equations case c


Related Questions

What is the area of a circle with a diameter of 12.6 in.?

Use 3.14 for pi and round your final answer to the nearest hundredth.


Enter your answer in the box.

Answers

Hey there! I'm happy to help!

To find the area of a circle, you square the radius and then multiply by pi (3.14 in our case).

The radius is half of the diameter.

12.6/2=6.3

We square this.

6.3²=39.69

We multiply by 3.14

39.69×3.14=124.6266

We round to the nearest hundredth, giving us an area of 124.63 in².

Now you can find the area of a circle! Have a wonderful day! :D

You can use formula for area of circle which simply is pi times square of radius. The radius is half of diameter.

The area of the given circle is 124.63 sq inches

Given that:A circle has diameter of 12.6 inches.To find:

Area of circle using pi = 3.14 and approximated to nearest hundredth.

Formula for Area of circle with radius r units:

[tex]\text{Area} = \pi \times r^2[/tex]

Finding radius:

[tex]\text{Radius} = \dfrac{\text{diameter}}{2}\\ r = \dfrac{12.6}{2} = 6.3 \: \rm inch[/tex]

Finding the area:

[tex]Area = \pi \times r^2 \approx 3.14 \times 6.3^2 \approx 124.626 \approx 124.63 \: \rm inch^2[/tex]

Thus, the area of the given circle is 124.63 sq inches

Learn more about area of circle here:

https://brainly.com/question/266951

Which of these constructions is impossible using only a compass and straightedge?

A. Doubling the square
B. Bisecting any angle
C. Doubling the cube
D. Trisecting a right angle

Answers

Answer:

C.

Step-by-step explanation:

The topic is on: 'impossible geometric construction"

The three areas of concern are : Trisecting an angle, squaring a circle and doubling a cube.

In double a cube the , when the edge in 1 unit will give the equation will give the equation x³=2 whose solution yields cube root of 2. This problem can not be solve because cube root of 2 is not an Euclidean number.

Answer:

C. Doubling the cube.

Step-by-step explanation:

Geometric construction is majorly a two dimensional drawing, excluding some form of projections (isometric and oblique drawing) which are three dimensional. Essential instruments to use in construction are; a pair of compass and straightedge (eg ruler).

From the options stated in the given question, doubling the cube is difficult to construct using the instruments given. A cube is a three dimensional shape that has all sides to be equal. It is a prism formed from a square, and it has six faces.

Stefan's family rented a rototiller to prepare an area in their backyard for spring planting. The rental company charged an initial fee of $43 with an additional fee per hour. If they paid $64 after renting the rototiller for 7 hours, what was the hourly fee?

Answers

Answer:

The hourly fee is $ 3.

Step-by-step explanation:

Given,

The initial fee = $ 43,

Let x be the additional hourly fee ( in dollars ),

Thus, the total additional fee for 7 hours = 7x dollars,

And, the total fee for 7 hours = Initial fee + Additional fee for 7 hours

= ( 43 + 7x ) dollars,

According to the question,

43 + 7x = 64

7x = 21      ( Subtracting 43 on both sides )

x = 3          ( Divide both sides by 7 )

Hence, the hourly fee is $ 3.

Answer:

7h+43=64

$3

Step-by-step explanation:

did it on edge

Matrix X is shown below.


If matrices X and Y are equal, what is the value of y12+y13+y32+y33?
7.5
27
40
49.5

Answers

Answer:

option C

40

Step-by-step explanation:

[tex]x_{nm}[/tex]

here n = number of row

        m = number of column

so the labelled 3x3 matrix would be like this

[tex]y=\left[\begin{array}{ccc}y11&y12&y13\\y21&y22&y23\\y31&y32&y33\end{array}\right][/tex]

Given in the question matrixX since matrixY is eaxctly same as matrixX so,  

[tex]y=\left[\begin{array}{ccc}1&6&-7\\-5&0&8.5\\-1&14&27\end{array}\right][/tex]

so

y12 = 6

+

y13 = -7

+

y32 = 14

+

y33 = 27

=

40

Answer:

The answer C, is right!

Step-by-step explanation:

Trapezoid ABCD and WXYZ are congruent trapezoids. What is the value of x?

A. x = -5
B. x = 5
C. x = 15
D. x = -15

Answers

Answer:

B. x=5

Step-by-step explanation:

Two shapes are congruent if you can turn one into the other by moving, rotating or flipping. So if we rotate 180 degrees, say, trapezoid WXYZ and then moving it to the left, it will match trapezoid ABCD. If so, it will be true that:

[tex]\angle BAD=\angle XWZ \\ \\ \angle BAD=4x-7 \\ \\ \angle XWZ=2x+3 \\ \\ 4x-7=2x+3 \\ \\ Solving \ for \ x: \\ \\ 4x-2x=7+3 \\ \\ 2x=10 \\ \\ \boxed{x=5}[/tex]

Answer:

Answer is B x=5

Step-by-step explanation:

Hope this helps!!

Help is much needed!!!!

Answers

Answer:

b = 6√3.

Step-by-step explanation:

Use trigonometry.

cos 30 = adjacent side / hypotenuse = b / 12

√3 / 2 = b / 12

2b = 12√3

b = 6√3 answer.

Please help!!! Show work if needed

Answers

Answer:

2h+2f=10.50

4h+3f=19.50

Step-by-step explanation:

2h+2f=10.50

4h+3f=19.50

• To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

{2h2f=10.5,4h3f=19.5}

• Choose one of the equations and solve it for h by isolating h on the left hand side of the equal sign.

2h+2f=10.5

• Subtract 2f from both sides of the equation.

2h=−2f+10.5

• Divide both sides by 2.

h=1/2 (−2f+10.5)

• Multiply 1/2  times −2f+10.5.

h=−f+21/4

• Substitute −f+21/4  for h in the other equation, 4h+3f=19.5.

4(−f+21/4)+3f=19.5

• Multiply 4 times −f+21/4.

−4f+21+3f=19.5

• Add −4f to 3f.

−f+21=19.5

• Subtract 21 from both sides of the equation.

−f=−1.5

• Divide both sides by −1.

f=1.5

• Substitute 1.5 for f in h=−f+21/4. Because the resulting equation contains only one variable, you can solve for h directly.

h=−1.5+21/4

• Add 21/4  to −1.5 by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.

h=15/4  

Find the domain of y=\sqrt{3x-8}

Answers

Answer:

Step-by-step explanation        

x

{x|x≥8/3}





What is the quotient (x3 – 3x2 + 5x – 3) ÷ (x – 1)?















What is the quotient (x3 + 3x2 + 5x + 3) ÷ (x + 1)?

Answers

Answer:

x^2 -2x +3x^2 +2x +3

Step-by-step explanation:

The quotient in each case can be found by any of several means, including synthetic division (possibly the easiest), polynomial long division, or graphing.

1. The graph shows you the quotient is (x-1)^2 +2 = x^2 -2x +3.

2. The graph shows you the quotient is (x+1)^2 +2 = x^2 +2x +3.

will mark brainliest pleassse help someone
Pyramid A is a square pyramid with a base side length of 9 inches and a height of 10 inches. what is the volume

Answers

Check the picture below.

[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=&area~of\\ &its~base\\ h=&height\\ \cline{1-2} B=&\stackrel{9\times 9}{81}\\ h=&10 \end{cases}\implies V=\cfrac{1}{3}(81)(10)\implies V=270[/tex]

Let A = {x | x < 5} and B = {x | x ≤ 7}. Find A B.

Answers

Answer:

A B = {x | x < 5}

Step-by-step explanation:

The domain of A B will be given by {x | x < 5}

The domain of A is given as  {x | x < 5} while that of B is {x | x ≤ 7}. From this we can infer that the domain of A is a subset of B since A is contained in B. The domain of A B is simply the intersection of these two sets which is A.

Which expression has a negative value?

Answers

Answer:

im pretty sure its d

Step-by-step explanation:

-35/5 is the answer

A rectangular ower garden is 5.3 yards wide and 9.4 yards long. A uniform path of

width 2 yards is laid around the garden. Find the area of the path.

Answers

Answer:

  74.8 square yards

Step-by-step explanation:

The centerline of the path is a rectangle 5.3+2 = 7.3 yards wide and 9.4+2 = 11.4 yards long. The perimeter of that rectangle is 2(7.3+11.4) = 37.4 yards long. The area of the path is this length times the width of the path:

  path area = (37.4 yd)(2 yd) = 74.8 yd²

The area of the path is 74.8 square yards.

First, we calculate the area of the garden:

[tex]\[ A_{\text{garden}} = \text{length} \times \text{width} = 9.4 \text{ yards} \times 5.3 \text{ yards} \][/tex]

[tex]\[ A_{\text{garden}} = 49.82 \text{ square yards} \][/tex]

Next, we need to find the area of the entire region including the path. The path adds an additional width of 2 yards on all sides of the garden.

The total length and width of the region including the path are:

[tex]\[ \text{Total length} = 9.4 \text{ yards} + 2 \times 2 \text{ yards} = 13.4 \text{ yards} \][/tex]

[tex]\[ \text{Total width} = 5.3 \text{ yards} + 2 \times 2 \text{ yards} = 9.3 \text{ yards} \][/tex]

Now we calculate the area of the entire region including the path:

[tex]\[ A_{\text{total}} = \text{Total length} \times \text{Total width} = 13.4 \text{ yards} \times 9.3 \text{ yards} \][/tex]

[tex]\[ A_{\text{total}} = 124.62 \text{ square yards} \][/tex]

Finally, we subtract the area of the garden from the total area to find the area of the path:

[tex]\[ A_{\text{path}} = A_{\text{total}} - A_{\text{garden}} \][/tex]

[tex]\[ A_{\text{path}} = 124.62 \text{ square yards} - 49.82 \text{ square yards} \][/tex]

[tex]\[ A_{\text{path}} = 74.8 \text{ square yards} \][/tex].

40 POINTS PLEASE HURRY
Pete grabbed 18 mixed nuts, 2/9 of which were almonds. Which equation shows how to determine the number of almonds Pete grabbed?
A.18 divided by 2/9 =81
B. 18 x 2/9 = 4
C. 2/9 divided by 18=1/81
D. 9/2 divided by 18=1/4

Answers

Answer:

B 18*2/9 =4

Step-by-step explanation:

To determine the number of mixed nuts that were almonds, take the number of nuts and multiply by the fraction that were almonds

nuts * 2/9= almonds

18 * 2/9

36/9

4

Find one positive angle and one negative angle that are coterminal with the given angle. Explain.

10. 255°

12. -800° ​

Answers

Answer: 10) 615° & -105°

               12) -440° & 280°

Step-by-step explanation:

Coterminal means it is in the exact same spot on the Unit Circle but one or more rotations clockwise or counterclockwise.

Since one rotation = 360°, add or subtract that from the given angle until you get a positive or negative number.

10) 255° + 360° = 615°     (this is a POSITIVE coterminal angle to 255°)

     255° - 360° = -105°     (this is a Negative coterminal angle to 255°)

12) -800° + 360° = -440°   (this is a Negative coterminal angle to -800°)

    -440° + 360° =  -80°      (this is a Negative coterminal angle to -800°)

      -80° + 360° = 280°     (this is a POSITIVE coterminal angle to -800°)

Final answer:

Coterminal angles for 255° are 615° (positive) and -105° (negative) by adding or subtracting 360° respectively. For -800°, the coterminal angles are -80° (positive) and -1160° (negative).

Explanation:

To find a positive and a negative angle coterminal with the given angle of 255°, we can add or subtract multiples of 360° (the total degrees in a circle). For a positive coterminal angle, we can add 360° to 255°:

255° + 360° = 615°

For a negative coterminal angle, we subtract 360° from 255° until we get a negative result:

255° - 360° = -105°

Similarly, for -800°, to find a positive coterminal angle, we keep adding 360° until we get a positive result:

-800° + 360° = -440°
-440° + 360° = -80°

For a negative coterminal angle, we can subtract 360° from -800°:

-800° - 360° = -1160°

Which conic section is represented by the equation shown below?

[tex]2x^2-9x+4y^2+8x=16[/tex]

A. Parabola
B. Ellipse
C. Circle
D. Hyperbola

Answers

Answer: Option B.  Ellipse

[tex]\frac{(x-\frac{1}{4})^2}{\frac{129}{16}}+\frac{(y-0)^2}{\frac{129}{32}}=1[/tex]

Step-by-step explanation:

To know what type of conic section the function is

[tex]2x ^ 2-9x + 4y ^ 2 + 8x = 16[/tex] we must simplify it.

[tex]2x ^ 2-9x + 4y ^ 2 + 8x = 16\\\\2x^2 -x +4y^2 =16[/tex]

complete the square of the expression:

[tex]2x ^ 2 -x\\\\\\2(x^2 -\frac{1}{2}x)\\\\2(x^2-\frac{1}{2}x +\frac{1}{16})-2\frac{1}{16}\\\\2(x-\frac{1}{4})^2 -\frac{1}{8}[/tex]

So we have

[tex]2(x-\frac{1}{4})^2 -\frac{1}{8}+4y^2 =16\\\\2(x-\frac{1}{4})^2+4y^2 =\frac{129}{8}\\\\\frac{8}{129}[2(x-\frac{1}{4})^2] +\frac{8}{129}[4y^2] =1\\\\\frac{16(x-\frac{1}{4})^2}{129}+\frac{32(y-0)^2}{129}=1[/tex]

[tex]\frac{(x-\frac{1}{4})^2}{\frac{129}{16}}+\frac{(y-0)^2}{\frac{129}{32}}=1[/tex]

We know that the general equation of an ellipse has the form

[tex]\frac{(x-h)^2}{a^2} +\frac{(y-k)^2}{b^2}=1[/tex]

Then the equation

[tex]\frac{(x-\frac{1}{4})^2}{\frac{129}{16}}+\frac{(y-0)^2}{\frac{129}{32}}=1[/tex]

is an ellipse with center [tex](\frac{1}{4}, 0)[/tex]

[tex]a =\sqrt{\frac{129}{16}}[/tex]  and  [tex]b=\sqrt{\frac{129}{32}}[/tex]

Observe the attached image

Find the maximum value of the function for the polygonal convex set determined by the given system of inequalities (Picture provided)

Answers

Answer:

- The maximum value is 86 occurs at (8 , 7)

Step-by-step explanation:

* Lets remember that a function with 2 variables can written

 f(x , y) = ax + by + c

- We can find a maximum or minimum value that a function has for

 the points in the polygonal convex set

- Solve the inequalities to find the vertex of the polygon

- Use f(x , y) = ax + by + c to find the maximum value

∵ 3x + 4y = 19 ⇒ (1)

∵ -3x + 7y = 25 ⇒ (2)

- Add (1) and (2)

∴ 11y = 44 ⇒ divide both sides by 11

∴ y = 4 ⇒ substitute this value in (1)

∴ 3x + 4(4) = 19

∴ 3x + 16 = 19 ⇒ subtract 16 from both sides

∴ 3x = 3 ⇒ ÷ 3

∴ x = 1

- One vertex is (1 , 4)

∵ 3x + 4y = 19 ⇒ (1)

∵ -6x + 3y = -27 ⇒ (2)

- Multiply (1) by 2

∴ 6x + 8y = 38 ⇒ (3)

- Add (2) and (3)

∴ 11y = 11 ⇒ ÷ 11

∴ y = 1 ⇒ substitute this value in (1)

∴ 3x + 4(1) = 19

∴ 3x + 4 = 19 ⇒ subtract 4 from both sides

∴ 3x = 15 ⇒ ÷ 3

∴ x = 5

- Another vertex is (5 , 1)

∵ -3x + 7y = 25 ⇒ (1)

∵ -6x + 3y = -27 ⇒ (2)

- Multiply (1) by -2

∴ -6x - 14y = -50 ⇒ (3)

- Add (2) and (3)

∴ -11y = -77 ⇒ ÷ -11

∴ y = 7 ⇒ substitute this value in (1)

∴ -3x + 7(7) = 25

∴ -3x + 49 = 25 ⇒ subtract 49 from both sides

∴ -3x = -24 ⇒ ÷ -3

∴ x = 8

- Another vertex is (8 , 7)

* Now lets substitute them in f(x , y) to find the maximum value

∵ f(x , y) = 2x + 10y

∴ f(1 , 4) = 2(1) + 10(4) = 2 + 40 = 42

∴ f(5 , 1) = 2(5) + 10(1) = 10 + 10 = 20

∴ f(8 , 7) = 2(8) + 10(7) = 16 + 70 = 86

- The maximum value is 86 occurs at (8 , 7)

Answer:

B  (5, 1)

Step-by-step explanation:

a carpenter agrees to work under the condition that she is to be paid $55 every day she works and she must pay $66 every day she does not work. at the end of 30 days, she finds she has earned 77$. how many days did she work?

Answers

Answer:

17 days

Step-by-step explanation:

For each day she works, she earns +55 and each day she DOES NOT work she earns -66. Total 30 days.

Let number of days she works be x

thus, number of days she DOES NOT work is 30 - x

We can setup an equation as:

55(x) + -66(30-x) = 77

This means, she works x days for 55 each and 30 - x days getting -66 each, totalling 77.

We can solve for x to find number of days she worked. Work shown below:

[tex]55(x) + -66(30-x) = 77\\55x-66(30)+66x=77\\121x -1980 = 77\\121x = 77+1980\\121x = 2057\\x=\frac{2057}{121}\\x=17[/tex]

Thus, she worked 17 days

La expresión algebraica que indica: «Si al cuadrado de la suma de dos números a y b le restamos la mitad de c y la diferencia resultante la multiplicamos por 5» es:

Answers

The sum of two number a and b is [tex]a+b[/tex]

Its square is [tex](a+b)^2[/tex]

Half of c is [tex]\frac{c}{2}[/tex]

And we have to subtract this from what we got before:

[tex](a+b)^2-\dfrac{c}{2}[/tex]

Finally, we multiply everything by 5:

[tex]5\left[(a+b)^2-\dfrac{c}{2}\right][/tex]

Queremos, a partir de una frase, escribir la correspondiente expresión algebraica.

Obtendremos:

[tex][(a + b)^2 - c/2]*5[/tex]

-----------------------------------

Lo que nos dan es:

"Si al cuadrado de la suma de dos números a y b le restamos la mitad de c y la diferencia resultante la multiplicamos por 5"

Veamos esto en partes, la primera dice:

"Si al cuadrado de la suma de dos números a y b..."

El cuadrado de la suma de dos números a y b se escribe como:

[tex](a + b)^2[/tex]

Ahora tenemos:

"Si al cuadrado de la suma de dos números a y b le restamos la mitad de c ..."

Ahora le restamos la mitad de c a lo que encontramos antes:

[tex](a + b)^2 - c/2[/tex]

Finalmente:

"Si al cuadrado de la suma de dos números a y b le restamos la mitad de c y la diferencia resultante la multiplicamos por 5"

Es decir, debemos multiplicar por 5 a la diferencia (la resta) de arriba:

[tex][(a + b)^2 - c/2]*5[/tex]

Está es la expresión que queriamos encontrar.

Si quieres aprender más, puedes leer:

https://brainly.com/question/24758907

Graph each function. Label x-axis.​

Answers

Answer:

Here's what I get.

Step-by-step explanation:

Question 4

The general equation for a sine function is

y = a sin[b(x - h)] + k

where a, b, h, and k are the parameters.

Your sine wave is

y = 3sin[4(x + π/4)] - 2

Let's examine each of these parameters.

Case 1. a = 1; b = 1; h = 0; k = 0

y = sin x

This is a normal sine curve (the red line in Fig. 1).

(Sorry. I forgot to label the x-axis, but it's always the horizontal axes)

Case 2. a = 3; b = 1; h = 0; k = 0

y = 3sin x

The amplitude changes from 1 to 3.

The parameter a controls the amplitude of the wave (the blue line in Fig. 1).

Case 3. a = 3; b = 1; h = 0; k = 2

y = 3sin x - 2

The graph shifts down two units.

The parameter k controls the vertical shift of the wave (the green line

in Fig. 1).

Case 4. a = 3; b = 4; h = 0; k = 2

y = 3sin(4x) - 2

The period decreases by a factor of four, from 2π to π/2.

The parameter b controls the period of the wave (the purple line in Fig. 2).

Case 5. a = 3; b = 4; h = -π/4; k = 2

y = 3sin[4(x + π/4)] - 2

The graph shifts π/4 units to the left.

The parameter h controls the horizontal shift of the wave (the black dotted line in Fig. 2).

[tex]\boxed{a = 3; b = 4; h = \frac{\pi}{2}; k = -2}}[/tex]

[tex]\text{amplitude = 3; period = } \dfrac{\pi}{2}}[/tex]

[tex]\textbf{Transformations:}\\\text{1. Dilate across x-axis by a scale factor of 3}\\\text{2. Translate down two units}\\\text{3. Dilate across y-axis by a scale factor of } \frac{1}{4}\\\text{4. Translate left by } \frac{\pi}{4}[/tex]

Question 6

y = -1cos[1(x – π)] + 3

[tex]\boxed{a = -1, b = 1, h = \pi, k = 3}[/tex]

[tex]\boxed{\text{amplitude = 1; period = } \pi}[/tex]

Effect of parameters

Refer to Fig. 3.

Original cosine: Solid red line

m = -1: Dashed blue line (reflected across x-axis)

 k = 3: Dashed green line (shifted up three units)

 b = 1: No change

h = π: Orange line (shifted right by π units)

[tex]\textbf{Transformations:}\\\text{1. Reflect across x-axis}\\\text{2. Translate up three units}\\\text{3. Translate right by } \pi[/tex]

Two rigid transformations are used to map ABC to QRS. The first is a translation of vertex B to vertex R. What is the second transformation?




a reflection across the line containing AB




a rotation about point B




a reflection across the line containing CB




a rotation about point C

Answers

Answer:a reflection across the line containing AB

Step-by-step explanation:

The correct option is A).

Step-by-step explanation:

Given :

First Transformation is a translation of vertex B to vertex R.

AB = RQ   (refer the given figure)

Solution :

The second transformation is obviously a reflection across the line containing AB because AB = RQ and there is translation of vertex B to vertex R therefore there is also a translation of vertex A to vertex Q and through observing the given diagram we can say that there is a reflection across the line containing AB.

Hence, the correct option is A).

For more information, refer the link given below

https://brainly.com/question/21454252?referrer=searchResults

polynomials what is the product of
1/2x - 1/4 and 5x^2-2x+6

Answers

Answer:

[tex]\frac{5}{2}x^3-\frac{9}{4}x^2+\frac{7}{2}x-\frac{3}{2}[/tex]

Step-by-step explanation:

Given polynomials are [tex]\frac{1}{2}x-\frac{1}{4}[/tex] and [tex]5x^2-2x+6[/tex].

Now we need to find their product which can be done as follows:

[tex]\left(\frac{1}{2}x-\frac{1}{4}\right)\left(5x^2-2x+6\right)[/tex]

[tex]=5x^2\left(\frac{1}{2}x-\frac{1}{4}\right)-2x\left(\frac{1}{2}x-\frac{1}{4}\right)+6\left(\frac{1}{2}x-\frac{1}{4}\right)[/tex]

[tex]=\frac{5}{2}x^3-\frac{5}{4}x^2-x^2+\frac{1}{2}x+3x-\frac{3}{2}[/tex]

[tex]=\frac{5}{2}x^3-\frac{9}{4}x^2+\frac{7}{2}x-\frac{3}{2}[/tex]

Hence final answer is [tex]\frac{5}{2}x^3-\frac{9}{4}x^2+\frac{7}{2}x-\frac{3}{2}[/tex].

The function[tex]f(x)=-3x^{3} +x^{2} +2x[/tex] rises as x grows very small.

A. True
B. False

Answers

Answer:

True

Step-by-step explanation:

True.

Like the cubic term -3x^3 is negative, for small values of "x", the dependent variable "y" will rise. All this can be verified by looking at the graph.

Examine today’s stock listing for SFT Legal, shown below.








52 wk High


52 wk Low


Symbol


Div.


Close


Net Change



74.80


44.61


SFT


8.94


56.11


5.74







What was the price of SFT Legal yesterday?

Answers

Answer:

its D

Step-by-step explanation:

Answer:it would be c because the stock increased by 5.74 over yesterday’s price

Step-by-step explanation:

MATH HELP

use distance = rate time (d=rt) to find the number of miles per hour Etty must drive to go 45 miles in 35 minutes. ( remember time is written in hours?

Answers

Answer:

rate=1.28571428571.. (1.29) miles per minute, or 77.1428571429.. (77.14) mph

Step-by-step explanation:

"use distance = rate time (d=rt) to find the number of miles per hour Etty must drive to go 45 miles in 35 minutes. ( remember time is written in hours?"

distance=rate*time--- we know distance and time

45 mi= rate*35

rate=45/35

rate=1.28571428571 miles per minute, or 77.1428571429 mph

Answer:

Step-by-step explanation:

77/14mph

A function is created to represent the amount of money you save or spend each day of the week. What restrictions would be made to the range?

A) The range would only include integers.
B) The range would only include positive integers.
C) The range would only include negative integers.
D) The range would include all real numbers.

Answers

The range would only include positive integers.

Answer B

Which solid does NOT have the net form? hexagonal prism hexagonal pyramid rectangular prism rectangular pyramid

Answers

Answer:

hexagonal pyramid

Step-by-step explanation:

is this right? in the triangle below what ration is csc 0?

Answers

Answer:

[tex]\frac{13}{5}[/tex]

Step-by-step explanation:

we know that

[tex]csc(\theta)=\frac{1}{sin(\theta)}[/tex]

In this problem

[tex]sin(\theta)=\frac{1.5}{3.9}[/tex]

substitute

[tex]csc(\theta)=\frac{3.9}{1.5}[/tex]

Multiply by 10 both numerator and denominator

[tex]csc(\theta)=\frac{39}{15}[/tex]

Divide by 3 both numerator and denominator

[tex]csc(\theta)=\frac{13}{5}[/tex]

The dairy cows on Mr. Aaron's farm eat 9,315 pounds of grain in 3 months.How many pounds of grain will the cows eat in one month.

Answers

Answer:

3,105

Step-by-step explanation:

the answer is 3,105 because you simply take the total number that was eaten in 3 months and divide it by 3 since they only want to know what was eaten in 1 month

A certain forest covers an area of 2600 km 2 suppose that each year this area decreases by 9% . What will the area be after 5 years ?

Answers

Answer:

Final answer is approx 1622.48 square kilometers.

Step-by-step explanation:

Given that a certain forest covers an area of 2600 km 2 suppose that each year this area decreases by 9% . Now we need to find about what will the area be after 5 years.

So we need to plug these values into decay formula which is given by:

[tex]A=P(1-r)^t[/tex]

Where P=2600

r= rate = 9%= 0.09

t=time = 5 years

Plug these values into above formula, we get:

[tex]A=2600(1-0.09)^5[/tex]

[tex]A=2600(0.91)^5[/tex]

[tex]A=2600(0.6240321451)[/tex]

[tex]A=1622.48357726[/tex]

Hence final answer is approx 1622.48 square kilometers.

Final answer:

Using the exponential decay formula, A = A_0 (1-r)^t, the forest area after 5 years with an annual decrease of 9% is approximately 1622.4 km².

Explanation:

To calculate the forest area after 5 years with an annual decrease of 9%, we can use the formula for exponential decay. The original area of the forest is 2600 km2.

Formula for exponential decay: A = A_0 (1-r)^t, where A is the area after time t, A_0 is the original area, r is the rate of decrease, and t is time in years.Convert the percentage to a decimal: r = 9% or r = 0.09.Substitute the values into the formula: A = 2600 (1-0.09)^5.Calculate: A ≈ 2600 (0.91)^5.Compute the final area: A ≈ 2600 * 0.624 ≈ 1622.4 km2.

So, if the forest continues to decrease by 9% annually, the area will be approximately 1622.4 km2 after 5 years.

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