Answer:
a)impulse = 10.7296 kg-m/s (upward)
b) F = 268.24 N (upward)
Explanation:
(a)
velocity of ball before it strikes the floor:
initial gravitational potential energy = final kinetic energy
mgh = (1/2)mv²
v = sqrt(2gh)
v = sqrt[2(9.81 m/s²)(19.5 m)]
v = 19.5599 m/s
velocity of ball after striking the floor:
initial kinetic energy = final gravitational potential energy
(1/2)mv² = mgh
v = sqrt(2gh)
v = sqrt[2(9.81 m/s²)(15.5m)]
v = 17.4387 m/s
impulse = change in momentum
impulse = (0.290 kg)(17.4387 m/s - (-19.5599 m/s))
impulse = 10.7296 kg-m/s (upward)
(b)
impulse = (force exerted)(time)
10.7296 kg-m/s = F(0.04 s)
F = 268.24 N (upward)