ANSWER ASAP AND I WILL GIVE BRAINLYEST!!!!

ANSWER ASAP AND I WILL GIVE BRAINLYEST!!!!

Answers

Answer 1

Answer:

20m

Explanation:

mark brainliest


Related Questions

If 1.30 grams of a protein (non -electrolyte) are added to a 100.0 mL of water, the osmotic pressure of the resulting solution is 0.0074 atm at 298 K. What is the molar mass of the protein ?

Answers

Answer:

M = 0.43× 10⁵ g/mol

Explanation:

Given data:

Mass of protein = 1.30 g

Volume of water = 100.0 mL ( 100/1000 =0.1 L)

Pressure of solution = 0.0074 atm

Temperature = 298 K

Molar mass of protein = ?

Solution:

Formula:

PV = nRT

n = PV / RT

n = 0.0074 atm ×0.1 L / 0.0821 atm. L / mol.K × 298 K

n = 0.00074 / 24.5 /mol

n = 3.0 × 10⁻⁵ mol

Molar mass of protein:

Number of moles = mass /  molar mass

3.0 × 10⁻⁵ mol = 1.30 g/ M

M = 1.30 g/  3.0 × 10⁻⁵ mol

M = 0.43× 10⁵ g/mol

Write the balanced molecular equation for the reaction of barium hydroxide with perchloric acid. What is the coefficient of H2O?​

Answers

Answer:

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + 2H2O

The coefficient of H2O is 2

Explanation:

Ba(OH)2 + HClO4 —> Ba(ClO4)2 + H2O

Now let us balance the equation as shown below:

There are 2 atoms of Cl on the right and 1 atom on the left. It can be balanced by putting 2 in front of HClO4 as shown below:

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + H2O

Now, there are a total of 4 atoms of H on the left and 2 on the right. It is balanced by putting 2 in front of H2O as shown below

Ba(OH)2 + 2HClO4 —> Ba(ClO4)2 + 2H2O

Now, the equation is balanced. From the balanced equation, the coefficient of H2O is 2

The balanced molecular equation for the reaction of barium hydroxide (Ba(OH)₂) with perchloric acid (HClO₄) is:

Ba(OH)₂ + 2HClO₄ -> Ba(ClO₄)₂ + 2H₂O

In this equation, the coefficient of H₂O is 2.

A balanced equation is a chemical equation in which the number of atoms of each element is equal on both sides of the equation. It represents a chemical reaction by showing the reactants on the left side and the products on the right side, with appropriate coefficients to balance the equation.

In a balanced equation, the total mass and the total charge of the reactants are equal to the total mass and total charge of the products. This ensures that the law of conservation of mass and the law of conservation of charge are satisfied.

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if a sample of gas at 25.2°C has a volume of 536 ml at 637 torr, what will its volume be if the pressure is increased to 712 torr?

Answers

Answer:

V = 479.6 mL

Explanation:

assuming ideal gas:

PV = RTn

∴ T = 25.2°C ≅ 298.2 K.........remains constant

∴ P1 = 637 torr = 0.8382 atm

∴ V1 = 536 mL = 0.536 L

∴ R = 0.082 atm.L/K.mol

⇒ n = (P1V1)/(RT) = ((0.8382 atm)*(0.536 L))/((0.082 atmL/Kmol)*(298.2K))

⇒ n = 0.0184 mol......remains constant

∴ P2 = 712 torr = 0.936842 atm

⇒ V2 = RTn/P2 = [(0.082atmL/Kmol)*(298.2K)*(0.0184mol)]/(0.936842atm)

⇒ V2 = 0.4796 L

Final answer:

Boyle's Law can be applied in this situation to show that when pressure on a gas sample increases, its volume decreases, assuming a constant temperature. By substituting the given values into the Boyle's Law formula, we find that the new volume, with increased pressure, is approximately 478 mL.

Explanation:

The volume of gas changing with pressure can be explained by Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. In this case, we can set up an equation based on Boyle's Law (P1V1 = P2V2), where P1 and V1 represent the initial pressure and volume, and P2 and V2 represent the final pressure and volume.

To solve for V2, you can rearrange the formula to: V2 = (P1V1) / P2. Substituting the given values into the formula:
V2 = (637 torr * 536 mL) / 712 torr =  478 mL approximately.

So, if the pressure is increased to 712 torr, the volume of the gas decreases to roughly 478 ml.

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This help with this chart

Answers

Answer:

Explanation:

Atomic mass is the sum of number of protons and neutrons while atomic number is the number of protons or electrons.

A neutral atom has equal number of protons and electrons that's why atomic number could be either number of protons or electrons.

Element            Symbol      Atomic#      Mass#     Protons       Neutrons    

Mercury                Hg                  80            200          80                120

Solution:

number of neutrons = mass number - atomic number

number of neutrons = 200 - 80

number of neutrons = 120

Element            Symbol      Atomic#      Mass#     Protons       Neutrons    

Tungsten                 W              74                 184             74            110

Solution:

number of neutrons = mass number - atomic number

number of neutrons = 184 - 74

number of neutrons = 110

Element            Symbol      Atomic#      Mass#     Protons       Neutrons    

Sodium                 Na              11                 23             11                  12

Solution:

number of neutrons = mass number - atomic number

number of neutrons = 23 - 11

number of neutrons = 12

Element            Symbol      Atomic#      Mass#     Protons       Neutrons    

Antimony               Sb              51                122             51                  71

Solution:

number of neutrons = mass number - atomic number

number of neutrons = 122 - 51

number of neutrons = 71

Element            Symbol      Atomic#      Mass#     Protons       Neutrons    

Silver                   Ag               47                108             47                61

Solution:

number of neutrons = mass number - atomic number

number of neutrons = 108 - 47

number of neutrons = 61

Which of the statements is correct regarding catalysts ( click 4 that apply )

Catalyst increase the rate of reaction

Catalyst decrease the rate of reaction

Catalyst increase the activation energy needed to start a reaction

Catalyst decrease the activation energy needed to start a reaction

They are used up in the reaction

They are not used up in the reaction

Catalyst are very specific

Catalyst are not very specific

Answers

Catalyst increase the rate of reaction

Catalyst decrease the activation energy needed to start a reaction

They are not used up in the reaction

Catalyst are not very specific

Explanation:

From the basic chemistry it is known Catalysts are substance that accelerates the rate of reaction without altering the nature of reaction.

Catalysts decreases the energy required for activation, in order to make collisions quicker.

Then, Catalyst just alters the rate of reaction alone and doesn't takes part in the chemical reaction.

Some catalysts are specific. But in general most of the catalysts are not specific in nature.

Propane burns in oxygen to produce carbon dioxide and steam. Which of the chemical equations matches the reaction above?

A. C3H8 + 5O2 3CO2 + 4H2O


B. C3H8 + 4O2 2CO2 + 4H2O


C. C3H8 + 6O2 2CO2 + 8H2O


D. C3H8 + 6O2 3CO2 + 6H2O

Answers

Answer: A

Explanation:

Balancing a chemical reaction, we must take into consideration every element both at the reactant and products side.

Since we were told propane reacts with oxygen to produce steam and carbon dioxide, we already have an idea of how the equation would be just remaining balancing the stoichiometry of the equation.

C3H8 + 5O2 =====》 3CO2 + 4H20

From the equation above,

3 atoms of carbon is present at reactant side and 3 carbon is also at the product side.

8 Hydrogen at reactant = 4 * 2 Hydrogen at product.

10 Oxygen at reactant = 3*2 + 4 oxygen at product

The equation must be balanced because law of conservation of matter must take place in every chemical reaction, matter can neither be created nor destroyed but can change form.

Answer:

A

Explanation:

Propane burns in oxygen to produce carbon dioxide and steam. The chemical equation is written with chemical symbols below:

C3H8 + O2  CO2 + H2O

There are three carbon atoms on the left side, but only one on the right, so we need to put a 3 in front of the carbon dioxide molecule to give three carbons on each side:

C3H8 + O2  3CO2 + H2O

There are eight hydrogen atoms on the left side and two on the right side, so we need to place a 4 in front of the water molecules on the right side:

C3H8 + O2  3CO2 + 4H2O

There are 2 oxygen atoms on the left side and 10 on the right side, so we need to place a 5 in front of the oxygen molecule on the left side:

C3H8 + 5O2  3CO2 + 4H2O

The equation has been balanced.

| Solve
-15 =5m/7 find m​

Answers

Answer:

m= −21

Explanation:

Solve for m by simplifying both sides of the equation, then isolating the variable. m= −21

Describe the difference between Al3+
and N3-

Answers

Al3+ is cation due to its positve charge
N3- is an anion due to its negative charge

how is energy transferred to or from an object if the kinetic energy changes

Answers

typically kinetic energy changes is passed through objects when it crashes

the electrical current in a circuit is measured in which of the following units.

volts
resistance
amperes
pressure​

Answers

The answer should be volts

The electrical current in a circuit is measured in amperes (amps). According to Ohm's Law, current (I) equals voltage (V) divided by resistance (R). Understanding these units helps grasp the flow of electricity in circuits.

The electrical current in a circuit is measured in amperes (often abbreviated as amps and symbolized by 'A'). According to Ohm's Law, the electric current (I) can be calculated by dividing the voltage (V) by the resistance (R). These relationships and units help in understanding the flow of electric current in circuits:

Voltage (V) is measured in volts.Resistance (R) is measured in ohms.Electric current (I) is measured in amperes.

What mass of K2SO4 What do you need to prepare 1200 g of an 8% K2SO4 m/m solution

Answers

Answer:

96 grams are required.

Explanation:

Given data:

Mass of K₂SO₄ required = ?

Mass of K₂SO₄ from = 1200 g of 8%

Solution:

Formula:

m/m% = mass required / mass given

Now we will put the values:

8%= x / 1200 g

8/100 = x / 1200 g

0.08 = x / 1200 g

0.08 × 1200 g= x

x = 96 g

So 96 gram of 1200 g is required.

What is the molar mass of the anhydrous
compound? Answer using four significant figures.
36.02 g/mol
120.15 g/mol
156.12 g/mol​

Answers

Answer: 120.15

Explanation:

Answer:

120.15

Explanation:

Look at the periodic table

Carbon dioxide and water are produced when pentane (C5H12) reacts with oxygen. What are the coefficients for this reaction?

Answers

Answer:

C5H12 + 8O2 —> 5CO2 + 6H2O

The coefficients are 1, 8, 5,6

Explanation:

The equation for the reaction is given below:

C5H12 + O2 —> CO2 + H2O

Now let us balance the equation. This is illustrated below:

There are 5 atoms of C on the left side and 1atom on the right side. It can be balance by putting 5 in front of CO2 as illustrated below:

C5H12 + O2 —> 5CO2 + H2O

There are 12 atoms of H on the left side and 2atoms on the right. It can be balance by putting 6 in front of H2O as illustrated below:

C5H12 + O2 —> 5CO2 + 6H2O

There are a total of 16 atoms of O on the right side and 2atoms on the left side. It will be balance by putting 8 in front of O2 as illustrated below:

C5H12 + 8O2 —> 5CO2 + 6H2O

Now we see clearly that the equation is balanced as the number of atoms of the different elements on both sides of the equation are the same.

The coefficients are 1, 8, 5,6

The chemical equation below shows the reaction of glucose and oxygen.
C6H12O6 + 6O2 -> 6CO2 + 6H2O + 36ATP
Which process does this equation represent and two of its products would be the reactants to which process?
⦁ Photosynthesis, aerobic respiration
⦁ Aerobic respiration, photosynthesis
⦁ Anaerobic respiration, photosynthesis
⦁ Nitrogen fixation, aerobic respiration

Answers

• Aerobic respiration, photosynthesis


It is aerobic because it requires oxygen to be carried out. Anaerobic on the other hand does not require oxygen.

It’s two products would be the reactants for photosynthesis because in photosynthesis the reverse reaction takes place as glucose is produced along with water from carbon dioxide (CO2) and water (H2O) in the presence of chlorophyll and sunlight.

Why do reactivity increases on moving from top to bottom in group 2 of modern periodic table?

Answers

Answer:

that's because....

group 1 (e.g Na, K) those tend to lose one electron to gain noble gas electron configuration.

they can achieve that by just losing one electron from their outer shell.

as you go down the group 1, element gets bigger in size, which means there is more space between nucleus (which is in center of atom) and electron of outer shell. the more far away they are the less attraction force between them.

so its easier for potassuim to lose one electron than for lithuim.

so that means potassium will easily give up 1 electron to react with non metal or other element therefore it is more reactive than lithuim

but in case of non metal, the opposite happens but simple to understand.

as you go down the group 7 (halogen- Cl, Br, I) element will get bigger therefore force between nucleus and outer electron is getting smaller. they have to gain 1 electron in order to fill the outer shell (to gain noble gas electron configuration.)

as florine is more smaller in size than clorine it is more reactive because florine has more tendency to pull extra electron from metal or other element towards its side. so it easily gain 1 electron to react.

What information does a net ionic equation give?
O
A. It lists only the spectator ions that are present.
B. It lists only the components that are ions.
O
C. It lists only the substances that are changed.
D. It lists only the aqueous components of the reaction.

Answers

Answer:

C. It lists only the substances that are changed.

Explanation:

Balanced Chemical equation:

HClO₂(aq) + NaOH(aq) → H₂O(l) + NaClO₂ (aq)

Ionic equation:

H⁺(aq) + ClO₂⁻(aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + ClO₂⁻ (aq)

Net ionic equation:

H⁺(aq) + OH⁻(aq) → H₂O(l)  

The ClO₂⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.  This'e why it is written in net ionic equation.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

Final answer:

A net ionic equation lists only the substances that change during a reaction, excluding spectator ions that do not participate in the chemical process. Therefore, the correct answer is C: It lists only the substances that are changed.

Explanation:

A net ionic equation is a chemical equation that shows only the species that actually participate in the reaction. These species are the ions that undergo a chemical or physical change during the reaction, which is different from the spectator ions that do not participate in the reaction. Spectator ions are present in the solution before and after the chemical reaction and do not undergo any change, so they are not included in the net ionic equation.

Correctly answering the student's question, a net ionic equation provides information about option C: It lists only the substances that are changed. This type of equation demonstrates the actual chemical change between the ionic compounds, excluding all the spectator ions that remain unchanged during the reaction process.

QUESTION 1: Using the experimental data, calculate the standard reduction potential for each metal, and organise them into a standard reduction table. Assume E° for B is 0V.

QUESTION 2: Deduce which two metals would produce the highest cell potential in a galvanic cell. Give reasons for your conclusion.

Answers

Final answer:

To calculate the standard reduction potential for each metal and organize them into a standard reduction table, we can use the formula Ecell = Ered - Eox. The standard potential for Q is -0.38V and for G is +0.72V.

Explanation:

To calculate the standard reduction potential for each metal, we can use the formula Ecell = Ered - Eox. Given the reduction potentials for Q and G, we can assume the reduction potential for Q is +0.38V and the reduction potential for G is -0.72V. Since Q is oxidized when connected to the standard hydrogen electrode, its standard potential is negative (-0.38V). On the other hand, since G is reduced when connected to the standard hydrogen electrode, its standard potential is positive (+0.72V).

Organizing the metals into a standard reduction table:

MetalStandard Reduction Potential (E°)Q-0.38VG+0.72V

Metal B has the highest standard reduction potential (0.85 V), and metal E follows closely (0.63 V). B-E galvanic cell would yield the highest potential due to their strong reduction tendencies.

To calculate the standard reduction potential for each metal, you can use the Nernst equation:

[tex]E_{\text {cell }}^{\circ}=E_{\text {cathode }}^{\circ}-E_{\text {anode }}^{\circ}[/tex]

where [tex]E_{\text {cell }}^{\circ}[/tex] is the standard cell potential, [tex]E_{\text {cathode }}^{\circ}[/tex] is the standard reduction potential of the cathode, and [tex]E_{\text {anode }}^{\circ}[/tex] is the standard oxidation potential of the anode.

First, let's assign oxidation numbers and write the balanced half-reactions for each cell:

1. [tex]\mathrm{A}(\mathrm{s})+\mathrm{B}^{2+}(\mathrm{aq}) \rightarrow \mathrm{A}^{2+}(\mathrm{aq})+\mathrm{B}(\mathrm{s})[/tex]

Reduction half-reaction: [tex]\mathrm{B}^{2+}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{B}(\mathrm{s})[/tex]

[tex]E_{\text {cathode }}^{\circ}[/tex] = 0.85

[tex]E_{\text {anode }}^{\circ}[/tex] = 0

2. [tex]\mathrm{B}^{2+}(\mathrm{aq})+\mathrm{C}(\mathrm{aq}) \rightarrow \mathrm{B}(\mathrm{s})+\mathrm{C}^{2+}(\mathrm{aq})[/tex]

Reduction half-reaction: [tex]\mathrm{C}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{C}^{2+}(\mathrm{aq})[/tex]

[tex]E_{\text {cathode }}^{\circ}[/tex] = −0.24

[tex]E_{\text {anode }}^{\circ}[/tex] = 0

3. [tex]2 \mathrm{D}^{+}(\mathrm{aq})+\mathrm{C}(\mathrm{s}) \rightarrow 2 \mathrm{D}(\mathrm{s})+\mathrm{C}^{2+}(\mathrm{aq})[/tex]

Reduction half-reaction: [tex]\mathrm{C}(\mathrm{s})+2 e^{-} \rightarrow \mathrm{C}^{2+}(\mathrm{aq})[/tex]

[tex]E_{\text {cathode }}^{\circ}[/tex] = 0

[tex]E_{\text {anode }}^{\circ}[/tex] = 0.58

4. [tex]\mathrm{B}(\mathrm{s})+\mathrm{B}^{2+}(\mathrm{aq}) \rightarrow \mathrm{B}^{2+}(\mathrm{aq})+\mathrm{B}(\mathrm{s})[/tex]

Reduction half-reaction: [tex]\mathrm{B}^{2+}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{B}(\mathrm{s})[/tex]

[tex]E_{\text {cathode }}^{\circ}[/tex] = 0

[tex]E_{\text {anode }}^{\circ}[/tex] = 0

5. [tex]\mathrm{B}(\mathrm{s})+\mathrm{E}^{2+}(\mathrm{aq}) \rightarrow \mathrm{B}^{2+}(\mathrm{aq})+\mathrm{E}(\mathrm{s})[/tex]

Reduction half-reaction:  [tex]\mathrm{E}^{2+}(\mathrm{aq})+2 e^{-} \rightarrow \mathrm{E}(\mathrm{s})[/tex]

[tex]E_{\text {cathode }}^{\circ}[/tex] = 0.63

[tex]E_{\text {anode }}^{\circ}[/tex] = 0

Now, let's calculate the standard reduction potentials for each metal:

[tex]\begin{aligned}& E_{\mathrm{B}}^{\circ}=0.85-0=0.85 \\& E_{\mathrm{C}}^{\circ}=-0.24-0=-0.24 \\& E_{\mathrm{D}}^{\circ}=0-0.58=-0.58 \\& E_{\mathrm{B}}^{\circ}=0 \\& E_{\mathrm{E}}^{\circ}=0.63-0=0.63\end{aligned}[/tex]

The two metals that would produce the highest cell potential in a galvanic cell are the ones with the highest standard reduction potentials. In this case, metals B and E have the highest reduction potentials, so a galvanic cell composed of B and E would have the highest cell potential. The reason is that a higher standard reduction potential indicates a stronger tendency to be reduced, and therefore, a higher cell potential in a galvanic cell.

When turbidity currents deposit graded beds of mud and sand on the ocean floor, what type of rock is formed?
A. Sedimentary
B. Metamorphic
C. Igneous basalt
D. Igneous granite

Answers

a. sedimentary
because the current will mold the mud and sand into rocks and currents forming rocks is a sedimentary rock formation
the is A. Sedimentary, someone else please explain why it is a.

How much mercury and oxygen could be obtained from 21.7g of mercury (II) oxide

Answers

20.06 g of Hg  and 1.6 g of O₂

Explanation:

To Find:

Number of Mercury and oxygen that can be obtained from 21.7 g of HgO

First we have to write the balanced equation for the decomposition reaction of Mercury(II) oxide as,

2 HgO (s) → 2Hg(l) + O₂ (g)

21.7 g of HgO  = [tex]\frac{21.7 g}{216.59 g / mol}[/tex]  

                         = 0.1 mol of HgO.

As per the above equation, we can find the mole ratio between HgO and Hg is 1: 1 and that of HgO and oxygen is 2:1 .

So amount of Hg produced = 0.1 mol × 200.59 g / mol ( molar mass of Hg)

                                                 = 20.06 g of Hg

Amount of oxygen produced = 0.05  mol × 32 g/ mol = 1.6 g of O₂

Thus it is clear that 20.06 g of Hg  and 1.6 g of O₂  is obtained from 21.7 g of HgO

Final answer:

From 21.7g of mercury (II) oxide, approximately 20.059 g of mercury and 1.6 g of oxygen can be produced through the decomposition reaction. This calculation uses the stoichiometry of the reaction and the molar masses of the substances involved.

Explanation:

To determine how much mercury and oxygen could be obtained from 21.7g of mercury (II) oxide, we need to consider the decomposition reaction of mercury (II) oxide under standard state conditions:

2HgO(s, red) → 2Hg(l) + O2(g)

By using the molar mass of mercury (II) oxide (216.59 g/mol), we can convert the mass of mercury (II) oxide to moles:

21.7 g HgO × (1 mol HgO / 216.59 g HgO) = 0.1 mol HgO

Following the stoichiometry of the reaction, 0.1 moles of HgO will produce 0.1 moles of Hg and 0.05 moles of O2, since 2 moles of HgO decompose to produce 1 mole of O2. We can then calculate the mass of mercury and oxygen produced:

0.1 mol Hg x (200.59 g Hg/mol) = 20.059 g of Hg

0.05 mol O2 x (32 g O2/mol) = 1.6 g of O2

Therefore, 21.7g of mercury (II) oxide will produce approximately 20.059 g of mercury and 1.6 g of oxygen.


If 0.899J of heat causes a 0,692 degree C temperature change, what mass of water
is present?

Answers

Final answer:

To calculate the mass of water present, we can use the formula Q = mcΔT, where Q is the heat energy (0.899 J), m is the mass of water, c is the specific heat capacity of water (4.184 J/g °C), and ΔT is the temperature change (0.692 °C). Rearranging the formula to solve for m, we find that the mass of water is approximately 0.307 g.

Explanation:

To calculate the mass of water present, we can use the formula:

Q = mcΔT

Where:

Q is the heat energy (0.899 J)

m is the mass of water

c is the specific heat capacity of water (4.184 J/g °C)

ΔT is the temperature change (0.692 °C)

Rearranging the formula to solve for m, we get:

m = Q / (cΔT)

Substituting the given values:

m = 0.899 J / (4.184 J/g °C * 0.692 °C)

Calculating m gives us:

m ≈ 0.307 g

Calculate the approximate volume of a 0.6000mol sample of gas at 288.15K and a pressure of 1.10atm.

Answers

Answer:

The volume of the sample of the gas is found to be 12.90 L.

Explanation:

Given pressure of the gas = P = 1.10 atm

Number of moles of gas = n = 0.6000 mole

Temperature = T = 288.15 K

Assuming the volume of the gas to be V liters

The ideal gas equation is shown below

[tex]\textrm{PV} =\textrm{nRT} \\1.10 \textrm{ atm}\times V \textrm{ L} = 0.6000 \textrm{ mole}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 288.5\textrm{K} \\\textrm{V} = 12.90 \textrm{ L}[/tex]

Volume occupied by gas = 12.90 L

You may remember that fresh water is the only type of water humans and animals can drink. For this reason, it is essential to life. What percentage of all water on Earth is fresh? options: 25% 75% 3% 90%.....

Answers

Answer:

3%

Explanation:

We have heard about the clean water crisis, but how can that happen if earth mostly covered in water? Even though 70% of the earth is covered in water, most of those water is at ocean and has a high concentration of salt. We can't drink those water because the salt will take more water from our bodies. Freshwater only makes up about 2.5-3% water bodies while the ocean makes up 97% of the rest. Out of 3% freshwater, we have, only 1% of them that easily accessible.

If 5.2 moles of oxygen react, how many moles of nitrogen monoxide are produced? _______ Round to the nearest tenth, include units on your answer.

Answers

Answer:

10.4 moles

Explanation:

Given parameters:

Number of moles of oxygen = 5.2moles

Number of moles of nitrogen monoxide = ?

Solution:

To solve this problem, we need to work from the known to the unknown specie according to the reaction.

Oxygen gas is known and we can estimate the amount of mole of nitrogen monoxide;

         

Let us write the balanced reaction equation;

                N₂    +      O₂          →          2NO

  according to this reaction;

       1 mole of oxygen gas will produce 2 mole of NO

       5.2 moles of oxygen gas will produce  (5.2 x 2)moles  = 10.4moles

Answer:

10.4 moles

Explanation:

The equation of the reaction between oxygen and nitrogen to produce nitrogen monoxide is,

N₂(g) + O₂ (g)→ 2NO (g)

1        :   1         :   2

This mean 1 mole of nitrogen gas react with 1 mole of oxygen gas to give 2 moles of nitrogen monoxide

In this case the if 5.2 moles of Oxygen react, it will give 2 moles of NO

5.2*2=10.4

1) ____ NaCl + ____ KOH  ____ NaOH + ____ KCl


2) ____ MgO + ____ Li2SO4  ____ MgSO4 + ____ Li2O


3) ____ H2O  ____ H2 + ____ O2


4) ____ RbF + ____ Be(NO3)2  ____ RbNO3 + ____ BeF2


5) ____ Ag +____ Cu(NO3)2  ____ AgNO3 + ____ Cu


6) ____ CO2 + ____ Cl2  ____ CCl4 + ____ O2


7) ____ CuSO4 + ____ HCN  ____ Cu(CN)2 + ____ H2SO4


8) ____ Ga2O3 + ____ Li  ____ Li2O + ____ Ga


9) ____ BaF2 + ____ Na2S  ____ BaS2 + ____ NaF


10) ____ NH3 ____ N2 + ____ H2


please solve as many as you can, the boxes are arrows

Answers

Answer:

hope it's helpful to you .

your 9th question is wrong but I did it correctly

it's not BaS2 it's BaS

Final answer:

The student's inquiry involved balancing a series of chemical equations, a fundamental concept in stoichiometry. Each balanced equation ensures that there is the same number of each element's atoms on the reactant side as on the product side, in accordance with the law of conservation of matter.

Explanation:

The questions you've posed involve stoichiometry, a field in chemistry that quantifies the relationships of different substances in a chemical reaction. Balancing chemical equations involves ensuring the conservation of atoms (each element in reactants should be equal to the count of the same element in products). Here are the balanced equations:

2 NaCl + 2 KOH → 2 NaOH + K2Cl2MgO + Li2SO4 → MgSO4 + 2Li2O2 H2O → 2 H2 + O22 RbF + Be(NO3)2 → 2 RbNO3 + BeF22 Ag + Cu(NO3)2 → 2 AgNO3 + CuNo reaction occurs in this case.3 CuSO4 + 6 HCN → 3 Cu(CN)2 + 3 H2SO46 Li + Ga2O3 → 3 Li2O + 2 Ga2 Na2S + BaF2 → BaS + 4 NaF2 NH3 → N2 + 3 H2

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Which of the following is true?
A
The sun has very little effect on natural cycles.
B
The sun is only helpful and is never dangerous.
The sun is very important, but its rays can also be harmful.
D
The sun is very dangerous and doesn't really support life on Earth.

Answers

Answer:

B

Explanation:

The sun can be dangerous but it also helps our Earth in a lot of ways

Final answer:

Answer C is true: The sun is critical for life on Earth, affecting natural cycles and providing necessary energy, but its UV rays can also be harmful to health and influence Earth's climate.

Explanation:

The correct answer is C: The sun is very important, but its rays can also be harmful. The sun radiates light and heat which are essential for the existence of life on Earth. It plays a crucial role in various natural cycles, such as those that regulate climate and weather, and it has enabled the development of all life forms as we know them. However, it is also true that the sun can be dangerous due to its intense ultraviolet (UV) rays, which can cause skin cancer, cataracts, and other health issues. Moreover, changes in the sun's energy can influence Earth's climate, potentially leading to warming or cooling periods.

Which of th following is true for a parallel circuit

Answers

Answer:

B. The voltage is the same across all resistors in the circuit.

Explanation:

The answer choices are:

A.The current is the same across all resistors in the circuit.B.The voltage is the same across all resistors in the circuit.C. As more resistors are added, the current will decrease.D. The sum of the voltage drops will equal the total voltage.

Solution

In a simple parallel circuit, each component (resistor) is connected directly to the battery forming different branches or pathways to the current.

Thus, the ends of each resistor receives the total potential difference or voltage from the battery, which is what the statement B. asserts. Hence, statement B is true.

On the other hand, the current will split among the different pathways, following Ohm's law: the greater the resistance of the resistor the lower the current. Thus, the statement A is false.

For a parallel circuit, the total resistance decreases as more resistors are added, which means that, again following Ohm's law, the current will increase, contradicting the statement C. Thus, the statement C is false.

It is in the series circuit that 'the sum of the voltage drops will equal the total voltage"; in a parallel circuit the voltage drop is the just one and the same for each resistor. Thus, the statement D is false,too.

How does the health of polar bears indicate the health of the environment

Answers

Answer:How it indicates the health of the environment is when the less food, shelter, and mates cause population reduction and if nothing done to stop (or reduce) the amount of thing being taken away they could go extincted.

Explanation:           Read above    /\

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hi anyone able to explain Why does the temperature of a substance remain the same when it is boiling using kinetic particles theory ? Thank you!

Answers

Answer:

The temperature remains

Explanation:

The temperature of a boiling substance remains the same because the extra energy is used in phase transition, that is to break the bonds between the molecules that hold them close together in the liquid state. With increased energy the molecules gain enough kinetic energy to overcome inter-molecular   forces and change state from liquid to gas

In which of the following substances does a beam of light travel the fastest?

A. water
B. plastic
C. glass
D. air

Answers

Answer:

d

Explanation:

The light is an electromagnetic radiation which can be perceived by our human eye. The beam of light travel fastest in air. The correct option is D.

What is light?

The light is defined as an electromagnetic radiation which help us to see the objects. It is composed of small packets of energy called photons. The light always moves in a straight line. Light travels at a faster rate than sound waves.

The speed of light is found to be 3 × 10⁸ m/s. Light does not require a physical medium for the propagation. It is known as a transverse wave which travels without the use of medium.

According to Einstein's theory of relativity, nothing can travel faster than light. When light is incident on any surface, the particles of light collide with the surface and thereby reflection and refractions occur.

Thus the correct option is D.

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Match each statement with the type of weathering it describes.

Answers

Answer: 1. Chemical weathering, 2. Mechanical weathering, 3. Chemical weathering, 4. Mechanical weathering, 5. Chemical weathering (all in the same order as the pick)

Explanation:

Statement 1,3 and 5 represent chemical weathering while statement 2 and 4 represent mechanical weathering.

What is  chemical weathering?

Chemical weathering is defined as a process of breaking down of rocks which is caused by the action of rain water which reacts with the minerals present in the rock and result in it's break down.This results in formation of new minerals and salts which are soluble.

The process of chemical weathering requires water and high temperatures,so places with warm and damp climate have higher rate of chemical weathering of rocks.There are three main different types of chemical weathering:

1) solution

2) hydrolysis

3)oxidation

Chemical weathering changes the composition of rocks,weathering caused by water which is called as hydrolysis results in production of new minerals in the rock.

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