At what height above the ocean the acceleration of gravity of the earth will have a value of 9.3m /s^2 ?

Answer:

1.5 x 10^-8 Tesla

Explanation:

E = 4.5 V/m

The relation between electric field and the magnetic field in electromagnetic wave is given by

c = E / B

Where, c be the velocity of light in vacuum, e be the electric field and B be the magnetic field

B = E / c

B = 4.5 / ( 3 x 10^8)

B = 1.5 x 10^-8 Tesla

The magnetic field of an electromagnetic wave at a specific point can be calculated using the known electric field and the speed of light. In this case, the magnitude of the magnetic field is 1.5 x 10^-8 Tesla (T).

In the context of an electromagnetic wave, the electric and magnetic fields are linked through Maxwell's Equations. Given that an electromagnetic wave propagates in free space, the ratio of the amplitudes of the electric field (E) to the magnetic field (B) is always equal to the speed of light (c), according to the equation c = E/B. Thus, when the magnitude of the electric field (E) is known, the magnetic field (B) can be calculated as B=E/c. In this case, the Electric field (E) is 4.50 V/m. Hence, using the value of speed of light c = 3x10^8 m/sec, we calculate the magnetic field (B) as follows: B = 4.50 V/m / 3x10^8 m/sec = 1.5 x 10^-8 Tesla (T).

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Answer:

Power = 47.0 Watt

Explanation:

As we know that friction force is given by

[tex]F_f = \mu mg[/tex]

now we have

[tex]\mu = 0.20[/tex]

m = 6.0 kg

now we have

[tex]F_f = 0.20(6.0)(9.80) = 11.76 N[/tex]

now since we need to find the rate of work done by friction force

so we can say rate of work done is power due to friction force

so it is given as

[tex]P = F_f (v)[/tex]

[tex]P = 11.76 (4.0)[/tex]

[tex]P = 47.0 Watt[/tex]

The rate at which the frictional force is doing work on the block when it's moving at a speed of 4.0 m/s is 47.04 Watts.

The rate at which the frictional force is doing work on the 6.0-kilogram block sliding along a horizontal surface can be obtained by recognizing that work done per unit time is equal to power. The frictional force (F) acting on the block is given by F = μkN, where μk is the coefficient of kinetic friction and N is the normal force. In this case, since the surface is horizontal, N is equal to the weight of the block, which is mass (m) times gravity (g).

Therefore, F = μkmg = 0.20 * 6.0 kg * 9.8 m/s² = 11.76 N.

The power (P) done by the force of friction is given by P = Fv, where v is the velocity. So, P = 11.76 N * 4.0 m/s = 47.04 Watts.

This calculates to be the rate at which the frictional force is doing work on the block when it is moving at a speed of 4.0 m/s.

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Answer:

The intensity of this wave and energy is 6.3385 N/m² and 2.0509 J.

Explanation:

Given that,

Electric field amplitude E₀= 69.1 V/m

Area A= 0.0247 m²

Time t= 13.1 s

We need to calculate the intensity

Using formula of intensity

[tex]S=\dfrac{1}{2}c\epsilon_{0}E_{0}^2[/tex]

Where, c = speed of light

Put the value into the formula

[tex]S=\dfrac{1}{2}\times3\times10^{8}\times8.85\times10^{-12}\times(69.1)^2[/tex]

[tex]S=6.3385\ N/m^2[/tex]

(b). We need to calculate the energy

Using formula of energy

[tex]E=SAt[/tex]

Where, A = area

t = time

S = intensity

Put the value into the formula

[tex]E =6.3385\times0.0247\times13.1[/tex]

[tex]E =2.0509\ J[/tex]

Hence, The intensity of this wave and energy is 6.3385 N/m² and 2.0509 J.

This statement is true.

Yes, supervisors can face disciplinary action for engaging in retaliation. They can be held accountable if they retaliate against an employee for reporting violations or participating in protected activities. Penalties can vary from warnings to termination.

True. Supervisors, just like any other employees, are subject to disciplinary action for engaging in retaliation. For instance, if a supervisor retaliates against an employee for reporting a violation of company policies or for engaging in protected activities like organizing or supporting a labor union, they can be held accountable. Disciplinary actions can range from written warnings to termination, depending on the severity of the retaliation. Therefore, it is essential for supervisors to respect the rights of the employees and abide by all workplace regulations to maintain a safe and fair environment.

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It takes Lukalu 2.5 seconds to reach the ground, and she lands 20 meters away from the cliff.

To determine how long it takes Lukalu to reach the ground, we need to find the value of [tex]\( t \)[/tex] when [tex]\( y(t) = 0 \)[/tex], since[tex]\( y(t) \)[/tex] represents her vertical position. The parametric equation for \( y(t) \) is given by[tex]\( y(t) = -16t^2 + 100 \).[/tex] Setting [tex]\( y(t) \)[/tex] equal to zero gives us the equation:

[tex]\[ -16t^2 + 100 = 0 \][/tex]

Solving for [tex]\( t \)[/tex], we get:

[tex]\[ 16t^2 = 100 \] \[ t^2 = \frac{100}{16} \] \[ t^2 = 6.25 \] \[ t = \sqrt{6.25} \] \[ t = 2.5 \][/tex]

So, it takes Lukalu 2.5 seconds to reach the ground.

Next, to find out how far away from the cliff she is when she lands, we need to evaluate [tex]\( x(t) \) at \( t = 2.5 \)[/tex] seconds. The parametric equation for [tex]\( x(t) \)[/tex] is given by [tex]\( x(t) = 8t \)[/tex]. Plugging in the value of [tex]\( t \),[/tex] we get:

[tex]\[ x(2.5) = 8 \times 2.5 \][/tex]

[tex]\[ x(2.5) = 20 \][/tex]

Therefore, Lukalu is 20 meters away from the cliff when she lands."

The work done by the gravitational force on a ball that rises to a height and then returns to its original point is zero, as the work done during the ascent is equivalent but opposite to the work done during the descent.

The work done by the gravitational force on an object that rises to a height and then returns to its original point is zero. This is because the work done by the gravitational force when the ball rises is equal in magnitude but opposite in direction to the work done when the ball falls back down.

When the ball ascends, the work done by the gravitational force is negative since the displacement (upwards) is opposite to the direction of gravitational force (downwards). The formula to calculate the work done in this phase is W = -mg * h, where 'm' is the mass of the ball, 'g' is the acceleration due to gravity and 'h' is the height.

During the ball's descent, the work done is positive as the displacement (downwards) is in the same direction as the direction of gravitational force (downwards). The work done in this phase can be calculated using the same formula W = mg * h (noting that 'h' is a negative height as the ball is descending). When you add these together, the total work done by gravity over the full journey of the object is zero.

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Answer:

An electric motor is a device that changes electrical energy into mechanical energy. This change occurs due to the interaction between the magnetic field of magnets and the magnetic field due to the  electric current in the  loop. The interaction between the two produces a torque that makes the loop rotate on a shaft.

An electric motor is electric machinery that converts electrical energy supplied to it to mechanical energy.

It works on the principle of applying a magnetic field in electromagnetism.

A current-carrying loop is exposed to a magnetic field which results in torque.

The torque formed rotates the coil which is then followed by rotation of propellers as the current passes through the loop.

Explanation

An electric motor consist of a rotor- a moving part, commutator, brushes, axle, field-magnet, power supply and a stator- a part going around the rotor.

Answer:

The critical angle for a diamond in air is 24 degrees, while the critical angle for glass is 41 degrees.

Explanation:

Rays exiting the material at an angle less than the critical angle will be refracted, and rays incident on the interface at greater than the critical angle will be totally reflected back inside the material.

we have that from the Question, it can be said that   distance x from the left-hand end of the bar is

x=1.834m

From the Question we are told

A uniform metal bar is 5.00 m long and has mass 0.300 kg. The bar is pivoted on a narrow support that is 2.00 m from the left-hand end of the bar. What distance x from the left-hand end of the bar should an object with mass 0.900 kg be suspended so the bar is balanced in a horizontal position?

Generally the equation for Balanced torque is mathematically given as

T=0.3/5*3

T=0.18kg

Therefore  

The clockwise torque is

T_c=0.18*1.5g

And

The anti-clockwise torque is

T=0.3/5*2g

T=0.12

Hence

0.18*1.5g=0.3/5*2g+0.9kxg

Therefore

x=1.834m

Therefore

distance x from the left-hand end of the bar is

x=1.834m

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The position of the 0.9 kg mass to balance the metal bar is 1.83 m.

The given parameters;

The center of gravity of the metal bar = 2.5 m

A sketch of weight on the metal bar;

|-----------2 m-----------|--- 0.5 m-----|

0---------------------------Δ--------------------------------------------------

   P ↓|-------- x----------|                     ↓

    0.9 kg                                   0.3 kg

Take moment about the pivot point;

0.9x = 0.3(0.5)

0.9x = 0.15

[tex]x = \frac{0.15}{0.9} \\\\x = 0.167 \ m[/tex]

2 m - P = 0.167 m

P = 2m - 0.167 m

P = 1.83 m

Thus, the position of the 0.9 kg mass to balance the metal bar is 1.83 m.

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Answer:

[tex]8.1^{\circ}, 171.9^{\circ}[/tex]

Explanation:

The magnitude of the magnetic force exerted on the moving electron is:

[tex]F=qvB sin \theta[/tex]

where here we have

[tex]F=1.40\cdot 10^{-16} N[/tex] is the magnitude of the force

[tex]q=1.6\cdot 10^{-19} C[/tex] is the magnitude of the electron charge

B = 1.23 T is the magnetic field intensity

[tex]\theta[/tex] is the angle between the direction of the electron's velocity and the magnetic field

Solving the equation for [tex]\theta[/tex], we find:

[tex]sin \theta = \frac{F}{qvB}=\frac{1.40\cdot 10^{-16}N}{(1.6\cdot 10^{-19} C)(5.06\cdot 10^3 m/s)(1.23 T)}=0.141[/tex]

which gives the following two angles:

[tex]\theta = 8.1^{\circ}\\\theta = 180^{\circ}-8.1^{\circ} = 171.9^{\circ}[/tex]

Answer:

102.5 N

Explanation:

The impulse theorem applied to this situation states that:

[tex]F \Delta t = m \Delta v[/tex]

where

F is the average force applied on the child and the sled

[tex]\Delta t[/tex] is the time interval during which the force is applied

The term on the right represents the variation of momentum, which is the product of:

m is the mass of the child+sled

[tex]\Delta v[/tex] is the change in velocity of the child+sled

In this situation we have:

[tex]\Delta v = 0 - 1.5 m/s = -1.5 m/s[/tex]

m = 41 kg

[tex]\Delta t = 0.60 s[/tex]

So we can solve to find the average force:

[tex]F=\frac{m\Delta v}{\Delta t}=\frac{(41 kg)(-1.5 m/s)}{0.60 s}=-102.5 N[/tex]

And the negative sign means the force is applied against the direction of motion of the child. So the magnitude of the force is 102.5 N.

To stop a sled with a mass of 41 kg sliding at 1.5 m/s within 0.60 s, one needs to apply an average force of 102.5 N opposite to its direction of motion, using the concepts of impulse and momentum.

To calculate the magnitude of the average force needed to stop a sled, using the concepts of impulse and momentum. The initial velocity of the child and sled is 1.5 m/s to the right, with the mass being 41 kg, and the time over which the force is applied is 0.60 s.

Impulse equals the change in momentum, so the initial momentum (pi) is mass times velocity (41 kg x 1.5 m/s), and the final momentum (pf) is 0 (since the sled stops). Therefore, the change in momentum (Δp) is simply the initial momentum. The impulse (•Ft) equals the force times the time interval (0.60 s), equals the change in momentum. So, we can solve for force (•F) using •F = Δp / t.

The calculation is as follows: Initial momentum = 41 kg x 1.5 m/s = 61.5 kg·m/s. Since the final momentum is 0, the change in momentum (Δp) is -61.5 kg·m/s (negative, indicating a direction opposite to the initial motion). So, the magnitude of the average force needed is |Δp| / t = |(-61.5 kg·m/s) / (0.60 s)| = 102.5 N.

Therefore, the magnitude of the average force you need to apply to stop the sled is 102.5 N.

answer is earth. Earth is having everything that is required for a magnetic field to operate.

Based on the assumption that a liquid conducting core and rapid rotation are both required for a magnetic field to operate, only Earth have magnetic fields.

Because of their compact, rocky surfaces akin to Earth's terra firma, the planets Mercury, Venus, Earth, and Mars are referred to as terrestrial. The four planets closest to the sun are the terrestrial planets. None of the terrestrial planets have rings, although Earth does have radiation belts that have been trapped.

Only Earth possesses a sizable planetary magnetic field among the terrestrials. There is no global magnetic field on Mars or the moon of Earth, although there are localised regional magnetic fields at various locations across their surfaces.

Venus, Earth, and Mars are the only terrestrial planets with noticeable atmospheres.

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Answer:

Required time, t = 0.84 seconds

Explanation:

It is given that,

Initial speed of an object, u = 22 m/s

Final velocity of an object, v = 27 m/s

Acceleration, a = 5.93 m/s²

We have to find the time required for an object to go a speed of 22 m/s to a speed of 27 m/s. It can be solved by using first equation of motion as:

[tex]v=u+at[/tex]

Where

t = time

[tex]t=\dfrac{v-u}{a}[/tex]

[tex]t=\dfrac{27\ m/s-22\ m/s}{5.93\ m/s^2}[/tex]

t = 0.84 seconds

Hence, the time required for an object is 0.84 seconds.

Answer:

1.974 g

Explanation:

Electrochemical equivalent of copper, z = 0.000329 g/C

I = 10 A

t = 10 minutes = 10 x 60 = 600 seconds

By the use of Farady's law of electrolysis

m = z I t

m = 0.000329 x 10 x 600

m = 1.974 g

Answer with Explanations:

Given:

Mass of object, m = 100 lb

height fallen, h = 600 ft

initial velocity, u = 50 ft/s

acceleration due to gravity, g = 31.5 ft/s^2

Find final velocity when it touches ground.

Solution:

Use standard kinematics equation, in the absence of air resistance and variation of g with height,

v^2 - u^2 = 2aS

where

v = final velocity

u = initial velocity

a = acceleration due to gravity

S = distance travelled

Substitute values

v^2 = u^2 + 2aS

= 50^2 + 2*31.5*600

= 40300 ft^2/s^2

Final velocity,

v = sqrt(40300) ft/s

= 200.75 ft/s

= 201 ft/s  to the nearest foot.

Answer:

6.83 m/s

Explanation:

Momentum is conserved.

Initial momentum = final momentum

(300 g) (-2.15 m/s) + (22.5 g) (35.5 m/s) = (22.5 g) v

v = 6.83 m/s

Answer:

Change in momentum is 1.1275 kg-m/s

Explanation:

It is given that,

Mass of the ball, m = 274 g = 0.274 kg

It hits the floor and rebounds upwards.

The ball hits the floor with a speed of 2.40 m/s i.e. u = -2.40 m/s  (-ve because the ball hits the ground)

It rebounds with a speed of 1.7 m/s i.e. v = 1.7 m/s (+ve because the ball rebounds in upward direction)

We have to find the change in the ball's momentum. It is given by :

[tex]\Delta p=p_f-p_i[/tex]

[tex]\Delta p=m(v-u)[/tex]

[tex]\Delta p=0.275\ kg(1.7\ m/s-(-2.4\ m/s))[/tex]

[tex]\Delta p=1.1275\ kg-m/s[/tex]

So, the change in the momentum is 1.1275 kg-m/s

The magnitude of the change in the ball's momentum when rebounding off the floor is 1.1275 kg·m/s, accounting for the change in direction during impact.

To determine the magnitude of the change in the ball's momentum, you should first consider the initial and final momenta of the ball. Momentum is calculated as the product of mass and velocity. When the ball hits the floor, it has a downward momentum of (mass × velocity before hitting the floor). After rebounding, it has an upward momentum of (mass × velocity after rebounding). Since the problem states that up is in the positive direction, you will have to take into account the change in direction when calculating the change in momentum.

To calculate the magnitude of the change in momentum (Δp), you use the formula Δp = p_final - p_initial. Plugging in the values:

p_initial = mass × velocity before hitting = 0.275 kg × (-2.40 m/s) = -0.66 kg·m/s

p_final = mass × velocity after rebounding = 0.275 kg × 1.70 m/s = 0.4675 kg·m/s

Δp = p_final - p_initial = 0.4675 kg·m/s - (-0.66 kg·m/s) = 1.1275 kg·m/s

The negative sign for p_initial indicates that it was directed downwards. The magnitude of the change in momentum is simply the absolute value of Δp, which is 1.1275 kg·m/s.

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Answer:

sorry I've never took in this class before I will not be able to help you

A temperature increase of 1°C every minute translates to a temperature increase of 1.8°F every minute. Over 10 minutes, the temperature would therefore increase by 18°F.

The question is asking about temperature increase in an object. If an object with an initial temperature of 300 K increases its temperature by 1°C every minute, we first need to understand the connection between degrees Celsius and Fahrenheit. Namely, a difference of 1 degree Celsius is equivalent to a difference of 1.8 degrees Fahrenheit.

So, if the temperature increases by 1°C every minute, it would increase by 1.8°F every minute. If we look at a span of 10 minutes, we use simple multiplication to find the total increase. The temperature would increase by 1.8°F x 10 = 18°F over the course of 10 minutes.

Thus, the answer is (C) 18°F.

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Explanation:

It is given that,

Radius of curvature of the mirror, R = 1.54 cm

(a) We have to find the focal length of the mirror. The relationship between the focal length and the radius of curvature is given by :

[tex]R=2f[/tex]

f = focal length of the mirror

[tex]f=\dfrac{1.54\ cm}{2}[/tex]

f = 0.77 cm

(b) The power of mirror is given by the reciprocal of focal length i.e.

Power, [tex]P=\dfrac{1}{f}[/tex]

P = 1.29 diopters

Hence, this is the required solution.

Answer:

- 1.3 x 10⁻¹⁵ C/m

Explanation:

Q = Total charge on the circular arc = - 353 e = - 353 (1.6 x 10⁻¹⁹) C = - 564.8 x 10⁻¹⁹ C

r = Radius of the arc = 5.30 cm = 0.053 m

θ = Angle subtended by the arc = 48° deg = 48 x 0.0175 rad = 0.84 rad        (Since 1 deg = 0.0175 rad)

L = length of the arc

length of the arc is given as

L = r θ

L = (0.053) (0.84)

L = 0.045 m

λ = Linear charge density

Linear charge density is given as

[tex]\lambda =\frac{Q}{L}[/tex]

Inserting the values

[tex]\lambda =\frac{-564.8\times 10^{-19}}{0.045}[/tex]

λ = - 1.3 x 10⁻¹⁵ C/m

Hello! My name is Zalgo and I am here to help you out on this concluding day. The answer would be C);lower. The reason it would be lower is because the hottest color of flames would be blue. Considering the way a start emits light is fire, this would be the most logical reason for it.

I hope that this helps! :P

"Stay Brainly and stay proud!" - Zalgo

(By the way, do you mind marking me as Brainliest? I'd greatly appreciate it! Thanks! X3)

Answer:

C

Explanation:

Centripetal acceleration is:

a = v² / r

First, convert km/h to m/s:

108 km/h × (1000 m / km) × (1 h / 3600 s) = 30 m/s

Therefore, the acceleration is:

a = (30 m/s)² / 300 m

a = 3 m/s²

Answer:

C

Explanation:

Positive acceleration describes an increase in speed; negative acceleration describes a decrease in speed.

Answer:

The coefficient of friction is 0.34

Explanation:

It is given that,

Mass of the load, m = 1000 kg

It is dragged up an incline at 10 degrees to the horizontal by a force of 5 KN applied in the most effective direction, F = 5 × 10³ N

We need to find the coefficient of friction between the surface and the load.   From the attached figure, the load is dragged up with a force of F. A frictional force f will also act in this scenario.

So, [tex]F=f+mg\ sin\theta[/tex]

Since, [tex]f=\mu N[/tex]

or  [tex]f=\mu mg\ cos\theta[/tex]

[tex]F=\mu mg\ cos\theta+mg\ sin\theta[/tex]

[tex]F-mg\ sin\theta=\mu mg\ cos\theta[/tex]

[tex]5\times 10^3\ N-1000\ kg\times 9.8\ m/s^2\ sin(10)=\mu mg\ cos\theta[/tex]

[tex]\mu=\dfrac{3298.24}{1000\ kg\times 9.8\ m/s^2\times cos(10)}[/tex]

[tex]\mu=0.34[/tex]

So, the coefficient of friction is 0.34. Hence, this is the required solution.

Answer:

Elastic potential energy, E = 2 J

Explanation:

It is given that,

Spring constant of the spring, k = 2500 N/m

The spring is stretched to a distance of 4 cm i.e. x = 0.04 m

We have to find the elastic potential energy possessed by the spring. A spring possessed elastic potential energy and it is given by:

[tex]E=\dfrac{1}{2}kx^2[/tex]

[tex]E=\dfrac{1}{2}\times 2500\ N/m\times (0.04\ m)^2[/tex]

E = 2 Joules.

Hence, the correct option is (d) " 2 Joules ".

Answer:

Option (2)

Explanation:

The sun is a large astronomical body where there occurs the process of nuclear fusion. This process is responsible for the occurrence of two important things. Firstly, it helps in the conversion o f hydrogen atoms into helium, that fuels the energy of the sun, and secondly, it helps in the continuous conversion of matter into energy, that reaches the earth's surface and on which the living organisms are directly dependent on.

Thus, there occurs conversion of about 4 million tons of matter into energy every second.

Therefore, the correct answer is option (2).

Answer:

a = 5.05 x 10¹⁴ m/s²

Explanation:

Consider the motion along the horizontal direction

[tex]v_{x}[/tex] = velocity along the horizontal direction = 3.0 x 10⁶ m/s

t = time of travel

X = horizontal distance traveled = 11 cm = 0.11 m

Time of travel can be given as

[tex]t = \frac{X}{v_{x}}[/tex]

inserting the values

t = 0.11/(3.0 x 10⁶)

t = 3.67 x 10⁻⁸ sec

Consider the motion along the vertical direction

Y = vertical distance traveled = 34 cm = 0.34 m

a = acceleration = ?

t = time of travel  = 3.67 x 10⁻⁸ sec

[tex]v_{y}[/tex] = initial velocity along the vertical direction = 0 m/s

Using the kinematics equation

Y = [tex]v_{y}[/tex] t + (0.5) a t²

0.34 = (0) (3.67 x 10⁻⁸) + (0.5) a (3.67 x 10⁻⁸)²

a = 5.05 x 10¹⁴ m/s²

The vertical acceleration provided by the deflector is 5.05 x 10¹⁴ m/s².

Acceleration can be defined as the change in speed or direction of the object or particle.

First, calculate the time for horizontal motion,

[tex]t = \dfrac d v_x[/tex]

Where,

[tex]d[/tex] - horizontal distance = 11 cm = 0.11 m

[tex]v_x[/tex] - horijontal velocity = 3.0 x 10⁶ m/s

So,

t =  3.67 x 10⁻⁸ sec

Now calculate for vertical acceleration,

[tex]Y = v^o\times t + (0.5) a t^2[/tex]

Where,

Y - verical distance = 34 cm = 0.34 m

v^o - initial vertical velocity = 0 m/s.

a - acceleration = ?

Put the values in the formula,

0.34 = (0) (3.67 x 10⁻⁸) + (0.5) a (3.67 x 10⁻⁸)²

a = 5.05 x 10¹⁴ m/s²

Therefore, the vertical acceleration provided by the deflector is 5.05 x 10¹⁴ m/s².

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Answer:

(a) 152.85 Nm

(b) 1528.5 Nm

Explanation:

According to the formula of power

P = τ ω

ω = 2 π f

(a) f = 2500 rpm = 2500 / 60 = 41.67 rps

So, 40 x 1000 = τ x 2 x 3.14 x 41.67

τ = 152.85 Nm

(b) f = 250 rpm = 250 / 60 = 4.167 rps

So, 40 x 1000 = τ x 2 x 3.14 x 4.167

τ = 1528.5 Nm

Let the bigger sphere be sphere 1 and the let the smaller sphere be sphere 2. Rest of the answer is in the picture.

Answer:

7.85 cm

30 degree

Explanation:

As we know that that the angular displacement in one turn is 360 degree.

As there are 12 parts which are equally divided so the angle turn by each part is

= 360 / 12 = 30 degree

Thus, the angular displacement of each slice is 30 degree.

Radius of pie = 15 cm

Circumference of pie = 2 x 3.14 x 15 = 94.2 cm

Arc length for complete 360 degree = 94.2 cm

Arc length for 30 degree turn = 94.2 x 30 / 360 = 7.85 cm