Answer:
0 J
Explanation:
The work done by an ideal gas is given by the equation:
[tex]W=p\Delta V[/tex]
where
W is the work done by the gas
p is the pressure of the gas
[tex]\Delta V[/tex] is the change in volume of the gas
In this problem, we have a gas kept at a constant volume of
V = 2.00 L
This is an isochoric process (constant volume). Since the volume is constant, the change in volume is zero:
[tex]\Delta V=0[/tex]
And therefore, this means that the work done by the gas is zero:
W = 0
Uranium is an element that is often used in nuclear power plants. Uranium atoms are very large, and the substance can be dangerous if it is not carefully contained. What is true about all uranium atoms?
Answer:
The answer for this is that they each have the same number of protons.
Explanation:
Plutonium is an element that is also used in nuclear power plants, because of the same amount of protons in it, plutonium is used in nuclear power plants.
The fact about all uranium atoms is that they have the same number of protons that make them very large and can be harmful if not carefully treated.
Answer:
same number of protons
Explanation:
The spring of a spring gun has force constant k =400 N/m and negligible mass. The spring is compressed6.00 cm and a ball with mass 0.0300 kg isplaced in the horizontal barrel against the compressed spring. Thespring is then released, and the ball is propelled out the barrelof the gun. The barrel is 6.00 cm long, so the ballleaves the barrel at the same point that it loses contact with thespring. The gun is held so the barrel is horizontal.
Calculate the speed with which the ballleaves the barrel if you can ignore friction.
Calculate the speed of the ball as it leavesthe barrel if a constant resisting force of 6.00 Nacts on the ball as it moves along the barrel.
For the situation in part (b), at whatposition along the barrel does the ball have the greatest speed?(In this case, the maximum speed does not occur at the end of thebarrel.)
What is that greatest speed?
a) 6.9 m/s
b) 4.9 m/s
c) After 4.50 cm
d) 5.2 m/s
Explanation:
a)
In this case, there is no resistive force. Therefore, according to the law of conservation of energy, all the initial elastic potential energy stored in the spring when it is compressed is converted into kinetic energy of the ball as it leaves the barrel; so we can write:
[tex]\frac{1}{2}kx^2=\frac{1}{2}mv^2[/tex]
where:
k = 400 N/m is the spring constant
x = 6.00 cm = 0.06 m is the compression of the spring
m = 0.03 kg is the mass of the ball
v is the velocity of the ball as it leaves the barrel
Solving the equation, we can find the speed of the ball:
[tex]v=\sqrt{\frac{kx^2}{m}}=\sqrt{\frac{(400)(0.06)^2}{0.03}}=6.9 m/s[/tex]
b)
In this case, there is a constant resistive force of
[tex]F_r = 6.00 N[/tex]
acting on the ball as it moves along the barrel.
The work done by this force on the ball is:
[tex]W=-F_rd[/tex]
where
d = 6.00 cm = 0.06 m is the length of the barrel
And where the negative sign is due to the fact that the force is opposite to the motion of the ball
Substituting,
[tex]W=-(6.00)(0.06)=-0.36 J[/tex]
Therefore, part of the initial elastic potential energy stored in the spring has been converted into thermal energy due to the resistive force. So, the final kinetic energy of the ball will be less than before:
[tex]\frac{1}{2}kx^2+W=\frac{1}{2}mv^2[/tex]
And solving for v, we find the new speed:
[tex]v=\sqrt{\frac{kx^2}{m}+\frac{2W}{m}}=4.9 m/s[/tex]
c)
The (forward) force exerted by the spring on the ball is
[tex]F=k(x_0-x)[/tex]
where
k = 400 N/m
x is the distance covered by the ball
[tex]x_0=0.06 m[/tex] is the maximum displacement of the spring
While the (backward) resistive force is instead
[tex]F_r=6.0 N[/tex]
So the net force on the ball is
[tex]F=k(x-x_0)-F_r[/tex]
The term [tex]k(x-x_0)[/tex] prevails at the beginning, so the ball continues accelerating forward, until this term becomes as small as [tex]F_r[/tex]: after that point, the negative resistive force will prevail, so the ball will start delecerating. Therefore, the greatest speed is reached when the net force is zero; so:
[tex]k(x_0-x)-F_r=0\\x=x_0-\frac{F_r}{k}=0.06-\frac{6.00}{400}=0.045 m[/tex]
d)
After the ball has covered a distance of
x = 0.045 m
The work done by the resistive force so far is:
[tex]W=-F_r x =-(6.00)(0.045)=-0.27 J[/tex]
The total elastic potential energy of the spring at the beginning was
[tex]E_e=\frac{1}{2}kx_0^2 = \frac{1}{2}(400)(0.06)^2=0.72 J[/tex]
While the elastic potential energy left now is
[tex]E_e'=\frac{1}{2}k(x_0-x)^2=\frac{1}{2}(400)(0.015)^2=0.045 J[/tex]
So, the kinetic energy now is:
[tex]K=E_e-E_e'+W=0.72-0.045-0.27=0.405 J[/tex]
And by using the equation
[tex]K=\frac{1}{2}mv^2[/tex]
We can find the greatest speed:
[tex]v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(0.405)}{0.03}}=5.2 m/s[/tex]
In a cyclic process, a gas performs 123 J of work on its surroundings per cycle. What amount of heat, if any, transfers into or out of the gas per cycle?
123 J transfers out of the gas
123 J transfers into the gas
246 J transfers into the gas
0 J (no heat transfers)
Answer:
123 J transfer into the gas
Explanation:
Here we know that 123 J work is done by the gas on its surrounding
So here gas is doing work against external forces
Now for cyclic process we know that
[tex]\Delta U = 0[/tex]
so from 1st law of thermodynamics we have
[tex]dQ = W + \Delta U[/tex]
[tex]dQ = W[/tex]
so work done is same as the heat supplied to the system
So correct answer is
123 J transfer into the gas
Which molecule of the gpcr-adenylyl cyclase signal transduction system phosphorylates proteins to create the cellular response?
Answer:
Protein kinase A
Explanation:
Protein kinase A is also called Cyclic AMP- dependent protein kinase or A kinase. It is an enzyme that enhance protein covalently using the phosphate group. The function of this enzyme is that it helps to end the effect of different hormones working via the Cyclic AMP signalling pathway. Protein kinase A can be found in the cytoplasm which phosphorylate proteins.
Protein kinase A helps the cell in regulating sugar, glycogen and lipids metabolism level.
Answer:
The answer is Protein Kinase A.
Refer below for the explanation.
Explanation:
In cell science, protein kinase A is a group of compounds whose movement is reliant on cell levels of cyclic AMP. PKA is otherwise called cAMP-subordinate protein kinase. Protein kinase A has a few capacities in the cell, including guideline of glycogen, sugar, and lipid digestion.
A vector A⃗ has a magnitude of 40.0 m and points in a direction 20.0 ∘ below the positive x axis. A second vector, B⃗ , has a magnitude of 75.0 m and points in a direction 50.0 ∘ above the positive x axis.
a) Sketch the vectors A⃗ , B⃗ , and C⃗=A⃗+B⃗ .
b) Using the component method of vector addition, find the magnitude of the vector C⃗ .
c) Using the component method of vector addition, find the direction of the vector C
Answer:
Explanation:
Check attachment for solution
The analytical method of the components allows to find the results for the questions about the sum vector are:
a) In the attached we have a scheme of the vectors
b) the modulus is C = 96.3 m
c) The angle is θ = 27.0º
Given parameters
Vector A with modulus A = 40.0 m and an angle of θ₁ = -20º Vector B has a modulus B = 75.0 m and an angle of θ₂ = 50ºTo find
a) Draw the vectors and their sum.
b) The module.
c) the adirection.
The sum of vectors has several methods of resolution:
Graphic. In this case the vectors are drawn and the second is placed on the tip of the first and the resulting vector goes from the origin of the first to the tip of the last. This method is complicated when there are several vectors. Analytical. This method is very precise and is the most used when there are many vectors.
The analytical method consists:
Decompose each vector into its components with respect to a given reference frame, using trigonometry. Find the sum of each component Construct the final vector using trigonometry and the Pythagorean theorem.
In the attached we have a diagram of each vector and its sum. Let's use trigonometry to find the component of each vectors.
Vector A
cos θ₁ = [tex]\frac{A_x}{A}[/tex]
sin θ₁ = [tex]\frac{A_y}{A}[/tex]
Aₓ = A cos θ₁
[tex]A_y[/tex] = A sin θ₁
Aₓ = 40 cos (-20) = 37.59 m
[tex]A_y[/tex]= 40 sin (-20) = -13.68 m
Vector B
cos θ₂ = [tex]\frac{B_x}{B}[/tex]
sin θ₂ = [tex]\frac{B_y}{B}[/tex]
Bₓ = B cos θ₂
[tex]B_y[/tex] = B sin θ₂
Bₓ = 75 cos 50 = 48.21 m
[tex]B_y[/tex] = 75 sin 50 = 57.45 m
we add the components.
Cₓ = Aₓ + Bₓ
[tex]C_y = A_y + B_y[/tex]
Cₓ = 37.59 + 48.20 = 85.8 m
Cy = -13.68 + 57.45 = 43.8 m
b) We use the Pythagorean theorem to find the modulus of the resultant vector.
C² = Cₓ² + [tex]C_y^2[/tex]
C = [tex]\sqrt{85.8^2 + 43.8^2 }[/tex]
C = 96.3 m.
c) We use trigonometry to find the angle of the resultant vector.
tan θ =[tex]\frac{C_y}{C_x}[/tex]
θ = tan⁻¹ [tex]\frac{C_y}{C_x}[/tex]
θ = tan⁻¹ [tex]\frac{43.8}{85.8}[/tex]
θ = 27.0º
In conclusion, using the analytical method of the components we can find the results for the questions about the sum vector are:
a) In the attached we have a scheme of the vectors
b) the modulus is C = 96.3 m
c) The angle is θ = 27.0º
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What is the frequency of highly energetic ultraviolet radiation that has a wavelength of 129 nm? The speed of light is 3 × 108 m/s. Answer in units of Hz.
Answer:
[tex]2.33*10^{15}Hz[/tex]
Explanation:
The relationship between velocity v, frequency f and wavelength for electromagnetic waves is given by;
[tex]v=\lambda f..............(1)[/tex]
Given;
[tex]v=3*10^8m/s\\\lambda=129nm=129*10^{-9}m\\f=?[/tex]
We make substitutions into equation (1) as follows;
[tex]f=\frac{v}{\lambda}\\f=\frac{3*10^8}{129*10^{-9}}[/tex]
Explanation:
Below is an attachment containing the solution.
A spotlight on a boat is y = 2.2 m above the water, and the light strikes the water at a point that is x = 8.5 m horizontally displaced from the spotlight (see the drawing). The depth of the water is 4.0 m. Determine the distance d, which locates the point where the light strikes the bottom.
Answer:
The answer to the question is
The distance d, which locates the point where the light strikes the bottom is 29.345 m from the spotlight.
Explanation:
To solve the question we note that Snell's law states that
The product of the incident index and the sine of the angle of incident is equal to the product of the refractive index and the sine of the angle of refraction
n₁sinθ₁ = n₂sinθ₂
y = 2.2 m and strikes at x = 8.5 m, therefore tanθ₁ = 2.2/8.5 = 0.259 and
θ₁ = 14.511 °
n₁ = 1.0003 = refractive index of air
n₂ = 1.33 = refractive index of water
Therefore sinθ₂ = [tex]\frac{n_1sin\theta_1}{n_2}[/tex] = [tex]\frac{1.003*0.251}{1.33}[/tex] = 0.1885 and θ₂ = 10.86 °
Since the water depth is 4.0 m we have tanθ₂ = [tex]\frac{4}{x_2}[/tex] or x₂ = [tex]\frac{4}{tan\theta_2 }[/tex] =[tex]\frac{4}{tan(10.86)}[/tex] = 20.845 m
d = x₂ + 8.5 = 20.845 m + 8.5 m = 29.345 m.
When Dr. Hewitt immerses an object in water the second time and catches the water that is displaced by the object, how does the weight lost by the object compare to the weight of the water displaced?
Answer:
Explanation:
- The volume of water displaced by immersing the object is equal the amount of water spilled and caught by Dr. Hewitt.
- The amount of water is proportional to the volume of object of fraction of object immersed in water will lead to the same fraction of water displaced and caught by Dr. Hewitt.
- When the object is immersed the force of Buoyancy acts against the weight and reducing the scale weight.
- The amount of Buoyancy Force is proportional to the fraction of Volume of object immersed in water; hence, the same amount is spilled/lost.
What is the difference between porosity and permeability
Explanation:
Porosity is the percentage of spaces,(hollow) within a rock or a material that can contain air or fluid. This can be used in geology( study of rocks), soil mechanics, engineering and pharmaceutics. Industrial CT scanning can be used to test for porosity of a substance. While permeability is the ability of water or other fluids to flow through a rock or material that has spaces ( that is, that are porous). This is also applicable in the fields of chemical engineering and geology.
Porosity refers to the amount of void space in a material that can hold water, while permeability measures how well those spaces are connected, affecting water movement. Materials with high permeability have larger, well-connected pores, allowing water to flow easily; materials with low permeability do not. The hydraulic conductivity is a measure of permeability that accounts for both material and fluid properties.
Difference Between Porosity and Permeability
The difference between porosity and permeability concerns the storage and movement of water in subsurface materials like rock or sediment. Porosity refers to the percentage of open space within a material that can potentially hold water, expressed as a ratio of the volume of voids to the total volume of the material. Permeability, on the other hand, is about how well those pores are interconnected, determining the ease with which water can move through the material. Higher permeability indicates the presence of larger, well-connected pores, enabling water to flow with less friction. Conversely, materials with low permeability have fewer, smaller, and poorly connected pores, which restricts water movement.
Understanding both porosity and permeability is crucial when discussing groundwater storage and extraction, as they define an aquifer's ability to store and transmit water. Soil texture plays a significant role in determining these properties. Coarse-grained soils with larger pores tend to have both higher porosity and permeability, whereas fine-grained soils like clay can have high porosity but low permeability due to poorly connected pores.
A point charge Q moves on the x-axis in the positive direction with a speed of 160 m/s. A point P is on the y-axis at y = +20 mm. The magnetic field produced at the point P, as the charge moves through the origin, is equal to -0.6 μT k^k^. What is the charge Q? (μ 0 = 4π × 10-7 T · m/A)
Answer:
The charge on the particle = -0.00075 C = -0.75 mC = -750 μC
Explanation:
The solution to this question is presented in the attached image to this answer.
The Biot Savart's formula for calculating magnetic field due to moving point charge is used in this calculation.
Hope this Helps!!!
A diver makes 2.5 revolutions on the way from a 9.3-m-high platform to the water. Assuming zero initial vertical velocity, find the diver's average angular velocity during a dive.
Answer:
11.4 rad/s
Explanation:
The motion of the diver is a free-fall motion, so its center of mass falls down with constant acceleration of
[tex]g=9.8 m/s^2[/tex] towards the water
Therefore, we can use the following suvat equation:
[tex]s=ut-\frac{1}{2}gt^2[/tex]
where:
s = 9.3 m is the vertical displacement of the diver
u = 0 is the initial vertical velocity
[tex]g=9.8 m/s^2[/tex]
And t is the total time of flight. Solving for t,
[tex]t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(9.3)}{9.8}}=1.38 s[/tex]
So, the diver takes 1.38 s to reach the water.
During this time, the diver makes 2.5 revolutions; since 1 revolution is equal to an angle of [tex]2\pi[/tex] radians, then the total angular displacement is
[tex]\theta=2.5\cdot 2\pi =15.7 rad[/tex]
Therefore, the average angular velocity of the diver is the ratio between the total angular displacement and the time taken:
[tex]\omega=\frac{\theta}{t}=\frac{15.7}{1.38}=11.4 rad/s[/tex]
Suppose we placed a positive charge Q on the Moon and an equal positive charge Q on the Earth. What value of Q would be needed to neutralize the gravitational attraction of the Moon and the Earth?
Answer: q=5.70 x 10^13 C
Explanation:
gravitational attraction = electrostatic repulsion GMm/d^2 = kQ^2/d^2 as you can see the d^2 cancel out. that is why lunar distance is irrelevant. G is the universal gravitational constant = 6.67 x 10^-11 m^3 / kgs^2 M is earth's mass = 5.972 × 10^24 kg m is moon's mass = 7.342×10^22 kg Q is charge on earth and moon. k is coulomb's constant = 9 x10^9 N m^2 /C^2 On solving equation for Q. Q = sqrt (GMm/k) = sqrt ( 6.67 x 10^-11 x 5.972 x 10^24 * 7.342×10^22 / 9 x10^9) = 5.70 x 10^13 C
To neutralize the gravitational attraction between the Moon and the Earth using equal charges, calculate the total gravitational force and equate it to the electrostatic force of the charges. q=5.70 x 10¹³ C
gravitational attraction = electrostatic repulsion
GMm/d² = kQ²/d² as you can see the d² cancel out. that is why lunar distance is irrelevant. G is the universal gravitational constant = 6.67 x 10⁻¹¹ m³ / kgs² M is earth's mass = 5.972 × 10²⁴ kg m is moon's mass = 7.342×10²² kg Q is charge on earth and moon. k is coulomb's constant = 9 x10⁹ N m² /C² On solving equation for Q. Q = √ (GMm/k) = √ ( 6.67 x 10⁻¹¹x 5.972 x 10²⁴ × 7.342×10²² / 9 x10⁹) = 5.70 x 10¹³ C
How is the size of the mri signal related to the applied b0 field?
Answer:
Intensity Of MRI signal is related as square of [tex]B_{0}[/tex]
or
Intensity is related as [tex]B_{0}^{2}[/tex].
Explanation:
MRI simply means Magnetic Resonance Imaging. In this process by the resonance of magnetic field the frequency is produced which is used to image the body parts (Mainly the brain).
The signal Strength is the rate of change of Magnetization (M) with respect to the time. For the calculation of Intensity we use Bloch equation which is given by
[tex]\frac{dH}{dt} = M \times \gamma B[/tex]
On further solving
[tex]\frac{dH}{dt} =\mu B \times \gamma B \\\frac{dH}{dt} = \mu \times \gamma B^{2}[/tex]
So, Intensity is related as [tex]B_{0}^{2}[/tex].
explain why a law is accepted as facr, but a theory is not
Answer:
Explanation:
A law and theory are distinct levels in the scientific method. They do not lead to one another.
A law is a description of an observed phenomenon in the natural world. Laws are always true and do not provide explanations as to why they hold true.
A theory is an explanation of an observed phenomenon. It is usually based on experimental evidence and bounded most time in the limits of available data.
A law cannot be deposed. It is a fact and holds true at all times. Theories can be discarded even with new technological advancements that provides a new way of study. This is why it is not a fact.Two identical loudspeakers separated by distance d emit 200Hz sound waves along the x-axis. As you walk along the axis, away from the speakers, you don't hear anything even though both speakers are on.What are the three lowest possible values for d? Assume a sound speed of 340m/s.
Answer:
So three lowest possible values of d ar 0.85m, 2.55m and 4.25m
Explanation:
The wavelength of wave:
λ=v/f
λ=340/200=1.7m
The destructive interference condition is:
Δd=(m+1/2)λ where m=0,1,2,3........
For minimum destructive interference ,the value of m is equal to zero
Δd=(0+1/2)×1.7
Δd=0.85m
For m=1
Δd=(1+1/2)×1.7
Δd=2.55m
For m=2
Δd=(2+1/2)×1.7
Δd=4.25m
So three lowest possible values of d ar 0.85m, 2.55m and 4.25m
The interference of sound waves is causing silence at your location. The three lowest possible values for the distance between two speakers creating this effect, given the given frequency of 200Hz and sound speed of 340m/s, are 0.85m, 2.55m and 4.25m.
Explanation:This is a problem related to sound interference; that is when two or more sound waves overlap, the resultant sound you hear is different than when you hear the sound waves individually.
You are not hearing anything because the sounds from the two speakers are arriving out of phase at your location, causing destructive interference.
At destructive interference, the path difference is (n + 1/2)λ. For the first three lowest values for d, n = 0, 1, 2. The speed of sound v = λf, so λ = v / f. Substituting these values in we get d = (n + 1/2) * v/f.
Now, let's plug in the given values: f=200Hz, v=340m/s.
d for n=0: d = (0 + 1/2) * 340 / 200 = 0.85 md for n=1: d = (1 + 1/2) * 340 / 200 = 2.55 md for n=2: d = (2 + 1/2) * 340 / 200 = 4.25 mLearn more about Sound Interference here:
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Match the name of each gas law to the properties it compares. Part AA) Temperature and volumeB) Pressure and temperatureC) Pressure and volumePart B1. Boyle's law2. Charles's law 3. Gay-Lussac's law
Answer:
A. CHARLES' LAW
B. GAY-LUSSAC'S LAW
C. BOYLE'S LAW
Explanation:
THE QUESTION SEEKS ANSWER BY MATCHING THE PROPERTIES COMPARED BY A GAS LAW TO THE GAS LAW IN QUESTION.
A. CHARLES' LAW COMPARES TEMPERATURE AND VOLUME.
IT ESTABLISHED THE FACT THAT VOLUME AND TEMPERATURE ARE DIRECTLY PROPORTIONAL AT A FIXED PRESSURE
B. GAY-LUSSAC'S LAW COMPARE PRESSURE AND TEMPERATURE.
IT ESTABLISHED THE FACT THAT PRESSURE AND TEMPERATURE ARE DIRECTLY PROPORTIONAL FOR A GIVEN VOLUME OF GAS
C. BOYLE'S LAW COMPARES PRESSURE AND VOLUME
IT ESTABLISHED THAT BOTH ARE INVERSELY PROPORTIONAL AT A GIVEN TEMPERATURE
Answer:
1) D
2) B
3) E
Explanation: Edge 2020
Three point charges are arranged along the x axis. Charge q1=-4.00nC is located at x= .250 m and q2= 2.40 nC is at the x= -.300m. A positive point charge q3 is located at the origin. a) What must the value of q3 be for the net force on thispoint charge to have a magnitude 4.40 μN ?
Answer:
q₃=5.3nC
Explanation:
First, we have to calculate the force exerted by the charges q₁ and q₂. To do this, we use the Coulomb's Law:
[tex]F= k\frac{|q_aq_b|}{r^{2} } \\\\\\F_{13}=(9*10^{9} Nm^{2} /C^{2} )\frac{|(-4.00*10^{-9}C)q_3|}{(.250m)^{2} } =576q_3N/C\\\\F_{23}=(9*10^{9} Nm^{2} /C^{2} )\frac{|(2.40*10^{-9}C)q_3|}{(.300m)^{2} } =240q_3N/C\\[/tex]
Since we know the net force, we can use this to calculate q₃. As q₁ is at the right side of q₃ and q₁ and q₃ have opposite signs, the force F₁₃ points to the right. In a similar way, as q₂ is at the left side of q₃, and q₂ and q₃ have equal signs, the force F₂₃ points to the right. That means that the resultant net force is the sum of these two forces:
[tex]F_{Net}=F_{13}+F_{23}\\\\4.40*10^{-9} N=576q_3N/C+240q_3N/C\\\\4.40*10^{-6} N=816q_3N/C\\\\\implies q_3=5.3*10^{-9}C=5.3nC[/tex]
In words, the value of q₃ must be 5.3nC.
Technician A says that a heavy engine load results in high intake manifold vacuum and a high MAP sensor signal voltage. Technician B says that a manifold absolute pressure (MAP) sensor uses a perfect vacuum (zero absolute pressure) in the sensor to determine the pressure. Who is right?
Answer:
Technician B
Explanation:
A 75-hp compressor in a facility that operates at full load for 2500 h a year is powered by an electric motor that has an efficiency of 93 percent. If the unit cost of electricity is $0.11/kWh, the annual electricity cost of this compressor is
The annual electricity cost of the compressor is $15,386.25.
Explanation:To calculate the annual electricity cost of the compressor, we first need to find the energy consumption of the motor. We can use the formula:
Energy Consumption = Power x Time
Given that the compressor operates at full load for 2500 hours a year and has a power of 75 hp, we need to convert the power to watts:
1 hp = 746 watt
So, the power of the motor is 75 x 746 = 55,950 watts.
Now, we can calculate the energy consumption:
Energy Consumption = 55,950 watts x 2500 hours
Next, we need to convert the energy consumption to kilowatt-hours (kWh):
1 kWh = 1000 watt-hours
So, the energy consumption in kWh is 55,950 watts x 2500 hours / 1000 = 139,875 kWh.
Finally, we can calculate the annual electricity cost by multiplying the energy consumption by the unit cost of electricity:
Annual Electricity Cost = 139,875 kWh x $0.11/kWh
Therefore, the annual electricity cost of this compressor is $15,386.25.
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The ______ clause in an if statement allows a program to make one choice if the condition is true, and anothere choice if the condition is false.
Answer: The IF clause.
Explanation: This is the IF clause; you can use it as:
IF (something = true) then "something happens"
else "other thing happens"
Some example of it can be, suppose that your program reads a number X that the user inputs, then you can do:
If ( X > 5) then
print: "the number X is bigger than five"
Else
print: "the number X is smaller than five"
Where, of course, the statements depend on the language used, but the "if" clause works almost the same in every language.
A small space telescope at the end of a tether line of length L moves at linear speed v about a central space station. What will be the linear speed of the telescope if the length of the line is changed to x*L ? x = 2.8; v = 2 m/s?
Answer:
v' = 0.714 m/s
Explanation:
Solution:
- Assuming no external torque is acting on the system then the angular momentum is conserved for the system.
- The initial momentum angular Mi and final angular momentum Mf are as follows:
Mi = Mf
m*L*v = m*x*L*v'
Where,
m : mass of the telescope
L : Length of teether line
v: Initial speed
v' : Changed speed.
- Then we have:
L*v = x*L*v'
v' = v / x
v' = 2 / 2.8
v' = 0.714 m/s
Answer:
The answer to the question is
The linear speed of the telescope will be 5.6 m/s if the length of the line is changed to x*L where x = 2.8; and initial velocity v = 2 m/s
Explanation:
Speed = v₁ = ωL = 2 m/s
When the line is changed to x*L where x = 2.8 the linear speed will be
v₂ = 2.8 × L× ω = 2.8× 2 = 5.6 m/s
The linear speed varies with the angular speed following the relation v/r =ω where
ω = angular speed
v = linear speed and
r = radius of the path of travel of the object at the vertex
TheAurora Borealisis a night display in the Northern latitudes caused by ionizing radiation interacting with the Earth's magnetic field and the upper atmosphere. The distinctive green color is caused by the interaction of the radiation with oxygen and has a frequency of 5.38 x 1014units. What is the wavelength of this light?
Answer:
The answer is
The wavelength of the light is 557.2 x 10⁻⁻⁹nm
Explanation:
The wavelength of a wave is the distance between adjacent troughs and crests while the frequency of a wave is the number of completed cycles that pass a given per unit time
Electromagnetic radiation, such as light is usually described n terms of its frequency and wavelength
The equation relating the three quantities of speed of light, frequency and wavelength is as follows
Speed of light, c = Frequency of the light wave, ν × Wavelength of the light, λ
That is c = ν × λ
Where c = 299792458 m/s, v = 5.38 x 10¹⁴ Hz
Therefore the wavelength = [tex]\frac{c}{v}[/tex] = 5.572 x 10⁻⁷ m 557.2 x 10⁻⁻⁹nm
Is the magnitude of the acceleration of the center of mass of spool A greater than, less than, or equal to the magnitude of the acceleration of the center of mass of spool B?
Answer:
The acceleration of the centre of mass of spool A is equal to the magnitude of the acceleration of the centre of mass of spool B.
Explanation:
From the image attached, the description from the complete question shows that the two spools are of equal masses (same weight due to same acceleration due to gravity), have the same inextensible wire with negligible mass is attached to both of them over a frictionless pulley; meaning that the tension in the wire is the same on both ends.
And for the acceleration of both spools, we mention the net force.
The net force acting on a body accelerates the body in the same direction as that in which the resultant is applied.
For this system, the net force on either spool is exactly the same in magnitude because the net force is a difference between the only two forces acting on the spools; the tension in the wire and their similar respective weights.
With the net force and mass, for each spool equal, from
ΣF = ma, we get that a = ΣF/m
Meaning that the acceleration of the identical spools is equal also.
Hope this Helps!
If the volume of a sample of gas is reduced at constant temperature, the average velocity of the molecules _______, the average force of an individual collision _________, and the average number of collisions with the wall, per unit area, per second_______.
When the volume of gas is reduced at constant temperature, the average velocity of the molecules, the average force of an individual collision, and the average number of collisions with the wall all increase.
When the volume of a sample of gas is reduced at constant temperature, the average velocity of the molecules increases, the average force of an individual collision between molecules and the container walls increases, and the average number of collisions with the wall, per unit area, per second increases.
When the volume of a gas is reduced at constant temperature, the gas molecules’ average velocity remains unchanged, the force of each collision increases, and collisions with the wall per unit area per second become more frequent.
If the volume of a sample of gas is reduced at constant temperature, according to Boyle's law, the average velocity of the molecules remains the same, the average force of an individual collision increases, and the average number of collisions with the wall, per unit area, per second increases.
At a constant temperature, the kinetic energy of the gas molecules, as well as their average velocity, does not change. This is in accordance with the kinetic theory of gases. However, as the volume decreases, the gas molecules have less space to move around, which means they will encounter the container walls more frequently. Hence, the number of collisions with the wall per unit area per second increases. Since the same amount of molecules exert force over a smaller area of the container wall (because the volume is reduced), the average force per collision also increases.
It's important to clarify that while the average velocity does not change, the frequency of collisions leads to the increased pressure we observe in a confined volume of gas. Consequently, the gas exerts a greater pressure on the walls of the container.
When the compressor of an air conditioner starts up, it draws a current of 50 A. If the start-up time is 0.60 s, then the amount of charge passing through a cross-sectional area of the circuit during this time is:
Answer:
30 C
Explanation:
Given:
Current flowing in the circuit (I) = 50 A
Start-up time (t) = 0.60 s
Now, we know that, charge drawn in through a cross sectional area of the circuit is given as:
[tex]q=It[/tex]
Where, 'q' is the amount of charge drawn, 'I' is the current and 't' is the start-up time.
Now, plug in 50 A for 'I', 0.60 s for 't' and solve for 'q'. This gives,
[tex]q=50\ A\times 0.60\ s\\\\q=30\ C[/tex]
Therefore, the amount of charge drawn in the circuit at the start-up of the compressor of an air conditioner is 30 C.
Tech A says motor action occurs through the interaction of the magnetic fields of the field coils and the armature, which causes a rotational force to act on the armature, creating the turning motion. Tech B says two magnetic fields are required for motor action: one in the casing and the other in the rotating armature. Who is correct
Answer:
Both A and B
Explanation:
The interaction of magnetic fields and armature results into a rotational force of the armature hence turning motion. It's important to note that you will always need two magnetic fields in order to experience the force since one magnetic field is at the rotating armature and another at the casing. Considering the arguments of these two technicians, both of them are correct in their arguments.
Your roommate is working on his bicycle and has the bike upside down. He spins the 54.0 cm diameter wheel, and you notice that a pebble stuck in the tread goes by three times every second. A. What is the pebble's speed? B. What is the period of the pebble stone?
Answer:
If the diameter is 54cm, then the radius is half that, the radius is:
r = 54cm/2 = 27cm
Then the perimeter of the wheel is p = 2*pi*27cm
this would mean that the pebble travels the distance:
d = 3*2*pi*27cm in one second.
Then the velocity of the pebble is:
speed = 3*2*3.1416*27cm/s = 509cm/s
Now, we know that the pebble does 3 cycles in a second, so does each cycle in 1/3 seconds, so the period would be the time that it needs to do one cycle, that we already find that is equal to 1/3 seconds.
Final answer:
The pebble stuck in the bicycle wheel tread has a speed of 5.091 m/s, and the period of its motion is 0.333 seconds.
Explanation:
To solve for the pebble's speed and the period of its motion, we will perform calculations based on the given wheel diameter and the frequency of the pebble's motion. The wheel's diameter is 54.0 cm, which gives us a radius (r) of 27.0 cm or 0.27 meters.
The speed (v) of the pebble on the tread of the wheel can be found using the formula for the circumference (C) of the wheel and multiplying by the frequency (f) of the pebble's motion:
C = 2πr
v = C × f
Plugging in the values we get:
C = 2 × π × 0.27 m = 1.697 m
f = 3 rev/s (since it goes by three times every second)
v = 1.697 m × 3 rev/s = 5.091 m/s
The period (T) is the inverse of frequency:
T = 1 / f
T = 1 / 3 rev/s = 0.333 s
Therefore, the pebble's speed is 5.091 meters per second, and the period of the pebble stone is 0.333 seconds.
For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser pointer (λ=680nm) through the slit onto a screen 5.5 m away, a diffraction pattern appears. The bright band in the center of the pattern is 8.0 cm wide. What is the width of the slit?
Answer:
width of slit(a)≅ 0.1mm
Explanation:
Wave length of laser pointer =λ = 685 nm
Distance between screen and slit = L = 5.5 m
Width of bright band = W=8.0cm=0.08m
width of slit=a
recall the formula;
W=(2λL)/a
a=2λL/W
a=(2 *685*10⁻⁹*5.5m)/0.08m
a=7535*10⁻⁹/0.08
a=94187.5 *10⁻⁹
a=0.0000941875m
a=0.0941875mm
a≅0.1mm
Answer:
The wide of silt is a=93.5×10⁻⁶m
Explanation:
Given data
Wavelength λ=680 nm
Length L=5.5 m
Width w=8.0 cm
To find
Width of slit a
Solution
A single slit of width a has a bright central maximum of width
ω=2λL/a
a=2λL/ω
Substitute the given values
[tex]a=\frac{2*(680*10^{-9}m)5.5m}{0.08m} \\a=93.5*10^{-6}m[/tex]
The wide of silt is a=93.5×10⁻⁶m
A pen contains a spring with a spring constant of 257 N/m. When the tip of the pen is in its retracted position, the spring is compressed 5.1 mm from its unstrained length. In order to push the tip out and lock it into its writing position, the spring must be compressed an additional 6.1 mm. How much work is done by the spring force to ready the pen for writing
Final answer:
The work done by the spring force to ready the pen for writing is 0.404 J.
Explanation:
To find the work done by the spring force, we can use the formula for work: work = (1/2)k(x²), where k is the spring constant and x is the displacement of the spring from its unstressed length.
In this case, the spring is initially compressed 5.1 mm and then compressed an additional 6.1 mm. So the total displacement is 5.1 mm + 6.1 mm = 11.2 mm.
Substituting the values into the formula, we have work = (1/2)(257 N/m)((11.2 mm / 1000)²) = 0.404 J. The calculated work of 0.404 J represents the energy transferred to or from the spring as it undergoes the specified compressions, providing insight into the mechanical behavior of the system under the influence of the spring force.
1. Impulse is the product of force and distance. True or false?
2. The force necessary to lift an object is g. True or false?
3. A joule is a newton times a second. True or false?
4. Work is done to lift an object in the classroom. True or false?
5. Kinetic energy is the energy of position. True or false?
6. Stopping distance is doubled, if speed is quadrupled.True or false?
Answer:
Explanation:
1. Impulse, I = F.t
The statement impulse is the product of Force and distance is false.
2. F = m g
Force necessary to lift the object depends on the mass of the object.
statement 2 is false.
3. Joule is equal to Newton times meter.
Statement 3 is false.
4. Work done to lift an object is correct statement.
Statement 4 is true.
5. Kinetic energy of an object is due to motion.
Statement 5 is false.
6. Stopping distance is directly proportional to the square of velocity.
If velocity is doubled, stopping distance is quadrupled.
Statement 6 is false.
The correct answer is 1.False; 2.False; 3.False; 4.True; 5.False; 6.False.
1. Impulse is the product of force and time, not force and distance. Therefore, the statement is false.
2. The force necessary to lift an object is not simply g, but weight, which is calculated as mass times the gravitational acceleration g. So, this statement is false.
3. A joule is the unit of work or energy, equivalent to one newton meter (N·m), not a newton times a second. Thus, the statement is false.
4. Work is indeed done to lift an object in the classroom since work is the force applied over a distance in the direction of the force. Therefore, this statement is true.
5. Kinetic energy is the energy of motion, not the energy of position. Thus, this statement is false.
6. If the stopping distance is doubled when speed is quadrupled, it overlooks the fact that stopping distance increases with the square of the speed, meaning a quadrupling of speed typically increases the stopping distance by a factor of sixteen, not two. So, this statement is false.