Calculate the force of friction for a 5kg aluminum block being pulled with constant velocity (uniform motion) across a horizontal steel plank. ...?

The answer is not D.  Just got it incorrect on my quiz.

Answer:

A.  The light will take 200 million years to reach Earth.

Explanation:

Answer:

Explanation:

The gravitation force of attraction between the two bodies is directly proportional tp the product of masses of two bodies and inversely proportional to the square of distance between them.

Upon striking the ground, the person's momentum goes to zero as they stop, with the momentum transferred to the Earth. Bending the knees upon landing extends the stopping distance, reducing the force experienced.

When a person jumps from a tree to the ground, the momentum of the person upon striking the ground changes drastically. Momentum is a product of the mass of an object and its velocity. In this case, the person carries momentum as they fall, due to their velocity and mass. Upon impact with the ground, this momentum is quickly reduced to zero because the person comes to a stop. According to the law of conservation of momentum, the momentum lost by the person is transferred to the Earth.

However, because the Earth's mass is so immense compared to that of the person, the change in the Earth's velocity is negligible and unobservable. If the person lands with stiff knees, a large force is experienced over a shorter stopping distance, while bending the knees extends the stopping distance, resulting in a smaller force felt by the person.

Final answer:

Given the density of gold and the dimensions of a 10-centimeter cube, a solid gold phone would weigh about 45 lbs, making it too heavy to casually pass around a table. Therefore, the correct answer is 3.

Explanation:

The question asks if a solid gold phone, with a volume equal to a 10-centimeter cube of gold, could be casually passed around a table from hand to hand. Given the density of gold is 19,300 kg/m³, we first calculate the volume of the cube in cubic meters (m³) by converting its dimensions from centimeters to meters (0.1 m x 0.1 m x 0.1 m = 0.001 m³). Multiplying this volume by the density of gold gives us the mass of the gold phone (0.001 m³ x 19,300 kg/m³ = 19.3 kg). Converting this mass into pounds (1 kg ≈ 2.2 lbs), the weight of the phone is approximately 42.46 lbs.

Therefore, the correct answer is 3: No; it weighs about 45 lbs. Such a phone would be quite heavy and not easily passed around from hand to hand.

Answer:

The new volume of the gas is 2 m³

Explanation:

It is given that,

Initial temperature, [tex]T_1=5\ K[/tex]

Initial volume, [tex]V_1=1\ m^3[/tex]            

Final temperature, [tex]T_2=10\ K[/tex]

We need to find the new volume. The Charles law gives the relation between the temperature and the volume of the gas.    

i.e

[tex]V\propto T[/tex]

[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

[tex]V_2=\dfrac{V_1}{T_1}\times T_2[/tex]

[tex]V_2=\dfrac{1}{5}\times 10[/tex]

[tex]V_2=2\ m^3[/tex]

So, the new volume of the gas is 2 m³. Hence, this is the required solution.

Final answer:

To find the average force of traction for the car, you can use the work-energy principle to determine the work done, which equals the change in kinetic energy. The work done is equal to the force multiplied by the distance, and from this, the average force can be calculated. The average force of traction in this case is 2723.17 N.

Explanation:

To calculate the average force of traction for a 1250 kg car that accelerates from rest to 6.13 m/s over a distance of 8.58 m, we can use the work-energy principle. This principle states that the work done by a force on an object is equal to the change in kinetic energy of the object.

First, let's find the final kinetic energy (KE) of the car:

KE = 0.5 * m * v^2

KE = 0.5 * 1250 kg * (6.13 m/s)^2

KE = 23369.8125 J (joules)

The work done (W) by the traction force is also the change in kinetic energy, so W = KE = 23369.8125 J. Since work is defined as the force multiplied by the distance (W = F * d), we can rearrange the formula to solve for the average force (F):

F = W / d

F = 23369.8125 J / 8.58 m

F = 2723.17 N (newtons)

Therefore, the average force of traction that the car experienced was 2723.17 N.

To calculate the perimeter of the fence around the spa, you use the formula 2πr, substituting the spa's radius, 5/√2-1 feet, into the formula.

The radius of the spa is given as 5/√2-1 feet. To find the perimeter of the fence, which is the same as the circumference of the circular spa, you use the formula 2πr, where r is the radius of the circle.

Substitute the given radius into the formula:

Perimeter = 2π(5/√2-1)

Perform the multiplication to obtain the perimeter. This will give you the total length of the fence needed to surround the spa.

The magnitude of the acceleration of the cream tangerine as it passes by each window is constant at approximately 9.8 m/s² due to Earth's gravity.

You asked about the magnitude of the acceleration of a cream tangerine as it passes by three evenly spaced windows. When any object is thrown upward or downward close to the Earth's surface, it is accelerated by gravity. This acceleration is constant and has a magnitude of approximately 9.8 m/s² downward. This means that no matter which window the cream tangerine is passing, the magnitude of its acceleration will be the same because gravity is a constant force close to the surface of the Earth. Therefore, when ranking the windows according to the magnitude of acceleration of the cream tangerine while passing them, they will all be the same and thus tied for first place.

Final answer:

The frequency of the spring in the NASA test vehicle is approximately 2.28 Hz.

Explanation:

To determine the frequency of the spring in the NASA test vehicle, we need to use the equation for the frequency of a mass-spring system:

f = 1 / (2π) * sqrt(k / m)

Where f is the frequency, k is the force constant of the spring, and m is the mass of the ball.

Plugging in the given values, we get:

f = 1 / (2π) * sqrt(229 N/m / 3.50 kg)

Calculating this, we find that the frequency is approximately 2.28 Hz.

The question involves analyzing the motion of a football being kicked with given initial velocity and angle in Physics.

Physics: The question involves analyzing the motion of a football being kicked with given initial velocity and angle.

Example: Ingrid kicks a football with an initial velocity of 12 m/s at an angle of 45 degrees relative to the ground.

Concepts: Projectile motion, velocity, angle, and distance traveled are essential in solving such problems in physics.

 a)

At constant pressure, the work done for gas to expand is given by:

W = PΔV

⇒W = 1.65 × 10⁵Pa × (0.320 - 0.110)m³= 3.46 × 10⁴J

b)

The total heat (Q) added to the system is used in work done and the remaining energy goes into internal energy.

ΔU = ΔQ-ΔW

⇒ΔU = 1.15 ×10⁵J - 3.46 × 10⁴J = 0.8 × 10⁵ J

c)

It does not matter that the gas is ideal or real because the work done would remain same. It would vary for real gases only at very high pressure.

(a). The work done by the gas is [tex]\boxed{3.47 \times {{10}^4}\,{\text{J}}}[/tex].

(b). The change in the internal energy of the gas is [tex]\boxed{8.03 \times {{10}^4}\,{\text{J}}}[/tex].

(c). There is no effect of the gas being ideal gas or real gas on the work done by the gas.

Further Explanation:

Given:

The initial volume of the gas is [tex]0.110\,{{\text{m}}^{\text{3}}}[/tex] .

The final volume of the gas is [tex]0.320\,{{\text{m}}^{\text{3}}}[/tex] .

The constant pressure at which the expansion of the gas takes place is [tex]1.65 \times {10^5}\,{\text{Pa}}[/tex] .

The amount of heat added to the gas is [tex]1.15 \times {10^5}\,{\text{J}}[/tex].

Concept:

Part (a):

The expansion of the gas is taking place at constant pressure. Therefore, the work done by the gas is:

[tex]W = P\left( {{V_f} - {V_i}}\right)[/tex]

Here, [tex]P[/tex] is the pressure and [tex]{V_f}[/tex] is the final volume and [tex]{V_i}[/tex] is the initial volume of the gas.

Substitute the values of [tex]P[/tex] , [tex]{V_i}[/tex] and [tex]{V_f}[/tex] in above expression .

[tex]\begin{aligned}W&= \left( {1.65 \times {{10}^5}} \right) \times \left( {0.320 - 0.110} \right)\\&= 3.465 \times {10^4}\,{\text{J}}\\&\approx 3.{\text{47}} \times {\text{1}}{{\text{0}}^4}\,{\text{J}}\\\end{aligned}[/tex]

Therefore, the work done by the gas is [tex]\boxed{3.47 \times {{10}^4}\,{\text{J}}}[/tex]

Part (b):

The change in internal energy of the gas is given by the first law of thermodynamics:

[tex]\begin{aligned}\Delta Q = \Delta U + W \hfill\\\Delta U = \Delta Q - W \hfill\\\end{aligned}[/tex]

Here, [tex]\Delta Q[/tex] is the heat added, [tex]\Delta U[/tex] is the change in internal energy of system and  [tex]W[/tex] is the work done by the gas.

Substitute the values of [tex]\Delta Q[/tex] and [tex]W[/tex] in above equation.

Part (c):

The ideal gas or the real gas does not affect the process of the expansion of gas because the change in energy of the gas is given by the First law of thermodynamics. The first law of thermodynamics is based on the conservation of energy.

The energy of a system will always remain conserved whether it has the real gas or the ideal gas.

Thus, there is no effect of the gas being ideal gas or real gas on the work done by the gas.

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Answer Details:

Grade: High School

Subject: Physics

Chapter: Law of Thermodynamics

Keywords:  Ideal gas, cylinder, first law of thermodynamics, pressure constant, 0.110m^3 to 0.320 m^3, expansion, change in internal energy, work done by gas.

Answer: Fossils range from simple to complex across rock layers.

Explanation:

The finding of the fossils in the different layers of the earth crust suggests that the evolution of the living organisms from simple primitive one to the most complex organisms. The examination and determination of the morphological, anatomical and molecular features of the organisms in the fossils have helped in determining the chronological age and has also been helped in determination of the age of earth with respect to the fossils.

1200

Then; dn=k  

We can use the relationship to find the unknown, k:  

k = dn  

k = (24)(400) = 9600  

Then use k to find the unknown n:  

k= dn  

9600 = 8n  

n = 1200  

= 200 rpm

The mechanical advantage of the system is 0.1.

When you are applying the input force, rope is pulled by 10m.

The power is 40 Watt.

Mechanical advantage is the ratio of power output to the power input.

M.A= 20 N / 200 N

M.A = 0.1

Thus, the mechanical advantage is 0.1.

The length of rope pulled = 1m / M.A

= 1/0.1

= 10m

Thus, when you are applying the input force, rope is pulled by 10m.

Work done by the force = force * distance traveled

W = 200N * 1m = 200 J

Power = Work done /time

P = 200 J/5s

P = 40 Watt

Thus, the power is 40 Watt.

Learn more about Mechanical advantage.

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Final answer:

To lift a 200N box 1 meter with a MA of 10, you must pull the rope 10 meters. The mechanical advantage is calculated by dividing the output force by the input force. The power required to lift the box in 5 seconds is 40 Watts.

Explanation:

To calculate the mechanical advantage (MA) of the system, we divide the output force by the input force. In this case, the output force is 200 newtons, and the input force is 20 newtons. Therefore, the MA of the system is 200N / 20N = 10.

To find out how far you must pull the rope, we use the concept that work input equals work output, assuming negligible losses due to friction or inefficiency. Because the MA is 10, and to lift the load 1 meter, you have to pull the rope 10 meters. The distance you have to pull the rope is directly proportional to the MA when lifting a load using a pulley system.

The power of the system can be calculated by dividing the work done by the time taken. Work done is force times distance (Output force * height lifted = 200N * 1m = 200 Joules) and the time taken is 5 seconds. Power = Work/Time = 200J/5s = 40 Watts.

A substance that is made up of only one kind of atom is called an element.

Elements are pure substances that cannot be broken down into simpler substances by ordinary chemical or physical means. Each element is unique and consists entirely of one type of atom. For example, hydrogen, calcium, and iron are all elements, as they are each made up of only one type of atom.

The Periodic Table of the Elements lists all known elements, providing information about their atomic structure and properties. Many substances in the world are made up of combinations of different elements.

This question involves the concepts of the bouyant force, weight, and volume.

The area of the slab is "[tex]\frac{m}{h(\rho_w-\rho_s)}[/tex]".

In order for the styrofoam slab to float on the water, the buoyant force acting on it must be equal to its weight:

[tex]Weight = Buoyant\ Force\\(m+M)g=\rho_w Vg\\m+M=\rho_w V[/tex]

where,

m = mass of swimmer

A = area of styrofoam slab = ?

h = thickness of strrofoam slab

[tex]\rho_s[/tex] = density of styrofoam slab

[tex]\rho_w[/tex] = density of water

M = mass of styrofoam slab = [tex]Ah\rho_s[/tex]

V = volume of styrofoam slab = Ah

Therefore,

[tex]m+(Ah\rho_s) = Ah\rho_w\\m= Ah(\rho_w-\rho_s)\\\\A=\frac{m}{h(\rho_w-\rho_s)}[/tex]

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From the calculations and the data supplied, the braking distance is 65 m

The braking force is the force that is applied as the object comes to rest.

We know that the mass of the car is obtained from; 14,700 N/10 m/s^2 = 1470 Kg

Now;

a = F/m = 7100 N/1470 Kg

a = 4.8 m/s^2

Given that;

v^2 = u^2 - 2as

u^2 = 2as

s =  u^2/2a

s = (25)^2/2 * 4.8

s = 625/9.6

s = 65 m

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To determine the time a projectile remains in the air, calculate the initial vertical velocity using the sine of the launch angle and then apply kinematic equations to solve for time using the vertical displacement and acceleration due to gravity.

The student's question is related to the time a projectile remains in the air, which is a topic in Physics, specifically in kinematics. To find the time of flight for the projectile, we need to consider the vertical motion since the horizontal and vertical motions are independent.

Given that the initial speed of the ball is 16.0 m/s and it is thrown at a 60.0° angle, we can find the initial vertical velocity (Vy) using the sine function: Vy = 16.0 m/s * sin(60.0°).

The vertical displacement Δy for the ball when it hits the ground will be -2.00 m (negative since it's ending below the point of release). We will use the following kinematic equation for vertical displacement: Δy = Vy * t + 0.5 * g * t^2, where g is the acceleration due to gravity (-9.8 m/s^2, negative as it's directed downwards).

By substituting the known values and solving the quadratic equation for t (time), we can determine the total time the ball remains in the air.

Answer: The correct answer is "amplitude".

Explanation:

The expression of the energy in terms of frequency is as follows;

E=hf

Here, h is Planck's constant, E is the energy and f is the frequency of the wave.

Here, the energy is directly proportional to the frequency of the wave. The energy of the wave is inversely proportional to the wavelength of the wave.

Amplitude is the maximum displacement of the particle from its equilibrium position in the vertical direction.

The amount of energy carried by a wave is directly proportional to the square of the amplitude. More the energy of the wave, more will be amplitude of the wave. Lesser the energy of the wave, lesser will be the amplitude of the wave.

Therefore, the correct option is (B).

sublimation is the correct answer

Answer:

with longer vectors

Explanation:

In any motion map of vectors we know that length of vectors is used to represent the magnitude

while the direction of the vector is represented by the angle made by the vector.

So here we have to represent the larger or greater velocity

This represents the magnitude of the vector to be more

so the correct answer would be

"with Longer vectors" we can show or represent velocity vector of greater velocity.