Answer:
(a)[tex]\Delta H\textdegree = -2856.8\;\text{kJ}[/tex] per mole reaction.
(b)[tex]\Delta H\textdegree = -22.3\;\text{kJ}[/tex] per mole reaction.
Explanation:
What is the standard enthalpy of formation [tex]\Delta H_f\textdegree{}[/tex] of a substance? [tex]\Delta H_f\textdegree{}[/tex] the enthalpy change when one mole of the substance is formed from the most stable allotrope of its elements under standard conditions.
Naturally, [tex]\Delta H_f\textdegree{} = 0[/tex] for the most stable allotrope of each element under standard conditions. For example, oxygen [tex]\text{O}_2[/tex] (not ozone [tex]\text{O}_3[/tex]) is the most stable allotrope of oxygen. Also, under STP [tex]\text{O}_2[/tex] is a gas. Forming [tex]\text{O}_2\;(g)[/tex] from itself does not involve any chemical or physical change. As a result, [tex]\Delta H_f\textdegree{} = 0[/tex] for [tex]\text{O}_2\;(g)[/tex].
Look up standard enthalpy of formation [tex]\Delta H_f\textdegree{}[/tex] data for the rest of the species. In case one or more values are not available from your school, here are the published ones. Note the state symbols of the compounds (water/steam [tex]\text{H}_2\text{O}[/tex] in particular) and the sign of the enthalpy changes.
[tex]\text{C}_2\text{H}_6\;(g)[/tex]: [tex]-84.0\;\text{kJ}\cdot\text{mol}^{-1}[/tex];[tex]\text{CO}_2\;(g)[/tex]: [tex]-393.5\;\text{kJ}\cdot\text{mol}^{-1}[/tex];[tex]\text{H}_2\text{O}\;{\bf (g)}[/tex]: [tex]-241.8\;\text{kJ}\cdot\text{mol}^{-1}[/tex];[tex]\text{PbO}\;(s)[/tex]: [tex]-217.9\;\text{kJ}\cdot\text{mol}^{-1}[/tex];[tex]\text{PbO}_2\;(s)[/tex]: [tex]-276.6\;\text{kJ}\cdot\text{mol}^{-1}[/tex];[tex]\text{Pb}_3\text{O}_4\;(s)[/tex]: [tex]-734.7\;\text{kJ}\cdot\text{mol}^{-1}[/tex]How to calculate the enthalpy change of a reaction [tex]\Delta H_\text{rxn}[/tex] (or simply [tex]\Delta H[/tex] from enthalpies of formation?
Multiply the enthalpy of formation of each product by its coefficient in the equation.Find the sum of these values. Label the sum [tex]\Sigma (n\cdot \Delta_f(\text{Reactants}))[/tex] to show that this value takes the coefficients into account.Multiply the enthalpy of formation of each reactant by its coefficient in the equation.Find the sum of these values. Label the sum [tex]\Sigma (n\cdot \Delta_f(\text{Products}))[/tex] to show that this value takes the coefficient into account.Change = Final - Initial. So is the case with enthalpy changes. [tex]\Delta H_\text{rxn} = \Sigma (n\cdot \Delta_f(\textbf{Products})) - \Sigma (n\cdot \Delta_f(\textbf{Reactants}))[/tex].For the first reaction:
[tex]\Sigma (n\cdot \Delta_f(\text{Reactants})) = 4\times (-393.5) + 6\times (-241.8) = -3024.8\;\text{kJ}\cdot\text{mol}^{-1}[/tex];[tex]\Sigma (n\cdot \Delta_f(\text{Products})) = 2\times (-84.0) + 7\times 0 = -168.0\;\text{kJ}\cdot\text{mol}^{-1}[/tex];[tex]\begin{aligned}\Delta H_\text{rxn} &= \Sigma (n\cdot \Delta_f(\textbf{Products})) - \Sigma (n\cdot \Delta_f(\textbf{Reactants}))\\ &= (-3024.8\;\text{kJ}\cdot\text{mol}^{-1}) - (-168.0\;\text{kJ}\cdot\text{mol}^{-1})\\ &= -2856.8\;\text{kJ}\cdot\text{mol}^{-1} \end{aligned}[/tex].Try these steps for the second reaction:
[tex]\Delta H_\text{rxn} = -22.3\;\text{kJ}\cdot\text{mol}^{-1}[/tex].
A gas is collected over water at a certain temperature. The total pressure is 762. mmHg. The vapor pressure of water at this temperature is 17 mmHg. What is the partial pressure of the collected gas?
A. 762 mmHg
B. 17 mmHg
C. 779 mmHg
D. 745 mmHg
E. None of the above
I strongly would choose D
CS2 (s) + 3 O2 (g) → CO2 (g) + 2 SO2 (g)
Using the formula above how many liters of SO2 can be made from 3.1 L of O2 at STP? Round your answer to two decimal places.
Answer:
2.067 L ≅ 2.07 L.
Explanation:
The balanced equation for the mentioned reaction is:CS₂(g) + 3O₂(g) → CO₂(g) + 2SO₂(g),
It is clear that 1.0 mole of CS₂ react with 3.0 mole of O₂ to produce 1.0 mole of CO₂ and 2.0 moles of SO₂.
At STP, 3.6 L of H₂ reacts with (?? L) of oxygen gas:It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.
using cross multiplication:
1.0 mol of O₂ represents → 22.4 L.
??? mol of O₂ represents → 3.1 L.
∴ 3.1 L of O₂ represents = (1.0 mol)(3.1 L)/(22.4 L) = 0.1384 mol.
To find the no. of moles of SO₂ produced from 3.1 liters (0.1384 mol) of hydrogen:Using cross multiplication:
3.0 mol of O₂ produce → 2.0 mol of SO₂, from stichiometry.
0.1384 mol of O₂ produce → ??? mol of SO₂.
∴ The no. of moles of SO₂ = (2.0 mol)(0.1384 mol)/(3.0 mol) = 0.09227 mol.
Again, using cross multiplication:1.0 mol of SO₂ represents → 22.4 L, at STP.
0.09227 mol of SO₂ represents → ??? L.
∴ The no. of liters of SO₂ will be produced = (0.09227 mol)(22.4 L)/(1.0 mol) = 2.067 L ≅ 2.07 L.
Atoms with an atomic number greater than ____ will undergo fission.
Answer:
26
Explanation:
THIS IS FOR AP EX I SWEAR TO GOD, IT IS NOT 56.
Atoms with an atomic number greater than 92, like U-235 or U-238 and 239Pu, are usually the ones to undergo nuclear fission. Fission involves a large nucleus splitting into smaller parts and often releasing neutrons that can continue the reaction. However, the outcome of the process varies.
Explanation:Atoms with an atomic number greater than 92, such as Uranium-235 or 238 and Plutonium-239, are typically the ones that undergo nuclear fission. Nuclear fission refers to the process of a large nucleus splitting into smaller nuclei, often induced by bombardment with neutrons. When a nucleus such as Uranium-235 (235U) undergoes fission, as in the example of 235U + n, the large U-235 nucleus produces two or three neutrons in the process, each capable of causing fission in another nucleus, which can potentially lead to a nuclear chain reaction.
However, it's important to note that not all atoms with an atomic number greater than 92 will necessarily go through fission. Fission is a statistical process and various products are produced with different probabilities. Therefore, though certain isotopes like 235U and 239Pu are easier to instigate fission in, the outcome can vary.
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A 50.0 g sample of water at 100.00 C was placed in an insulated cup. Then 25.3 g of zinc at 25.00 C was added to the water. The temperature of the water dropped to 96.68 C. What is the specific heat of the zinc ( the specific heat of h2o is 4.184 J/g C.
Answer: 8.2689J/gC
H=mc(change in temp)
H(water)=50*4.184*3.32=694.5J
H(zinc)=694.5J
c(zinc)=694.5/(25.3*3.32)=8.2689J/gC
Taking into account the expressions and the principle of calorimetry that ensures that the body with a higher temperature will give up thermal energy to the one with a lower temperature until both are in an identical energy state, the specific heat of the zinc is 0.383 [tex]\frac{J}{gC}[/tex].
In first place, you need to know that the Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
The equation for calculating heat exchanges results from the product of the specific heat times the mass of the body and the temperature difference. That is, the amount of heat that a body receives or transmits is determined by:
Q = c×m×ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation (being ΔT= Tfinal - Tinitial)
On the other hand, a calorimeter is a device used to measure the heat of flow of a chemical reaction or physical change. It consists of a container built with insulating walls that limit heat exchanges with the environment in which the substances that give and receive heat are found. Being in a container with insulating walls that do not allow the exchange of energy with the outside, a principle ensures that the body with a higher temperature will give up thermal energy to the one with a lower temperature until both are in an identical energy state. That is, the heat change in the system must be 0. This is:
Qsystem= Qabsorbed + Qyielded
0= Qabsorbed + Qyielded
In this case, the water, when going from a higher temperature to a lower one, delivers a quantity of heat. Then
Qyielded= Qwater= cwater×mwater ×ΔT= 4.184[tex]\frac{J}{gC}[/tex] × 50 g× (96.68 C - 100 C)
On the other hand, the heat given off by the water will be absorbed by the zinc. Then:
Qabsorbed= Qzinc= czinc×mzinc×ΔT= czinc× 25.3 g× (96.68 C - 25 C)
Taking into account the principle mentioned above, it is possible to express:
0= czinc× 25.3 g× (96.68 C - 25 C) + 4.184[tex]\frac{J}{gC}[/tex] × 50 g× (96.68 C - 100 C)
Solving:
0= czinc× 25.3 g× (96.68 C - 25 C) + 4.184[tex]\frac{J}{gC}[/tex] × 50 g× (96.68 C - 100 C)
0= czinc× 25.3 g× 71.68 C + 4.184[tex]\frac{J}{gC}[/tex] × 50 g× (-3.32 C)
0= czinc× 1813.504 g×C - 694.544 J
694.544 J= czinc× 1813.504 g×C
[tex]\frac{694.544 J}{1813.504 gC} =czinc[/tex]
0.383 [tex]\frac{J}{gC}[/tex] =czinc
In summary, the specific heat of the zinc is 0.383 [tex]\frac{J}{gC}[/tex]
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If a geologist wanted to determine if two landmasses were once connected millions of years ago, by using the theory of Continental Drift. Explain what evidence maybe be collected for their investigation, and how they may use this evidence to determine if these land masses were connected.
Fossils found on both landmasses can indicate whether they were connected in the past.
Hello!
I know I am super late to this but this answer is so the other person can have brainliest :)
Have a great day!
~Grace~
How many moles of nitrogen we have at a temperature of 30 ºC, a pressure of 4.0 atm, and a volume of 4000.mL?
Answer:
0.643 mol.
Explanation:
We can use the general law of ideal gas: PV = nRT.where, P is the pressure of the gas in atm (P = 4.0 atm).
V is the volume of the gas in L (V = 4000 mL = 4.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 30ºC + 273 = 303 K).
∴ n = PV/RT = (4.0 atm)(4.0 L)/(0.0821 L.atm/mol.K)(303 K) = 0.643 mol.
Daily exercise is an important part of a healthy lifestyle. Which of the following goals could physical exercise help an individual accomplish?
A.
toning or gaining muscle
B.
reducing the risk of heart disease
C.
lowering body fat
D.
all of these
D. All Of These Would Help An Individual
If a 0.075 liter solution contains 0.0877 mil of CuSO4, what is the concentration in molarity?
Answer:
1.17 M
Explanation:
molarity of a solution is defined as the number of moles dissolved in 1 L of solution
molarity = number of moles / volume of solution
volume of solution is 0.075 L
number of moles of CuSO₄ - 0.0877 mol
substituting these values in the equation
molarity = 0.0877 mol / 0.075 L
molarity = 1.17 mol/L
molarity of CuSO₄ is 1.17 M
After chlorofluorocarbons we’re banned, which class of chemicals was used in their place
Hydrofluorocarbons
Methane
Carbon dioxide
Sulfur dioxide
Answer:
Hydrofluorocarbons
Explanation:
Answer:
Hydrofluorocarbons
Explanation:
Earlier chlorofluorocarbons were used for refrigeration purpose. But they were banned as they were primary cause of ozone depletion.
In order to replace chlorofluorocarbons, now hydrofluorocarbons are used which helps to protect earth from stratospheric ozone-depleting substances.
The difference between chlorofluorocarbons and hydrofluorocarbons is of hydrogen. In hydrofluorocarbons one of the halogen is being replaced by hydrogen.
How many of the following atomic particles does a neutral magnesium
atom have if atomic number is 12, and mass is 24.3050 ?
Protons-
Neutrons-
Electrons-
Answer:
[tex]\boxed{\text{12 p, 12 n, and 12 e}}[/tex]
Explanation:
No atoms of Mg have a mass of 24.3050 u. That is the average mass of all the isotopes of Mg.
However, the most common isotope of Mg is ₁₂²⁴Mg (mass = 23.99 u)
The atomic number of Mg is 12. It has 12 protons.
The atomic mass of ²⁴Mg is 24. That's the total number of protons and neutrons.
p + n = 24
12 + n = 24
n = 12
An atom of ²⁴Mg has 12 neutrons.
If the atom is neutral, the number of electrons equals the number of protons.
e = p = 12
[tex]\text{An atom of }$^{24}$\text{Mg contains }\boxed{\textbf{12 p, 12 n, and 12 e}}[/tex]
Top answer
it seems most correct
What wind direction change usually occurs as a cold front moves through an area?
Answer:
northern winds
Explanation:
The answer is SW to NW
How do the conditions for hurricane differ from the conditions for tornado?
Answer:
The conditions for hurricanes differ from the conditions of tornadoes because of D, Tornadoes form over land, while hurricanes form over bodies of water.
Explanation:
Hurricanes form over warm water in tropical ocean settings and tornadoes form over land within storms.
Nitrogen in a 29 L container at a pressure of 398 mm Hg and 293 K is transferred to a container with a pressure of 307 mm Hg. What is the new temperature if the volume changes to 156 L?
Answer:
70.61°c=T₂
Explanation:
This question is on Combined Gas Laws
The volume of a gas is directly proportional to the absolute temperature and inversely proportional to the pressure.
P₁V₁T₁=P₂V₂T₂
where
P₁=Initial pressure, P₂=final pressure
V₁=Initial volume,V₂=final volume
T₁=Initial temperature in Kevin, T₂=final temperature in Kelvin
Given
P₁=398mm Hg, V₁=29 L and T₁=293 K
P₂=307 mm Hg, V₂=156 L and T₂=?
Solution
P₁V₁T₁=P₂V₂T₂
Substitute values
398×29×293=307×156×T₂
3381806=47892T₂
3381806/47892=T₂
70.61°c=T₂
70.61+273=343.61 K
What would the potential of a standard hydrogen electrode (S.H.E.) be if it was under the following conditions?
[H+] = 0.88M Ph2= 1.7atm T=298k
Answer:
[tex]\boxed{\text{-8.5 mV}}[/tex]
Explanation:
The SHE is not under standard conditions, so we must use the Nernst Equation, which relates the cell potential to the standard potential and to the activities of the electroactive species.
[tex]E = E^{\circ} - \frac{RT}{zF}lnQ[/tex]
Step 1. Write the equation for the cell reaction
Anode: H₂(1 atm) ⇌ 2H⁺(1 mol·L⁻¹) + 2e⁻
Cathode: 2H⁺(0.88 mol·L⁻¹) + 2e⁻ ⇌ H₂(1.7 atm)
Overall: H₂(1 atm) + 2H⁺(0.88 mol·L⁻¹) ⇌ 2H⁺(1 mol·L⁻¹) + H₂(1.7 atm)
Step 2. Calculate Q
[tex]Q = \frac{1 \times 1.7 }{ 1 \times 0.88} = 1.93[/tex]
Step 3. Apply the Nernst equation
Data:
E° = 0 V
R = 8.314 J·K⁻¹mol⁻¹
T = 298 K
n = 2
F = 96 485 C/mol
Calculation:
[tex]E = 0 - \frac{8.314 \times 298}{2 \times 96 485}\ln1.93[/tex]
= -0.0128 × 0.658
= -0.0085 V
= [tex]\boxed{\text{-8.5 mV}}[/tex]
Write the complete symbol for a positron
Answer:
(β⁺), and another one is 01e
The website of a popular stargazers club notes that on Wednesday the moon will rise at 6:23 PM and set at 6:12 PM on Thursday. What is a mistake in this information?
A) The moon sets before 6:00 PM everyday
B) The setting time should have been 6:12 AM
C) The moon rises only after 9:00 PM everyday
D) It is difficult to predict when the moon would set
It's C that's correct because it's very true...
Answer:
the answer is B
Explanation:
if 45.0 ml of 1.50 M Ca(OH)2 are needed to neutralize 25.0 ml of HI of unknown concentration, what is the molarity of the HI?
Answer:
M of HI = 5.4 M.
Explanation:
We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.(XMV) acid = (XMV) base.
where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.
M is the molarity of the acid or base.
V is the volume of the acid or base.
(XMV) HI = (XMV) Ca(OH)₂.
For HI; X = 1, M = ??? M, V = 25.0 mL.
For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.
∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = 5.4 M.
Amoeba use _________ to move and ingest prey.
Answer:
pseudopodia
Explanation:
Giant amoebae engulf their prey by gathering of pseudopods around the bacteria, as the bacteria is drawn in, the cell membrane that surrounds it, pinches off to form an inter-cellular compartment called the vacuole.
you place a balloon in a closed chamber at STP. You increase the chamber pressure by a factor of 10. What happens to the balloon?
pops because of increasing the atmospheric pressure
Answer : The temperature of balloon increases to 10 times of original temperature.
Explanation :
In this problem, volume remain constant. The temperature and pressure will vary.
Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.
[tex]P\propto T[/tex]
or,
[tex]\frac{P_1}{P_2}=\frac{T_1}{T_2}[/tex]
where,
[tex]P_1[/tex] = let initial pressure = x
[tex]P_2[/tex] = final pressure = 10x
[tex]T_1[/tex] = initial temperature
[tex]T_2[/tex] = final temperature
Now put all the given values in the above equation, we get:
[tex]\frac{x}{10x}=\frac{T_1}{T_2}[/tex]
[tex]\frac{T_1}{T_2}=\frac{1}{10}[/tex]
[tex]T_2=10T_1[/tex]
From this we conclude that, the temperature increases to 10 times of original temperature.
Hence, the temperature of balloon increases to 10 times of original temperature.
When does incomplete combustion occur?
A.
sufficient supply of oxygen
B.
insufficient supply of carbon dioxide
C.
sufficient supply of carbon dioxide
D.
insufficient supply of oxygen
Answer:
D. insufficient supply of oxygen
Explanation:
Combustion is an exothermic reaction which involves the burning of a compound in the presence of oxygen. Combustion is a very useful life process as it produces heat and light.
For a complete combustion reaction to occur, the compound must be burnt over excess oxygen. The product is usually carbondioxide and water with release of some particulate matter.
In incomplete combustion, there is deficiency of oxygen. Here, oxygen becomes the limiting agent and it drives the reaction to an end. Incomplete combustion is always accompanied with the production of poisonous carbon monoxide and Carbon. We see incomplete combustion when smoke forms or when burning is accompanied by production of soot.
What makes a combustive process complete or not is the availability of oxygen gas for the reaction.
What is the solute and solvent in an aqueous solution made from sugar and water?
An aqueous solution is a solution in which the solvent is water. It is mostly shown in chemical equations by appending (aq) to the relevant chemical formula. For example, a solution of table salt, or sodium chloride (NaCl), in water would be represented as Na+(aq) + Cl−(aq).
Sugar is the solute and water is the solvent.
What is the solution?A solution is a homogeneous mixture of one or more solutes dissolved in a solvent.
Solvent: the substance in which a solute dissolves to produce a homogeneous mixture.
Solute: the substance that dissolves in a solvent to produce a homogeneous mixture.
Hence, sugar is the solute and water is the solvent.
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how will you prove that a given colourless liquid is an acid
Answer:
Explanation:
One: You could mix a small sample of it with a reactive metal. Underline small. You should see gas bubbles being given up. Usually the bubbles are hydrogen.
Example : K + HCl ===> KCl + H2
Two: You could use an indicator to watch it turn color as it goes from acidic to neutral. Litmus will go from red to blue under these conditions.
Three: Those are the two safest ways. If you knew the acid was dilute, you could put a small (underline small again) amount on your tongue. If it tastes like orange juice, it is likely an acid. This is a test every textbook mentions. You should never do it under any circumstances.
Answer:
1. Using Litmus papers. Litmus paper will turn blue if solution is acidic or it will turn blue if it is basic. ... If pH is below 7 or reddish then the given solution is acidic and if pH is higher than 7 or bluish then the solution is basic.
Explanation:
How many Milligrams of potassium chloride KCl are required to make a 15 mL of a 1.20 M solution?
Answer:
1340 mg
Explanation:
concentration is the number of moles of solute in a 1000 mL of solution
the concentration of KCl solution is 1.20 M
There are 1.20 mol in 1000 mL of solution
a volume of 1000 mL contains - 1.20 mol
therefore 15 mL solution contains - 1.20 mol / 1000 mL x 15 mL = 0.018 mol
the molar mass of KCl is - 74.5 g/mol
mass of 1 mol is - 74.5 g
therefore mass of 0.018 mol is - 74.5 g/mol x 0.018 mol = 1.34 g
1000 mg - 1 g
therefore 1.34 g in milligrams is - 1.34 g x 1000 mg/g = 1340 mg
Need help !!!!! ASAP
The answer is:
Hence, the new pressure will be 2.07 atm.
[tex]P_{2}=2.07atm[/tex]
Why?Since we know that the gas is inside of a rigid container, meaning that the volume will be kept constant, we can solve the problem using the Gay-Lussac's Law.
The the Gay-Lussac's Law establishes that when an ideal gas is kept at constant volume, the pressure and the temperature will be proportional.
We need to pay special attention when we are working with the Gay-Lussac's Law since its equations with absolute temperatures (Kelvin ), so, if we are working with relative temperatures such as Celsius degrees or Fahrenheit degrees, we need to convert the temperatures to Kelvin (absolute temperature)
We can convert from Celsius degrees to Kelvin using the following formula:
[tex]Temperature(K)=Temperature(C\°)+273[/tex]
Then we have the Gay-Lussac's equation:
[tex]\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}[/tex]
Therefore, we are given the following information:
[tex]T_{1}=30\° \\P_{1}=2atm\\T_{2}=40\°[/tex]
Therefore, converting the given temperatures from Celsius degrees to Kelvin, we have:
[tex]T_{1}=30C\°=30+273K=303K\\\\T_{1}=40C\°=40+273K=313K\\[/tex]
Now, calculating we have:
[tex]\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}[/tex]
[tex]P_{2}=\frac{P_{1}}{T_{1}}*T_{2}\\\\P_{2}=\frac{2atm}{303K}*313K=2.07atm[/tex]
Hence, the new pressure will be 2.07 atm.
[tex]P_{2}=2.07atm[/tex]
Have a nice day!
Which energy position do electrons generally want to be in?
the excited state
the ground state
the highest possible energy level
the medium energy level
Answer: the ground state
Explanation: when electron's are attracted to something, they typically rotate counter clockwise, in theory we can apply this to darwin, i recomend that book btw but counter clockwise goes to ground
Answer:
Ground state is correct
If a 53.27g sample of potassium nitrate (KNO3) is dissolved in enough water to make 461 mL of solution, what will be the molarity?
Answer:
1.143 M.
Explanation:
Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.
M = (no. of moles of solute)/(V of the solution (L)).
∴ M = (mass/molar mass)of KNO₃/(V of the solution (L)).
∴ M = (mass/molar mass)of KNO₃/(V of the solution (L)) = (53.27 g / 101.1 g/mol)/(0.461 L) = 1.143 M.
What does the principle of uniformitarianism state
Answer:
Explanation:
Uniformitarianism - "The Present is the Key to the Past"
Uniformitarianism is a geological doctrine. It states that current geologic processes, occurring at the same rates observed today, in the same manner, account for all of Earth's geological features. Thus, it assumes that geological processes are essentially unchanged today from those of the unobservable past, and that there have been no cataclysmic events in earth's history. As present processes are thought to explain all past events, the Uniformitarian slogan is, "the present is the key to the past.
Answer:
I hope this helps! <3
Explanation:
What is pH level, what are its characteristics, and how does it contribute to pollution?
Answer:
pH Scale:
The pH scale refers to the negative logarithm of molar concentration of hydrogen ions: pH = -log [H+].
Characteristics:
The pH scale ranges from 0 to 14. A solution of a compound of pH 7 or pOH 7 is a neutral solution. Solutions of pH less than 7 are acidic and more than 7 are basic.
Low pH of water is acidic in nature as it enters into the ground and collects in streams, it can have bad impacts on the ecosystem.
Significant Figures For 7.06 × 10^5 ÷ 5.3 × 10^-2
Answer:
[tex]\boxed{\text{two}}[/tex]
Explanation:
In multiplication and division problems, your answer can have no more significant figures than the number with the fewest significant figures.
[tex]\dfrac{7.06 \times 10^{5}}{5.3 \times 10^{-2}}= 1.332 075 472 \times 10^{7}[/tex] (by my calculator)
There are three significant figures in 7.06 and two in 2.3.
You must round to [tex]\boxed{\textbf{two}}[/tex] significant figures and report the answer as 1.3 × 1.0⁷.
On dividing the exponents, [tex]\frac{7.06* 10^{5} }{5.3*10^{-2}} = 1.33 * 10^{7}[/tex].
How to divide exponents?To divide them, you take the exponent value in the numerator (the top exponent) and subtract the exponent value of the denominator (the bottom exponent).
[tex]= \frac{7.06* 10^{5} }{5.3*10^{-2}} \\\\= \frac{7.06}{5.3}* 10^{5+2}\\ \\= 1.33 * 10^{7}[/tex]
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what is an emperical formula?
An empirical formula is the chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms.
For example the molecule 'CH2O' is the empirical formula for glucose.