Which of the following would likely form a heterogeneous mixture? Sugar and waterSalt and waterSand and waterBaking soda and water

-Are the most used in daily life and basic human needs

(such as oxygen,nitrogen,carbon, etc)

Explanation:

The most familiar elements are the ones most abundant in the earth and therefore the most economic ones. Good examples of this elements are oxygen, carbon, nitrogen silicium.

Answer:

C. two blue boxes representing 1s and 2s orbitals, and one set of three blue boxes representing 2p orbitals; 1s and 2s orbitals have a pair of up and down arrows; 2p orbitals show three partially filled orbitals with a single up-facing arrow

Explanation:

This problem is concerned with the electronic distribution of electrons into the energy levels or sub-level of the atom of nitrogen. Here in particular, we want to know the sublevel arrangement of electrons in the nitrogen atom.

Nitrogen has 7 electrons.

In order to know the sequence of filling of the atoms we must be guided by some principles:

Obeying these principles, we have:

N  (7) = 1s²2s²2p³

The first blue boxes are the s-sublevels 1s²2s²  with one orbital and would have two electrons each oriented in the up and down direction.

The p-sublevel has three orbitals and according to hund's rule, electrons would go in singly before pairing starts. This leaves the three orbitals with a single up facing arrow.

The correct arrangement of seven electrons in a nitrogen atom is: two pairs in the 1s and 2s orbitals, and one electron in each of the three 2p orbitals. This matches the description given in option C.

The correct answer is C. The atomic structure of nitrogen (atomic number 7) includes seven electrons, distributed over the 1s, 2s, and 2p orbitals. These orbitals follow the rules of Hund's Rule, which states that all orbitals in a given subshell (2p in this case) must be singly occupied before any double occupation occurs. Therefore, the nitrogen atom fills the 1s and 2s orbitals with two electrons each and has one electron in each of the three 2p orbitals.

So, the diagram representing nitrogen's electron arrangement is: two blue boxes representing 1s and 2s orbitals, both filled with a pair of up and down arrows (indicating two electrons in each); followed by a set of three blue boxes indicating 2p orbitals, where each box contains a single upward arrow (representing one electron in each 2p orbital) which matches the description of option C.

https://brainly.com/question/29157546

#SPJ12

Answer:

Isocyanates

Explanation:

The functional group is cyanate ion of the formula NCO⁻. The atoms in this functional group occur in a straight line giving it a linear structure. It has a singe C-O bond and a triple N ≡ C bond. It forms cyanate salts when it reacts with pure elements like sodium and other reactive metals as it has some acidic properties. It also forms complexes like silver cyanato [Ag(NCO)₂]⁻

Answer:

1.46 $.

Explanation:

2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O.

Every 2 moles of HCl are neutralized by 1 mole of Mg(OH)₂.

The no. of moles of HCl = (MV) of HCl = (2.0 L)(0.5 mol/L) = 1.0 mol.

This requires 0.5 mol of Mg(OH)₂ to be neutralized.

∵ no. of moles of Mg(OH)₂ = mass/molar mass.

∴ mass of Mg(OH)₂ = (no. of moles of Mg(OH)₂)(molar mass) = (0.5 mol)(58.32 g/mol) = 29.16 g.

1.0 g of Mg(OH)₂ costs → 0.05 $.

29.16 g of Mg(OH)₂ costs → ??? $.

∴ The cost of tablets = (29.16 g)(0.05 $) = 1.46 $.

The cost of the magnesium hydroxide tablet that will be required to neutralize 2.00 L of 0.500 M HCl would be 1.46 dollars

From the equation of the reaction:

Mg(OH)2 + 2HCl ---------------> MgCl2 + 2H2O

The mole ratio of Mg(OH)2 to HCl = 1:2

Mole of 2.00 L, 0.500 M HCl = 0.500 x 2.00 = 1 mole

Equivalent mole of Mg(OH)2 = 1/2 = 0.5 moles

Mass of 0.5 mole Mg(OH)2 = 0.5 x 58.3

                                                  = 29.15 g

Since 1 tablet = 1.00 g Mg(OH)2 = 0.05 dollars.

29.15 g Mg(OH)2 = 29.15 tablet = 29.15 x 0.05 dollars

                                      = 1.46 dollars

More on stoichiometric calculations can be found here: https://brainly.com/question/8062886

The solutions having pOH=3.37, [h+]=3.8x10^-4 and pH=5.11 are acidic. Solutions with pOH=11.40, [OH-]=6.6x10^-3 and pH=12.94 are basic. The solution with [h+]=1.0x10^-7 is neutral. The solutions with [h+]=5.8x10^-8 and [OH-]=3.5x10^-12 are mildly acidic and basic respectively.

In an aqueous solution at 25 °C, the pH and pOH scales are defined so that water, which is neutral, has a pH of 7.00 and a pOH of 7.00. If the pH is less than 7, the solution is acidic. If the pH is greater than 7, the solution is basic. Hence, solutions with pOH=3.37 and [h+]=3.8x10^-4 are acidic, as they would have a pH lower than 7. The solutions with pOH=11.40, [OH-]=6.6x10^-3 and pH=12.94 are basic, as they would have a pH higher than 7. The solution with [h+]=1.0x10^-7 is neutral as it has a pH of 7. The solutions with [h+]=5.8x10^-8 and [OH-]=3.5x10^-12 are slightly acidic and basic respectively due to being close to the pH of 7. The solution with pH=5.11 is acidic as it's less than 7.

https://brainly.com/question/35891346

#SPJ12

The given solutions can be classified based on pH, pOH, [H+] and [OH-]. Based on these values, they are categorised as acidic, basic, or neutral.

The values provided are measures of the concentration of Hydronium ions [H+], hydroxide ions [OH-], pH, and pOH, which help determine whether a solution is acidic, basic, or neutral. At 25 degrees Celsius, a neutral solution has pH = 7, pOH=7, [H+] = 1.0x10^-7, and [OH-] = 1.0x10^-7. If the pH or [H+] is less than 7, or pOH or [OH-] is greater than 7, the solution is acidic. If the pH or [H+] is greater than 7, or pOH or [OH-] is less than 7, the solution is basic.

Applying this for each solution: pOH=3.37, acidic; pOH=11.40, basic; [H+]=3.8x10^-4, acidic; [H+]=5.8x10^-8, acidic; [OH-]=3.5x10^-12, acidic; [OH-]=6.6x10^-3, basic; [H+]=1.0x10^-7, neutral; pOH=7, neutral; pH=5, acidic; pH=12.94, basic.

https://brainly.com/question/38690417

#SPJ11

Answer:

2As2S3 + 9O2 = 2As2O3 + 6SO2

Explanation:

The correct balanced reaction is:-

2 As₂S₃ (s) + 9 O₂ (g) → 2 As₂O₃ (s) + 6 SO₂ (aq)

A balanced chemical equation occurs when the number of the atoms involved in the reactants side is equal to the number of atoms in the products side. In this chemical reaction, nitrogen (N₂) reacts with hydrogen (H) to produce ammonia (NH₃). The reactants are nitrogen and hydrogen, and the product is ammonia. It means to make the number of atoms the same on both the reactants and products side.

To learn more about balanced reaction,refer here :

https://brainly.com/question/15355912

#SPJ2

Answer:

D.gain enough kinetic energy to get past each other.

Explanation:

Melting can be best described as a process in which molecules gain enough kenetic energy to put past each other.

Answer:

D

Explanation:

Edge 2020

Answer:

C) After reacting, each ion has a stable octet.

Explanation:

Atoms bond to gain stability and to do that they must fill in their outer energy shell with 8 electrons, which we call an octet. In the case of sodium and chlorine, the sodium atom donates one electron to chlorine. When an atom loses an electron, the protons outnumber the electrons, so they become positively charged. This means it will become a cation.

Answer:

C) After reacting, each ion has a stable octet.

Explanation:

Answer:

Sublimation

Explanation:

Sublimation is the direct conversion of a solid to a gas.

A. is wrong. Melting is the conversion of a solid to a liquid.

C. is wrong. Condensation is the conversion of a gas to a liquid.

D. is wrong. Evaporation is the conversion of a liquid to a gas.

Answer:

FeSO4.

Explanation:

We divide the percentages by the relative atomic masses of the elements:

Iron =  36.76 / 55.845= 0.6583

Sulphur = 21.11 / 32.06 = 0.6584

Oxygen = 42.13 / 15.999 = 2.6333

Simplifying the ratios:

Fe : S : O =

0.6583: 0.6584: 2.6333

= 1 : 1 : 4

The empirical formula is FeSO4.   (Ferrous Sulphate).

Answer & Explanation:

∴ The mass of 1.0 mol of NaHCO₃ = (no. of moles of NaHCO₃)(the molecular mass of NaHCO₃)

∴ The mass of 1.0 mol of NaHCO₃ = (1)(the molecular mass of NaHCO₃) = (the molecular mass of NaHCO₃).

∴ The mass of 1.0 mol of NaHCO₃ = (atomic weight of Na) + (atomic weight of H) + (atomic weight of C) + 3(atomic weight of O) = (23.0 g of Na) + (1.0 g of H) + (12.0 g of C) + 3(16.0 g of O) = (23.0 g of Na) + (1.0 g of H) + (12.0 g of C) + (48.0 g of O) = 84.0 g.

For Na:

The mass% of Na = (the mass of Na)/(the mass of  NaHCO₃) = (23.0 g)/(84.0 g) x 100 = 27.381%.

For H:

The mass% of H = (the mass of H)/(the mass of  NaHCO₃) = (1.0 g)/(84.0 g) x 100 = 1.19%.

For C:

The mass% of C = (the mass of C)/(the mass of  NaHCO₃) = (12.0 g)/(84.0 g) x 100 = 14.285%.

For O:

The mass% of O = (the mass of O)/(the mass of  NaHCO₃) = (48.0 g)/(84.0 g) x 100 = 57.143%.

The sum of % of elements = mass% of Na + mass% of H + mass% of C + mass% of O = 27.381% + 1.19% + 14.285% + 57.143% = 99.999% ≅ 100.0%.

Answer:

Here's what I get.

Explanation:

[tex]\text{The mass of one mole of NaHCO$_{3}$ is:}\\\\\text{$\boxed{23}$ g Na +$\boxed{1}$ g H + $\boxed{12}$ g C + $\boxed{48}$ g O = $\boxed{84}$ g}[/tex]

[tex]\text{mass $\%$ Na = $\boxed{23}$ g $/$ $\boxed{84}$ g $\times$ 100 = $\boxed{27.38}$ $\%$}\\\\\text{mass $\%$ H = $ \quad \boxed{1}$ g $/$ $\boxed{84}$ g $\times$ 100 = $\boxed{1.19}$ $\%$}\\\\\text{mass $\%$ C = $\:\: \boxed{12}$ g $/$ $\boxed{84}$ g $\times$ 100 = $\boxed{14.29}$ $\%$}\\\\\text{mass $\%$ O = $\:\: \boxed{48}$ g $/$ $\boxed{84}$ g $\times$ 100 = $\boxed{57.14}$ $\%$}[/tex]

[tex]\boxed{27.38} + \boxed{1.19} + \boxed{14.29} + \boxed{ 57.14} = \boxed{100.00}[/tex]

Answer:

Explanation:

The enthalpy change is calculated using the formula: ΔH=MC∅ where ΔH is the change in enthalpy, M the mass of the substance, C the specific heat capacity of the substance and ∅ the temperature change.

Thus, ΔH= 750g × 4.18 J/gK × (19-11)K

=25080 J

2. Enthalpy change= mass of substance × specific heat capacity of the substance× Change in temperature.

ΔH= MC∅

M= ΔH/(C∅)

Substituting for the values in the question.

M=8750 J/(0.9025/g°C×66.0 °C)

=146.9 grams

3. Enthalpy change =mass × specific heat capacity × Temperature

ΔH= MC∅

∅ = ΔH/(MC)

=6500 J/(250 g × 4.18 J/g°C)

=6.22° C

Final temperature =98.8 °C - 6.22°C

=92.58 °C

4. Specific heat capacity =mass × specific heat capacity × Temperature change.

ΔH=MC∅

C= ΔH/(M∅)

Substituting with the values in the question.

C = 4786 J/(89.0 g×(89.5° C-23°C))

=0.808 J/g°C

5. Heat lost lost copper is equal to the heat gained by water.

ΔH(copper)= ΔH(water)

MC∅(copper)=MC∅(water)

M×0.385 J/g°C× (75.6°C- (19.1 °C+5.5°C))=100.0g×4.18 J/g°C×5.5 °C

M=(100.0g×4.18J/g°C×5.5°C)/(0.385 J/g°C×51 °C)

=117.09 grams.

6 (a). From the equation 1 mole of methane gives out 890.4 kJ

There fore 2 moles give:

(2×890.4)/1= 1780.8 kJ  

(b) 22.4 g of methane.

Number of moles= mass/ RFM

RFM=12 + 4×1

=16

No. of moles =22.4 g/16g/mol

=1.4 moles

Therefore 1.4 moles produce:

1.4 moles × 890.4 kJ/mol=

=1246.56 kJ

7. From the equation, 2 moles of aluminium react with ammonium nitrate to produce 2030 kJ

Number of moles = mass/RAM

Therefore 9.75 grams = (9.75/26.982) moles of aluminium.

=0.3613 moles.

If 2 moles produce 2030 kJ, then 0.3613 moles produce:

(0.3631 moles×2030 kJ)/2

=368.55 kJ

8. From the equation, 4 moles of ammonia react with excess oxygen to produce 905.4 kJ of energy.

Number of moles= mass/molar mass

RMM= 14+3×1= 17

Therefore 0.5113 grams of ammonia = (0.5113 g/17g/mole) moles

= 0.0301 moles

If 4 moles produce 905.4 kJ, then 0.0301 moles produce:

(0.0301 moles×905.4 kJ)/4 moles

=6.81 kJ

9. From the equations, one mole of methane produces 890 kJ of energy while one mole of propane produces 2043 kJ.

Lets change 5.5 grams into moles of either alkane.

Number of moles= Mass/RMM

For propane, number of moles= 5.5g/ 44.097g/mol

=0.125 moles

For methane number of moles =5.5 g/ 16g/mol

=0.344 moles

0.125 moles of propane produce:

0.125 moles×2043 kJ/mol

=255.375kJ

0.344 moles of methane produce:

0.344 moles× 890 kJ/mol

= 306.16kJ

Therefore, 5.5 grams of methane produces more heat than 5.5 grams of propane.

Answer:

108.43 g.

Explanation:

ΔTf = i.Kf.m,

where, ΔTf is the elevation in boiling water (ΔTf = 0.0°C - (- 14.5°C) = 14.5 °C).

i is van 't Hoff factor, The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

i for KNO₃ = 2/1 = 2.

Kf is the molal freezing constant of water (Kf = 1.86 °C/m).

m is the molality of the solution.

∵ ΔTf = i.Kf.m,

∴ m = (ΔTf)/(i.Kf) = (14.5°C)/(2)(1.86 °C/m) = 3.9 m.

m = (no. of moles of KNO₃)/(mass of water (kg)) = (mass/molar mass of KNO₃)/(mass of water (kg)).

∴ 3.9 m = (mass of KNO₃ / 101.1 g/mol)/(0.275 kg).

∴  mass of KNO₃ = (3.9 m)(101.1 g/mol)(0.275 kg) = 108.43 g.

To create a solution that freezes at -14.5 °C, calculate the required molality using the freezing point depression formula, adjust for the dissociation of KNO3 into 2 ions, and then use this to find the moles and mass of KNO3 needed. In this case, 108.35 grams of KNO3 must be added to 275 mL of water.

To determine how many grams of KNO3 must be added to produce a solution that freezes at -14.5 °C, we use the freezing-point depression formula: ΔTf = Kf x m, where ΔTf is the freezing point depression, Kf is the freezing point depression constant (1.86 °C/m for water), and m is the molality. First, we calculate the molality needed for the desired freezing point depression:

ΔTf = -14.5 °C (because the freezing point is 14.5 °C below that of pure water)

Kf = 1.86 °C/m

So, m = ΔTf / Kf = -14.5 °C / 1.86 °C/m = -7.795 m

Since KNO3 dissociates into K+ and NO3−, each mole of KNO3 will produce 2 moles of ions. For KNO3, the van't Hoff factor (i) is 2. The molality (m) considering dissociation will now be half the earlier calculated value due to the doubling of particles when dissociation occurs:

m = -7.795 m / 2 = -3.8975 m

The molality is negative because freezing point depression is a negative value. But for the purpose of calculations, we use the positive value of 3.8975 m. We use the formula molality (m) = moles of solute / kilograms of solvent to find the moles of KNO3 needed;

0.275 kg water (275 mL of water converted to kg) x 3.8975 m = moles of KNO3

Moles of KNO3 = 1.0715 mol (after calculation)

Finally, to find the mass of KNO3, multiply the moles by the molar mass (101.1 g/mol for KNO3):

Mass = 1.0715 mol x 101.1 g/mol = 108.35 g (rounded to two decimal places)

Therefore, 108.35 grams of KNO3 must be added to 275 mL of water to produce a solution that freezes at -14.5 °C.

Answer:

True.

Explanation:

A non-rechargeable battery, which is also called a primary cell, is known to overheat and some even explode when placed in a charger. This can occur due to the toxic chemicals that might seep out when the battery is heated.

+if this helped you, please consider marking it the Brainliest in order to help me unlock the the next achievement. thank you!

Answer:

T1 is shorter than T2, and the concentration of products at the end T1 is higher than that of T2.

Explanation:

Rate of the reaction = - d[reactants]/dt = d[products]/dt

∵ Rate at T1 (1.8 x 10⁻⁶ M/s) > rate at T2 (1.0 x 10⁻⁶).

∴ T1 < T2, which means that T1 is shorter than T2.

As, the rate increases, the remaining of the reactants decrease and products formed increase.

So, concentration of reactants at the end of T1 is lower than that of T2 and the concentration of products at the end T1 is higher than that of T2.

T1 is shorter than T2, and the concentration of products at the end T1 is higher than that of T2.

Answer: The electronic configuration is given below.

Explanation:

Electronic configuration tells us about the number of electrons that are present in an atom. It also determines the atomic number of an element.

Boron is the 5th element of the periodic table having 5 electrons.

The electronic configuration for the given element = [tex]1s^22s^22p^1[/tex]

This element has 3 valence electrons.

Thus, the electronic configuration is given above.

Answer:

Ultraviolet radiation breaks down CFCs, molecules containing chlorine. Chlorine then breaks one oxygen atom away from ozone, leaving behind a paired oxygen molecule.

Explanation:

Chlorofluorocarbons are popular called CFCs and are great climate forcers. When released into the atmosphere they cause depletion of ozone layers in the stratosphere.

CFCs are readily broken down by ultraviolet rays from the sun. This atmospheric reaction releases an atom of Cl. Chlorine is a very reactive element because it is a halogen and it requires just an electron to make it stable.

Ozone is made of three oxygen atoms. On losing an oxygen atom, it has two oxygen atoms and this turns the ozone layer to an oxygen gas pool.

CFCs lead to ozone depletion by releasing chlorine atoms that transform ozone into oxygen, thereby reducing the ozone layer's protective capacity against harmful UV radiation.

Chlorofluorocarbons (CFCs) contribute to ozone depletion because they release chlorine atoms in the stratosphere, which then engage in a destructive cycle with ozone molecules. Ultraviolet radiation breaks down CFCs, releasing chlorine atoms. These chlorine atoms react with ozone (O3), converting it to oxygen molecules (O2) through the following reactions:

Cl + O3 → ClO + O2

ClO + O → Cl + 2O2

Not only does one chlorine atom destroy many ozone molecules, but it also acts as a catalyst, meaning that after each reaction, it can continue to destroy more ozone without being consumed itself. This process hinders the ozone layer's ability to absorb ultraviolet light, resulting in increased levels of harmful UV radiation reaching the Earth's surface. The Montreal Protocol has been a significant international effort to phase out the use of CFCs and limit future ozone depletion.

Answer:

C. at low temperature and low pressure.

Explanation:

2CO₂(g) ⇄ 2CO(g) + O₂(g), ΔH = -514 kJ.

Effect of pressure:

So, decreasing the pressure will shift the reaction to the side with higher no. of moles of gas (right side, products), so the equilibrium partial pressure of CO (g) can be maximized at low pressure.

Effect of temperature:

2CO₂(g) ⇄ 2CO(g) + O₂(g) + heat.

C. at low temperature and low pressure.

Answer:

3.44 liters

Explanation:

before we start we must convert the celcius to kelvin by adding 273

Next we must Know we are using charles law and the eqation is V1/T1= V2/T2 we must convert it to  V1 T1 / T2

so its must equal 7.80 times 698 divided by 308 wich gives you 3.44 liters  

Answer:

3.44 or answer c on treca

Explanation:

Hello There!

When the ice melts, the water level will drop slightly but not much.

REMEMBER Ice expands so when ice melts, it shrinks back to the state of being liquid.

No change is witnessed as the weight of the ice and water is equal.

At the point when an ice cube is set in a glass of water, it uproots enough water to help its weight and leads to the condition:

Weight of an ice cube = mass of water/thickness of water.  

After the ice cube melts totally the water level continues as before as the water uprooted is currently satisfied by the measure of water present in the ice (3D shape). Indeed, even in the wake of liquefying, the measure of water in the ice cube will gauge is equal mass of ice block/thickness of water.  

As the weight stays same, the measure of water dislodged doesn't change and the water level continues as before. But, there are some water droplets around the glass.

Answer:

It minimizes the harmful side effects of the radiation.

Explanation:

Radioisotopes with short half-lives are used in medical diagnostics to minimize the exposure time and overall radiation dose to the patient, ensuring safety and reducing potential radioactive damage.

It is important that radioisotopes used in diagnostic tests have short half-lives to limit the radiation dose to the patient. The half-life of a radioisotope is the time it takes for half of the isotope to decay. Short-lived radioisotopes decay more quickly, reducing the duration of radiation exposure to the body's tissues and thus minimizing potential radioactive damage. This is essential in medical imaging where the balance between obtaining a clear image and reducing patient exposure to radiation must be carefully managed.

For example, radioisotopes like technetium-99m, with a half-life of only 6 hours, are ideal for medical diagnostic purposes because they decay quickly, limiting the time radiation can interact with body cells. Additionally, having radioisotopes that clear rapidly from the body prevents unnecessary radiation exposure and makes it safer for both the patient and the environment.

Answer:

(2) the same molecular formula and different properties

Explanation:

Butane and methylpropane are both isomers.

Isomerism signifies the existence of two or more compounds with different molecular structure but having the same molecular formula.

The structural difference is as a result of arrangement of the atoms or the orientation of the atoms in space.

Compounds differing in their structures but having the same molecular formula are called isomers. Isomers like butane and methylpropane differs in both their physical and chemical properties.

when hydrochloric acid is added to a potassium hydroxide solution, the acid and base would react to form salt(potassium chloride) and water

Chemical Formula:

HCl(aq) +KOH(aq) ---> KCl (aq) + H20 (l)

Answer:  [tex]HCl(aq)+KOH(aq)\rightarrow KCl(aq)+H_2O(l)[/tex]

Explanation:

Neutralization is a chemical reaction in which an acid and a base reacts to form salt and water.

[tex]HX+BOH\rightarrow BX}H_2O[/tex]

Neutralization is a double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The chemical equation for reaction of hydrochloric acid solution with a potassium hydroxide solution is:

[tex]HCl(aq)+KOH(aq)\rightarrow KCl(aq)+H_2O(l)[/tex]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

[tex]P\cdot V = n\cdot R\cdot T[/tex],

[tex]\displaystyle V = \frac{n\cdot R\cdot T}{P}[/tex].

where

The numerical value of [tex]R[/tex] will be [tex]8.314[/tex] if [tex]P[/tex], [tex]V[/tex], and [tex]T[/tex] are in SI units. Convert these values to SI units:

Apply the ideal gas law:

[tex]\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}[/tex].

Answer:

METAL: found in periodic table, lithium, shiny, lose electrons easily, good conductor, elements

NONMETAL: brittle, ductile, semimetals, found in periodic table, often gain electrons, semiconductors, carbon, shiny, poor conductor, elements

METALLOID: solid, non- ductile, malleable, found in periodic table, silicon, shiny, can be liquids, elements

Jupiter has 63 moons, which is the most in our solar system.

Answer:

∆Hrxn = ∑Hproducts - ∑Hreactants = 392 kj

Explanation:

∆H (heat of reaction) of a reaction is the heat that accompanies the entire reaction. This is, it represents the heat released or absorbed during the reaction .  This value can be positive or negative, and will depend on whether the process is exothermic or endothermic. A process is considered exothermic when this happens, heat is released to the surroundings, this means that the system loses heat, so ∆H <0. The opposite is true for endothermic processes, which are characterized by absorbing heat from the surroundings, which implies that ∆H> 0.

For the calculation of the heat of reaction you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient (quantity of molecules of each compound that participates in the reaction) and finally subtract them:

Enthalpy of reaction = ΔH = ∑Hproducts - ∑Hreactants

In this case you have the reaction

CH₃OH (l) + 2 O₂(g) ⇒ CO₂ (g) + 2 H₂O (g)

PRODUCTS:

CO₂: It is O=C=O.  You have two bonds C=O, so the bond energy = 2*799 kJ/mol = 1598 kJ/mole*1 mol ( Upon observing the reaction, 1 mol of CO₂ is stoichiometrically produced) = 1598 kJ

H₂O: It is H-O-H. You have two bons O - H, so the bond energy = 2*464 kJ/mol = 928 kJ/mole*2 moles ( Upon observing the reaction, 2 mol of H₂O is stoichiometrically produced) = 1856 kJ

∑Hproducts= 1598 kJ + 1856 kJ = 3454 kJ

REACTANTS:

CH₃OH: has 3 C-H bonds, 1 C-O bond and 1 O-H bond, so the bond energy = 3*414 kJ/mol + 360 kJ/mol + 464 kJ/mol = 2066 kJ /mol*1 mol (Upon observing the reaction, stoichiometrically reacts 1 mol of CH₃OH)= 2066 kJ/mol

O₂: It is O=O, so the bond energy = 498 kJ/mol*2 moles (Upon observing the reaction, stoichiometrically reacts 2 mol of O₂)= 996 kJ

∑Hreactants  = 2066 kJ + 996 kJ = 3062 kJ

∆Hrxn = ∑Hproducts - ∑Hreactants =3454 kJ - 3062 kJ= 392 kj

The sign is negative indicating an endothermic reaction.

To estimate ΔH°rxn using bond energies, you need to calculate the sum of the bond energies broken minus the sum of the bond energies formed in the reaction. The bond energies of the bonds broken are multiplied by the number of those bonds broken, while the bond energies of the bonds formed are multiplied by the number of those bonds formed. From this, the estimated ΔH°rxn for the given reaction is -216 kJ/mol.

For the given reaction:

CH₃OH(l) + 2 O₂(g) → CO2₂(g) + 2 H₂O(g)

Bonds broken:

3 C-H bonds (3 x 414 kJ/mol) = 1242 kJ/mol

2 O=O bonds (2 x 498 kJ/mol) = 996 kJ/mol

Bonds formed:

2 C=O bonds (2 x 799 kJ/mol) = 1598 kJ/mol

4 O-H bonds (4 x 464 kJ/mol) = 1856 kJ/mol

ΔH°rxn = (energy of bonds broken) - (energy of bonds formed)

ΔH°rxn = (1242 kJ/mol + 996 kJ/mol) - (1598 kJ/mol + 1856 kJ/mol)

ΔH°rxn = -216 kJ/mol

Note that the negative sign indicates an exothermic reaction, meaning it releases energy.

Therefore, the estimated ΔH°rxn for the given reaction is -216 kJ/mol.

Learn more about energy here:

https://brainly.com/question/1932868

# SPJ 6

Answer:

d) non-radioactive material left over from the production, assembly, and use of nuclear reactors

Answer:

oceans,air,rocks,soil, also living things

Explanation: